Research Article Global Strong Solution to the Density-Dependent 2-D Liquid Crystal Flows

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Hindawi Publishing Corporation
Abstract and Applied Analysis
Volume 2013, Article ID 947291, 5 pages
http://dx.doi.org/10.1155/2013/947291
Research Article
Global Strong Solution to the Density-Dependent
2-D Liquid Crystal Flows
Yong Zhou,1 Jishan Fan,2 and Gen Nakamura3
1
Department of Mathematics, Zhejiang Normal University, Jinhua 321004, China
Department of Applied Mathematics, Nanjing Forestry University, Nanjing 210037, China
3
Department of Mathematics, Inha University, Incheon 402-751, Republic of Korea
2
Correspondence should be addressed to Yong Zhou; yzhoumath@zjnu.edu.cn
Received 6 November 2012; Accepted 14 February 2013
Academic Editor: Giovanni P. Galdi
Copyright © 2013 Yong Zhou et al. This is an open access article distributed under the Creative Commons Attribution License,
which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.
The initial-boundary value problem for the density-dependent flow of nematic crystals is studied in a 2-D bounded smooth domain.
For the initial density away from vacuum, the existence and uniqueness is proved for the global strong solution with the large initial
velocity 𝑒0 and small ∇𝑑0 . We also give a regularity criterion ∇𝑑 ∈ 𝐿𝑝 (0, 𝑇; πΏπ‘ž (Ω)) ((2/π‘ž) + (2/𝑝) = 1, 2 < π‘ž ≤ ∞) of the problem
with the Dirichlet boundary condition 𝑒 = 0, 𝑑 = 𝑑0 on πœ•Ω.
1. Introduction and Main Results
Let Ω ⊆ R2 be a bounded domain with smooth boundary
πœ•Ω, and 𝜈 is the unit outward normal vector on πœ•Ω. We
consider the global strong solution to the density-dependent
incompressible liquid crystal flow [1–4] as follows:
div 𝑒 = 0,
(1)
πœ•π‘‘ 𝜌 + div (πœŒπ‘’) = 0,
When 𝑑 is a given constant unit vector, then (1), (2),
and (3) represent the well-known density-dependent NavierStokes system, which has received many studies; see [5–7] and
references therein.
When 𝜌 ≡ 1 and Ω := R2 , Xu and Zhang [8] proved
global existence of weak solutions to the problem if 𝑒0 ∈
𝐿2 , ∇𝑑0 ∈ 𝐿2 , |𝑑0 | = 1, and
1 2 σ΅„©
1
σ΅„©2
σ΅„© σ΅„©2
exp (216(󡄩󡄩󡄩𝑒0 󡄩󡄩󡄩𝐿2 + ) ) σ΅„©σ΅„©σ΅„©∇𝑑0 󡄩󡄩󡄩𝐿2 < .
16
16
When 𝜌 ≡ 1 and (6) is replaced by
(2)
πœ•π‘‘ (πœŒπ‘’) + div (πœŒπ‘’ ⊗ 𝑒) + ∇πœ‹ − Δ𝑒 = −∇ ⋅ (∇𝑑 βŠ™ ∇𝑑) , (3)
πœ•π‘‘ 𝑑 + 𝑒 ⋅ ∇𝑑 − Δ𝑑 = |∇𝑑|2 𝑑,
(4)
in (0, ∞) × Ω with initial and boundary conditions
(𝜌, 𝑒, 𝑑) (⋅, 0) = (𝜌0 , 𝑒0 , 𝑑0 )
𝑒 = 0,
πœ•πœˆ 𝑑 = 0
in Ω,
on πœ•Ω,
(5)
(6)
where 𝜌 denotes the density, 𝑒 the velocity, 𝑑 the unit vector
field that represents the macroscopic molecular orientations,
and πœ‹ the pressure. The symbol ∇𝑑 βŠ™ ∇𝑑 denotes a matrix
whose (𝑖, 𝑗)th entry is πœ•π‘– π‘‘πœ•π‘— 𝑑, and it is easy to find that ∇𝑑 βŠ™
∇𝑑 = ∇𝑑𝑇 ∇𝑑.
𝑒 = 0,
𝑑 = 𝑑0
on πœ•Ω.
(7)
(8)
Lin et al. [9] proved the global existence of weak solutions
to the system (1)–(5) and (8), which are smooth away from
at most finitely many singular times, and they also prove a
regularity criterion
𝑑 ∈ 𝐿2 (0, 𝑇; 𝐻2 (Ω)) .
(9)
When 𝜌 = 1 and the term |∇𝑑|2 in (4) is replaced by (1 −
|𝑑| )𝑑, then the problem has been studied in [10–15].
Very recently, Wen and Ding [16] proved the global existence and uniqueness of strong solutions to the problem (1)–
(6) with small 𝑒0 and ∇𝑑0 and the local strong solutions with
large initial data when Ω ⊆ R2 is a smooth bounded domain.
2
2
Abstract and Applied Analysis
Testing (3) by 𝑒 and using (1) and (2), we see that
Fan et al. [17] studied the regularity criterion of the
Cauchy problem (1)–(5) when Ω := R2 .
We will prove the following.
1 𝑑
∫ πœŒπ‘’2 𝑑π‘₯ + ∫ |∇𝑒|2 𝑑π‘₯ = − ∫ (𝑒 ⋅ ∇) 𝑑 ⋅ Δ𝑑 𝑑π‘₯.
2 𝑑𝑑
1,π‘Ÿ
Theorem 1. Let 0 < π‘š ≤ 𝜌0 ≤ 𝑀 < ∞, 𝜌0 ∈ π‘Š for some
π‘Ÿ ∈ (2, ∞), 𝑒0 ∈ 𝐻01 ∩ 𝐻2 , and 𝑑0 ∈ 𝐻3 with div 𝑒0 =0, and
|𝑑0 | = 1 in Ω. If
2
𝐢2 σ΅„©
1
1
σ΅„©σ΅„©
σ΅„©2
σ΅„©2
, (10)
σ΅„©σ΅„©∇𝑑0 󡄩󡄩󡄩𝐿2 exp [216 0 (σ΅„©σ΅„©σ΅„©√𝜌0 𝑒0 󡄩󡄩󡄩𝐿2 + 2 ) ] ≤
π‘š
8𝐢0
8𝐢02
with an absolute constant 𝐢0 in (22), then the problem (1)–(6)
has a unique global-in-time strong solution (𝜌, 𝑒, 𝑑) satisfying
σ΅„©σ΅„© σ΅„©σ΅„©
σ΅„©σ΅„©πœŒσ΅„©σ΅„©πΏ∞ (0,𝑇;π‘Š1,π‘Ÿ ) ≤ 𝐢,
σ΅„©σ΅„© σ΅„©σ΅„©
σ΅„©σ΅„©πœŒπ‘‘ 󡄩󡄩𝐿∞ (0,𝑇;πΏπ‘Ÿ ) ≤ 𝐢,
‖𝑒‖𝐿∞ (0,𝑇;𝐻2 )∩𝐿2 (0,𝑇;π‘Š2,𝑠 ) ≤ 𝐢,
π‘“π‘œπ‘Ÿπ‘ π‘œπ‘šπ‘’ 𝑠 > 2,
(11)
Testing (4) by −Δ𝑑 − |∇𝑑|2 𝑑, using |𝑑| = 1, we find that
1 𝑑
󡄨
󡄨2
∫ |∇𝑑|2 𝑑π‘₯ + ∫ 󡄨󡄨󡄨󡄨Δ𝑑 + |∇𝑑|2 𝑑󡄨󡄨󡄨󡄨 𝑑π‘₯ = ∫ (𝑒 ⋅ ∇) 𝑑 ⋅ Δ𝑑 𝑑π‘₯.
2 𝑑𝑑
(20)
Summing up (19) and (20) and integrating over (0, 𝑇), we
get
𝑇
󡄨
󡄨
∫ (πœŒπ‘’2 + |∇𝑑|2 ) 𝑑π‘₯ + 2 ∫ ∫ (|∇𝑒|2 + 󡄨󡄨󡄨󡄨Δ𝑑 + |∇𝑑|2 𝑑󡄨󡄨󡄨󡄨) 𝑑π‘₯ 𝑑𝑑
0
‖𝑑‖𝐿∞ (0,𝑇;𝐻3 ) ≤ 𝐢.
󡄨2
󡄨
≤ ∫ (𝜌0 𝑒02 + 󡄨󡄨󡄨∇𝑑0 󡄨󡄨󡄨 ) 𝑑π‘₯.
2
Remark 2. When Ω := R , Theorem 1 is also correct, thus
improving the result in [18], where 𝑒0 and ∇𝑑0 are assumed
to be small.
Next, we consider (1)–(4) with 𝜌 ≡ 1 as follows:
div 𝑒 = 0,
(12)
πœ•π‘‘ 𝑒 + 𝑒 ⋅ ∇𝑒 + ∇πœ‹ − Δ𝑒 = −∇ ⋅ (∇𝑑 βŠ™ ∇𝑑) ,
(13)
πœ•π‘‘ 𝑑 + 𝑒 ⋅ ∇𝑑 − Δ𝑑 = |∇𝑑|2 𝑑,
(14)
𝑒 = 0,
𝑑 = 𝑑0
on πœ•Ω,
(𝑒, 𝑑) (⋅, 0) = (𝑒0 , 𝑑0 )
in Ω.
(15)
(16)
We will prove the following.
Theorem 3. Let 𝑒0 ∈ 𝐿2 and 𝑑0 ∈ 𝐻1 with div 𝑒0 = 0 and
|𝑑0 | = 1 in Ω and 𝑑0 ∈ 𝐢2,𝛽 (πœ•Ω) for some 𝛽 ∈ (0, 1). If 𝑑
satisfies
∇𝑑 ∈ πΏπ‘ž (0, 𝑇; 𝐿𝑝 ) ,
2 2
+ = 1,
π‘ž 𝑝
2 < 𝑝 ≤ ∞,
(17)
then the strong solution (𝑒, 𝑑) can be extended beyond 𝑇 > 0.
Remark 4. In [9], the authors prove the regularity criterion
(9) for the problem (12)–(16), and our condition (17) is weaker
than (9). Moreover, (17) is scaling invariant for (12)–(14).
2. Proof of Theorem 1
This section is devoted to the proof of Theorem 1. Since the
local-in-time well-posedness has been proved in [16], we
only need to establish a priori estimates. Also, by the local
well-posedness result in [16], we note that ∇𝑑 is absolutely
continuous on [0, 𝑇] for any given 𝑇 > 0.
By the maximum principle, it follows from (1) and (2) that
0 < π‘š ≤ 𝜌 ≤ 𝑀 < ∞.
(18)
(19)
(21)
Since πœ•πœˆ 𝑑 = 0 on (0, ∞) × πœ•Ω, we have the following
Gagliardo-Nirenberg inequality:
β€–∇𝑑‖2𝐿4 ≤ 𝐢0 β€–∇𝑑‖𝐿2 β€–Δ𝑑‖𝐿2 .
(22)
By (20) and the Ladyzhenskaya inequality in 2D, we
derive
1 𝑑
󡄨
󡄨2
∫ |∇𝑑|2 𝑑π‘₯ + ∫ 󡄨󡄨󡄨󡄨Δ𝑑 + |∇𝑑|2 𝑑󡄨󡄨󡄨󡄨 𝑑π‘₯
2 𝑑𝑑
≤ ‖𝑒‖𝐿4 β€–∇𝑑‖𝐿4 β€–Δ𝑑‖𝐿2
≤ √2‖𝑒‖1/2
⋅ √𝐢0 β€–∇𝑑‖1/2
β€–∇𝑒‖1/2
β€–Δ𝑑‖3/2
𝐿2
𝐿2
𝐿2
𝐿2
≤
β€–Δ𝑑‖2𝐿2
+ 216𝐢02 ‖𝑒‖2𝐿2 β€–∇𝑒‖2𝐿2 β€–∇𝑑‖2𝐿2
8
≤
𝐢2 σ΅„©
β€–Δ𝑑‖2𝐿2
σ΅„©2 σ΅„©
σ΅„©2
+ 216 0 (σ΅„©σ΅„©σ΅„©√𝜌0 𝑒0 󡄩󡄩󡄩𝐿2 + σ΅„©σ΅„©σ΅„©∇𝑑0 󡄩󡄩󡄩𝐿2 ) β€–∇𝑒‖2𝐿2 β€–∇𝑑‖2𝐿2 .
8
π‘š
(23)
On the other hand, since (π‘Ž + 𝑏)2 ≥ (π‘Ž2 /2) − 𝑏2 , we have
β€–Δ𝑑‖2𝐿2
󡄨2
󡄨
− β€–∇𝑑‖4𝐿4
∫ 󡄨󡄨󡄨󡄨Δ𝑑 + |∇𝑑|2 𝑑󡄨󡄨󡄨󡄨 𝑑π‘₯ ≥
2
β€–Δ𝑑‖2𝐿2
≥
− 𝐢02 β€–∇𝑑‖2𝐿2 β€–Δ𝑑‖2𝐿2 .
2
(24)
If the initial data β€–∇𝑑0 β€–2𝐿2 < (1/𝐢02 )(1/8), then there exists
𝑇1 > 0 such that for any 𝑑 ∈ [0, 𝑇1 ],
β€–∇𝑑 (𝑑)β€–2𝐿2 ≤
1 1
⋅ .
𝐢02 4
(25)
Abstract and Applied Analysis
3
We denote by 𝑇1∗ the maximal time such that (25) holds
on [0, 𝑇1∗ ]. Therefore, by (23), (24), and (25), it follows that for
any 𝑑 ∈ [0, 𝑇1∗ ],
𝑑
1
∫ |∇𝑑|2 𝑑π‘₯ + β€–Δ𝑑‖2𝐿2
𝑑𝑑
4
≤ 432
≤ 432
𝐢02
σ΅„©2 σ΅„©
σ΅„©2
σ΅„©
(σ΅„©σ΅„©√𝜌 𝑒 σ΅„©σ΅„© 2 + σ΅„©σ΅„©∇𝑑 σ΅„©σ΅„© 2 ) β€–∇𝑒‖2𝐿2 β€–∇𝑑‖2𝐿2
π‘š σ΅„© 0 0 󡄩𝐿 σ΅„© 0 󡄩𝐿
(26)
𝐢02 σ΅„©σ΅„©
1
σ΅„©2
(σ΅„©σ΅„©√𝜌0 𝑒0 󡄩󡄩󡄩𝐿2 + 2 ) β€–∇𝑒‖2𝐿2 β€–∇𝑑‖2𝐿2 ,
π‘š
8𝐢0
σ΅„© σ΅„©
β€–Δ𝑒‖𝐿2 ≤ 𝐢󡄩󡄩󡄩𝑓󡄩󡄩󡄩𝐿2
σ΅„©
σ΅„©
≤ 𝐢󡄩󡄩󡄩√πœŒπ‘’π‘‘ 󡄩󡄩󡄩𝐿2 + 𝐢‖𝑒‖𝐿4 β€–∇𝑒‖𝐿4 + 𝐢‖∇𝑑‖𝐿4 β€–Δ𝑑‖𝐿4
σ΅„©
σ΅„©
≤ 𝐢󡄩󡄩󡄩√πœŒπ‘’π‘‘ 󡄩󡄩󡄩𝐿2 + 𝐢‖∇𝑒‖𝐿2 β€–Δ𝑒‖1/2
+ 𝐢‖∇𝑒‖𝐿2
𝐿2
+ 𝐢‖Δ𝑑‖𝐿2 β€–∇Δ𝑑‖1/2
+ 𝐢‖Δ𝑑‖𝐿2 ,
𝐿2
σ΅„©
σ΅„©
β€–Δ𝑒‖𝐿2 ≤ 𝐢󡄩󡄩󡄩√πœŒπ‘’π‘‘ 󡄩󡄩󡄩𝐿2 + 𝐢‖∇𝑒‖2𝐿2 + 𝐢
1 𝑑
∫ β€–Δ𝑑(𝜏)β€–2𝐿2 π‘‘πœ
4 0
+ 𝐢‖Δ𝑑‖𝐿2 β€–∇Δ𝑑‖1/2
+ 𝐢‖Δ𝑑‖𝐿2 .
𝐿2
2
×∫
0
β€–∇𝑒‖2𝐿2 π‘‘πœ]
(27)
2
2
𝐢 σ΅„©
1
σ΅„©
σ΅„©2
σ΅„©2
≤ σ΅„©σ΅„©σ΅„©∇𝑑0 󡄩󡄩󡄩𝐿2 exp [216 0 (σ΅„©σ΅„©σ΅„©√𝜌0 𝑒0 󡄩󡄩󡄩𝐿2 + 2 ) ]
π‘š
8𝐢0
1 𝑑
∫ |∇𝑒|2 𝑑π‘₯ + ∫ πœŒπ‘’π‘‘2 𝑑π‘₯
2 𝑑𝑑
σ΅„©3/2
σ΅„©
σ΅„©
σ΅„©
≤ 𝐢󡄩󡄩󡄩√πœŒπ‘’π‘‘ 󡄩󡄩󡄩𝐿2 β€–∇𝑒‖𝐿2 + 𝐢󡄩󡄩󡄩√πœŒπ‘’π‘‘ 󡄩󡄩󡄩𝐿2 (β€–∇𝑒‖2𝐿2 + β€–∇𝑒‖𝐿2 )
σ΅„©
σ΅„©
σ΅„©
σ΅„©
+ 𝐢󡄩󡄩󡄩√πœŒπ‘’π‘‘ 󡄩󡄩󡄩𝐿2 β€–Δ𝑑‖𝐿2
+ 𝐢󡄩󡄩󡄩√πœŒπ‘’π‘‘ 󡄩󡄩󡄩𝐿2 β€–Δ𝑑‖𝐿2 β€–∇Δ𝑑‖1/2
𝐿2
1σ΅„©
1
σ΅„©2
≤ σ΅„©σ΅„©σ΅„©√πœŒπ‘’π‘‘ 󡄩󡄩󡄩𝐿2 + 𝐢‖∇𝑒‖4𝐿2 + 𝐢 + β€–∇Δ𝑑‖2𝐿2 + 𝐢‖Δ𝑑‖4𝐿2 .
8
8
(33)
1
≤
,
8𝐢02
which implies that 𝑇1∗ = 𝑇 if the initial data satisfies
2
2
𝐢 σ΅„©
1
1
σ΅„©σ΅„©
σ΅„©2
σ΅„©2
. (28)
σ΅„©σ΅„©∇𝑑0 󡄩󡄩󡄩𝐿2 exp [216 0 (σ΅„©σ΅„©σ΅„©√𝜌0 𝑒0 󡄩󡄩󡄩𝐿2 + 2 ) ] ≤
π‘š
8𝐢0
8𝐢02
Let 𝑇∗ be a maximal existence time for the solution
(𝜌, 𝑒, 𝑑). Then, (18), (21), and (27) ensure that 𝑇∗ = ∞ by
continuity argument.
Testing (3) by 𝑒𝑑 , using (1), (18), (21), (22), |𝑑| = 1, and the
Gagliardo-Nirenberg inequalities, we obtain
Applying Δ to (4), testing by Δ𝑑, using |𝑑| = 1, (21) and
(22), and the Gagliardo-Nirenberg inequalities, we have
1 𝑑
∫ |Δ𝑑|2 𝑑π‘₯ + ∫ |∇Δ𝑑|2 𝑑π‘₯
2 𝑑𝑑
󡄨
󡄨
≤ ∫ 󡄨󡄨󡄨󡄨∇ (|∇𝑑|2 𝑑)󡄨󡄨󡄨󡄨 |∇Δ𝑑| 𝑑π‘₯ + ∫ |∇ (𝑒 ⋅ ∇𝑑)| |∇Δ𝑑| 𝑑π‘₯
≤ 𝐢 (β€–∇𝑑‖3𝐿6 + β€–∇𝑑‖𝐿4 β€–Δ𝑑‖𝐿4 + ‖𝑒‖𝐿4 β€–Δ𝑑‖𝐿4
+β€–∇𝑒‖𝐿2 β€–∇𝑑‖𝐿∞ ) β€–∇Δ𝑑‖𝐿2
1 𝑑
∫ |∇𝑒|2 𝑑π‘₯ + ∫ πœŒπ‘’π‘‘2 𝑑π‘₯
2 𝑑𝑑
≤ 𝐢 (β€–∇𝑑‖𝐿2 β€–Δ𝑑‖2𝐿2 + β€–Δ𝑑‖𝐿2 β€–∇Δ𝑑‖1/2
+ β€–Δ𝑑‖𝐿2
𝐿2
= − ∫ πœŒπ‘’ ⋅ ∇𝑒 ⋅ 𝑒𝑑 𝑑π‘₯ − ∫ 𝑒𝑑 ⋅ ∇𝑑 ⋅ Δ𝑑 𝑑π‘₯
+ β€–∇𝑒‖1/2
β€–Δ𝑑‖1/2
β€–∇Δ𝑑‖1/2
𝐿2
𝐿2
𝐿2
σ΅„©
σ΅„©
≤ 𝐢󡄩󡄩󡄩√πœŒπ‘’π‘‘ 󡄩󡄩󡄩𝐿2 (‖𝑒‖𝐿4 β€–∇𝑒‖𝐿4 + β€–∇𝑑‖𝐿4 β€–Δ𝑑‖𝐿4 )
+ β€–∇𝑒‖1/2
+ β€–∇𝑒‖𝐿2
β€–Δ𝑑‖1/2
𝐿2
𝐿2
× β€–∇𝑑‖1/2
) β€–∇Δ𝑑‖𝐿2
β€–∇Δ𝑑‖1/2
𝐿2
𝐿2
σ΅„©
σ΅„©
+ ‖𝑒‖1/2
)
≤ 𝐢󡄩󡄩󡄩√πœŒπ‘’π‘‘ 󡄩󡄩󡄩𝐿2 [‖𝑒‖1/2
β€–∇𝑒‖𝐿2 (β€–Δ𝑒‖1/2
𝐿2
𝐿2
𝐿2
+ ‖𝑑‖1/2
)]
+ β€–∇𝑑‖1/2
β€–Δ𝑑‖𝐿2 (β€–∇Δ𝑑‖1/2
𝐿2
𝐿2
𝐿2
σ΅„©
σ΅„©
+ β€–∇𝑒‖𝐿2 + β€–Δ𝑑‖𝐿2
≤ 𝐢󡄩󡄩󡄩√πœŒπ‘’π‘‘ 󡄩󡄩󡄩𝐿2 (β€–∇𝑒‖𝐿2 β€–Δ𝑒‖1/2
𝐿2
× β€–∇Δ𝑑‖1/2
+ β€–Δ𝑑‖𝐿2 ) .
𝐿2
1
≤ β€–∇Δ𝑑‖2𝐿2 + 𝐢‖Δ𝑑‖4𝐿2 + 𝐢 + 𝐢‖∇𝑒‖4𝐿2 .
8
(34)
Here, we have used the Gagliardo-Nirenberg inequalities
(29)
β€–∇𝑑‖3𝐿6 ≤ 𝐢‖∇𝑑‖𝐿2 β€–Δ𝑑‖2𝐿2 ,
β€–∇𝑑‖2𝐿∞ ≤ β€–∇𝑑‖𝐿2 β€–∇Δ𝑑‖𝐿2 ,
On the other hand, (3) can be rewritten as
−Δ𝑒 + ∇πœ‹ = 𝑓 := −πœŒπ‘’π‘‘ − πœŒπ‘’ ⋅ ∇𝑒 − ∇ ⋅ (∇𝑑 βŠ™ ∇𝑑) .
(32)
Inserting (32) into (29), we deduce that
𝐢 σ΅„©
1
σ΅„©2
σ΅„©2
σ΅„©
≤ σ΅„©σ΅„©σ΅„©∇𝑑0 󡄩󡄩󡄩𝐿2 exp [432 0 (σ΅„©σ΅„©σ΅„©√𝜌0 𝑒0 󡄩󡄩󡄩𝐿2 + 2 )
π‘š
8𝐢0
𝑇1∗
(31)
which yields
which gives
β€–∇𝑑 (𝑑)β€–2𝐿2 +
By the 𝐻2 -theory of Stokes system, we have
(30)
β€–Δ𝑑‖2𝐿4 ≤ 𝐢‖Δ𝑑‖𝐿2 β€–∇Δ𝑑‖𝐿2 + 𝐢‖Δ𝑑‖𝐿2 .
(35)
4
Abstract and Applied Analysis
Combining (33) and (34) and using the Gronwall inequality, we have
‖𝑒‖𝐿∞ (0,𝑇;𝐻1 ) + ‖𝑒‖𝐿2 (0,𝑇;𝐻2 ) ≤ 𝐢,
σ΅„©σ΅„©σ΅„©√πœŒπ‘’π‘‘ σ΅„©σ΅„©σ΅„© 2
σ΅„©
󡄩𝐿 (0,𝑇;𝐿2 ) ≤ 𝐢,
(36)
‖𝑑‖𝐿∞ (0,𝑇;𝐻2 ) + ‖𝑑‖𝐿2 (0,𝑇;𝐻3 ) ≤ 𝐢.
(38)
(37)
Now, by the similar calculations as those in [17], we arrive
at
σ΅„©σ΅„©
σ΅„©
σ΅„©σ΅„©(𝑒𝑑 , ∇𝑑𝑑 )󡄩󡄩󡄩𝐿∞ (0,𝑇;𝐿2 )∩𝐿2 (0,𝑇;𝐻1 ) ≤ 𝐢,
β€–(𝑒, ∇𝑑)‖𝐿∞ (0,𝑇;𝐻2 ) ≤ 𝐢,
‖𝑒‖𝐿2 (0,𝑇;π‘Š2,𝑠 ) ≤ 𝐢 for some 𝑠 > 2,
σ΅„©σ΅„© σ΅„©σ΅„©
σ΅„©σ΅„© σ΅„©σ΅„©
σ΅„©σ΅„©πœŒπ‘‘ 󡄩󡄩𝐿∞ (0,𝑇;πΏπ‘Ÿ ) ≤ 𝐢.
σ΅„©σ΅„©πœŒσ΅„©σ΅„©πΏ∞ (0,𝑇;π‘Š1,π‘Ÿ ) ≤ 𝐢,
(39)
This completes the proof.
3. Proof of Theorem 3
This section is devoted to the proof of Theorem 3. By the
results in [9], we only need to prove (9).
Similar to (21), we still have
𝑇
󡄨
󡄨
∫ (𝑒2 + |∇𝑑|2 ) 𝑑π‘₯ + 2 ∫ ∫ (|∇𝑒|2 + 󡄨󡄨󡄨󡄨Δ𝑑 + |∇𝑑|2 𝑑󡄨󡄨󡄨󡄨) 𝑑π‘₯ 𝑑𝑑
0
≤
∫ (𝑒02
󡄨2
󡄨
+ 󡄨󡄨󡄨∇𝑑0 󡄨󡄨󡄨 ) 𝑑π‘₯.
(40)
We will use the following Gagliardo-Nirenberg inequalities:
1−(2/𝑝)
‖𝑒‖𝐿2𝑝/(𝑝−2) ≤ 𝐢‖𝑒‖𝐿2
1−(2/𝑝)
β€–∇𝑑‖𝐿2𝑝/(𝑝−2) ≤ 𝐢‖∇𝑑‖𝐿2
2/𝑝
β€–∇𝑒‖𝐿2 ,
2/𝑝
β€–Δ𝑑‖𝐿2 + 𝐢‖∇𝑑‖𝐿2 .
(41)
(42)
Testing (14) by −Δ𝑑, using |𝑑| = 1, (40), (41), and (42), we
have
1 𝑑
∫ |∇𝑑|2 𝑑π‘₯ + ∫ |Δ𝑑|2 𝑑π‘₯
2 𝑑𝑑
= ∫ (𝑒 ⋅ ∇𝑑 − |∇𝑑|2 𝑑) Δ𝑑 𝑑π‘₯
≤ (‖𝑒‖𝐿2𝑝/(𝑝−2) β€–∇𝑑‖𝐿𝑝 + β€–∇𝑑‖𝐿𝑝 β€–∇𝑑‖𝐿2𝑝/(𝑝−2) ) β€–Δ𝑑‖𝐿2
1−(2/𝑝)
≤ 𝐢‖∇𝑑‖𝐿𝑝 (‖𝑒‖𝐿2
2/𝑝
β€–∇𝑒‖𝐿2 + β€–∇𝑑‖𝐿2
1−(2/𝑝)
+ β€–∇𝑑‖𝐿2
2/𝑝
2/𝑝
β€–Δ𝑑‖𝐿2 ) β€–Δ𝑑‖𝐿2
2/𝑝
≤ 𝐢‖∇𝑑‖𝐿𝑝 (β€–∇𝑒‖𝐿2 + 1 + β€–Δ𝑑‖𝐿2 ) β€–Δ𝑑‖𝐿2
1
4/𝑝
4/𝑝
≤ β€–Δ𝑑‖2𝐿2 + 𝐢‖∇𝑑‖2𝐿𝑝 (β€–∇𝑒‖𝐿2 + 1 + β€–Δ𝑑‖𝐿2 )
4
1
2𝑝/(𝑝−2)
≤ β€–Δ𝑑‖2𝐿2 + β€–∇𝑒‖2𝐿2 + 𝐢‖∇𝑑‖𝐿𝑝
+ 𝐢,
2
which gives (9).
This completes the proof.
(43)
Acknowledgments
The authors would like to thank the referees for careful reading and helpful suggestions. This work is partially supported
by the Zhejiang Innovation Project (Grant no. T200905),
the ZJNSF (Grant no. R6090109), and the NSFC (Grant no.
11171154).
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