Hindawi Publishing Corporation Abstract and Applied Analysis Volume 2013, Article ID 943209, 6 pages http://dx.doi.org/10.1155/2013/943209 Research Article Growth of Meromorphic Solutions of Some π-Difference Equations Guowei Zhang School of Mathematics and Statistics, Anyang Normal University, Anyang, Henan 455000, China Correspondence should be addressed to Guowei Zhang; zhirobo@gmail.com Received 10 November 2012; Revised 6 January 2013; Accepted 17 January 2013 Academic Editor: Jesus Vigo-Aguiar Copyright © 2013 Guowei Zhang. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited. We estimate the growth of the meromorphic solutions of some complex π-difference equations and investigate the convergence exponents of fixed points and zeros of the transcendental solutions of the second order π-difference equation. We also obtain a theorem about the π-difference equation mixing with difference. 1. Introduction and Main Results In this paper, we mainly use the basic notation of Nevanlinna Theory, such as π(π, π), π(π, π), and π(π, π), and the notation π(π, π) is defined to be any quantity satisfying π(π, π) = π(π(π, π)) as π → ∞ possibly outside a set of π of finite linear measure (see [1–3]). In addition, we use the notation π(π) to denote the order of growth of the meromorphic function π(π§) and π(π) to denote the exponent of convergence of the zeros. We also use the notation π(π) to denote the exponent of convergence of fixed points of π. We give the definition of π(π) as following. Definition 1. Let π be a nonconstant meromorphic function. The exponent of convergence of fixed points of π is defined by π (π) = lim sup π→∞ log π (π, 1/ (π − π§)) . log π and Bergweiler et al. [10] studied the following functional equation π ∑ππ (π§) π (ππ π§) = π(π§) , (2) π=0 where π(0 < |π| < 1) is a complex number and ππ (π§), π = 0, 1, . . . , π and π(π§) are rational functions, and π0 (π§) ≡ΜΈ 0, ππ (π§) ≡ 1. They obtained the following two theorems. Theorem A. All meromorphic solutions of (2) satisfy π(π, π) = π((log π)2 ). Theorem B. All transcendental meromorphic solutions of (2) satisfy (log π)2 = π(π(π, π)). What will happen if the right-hand side of (2) is a rational function in π? That is, for the functional equation (1) Recently, a number of papers focused on complex difference equations, such as [4–6] and on difference analogues of Nevanlinna’s theory, such as [7, 8]. Correspondingly, there are many papers focused on the π-difference (or π-difference) equations, such as [9–14]. Because of the intimate relations between iteration theory and the functional equations of SchroΜder, BoΜttcher and Abel π ∑πΎπ (π§) π (ππ π§) = π (π§, π (π§)) = π=1 ∑π π=0 πΌπ (π§) ππ (π§) ∑π‘π=0 π½π (π§) ππ (π§) , (3) where π (0 < |π| < 1) is a complex number, πΌπ (π§) (π = 0, 1, . . . , π ), πΌπ (π§) ≡ΜΈ 0, π½π (π§) (π = 0, 1, . . . , π‘), π½π‘ (π§) ≡ΜΈ 0, πΎπ (π§) (π = 0, 1, . . . , π), and πΎπ = 1 are coefficients, and π (π§, π) is irreducible in π. Gundersen et al. [12] studied the case that π = 1 on the left-hand side of (3). Following the results in [12], we continue to study the properties of the solutions of (3) in 2 Abstract and Applied Analysis the case of π > 1 on the left-hand side. In fact, we obtain the following theorem. Theorem 2. Suppose that π is a nonconstant meromorphic solution of equation of (3) and the coefficients are small functions of π. Then, π = max{π , π‘} ≤ π and π(π) ≤ log(π/π)/(− log |π|). In particular, we concern the second-order π-difference equation with rational coefficients, that is, in the case of π = 2. From Theorem 2, we know that if π is a nonconstant meromorphic solution, then π ≤ 2. Thus, the second-order π-difference equation is the following form: π (π2 π§) + πΎ1 (π§) π (ππ§) πΌ (π§) + πΌ1 (π§) π (π§) + πΌ2 (π§) π2 (π§) . = 0 π½0 (π§) + π½1 (π§) π (π§) + π½2 (π§) π2 (π§) (4) First of all, we give some remarks. Remark 3. If πΌ2 (π§) and π½2 (π§) are not zero at the same time, by Theorem 2, we derive that the solution of (4) is of order zero. Remark 4. If πΌ2 (π§) = π½2 (π§) = π½1 (π§) ≡ 0, by Theorem A, the solutions of (4) is also of order zero. Remark 5. If πΌ2 (π§) = π½2 (π§) = 0, π½1 (π§) =ΜΈ 0, by Theorem 2, the order of the solutions is less than log(2)/(− log |π|). Thus, a question arises: does the equation have a solution which is of order nonzero under this situation? This question is still open. In [6], Chen and Shon proved some theorems about the properties of solutions of the difference PainleveΜ I and II equations, such as the exponents of convergence of fixed points and the zeros of transcendental solutions. A natural question arises: how about the exponents of convergence of the fixed points and the zeros of transcendental solutions of the π-difference equation (4)? Do the transcendental solutions have infinitely many fixed points and zeros? The following theorem, in which the coefficients are constants, answers the above questions partly. Theorem 6. Suppose that π is a transcendental solution of the equation π (π2 π§) + πΎ1 π (ππ§) = πΌ0 + πΌ1 π (π§) + πΌ2 π2 (π§) , π½0 + π½1 π (π§) + π½2 π2 (π§) Theorem C. Suppose that π is a transcendental solution of equation π ∑ ππ (π§) π (ππ π§) = π (π§, π (π§)) = π=1 In the rest of the paper, we consider (3) when |π| > 1. In [15], Heittokangas et al. considered the essential growth problem for transcendental meromorphic solutions of complex difference equations, which is to find lower bounds for their characteristic functions. Following this idea, Zheng and Chen [14] obtained the following theorem for π-difference equations. (6) where π ∈ C, |π| > 1, the coefficients ππ (π§) are rational functions, and π, π are relatively prime polynomials in π over the field of rational functions satisfying π = degπ π, π‘ = degπ π, and π = π − π‘ ≥ 2. If π has infinitely many poles, then for sufficiently large π, π(π, π) ≥ πΎπlog π/(π log |π|) holds for some constant πΎ > 0. Thus, the lower order of π, which has infinitely many poles, satisfies π(π) ≥ log π/(π log |π|). Regarding Theorem C, they obtained the lower bound of the order of solutions. Then, how about the upper bound of the order of the solutions? Can the conditions of Theorem C become a little more simple? In fact, we have the following theorem. Theorem 7. Suppose that π is a transcendental solution of (3), where |π| > 1, π < π = max{π , π‘} and the coefficients are rational functions. Then, log(π/π)/(π log |π|) ≤ π(π) ≤ log(π + π − 1)/(log |π|). We know that the difference analogues and π-difference analogues of Nevanlinna’s theory have been investigated. Consequently, many results on the complex difference equations and π-difference equations have been obtained respectively. Thus, mixing the difference and π-difference equations together is a natural idea. The following Theorem 8 is just a simple application of the above idea, and further investigation is required. In what follows, we will consider difference products and difference polynomials. By a difference product, we mean a difference monomial, that is, an expression of type π ππ ∏π(π§ + ππ ) , π (7) where π1 , . . . , ππ are complex numbers and π1 , . . . , ππ are natural numbers. A difference polynomial is a finite sum of difference products, that is, an expression of the form (5) where |π| < 1, the coefficients πΎ1 , πΌ0 , πΌ1 , πΌ2 , π½0 , π½1 , and π½2 are constants, and at least one of πΌ2 , π½2 is nonzero. Then, π(π) = 0 and (i)π has infinitely many fixed points, and (ii)π has infinitely many zeros, whenever πΌ0 =ΜΈ 0. π (π§, π (π§)) , π (π§, π (π§)) π (π§, π) = ∑ππ½ (π§) (∏π (π§ + ππ )) , (8) π∈π½ {π½} where ππ (π ∈ π½) is a set of distinct complex numbers and the coefficients ππ½ (π§) of difference polynomials are small functions as understood in the usual the Nevanlinna theory; that is, their characteristic is of type π(π, π). Theorem 8. Suppose that π is a nonconstant meromorphic solution of the equation π ∑ππ (π§) π (ππ π§) = ∑ππ½ (π§) (∏π (π§ + ππ )) , π=1 {π½} π∈π½ (9) Abstract and Applied Analysis 3 where |π| > 1 and the index set π½ consists of π elements and the coefficients ππ (π§) (ππ (π§) = 1) and ππ½ (π§) are small functions of π. If π is of finite order, then |π| < π + π − 1. function such that π(π, πΌ) = π(π(π, π)) on a set of logarithmic density 1, and in particular, πΌ is a constant, then π (π, 2. Some Lemmas The following important result by Valiron and Mohon’ko will be used frequently, one can find the proof in Laine’s book [16, page 29]. Lemma 9. Let π be a meromorphic function. Then, for all irreducible rational function in π, π π (π§, π (π§)) = ∑π=0 ππ (π§) π(π§)π π ∑π=0 ππ (π§) π(π§) π , (10) with meromorphic coefficients ππ (π§), ππ (π§), the characteristic function of π (π§, π(π§)) satisfies π (π, π (π§, π (π§))) = ππ (π, π) + π (Ψ (π)) , (11) where π = max{π, π} and Ψ(π) = max {π (π, ππ ) , π (π, ππ )} . π,π (12) 1 ) = π (π (π, π)) , π−πΌ on a set of logarithmic density 1. Lemma 13 (see [7]). Let π be a meromorphic function of finite order, and let π be a nonzero complex constant. Then one has π (π, π (π§) π (π§ + π) ) + π (π, ) = π (π, π) . π (π§) π (π§ + π) π (π, ππ ) = π (π, π) , π = 0, 1, . . . , π, π (π, ππ ) = π (π, π) , π = 0, 1, . . . , π, (13) (19) Lemma 14 (see [7]). Let π be a meromorphic function of finite order π, and let π is a nonzero complex constant. Then, for each π > 0, one has π (π, π (π§ + π)) = π (π, π) + π (ππ−1+π ) + π (log π) . (20) It is evident that π(π, π(π§ + π)) = π(π, π) from Lemma 14. By (7), (8), and Lemmas 13 and 14, Laine and Yang obtained the following lemma in [13]. Lemma 15. The characteristic function of a difference polynomial π(π§, π) in (8) satisfies π (π, π (π§, π)) ≤ ππ (π, π) + π (ππ−1+π ) + π (π, π) , In the particular case when (18) (21) provided that f is a meromorphic function of finite order π and the index set π½ consists of n elements. One has π(π, π (π§, π(π§))) = ππ(π, π) + π(π, π). 3. Proof of Theorems The next lemma on the relationship between π(π, π(ππ§)) and π(|π|π, π(π§)) is due to Bergweiler et al. [10, page 2]. Proof of Theorem 2. Set Φ(π) = maxπ,π,π {π(π, πΌπ (π§)), π(π, π½π (π§)), π(π, πΎπ (π§))} = π(π, π). From (3) and Lemmas 9 and 10 and noting 0 < |π| < 1, we immediately obtain Lemma 10. One case see that σ΅¨ σ΅¨ π (π, π (ππ§)) = π (σ΅¨σ΅¨σ΅¨πσ΅¨σ΅¨σ΅¨ π, π) + π (1) π (π, π (π§, π (π§))) = ππ (π, π) + π (Φ (π)) (14) π = π (π, ∑πΎπ (π§) π (ππ π§)) holds for any meromorphic function π and any constant π. π=1 Lemma 11 (see [12]). Let Φ : (1, ∞) → (0, ∞) be a monotone increasing function, and let π be a nonconstant meromorphic function. If for some real constant πΌ ∈ (0, 1), there exist real constants πΎ1 > 0 and πΎ2 ≥ 1 such that π (π, π) ≤ πΎ1 Φ (πΌπ) + πΎ2 π (πΌπ, π) + π (πΌπ, π) , σ΅¨ σ΅¨ ≤ ππ (σ΅¨σ΅¨σ΅¨πσ΅¨σ΅¨σ΅¨ π, π) + π (π, π) ≤ ππ (π, π) + π (π, π) , and so we have π ≤ π. From (22), we have (16) Lemma 12 (see [9, Theorem 2.2]). Let π(π§) be a nonconstant zero-order meromorphic solution of π (π§, π) = 0, (22) π=1 (15) then log πΎ2 log Φ (π) π (π) ≤ + lim sup . − log πΌ log π π→∞ π σ΅¨ σ΅¨π ≤ ∑π (σ΅¨σ΅¨σ΅¨πσ΅¨σ΅¨σ΅¨ π, π) + π (Φ (π)) (17) where π(π§, π) is a c-difference (or π-difference) equation in π(π§). If π(π§, πΌ) ≡ΜΈ 0, where πΌ is a zero-order meromorphic π (π, π) ≤ π σ΅¨σ΅¨ σ΅¨σ΅¨ π (σ΅¨πσ΅¨ π, π) + π (π, π) . π σ΅¨ σ΅¨ (23) Since π(π, π) = π(π(π, π)), we have π (π, π) ≤ π σ΅¨ σ΅¨ π (σ΅¨σ΅¨πσ΅¨σ΅¨ π, π) , π (1 − π) σ΅¨ σ΅¨ (24) for each π. From (24) and Lemma 11, we have π(π) ≤ log(π/π)/(− log |π|). 4 Abstract and Applied Analysis Proof of Theorem 6. Assume that π(π§) is a transcendental solution of (5). Since at least one of πΌ2 , π½2 is non-zero, by Remark 3, we obtain that π(π) = 0. (I) Set π(π§) = π(π§) − π§. Substituting π(π§) = π(π§) + π§ into (5), we obtain that 2 2 π (π π§) + πΎ1 π (ππ§) + π π§ + πΎ1 ππ§ 2 = πΌ0 + πΌ1 π (π§) + πΌ1 π§ + πΌ2 (π (π§) + π§) 2 π½0 + π½1 π (π§) + π½1 π§ + π½2 (π (π§) + π§) on a set of logarithmic density 1. Thus, π (π, π (π) = π (π) . (25) . π (ππ π§) = π1 (π§, π (π§)) := (π (π π§) + πΎ1 π (ππ§) + π π§ + πΎ1 ππ§) 2 × (π½0 + π½1 π (π§) + π½1 π§ + π½2 (π (π§) + π§) ) 2 − πΌ0 + πΌ1 π (π§) + πΌ1 π§ + πΌ2 (π (π§) + π§) . ∑π π=0 πΌπ (π§) ππ (π§) ∑π‘π=0 π½π (π§) ππ (π§) π−1 − ∑ πΎπ (π§) π (ππ π§) . By the properties of the Nevanlinna characteristic function and Lemma 9, we have π (π, π (ππ π§)) ≤ ππ (π, π) + ∑ π (π, πΎπ (π§) π (ππ π§)) π=1 By (26), we see that + [(π + ππΎ1 ) π½0 − πΌ1 ] π§ − πΌ0 . (27) (28) on a set of logarithmic density 1. Thus, 1 1 π (π, ) = π (π, ) = (1 − π (1)) π (π, π) , π−π§ π π−1 σ΅¨ σ΅¨π + ∑ π (σ΅¨σ΅¨σ΅¨πσ΅¨σ΅¨σ΅¨ π, π (π§)) + π (log π) π=1 σ΅¨ σ΅¨π−1 + π (logσ΅¨σ΅¨σ΅¨πσ΅¨σ΅¨σ΅¨ π) . Setting πΌ = 1/|π|, π = |π|π π, we have π(π , π (π§)) ≤ (π + π − 1) π (πΌπ , π(π§)) + π(log πΌπ ) . (39) (30) π (π) ≤ log(π + π − 1) . σ΅¨ σ΅¨ logσ΅¨σ΅¨σ΅¨πσ΅¨σ΅¨σ΅¨ π2 (π§, π) := [π (π2 π§) + πΎ1 π (ππ§)] [π½0 + π½1 π (π§) + π½2 π2 (π§)] 2 − [πΌ0 + πΌ1 π (π§) + πΌ2 π (π§)] . (31) By (31) and the assumption πΌ0 =ΜΈ 0, we obtain that (32) By Lemma 12 and (32), we have 1 ) = π (π (π, π)) , π π π=1 By Lemma 10 and noting |π| > 1, we obtain σ΅¨ σ΅¨π π (σ΅¨σ΅¨σ΅¨πσ΅¨σ΅¨σ΅¨ π, π) ≥ ππ (π, π) + π (π) , (41) (42) where π = π/π and |π(π)| < πΎ log π for some πΎ and all π greater than some π0 . Hence, for π > π0 , σ΅¨ σ΅¨ππ σ΅¨ σ΅¨π(π−1) σ΅¨ σ΅¨π(π−1) π (σ΅¨σ΅¨σ΅¨πσ΅¨σ΅¨σ΅¨ π, π) ≥ ππ (σ΅¨σ΅¨σ΅¨πσ΅¨σ΅¨σ΅¨ π, π) + π (σ΅¨σ΅¨σ΅¨πσ΅¨σ΅¨σ΅¨ π) ≥ ⋅⋅⋅ (33) (40) We now prove the lower bound of the order of the solutions. From (3), by the properties of the Nevanlinna characteristic function and Lemma 9, we have ∑ π (π, π (ππ π§)) ≥ ππ (π, π) + π (log π) . π2 (π§, 0) := πΌ0 ≡ΜΈ 0. (38) σ΅¨ σ΅¨π−1 ≤ (π + π − 1) π (σ΅¨σ΅¨σ΅¨πσ΅¨σ΅¨σ΅¨ π, π (π§)) (29) (II) By (5), we derive that π (π, By |π| > 1 and Lemma 10, we obtain σ΅¨ σ΅¨π π (σ΅¨σ΅¨σ΅¨πσ΅¨σ΅¨σ΅¨ π, π (π§)) ≤ ππ (π, π (π§)) Applying Lemma 11 to (39) yields on a set of logarithmic density 1. Hence, by (29), π has infinitely many fixed points and π (π) = π (π) = π (π) . (37) + π (log π) . Suppose that π1 (π§, 0) ≡ 0, and we split into two cases. If π2 + ππΎ1 = 0, then we obtain πΌ0 = πΌ1 = πΌ2 = 0. Thus, the right-hand side of (5) is vanishing. This contradicts to our assumption. If π2 + ππΎ1 =ΜΈ 0, we obtain πΌ0 = π½2 = 0 and πΌ2 /π½1 = πΌ1 /π½0 = π2 + ππΎ1 . Then, the right-hand side of (5) becomes (π2 + ππΎ1 )π; this also contradicts to our assumption. Thus, we have π1 (π§, 0) ≡ΜΈ 0. By Lemma 12, we obtain that 1 π (π, ) = π (π (π, π)) , π (36) π=1 π−1 (26) 2 (35) Proof of Theorem 7. From (3), we have 2 π1 (π§, 0) = (π2 + ππΎ1 ) π½2 π§3 + [(π2 + ππΎ1 ) π½1 − πΌ2 ] π§2 (34) on a set of logarithmic density 1. Hence, by (34), π has infinitely many zeros and By (25), we may define 2 1 ) = (1 − π (1)) π (π, π) , π ≥ ππ π (π, π) + πΈπ (π) , (43) Abstract and Applied Analysis 5 for each π. Since |π| > 1, we derive where σ΅¨ σ΅¨σ΅¨ σ΅¨ σ΅¨ σ΅¨σ΅¨πΈπ (π)σ΅¨σ΅¨σ΅¨ = σ΅¨σ΅¨σ΅¨σ΅¨ππ−1 π (π) + ππ−2 π (σ΅¨σ΅¨σ΅¨σ΅¨πσ΅¨σ΅¨σ΅¨σ΅¨π π) + ⋅ ⋅ ⋅ + π (σ΅¨σ΅¨σ΅¨σ΅¨πσ΅¨σ΅¨σ΅¨σ΅¨π(π−1) π)σ΅¨σ΅¨σ΅¨σ΅¨ σ΅¨ σ΅¨ σ΅¨ σ΅¨ ππ σ΅¨ σ΅¨ π−1 log σ΅¨σ΅¨σ΅¨πσ΅¨σ΅¨σ΅¨ π ≤ πΎππ−1 ∑ ππ π=0 (44) For π sufficiently large and π, we note that since π = π/π > 1, the two series converge, and hence (45) where πΆ is a positive constant. Since π is a transcendental meromorphic function, we can choose π0 sufficiently large such that for all π ≥ π0 , by the increasing property of π(π, π), we have π(π, π) ≥ πΆ log π for some constant πΆ. Hence, we get σ΅¨ σ΅¨ππ π (σ΅¨σ΅¨σ΅¨πσ΅¨σ΅¨σ΅¨ π, π) > πΆππ log π, (46) for some constant πΆ. By the definition of the order of π, we have σ΅¨ σ΅¨ππ log π (σ΅¨σ΅¨σ΅¨πσ΅¨σ΅¨σ΅¨ π, π) π (π) = lim sup σ΅¨ σ΅¨ππ π → ∞, π → ∞ log σ΅¨σ΅¨σ΅¨πσ΅¨σ΅¨σ΅¨ π ≥ (47) log πΆ + π log π + log log π . σ΅¨ σ΅¨ ππ log σ΅¨σ΅¨σ΅¨πσ΅¨σ΅¨σ΅¨ + log π So we have π(π) ≥ log(π/π)/(π log |π|). Thus, we complete the proof. Proof of Theorem 8. Suppose that the order of π is π < ∞. We rewrite (9) as π−1 π (ππ π§) = ∑ππ½ (π§) (∏π (π§ + ππ )) − ∑ ππ π§π (ππ π§) . (48) {π½} π∈π½ π=1 By the property of the Nevanlinna characteristic function, we have π (π, π (ππ π§)) ≤ π (π, ∑ππ½ (π§) (∏π (π§ + ππ ))) {π½} π∈π½ π−1 (49) + ∑ π (π, ππ (π§) π (ππ π§)) + π (1) . π=1 By Lemmas 10 and 15, we obtain π−1 σ΅¨ σ΅¨π σ΅¨ σ΅¨π π (σ΅¨σ΅¨σ΅¨πσ΅¨σ΅¨σ΅¨ π, π (π§)) ≤ ππ (π, π (π§)) + ∑ π (σ΅¨σ΅¨σ΅¨πσ΅¨σ΅¨σ΅¨ π, π (π§)) π π−1+π + π (π ) + π (π, π) , σ΅¨ σ΅¨π−1 σ΅¨ σ΅¨π−1 π−1+π ) + π (σ΅¨σ΅¨σ΅¨πσ΅¨σ΅¨σ΅¨ π, π) + π ((σ΅¨σ΅¨σ΅¨πσ΅¨σ΅¨σ΅¨ π) (51) for each π. Setting πΌ = 1/|π|, π = |π|π π, Φ(π ) = π((πΌπ )π−1+π ) and applying Lemma 11 to (51), yield ∞ ∞ 1 σ΅¨ σ΅¨π π ≤ πΎππ−1 (log σ΅¨σ΅¨σ΅¨πσ΅¨σ΅¨σ΅¨ ∑ π + log π∑ π ) . π=0 π π=0 π σ΅¨ σ΅¨σ΅¨ σ΅¨σ΅¨πΈπ (π)σ΅¨σ΅¨σ΅¨ ≤ πΆππ log π, σ΅¨ σ΅¨ σ΅¨ σ΅¨π−1 σ΅¨ σ΅¨π π (σ΅¨σ΅¨σ΅¨πσ΅¨σ΅¨σ΅¨ π, π (π§)) ≤ (π + π − 1) π (σ΅¨σ΅¨σ΅¨πσ΅¨σ΅¨σ΅¨ π, π (π§)) (50) π (π) = π ≤ log(π + π − 1) + π − 1 + π, σ΅¨ σ΅¨ log σ΅¨σ΅¨σ΅¨πσ΅¨σ΅¨σ΅¨ for each π. Thus, we obtain σ΅¨σ΅¨σ΅¨πσ΅¨σ΅¨σ΅¨ < π + π − 1. σ΅¨ σ΅¨ (52) (53) Acknowledgments The author wishes to express his thanks to the referee for his/her valuable suggestions and comments. The present investigation was supported by the National Natural Science Foundation under Grant no. 11226088 and the Key Project of Natural Science Foundation of Educational Committee of Henan Province under Grant no. 12A110002 of the People’s Republic of China. References [1] W. K. Hayman, Meromorphic Functions, Oxford Mathematical Monographs, Clarendon Press, Oxford, UK, 1964. [2] L. 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