Hindawi Publishing Corporation Abstract and Applied Analysis Volume 2013, Article ID 938027, 6 pages http://dx.doi.org/10.1155/2013/938027 Research Article Exponential Stability of Impulsive Delay Differential Equations G. L. Zhang, M. H. Song, and M. Z. Liu Department of Mathematics, Harbin Institute of Technology, Harbin 150001, China Correspondence should be addressed to M. H. Song; songmh@lsec.cc.ac.cn Received 8 September 2012; Revised 3 January 2013; Accepted 8 January 2013 Academic Editor: Xinan Hao Copyright © 2013 G. L. Zhang et al. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited. The main objective of this paper is to further investigate the exponential stability of a class of impulsive delay differential equations. Several new criteria for the exponential stability are analytically established based on Razumikhin techniques. Some sufficient conditions, under which a class of linear impulsive delay differential equations are exponentially stable, are also given. An Euler method is applied to this kind of equations and it is shown that the exponential stability is preserved by the numerical process. 1. Introduction Impulsive differential equations arise widely in the study of medicine, biology, economics, engineering, and so forth. In recent years, theory of impulsive differential delay equations (IDDEs) has been an object of active research (see [1–18] and references therein). The results about the existence and uniqueness of IDDEs have been studied in [2, 7]. The stability of IDDEs has attracted increasing interest in both theoretical research and practical applications (see [1, 3, 5–18] and references therein). In particular, special attention has been focused on exponential stability of IDDEs (see [1, 3, 8, 9, 15]) because it has played an important role in many areas. There is a little work done on exponential stability for IDDEs by the Lyapunov-Razumikhin method. Wang and Liu [15] have extended Lyapunov-Razumikhin method to IDDEs and established some exponential stability criteria. In this paper we restrict the length of each impulsive interval instead of some conditions in [15]. As a result, several new criteria on exponential stability are analytically derived. There are a few papers on numerical methods of impulsive differential equations. In [19], Covachev et al. obtained a convergent difference approximation for a nonlinear impulsive ordinary system in a Banach space. In [20, 21], the authors studied the stability of Runge-Kutta methods for linear impulsive ordinary differential equations. In [4], Ding et al. studied the convergence property of an Euler method for IDDEs. In [18], asymptotic stability of numerical solutions and exact solutions of a class of linear IDDEs was studied by the property of DDEs without impulsive perturbations. The convergence of the numerical methods for this kind of equations was studied. In this paper, we study exponential stability of the numerical solutions of linear IDDEs. The rest of the paper is organized as follows. In Section 2, we obtained two criteria on exponential stability for IDDEs by the Lyapunov-Razumikhin method. The results obtained are applied to a class of linear IDDEs. In the last section, we prove that the Euler method for the linear IDDEs preserves the analytic exponential stability. 2. Stability of Analytic Solutions Consider the impulsive delay differential system π₯σΈ (π‘) = π (π‘, π₯π‘ ) , Δπ₯ (π‘) = πΌπ (π‘, π₯π‘− ) , π‘ ∈ [π‘π−1 , π‘π ) , π = 1, 2, 3, . . . , π‘ = π‘π , π = 1, 2, 3, . . . , (1) where π : π + × PC([−π, 0], π π ) → π π ; πΌπ : PC([−π, 0], π π ) → π π ; 0 ≤ π‘0 < π‘1 < π‘2 < ⋅ ⋅ ⋅ < π‘π < ⋅ ⋅ ⋅, with π‘π → ∞ as π → ∞; PC([−π, 0], π π ) is a set of piecewise continuous functions π(π‘) which have a finite number of points of discontinuity in a finite interval and π(π‘) = π(π‘+ ) for all π‘. We assume that π(π‘, 0) ≡ 0, πΌπ (π‘, 0) ≡ 0, so that π₯ ≡ 0 is a solution of (1) as π₯π‘0 = Φ ≡ 0, which we call the zero solution. 2 Abstract and Applied Analysis Definition 1 (see [15]). A function π: π + × π π → π + is said to belong to the class π£0 if (i) π is continuous in each of the sets [π‘π−1 , π‘π ) × π π and for each π₯ ∈ π π , π‘ ∈ [π‘π−1 , π‘π ), lim(π‘,π¦) → (π‘π− ,π₯) π(π‘, π¦) = π(π‘π− , π₯) exists, π = 1, 2, . . .; (ii) π(π‘, π₯) is locally Lipschitzian in all π₯ ∈ π π , and for all π‘ ≥ π‘0 , π(π‘, 0) ≡ 0. Definition 2 (see [15]). Given a function π: π + × π π → π + , the upper right-hand derivative of π with respect to system (1) is defined by π·+ π (π‘, Ψ(0)) 1 = lim sup [π (π‘ + β, Ψ (0) + βπ (π‘, Ψ)) − π (π‘, Ψ (0))] , β → 0+ β (2) for (π‘, Ψ) ∈ π + × PC([−π, 0], π π ). Definition 3 (see [15]). The zero solution of (1) is said to be exponentially stable, if there exist constants π > 0 and π ≥ 1, such that for any initial data π₯π‘0 = Φ ∈ PC([−π, 0], π π ), σ΅©σ΅© σ΅© −π(π‘−π‘0 ) (3) , π‘ ≥ π‘0 . σ΅©σ΅©π₯ (π‘, π‘0 , Φ)σ΅©σ΅©σ΅© ≤ πβΦβπ π Theorem 4. Assume that there exist a function π ∈ π£0 ; constants ππ > −1, π = 1, 2, . . .; positive constants πΆ1 , πΆ2 , π, π1 ; and a function π(π‘) ∈ ππΆ([π‘0 −π, ∞), π + ) with inf π‘≥π‘0 −π π(π‘) ≥ π, such that for any Ψ(π‘) ∈ ππΆ([−π, 0], π π ) with Ψ(0− ) = Ψ(0) the following conditions hold: Remark 5. Theorem 3.1 in [15] requires that ππ ≥ 0, and ∑∞ π=0 ππ < ∞, which implies limπ → ∞ ππ = 0. In our Theorem 4, we require π‘π − π‘π−1 ≥ π1 for π = 1, 2, . . ., and supπ {1 + ππ } < πππ1 instead. This means that the impulsive effects are bounded instead of tending to zero (see Example 13). Theorem 6. Assume that there exist a function π ∈ π£0 ; constants ππ ∈ (−1, 0), π = 1, 2, . . .; positive constants π1 , π2 , πΆ1 , πΆ2 , π; and a function π(π‘) ∈ PC([π‘0 − π, ∞), π + ) with supπ‘≥π‘0 −π π(π‘) ≤ π, such that for any Ψ(π‘) ∈ PC([−π, 0], π π ) with Ψ(0− ) = Ψ(0), the following conditions hold: (i) πΆ1 βπ₯β ≤ π(π‘, π₯) ≤ πΆ2 βπ₯β for all π‘ ∈ π + , π₯ ∈ π π ; (ii) π·+ π(π‘, Ψ(0)) ≤ π(π‘)π(π‘, Ψ(0)) for all π‘ ∈ [π‘π , π‘π+1 ), π = 1, 2, . . ., whenever π(π‘, Ψ(0)) ≥ πΎπ(π‘ + π , Ψ(π )) for π ∈ [−π, 0], where πΎ is a constant and 0 < πΎ < π π»2 , π»2 = inf π {1 + ππ } and π is the smallest integer larger than or equal to π/π1 ; (iii) π(π‘π , Ψ(0) + πΌπ (π‘π , Ψ)) ≤ (1 + ππ )π(π‘π− , Ψ(0)), π = 1, 2, . . .; (iv) π1 ≤ π‘π − π‘π−1 ≤ π2 for π = 1, 2, . . ., and 0 < π»2 ≤ π»1 < π−ππ2 , where π»1 = supπ {1 + ππ }, π»2 = inf π {1 + ππ }. Then the zero solution of (1) is exponentially stable. Proof. Let π₯(π‘) = π₯(π‘, π‘0 , Φ) be the solution of system (1) and π(π‘) = π(π‘, π₯(π‘)). We will prove (i) πΆ1 βπ₯β ≤ π(π‘, π₯) ≤ πΆ2 βπ₯β for all π‘ ∈ π + , π₯ ∈ π π ; (ii) π·+ π(π‘, Ψ(0)) ≤ −π(π‘)π(π‘, Ψ(0)) for all π‘ ∈ [π‘π , π‘π+1 ), π π‘ whenever π(π‘, Ψ(0)) ≥ π(π‘ + π , Ψ(π ))π− ∫π‘−π π(π )ππ for π ∈ [−π, 0]; (iii) π(π‘π , Ψ(0) + πΌπ (π‘π , Ψ(0))) ≤ (1 + ππ )π(π‘π− , Ψ(0)) for π = 1, 2, . . .; (iv) π‘π − π‘π−1 ≥ π1 for π = 1, 2, . . ., and −ππ1 + ln π»1 < 0, where π»1 = supπ {1 + ππ }. Then the zero solution of (1) is exponentially stable. Proof. Similar to the proof of Theorem 3.1 in [15], we obtain that π π‘ − ∫π‘ π(π )ππ π (π‘, π₯) ≤ πΆ2 ∏ (1 + ππ ) βΦβπ π 0 , π=1 (4) π‘ ∈ [π‘π , π‘π+1 ) , π = 1, 2, . . . . Since −ππ1 + ln π»1 < 0, there exists πΌ such that 0 < πΌ < π and −(π − πΌ)π1 + ln π»1 < 0. So πΆ1 βπ₯β ≤ π (π‘, π₯) ≤ πΆ2 π»1π βΦβπ π−π(π‘−π‘0 ) ≤ πΆ2 βΦβπ π−π(π‘−π‘0 )+π ln π»1 < πΆ2 βΦβπ π−π(π‘−π‘0 )+(π−πΌ)ππ1 ≤ πΆ2 βΦβπ π−πΌ(π‘−π‘0 ) . Hence the zero solution of (1) is exponentially stable. (5) π‘ ∫ π(π )ππ π (π‘) ≤ πΆ2 ∏ (1 + ππ ) βΦβπ π π‘0 , π=1 (6) π‘ ∈ [π‘π , π‘π+1 ) , π = 1, 2, . . . . Let π π‘ ∫ π(π )ππ { { , π (π‘) − πΆ2 ∏ (1 + ππ ) βΦβπ π π‘0 { { π=1 { { { { { { π‘ ∈ [π‘π , π‘π+1 ) , π = 1, 2, . . . , { π (π‘) = { { π‘ { ∫π‘ π(π )ππ { { 0 π − πΆ π , π‘ ∈ [π‘0 , π‘1 ) , (π‘) βΦβ { 2 π { { { { { {π (π‘) − πΆ2 βΦβπ , π‘ ∈ [π‘0 − π, π‘0 ] . (7) We need to show that π(π‘) ≤ 0 for all π‘ ≥ π‘0 . It is clear that π(π‘) ≤ 0 for π‘ ∈ [π‘0 − π, π‘0 ], since π(π‘) = π(π‘) − πΆ2 βΦβπ ≤ 0 by condition (i). Next we shall show π(π‘) ≤ 0, for π‘ ∈ [π‘0 , π‘1 ). Suppose this is not true. Then there is a π‘∗ such that π‘∗ ≤ inf{π‘ ∈ [π‘0 , π‘1 ), π(π‘) > 0}, π(π‘∗ ) ≤ 0, π(π‘∗ ) ≥ (πΎ − 1)πΆ2 βΦβπ , and π·+ π (π‘∗ ) > 0. (8) Abstract and Applied Analysis 3 ∫ π‘∗ Note that π(π‘∗ ) = π(π‘∗ ) + πΆ2 βΦβπ π π‘0 π‘∗ ∫π‘ 0 π(π)ππ . Then π(π‘∗ + π‘∗ ∫π‘ 0 π(π)ππ π(π)ππ π ) ≤ πΆ2 βΦβπ π ≤ πΎ−1 (π(π‘∗ ) + πΆ2 βΦβπ π ) = −1 ∗ + ∗ πΎ π(π‘ ) for π ∈ [−π, 0]. By condition (ii), π· π(π‘ ) ≤ π(π‘∗ )π(π‘∗ ). So + ∗ + ∗ ) (9) π π‘∗ ∫ π(π )ππ ) = 0, (13) which contradicts (11). Hence π(π‘) ≤ 0 for all π‘ ∈ [π‘π , π‘π+1 ). By induction, π(π‘) ≤ 0 for all π‘ ≥ π‘0 . In view of π(π‘) ≤ π for all π‘ ≥ π‘0 − π, we obtain = 0, which contradicts (8). Hence π(π‘) ≤ 0, for all π‘ ∈ [π‘0 , π‘1 ). Assume that π(π‘) ≤ 0, for π‘ ∈ [π‘0 , π‘π ), π ≥ 1. We shall show that π(π‘) ≤ 0, for π‘ ∈ [π‘0 , π‘π+1 ). Obviously, by condition (iii) π π‘ π=1 π π π‘ ∫ π(π )ππ π (π‘) ≤ πΆ2 ∏ (1 + ππ ) βΦβπ π π‘0 π=1 π‘ ∫ π(π )ππ ≤ πΆ2 βΦβπ π»1π π π‘0 π‘ ∫π‘ π 0 − ≤ (1 + ππ ) π (π‘π ) − πΆ2 ∏ (1 + ππ ) βΦβπ π π(π )ππ π=1 for π‘ ∈ [π‘π , π‘π+1 ), π = 1, 2, . . .. Since π»1 < π−ππ2 , there exists πΌ such that 0 < πΌ < π and ππ2 + ln π»2 < −πΌπ2 . By condition (i) πΆ1 βπ₯β ≤ π (π‘, π₯) − ππ ) π (π‘π ) ≤ πΆ2 π»1π βΦβπ ππ(π‘−π‘0 ) ≤ πΆ2 βΦβπ ππ(π‘−π‘0 )+π ln π»1 ≤ 0. (10) Suppose that there exists a π‘ such that π‘ ∈ [π‘π , π‘π+1 ) and π(π‘) > 0. There is a π‘∗ such that π‘∗ ≤ inf{π‘ ∈ [π‘π , π‘π + −π 1), π(π‘) > 0}, π(π‘∗ ) ≤ 0, π(π‘∗ ) ≥ (πΎπ»2 − 1)πΆ2 ∏π π=1 (1 + ππ )βΦβπ , and π·+ π (π‘∗ ) > 0. (11) π‘∗ ∫ π‘0 Since π(π‘∗ ) = π(π‘∗ ) + πΆ2 ∏π π=1 (1 + ππ )βΦβπ π for any π ∈ [−π, 0], we have π−π π(π )ππ π‘∗ +π ∫π‘ 0 π (π‘∗ + π ) ≤ π (π‘∗ + π ) + πΆ2 ∏ (1 + ππ ) βΦβπ π , then π(π)ππ π‘∗ ∫ ≤ π»2 πΆ2 ∏ (1 + ππ ) βΦβπ π π‘0 Remark 7. Theorem 6 says that the delay differential equation is unstable and the suitable impulse effects are given, then it will become stable (see Example 14). Compared with the Theorem 3.1 in [16], we do not require that π ≤ π‘π − π‘π−1 . For example, by Theorem 6 we know that the zero solution of the following system is exponentially stable: 1 1 π₯σΈ (π‘) = π₯ (π‘) + π₯ (π‘ − 1) , 2 8 π‘π = π , π = 1, 2, . . . , 2 (16) π , π = 1, 2, . . . . 2 In the following we consider π=1 π where π = πΆ2 π(π+πΌ)π2 . Hence the zero solution of (1) is exponentially stable. 1 π₯ (π‘π ) = π₯ (π‘π− ) , 3 π(π)ππ (15) ≤ πΆ2 βΦβπ ππ(π‘−π‘0 )−(π+πΌ)ππ2 ≤ πβΦβπ π−πΌ(π‘−π‘0 ) , π‘ ≥ 0, π‘ =ΜΈ π‘π , π‘π = π=1 π (14) ≤ πΆ2 π»1π βΦβπ ππ(π‘−π‘0 ) , ∫ π π(π )ππ π (π‘π ) = π (π‘π ) − πΆ2 ∏ (1 + ππ ) βΦβπ π π‘0 −π π(π )ππ π=1 = π (π‘∗ ) π (π‘∗ ) = (1 + π‘∗ = π (π‘∗ ) π (π‘∗ ) π(π )ππ ≤ π (π‘∗ ) (π (π‘∗ ) − πΆ2 βΦβπ π ∫ π=1 π(π )ππ π· π (π‘ ) = π· π (π‘ ) − π (π‘ ) πΆ2 βΦβπ π π‘∗ ∫π‘ 0 π π·+ π (π‘∗ ) = π·+ π (π‘∗ ) + π (π‘∗ ) πΆ2 ∏ (1 + ππ ) βΦβπ π π‘0 ≤ π (π‘∗ ) (π (π‘∗ ) − πΆ2 ∏ (1 + ππ ) βΦβπ π π‘0 π‘∗ ∫π‘ 0 ∗ Thus by condition (ii), π·+ π(π‘∗ ) ≤ π(π‘∗ )π(π‘∗ ), then π‘∗ ∫π‘ 0 ≤ πΎ−1 (π (π‘∗ ) + πΆ2 ∏ (1 + ππ ) βΦβπ π π(π)ππ π₯σΈ (π‘) = ππ₯ (π‘) + ππ₯ (π‘ − π) , ) π=1 π‘ ≥ 0, π‘ ∈ [(π − 1) π, ππ) π = 1, 2, . . . , π₯ (π‘π ) = (1 + ππ ) π₯ (π‘π− ) , ≤ πΎ−1 π (π‘∗ ) . (12) π‘π = ππ, π = 1, 2, . . . , where π > 0, and ππ , π, π ∈ π are constants. (17) 4 Abstract and Applied Analysis Theorem 8. Assume that ππ =ΜΈ − 1, π = 1, 2, . . ., and there is a constant π > 0 such that π + |π|πππ ≤ −π and 0 < π»1 < πππ , where π»1 = supπ {|1 + ππ |}. Then the zero solution of (17) is exponentially stable. where β = π/π. Let π = ππ + π, then π₯π = π₯ππ+π = π₯π,π is an approximation for the exact solution π₯((ππ + π)β) for π = 0, 1, 2, . . . , π = 0, 1, 2, . . . , π − 1, and π₯π,π is an approximation for π₯((π + 1)π− ). Proof. Assume that π(π₯) = π(π‘, π₯) = |π₯|. Definition 10. The Euler method for (11) is said to be exponentially stable if there exist positive constants π, π, and π1 , for any Φ ∈ PC([−π, 0], π ), such that βπ₯π β ≤ πβΦβπ π−ππβ for β = π/π, π ≥ π1 , and π = 1, 2, . . .. (i) Obviously, there exist πΆ1 = πΆ2 = 1, such that πΆ1 |π₯| ≤ π(π₯) ≤ πΆ2 |π₯|. (ii) Assume that π(π‘) = π for all π‘ ≥ −π. For any Ψ ∈ PC([−π, 0], π ), if π‘ − ∫π‘−π π (π‘, Ψ (0)) ≥ π (π‘ + π , Ψ (π )) π π(π )ππ = π (π‘ + π , Ψ (π )) π−ππ , (18) Theorem 11. Under the conditions of Theorem 8, the Euler method for (17) is exponentially stable. we have |Ψ(−π)| ≤ πππ |Ψ(0)|. For π ∈ [−π, 0], we have Proof. If π < 0, then π1 = −ππ. (i) If π»1 > 1, we want to prove that π·+ π (π‘, Ψ (0)) ≤ π |Ψ (0)| + |π| |Ψ (−π)| ≤ π |Ψ (0)| + |π| πππ |Ψ (0)| ππ = (π + |π| π ) |Ψ (0)| (19) = − π (π‘) π (π‘, Ψ (0)) . σ΅¨ σ΅¨ = (1 + ππ ) σ΅¨σ΅¨σ΅¨π₯ (π‘π− )σ΅¨σ΅¨σ΅¨ = (1 + ππ ) π (π₯ (π‘π− )) . σ΅¨ σ΅¨σ΅¨ σ΅¨σ΅¨ σ΅¨σ΅¨ σ΅¨σ΅¨π₯0,1 σ΅¨σ΅¨ = σ΅¨σ΅¨π₯0,0 + βππ₯0,0 + βππ₯−1,0 σ΅¨σ΅¨σ΅¨ σ΅¨ σ΅¨ σ΅¨ σ΅¨ ≤ (1 + βπ) σ΅¨σ΅¨σ΅¨π₯0,0 σ΅¨σ΅¨σ΅¨ + β |π| σ΅¨σ΅¨σ΅¨π₯−1,0 σ΅¨σ΅¨σ΅¨ (20) (iv) Obviously, π1 = π = π‘π − π‘π−1 and −ππ1 + ln π»1 < 0. By Theorem 4, the zero solution of (11) is exponentially stable. Similarly, by Theorem 6 we have the following theorem. Theorem 9. Assume that 0 < |1 + ππ | < 1, π = 1, 2, . . ., and there are constants π and πΎ such that π > 0, 0 < πΎ < π»2 ≤ π»1 < π−ππ , and π + |π|πΎ−1 ≤ π, where π»1 = supπ {|1 + ππ |}, π»2 = inf π {|1 + ππ |}. Then the zero solution of (17) is exponentially stable. In this section, we consider the exponential stability of the Euler method for (17). The convergence property can be proved similarly to [4]. The Euler method for (17) with initial function Φ ∈ PC([−π, 0], π ) is given by π₯π, π+1 = π₯π, π + βππ₯π, π + βππ₯π−1, π , π = 0, 1, . . . , π − 1, π = 0, 1, . . . , π = 0, 1, 2, . . . , π₯−1, π = Φ (−π + πβ) , (22) ≤ (1 + βπ) βΦβπ + β |π| βΦβπ (23) ≤ (1 + βπ + β |π| πππ ) βΦβπ . Because π + |π|πππ ≤ −π, we have |π₯0,1 | ≤ (1 − βπ)βΦβπ . By the inequality π−π₯ ≥ 1 − π₯ holding for all π₯ ∈ π , we get |π₯0,1 | ≤ βΦβπ π−πβ . Assume that |π₯0,π | ≤ βΦβπ π−ππβ for π < π ≤ π. Then σ΅¨σ΅¨ σ΅¨σ΅¨ σ΅¨σ΅¨ σ΅¨ σ΅¨σ΅¨π₯0,π σ΅¨σ΅¨ = σ΅¨σ΅¨π₯0,π−1 + βππ₯0, π−1 + βππ₯−1, π−1 σ΅¨σ΅¨σ΅¨ σ΅¨ σ΅¨ σ΅¨ σ΅¨ ≤ (1 + βπ) σ΅¨σ΅¨σ΅¨π₯0, π−1 σ΅¨σ΅¨σ΅¨ + β |π| σ΅¨σ΅¨σ΅¨π₯−1, π−1 σ΅¨σ΅¨σ΅¨ ≤ (1 + βπ) βΦβπ π−π(π−1)β + β |π| βΦβπ 3. The Euler Method for Linear IDDEs π₯(π+1), 0 = (1 + ππ+1 ) π₯π,π , σ΅¨σ΅¨ σ΅¨σ΅¨ π −(ππ+π)πβ , σ΅¨σ΅¨π₯π,π σ΅¨σ΅¨ ≤ βΦβπ π»1 π for π = 0, 1, 2, . . ., π = 0, 1, 2, . . . , π. Obviously, |π₯0,0 | = |Φ(0)| ≤ βΦβπ . Firstly, we consider the case π = 0 and π = 1. Because β = π/π and π ≥ π1 , so 1 + βπ ≥ 0. Hence we have ≤ − π |Ψ (0)| (iii) Suppose that 1 + ππ = |(1 + ππ )|. Hence σ΅¨ σ΅¨ σ΅¨ σ΅¨σ΅¨ σ΅¨ π (π₯ (π‘π )) = σ΅¨σ΅¨σ΅¨π₯ (π‘π )σ΅¨σ΅¨σ΅¨ = σ΅¨σ΅¨σ΅¨(1 + ππ )σ΅¨σ΅¨σ΅¨ σ΅¨σ΅¨σ΅¨π₯ (π‘π− )σ΅¨σ΅¨σ΅¨ The following theorem indicates that the Euler method preserves the property of exact solutions which was obtained above. (21) ≤ (1 + βπ + β |π| πππ ) βΦβπ π−π(π−1)β (24) ≤ (1 − βπ) βΦβπ π−π(π−1)β ≤ βΦβπ π−ππβ . So (22) holds for π = 0, π = 0, 1, 2, . . . , π. Suppose that (22) holds for π < π, π = 0, 1, 2, . . . , π. Next, we shall prove (22) holds, when π = π, π = 0, 1, 2, . . . , π. Hence σ΅¨σ΅¨ σ΅¨ σ΅¨σ΅¨ σ΅¨σ΅¨ σ΅¨σ΅¨ π −πππβ . σ΅¨σ΅¨π₯π,0 σ΅¨σ΅¨ = σ΅¨σ΅¨1 + ππ σ΅¨σ΅¨σ΅¨ σ΅¨σ΅¨σ΅¨π₯π−1,π σ΅¨σ΅¨σ΅¨ ≤ βΦβπ π»1 π (25) Abstract and Applied Analysis 5 1 10 0.9 9 0.8 8 0.7 7 0.6 π₯ 0.5 π₯ 0.4 6 5 0.3 4 0.2 3 0.1 2 0 −1 0 1 2 3 1 −1 4 π‘ 1.6 1.4 1.2 π₯ (26) ) βΦβπ π»1π π−(ππ+π−1)πβ 0.2 0 −2 Hence (22) holds. Since −ππ1 + ln π»1 < 0, there exists πΌ such that 0 < πΌ < π and −(π − πΌ)π1 + ln π»1 < 0. Hence ≤ βΦβπ π (27) . (ii) If π»1 ≤ 1, we can prove that σ΅¨σ΅¨ σ΅¨σ΅¨ −π(ππ+π)β . σ΅¨σ΅¨π₯π,π σ΅¨σ΅¨ ≤ βΦβπ π (28) Theorem 12. Under the conditions of Theorem 9, the Euler method for (17) is exponentially stable. Example 13. Consider the system π₯ (π‘) = − 4π₯ (π‘) + π₯ (π‘ − 1) , π₯ (π) = 2π₯ (π− ) , 0 2 4 6 π‘ ≥ 0, π‘ =ΜΈ π, π = 1, 2, . . . , π = 1, 2, . . . . (29) 8 10 π‘ Figure 3: The solutions of (31), as Φ ≡ 1, β = 1/10. Obviously, π = 1 satisfies the Theorem 8. Therefore the zero solution of (29) is exponentially stable. By Theorem 11, the Euler method for (29) is also exponentially stable (see Figure 1). Example 14. Obviously, the zero solution of the system 1 1 π₯σΈ (π‘) = π₯ (π‘) + π₯ (π‘ − 1) , 2 8 Consequently, the theorem holds. σΈ 0.8 0.4 βΦβπ π»1π π−(ππ+π)πβ . −πΌ(ππ+π)β 1 0.6 ≤ (1 − βπ) βΦβπ π»1π π−(ππ+π−1)πβ π σ΅¨σ΅¨ σ΅¨σ΅¨ π −(ππ+π)πβ ≤ βΦβπ (πln π»1 −ππβ ) π−ππβ σ΅¨σ΅¨π₯π,π σ΅¨σ΅¨ ≤ βΦβπ π»1 π 4 1.8 ≤ (1 + βπ) βΦβπ π»1π π−(ππ+π−1)πβ ≤ 3 2 σ΅¨σ΅¨ σ΅¨σ΅¨ σ΅¨σ΅¨ σ΅¨ σ΅¨σ΅¨π₯π,π σ΅¨σ΅¨ = σ΅¨σ΅¨π₯π,π−1 + βππ₯π,π−1 + βππ₯π−1, π−1 σ΅¨σ΅¨σ΅¨ σ΅¨ σ΅¨ σ΅¨ σ΅¨ ≤ (1 + βπ) σ΅¨σ΅¨σ΅¨π₯π,π−1 σ΅¨σ΅¨σ΅¨ + β |π| σ΅¨σ΅¨σ΅¨π₯π−1, π−1 σ΅¨σ΅¨σ΅¨ ≤ (1 + βπ + β |π| π 2 Figure 2: The solution of (30) as Φ(π‘) ≡ 1, π‘ ∈ [−π, 0]. Assume that |π₯π,π’ | ≤ βΦβπ π»1π π−(ππ+π’)πβ for π’ < π ≤ π. Then ππ 1 π‘ Figure 1: The solutions of (29), as Φ ≡ 1, β = 1/10. σ΅¨ σ΅¨ + β |π| ⋅ βΦβπ π»1π−1 σ΅¨σ΅¨σ΅¨1 + ππ σ΅¨σ΅¨σ΅¨ π−(ππ−π+π−1)πβ 0 π‘ ≥ 0, (30) is unstable (see Figure 2) while the zero solution of the following system 1 1 π₯σΈ (π‘) = π₯ (π‘) + π₯ (π‘ − 1) , 2 8 1 π₯ (π) = π₯ (π− ) , 3 π‘ ≥ 0, π‘ =ΜΈ π, π = 1, 2, . . . , π = 1, 2, . . . , (31) 6 is exponentially stable by Theorem 9 with π = 1. By Theorem 12, the Euler method for (31) is also exponentially stable (see Figure 3). Acknowledgments The authors wish to thank referees for valuable comments. The research was supported by the NSF of China no. 11071050. References [1] A. Anokhin, L. Berezansky, and E. Braverman, “Exponential stability of linear delay impulsive differential equations,” Journal of Mathematical Analysis and Applications, vol. 193, no. 3, pp. 923–941, 1995. [2] G. Ballinger and X. 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