Research Article Nonexistence Results of Semilinear Elliptic Equations Coupled Hyungjin Huh

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Hindawi Publishing Corporation
Abstract and Applied Analysis
Volume 2013, Article ID 467985, 5 pages
http://dx.doi.org/10.1155/2013/467985
Research Article
Nonexistence Results of Semilinear Elliptic Equations Coupled
with the Chern-Simons Gauge Field
Hyungjin Huh
Department of Mathematics, Chung-Ang University, Seoul 156-756, Republic of Korea
Correspondence should be addressed to Hyungjin Huh; huh@cau.ac.kr
Received 1 November 2012; Accepted 15 January 2013
Academic Editor: Khalil Ezzinbi
Copyright © 2013 Hyungjin Huh. This is an open access article distributed under the Creative Commons Attribution License, which
permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.
We discuss the nonexistence of nontrivial solutions for the Chern-Simons-Higgs and Chern-Simons-Schrödinger equations. The
Derrick-Pohozaev type identities are derived to prove it.
1. Introduction and Main Results
In this paper, we are concerned with the nonexistence of
nontrivial solutions to some elliptic equations coupled with
Chern-Simons gauge field. More precisely, let us first consider
the following system:
2
󡄨 󡄨2
−(πœ” + 𝐴 0 ) πœ™ − 𝐷1 𝐷1 πœ™ − 𝐷2 𝐷2 πœ™ + 𝑉󸀠 (σ΅„¨σ΅„¨σ΅„¨πœ™σ΅„¨σ΅„¨σ΅„¨ ) πœ™ = 0,
2
(1)
(2)
πœ•2 𝐴 0 = Im (πœ™π·1 πœ™) ,
(3)
󡄨 󡄨2
πœ•1 𝐴 2 − πœ•2 𝐴 1 = − (πœ” + 𝐴 0 ) σ΅„¨σ΅„¨σ΅„¨πœ™σ΅„¨σ΅„¨σ΅„¨ ,
(4)
which is derived from the system (5) with stationary solution
ansatz πœ“(𝑑, π‘₯) = π‘’π‘–πœ”π‘‘ πœ™(π‘₯), πœ™ ∈ C, and 𝐴 πœ‡ (𝑑, π‘₯) = 𝐴 πœ‡ (π‘₯) for
πœ‡ = 0, 1, 2. Consider
󡄨 󡄨2
𝐷0 𝐷0 πœ“ − (𝐷1 𝐷1 + 𝐷2 𝐷2 ) πœ“ + 𝑉󸀠 (σ΅„¨σ΅„¨σ΅„¨πœ“σ΅„¨σ΅„¨σ΅„¨ ) πœ“ = 0,
πœ•0 𝐴 2 − πœ•2 𝐴 0 = − Im (πœ“π·1 πœ“) ,
󡄨2
󡄨
󡄨2
󡄨
𝐸 (𝑑) = ∫ ∑ 󡄨󡄨󡄨𝐷𝛼 πœ“ (𝑑, π‘₯)󡄨󡄨󡄨 + 𝑉 (σ΅„¨σ΅„¨σ΅„¨πœ“ (𝑑, π‘₯)󡄨󡄨󡄨 ) 𝑑π‘₯ = 𝐸 (0) .
R2
𝛼=0
πœ•1 𝐴 0 = − Im (πœ™π·2 πœ™) ,
πœ•0 𝐴 1 − πœ•1 𝐴 0 = Im (πœ“π·2 πœ“) ,
The Chern-Simons-Higgs system in (5) was introduced
in [1, 2] to deal with the electromagnetic phenomena in
planar domain such as fractional quantum Hall effect or high
temperature superconductivity. The system in (5) has the
conservation of the total energy
(6)
The special case with a self-dual potential 𝑉(|πœ™|2 ) = (1/4)
|πœ™| (|πœ™|2 − 1)2 has received much attention and has been
studied by several authors, where one can derive the following
system of first-order equations called self-dual equations (see
[1, 2])
2
𝐷1 πœ™ − 𝑖𝐷2 πœ™ = 0,
1 󡄨 󡄨2 󡄨 󡄨2
πœ•1 𝐴 2 − πœ•2 𝐴 1 + σ΅„¨σ΅„¨σ΅„¨πœ™σ΅„¨σ΅„¨σ΅„¨ (σ΅„¨σ΅„¨σ΅„¨πœ™σ΅„¨σ΅„¨σ΅„¨ − 1) = 0,
2
(5)
πœ•1 𝐴 2 − πœ•2 𝐴 1 = − Im (πœ“π·0 πœ“) ,
where πœ•0 = πœ•/πœ•π‘‘, πœ•1 = πœ•/πœ•π‘₯1 , πœ•2 = πœ•/πœ•π‘₯2 for (𝑑, π‘₯1 , π‘₯2 ) ∈
R1+2 , πœ“ : R1+2 → C is the complex scalar field, 𝐴 πœ‡ : R1+2 →
R is the gauge field, π·πœ‡ = πœ•πœ‡ + 𝑖𝐴 πœ‡ is the covariant derivative
for πœ‡ = 0, 1, 2, and 𝑖 denotes the imaginary unit.
πœ” + 𝐴0 −
(7)
𝑖 󡄨󡄨 󡄨󡄨2
(σ΅„¨πœ™σ΅„¨ − 1) πœ™ = 0.
2 󡄨 󡄨
We note that solutions to the self-dual equations (7) provide
solutions to (1)–(4). For the self-dual potential 𝑉(|πœ™|2 ) =
(1/4)|πœ™|2 (|πœ™|2 − 1)2 , there are two possible boundary conditions to make the energy finite; either |πœ™| → 1 or
|πœ™| → 0 as |π‘₯| → ∞. The former boundary condition is
called “topological” while the latter “non-topological.” A lot
2
Abstract and Applied Analysis
of works have been done for the existence of solutions to the
self-dual system [3–7]. Some existence results for the nonselfdual Chern-Simons-Higgs equations with the topological
boundary condtion have been proved in [8–10]. From the
mathematical point of view, it is meaningful to study existence and nonexistence of nontrivial solutions under various
conditions on 𝑉. In this paper, we are concerned with the
nonexistence of the non-trivial solution to (1)–(4) with the
non-topological boundary condtion. The following is our first
result.
Theorem 1. Let (πœ™, 𝐴 0 , 𝐴 1 , 𝐴 2 ) be a classical solution of (1)–
(4) such that πœ™ ∈ 𝐻1 (R2 ) and 𝐴 0 ∈ 𝐿𝑝 (R2 ), 𝐴 1 , 𝐴 2 ∈ πΏπ‘ž (R2 )
for any 2 < 𝑝, π‘ž ≤ ∞. Let 𝑉 : R → R be a 𝐢1 function
such that 𝑉(0) = 0, inf{π‘₯ > 0 | 𝑉(π‘₯) =ΜΈ 0} = 0 and 𝑉(|πœ™|2 ),
|πœ™|2 𝑉󸀠 (|πœ™|2 ) ∈ 𝐿1 (R2 ). Assume that
σΈ€ 
𝑑𝑉 (𝑠) 𝑠 − 𝑉 (𝑠) ≥ 0 ∀𝑠 ≥ 0,
(8)
where 0 ≤ 𝑑 ≤ 1 is a constant. Then, one has πœ™ ≡ 0.
The proof is based on the following Derrick-Pohozaev
type identity for (1)–(4):
2 󡄨 󡄨2
󡄨
󡄨2 󡄨
󡄨2
∫ 𝑑 (󡄨󡄨󡄨𝐷1 πœ™σ΅„¨σ΅„¨σ΅„¨ + 󡄨󡄨󡄨𝐷2 πœ™σ΅„¨σ΅„¨σ΅„¨ ) + (1 − 𝑑) (πœ” + 𝐴 0 ) σ΅„¨σ΅„¨σ΅„¨πœ™σ΅„¨σ΅„¨σ΅„¨
R2
󡄨 󡄨2 󡄨 󡄨2
󡄨 󡄨2
+ 𝑑𝑉 (σ΅„¨σ΅„¨σ΅„¨πœ™σ΅„¨σ΅„¨σ΅„¨ ) σ΅„¨σ΅„¨σ΅„¨πœ™σ΅„¨σ΅„¨σ΅„¨ − 𝑉 (σ΅„¨σ΅„¨σ΅„¨πœ™σ΅„¨σ΅„¨σ΅„¨ ) 𝑑π‘₯ = 0.
(9)
σΈ€ 
As a typical example, we consider 𝑉(|πœ™|2 ) = 𝛼|πœ™|6 + 𝛽|πœ™|4 .
Then it is easy to check that 𝑑𝑉󸀠 (𝑠)𝑠 − 𝑉(𝑠) = 𝛼(3𝑑 − 1)𝑠3 +
𝛽(2𝑑−1)𝑠2 . If one of the following conditions is satisfied, then
we have πœ™ ≡ 0.
(1) For 𝛼 > 0, 𝛽 > 0, we take 1/2 < 𝑑 < 1.
(2) For 𝛼 > 0, 𝛽 < 0, we take 1/3 < 𝑑 < 1/2.
Note that for the self-dual potential 𝑉(|πœ™|2 ) = (1/4)|πœ™|2 (|πœ™|2 −
1)2 , we have
3𝑑 − 1 3 2𝑑 − 1 2 𝑑 − 1
𝑠 −
𝑠 +
𝑠
4
2
4
(10)
which is not nonnegative for 𝑠 ≥ 0.
The following Chern-Simons gauged Schrödinger system
was proposed in [11] when the second quantized 𝑁 body
anyon problem is considered
πœ•0 𝐴 1 − πœ•1 𝐴 0 = − Im (πœ“π·2 πœ“) ,
πœ•1 𝐴 2 − πœ•2 𝐴 1 = −
1 󡄨󡄨 󡄨󡄨2
σ΅„¨πœ“σ΅„¨ .
2 󡄨 󡄨
(12)
πœ•1 𝐴 0 = Im (πœ™π·2 πœ™) ,
(13)
πœ•2 𝐴 0 = − Im (πœ™π·1 πœ™) ,
(14)
1 󡄨 󡄨2
πœ•1 𝐴 2 − πœ•2 𝐴 1 = − σ΅„¨σ΅„¨σ΅„¨πœ™σ΅„¨σ΅„¨σ΅„¨ .
2
(15)
In the special case with the potential 𝑉(|πœ™|2 ) = −(1/2)|πœ™|4 ,
we can derive the following self dual equations [11–13]
𝐷1 πœ™ + 𝑖𝐷2 πœ™ = 0,
1 󡄨 󡄨2
πœ” + 𝐴 0 − σ΅„¨σ΅„¨σ΅„¨πœ™σ΅„¨σ΅„¨σ΅„¨ = 0,
2
(16)
1 󡄨 󡄨2
πœ•1 𝐴 2 − πœ•2 𝐴 1 + σ΅„¨σ΅„¨σ΅„¨πœ™σ΅„¨σ΅„¨σ΅„¨ = 0.
2
Note that solutions to the self-dual system (16) provide solutions to (12)–(15). The self-dual equations (16) can be transformed into the Liouville equation, an integrable equation
whose solutions are explicitly known.
For the nonself-dual potential of the form 𝑉(|πœ™|2 ) =
−πœ†|πœ™|𝑝 (πœ† > 0, 𝑝 > 2), some existence and nonexistence
results have been studied in [14, 15] under the condition of
the radially symmetric solution πœ“(𝑑, π‘₯) = π‘’π‘–πœ”π‘‘ 𝑒(|π‘₯|) (𝑒 ∈ R).
We prove the following nonexistence result, under various
conditions on 𝑉, for (12)–(15).
Theorem 2. Let (πœ™, 𝐴 0 , 𝐴 1 , 𝐴 2 ) be a classical solution of (1)–
(4) such that πœ™ ∈ 𝐻1 (R2 ), 𝐴 0 ∈ 𝐿𝑝 (R2 ) and 𝐴 1 , 𝐴 2 ∈ πΏπ‘ž (R2 )
for 1 < 𝑝 ≤ ∞ and 2 < π‘ž ≤ ∞. One also assumes that 𝑉 :
R → R is a 𝐢1 function such that 𝑉(0) = 0 and 𝑉(|πœ™|2 ),
|πœ™|2 𝑉󸀠 (|πœ™|2 ) ∈ 𝐿1 (R2 ).
𝑉󸀠 (𝑠) 𝑠 − 𝑉 (𝑠) ≥ 0 ∀𝑠 ≥ 0,
(17)
then one has πœ™ ≡ 0.
(2) Suppose that πœ™ is a real-valued function; that is, πœ™(π‘₯) =
𝑒(π‘₯) ∈ R and 1/𝑝 + 1/π‘ž = 1 for 2 < π‘ž < ∞. If the
potential 𝑉 satisfies, for a constant β„Ž ≥ 2/3,
πœ” (β„Ž − 1) 𝑠 + β„Žπ‘‰σΈ€  (𝑠) 𝑠 − 𝑉 (𝑠) ≥ 0 ∀𝑠 ≥ 0,
(18)
then one has 𝑒 ≡ 0.
The proof is based on the Derrick-Pohozaev type identities (40) and (45) for (12)–(15).
󡄨 󡄨2
𝑖𝐷0 πœ“ + (𝐷1 𝐷1 + 𝐷2 𝐷2 ) πœ“ − 𝑉󸀠 (σ΅„¨σ΅„¨σ΅„¨πœ™σ΅„¨σ΅„¨σ΅„¨ ) πœ™ = 0,
πœ•0 𝐴 2 − πœ•2 𝐴 0 = Im (πœ“π·1 πœ“) ,
󡄨 󡄨2
(πœ” + 𝐴 0 ) πœ™ − 𝐷1 𝐷1 πœ™ − 𝐷2 𝐷2 πœ™ + 𝑉󸀠 (σ΅„¨σ΅„¨σ΅„¨πœ™σ΅„¨σ΅„¨σ΅„¨ ) πœ™ = 0,
(1) If the potential V satisfies
(3) For 𝛼 < 0, 𝛽 < 0, we take 0 < 𝑑 < 1/3.
𝑑𝑉󸀠 (𝑠) 𝑠 − 𝑉 (𝑠) =
With the stationary solution ansatz πœ“(𝑑, π‘₯) = π‘’π‘–πœ”π‘‘ πœ™(π‘₯), πœ™ ∈ C
and 𝐴 πœ‡ (𝑑, π‘₯) = 𝐴 πœ‡ (π‘₯) for πœ‡ = 0, 1, 2, we arrive at
(11)
Example 3. For the static solution (πœ” = 0), we consider the
potential 𝑉(𝑠) = 𝑠3 − 𝑠2 − 𝑠. Then, taking β„Ž = 2/3, we can
check
2 σΈ€ 
1
1
𝑉 (|𝑒|2 ) |𝑒|2 − 𝑉 (|𝑒|2 ) = |𝑒|6 − |𝑒|4 + |𝑒|2 ≥ 0. (19)
3
3
3
Abstract and Applied Analysis
3
However we have, for the complex solution,
󡄨 󡄨2 󡄨 󡄨2
󡄨 󡄨6 󡄨 󡄨4
󡄨 󡄨2
𝑉󸀠 (σ΅„¨σ΅„¨σ΅„¨πœ™σ΅„¨σ΅„¨σ΅„¨ ) σ΅„¨σ΅„¨σ΅„¨πœ™σ΅„¨σ΅„¨σ΅„¨ − 𝑉 (σ΅„¨σ΅„¨σ΅„¨πœ™σ΅„¨σ΅„¨σ΅„¨ ) = 2σ΅„¨σ΅„¨σ΅„¨πœ™σ΅„¨σ΅„¨σ΅„¨ − σ΅„¨σ΅„¨σ΅„¨πœ™σ΅„¨σ΅„¨σ΅„¨
For II, we have
(20)
which is not nonnegative.
The paper is organized as follows. In Section 2, we
prove Theorem 1 by deriving Derrick-Pohozaev type identity.
Theorem 2 is proved in Section 3. We conclude this section
by giving a few notations.
󡄨
󡄨2
II = ∫ πœ•π‘— (π‘₯π‘˜ 𝐷𝑗 πœ™π·π‘˜ πœ™) − 󡄨󡄨󡄨󡄨𝐷𝑗 πœ™σ΅„¨σ΅„¨σ΅„¨σ΅„¨ − π‘₯π‘˜ 𝐷𝑗 πœ™π·π‘— π·π‘˜ πœ™π‘‘π‘₯
𝐡𝑅
= ∫
π‘₯𝑗 π‘₯π‘˜
𝑅
πœ•π΅π‘…
𝐷𝑗 πœ™π·π‘˜ πœ™π‘‘πœŽπ‘…
󡄨
󡄨2
− ∫ 󡄨󡄨󡄨󡄨𝐷𝑗 πœ™σ΅„¨σ΅„¨σ΅„¨σ΅„¨ 𝑑π‘₯ − ∫ π‘₯π‘˜ 𝐷𝑗 πœ™ (π·π‘˜ 𝐷𝑗 πœ™ + π‘–πΉπ‘—π‘˜ πœ™)𝑑π‘₯,
𝐡
𝐡
𝑅
𝑅
(24)
(i) 𝐻1 (R2 ) denotes the usual Sobolev space π‘Š1,2 (R2 ).
(ii) 𝐡𝑅 := {π‘₯ ∈ R2 | |π‘₯| ≤ 𝑅} and πœ•π΅π‘… := {π‘₯ ∈ R2 | |π‘₯| =
𝑅}.
where we used the notation πΉπ‘—π‘˜ = πœ•π‘— 𝐴 π‘˜ − πœ•π‘˜ 𝐴 𝑗 and the following identity:
𝐷𝑗 π·π‘˜ πœ™ = π·π‘˜ 𝐷𝑗 πœ™ + π‘–πΉπ‘—π‘˜ πœ™.
(iii) π‘‘πœŽπ‘… := the surface measure on πœ•π΅π‘… .
(25)
Taking the real parts and integrating by parts, we obtain
2. Proof of Theorem 1
π‘₯𝑗 π‘₯π‘˜
󡄨
󡄨2
𝐷𝑗 πœ™π·π‘˜ πœ™ π‘‘πœŽπ‘… − ∫ 󡄨󡄨󡄨󡄨𝐷𝑗 πœ™σ΅„¨σ΅„¨σ΅„¨σ΅„¨ 𝑑π‘₯
𝑅
𝐡𝑅
Re {II} = ∫
πœ•π΅π‘…
We apply Derrick-Pohozaev argument to derive the identity
(9) which prove Theorem 1. From now on, we adopt the
summation convention for repeated indices.
Suppose that (πœ™, 𝐴 0 , 𝐴 1 , 𝐴 2 ) is a solution of (1)–(4).
Multiplying (1) by π‘₯π‘˜ π·π‘˜ πœ™ and integrating over 𝐡𝑅 , we obtain
−∫
𝐡𝑅
1
󡄨
󡄨2
π‘₯π‘˜ πœ•π‘˜ (󡄨󡄨󡄨󡄨𝐷𝑗 πœ™σ΅„¨σ΅„¨σ΅„¨σ΅„¨ ) 𝑑π‘₯
2
− ∫ π‘₯π‘˜ πΉπ‘—π‘˜ Im (πœ™π·π‘— πœ™) 𝑑π‘₯
𝐡𝑅
2
− ∫ (πœ” + 𝐴 0 ) πœ™ π‘₯π‘˜ π·π‘˜ πœ™ 𝑑π‘₯ − ∫ 𝐷𝑗 𝐷𝑗 πœ™ π‘₯π‘˜ π·π‘˜ πœ™ 𝑑π‘₯
𝐡𝑅
𝐡𝑅
󡄨 󡄨2
+ ∫ 𝑉 (σ΅„¨σ΅„¨σ΅„¨πœ™σ΅„¨σ΅„¨σ΅„¨ ) πœ™π‘₯π‘˜ π·π‘˜ πœ™ 𝑑π‘₯ = 0.
𝐡
π‘₯𝑗 π‘₯π‘˜
= ∫
𝑅
πœ•π΅π‘…
(21)
σΈ€ 
+∫
𝑅
𝐡𝑅
Now we set
𝐷𝑗 πœ™π·π‘˜ πœ™ π‘‘πœŽπ‘… − ∫
πœ•π΅π‘…
𝑅 󡄨󡄨
󡄨2
󡄨󡄨𝐷 πœ™σ΅„¨σ΅„¨σ΅„¨ π‘‘πœŽ
2󡄨 𝑗 󡄨 𝑅
1 󡄨󡄨 󡄨󡄨2
󡄨 󡄨2
2
σ΅„¨πœ™σ΅„¨ π‘₯ πœ• (𝐴 ) 𝑑π‘₯ + ∫ πœ”σ΅„¨σ΅„¨σ΅„¨πœ™σ΅„¨σ΅„¨σ΅„¨ π‘₯𝑗 πœ•π‘— 𝐴 0 𝑑π‘₯,
2󡄨 󡄨 𝑗 𝑗 0
𝐡𝑅
(26)
where we used (2)–(4) in the following way:
2
I = ∫ (πœ” + 𝐴 0 ) πœ™π‘₯π‘˜ π·π‘˜ πœ™π‘‘π‘₯,
− ∫ π‘₯1 𝐹21 Im (πœ™π·2 πœ™) + π‘₯2 𝐹12 Im (πœ™π·1 πœ™) 𝑑π‘₯
𝐡𝑅
𝐡𝑅
II = ∫ 𝐷𝑗 𝐷𝑗 πœ™π‘₯π‘˜ π·π‘˜ πœ™π‘‘π‘₯,
𝐡𝑅
𝑅
󡄨 󡄨2
III = ∫ 𝑉󸀠 (σ΅„¨σ΅„¨σ΅„¨πœ™σ΅„¨σ΅„¨σ΅„¨ ) πœ™π‘₯π‘˜ π·π‘˜ πœ™π‘‘π‘₯.
𝐡
Combining (23) and (26), we have from the identity (21)
𝑅
Then, integrating by parts and taking real parts, we have
Re {I} = ∫
πœ•π΅π‘…
𝐡𝑅
Re {III} = ∫
πœ•π΅π‘…
1
󡄨 󡄨2
π‘₯ πœ• (𝐴2 ) σ΅„¨σ΅„¨πœ™σ΅„¨σ΅„¨ 𝑑π‘₯,
2 𝑗 𝑗 0 󡄨 󡄨
𝑅 󡄨󡄨 󡄨󡄨2
󡄨 󡄨2
𝑉 (σ΅„¨σ΅„¨πœ™σ΅„¨σ΅„¨ ) π‘‘πœŽπ‘₯ − ∫ 𝑉 (σ΅„¨σ΅„¨σ΅„¨πœ™σ΅„¨σ΅„¨σ΅„¨ ) 𝑑π‘₯.
2
𝐡𝑅
𝑅
−
𝑅
−∫
𝑅
π‘₯𝑗 π‘₯π‘˜
πœ•π΅π‘…
2 󡄨 󡄨2
− ∫ (πœ” + 𝐴 0 ) σ΅„¨σ΅„¨σ΅„¨πœ™σ΅„¨σ΅„¨σ΅„¨ 𝑑π‘₯
𝐡
𝑅
2 󡄨 󡄨2
󡄨 󡄨2
∫ (πœ” + 𝐴 0 ) σ΅„¨σ΅„¨σ΅„¨πœ™σ΅„¨σ΅„¨σ΅„¨ 𝑑π‘₯ − ∫ 𝑉 (σ΅„¨σ΅„¨σ΅„¨πœ™σ΅„¨σ΅„¨σ΅„¨ ) 𝑑π‘₯
𝐡
𝐡
=∫
𝑅
2 󡄨 󡄨2
(πœ” + 𝐴 0 ) σ΅„¨σ΅„¨σ΅„¨πœ™σ΅„¨σ΅„¨σ΅„¨ π‘‘πœŽπ‘₯
2
󡄨 󡄨2
− ∫ πœ”πœ•π‘— 𝐴 0 π‘₯𝑗 σ΅„¨σ΅„¨σ΅„¨πœ™σ΅„¨σ΅„¨σ΅„¨ 𝑑π‘₯
𝐡
(27)
󡄨 󡄨2
= ∫ π‘₯𝑗 σ΅„¨σ΅„¨σ΅„¨πœ™σ΅„¨σ΅„¨σ΅„¨ (πœ” + 𝐴 0 ) πœ•π‘— 𝐴 0 𝑑π‘₯.
𝐡
(22)
(23)
𝑅
Re (𝐷𝑗 πœ™ π·π‘˜ πœ™) −
𝑅 󡄨󡄨
󡄨2
󡄨󡄨𝐷 πœ™σ΅„¨σ΅„¨σ΅„¨
2󡄨 𝑗 󡄨
(28)
𝑅 󡄨󡄨 󡄨󡄨2
𝑅
2 󡄨 󡄨2
𝑉 (σ΅„¨σ΅„¨πœ™σ΅„¨σ΅„¨ ) + (πœ” + 𝐴 0 ) σ΅„¨σ΅„¨σ΅„¨πœ™σ΅„¨σ΅„¨σ΅„¨ π‘‘πœŽπ‘… .
2
2
Thus we have
󡄨󡄨
󡄨󡄨
󡄨
󡄨󡄨
󡄨󡄨∫ (πœ” + 𝐴 0 )2 σ΅„¨σ΅„¨σ΅„¨σ΅„¨πœ™σ΅„¨σ΅„¨σ΅„¨σ΅„¨2 − 𝑉 (σ΅„¨σ΅„¨σ΅„¨σ΅„¨πœ™σ΅„¨σ΅„¨σ΅„¨σ΅„¨2 ) 𝑑π‘₯󡄨󡄨󡄨
󡄨󡄨
󡄨󡄨󡄨 𝐡𝑅
󡄨
≤ 𝐢∫
πœ•π΅π‘…
󡄨
󡄨2
󡄨 󡄨2
𝑅 (󡄨󡄨󡄨󡄨𝐷𝑗 πœ™σ΅„¨σ΅„¨σ΅„¨σ΅„¨ + πœ”2 σ΅„¨σ΅„¨σ΅„¨πœ™σ΅„¨σ΅„¨σ΅„¨
󡄨 󡄨2 󡄨 󡄨2
󡄨 󡄨2
+󡄨󡄨󡄨𝐴 0 󡄨󡄨󡄨 σ΅„¨σ΅„¨σ΅„¨πœ™σ΅„¨σ΅„¨σ΅„¨ + 𝑉 (σ΅„¨σ΅„¨σ΅„¨πœ™σ΅„¨σ΅„¨σ΅„¨ )) π‘‘πœŽπ‘… ,
(29)
4
Abstract and Applied Analysis
where 𝐢 is a positive constant. Considering the Sobolev
embedding and the condition of Theorem 1, we know that
|𝐷𝑗 πœ™|2 , πœ”2 |πœ™|2 , |𝐴 0 |2 |πœ™|2 , 𝑉(|πœ™|2 ) ∈ 𝐿1 (R2 ). Applying the idea
in [16], we know that there exists a sequence {𝑅𝑛 } → ∞ such
that
∫
πœ•π΅π‘…π‘›
Now we set
I = ∫ (πœ” + 𝐴 0 ) πœ™ π‘₯π‘˜ π·π‘˜ πœ™ 𝑑π‘₯,
𝐡𝑅
II = ∫ 𝐷𝑗 𝐷𝑗 πœ™ π‘₯π‘˜ π·π‘˜ πœ™ 𝑑π‘₯,
(35)
𝐡𝑅
󡄨
󡄨2
󡄨 󡄨2 󡄨 󡄨2 󡄨 󡄨2
󡄨 󡄨2
𝑅𝑛 (󡄨󡄨󡄨󡄨𝐷𝑗 πœ™σ΅„¨σ΅„¨σ΅„¨σ΅„¨ + πœ”2 σ΅„¨σ΅„¨σ΅„¨πœ™σ΅„¨σ΅„¨σ΅„¨ + 󡄨󡄨󡄨𝐴 0 󡄨󡄨󡄨 σ΅„¨σ΅„¨σ΅„¨πœ™σ΅„¨σ΅„¨σ΅„¨ + 𝑉 (σ΅„¨σ΅„¨σ΅„¨πœ™σ΅„¨σ΅„¨σ΅„¨ )) π‘‘πœŽπ‘…π‘›
󡄨 󡄨2
III = ∫ 𝑉󸀠 (σ΅„¨σ΅„¨σ΅„¨πœ™σ΅„¨σ΅„¨σ΅„¨ ) πœ™ π‘₯π‘˜ π·π‘˜ πœ™ 𝑑π‘₯.
𝐡𝑅
󳨀→ 0,
(30)
Re {I} = ∫
and consequently
πœ•π΅π‘…
2 󡄨 󡄨2
󡄨 󡄨2
∫ (πœ” + 𝐴 0 ) σ΅„¨σ΅„¨σ΅„¨πœ™σ΅„¨σ΅„¨σ΅„¨ − 𝑉 (σ΅„¨σ΅„¨σ΅„¨πœ™σ΅„¨σ΅„¨σ΅„¨ ) 𝑑π‘₯
R2
= lim ∫
𝑛→∞ 𝐡
𝑅𝑛
Then, integrating by parts and taking real parts, we have
𝐡𝑅
(31)
󡄨 󡄨2
0 = ∫ πœ™ (−(πœ” + 𝐴 0 ) πœ™ − 𝐷𝑗 𝐷𝑗 πœ™ + 𝑉 (σ΅„¨σ΅„¨σ΅„¨πœ™σ΅„¨σ΅„¨σ΅„¨ ) πœ™) 𝑑π‘₯
2
R
−∫
𝐡𝑅
(32)
󡄨 󡄨2 󡄨 󡄨2
󡄨 󡄨2
+ 𝑑𝑉󸀠 (σ΅„¨σ΅„¨σ΅„¨πœ™σ΅„¨σ΅„¨σ΅„¨ ) σ΅„¨σ΅„¨σ΅„¨πœ™σ΅„¨σ΅„¨σ΅„¨ − 𝑉 (σ΅„¨σ΅„¨σ΅„¨πœ™σ΅„¨σ΅„¨σ΅„¨ ) 𝑑π‘₯ = 0,
𝑅 󡄨󡄨 󡄨󡄨2
󡄨 󡄨2
𝑉 (σ΅„¨σ΅„¨πœ™σ΅„¨σ΅„¨ ) π‘‘πœŽπ‘₯ − ∫ 𝑉 (σ΅„¨σ΅„¨σ΅„¨πœ™σ΅„¨σ΅„¨σ΅„¨ ) 𝑑π‘₯.
2
𝐡𝑅
󡄨 󡄨2
󡄨 󡄨2
∫ 𝑉 (σ΅„¨σ΅„¨σ΅„¨πœ™σ΅„¨σ΅„¨σ΅„¨ ) + (πœ” + 𝐴 0 ) σ΅„¨σ΅„¨σ΅„¨πœ™σ΅„¨σ΅„¨σ΅„¨ 𝑑π‘₯
𝐡𝑅
=∫
πœ•π΅π‘…
−
π‘₯𝑗 π‘₯π‘˜
𝑅
Re (𝐷𝑗 πœ™ π·π‘˜ πœ™) +
𝑅 󡄨󡄨
󡄨2
󡄨󡄨𝐷 πœ™σ΅„¨σ΅„¨σ΅„¨
2󡄨 𝑗 󡄨
(37)
𝑅 󡄨󡄨 󡄨󡄨2
𝑅
󡄨 󡄨2
𝑉 (σ΅„¨σ΅„¨πœ™σ΅„¨σ΅„¨ ) + (πœ” + 𝐴 0 ) σ΅„¨σ΅„¨σ΅„¨πœ™σ΅„¨σ΅„¨σ΅„¨ π‘‘πœŽπ‘… .
2
2
Applying the same argument in Section 2, the right hand side
of the above equality vanishes. Then we conclude that
+
Repeating the similar argument to the proof of Theorem 1,
we derive Derrick-Pohozaev type identities for (12)–(15).
Suppose that (πœ™, 𝐴 0 , 𝐴 1 , 𝐴 2 ) is a solution of (12)–(15). Multiplying (12) by π‘₯π‘˜ π·π‘˜ πœ™ and integrating over 𝐡𝑅 , we obtain
∫ (πœ” + 𝐴 0 ) πœ™ π‘₯π‘˜ π·π‘˜ πœ™ 𝑑π‘₯ − ∫ 𝐷𝑗 𝐷𝑗 πœ™ π‘₯π‘˜ π·π‘˜ πœ™ 𝑑π‘₯
𝑅
1
󡄨 󡄨2
π‘₯ πœ• 𝐴 σ΅„¨σ΅„¨πœ™σ΅„¨σ΅„¨ 𝑑π‘₯,
2 𝑗 𝑗 0󡄨 󡄨
πœ•π΅π‘…
(33)
3. Proof of Theorem 2
󡄨 󡄨2
+ ∫ 𝑉󸀠 (σ΅„¨σ΅„¨σ΅„¨πœ™σ΅„¨σ΅„¨σ΅„¨ ) πœ™ π‘₯π‘˜ π·π‘˜ πœ™ 𝑑π‘₯ = 0.
𝐡
πœ•π΅π‘…
𝑅 󡄨󡄨
󡄨2
󡄨󡄨𝐷𝑗 πœ™σ΅„¨σ΅„¨σ΅„¨ π‘‘πœŽπ‘…
󡄨
󡄨
2
Then we have from the identity (34)
where 0 ≤ 𝑑 ≤ 1 is a constant. We are ready to prove
Theorem 1.
(1) For 0 < 𝑑 ≤ 1, we have 𝐷𝑗 πœ™ ≡ 0. If πœ™(π‘₯0 ) =ΜΈ 0, then
there exists 𝛿 > 0 such that πœ™(π‘₯) =ΜΈ 0 for 𝐡π‘₯0 (𝛿) = {π‘₯ | |π‘₯ −
π‘₯0 | < 𝛿}. In the region 𝐡π‘₯0 (𝛿), we have 𝐴 𝑗 = 𝑖(πœ•π‘— πœ™/πœ™). Using
(4) we have 𝐴 0 (π‘₯) + πœ” = 0 in 𝐡π‘₯0 (𝛿). On the other hand, from
(2) and (3), we deduce that 𝐴 0 (π‘₯) = constant = −πœ”. By (1),
we obtain 𝑉󸀠 (|πœ™|2 )πœ™ = 0 for all π‘₯ ∈ R2 . By the condition of 𝑉󸀠
and πœ™ ∈ 𝐿2 , we conclude that πœ™ ≡ 0.
(2) For 𝑑 = 0, we have 𝑉(|πœ™|2 ) = 0. By the condition of 𝑉
and πœ™ ∈ 𝐿2 , we have πœ™ ≡ 0.
𝐡𝑅
Re {III} = ∫
𝐷𝑗 πœ™π·π‘˜ πœ™ π‘‘πœŽπ‘… − ∫
(36)
by taking care of the boundary integral terms as before. Combining (31) and (32), we obtain
󡄨
󡄨2
2 󡄨 󡄨2
∫ 𝑑󡄨󡄨󡄨󡄨𝐷𝑗 πœ™σ΅„¨σ΅„¨σ΅„¨σ΅„¨ + (1 − 𝑑) (πœ” + 𝐴 0 ) σ΅„¨σ΅„¨σ΅„¨πœ™σ΅„¨σ΅„¨σ΅„¨
2
R
𝑅
πœ•π΅π‘…
σΈ€ 
󡄨
󡄨2
2 󡄨 󡄨2
󡄨 󡄨2 󡄨 󡄨2
= ∫ −(πœ” + 𝐴 0 ) σ΅„¨σ΅„¨σ΅„¨πœ™σ΅„¨σ΅„¨σ΅„¨ + 󡄨󡄨󡄨󡄨𝐷𝑗 πœ™σ΅„¨σ΅„¨σ΅„¨σ΅„¨ + 𝑉󸀠 (σ΅„¨σ΅„¨σ΅„¨πœ™σ΅„¨σ΅„¨σ΅„¨ ) σ΅„¨σ΅„¨σ΅„¨πœ™σ΅„¨σ΅„¨σ΅„¨ 𝑑π‘₯,
2
R
π‘₯𝑗 π‘₯π‘˜
Re {II} = ∫
On the other hand, we know from (1) that
𝐡𝑅
1
󡄨 󡄨2
π‘₯ πœ• 𝐴 σ΅„¨σ΅„¨πœ™σ΅„¨σ΅„¨ 𝑑π‘₯,
2 𝑗 𝑗 0󡄨 󡄨
−∫
2 󡄨 󡄨2
󡄨 󡄨2
(πœ” + 𝐴 0 ) σ΅„¨σ΅„¨σ΅„¨πœ™σ΅„¨σ΅„¨σ΅„¨ − 𝑉 (σ΅„¨σ΅„¨σ΅„¨πœ™σ΅„¨σ΅„¨σ΅„¨ ) 𝑑π‘₯ = 0.
2
𝑅
󡄨 󡄨2
󡄨 󡄨2
(πœ” + 𝐴 0 ) σ΅„¨σ΅„¨σ΅„¨πœ™σ΅„¨σ΅„¨σ΅„¨ π‘‘πœŽπ‘₯ − ∫ (πœ” + 𝐴 0 ) σ΅„¨σ΅„¨σ΅„¨πœ™σ΅„¨σ΅„¨σ΅„¨ 𝑑π‘₯
2
𝐡𝑅
(34)
󡄨 󡄨2
󡄨 󡄨2
∫ 𝑉 (σ΅„¨σ΅„¨σ΅„¨πœ™σ΅„¨σ΅„¨σ΅„¨ ) + (πœ” + 𝐴 0 ) σ΅„¨σ΅„¨σ΅„¨πœ™σ΅„¨σ΅„¨σ΅„¨ 𝑑π‘₯ = 0.
R2
(38)
On the other hand, we know from (12)
󡄨2
󡄨 󡄨2 󡄨
󡄨 󡄨2 󡄨 󡄨2
∫ (πœ” + 𝐴 0 ) σ΅„¨σ΅„¨σ΅„¨πœ™σ΅„¨σ΅„¨σ΅„¨ + 󡄨󡄨󡄨󡄨𝐷𝑗 πœ™σ΅„¨σ΅„¨σ΅„¨σ΅„¨ + 𝑉󸀠 (σ΅„¨σ΅„¨σ΅„¨πœ™σ΅„¨σ΅„¨σ΅„¨ ) σ΅„¨σ΅„¨σ΅„¨πœ™σ΅„¨σ΅„¨σ΅„¨ 𝑑π‘₯ = 0.
R2
(39)
Combining (38) and (39), we end up with
󡄨
󡄨2
󡄨 󡄨2
󡄨 󡄨2 󡄨 󡄨2
∫ 󡄨󡄨󡄨󡄨𝐷𝑗 πœ™σ΅„¨σ΅„¨σ΅„¨σ΅„¨ + 𝑉󸀠 (σ΅„¨σ΅„¨σ΅„¨πœ™σ΅„¨σ΅„¨σ΅„¨ ) σ΅„¨σ΅„¨σ΅„¨πœ™σ΅„¨σ΅„¨σ΅„¨ − 𝑉 (σ΅„¨σ΅„¨σ΅„¨πœ™σ΅„¨σ΅„¨σ΅„¨ ) 𝑑π‘₯ = 0.
2
R
(40)
Following the reasoning in Theorem 1, we deduce πœ™ ≡ 0 from
the fact 𝐷𝑗 πœ™ ≡ 0.
For the proof of the second result in Theorem 2, we
assume πœ™(π‘₯) = 𝑒(π‘₯) ∈ R. Then (13)–(15) can be rewritten
by
πœ•1 𝐴 0 = 𝐴 2 𝑒2 ,
πœ•2 𝐴 0 = −𝐴 1 𝑒2 ,
1
πœ•1 𝐴 2 − πœ•2 𝐴 1 = − 𝑒2 .
2
(41)
Abstract and Applied Analysis
5
It is easy to check the following identity:
1
πœ•1 (𝐴 2 𝐴 0 ) − πœ•2 (𝐴 1 𝐴 0 ) = (𝐴21 + 𝐴22 − 𝐴 0 ) 𝑒2 ,
2
(42)
from which we derive, with the condition 𝐴 0 ∈ 𝐿𝑝 , 𝐴 1 , 𝐴 2 ∈
πΏπ‘ž for 1/𝑝 + 1/π‘ž = 1, 2 < π‘ž < ∞,
∫
R2
1
𝐴 𝑒2 𝑑π‘₯ = ∫ (𝐴21 + 𝐴22 ) 𝑒2 𝑑π‘₯.
2 0
𝑅2
(43)
Considering |𝐷𝑗 𝑒|2 = |∇𝑒|2 + (𝐴21 + 𝐴22 )𝑒2 , we have from (38)
and (39)
∫ 𝑉 (|𝑒|2 ) + πœ”|𝑒|2 + 2 (𝐴21 + 𝐴22 ) 𝑒2 𝑑π‘₯ = 0,
R2
∫ |∇𝑒|2 + 3 (𝐴21 + 𝐴22 ) 𝑒2 + πœ”|𝑒|2 + 𝑉󸀠 (|𝑒|2 ) |𝑒|2 𝑑π‘₯ = 0.
R2
(44)
Then we obtain, for a constant β„Ž ≥ 2/3,
∫ β„Ž|∇𝑒|2 + (3β„Ž − 2) (𝐴21 + 𝐴22 ) 𝑒2 + πœ” (β„Ž − 1) |𝑒|2
R2
σΈ€ 
2
2
(45)
2
+ β„Žπ‘‰ (|𝑒| ) |𝑒| − 𝑉 (|𝑒| ) 𝑑π‘₯ = 0,
which proves the second result in Theorem 2.
Acknowledgments
The author was supported by Basic Science Research Program
through the National Research Foundation of Korea (NRF)
funded by the Ministry of Education, Science and Technology
(2011-0015866) and also partially supported by the TJ Park
Junior Faculty Fellowship.
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