Gen. Math. Notes, Vol. 16, No. 1, May, 2013, pp. 40-48 ISSN 2219-7184; Copyright © ICSRS Publication, 2013 www.i-csrs.org Available free online at http://www.geman.in The Inversion of an Integral Equation Pertaining to a Generalized Polynomial Set V.B.L. Chaurasia1 and J.C. Arya2 1 Department of Mathematics, University of Rajasthan Jaipur-302004, India E-mail: drvblc@yahoo.com 2 Department of Mathematics, Govt. Post Graduate College Neemuch-458441 (M.P.), India E-mail: profarya76@gmail.com (Received: 4-2-13 / Accepted: 5-3-13) Abstract The main object of this paper is to evaluate a certain class of convolution integral equation of Fredholm type with n-generalized polynomial sets. Here, the integral equation is solved by applying the Mellin transform. Keywords: Mellin Transform, convolution integral equation, generalized polynomial set. 1 Introduction This paper deals with the investigation of the inversion of the integral ∏ i =1,...,n g i ( x) = ∞ ∏ ∫0 i =1,...,n x dy h i f i ( y) , ( x > 0), y y …(1) The Inversion of an Integral Equation… 41 Where gi is a prescribed function, fi is an unknown function to be determined and the kernel hi is given by ( a x αi + b ) pi ( c x βi + d ) qi i i i Kn ∏ h i ( x) = ∏ i ξi i − t x i =1,...,n i =1,...,n e i p i ,q i . Rn i [ x, a i , b i , c i , d i ; α i , β i , γ i , δ i ; e −ti x ξi ξ θi ni αi pi + γ i n i βi q i + δi n i − t i x i = ∏ {x ( φ + xD x )} {( a i x + b i ) (ci x + d i ) e } i =1,...,n …(2) q [ x] is introduced by Agrawal and Chaubey [1] by Where the polynomial set R p, n means of the following formula q q R p, [ x] = R p, [ x, a, b, c, d ; α, β, γ, δ ; ω( x)] n n = ( ax α + b) − p ( cx β + d) −q n Tθ,φ [( ax α + b) p + γn ( cx β + d) q +δn ω( x)], n = 0,1,2,... K n ω( x) …(3) Where Tθn,φ = x θ ( φ + x D x ) , D x = d dx …(4) {K n }∞n =0 is a sequence of constants, a,b,c,d, α,β,γ,δ,p,q are constants and ω(x) is any general function of x, differentiable an arbitrary number of times. The polynomial R np,q [ x] is general in nature and yields a number of known polynomials as its special cases. In particular α = β = 1, Kn = n!, φ = 0, θ = &1, the polynomial set R np,q [ x] reduces to S np,q [ x, a, b, c, d; γ, δ; ω( x)], given by Srivastava and Panda [6]. 42 V.B.L. Chaurasia et al. 2 Lemma ∏ We begin with Lemma involving the Mellin transform of i =1,...,n h i ( x) which is as follows: If ∏ i =1,...,n H i (s) = ∏ i =1,...,n M {h i ( x) ; s } where ni ∏ H i (s) = ∏ ∑ i =1,...,n i =1,...,n k i =0 . ( −q i − δ i n i ) m mi ! i (φ) n i −ki pi + γ i n i qi + δi n i ∑ ∑ ℓ i =0 (bi ) ( −1) ∏ i =1,...,n h i ( x) is defined by (2), then k i + ℓ i + mi ( −n i ) k ( − p i − γ i n i ) ℓ i ki ! mi =0 pi + γ i n i − ℓ i (d i ) q i + δi n i − m i i ℓi ! m ℓ (a i ) i ( c i ) i ( θi ) ki s + θ n + α ℓ +β m i i i i i i ξi − s + θ n 1 s + θ n + α ℓ + β m i i i i i i i i . − (ti ) Γ ξi θ i k | ξ i | , i …(5) Provided that 0 < Re (s + θ i n i + α i ℓ i + β i m i ) < ξ i , when ξ i > 0; ξ i < Re (s + θ i n i + α i ℓ i + β i m i ) < 0, when ξ i < 0; θ i ≠ 0 and n i , ( p i + γ i n i ), ( q i + δ i n i ) ∈ N 0 , where i = 1,..., n Proof: θ n Using binomial expansions for [ x i ( φ + x D x )] i , ( a i x (ci x βi + di ) qi + δi n i αi + bi ) pi + γ i n i in (2), we get ni ∏ h i ( x) = ∏ ∑ i =1,...,n i =1,...,n k i =0 p i + γ i n i q i + δi n i ∑ ∑ ℓ i =0 ( −1) k i + ℓ i + mi ( − n i ) k ( −p i − γ i n i ) ℓ mi =0 i ki ! i ℓi ! . ( −q i − δ i n i ) m mi ! i ( φ) and n i −ki (bi ) pi + γ i n i − ℓ i (d i ) q i + δi n i − m i ℓ (a i ) i (ci ) mi x θi ( n i − k i ) . The Inversion of an Integral Equation… . θ +1 (x i D ki ) {x x αiℓ i +βi mi e ξ − ti x i 43 } . …(6) Now applying Mellin transform of both sides of the equation (6) and using known results [9, p.14, eq. (2.2)]; [5, p.307,eq.(7)]. We find that ni ∏ H i (s) = ∏ ∑ i =1,...,n i =1,...,n k i =0 . ( −q i − δ i n i ) m i mi ! pi + γ i n i qi + δi n i ∑ ∑ ℓ i =0 mi =0 n i −ki (bi ) (φ) ( −1) k i + ℓ i + mi pi + γ i n i − ℓ i (d i ) ( −n i ) k ( − p i − γ i n i ) ℓ i ki ! q i + δi n i − m i i ℓi ! ℓ m ( a i ) i (c i ) i (θi ) s + θ n αiℓ i +βimi − ti x ξi i i . − , s + θ i n i e M x θ i k i ki …(7) Again, using [5, p.307, eq. (7)] and the known result [5, p.313, eq. (15)] h M {(e −ax ); s} = 1 -(s/h) s a Γ , |h| h …(8) We arrive at the required result (3). 3 Solution of the Integral Equation (1) Theorem: Let the Mellin transforms Fi(s), Gi(s) and Hi(s) ≠ 0 of the functions fi(x), gi(x) and hi(x) defined by (2) exist and be analytic in some infinite strip ηi < Re(s) < λi of the complex s-plane. Also suppose that for a fixed σi ∈ (ηi, λi), h *i ( x) is defined by ∏ i =1,...,n h *i ( x) = = ∏ i =1,...,n i =1,...,n H *i (s) σ + ω∞ i 1 ∏ 2πω ∫σ −ω∞ x −s H *i (s) ds, i =1,...,n i Where ω = − 1 , ∏ [M −1 {H *i (s); x}] …(9) 44 V.B.L. Chaurasia et al. E = ∏ Bi i i =1,...,n s Γ − ni B i ∑ k =0 s Γ − E i − i Bi pi + γi n i q i +δi n i ∑ ∑ ℓ i =0 ( −1) k i + ℓ i + mi mi =0 ( −n i ) k ( −p i − γ i n i ) ℓ i ki ! ℓi ! . . ( −q i − δ i n i ) m mi ! i ( φ) n i −ki (bi ) pi + γ i n i − ℓ i (d i ) qi + δi n i − mi ℓi (a i ) (ci ) mi ( θi ) ki | ξi | . −1 s + θi n i + Bi E i + C i s + Bi E i + C i + θi n i + α i ℓ i + βi m i Γ Γ 1 + θ ξ i i , . s + B E + C + θ n + α ℓ +β m i i i i i i i i i s + θi n i + Bi E i + C i ξi Γ − k i + 1 ( t i ) θ i …(10) provided that 0 < Re (s + Bi E i + C i + θ i n i + α i ℓ i + β i m i ) < ξ i , when ξ i > 0; ξ i < Re(s + Bi E i + C i + θ i n i + α i ℓ i + β i m i ) < 0, when ξ i < 0 ; ξ i , Bi ; θ i ≠ 0 n i , (p i + γ i n i ) , ( q i + δ i n i ) ∈ N 0 , where i = 1,..., n. Then the integral equation (1) has its solution given by −BiEi −Ci ∞ −1 * x Bi +1 Ei Ci y h ( y D ) { y g ( y)} dy ∏ f i ( x) = ∏ x , ∫0 i y y i i =1,...,n i =1,...,n …(11) provided that the integral exists. Proof: By convolution Theorem for Mellin transforms [5, p.308, eq.(14)], equation (1) changes into ∏ i =1,...,n H i (s) Fi (s) = ∏ i =1,...,n G i (s), …(12) i The Inversion of an Integral Equation… 45 Where Hi(s), Fi(s) and Gi(s) are Mellin transforms of hi(x), fi(x) and gi(x) respectively. Replacing s in (12) by (s+BiEi+Ci), we have ∏ i =1,...,n Fi (s + Bi E i + C i ) * Ei s + Bi E i = ∏ H i (s) Bi − G i ( s + B i E i + C i ) , B i =1,...,n i E i …(13) Where H *i ( s) is given by (10). Now by using known results [6, p.14, eq.(2.2)] and [5, p.307, eq. (7)], we obtain ∏ i =1,...,n Fi (s + Bi E i + C i ) = ∏ i =1,...,n H *i (s) [M{(y Bi +1 D y ) Ei C y i g i ( y)}dy ; s] …(14) and by using the known results [5, p.307, eq. (7) and [5, p.308, eq. (14)] in (14), we have ∏ M [x Bi Ei +Ci i =1,...,n = f i ( x); s ] ∞ −1 * x B +1 E C ∏ M ∫0 y h i y ( y i D y ) i ( y i g i ( y)) dy ; s , i =1,...,n …(15) Inverting both sides of (15) by using the Mellin inversion Theorem [5, p.307, eq. (1)], we arrive at the required solution (11). 4 Applications 4.1. By setting i = 1 to 3 in (2), we have the following corollary Corollary: The convolution integral equation ∏ i =1,2,3 g i ( x) = ∞ ∏ ∫0 i =1,2,3 Where, the kernel x y −1h i f i ( y) dy, y (x > 0) …(16) 46 V.B.L. Chaurasia et al. ( a x αi + b ) pi ( c x βi + d ) qi i i i Kn ∏ h i ( x) = ∏ i ξi i − ti x i =1,2,3 i =1,2,3 e ξ p i ,q i −ti x i . R n [ x, a i , b i , c i , d i ; α i , β i , γ i , δ i ; e ] i …(17) ξ θi ni αi pi + γ i n i qi + δi n i − t i x i βi = ∏ {x ( φ + x D x )} {( a i x + b i ) (ci x + d i ) e } i =1,2,3 has the solution ∏ i =1,2,3 = f i ( x) −BiEi −Ci ∞ −1 * x Bi +1 E c ∏ x ∫0 y h i y ( y D y ) i {y i g i ( y)}dy , i =1,2,3 provided that the integral exists and ∏ i =1,2,3 ∏ i =1,2,3 …(18) h *i ( x) is the Mellin inverse transform H *i (s) E = ∏ Bi i i =1,2,3 s Γ − ni B i ∑ k =0 s Γ − E i − i Bi pi + γi n i qi + δi n i ∑ ∑ ℓ i =0 ( −1) k i + ℓ i + mi mi = 0 ( −n i ) k ( −p i − γ i n i )ℓ i ki ! ℓi ! . . ( −q i − δ i n i ) m mi ! i ( φ) n i −ki (bi ) pi + γ i n i − ℓ i (d i ) q i + δi n i − m i ℓi (a i ) (ci ) mi ( θi ) ki | ξi | . −1 s + θi n i + Bi E i + C i s + Bi E i + C i + θi n i + α i ℓ i + βi m i Γ Γ 1 + θ ξ i i , . s + B E + C + θ n + α ℓ + β m s + θi n i + Bi E i + C i i i i i i i i i i Γ − k i + 1 t i ξi θi …(19) i The Inversion of an Integral Equation… 47 provided that 0 < Re (s + Bi E i + C i + θ i n i + α i ℓ i + β i m i ) < ξ i , when ξ i > 0; ξ i < Re(s + Bi E i + C i + θ i n i + α i ℓ i + β i m i ) < 0, when ξ i < 0 ; ξ i , Bi ; θ i ≠ 0 n i , (p i + γ i n i ) , ( q i + δ i n i ) ∈ N 0 , where i = 1,2,3. 4.2. By taking i = 1,2 in (2), the main theorem reduces to a known result recently obtained by Chaurasia and Agnihotri in [4]. q 4.3. 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