Geometry Lesson 1.6 – Notes Name ___________________________

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Lesson 1.6 – Notes
Geometry
Name ___________________________
Angles:
Definition: formed by _______ ________________ with the same _____________________________________.
B
There are 4 ways to name this angle.
1
T
Name
Q
1)
2)
2)
4)
1)
2)
CED in two other ways.
Turn to page 37 to fill out the chart below. The first one has been done for you,
Angle Classification
Angle
Name
Acute
Right
Obtuse
Straight
Angle Measure Description
0 < x < 90
Example
Examples
1) Name all the acute angles in the figure.
2) Name all the obtuse angles in the figure
3) Name all the right angles in the figure.
Measuring Angles
Find the measure of each angle and classify each as acute, right, obtuse, or straight.
Angle Addition


Adding two angles together
to form a larger angle.
1  2  AED
Example using angle addition.
1)
a) Of the three angles mentioned above, which is the largest angle
looking at the picture?
b) Which two angles will be added together to find the largest angle?
c) Solve for x.
d) Find the measurement of  COD,
 BOC.,  BOD.
2)
Find the angle measures.
Identifying Angles
Turn to page 38 to fill out the chart. The first one has been done for you.
Angle Pairs
NAME
Congruent
Angles
Description
2 angles with same
measure
2 angles whose
sides are opposite
rays
2 coplanar angles
with common side,
vertex and no
common interior
points
2 angles whose
measurements sum
to 90
2 angles whose
measures sum to
180
Examples.
1)
complementary to
2) supplementary to
3) adjacent and congruent to
4) vertical to <EOD
Example
<1  <2
Find the measurement of the angles using your information about complementary, supplementary, and straight angles.
1)
2)
3)
4)
5)
6)
Drawing Conclusions:
What do you conclude? Are they Congruent, Adjacent,
Vertical, Complementary, or Supplementary.
1)
1 & 2
2)
1 & 4
3)
4 & 5
4)
2 & 3
Can you make this conclusion?
1) TW = WV
2) TW = WQ
3) TV is perpendicular to PQ
4) TV bisects PQ
5) W is the midpoint of TV
Solve for x.
<AOB = 5x + 2
<AOC = 10x + 2
<BOC = 3x + 1
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