Formula Sheet – PHY 161 – Exam D Chapter 1: Introduction 4 Sphere (radius π ): Area π΄ = 4ππ 2 , Volume π = π π 3 . 3 Cylinder (radius π , height β): Area π΄ = 2ππ 2 + 2ππ β, Volume π = ππ 2 β. Density (mass π, volume π): π = π/π. Chapter 2: One-Dimensional Kinematics Definitions Change (β) is final value minus initial value: βπ₯ = π₯ − π₯0 , βπ‘ = π‘ − π‘0 , βπ£ = π£ − π£0 . Instantaneous quantities: π£ = ππ₯ ππ‘ Average quantities: π£Μ = π£ππ£π = , π= βπ₯ βπ‘ ππ£ ππ‘ = , πππ£π = π2 π₯ ππ‘ 2 βπ£ βπ‘ . . Speed (π always positive or zero): π = |π£| , π ππ£π = Acceleration due to gravity: π = −π , π = 9.8 Kinematic equations of motion If we let π = constant and π‘0 = 0, then 1 π₯ = π₯0 + π£0 π‘ + ππ‘ 2 , π£ = π£0 + ππ‘, 2 π£ 2 = π£02 + 2πβπ₯ , π£ππ£π = π£0 +π£ 2 . π π 2 π‘ππ‘ππ πππ π‘ππππ π‘ . , “g-factor”= π/π. Chapter 3: Vectors Components: ππ₯ = π cos π, ππ¦ = π sin π, π = √ππ₯2 + ππ¦2 , tan π = ππ¦ /ππ₯ . ββ, if and only if πΆπ₯ = π΄π₯ + π΅π₯ and πΆπ¦ = π΄π¦ + π΅π¦ . Addition: πΆβ = π΄β + π΅ ββ = π΄π₯ π΅π₯ + π΄π¦ π΅π¦ + π΄π§ π΅π§ = π΄π΅ cos π. Scalar (dot) product: π΄β β π΅ Vector (cross) product: ββ = (π΄π¦ π΅π§ − π΄π§ π΅π¦ )πΜ + (π΄π§ π΅π₯ − π΄π₯ π΅π§ )πΜ + (π΄π₯ π΅π¦ − π΄π¦ π΅π₯ )πΜ. π΄β × π΅ Chapter 4: Two-Dimensional Kinematics ββπ΄πΆ = π ββπ΄π΅ + π ββπ΅πΆ . Relative motion: π Uniform circular motion (speed π£, radius π , period π): 2 π = π£ ⁄π , π£ = 2ππ ⁄π . Chapter 5: Newton’s Laws, Part 1 Here πΉβ refers to the total force acting on an object, equal to the vector sum of all individual forces acting on the object: πΉβ = ββββ πΉ1 + βββββ πΉ2 + βββββ πΉ3 + β― First Law: πΉβ = 0 if and only if πβ = 0, where πβ is the object's acceleration. Second Law: πΉβ = ππβ, where π is the object's (inertial) mass, a constant. Third Law: If two objects are interacting, then πΉβ21 = −πΉβ12 . Weight: π€ = ππ, where π = 9.8π/π 2 . Chapter 6: Newton’s Laws, Part 2 APPLICATIONS of Newton's Laws Static friction: ππ ≤ ππ ,πππ₯ = ππ π, where ππ is a constant and π is the normal force. Kinetic (or sliding) friction: ππ = ππ π, where ππ is a constant. Centripetal force: This is required for circular motion. πΉ = ππ£ 2 /π , where π£ is the speed and π is the radius of curvature. Drag force (air/fluid resistance): This can be parameterized as π· = 12πΆππ΄π£ 2 , where πο is the fluid density, π΄ is the object’s cross-sectional area, π£ is the object’s speed relative to the fluid, and πΆ is parameter of order 1 called the drag coefficient. Chapter 7: Work and Energy Kinetic Energy: πΎ = 12ππ£ 2 Definition of work done by arbitrary force: πππΉ = πΉβ β ππ₯β Work done by a constant force: ππΉ = πΉβ β βπ₯β Work done by gravity: ππ = −ππβπ¦ , where βπ¦ is the change in elevation. Work done by a spring: πΉπ = −ππ₯, ππ = 12ππ₯02 − 12ππ₯ 2 Work-Energy Theorem: ππππ ππππππ = βπΎ Power: πππ£π = π βπ‘ , π= ππ ππ‘ = πΉβ β π£β Chapter 8: Conservation of Energy Conservative force: π (π΄ → π΅) = πππππππππππ‘ ππ πππ‘β Potential energy difference: only defined for conservative force, βπ(π΄ → π΅) = −π (π΄ → π΅) Potential energy: where π₯0 is the reference point and we choose π0 at will, π(π₯0 ) = π0 , π(π₯ ) = π(π₯0 ) + βπ(π₯0 → π₯ ) Force associated with potential energy: πΉ = − ππ ππ₯ Potential energy for specific forces For gravity: βππ = ππβπ¦, where π¦ is the elevation, or ππ = ππβ, choosing the equilibrium point π¦0 = 0 as the reference point, π0 = 0, and β = π¦. For a spring-mass system: βππ = 12ππ₯ 2 − 12ππ₯02 → ππ = 12ππ₯ 2 , choosing the equilibrium point π₯0 = 0 as the reference point, and π0 = 0. Mechanical energy: πΈπππβ = πΎ + π, the sum of kinetic and potential energy. Work-Energy Theorem (version 2): ππππ−ππππ πππ£ππ‘ππ£π ππππππ = βπΈπππβ Work-Energy Theorem (version 3): πππ₯π‘πππππ ππππππ = βπΈ = βπΈπππβ + βπΈπ‘βπππππ + βπΈπππ‘πππππ Work-Energy Theorem (isolated system): πππ₯π‘πππππ ππππππ = 0 Chapter 9: Linear Momentum and Collisions Systems of Particles Center of Mass: In the following the particles are numbered, π = 1,2,3, … , π. The system total mass is π = ∑π π=1 ππ . 1 Position: π ββπΆπ = ( ) ∑π π=1 ππ πβπ , and its components 1 π ππΆπ = ( ) ∑π π=1 ππ π₯π , π 1 ππΆπ = ( ) ∑π π=1 ππ π¦π . π ββπΆπ = π π ββπΆπ , and π΄βπΆπ = π π ββ . Velocity and acceleration: π ππ‘ ππ‘ πΆπ ππβ Momentum, single particle: πβ = ππ£β, πΉβ = ππβ = . Total Momentum: πββπ‘ππ‘ππ = Impulse: π½β = βπβ = πΉππ£π βπ‘. ∑π π=1 ππ ππ‘ ββπΆπ , πΉβπ‘ππ‘ππ = ππ΄βπΆπ = π£βπ = ππ π ββ π . ππ‘ π‘ππ‘ππ Collisions Completely inelastic (sticking) collisions: When two particles with masses (π1 , π2 ) and initial velocities (π£1 , π£2 ) collide and stick together, they share a final velocity π. Conservation of momentum gives π1 π£1 + π2 π£2 = (π1 + π2 )π. Elastic collisions: When two particles with masses (π1 , π2 ) and initial velocities (π£1 , π£2 ) undergo an elastic collision their final velocities are (π£′1 , π£′2 ): π£1′ = [ π1 − π2 2π2 ] π£1 + [ ]π£ , π1 + π2 π1 + π2 2 2π1 π2 − π1 π£2′ = [ ] π£1 + [ ]π£ . π1 + π2 π1 + π2 2