GENERALIZATION OF AN IMPULSIVE NONLINEAR SINGULAR GRONWALL-BIHARI INEQUALITY WITH DELAY Gronwall-Bihari Inequality Shengfu Deng and Carl Prather vol. 9, iss. 2, art. 34, 2008 SHENGFU DENG AND CARL PRATHER Department of Mathematics Virginia Polytechnic Institute and State University Blacksburg, VA 24061, USA EMail: sfdeng@vt.edu Title Page Contents prather@math.vt.edu Received: 25 August, 2007 Accepted: 23 May, 2008 Communicated by: S.S. Dragomir 2000 AMS Sub. Class.: 26D15, 26D20. Key words: Gronwall-Bihari inequality, Nonlinear, Impulsive. Abstract: This paper generalizes a Tatar’s result of an impulsive nonlinear singular Gronwall-Bihari inequality with delay [J. Inequal. Appl., 2006(2006), 1-12] to a new type of inequalities which includes n distinct nonlinear terms. JJ II J I Page 1 of 20 Go Back Full Screen Close Contents 1 Introduction 3 2 Main Results 5 Gronwall-Bihari Inequality Shengfu Deng and Carl Prather vol. 9, iss. 2, art. 34, 2008 Title Page Contents JJ II J I Page 2 of 20 Go Back Full Screen Close 1. Introduction In order to investigate problems of the form x0 = f (t, x), ∆x = Ik (x), t 6= tk , t = tk , Samoilenko and Perestyuk [6] first used the following impulsive integral inequality Z t X u(t) ≤ a + b(s)u(s)ds + ηk u(tk ), t ≥ 0. c Gronwall-Bihari Inequality Shengfu Deng and Carl Prather vol. 9, iss. 2, art. 34, 2008 0<tk <t Then Bainov and Hristova [2] studied a similar inequality with constant delay. In 2004, Hristova [3] considered a more general inequality with nonlinear functions in u. All of these papers treated the functions (kernels) involved in the integrals which are regular. Recently, Tatar [7] investigated the following singular inequality Z t Z t m u(t) ≤ a(t) + b(t) k1 (t, s)u (s)ds + c(t) k2 (t, s)un (s − τ )ds 0 0 X +d(t) ηk u(tk ), t ≥ 0, Title Page Contents JJ II J I Page 3 of 20 Go Back 0<tk <t (1.1) u(t) ≤ ϕ(t), t ∈ [−τ, 0], τ > 0 where the kernels ki (t, s) are defined by ki (t, s) = (t − s)βi −1 sγi Fi (s) for βi > 0 and γi > −1, i = 1, 2, the points tk (called "instants of impulse effect") are in increasing order and limk→∞ tk = +∞. This inequality was called the impulsive nonlinear singular version of the Gronwall inequality with delay by Tatar [7]. In this paper, we Full Screen Close will consider an inequality n Z X u(t) ≤ a(t) + + j=n+1 (1.2) + d(t) Z (t − s)βi −1 sri fi (t, s)wi (u(s))ds 0 i=1 m+n X bi (t) bj (t) (t − s)βj −1 srj fj (t, s)wj (u(s − τ ))ds 0 X Gronwall-Bihari Inequality ηL u(tL ), t ≥ 0, 0<tL <t u(t) ≤ ϕ(t), Shengfu Deng and Carl Prather vol. 9, iss. 2, art. 34, 2008 t ∈ [−τ, 0], τ > 0, where n, m are positive integers, βl > 0, rl > −1 for l = 1, . . . , n + m and ηL ≥ 0 and other assumptions are given in Section 2. This inequality is more general than (1.1) since (1.2) has n nonlinear terms. Title Page Contents JJ II J I Page 4 of 20 Go Back Full Screen Close 2. Main Results Notation: Following [1] and [5], we say w1 ∝ w2 for w1 , w2 : A ⊂ R → R\{0} 2 if w is nondecreasing on A. This concept helps us to compare the monotonicity of w1 different functions. Now we make the following assumptions: (H1) all wi (i = 1, . . . , n + m) are continuous and nondecreasing on [0, ∞) and positive on (0, ∞), and w1 ∝ w2 ∝ · · · ∝ wn Gronwall-Bihari Inequality Shengfu Deng and Carl Prather (H2) a(t) and d(t) are continuous and nonnegative on [0, ∞); (H3) all bl : [0, ∞) → [0, ∞) are continuously differentiable and nondecreasing such that 0 ≤ bl (t) ≤ t on [0, ∞), tL ≤ bl (t) ≤ tL + τ for t ∈ [tL , tL + τ ] and tL + τ ≤ bl (t) ≤ tL+1 for t ∈ [tL + τ, tL+1 ], l = 1, . . . , n + m and L = 0, 1, 2, . . . where t0 = 0. The points tL are called instants of impulse effect which are in increasing order, and limL→∞ tL = ∞; (H4) all fl (t, s) (l = 1, . . . , n + m) are continuous and nonnegative functions on [0, ∞) × [0, ∞); (H5) ϕ(t) is nonnegative and continuous; (H6) u(t) is a piecewise continuous function from R → R+ = [0, ∞) with points of discontinuity of the first kind at the points tL ∈ R. It is also left continuous at the points tL . This space is denoted by P C(R, R+ ). Without loss of generality, we will suppose that the tL satisfy τ < tL+1 −tL ≤ 2τ , L = 0, 1, 2, . . . . As in Remark 3.2 of [7], other cases can be reduced to this one. vol. 9, iss. 2, art. 34, 2008 Title Page Contents JJ II J I Page 5 of 20 Go Back Full Screen Close Theorem 2.1. Let the above assumptions hold. Suppose that u satisfies (1.2) and is in P C([−τ, ∞), [0, ∞)). Then if βα > − p1 + 1 and rα > − p1 , it holds that uL,0 (t), t ∈ (tL , tL + τ ], uL,1 (t), t ∈ (tL + τ, tL+1 ], uk,0 (t), t ∈ (tk , tk + τ ] if tk + τ ≤ T, u(t) ≤ uk,1 (t), t ∈ (tk + τ, T ] if tk + τ < T, uk,0 (t), t ∈ (tk , T ] if tk + τ > T, where tk ≤ T < tk+1 and " uL,l (t) = Wn−1 Z + bn (t) (n + m + L + 1)q−1 cqn (t)f˜nq (t, s)ds Wj−1 (γL,l,j−1 (t)) γL,l,1 (t) = (n + m + L + 1) q−1 q ã (t) + n Z X i=1 + j=n+1 0 II J I Go Back j 6= 1, Full Screen " bj (t) JJ Page 6 of 20 bj−1 (t) q q−1 q ˜ (n + m + L + 1) cj−1 (t)fj−1 (t, s)ds , Z Contents , tL +lτ n+m X vol. 9, iss. 2, art. 34, 2008 !# 1q tL +lτ γL,l,j (t) = Shengfu Deng and Carl Prather Title Page Z Wn (γL,l,n (t)) + −1 Wj−1 Gronwall-Bihari Inequality tL +lτ Close cqi (t)f˜iq (t, s)wiq (φ(s))ds 0 cqj (t)f˜jq (t, s)wjq (ψ(s − τ ))ds + L X e=1 # d˜q (t)ηeq uqe−1,1 (te ) , u (t), t ∈ (tL , tL + τ ], t ∈ (tk , tk + τ ] if tk + τ ≤ T, L,0 and t ∈ (tk , T ] if tk + τ > T, φ(t) = uL,1 (t), t ∈ (tL + τ, tL+1 ] and t ∈ (tk + τ, T ] if tk + τ < T, ϕ(t), t ∈ [−τ, 0], uL,0 (t), t ∈ (tL , tL + τ ], t ∈ (tk , tk + τ ] if tk + τ ≤ T, ψ(t) = and t ∈ (tk , T ] if tk + τ > T, uL,1 (t), t ∈ (tL + τ, tL+1 ] and t ∈ (tk + τ, T ] if tk + τ < T, ˜ = max d(x), f˜α (t, s) = max fα (x, s), d(t) 0≤x≤t 0≤x≤t 0≤x≤t Z u dv Wi (u) = u > 0, ui > 0, 1 , q ui wi (v q ) 1 1 Γ(1 + p(βα − 1))Γ(1 + prα ) p +βα +rα −1 p cα (t) = t , Γ(2 + p(βα + rα − 1)) ã(t) = max a(x), for L = 0, 1, . . . , k − 1, α = 1, 2, . . . , n + m, l = 0, 1, and i, j = 1, . . . , n where 1 + 1q = 1 for p > 0 and q > 1, and T is the largest number such that p Z bj (t) (2.1) Wj (γL,l,j (t)) + tL +lτ (n + m + L + 1)q−1 cj (t)f˜jq (t, s)ds ≤ Z ∞ uj dz , wjq (z 1/q ) for all t ∈ (tL , tL + τ ], all t ∈ (tk , tk + τ ] if tk + τ ≤ T and all t ∈ (tL , T ] if tk + τ > T as l = 0, or all t ∈ [tL + τ, tL+1 ] and all t ∈ [tk + τ, T ) if tk + τ < T as l = 1 where j = 1, . . . , n, l = 0, 1 and L = 0, 1 . . . , k − 1. Gronwall-Bihari Inequality Shengfu Deng and Carl Prather vol. 9, iss. 2, art. 34, 2008 Title Page Contents JJ II J I Page 7 of 20 Go Back Full Screen Close Before the proof, we introduce a lemma which will play a very important role. Lemma 2.2 ([1]). Suppose that 1. all wi (i = 1, . . . , n) are continuous and nondecreasing on [0, ∞) and positive on (0, ∞), and w1 ∝ w2 ∝ · · · ∝ wn . 2. a(t) is continuously differentiable in t and nonnegative on [t0 , t1 ), 3. all bl are continuously differentiable and nondecreasing such that bl (t) ≤ t for t ∈ [t0 , t1 ) where t0 , t1 are constants and t0 < t1 . If u(t) is a continuous and nonnegative function on [t0 , t1 ) satisfying n Z bi (t) X u(t) ≤ a(t) + fi (t, s)wi (u(s))ds, t0 ≤ t < t1 , i=1 then Gronwall-Bihari Inequality Shengfu Deng and Carl Prather vol. 9, iss. 2, art. 34, 2008 Title Page Contents bi (t0 ) " u(t) ≤ W̃n−1 W̃n (γn (t)) + Z bn (t) # f˜n (t, s)ds , t0 ≤ t ≤ T1 , JJ II J I bn (t0 ) Page 8 of 20 where " γi (t) = −1 W̃i−1 Z bi−1 (t) W̃i−1 (γi−1 (t)) + # f˜i−1 (t, s)ds , Go Back i = 2, 3, . . . , n, Full Screen bi−1 (t0 ) Z t γ1 (t) = a(t0 ) + |a0 (s)|ds, u Z W̃i (u) = t0 ui T1 < t1 and T1 is the largest number such that Z bi (T1 ) Z ˜ W̃i (γi (T1 )) + fi (T1 , s)ds ≤ ∞ bi (t0 ) ui dz , wi (z) ui > 0, dz , wi (z) i = 1, . . . , n. Close Proof of Theorem 2.1. Since βα > − p1 + 1 and rα > − p1 for α = 1, . . . , n + m, by Hölder’s inequality we obtain ! 1q p1 Z bi (t) n Z t X q q u(t) ≤ a(t) + (t − s)p(βi −1) spri ds fi (t, s)wi (u(s))ds 0 i=1 + m+n X Z p(βj −1) prj (t − s) s ds X Z bj (t) ! 1q fjq (t, s)wjq (u(s − τ ))ds Gronwall-Bihari Inequality 0 0 j=n+1 + t 0 1 p Shengfu Deng and Carl Prather vol. 9, iss. 2, art. 34, 2008 d(t)ηL u(tL ) 0<tL <t ≤ a(t) + n X ci (t) + ! 1q Title Page fiq (t, s)wiq (u(s))ds Contents 0 i=1 m+n X bi (t) Z Z bj (t) cj (t) ! 1q fjq (t, s)wjq (u(s − τ ))ds + 0 j=n+1 X d(t)ηL u(tL ) 0<tL <t where we use bα (t)≤t and the definition of cα(t). Now we use the following result [4]: If A1 , . . . , An are nonnegative for n ∈ N, then for q > 1, (A1 + · · · + An )q ≤ nq−1 (Aq1 + · · · + Aqn ). Since tk ≤ t ≤ T < tk+1 , we have " Z bi (t) n X q q q−1 q u (t) ≤ (1 + n + m + k) a (t) + ci (t) fiq (t, s)wiq (u(s))ds i=1 + m+n X j=n+1 cqj (t) Z 0 bj (t) 0 fjq (t, s)wjq (u(s − τ ))ds + k X L=1 # dq (t)ηLq uq (tL ) . JJ II J I Page 9 of 20 Go Back Full Screen Close ˜ ≥ d(t) and f˜α (t, s) ≥ fα (t, s) and they are continuous We note that ã(t) ≥ a(t), d(t) and nondecreasing in t. The above inequality becomes " Z tL+1 n k−1 X X q q q−1 q u (t) ≤ (1 + n + m + k) ã (t) + ci (t) f˜iq (t, s)wiq (u(s))ds i=1 + cqi (t) Z bi (t) tL L=0 ! f˜iq (t, s)wiq (u(s))ds Gronwall-Bihari Inequality tk + (2.2) + m+n X k−1 X j=n+1 L=0 cqj (t) Z bj (t) Shengfu Deng and Carl Prather cqj (t) Z tL+1 vol. 9, iss. 2, art. 34, 2008 f˜jq (t, s)wjq (u(s − τ ))ds tL ! f˜jq (t, s)wjq (u(s − τ ))ds k X + tk Title Page # d˜q (t)ηLq uq (tL ) . Contents L=1 In the following, we apply mathematical induction with respect to k. JJ II (1) k = 0. We note that t0 = 0 and we have for any fixed t̃ ∈ [0, t1 ] " Z bi (t) n X q q q−1 q (2.3) u (t) ≤ (n + m + 1) ã (t̃) + c (t̃) f˜q (t̃, s)wq (u(s))ds J I i + i=1 m+n X j=n+1 i Page 10 of 20 i Go Back 0 cqj (t̃) Z bj (t) # f˜jq (t̃, s)wjq (u(s − τ ))ds 0 for t ∈ [0, t̃] since cα (t) are nondecreasing. Now we consider t̃ ∈ [0, τ ] ⊂ [0, t1 ] and t ∈ [0, t̃]. Note that 0 ≤ bj (t) ≤ t so −τ ≤ bj (t) − τ ≤ 0 for t ∈ [0, t̃]. Since u(t) ≤ ϕ(t) for t ∈ [−τ, 0], we have uq (t) ≤ z0,0 (t), t ∈ [0, t̃], Full Screen Close where " (2.4) z0,0 (t) = (n + m + 1) q−1 q ã (t̃) + n X cqi (t̃) + f˜iq (t̃, s)wiq (u(s))ds 0 i=1 m+n X bi (t) Z cqj (t̃) Z bj (t̃) # f˜jq (t̃, s)wjq (ϕ(s − τ ))ds . 0 j=n+1 Gronwall-Bihari Inequality It implies that Shengfu Deng and Carl Prather 1/q u(t) ≤ z0,0 (t) (2.5) , t ∈ [0, t̃]. n X Z vol. 9, iss. 2, art. 34, 2008 Thus, (2.4) becomes Title Page " (2.6) z0,0 (t) ≤ (n + m + 1)q−1 ãq (t̃) + cqi (t̃) + cqj (t̃) Z bj (t̃) # f˜jq (t̃, s)wjq (ϕ(s − τ ))ds . 0 j=n+1 By Lemma 2.2, (2.6) and (2.1), we have " Z −1 z0,0 (t) ≤ Wn Wn (γ̃0,0,n (t)) + 1/q f˜iq (t̃, s)wiq (z0,0 (s))ds 0 i=1 m+n X bi (t) Contents JJ II J I Page 11 of 20 Go Back # bn (t) (n + m + 1) q−1 cn (t̃)f˜nq (t̃, s)ds 0 , Full Screen Close −1 γ̃0,0,j (t) = Wj−1 Wj−1 (γ̃0,0,j−1 (t)) Z + # bj−1 (t) (n + m + 1) 0 q−1 q cj−1 (t̃)f˜j−1 (t̃, s)ds , j 6= 1, " γ̃0,0,1 (t) = (n + m + 1)q−1 ãq (t̃) + n+m X bj (t̃) Z j=n+1 # cqj (t̃)f˜jq (t̃, s)wjq (ψ(s − τ ))ds 0 since ψ(t) = ϕ(t) for t ∈ [−τ, 0]. Since (2.5) is true for any t ∈ [0, t̃] and γ̃0,0,j (t̃) = γ0,0,j (t̃), we have u(t̃) ≤ z0,0 (t̃)1/q ≤ u0,0 (t̃). Gronwall-Bihari Inequality We know that t̃ ∈ [0, τ ] is arbitrary so we replace t̃ by t and get u(t) ≤ u0,0 (t), (2.7) Shengfu Deng and Carl Prather vol. 9, iss. 2, art. 34, 2008 for t ∈ [0, τ ]. This implies that the theorem is true for t ∈ [0, τ ] and k = 0. For t ∈ [τ, t̃] and t̃ ∈ [τ, t1 ], use the assumption (H3) and then we know that bα (τ ) = τ and τ ≤ bα (t) ≤ t1 for t ∈ [τ, t1 ] and α = 1, . . . , n + m. Thus, 0 ≤ bα (t) − τ ≤ t1 − τ ≤ τ since τ < t1 − t0 = t1 ≤ 2τ . Using this fact, (2.3) and (2.7), we get " Z τ n X q q q−1 q u (t) ≤ (n + m + 1) ã (t̃) + c (t̃) f˜q (t̃, s)wq (u(s))ds i i=1 + + n X cqi (t̃) i=1 m+n X + j=n+1 Contents JJ II J I Page 12 of 20 i 0 Go Back f˜iq (t̃, s)wiq (u(s))ds Full Screen τ Close τ cqj (t̃) Z cqj (t̃) Z f˜jq (t̃, s)wjq (ψ(s − τ ))ds 0 j=n+1 m+n X bi (t) Z i Title Page τ bj (t̃) # f˜jq (t̃, s)wjq (u(s − τ ))ds " ≤ (n + m + 1) q q−1 ã (t̃) + n X cqi (t̃) + + cqi (t̃) i=1 m+n X bi (t) Z + cqj (t̃) f˜iq (t̃, s)wiq (u(s))ds τ Z f˜jq (t̃, s)wjq (ψ(s − τ ))ds cqj (t̃) Z Shengfu Deng and Carl Prather bj (t̃) # τ ≤ (n + m + 1)q−1 ãq (t̃) + n X cqi (t̃) + cqi (t̃) j=n+1 bi (t) Z Z Title Page τ f˜iq (t̃, s)wiq (φ(s))ds f˜iq (t̃, s)wiq (u(s))ds τ cqj (t̃) Z bj (t̃) # f˜jq (t̃, s)wjq (ψ(s − τ ))ds JJ II J I Page 13 of 20 Go Back 0 := z0,1 (t), Full Screen where we use the definitions of φ and ψ. Thus, (2.8) Contents 0 i=1 i=1 m+n X vol. 9, iss. 2, art. 34, 2008 f˜jq (t̃, s)wjq (u0,0 (s − τ ))ds " + Gronwall-Bihari Inequality 0 j=n+1 n X f˜iq (t̃, s)wiq (u0,0 (s))ds τ j=n+1 m+n X τ 0 i=1 n X Z 1/q u(t) ≤ z0,1 (t), t ∈ [τ, t̃]. Close Therefore, " z0,1 ≤ (n + m + 1) q−1 + q ã (t̃) + n X cqi (t̃) n X cqi (t̃) i=1 bi (t) Z τ Z f˜iq (t̃, s)wiq (φ(s))ds 0 1/q f˜iq (t̃, s)wiq (z0,1 (s))ds τ i=1 Gronwall-Bihari Inequality m+n X + cqj (t̃) bj (t̃) Z # f˜jq (t̃, s)wjq (ψ(s − τ ))ds . 0 j=n+1 Using Lemma 2.2, (2.1) and bα (τ ) = τ , we obtain for t ∈ [τ, t̃] " # Z bn (t) z0,1 (t) ≤ Wn−1 Wn (γ̃0,1,n (t)) + (n + m + 1)q−1 cqn (t̃)f˜nq (t̃, s)ds , γ̃0,1,j (t) = Contents Wj−1 (γ̃0,1,j−1 (t)) JJ II J I Page 14 of 20 Z bj−1 (t) + # q (n + m + 1)q−1 cqj−1 (t̃)f˜j−1 (t̃, s)ds , j 6= 1, τ q−1 Go Back Full Screen " γ̃0,1,1 (t) = (n + m + 1) vol. 9, iss. 2, art. 34, 2008 Title Page τ −1 Wj−1 Shengfu Deng and Carl Prather q ã (t̃) + + n Z X Close τ cqi (t̃)f˜iq (t̃, s)wiq (φ(s))ds i=1 0 n+m X Z bj (t̃) j=n+1 0 # cqj (t̃)f˜jq (t̃, s)wjq (ψ(s − τ ))ds . Since (2.8) is true for any t ∈ [τ, t1 ] and γ̃0,1,1 (t̃) = γ0,1,1 (t̃), we have 1/q u(t̃) ≤ z0,1 (t̃) ≤ u0,1 (t̃). We know that t̃ ∈ [τ, t1 ] is arbitrary so we replace t̃ by t and get u(t) ≤ u0,1 (t), (2.9) t ∈ [τ, t1 ]. This implies that the theorem is valid for t ∈ [τ, t1 ] and L = 0. (2) L = 1. First we consider t ∈ (t1 , t̃], where t̃ ∈ (t1 , t1 + τ ] is arbitrary. Note that τ < t2 − t1 ≤ 2τ . (H3) gives bα (t1 ) = t1 and t1 ≤ bα (t) ≤ t1 + τ for t ∈ (t1 , t1 + τ ] so t1 − τ ≤ bα (t) − τ ≤ t1 for t ∈ (t1 , t1 + τ ]. By (2.7) and (2.9), (2.2) can be written as " Z τ Z t1 n X q q q−1 q u (t) ≤ (n + m + 2) ã (t̃) + ci (t̃) + f˜iq (t̃, s)wiq (u(s))ds 0 i=1 + + n X cqi (t̃) i=1 m+n X bi (t) Z cqj (t̃) + cqj (t̃) τ t1 + 0 j=n+1 n X f˜iq (t̃, s)wiq (u(s))ds Z Z bj (t̃) τ i=1 cqi (t̃) bi (t) t1 JJ II J I Full Screen Close n X i=1 + Contents Go Back f˜jq (t̃, s)wjq (u(s − τ ))ds + d˜q (t̃)η1q uq (t1 ) ≤ (n + m + 2)q−1 ãq (t̃) + Z Title Page # " n X vol. 9, iss. 2, art. 34, 2008 Page 15 of 20 f˜jq (t̃, s)wjq (u(s − τ ))ds t1 j=1 Shengfu Deng and Carl Prather τ t1 Z Gronwall-Bihari Inequality cqi (t̃) Z 0 f˜iq (t̃, s)wiq (u(s))ds t1 f˜iq (t̃, s)wiq (φ(s))ds + m+n X cqj (t̃) Z bj (t̃) # f˜jq (t̃, s)wjq (ψ(s − τ ))ds + d˜q (t̃)η1q uq0,1 (t1 ) 0 j=n+1 :=z1,0 (t), where we use the definitions of φ and ψ so 1/q u(t) ≤ z1,0 (t), (2.10) t ∈ (t1 , t̃]. Gronwall-Bihari Inequality Thus, Shengfu Deng and Carl Prather " z1,0 (t) ≤ (n + m + 2) q q−1 ã (t̃) + n X cqi (t̃) Z i=1 + n X cqi (t̃) bi (t) vol. 9, iss. 2, art. 34, 2008 f˜iq (t̃, s)wiq (φ(s))ds 0 Title Page 1/q f˜iq (t̃, s)wiq (z1,0 (s))ds Contents t1 i=1 + Z t1 m+n X cqj (t̃) Z bj (t̃) # f˜jq (t̃, s)wjq (ψ(s − τ ))ds + d˜q (t̃)η1q uq0,1 (t1 ) . 0 j=n+1 By Lemma 2.2, (2.1) and bα (t1 ) = t1 , we obtain for t ∈ (t1 , t̃] " # Z bn (t) z1,0 (t) ≤ Wn−1 Wn (γ̃1,0,n (t)) + (n + m + 2)q−1 cqn (t̃)f˜nq (t̃, s)ds , t1 JJ II J I Page 16 of 20 Go Back Full Screen Close −1 γ̃1,0,j (t) = Wj−1 Wj−1 (γ̃1,0,j−1 (t)) Z # bj−1 (t) + (n + m + t1 q 2)q−1 cqj−1 (t̃)f˜j−1 (t̃, s)ds , j 6= 1, " γ̃1,0,1 (t) = (n + m + 2) q q−1 ã (t̃) + n Z X i=1 n+m X Z + bj (t̃) t1 cqi (t̃)f˜iq (t̃, s)wiq (φ(s))ds 0 # cqj (t̃)f˜jq (t̃, s)wjq (ψ(s − τ ))ds + d˜q (t̃)η1q uq0,1 (t1 ) . 0 j=n+1 Since (2.10) is true for any t ∈ (t1 , t̃] and γ̃1,0,1 (t̃) = γ1,0,1 (t̃), we have Gronwall-Bihari Inequality Shengfu Deng and Carl Prather 1/q u(t̃) ≤ z1,0 (t̃) ≤ u1,0 (t̃). vol. 9, iss. 2, art. 34, 2008 We know that t̃ ∈ (t1 , t1 + τ ] is arbitrary so we replace t̃ by t and get u(t) ≤ u1,0 (t), (2.11) t ∈ (t1 , t1 + τ ]. Title Page Contents This implies that the theorem is valid for t ∈ (t1 , t1 + τ ] and L = 1. We now consider t ∈ [t1 + τ, t̃], where t̃ ∈ [t1 + τ, t2 ] is arbitrary. Again, by (H3) we have t1 + τ ≤ bα (t) ≤ t2 for t ∈ [t1 + τ, t2 ] and bα (t1 + τ ) = t1 + τ so t1 ≤ bα (t) − τ ≤ t2 − τ ≤ t1 + τ since τ < t2 − t1 ≤ 2τ . Obviously, by (2.7), (2.9) and (2.11), (2.2) becomes " Z t1 +τ n X q q q−1 q u (t) ≤ (n + m + 2) ã (t̃) + ci (t̃) f˜iq (t̃, s)wiq (u(s))ds i=1 + + n X cqi (t̃) i=1 m+n X j=n+1 Z bi (t) 0 f˜iq (t̃, s)wiq (u(s))ds t1 +τ cqj (t̃) Z 0 t1 +τ f˜jq (t̃, s)wjq (u(s − τ ))ds JJ II J I Page 17 of 20 Go Back Full Screen Close + m+n X cqj (t̃) bj (t̃) Z # f˜jq (t̃, s)wjq (u(s − τ ))ds + d˜q (t̃)η1q uq1,0 (t1 ) t1 +τ j=n+1 " ≤ (n + m + 2) q−1 q ã (t̃) + n X cqi (t̃) + + n X cqi (t̃) i=1 m+n X bi (t) t1 +τ f˜iq (t̃, s)wiq (φ(s))ds 0 i=1 Z Z f˜iq (t̃, s)wiq (u(s))ds Gronwall-Bihari Inequality t1 +τ cqj (t̃) Z Shengfu Deng and Carl Prather bj (t̃) # vol. 9, iss. 2, art. 34, 2008 f˜jq (t̃, s)wjq (ψ(s − τ ))ds + d˜q (t̃)η1q uq0,1 (t1 ) 0 j=n+1 Title Page := z1,1 (t), Contents that is, 1/q u(t) ≤ z1,1 (t), (2.12) t ∈ [t1 + τ, t̃]. Thus, JJ II J I Page 18 of 20 " z1,1 (t) ≤ (n + m + 2)q−1 ãq (t̃) + n X i=1 + cqi (t̃) Z bi (t) cqi (t̃) Z t1 +τ Go Back f˜iq (t̃, s)wiq (φ(s))ds 0 Full Screen 1/q f˜iq (t̃, s)wiq (z1,1 (s))ds Close t1 +τ + m+n X j=n+1 cqj (t̃) Z 0 bj (t̃) # f˜jq (t̃, s)wjq (ψ(s − τ ))ds + d˜q (t̃)η1q uq0,1 (t1 ) . Using Lemma 2.2, (2.1) and bα (t1 + τ ) = t1 + τ , we obtain for t ∈ (t1 , t̃] " # Z bn (t) z1,1 (t) ≤ Wn−1 Wn (γ̃1,1,n (t)) + (n + m + 2)q−1 cqn (t̃)f˜nq (t̃, s)ds , t1 +τ h −1 Wj−1 (γ̃1,1,j−1 (t)) γ̃1,1,j (t) = Wj−1 # Z bj−1 (t) q + (n + m + 2)q−1 cqj−1 (t̃)f˜j−1 (t̃, s)ds , j 6= 0, " γ̃1,1,1 (t) = (n + m + 2) q ã (t̃) + n Z X i=1 + n+m X Z j=n+1 bj (t̃) t1 +τ cqi (t̃)f˜iq (t̃, s)wiq (φ(s))ds Title Page 0 Contents # cqj (t̃)f˜jq (t̃, s)wjq (ψ(s − τ ))ds + d˜q (t̃)η1q uq0,1 (t1 ) . 0 Since (2.12) is true for any t ∈ (t1 , t̃] and γ̃1,1,1 (t̃) = γ1,1,1 (t̃), we have 1/q u(t̃) ≤ z1,1 (t̃) ≤ u1,1 (t̃). We know that t̃ ∈ [t1 + τ, t2 ] is arbitrary so we replace t̃ by t and get u(t) ≤ u1,1 (t), JJ II J I Page 19 of 20 Go Back Full Screen t ∈ [t1 + τ, t2 ]. This implies that the theorem is valid for t ∈ [t1 + τ, t2 ] and L = 1. (3) Finally, suppose that the theorem is valid for k, then for k + 1 we redefine φ and ψ by replacing k with k + 1. In a similar manner as in steps (1) and (2), we can see that the theorem holds for t ∈ (tk+1 , T ] ⊂ (tk+1 , tk+2 ]. The proof is now completed. Shengfu Deng and Carl Prather vol. 9, iss. 2, art. 34, 2008 t1 +τ q−1 Gronwall-Bihari Inequality Close References [1] R.P. AGARWAL, S. DENG AND W. ZHANG, Generalization of a retarded Gronwall-like inequality and its applications, Appl. Math. Comput., 165 (2005), 599–612. [2] D.D. BAINOV AND S.G. HRISTOVA, Impulsive integral inequalities with a deviation of the argument, Math. Nachr., 171 (1995), 19–27. [3] S.G. HRISTOVA, Nonlinear delay integral inequalities for piecewise continuous functions and applications, J. Inequal. Pure Appl. Math., 5(4) (2004), Art. 88. [ONLINE: http://jipam.vu.edu.au/article.php?sid=441]. [4] M. MEDVED, A new approach to an analysis of Henry type integral inequalities and their Bihari type versions, J. Math. Anal. Appl., 214 (1997), 349–366. [5] M. PINTO, Integral inequalities of Bihari-type and applications, Funkcial. Ekvac., 33 (1990), 387–403. [6] A.M. SAMOILENKO AND N.A. PERESTJUK, Stability of the solutions of differential equations with impulsive action, Differential Equations, 13 (1977), 1981–1992 (Russian). [7] N.E. TATAR, An impulsive nonlinear singular version of the Gronwall-Bihari inequality, J. Inequal. Appl., 2006 (2006), 1–12. Gronwall-Bihari Inequality Shengfu Deng and Carl Prather vol. 9, iss. 2, art. 34, 2008 Title Page Contents JJ II J I Page 20 of 20 Go Back Full Screen Close