SOME INEQUALITIES REGARDING A GENERALIZATION OF EULER’S CONSTANT Generalization of Euler’s Constant ALINA SÎ NTĂMĂRIAN Alina Sîntămărian vol. 9, iss. 2, art. 46, 2008 Department of Mathematics Technical University of Cluj-Napoca Str. C. Daicoviciu nr. 15 400020 Cluj-Napoca, Romania. Title Page EMail: Alina.Sintamarian@math.utcluj.ro Received: 28 November, 2007 Accepted: 20 March, 2008 Communicated by: Contents JJ II L. Tóth J I 2000 AMS Sub. Class.: 11Y60, 40A05. Page 1 of 15 Key words: Sequence, Convergence, Euler’s constant, Approximation, Estimate, Series. Abstract: The purpose of this paper is to evaluate the limit γ(a) of the sequence 1 1 1 a+n−1 + + ··· + − ln , a a+1 a+n−1 a n∈N where a ∈ (0, +∞). We give some lower and upper estimates for 1 1 1 a+n−1 + + ··· + − ln − γ(a), a a+1 a+n−1 a n ∈ N. Go Back Full Screen Close Contents 1 Introduction 3 2 The Number γ(a) 4 3 Proving Some Estimates for yn − γ(a) using the Logarithmic Derivative of the Gamma Function 6 Generalization of Euler’s Constant Alina Sîntămărian vol. 9, iss. 2, art. 46, 2008 Title Page Contents JJ II J I Page 2 of 15 Go Back Full Screen Close 1. Introduction Let (Dn )n∈N be the sequence defined by Dn = 1 + 21 + · · · + n1 − ln n, for each n ∈ N. It is well-known that the sequence (Dn )n∈N is convergent and its limit, usually denoted by γ, is called Euler’s constant. For Dn − γ, n ∈ N, many lower and upper estimates have been obtained in the literature. We recall some of them: • 1 2(n+1) < Dn − γ < 1 , 2(n−1) • 1 2(n+1) < Dn − γ < 1 , 2n • 1 2n+1 < Dn − γ < 1 , 2n • 1 2n+ 25 < Dn − γ < 1 2n+ 13 • 1 2n+ 2γ−1 1−γ for each n ∈ N \ {1} ([14]); Generalization of Euler’s Constant Alina Sîntămărian vol. 9, iss. 2, art. 46, 2008 ≤ Dn − γ < for each n ∈ N ([8], [19]); Title Page for each n ∈ N ([17]); Contents , for each n ∈ N ([15], [16]); 1 2n+ 13 , for each n ∈ N ([16, Editorial comment], [2], [3]). In Section 2 we present a generalization of Euler’s constant as the limit of the sequence 1 1 1 a+n−1 + + ··· + − ln , a ∈ (0, +∞), a a+1 a+n−1 a n∈N and we denote this limit by γ(a). In Section 3 we give some lower and upper estimates for 1 1 a+n−1 1 + + ··· + − ln − γ(a), a a+1 a+n−1 a n ∈ N. JJ II J I Page 3 of 15 Go Back Full Screen Close 2. The Number γ(a) It is known that the sequence 1 1 1 a+n−1 + + ··· + − ln , a a+1 a+n−1 a n∈N a ∈ (0, +∞), is convergent (see for example [5, p. 453], [7], where problems in this sense were proposed; [6]; [13]). The results contained in the following theorem were given in [10]. Theorem 2.1. Let a ∈ (0, +∞). We consider the sequences (xn )n∈N and (yn )n∈N defined by 1 1 1 a+n xn = + + ··· + − ln a a+1 a+n−1 a and 1 1 1 a+n−1 yn = + + ··· + − ln , a a+1 a+n−1 a for each n ∈ N. Then: Generalization of Euler’s Constant Alina Sîntămărian vol. 9, iss. 2, art. 46, 2008 Title Page Contents JJ II J I Page 4 of 15 Go Back (i) the sequences (xn )n∈N and (yn )n∈N are convergent to the same number, which we denote by γ(a), and satisfy the inequalities xn < xn+1 < γ(a) < yn+1 < yn , for each n ∈ N; (ii) 0 < 1 a − ln 1 + 1 a < γ(a) < a1 ; (iii) lim n(γ(a) − xn ) = n→∞ 1 2 and lim n(yn − γ(a)) = 12 . n→∞ Full Screen Close Remark 1. The sequence (yn )n∈N from Theorem 2.1, for a = 1, becomes the sequence (Dn )n∈N , so γ(1) = γ. The following theorem was given by the author in [12, Theorem 2.3]. Theorem 2.2. Let a ∈ (0, +∞). We consider the sequence (un )n∈N defined by 1 un = yn − 2(a+n−1)+ 1 , for each n ∈ N, where (yn )n∈N is the sequence from the 3 statement of Theorem 2.1. Also, we specify that γ(a) is the limit of the sequence (yn )n∈N . Then: 3 (i) un < un+1 < γ(a), for each n ∈ N \ {1}, and lim n (γ(a) − un ) = n→∞ Generalization of Euler’s Constant Alina Sîntămărian vol. 9, iss. 2, art. 46, 2008 1 ; 72 Title Page (ii) 1 2(a+n−1)+ 11 28 < yn − γ(a) < 1 2(a+n−1)+ 13 , for each n ∈ N \ {1}. Contents Remark 2. The lower estimate from part (ii) of Theorem 2.2 holds for n = 1 as well. JJ II Remark 3. The second limit from part (iii) of Theorem 2.1 also follows from part (ii) of Theorem 2.2. J I Page 5 of 15 Go Back Full Screen Close 3. Proving Some Estimates for yn − γ(a) using the Logarithmic Derivative of the Gamma Function As we already mentioned in Section 1, it is known that ([16, Editorial comment], [2, Theorem 3], [3, Theorem 1.1]) 1 1 , 2γ−1 ≤ Dn − γ < 2n + 13 2n + 1−γ Generalization of Euler’s Constant Alina Sîntămărian 2γ−1 1−γ 1 3 for each n ∈ N, the constants and being the best possible with this property. Let a ∈ (0, +∞). In a similar way as in the proof given by H. Alzer in [2, Theorem 3], we shall obtain lower and upper estimates for yn − γ(a) (n ∈ N), where (yn )n∈N is the sequence from the statement of Theorem 2.1, the limit of which we denoted by γ(a). In order to do this we shall prove, in a similar way as in [3, Lemma 2.1], some finer inequalities than those used by H. Alzer in [2, Theorem 3]. Lemma 3.1. We have: (i) ψ(x + 1) − ln x > (ii) 1 x − ψ 0 (x + 1) < 1 2x 1 2x2 − − 1 12x2 1 6x3 + + 1 120x4 1 30x5 − − 1 , 252x6 1 42x7 + for each x ∈ (0, +∞); 1 , 30x9 for each x ∈ (0, +∞). We specify that the function ψ is the logarithmic derivative of the gamma function, 0 (x) i.e. ψ(x) = ΓΓ(x) , for each x ∈ (0, +∞). R ∞ −t −xt Proof. (i) It is known (see, for example, [18, p. 116]) that ln x = 0 e −e dt, for t each x ∈ (0, +∞). Also, we shall need the formula Z ∞ −t e e−xt ψ(x) = − dt, t 1 − e−t 0 vol. 9, iss. 2, art. 46, 2008 Title Page Contents JJ II J I Page 6 of 15 Go Back Full Screen Close which holds for each x ∈ (0, +∞), known as Gauss’ expression of ψ(x) as an infinite integral (see, for example, [18, p. 247]). Having in view the above relations, we are able to write that Z ∞ 1 1 ψ(x + 1) − ln x = − t e−xt dt, t e −1 0 for each x ∈ (0, +∞). It is not difficult to verify that Z ∞ Generalization of Euler’s Constant Alina Sîntămărian tn e−xt dt = 0 n! , xn+1 for each n ∈ N ∪ {0}, any x ∈ (0, +∞). Then we have 1 1 1 1 + − + ψ(x + 1) − ln x − 2x 12x2 120x4 252x6 Z ∞ 1 1 1 t t3 t5 = − t − + − + e−xt dt t e − 1 2 12 720 30240 Z0 ∞ 1 [30240(et − 1) − 30240t − 15120t(et − 1) + 2520t2 (et − 1) = t − 1) 30240t(e 0 − 42t4 (et − 1) + t6 (et − 1)]e−xt dt " Z ∞ ∞ ∞ n+1 ∞ n+2 X X X tn t t 1 30240 − 15120 + 2520 = 30240t(et − 1) n! n! n! 0 n=2 n=1 n=1 # ∞ n+4 ∞ n+6 X X t t −42 + e−xt dt n! n! n=1 n=1 vol. 9, iss. 2, art. 46, 2008 Title Page Contents JJ II J I Page 7 of 15 Go Back Full Screen Close Z = 0 ∞ ∞ P n=9 (n−3)(n−5)(n−7)(n−8)(n2 +8n+36) n t n! 30240t(et − 1) · e−xt dt > 0, for each x ∈ (0, +∞). (ii) In part (i) we obtained that Z ln x − ψ(x + 1) = 0 ∞ et 1 1 − −1 t e−xt dt, for each x ∈ (0, +∞). Differentiating here we get that Z ∞ 1 t 0 − ψ (x + 1) = 1− t e−xt dt, x e − 1 0 for each x ∈ (0, +∞). Then we have 1 1 1 1 1 1 − ψ 0 (x + 1) − 2 + 3 − + − x Z 2x 6x 30x5 42x7 30x9 ∞ 2 t t t t4 t6 t8 = 1− t − + − + − e−xt dt e − 1 2 12 720 30240 1209600 Z0 ∞ 1 [1209600(et − 1) − 1209600t − 604800t(et − 1) = t − 1) 1209600(e 0 + 100800t2 (et − 1) − 1680t4 (et − 1) + 40t6 (et − 1) − t8 (et − 1)]e−xt dt Generalization of Euler’s Constant Alina Sîntămărian vol. 9, iss. 2, art. 46, 2008 Title Page Contents JJ II J I Page 8 of 15 Go Back Full Screen Close Z ∞ = 0 " ∞ ∞ n+1 X X tn 1 t 1209600 − 604800 1209600(et − 1) n! n! n=2 n=1 +100800 Z =− 0 ∞ ∞ n+2 X t n! − 1680 ∞ n+4 X t n! + 40 ∞ n+6 X t n! n=1 n=1 n=1 (n−3)(n−5)(n−7)(n−9)(n−10)(n+4)(n2 +2n+32) n t n=11 n! 1209600(et − 1) P∞ − ∞ n+8 X t n=1 # n! e−xt dt · e−xt dt < 0, Generalization of Euler’s Constant Alina Sîntămărian for each x ∈ (0, +∞). vol. 9, iss. 2, art. 46, 2008 Remark 4. In fact, these inequalities from Lemma 3.1 come from the asymptotic formulae (see, for example, [1, pp. 259, 260]) Title Page ∞ X B2n 1 ψ(x) ∼ ln x − − 2x n=1 2nx2n = ln x − 1 1 1 1 − + − + ··· 2 4 2x 12x 120x 252x6 Contents JJ II J I Page 9 of 15 and ∞ X B2n 1 1 ψ (x) ∼ + 2 + x 2x x2n+1 n=1 Go Back 0 = 1 1 1 1 1 1 + 2+ 3− + − + ··· , 5 7 x 2x 6x 30x 42x 30x9 where B2n is the Bernoulli number of index 2n. Theorem 3.2. Let a ∈ (0, +∞). We consider the sequence (yn )n∈N from the statement of Theorem 2.1, the limit of which we denoted by γ(a). Full Screen Close Then 1 1 ≤ yn − γ(a) < , 2(a + n − 1) + α 2(a + n − 1) + β 1 − 2(a + 2) and β = 31 . for each n ∈ N \ {1, 2}, with α = y3 −γ(a) Moreover, the constants α and β are the best possible with this property. Proof. The inequalities from the statement of the theorem can be rewritten in the form 1 β< − 2(a + n − 1) ≤ α, yn − γ(a) for each n ∈ N \ {1, 2}. Taking into account that ψ(x + 1) = ψ(x) + x1 , for each x ∈ (0, +∞), we can write that 1 1 1 ψ(a + n) − ψ(a) = + + ··· + , a a+1 a+n−1 for each n ∈ N (see, for example, [1, p. 258]). It is known that we have the series expansion (see, for example, [9, p. 336]) ∞ X 1 1 ψ(x) = ln x − − ln 1 + , x+k x+k k=0 for each x ∈ (0, +∞). So, we are able to write the following relation between γ(a) and the logarithmic derivative of the gamma function: γ(a) = ln a − ψ(a) (see [6, Theorem 7], [11, Theorem 4.1, Remark 4.2]). Generalization of Euler’s Constant Alina Sîntămărian vol. 9, iss. 2, art. 46, 2008 Title Page Contents JJ II J I Page 10 of 15 Go Back Full Screen Close Then a+n−1 − [ln a − ψ(a)] a = ψ(a + n) − ln(a + n − 1), yn − γ(a) = ψ(a + n) − ψ(a) − ln for each n ∈ N. It means that, in fact, we have to prove that 1 − 2(a + n − 1) ≤ α, β< ψ(a + n) − ln(a + n − 1) for each n ∈ N \ {1, 2}, and that the constants α and β are the best possible with this property. We consider the function f : (0, +∞) → R, defined by 1 f (x) = − 2x, ψ(x + 1) − ln x for each x ∈ (0, +∞). Differentiating, we get that f 0 (x) = 1 x 0 2 − ψ (x + 1) − 2[ψ(x + 1) − ln x] , [ψ(x + 1) − ln x]2 for each x ∈ (0, +∞). Using the inequalities from Lemma 3.1, we are able to write that 1 − ψ 0 (x + 1) − 2[ψ(x + 1) − ln x]2 x 2 1 1 1 1 1 1 1 1 1 < 2− 3+ − + −2 − + − 2x 6x 30x5 42x7 30x9 2x 12x2 120x4 252x6 1 1 1 1 221 1 1 1 =− + + − − + + − 4 5 6 7 8 9 10 72x 60x 360x 63x 151200x 30x 7560x 31752x12 =: g(x), Generalization of Euler’s Constant Alina Sîntămărian vol. 9, iss. 2, art. 46, 2008 Title Page Contents JJ II J I Page 11 of 15 Go Back Full Screen Close for 3 each x 3 ∈ (0, +∞). It is not difficult to verify that g(x) < 0, for each x ∈ , +∞ ( 2 not being the best lower value possible with this property). It follows 2 f 0 (x) < 0, for each x ∈ 32 , +∞ . So, the function f is strictly decreasing on that 3 , +∞ . This means that the sequence (f (a + n − 1))n≥3 is strictly decreasing. 2 Therefore lim f (a + k − 1) < f (a + n − 1) k→∞ ≤ f (a + 2) 1 − 2(a + 2), = y3 − γ(a) for each n ∈ N \ {1, 2}. The asymptotic formula for the function ψ, mentioned in Remark 4, permits us to write that 1 + O x12 1 6 = . lim f (x) = lim 1 1 x→∞ x→∞ 3 +O x 2 Generalization of Euler’s Constant Alina Sîntămărian vol. 9, iss. 2, art. 46, 2008 Title Page Contents JJ II J I Page 12 of 15 1 Theorem 3.3. Let a ∈ 2 , +∞ . We consider the sequence (yn )n∈N from the statement of Theorem 2.1, the limit of which we denoted by γ(a). Then 1 1 ≤ yn − γ(a) < , 2(a + n − 1) + α 2(a + n − 1) + β 1 for each n ∈ N \ {1}, with α = y2 −γ(a) − 2(a + 1) and β = 31 . Moreover, the constants α and β are the best possible with this property. Proof. Since a ∈ 12 , +∞ , it follows that the sequence (f (a + n − 1))n≥2 is strictly decreasing, where f is the function defined in the proof of Theorem 3.2. Go Back Full Screen Close Theorem 3.4. Let a ∈ 32 , +∞ . We consider the sequence (yn )n∈N from the statement of Theorem 2.1, the limit of which we denoted by γ(a). Then 1 1 ≤ yn − γ(a) < , 2(a + n − 1) + α 2(a + n − 1) + β 1 for each n ∈ N, with α = y1 −γ(a) − 2a = a[2aγ(a)−1] and β = 13 . 1−aγ(a) Moreover, the constants α and β are the best possible with this property. Proof. Since a ∈ 32 , +∞ , it follows that the sequence (f (a + n − 1))n∈N is strictly decreasing, where f is the function defined in the proof of Theorem 3.2. Generalization of Euler’s Constant Alina Sîntămărian vol. 9, iss. 2, art. 46, 2008 Title Page Contents JJ II J I Page 13 of 15 Go Back Full Screen Close References [1] M. ABRAMOWITZ AND I.A. STEGUN, Handbook of Mathematical Functions with Formulas, Graphs, and Mathematical Tables, National Bureau of Standards Applied Mathematics Series 55, Washington, 1964. [2] H. ALZER, Inequalities for the gamma and polygamma functions, Abh. Math. Sem. Univ. Hamburg, 68 (1998), 363–372. 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YOUNG, Euler’s constant, Math. Gaz., 75(472) (1991), 187–190. Title Page Contents JJ II J I Page 15 of 15 Go Back Full Screen Close