Journal of Inequalities in Pure and Applied Mathematics ON THE LOCATION OF ZEROS OF COMPLEX POLYNOMIALS MATTHIAS DEHMER Technische Universität Darmstadt Department of Computer Science Hochschulstraße 10 64289 Darmstadt, Germany. volume 7, issue 1, article 26, 2006. Received 05 April, 2004; accepted 12 December, 2005. Communicated by: D. Stefanescu EMail: matthias@dehmer.org Abstract Contents JJ J II I Home Page Go Back Close c 2000 Victoria University ISSN (electronic): 1443-5756 073-04 Quit Abstract This paper proves bounds for the zeros of complex valued polynomials. The assertions stated in this work have been specialized in the area of the location of zeros for complex polynomials in terms of two foci: (i) finding bounds for complex valued polynomials with special conditions for the coefficients and (ii) locating zeros of complex valued polynomials without special conditions for the coefficients − especially we are searching for bounds, which again are positive roots of concomitant polynomials. As a result we obtain new zero bounds for univariate polynomials with complex coefficients. 2000 Mathematics Subject Classification: 30C15. Key words: Complex polynomials, zeros, inequalities. I thank the referee of the present paper for fruitful comments. Furthermore I thank Frank Emmert-Streib (Stowers Institute, USA) and Ralf Tandetzky (University of Jena, Germany) for helpful discussions and comments concerning this work. Contents 1 2 Introduction . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 3 Bounds for the Zeros of Complex Polynomials with Special Conditions for the Coefficients . . . . . . . . . . . . . . . . . . . . . . . . . 4 3 Further Bounds for the Zeros of Complex Polynomials . . . . . 11 4 Evaluation of Zero Bounds . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 21 5 Conclusions . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 25 References On the Location of Zeros of Complex Polynomials Matthias Dehmer Title Page Contents JJ J II I Go Back Close Quit Page 2 of 27 J. Ineq. Pure and Appl. Math. 7(1) Art. 26, 2006 http://jipam.vu.edu.au 1. Introduction The problems in the analytic theory of polynomials concerning locating zeros of complex polynomials have been frequently investigated. Over many decades, a large number of research papers, e.g, [1, 2, 3, 5, 6, 8, 9, 12, 13, 14] and monographs [7, 10, 11] have been published. The new theorems in this paper provide closed disks in the complex plane K(z0 , r) := {z ∈ C | |z − z0 | ≤ r}, z0 ∈ C, r ∈ R+ , containing all zeros of a complex valued polynomial. The steps to achieve this are as follows: Let n X fn : C −→ C; fn (z) = ai z i , ai ∈ C, n ≥ 1, On the Location of Zeros of Complex Polynomials i=0 Title Page be a complex polynomial. Construct a bound S = S(a0 , a1 , . . . , an ) in such a way that all zeros of f (z) are situated in the closed disk Contents K(z0 , S(a0 , a1 , . . . , an )) := {z ∈ C | |z − z0 | ≤ S(a0 , a1 , . . . , an )} . Without loss of generality we set z0 = 0. A special case is the existence of certain conditions, thus resulting in special bounds. This paper is organized as follows: Section 2 provides such bounds on the basis of certain conditions, concerning the polynomials’ coefficients. In Section 3 mainly zero bounds are proved which are positive roots of algebraic equations. The main result of Section 3 is a theorem which is an extension of a classical result of Cauchy. Section 4 shows applications of the bounds in such a way that the bounds will be evaluated with certain polynomials. The paper finishes in Section 5 with conclusions. Matthias Dehmer JJ J II I Go Back Close Quit Page 3 of 27 J. Ineq. Pure and Appl. Math. 7(1) Art. 26, 2006 http://jipam.vu.edu.au 2. Bounds for the Zeros of Complex Polynomials with Special Conditions for the Coefficients Definition 2.1. Let fn : C −→ C; fn (z) = n X ai z i , n ≥ 1, i=0 be a complex polynomial. fn (z) = an z n + fn−1 (z) , (2.1) On the Location of Zeros of Complex Polynomials f0 (z) := a0 Matthias Dehmer denotes the recursive description of fn (z). Theorem 2.1. Let P (z) be a complex polynomial, such that P (z) is reducible in C[z], P (z) := fn1 (z)gn2 (z) = (bn1 z n1 + fn1 −1 (z))(cn2 z n2 + gn2 −1 (z)) with |bn1 | > |bi |, 0 ≤ i ≤ n1 − 1, |cn2 | > |ci |, 0 ≤ i ≤ n2 − 1. K(0, δ), (2.3) z − 4z n1 +n2 +1 It holds for 1 < δ < 2 + √ + 2z n1 +n2 +z JJ J II I Close Quit where δ > 1 is the positive root of the equation n1 +n2 +2 Contents Go Back If n1 + n2 > 1, then all zeros of the polynomial P (z) lie in the closed disk (2.2) Title Page n2 +1 Page 4 of 27 +z n1 +1 − 1 = 0. J. Ineq. Pure and Appl. Math. 7(1) Art. 26, 2006 2. http://jipam.vu.edu.au Proof. Expanding fn1 −1 (z), we conclude fn1 −1 (z) = nX 1 −1 bi z i , i=0 analogously gn2 −1 (z) = nX 2 −1 ci z i . i=0 Assuming (2.4) |bn1 | > |bi |, 0 ≤ i ≤ n1 − 1, |cn2 | > |ci |, 0 ≤ i ≤ n2 − 1, On the Location of Zeros of Complex Polynomials Matthias Dehmer it follows that P 1 −1 i | ni=0 bi z | |fn1 −1 (z)| = |bn1 | |bn1 | nX −1 1 |bi | i ≤ |z| |b | n 1 i=0 < nX 1 −1 |z|i = i=0 |z|n1 − 1 . |z| − 1 With the inequalities (2.4) above, we find that |P (z)| = (bn1 z n1 + fn1 −1 (z))(cn2 z n2 + gn2 −1 (z))| ≥ |bn1 ||cn2 ||z|n1 +n2 − {|bn1 ||z n1 ||gn2 −1 (z)| + |cn2 ||z n2 ||fn1 −1 (z)| + |fn1 −1 (z)||gn2 −1 (z)|} Title Page Contents JJ J II I Go Back Close Quit Page 5 of 27 J. Ineq. Pure and Appl. Math. 7(1) Art. 26, 2006 http://jipam.vu.edu.au |gn −1 (z)| |fn −1 (z)| = |bn1 ||cn2 | |z| − | z|n1 2 + |z|n2 1 |c | |bn1 | n2 |fn1 −1 (z)| |gn2 −1 (z)| + · |bn1 | |cn2 | |z|n2 − 1 |z|n1 − 1 n1 +n2 > |bn1 ||cn2 | |z| − |z|n1 + |z|n2 |z| − 1 |z| − 1 n1 n2 (|z| − 1)(|z| − 1) + (|z| − 1)2 |bn1 ||cn2 | = {|z|n1 +n2 +2 − 4|z|n1 +n2 +1 + 2|z|n1 +n2 + |z|n2 +1 + |z|n1 +1 − 1}, 2 (|z| − 1) | {z } n1 +n2 On the Location of Zeros of Complex Polynomials Matthias Dehmer >0 Title Page Let Contents H(|z|) := |z|n1 +n2 +2 − 4|z|n1 +n2 +1 + 2|z|n1 +n2 + |z|n2 +1 + |z|n1 +1 − 1, and we assume n1 + n2 > 1. Hence |P (z)| > 0 if H(|z|) > 0. Applying Descartes’ Rule of Signs [4] to H(|z|), we can conclude that H(|z|) has either one or three positive zeros δ1 , δ2 , and δ3 . Now we examine the positive zeros of H(|z|). At first H(1) = 0 . JJ J II I Go Back Close Quit Page 6 of 27 Dividing H(|z|) by |z| − 1 yields J. Ineq. Pure and Appl. Math. 7(1) Art. 26, 2006 (|z|n1 +n2 +2 − 4|z|n1 +n2 +1 + 2|z|n1 +n2 + |z|n2 +1 + |z|n1 +1 − 1) : (|z| − 1) http://jipam.vu.edu.au n1 +n2 +1 = |z| n1 +n2 − 3|z| − n1 +n X2 −1 j |z| + j=n1 +1 n2 X |z|j . j=0 Further, let R(|z|) := |z|n1 +n2 +1 − 3|z|n1 +n2 − n1 +n X2 −1 |z|j + j=n1 +1 n2 X |z|j . j=0 We see that R(1) = 0 and infer On the Location of Zeros of Complex Polynomials H(|z|) = (|z| − 1)R(|z|) = (|z| − 1)2 Q(|z|), deg(Q(|z|)) = n1 + n2 , hence δ1 = δ2 = 1 is a zero with multiplicity two. Altogether, H has exactly three positive zeros. Now, we note that sign{H(0)} = −1, sign{H(∞)} = 1, and we choose K > 1 such that H(K) > 0. On the other hand, it holds that H(1) = H 0 (1) = 0 and H 00 (1) < 0. Therefore, there exists a θ > 0 such that H(z) < 0, 1 ≤ z ≤ 1 + θ. Now, we obtain H(1 + θ) < 0 < H(K) and therefore δ3 := δ ∈ (1 + θ, K), hence δ > 1. Thus, |P (z)| > 0, if H(|z|) > 0, |z| > δ. According to this, all zeros of P (z) lie in the closed disk K(0, δ). In order to examine the value of δ > 1, we replace |z| with δ in equation (2.3) and examine the equation R(δ) = δ n1 +n2 +1 − 3δ n1 +n2 − n1 +n X2 −1 j=n1 +1 δj + n2 X j=0 δ j = 0. Matthias Dehmer Title Page Contents JJ J II I Go Back Close Quit Page 7 of 27 J. Ineq. Pure and Appl. Math. 7(1) Art. 26, 2006 http://jipam.vu.edu.au The formulas 1 + δ + δ 2 + · · · + δ n1 + δ n1 +1 + · · · + δ n1 +n2 −1 = ⇐⇒ n1 +n X2 −1 δj = δ n1 +n2 − 1 − (1 + δ + δ 2 + · · · + δ n1 ) δ−1 δj = δ n1 +n2 − 1 δ n1 +1 − 1 δ n1 +n2 − δ n1 +1 − = δ−1 δ−1 δ−1 j=n1 +1 ⇐⇒ n1 +n X2 −1 δ n1 +n2 − 1 δ−1 j=n1 +1 yield the result Matthias Dehmer δ n1 +n2 +1 − 3δ n1 +n2 − δ n1 +n2 − δ n1 +1 δ n2 +1 − 1 = 0. + δ−1 δ − 1 | {z } >0 From this equation follows the inequality δ n1 +n2 +1 − 3δ n1 +n2 − δ n1 +n2 − δ n1 +1 < 0, δ−1 and, furthermore, (2.5) On the Location of Zeros of Complex Polynomials Title Page Contents JJ J II I Go Back Close δ n1 +1 (δ n2 +1 − 4δ n2 + 2δ n2 −1 + 1) < 0 . Quit Page 8 of 27 Inequality (2.5) implies δ n2 2 δ−4+ δ < −1 J. Ineq. Pure and Appl. Math. 7(1) Art. 26, 2006 http://jipam.vu.edu.au and we finally conclude δ 2 − 4δ + 2 < 0 . (2.6) To solve inequality (2.6) take a closer look at ξ 2 − 4ξ + 2 = 0, and see that ξ1,2 = 2 ± √ 2. With the fact that δ > 1, the inequality holds for 1 < δ < 2 + completes the proof of Theorem 2.1. √ 2. This On the Location of Zeros of Complex Polynomials Matthias Dehmer Theorem 2.1 can be strengthened by Theorem (2.2). Title Page Theorem 2.2. Let P (z) := an z n + an−1 z n−1 + · · · + a0 , Contents an 6= 0 , n ≥ 1, i = 0, 1, . . . , n be a complex polynomial such that |an | > |ai |, i = 0, 1, . . . , n − 1. Then all zeros of P (z) lie in the closed disk K(0, 2). Proof. For |z| ≤ 1 the conclusion of Theorem 2.2 is evident. If we assume that |z| > 1 we obtain immediately |P (z)| = |an z n + an−1 z n−1 + · · · + a0 | ≥ |an ||z|n − {|an−1 |z|n−1 + · · · + a0 } |an−1 | 1 |a0 | 1 n = |an ||z| 1 − + ··· + . |an | |z| |an | |z|n JJ J II I Go Back Close Quit Page 9 of 27 J. Ineq. Pure and Appl. Math. 7(1) Art. 26, 2006 http://jipam.vu.edu.au Now if |an | > |ai |, i = 0, 1, . . . , n − 1 is assumed, we conclude |an−1 | 1 |a0 | 1 n |P (z)| ≥ |an ||z| 1 − + ··· + |an | |z| |an | |z|n ( ) n X 1 > |an ||z|n 1 − |z|j j=1 ) ( ∞ X 1 > |an ||z|n 1 − |z|j j=1 ) ( 1 = |an ||z|n 1 − 1 +1 1 − |z| = |an ||z|n {|z| − 2}. |z| − 1 | {z } Matthias Dehmer Title Page Contents >0 Hence, we get |P (z)| > 0 if On the Location of Zeros of Complex Polynomials |z| > 2. JJ J II I Go Back Close Quit Page 10 of 27 J. Ineq. Pure and Appl. Math. 7(1) Art. 26, 2006 http://jipam.vu.edu.au 3. Further Bounds for the Zeros of Complex Polynomials Now we prove Theorem 3.2, which is similar to Theorem 3.1. Theorem 3.1 is a classic result for the location of zeros found by Cauchy [7]. The zero bound of the new Theorem 3.2, as well as Theorem 3.1, depends on an algebraic equation’s positive root. Theorem 3.1 (Cauchy). Let n f (z) = an z + an−1 z n−1 + · · · + a0 , an 6= 0, k = 0, 1, . . . , n On the Location of Zeros of Complex Polynomials Matthias Dehmer be a complex polynomial. All zeros of f (z) lie in the closed disk K(0, ρC ), where ρC denotes the positive zero of HC (z) := |a0 | + |a1 |z + · · · + |an−1 |z n−1 n − |an |z . Theorem 3.2. Let f (z) = an z n + an−1 z n−1 + · · · + a0 , an 6= 0, k = 0, 1, . . . , n be a complex polynomial. All zeros of f (z) lie in the closed disk K(0, max(1, δ)), a where M := max anj and δ 6= 1 denotes the positive root of the equation Title Page Contents JJ J II I Go Back Close 0≤j≤n−1 Quit z n+1 − (1 + M )z n + M = 0. Proof. On the basis of the inequality (3.1) |f (z)| ≥ |an | |z|n − M {|z|n−1 + · · · + 1} , Page 11 of 27 J. Ineq. Pure and Appl. Math. 7(1) Art. 26, 2006 http://jipam.vu.edu.au we get the modulus of f (z) |f (z)| ≥ |an | |z|n − M {|z|n−1 + · · · + 1} |z|n − 1 n = |an | |z| − M |z| − 1 n+1 |z| − |z|n (1 + M ) + M . = |an | |z| − 1 Define F (z) := z n+1 n − z (1 + M ) + M. Using the Descartes’ Rule of Signs we have that F (z) has exactly two positive zeros δ1 and δ2 , and F (δ1 = 1) = 0 holds. With On the Location of Zeros of Complex Polynomials Matthias Dehmer Title Page sign{F (0)} = 1 Contents and from the fact that F (z) has exactly two positive zeros, we finally conclude that |f (z)| > 0 for |z| > max(1, δ). JJ J II I Go Back Hence, all zeros of f (z) lie in K(0, max(1, δ)). Close Now, we express a further theorem, the proof of which is similar to that of Theorem 3.2. Page 12 of 27 Theorem 3.3. Let f (z) = an z n + an−1 z n−1 + · · · + a0 , Quit an 6= 0, k = 0, 1, . . . , n J. Ineq. Pure and Appl. Math. 7(1) Art. 26, 2006 http://jipam.vu.edu.au be a complex polynomial. All zeros of f (z) lie in the closed disk K(0, max(1, δ)), where an−j − an−j−1 , a−1 := 0 M̃ := max 0≤j≤n an and δ 6= 1 denotes the positive root of the equation z n+2 − (1 + M̃ )z n+1 + M̃ = 0. Furthermore we can state immediately a new Theorem 3.4 which is very similar to a well known theorem due to Cauchy [7]. It provides an upper bound for all zeros of a complex polynomial f (z). In many cases the bound of Theorem 3.4 is sharper than the bound of Cauchy [7] (K(0, 1 + M )). Theorem 3.4. Let f (z) = an z n + an−1 z n−1 + · · · + a0 , On the Location of Zeros of Complex Polynomials Matthias Dehmer Title Page an 6= 0, k = 0, 1, . . . , n be a complex polynomial. All zeros of f (z) lie in the closed disk K(0, 1 + M̃ ). Proof. For the zeros with |z| ≤ 1, we have nothing to prove. Assuming |z| > 1 and define P (z) := (1 − z)f (z) = −an z n+1 + (an − an−1 )z n + · · · + (a1 − a0 )z + a0 . Now, we obtain the estimation |P (z)| ≥ |an ||z|n+1 − |an − an−1 ||z|n + |an−1 − an−2 ||z|n−1 + · · · +|a1 − a0 ||z| + |a0 |} Contents JJ J II I Go Back Close Quit Page 13 of 27 J. Ineq. Pure and Appl. Math. 7(1) Art. 26, 2006 http://jipam.vu.edu.au an − an−1 n an−1 − an−2 n−1 n+1 |z| = |an | |z| − + ··· |z| + an an a1 − a0 a0 − 0 + |z| + an an ( ) n X ≥ |an | |z|n+1 − M̃ |z|i i=0 n+1 |z| −1 n+1 = |an | |z| − M̃ |z| − 1 |z|n n+1 > |an | |z| − M̃ |z| − 1 n o |an | n+2 n+1 = |z| − |z| (1 + M̃ ) . |z| − 1 | {z } >0 Finally, we conclude |z|n+2 − |z|n+1 (1 + M̃ ) = |z|n+1 [|z| − (1 + M̃ )] > 0. On the Location of Zeros of Complex Polynomials Matthias Dehmer Title Page Contents JJ J II I Go Back We infer |P (z)| > 0 if |z| > 1+ M̃ . Hence, all zeros of P (z) lie in K(0, 1+ M̃ ). Because of the fact that all zeros of f (z) are zeros of P (z), Theorem 3.4 holds also for f (z). Now, we prove Theorem 3.5, which provides a zero bound for complex polynomials that are in a more general form than the previous ones. Close Quit Page 14 of 27 J. Ineq. Pure and Appl. Math. 7(1) Art. 26, 2006 http://jipam.vu.edu.au Theorem 3.5. Let f (z) = an z n + an−1 z n−1 + · · · + a0 , an 6= 0, k = 0, 1, . . . , n be a complex polynomial and H(z) := (f (z))σ , N 3 σ ≥ 1. All zeros of H(z) lie in the closed disk K(0, ρ), where ρ is the positive zero of ( n−1 !σ X |ai |z i (3.2) H̃(z) := |an |σ z nσ − i=0 + σ−1 X j=1 |an |j z nj n−1 X i=0 !σ−j σ . |ai |z i j Proof. Define H(z) := (f (z))σ , this yields the estimation !σ !σ n−1 n X X |H(z)| = ai z i = ai z i + an z n i=0 i=0 !σ−j X n−1 X σ σ (an z n )j = ai z i j j=0 i=0 !σ−j σ−1 n−1 X X σ (an z n )j = (an z n )σ + ai z i j j=0 i=0 !σ−j σ−1 n−1 X X σ (an z n )j ≥ |an z n |σ − ai z i j j=0 i=0 On the Location of Zeros of Complex Polynomials Matthias Dehmer Title Page Contents JJ J II I Go Back Close Quit Page 15 of 27 J. Ineq. Pure and Appl. Math. 7(1) Art. 26, 2006 http://jipam.vu.edu.au !σ σ−1 !σ−j n−1 n−1 X X X σ (an z n )j = |an z n |σ − ai z i + ai z i j i=0 j=1 i=0 ! ! σ σ−j n−1 σ−1 n−1 X X X σ (an z n )j ≥ |an z n |σ − ai z i + ai z i j i=0 j=1 i=0 ( n−1 !σ X ≥ |an |σ |z|nσ − |ai ||z|i i=0 + σ−1 X j=1 |an z n |j !σ−j n−1 X σ |ai ||z|i j On the Location of Zeros of Complex Polynomials Matthias Dehmer i=0 Title Page := H̃(|z|) . H̃(z) is a polynomial with only real and positive coefficients. Therefore we apply the Descartes’ Rule of Signs and obtain that H̃(z) has exactly one positive zero ρ. Furthermore, we determine easily H̃(0) = −|a0 |σ < 0. With !σ−j σ−1 n−1 X X σ (an z n )j H̃1 (z) := (an z n )σ and H̃2 (z) := ai z i , j j=0 i=0 Contents JJ J II I Go Back Close Quit Page 16 of 27 we infer deg(H̃1 (z)) > deg(H̃2 (z)). Finally, it follows that all zeros of H(z) lie in the closed disk K(0, ρ). J. Ineq. Pure and Appl. Math. 7(1) Art. 26, 2006 http://jipam.vu.edu.au The following corollary states that the bound of Theorem 3.5 is a generalization of Cauchy’s bound concerning Theorem 3.1. Corollary 3.6. σ = 1 in Equation (3.2) leads to the bound of Cauchy, Theorem 3.1. Proof. If we set σ = 1 in equation (3.2), we obtain n H̃(z) = |an |z − n−1 X |ai |z i . On the Location of Zeros of Complex Polynomials i=0 Therefore, we have H̃(z) = −HC (z) and H̃(z) posseses the same positive zero as HC (z). Thus we have the bound of Cauchy, Theorem 3.1. The last theorem in this paper expresses another bound for the zeros of H(z). Here, the belonging concomitant polynomial is easier to solve that the concomitant polynomial of Theorem 3.5. Theorem 3.7. Let f (z) = an z n + an−1 z n−1 + · · · + a0 , an 6= 0, k = 0, 1, . . . , n be a complex polynomial and H(z) := (f (z))σ , N 3 σ ≥ 1. Furthermore let B := max0≤i≤n−1 |ai | and K := max0≤j≤σ−1 |an |j B σ−j σj . All zeros of H(z) lie in the closed disk K(0, ρ), where ρ > 1 is the largest positive zero of the equation |an |σ (|z| − 1)σ − K|z|σ − B σ |z| + B σ . Matthias Dehmer Title Page Contents JJ J II I Go Back Close Quit Page 17 of 27 J. Ineq. Pure and Appl. Math. 7(1) Art. 26, 2006 http://jipam.vu.edu.au Proof. Starting from H̃(|z|), obtained in the proof of Theorem 3.5 and the inequality n−1 n−1 X X i ai |z| ≤ B |z|i , i=0 i=0 we have σ nσ |H(z)| ≥ |an | |z| σ n |z| − 1 σ − B |z| − 1 " n σ−j #) σ−1 X σ |z| − 1 + |an |j |z|nj B σ−j . j |z| − 1 j=1 On the Location of Zeros of Complex Polynomials Matthias Dehmer If we now assume |z| > 1 we obtain the inequalities ( σ n σ−j ) σ−1 n X |z| − 1 |z| − 1 |H(z)| > |an |σ |z|nσ − B σ +K |z|nj |z| − 1 |z| − 1 j=1 ( ) σ−1 X |z|nσ |z|nσ σ nσ σ +K > |an | |z| − B (|z| − 1)σ (|z| − 1)σ−j j=1 #) ( " σ−1 σ X K B + (|z| − 1)j . = |z|nσ |an |σ − (|z| − 1)σ (|z| − 1)σ j=1 JJ J On the basis of the relation Page 18 of 27 σ−1 X j=1 (|z| − 1)j < σ−1 X j=0 |z|j , Title Page Contents II I Go Back Close Quit J. Ineq. Pure and Appl. Math. 7(1) Art. 26, 2006 http://jipam.vu.edu.au we conclude furthermore that Bσ K |z|σ − 1 nσ σ |H(z)| > |z| |an | − + · (|z| − 1)σ (|z| − 1)σ |z| − 1 Bσ K|z|σ nσ σ > |z| |an | − + (|z| − 1)σ (|z| − 1)σ+1 |z|nσ = |an |σ (|z| − 1)σ+1 − K|z|σ − B σ |z| + B σ . σ+1 (|z| − 1) | {z } >0 Define P (z) := |an |σ (z − 1)σ+1 − Kz σ − B σ z + B σ . We see immediately that deg(P (z)) = deg |an |σ (z − 1)σ+1 − Kz σ − B σ z + B σ ! σ+1 X σ + 1 = deg |an |σ (−1)j z σ+1−j − Kz σ − B σ z + B σ j j=0 Matthias Dehmer Title Page Contents JJ J = σ + 1, hence we infer lim P (z) = ∞. (3.3) z→∞ Now, it holds ( P (0) = On the Location of Zeros of Complex Polynomials |an |σ + B σ : σ is odd −|an |σ + B σ : σ is even Furthermore we obtain P (1) = −K < 0. In the first case P (0) = |an |σ + B σ > 0 it follows that P (z) has at least two positive zeros α1 < α2 and α2 > 1. The II I Go Back Close Quit Page 19 of 27 J. Ineq. Pure and Appl. Math. 7(1) Art. 26, 2006 http://jipam.vu.edu.au case P (0) = −|an |σ + B σ > 0 ⇐⇒ B σ > |an |σ leads us to the same situation. Now, we assume P (0) = −|an |σ + B σ < 0 ⇐⇒ B σ < |an |σ and it holds that P (1) < 0. With equation (3.3) we conclude that P (z) has at least one positive zero α > 1. Let α1 , α2 , . . . , ατ , 1 ≤ τ ≤ deg(P (z)) be the positive zeros of P (z) and ρ := max (α1 , α2 , . . . , ατ ). 1≤τ ≤deg(H̃(x)) Finally, we infer that |P (z)| > 0 if |z| > ρ > 1. This inequality completes the proof of Theorem 3.7. On the Location of Zeros of Complex Polynomials Matthias Dehmer Title Page Contents JJ J II I Go Back Close Quit Page 20 of 27 J. Ineq. Pure and Appl. Math. 7(1) Art. 26, 2006 http://jipam.vu.edu.au 4. Evaluation of Zero Bounds P Let f (z) = ni=0 ai z i , an 6= 0, n ≥ 1, be a complex polynomial and z1 , z2 , . . . , zn be the zeros of f (z). Define ξ := max (|z1 |, |z2 |, . . . , |zn |) and S1 := max(1, δ), Theorem(2.1) S2 := δ, Theorem(3.2) S3 := δ, Theorem(3.3) S4 := 1 + M̃ , Theorem(3.4) S5 := ρ, Theorem(3.7) On the Location of Zeros of Complex Polynomials Now, we consider the closed disks |z| ≤ Si , i = 1, 2, . . . , 4 for each complex polynomial fj (z), j = 1, 2, . . . , 6. Matthias Dehmer Title Page 1. f1 (z) := 360 · z 6 − 194z 5 − 79z 4 + 33z 3 + 11z 2 − 12z − 5 = (18z 2 − 7z − 5) · (20z 4 − 3z 3 + z + 1), therefore it holds |b2 | > |bi |, 0 ≤ i ≤ 1, |c4 | > |ci |, 0 ≤ i ≤ 3. Contents JJ J II I Go Back Close Zeros of f1 (z): z1 z2 z3 z4 . = −0, 3051 − 0, 2775i , . = −0, 3051 + 0, 2775i , . = 0, 3801 − 0, 3864i , . = 0, 3801 + 0, 3864i , Quit Page 21 of 27 J. Ineq. Pure and Appl. Math. 7(1) Art. 26, 2006 http://jipam.vu.edu.au . z5 = −0, 3673 , . z6 = 0, 7562 . 2. f2 (z) := z 5 − iz 4 + iz 2 − z + i. Zeros of f2 (z): z1 z2 z3 z4 z5 . = −1, 1140 − 0, 1223i , . = −0, 8766i , . = 0, 5950i , . = 1, 5262i , . = 1, 1140 − 0, 1223i . On the Location of Zeros of Complex Polynomials Matthias Dehmer Title Page 3. f3 (z) := z 3 − 1000z 2 + 2000z + 1500. Zeros of f3 (z): . z1 = −0, 5810 , . z2 = 2, 5866 , . z3 = 997, 9944 . 4. Contents JJ J II I Go Back Close Quit f4 (z) := 10z 4 + z 3 + (3 + 2i)z 2 + z(−2 + i) + i = (5z 2 − 2z + i) · (2z 2 + z + 1), Page 22 of 27 J. Ineq. Pure and Appl. Math. 7(1) Art. 26, 2006 http://jipam.vu.edu.au therefore it holds |b2 | > |bi |, 0 ≤ i ≤ 1, |c2 | > |ci |, 0 ≤ i ≤ 1. Zeros of f4 (z): z1 z2 z3 z4 = −0, 25 − 0, 6614i , = −0, 25 + 0, 6614i , = −0, 1492 + 0, 2863i , = −0, 5492 + 0, 2863i . On the Location of Zeros of Complex Polynomials Matthias Dehmer 7 5. f5 (z) := z − z + 1. Zeros of f5 (z): Title Page z1 z2 z3 z4 z5 z6 z7 . = −1, 1127 , . = −0, 6170 − 0, 9008i , . = −0, 6170 + 0, 9008i , . = 0, 3636 − 0, 9525i , . = 0, 3636 + 0, 9525i , . = 0, 8098 − 0, 2628i , . = 0, 8098 + 0, 2628i . Contents JJ J II I Go Back Close Quit Page 23 of 27 4 3 2 2 6. f6 (z) := (2z − z + z + 2z − 1) , σ = 2. J. Ineq. Pure and Appl. Math. 7(1) Art. 26, 2006 http://jipam.vu.edu.au fi f1 f2 f3 f4 f5 f6 S1 3,2918 3,1746 - S2 1,4895 1,9659 1501,0 1,7897 1,9919 2,7494 S3 2,5366 2,4069 3001,0 1,8595 1,2301 4,2499 S4 2,5388 2,4142 3001,0 1,9 3,0 4,25 S5 ξ 2,1757 (σ = 1) 0,756 1,5262 997,9914 1.6683 (σ = 1) 1,25 1,1127 3,850 (σ = 2) 0,4184 Figure 1: Comparison of zero bounds On the Location of Zeros of Complex Polynomials Matthias Dehmer Zeros of f6 (z): z1 z2 z3 z4 z5 z6 z7 z8 . = −0, 8935 , . = 0, 4184 , . = 0, 4875 − 1, 0485i , . = 0, 4875 + 1, 04857i , . = −0, 8935 , . = 0, 4184 , . = 0, 4875 − 1, 04857i , . = 0, 4875 + 1, 04857i . Title Page Contents JJ J II I Go Back Close Quit Page 24 of 27 J. Ineq. Pure and Appl. Math. 7(1) Art. 26, 2006 http://jipam.vu.edu.au 5. Conclusions Table 1 shows the overall results of the comparison of the new zero bounds. In general, the comparison between zero bounds is very difficult. Hence, it is not possible to obtain general assertions for describing the quality of zero bounds. Table 1 shows that the quality of the proven bounds depends on the polynomial under consideration. We observe that the bounds S3 , S4 are very large for f3 (z). a This is due to the fact that the number M := max anj is very large. In the 0≤j≤n−1 case of a polynomial H(z) := (f (z))σ , the bound of Theorem 3.5 is directly applicable (without expanding H(z)) in order to determine the value of the bound. The new bounds of the present paper can be used in many applications. The characteristic property of our new bounds is that we can compute these zero bounds more effectively than the classic bound of Theorem 3.1. On the Location of Zeros of Complex Polynomials Matthias Dehmer Title Page Contents JJ J II I Go Back Close Quit Page 25 of 27 J. Ineq. Pure and Appl. Math. 7(1) Art. 26, 2006 http://jipam.vu.edu.au References [1] H. ALZER, Bounds for the zeros of polynomials, Complex Variables, Theory Appl., 8(2) (2001), 143–150. [2] M. DEHMER, Schranken für die Nullstellen komplexwertiger Polynome, Die Wurzel, 8 (2000), 182–185. [3] F. HEIGL, Neuere Entwicklungen in der Geometrie der Polynome, Jber. Deutsch. Math.-Verein., 65 (1962/63), 97–142. [4] P. HENRICI, Applied and computational complex analysis. Volume I, Wiley Classics Library Edition, (1988). [5] F. KITTANEH, Bounds for the zeros of polynomials from matrix inequalities, Arch. Math., 81(5) (2003), 601–608. [6] S. LIPKA, Über die Abgrenzung der Wurzeln von algebraischen Gleichungen, Acta. Litt. Sci. 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SPECHT, Die Lage der Nullstellen eines Polynoms, Mathematische Nachrichten, 15 (1956), 353–374. [14] E.C. WESTERFIELD, A new bound for the zeros of polynomials, Amer. Math. Monthly, 40 (1933), 18–23. On the Location of Zeros of Complex Polynomials Matthias Dehmer Title Page Contents JJ J II I Go Back Close Quit Page 27 of 27 J. Ineq. Pure and Appl. Math. 7(1) Art. 26, 2006 http://jipam.vu.edu.au