Journal of Inequalities in Pure and Applied Mathematics ZERO AND COEFFICIENT INEQUALITIES FOR HYPERBOLIC POLYNOMIALS volume 7, issue 1, article 25, 2006. J. RUBIÓ-MASSEGÚ, J.L. DÍ AZ-BARRERO AND P. RUBIÓ-DÍ AZ Applied Mathematics III Universitat Politècnica de Catalunya Jordi Girona 1-3, C2, 08034 Barcelona, Spain. Received 26 May, 2005; accepted 09 December, 2005. Communicated by: S.S. Dragomir EMail: josep.rubio@upc.edu EMail: jose.luis.diaz@upc.edu EMail: pere.rubio@upc.edu Abstract Contents JJ J II I Home Page Go Back Close c 2000 Victoria University ISSN (electronic): 1443-5756 166-05 Quit Abstract In this paper using classical inequalities and Cardan-Viète formulae some inequalities involving zeroes and coefficients of hyperbolic polynomials are given. Furthermore, considering real polynomials whose zeros lie in Re(z) > 0, the previous results have been extended and new inequalities are obtained. Zero and Coefficient Inequalities for Hyperbolic Polynomials 2000 Mathematics Subject Classification: 12D10, 26C10, 26D15. Key words: Zeroes and coefficients, Inequalities in the complex plane, Inequalities for polynomials with real zeros, Hyperbolic polynomials. J. Rubió-Massegú, J.L. Díaz-Barrero and P. Rubió-Díaz Contents 1 Introduction . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 2 The Inequalities . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . References 3 4 Title Page Contents JJ J II I Go Back Close Quit Page 2 of 14 J. Ineq. Pure and Appl. Math. 7(1) Art. 25, 2006 1. Introduction The problem of finding relations between the zeroes and coefficients of a polynomial occupies a central role in the theory of equations. The most well known of such relations are Cardan-Viète’s formulae [1]. Many papers devoted to obtaining inequalities between the zeros and coefficient have been written giving new bounds or improving the classical known ones ([2], [3], [4]). Furthermore, inequalities for polynomials with all zeros real also called hyperbolic polynomials, have been fully documented in [5]. In this paper, using some classical inequalities, several inequalities involving zeros and coefficients of polynomials with real zeros have been obtained and the main result has been extended to polynomials whose zeros lie in the right half plane. Zero and Coefficient Inequalities for Hyperbolic Polynomials J. Rubió-Massegú, J.L. Díaz-Barrero and P. Rubió-Díaz Title Page Contents JJ J II I Go Back Close Quit Page 3 of 14 J. Ineq. Pure and Appl. Math. 7(1) Art. 25, 2006 2. The Inequalities In what follows some zero and coefficient inequalities involving polynomials whose zeros are strictly positive real numbers are obtained. We begin with Pn k Theorem 2.1. Let A(x) = k=0 ak x , an 6= 0, be a hyperbolic polynomial with all its zeroes x1 , x2 , . . . , xn strictly positive. If α, p and b are strictly positive real numbers such that α < p, then 1 1 −1 n X 1 α p p − α α p a1 (2.1) . 1 ≤ 1 p b a α α 0 [x + b] p k k=1 p1 n bα . Equality holds when A(x) = an x − p−α Proof. Let β and a be strictly positive real numbers defined by β = 1 − αp > 0 bα and a = pβ > 0. Taking into account that αp + β = 1 and applying the powered AM-GM inequality, we have for all k, 1 ≤ k ≤ n, α α (2.2) (xpk ) p aβ ≤ xpk + βa. p Inverting the terms in (2.2) yields 1 1 ≤ α β, α p x + βa xk a p k Zero and Coefficient Inequalities for Hyperbolic Polynomials J. Rubió-Massegú, J.L. Díaz-Barrero and P. Rubió-Díaz Title Page Contents JJ J II I Go Back 1 ≤ k ≤ n, Close Quit or equivalently xpk α 1 1 ≤ · α β. p + α βa p xk a Page 4 of 14 J. Ineq. Pure and Appl. Math. 7(1) Art. 25, 2006 Taking into account that αp βa = b and β = xpk p−α , p we have α 1 1 1 ≤ · β α +b p xk bα pβ = α pβ β β 1 · p bβ αβ xαk α α 1− p−α 1− α p p( p ) p 1 · α = · α α xk p b1− p α1− p α 1− αp αp p − α 1 = . p b xαk Raising to 1 α both sides of the preceding inequality, yields 1 1 −1 αp p − α α p 1 1 , 1 ≤ k ≤ n. 1 ≤ 1 xk b [xpk + b] α pα Finally, adding up the preceding inequalities, we obtain 1 1 1 −1 n 1 −1 n X 1 αp p − α α p X 1 α p p − α α p a1 = 1 1 ≤ 1 p b x b a0 α α k [x + b] p pα k k=1 k=1 and (2.1) is proved. Notice that equality holds in (2.1) if and only if equality holds in (2.2) for 1 1 ≤ k ≤ n. Namely, equality holds when xpk= a, 1 ≤ k ≤ n or xk = a p = p1 p1 p1 n bα bα bα = p−α . That is, when A(x) = an x − p−α , an 6= 0. pβ Zero and Coefficient Inequalities for Hyperbolic Polynomials J. Rubió-Massegú, J.L. Díaz-Barrero and P. Rubió-Díaz Title Page Contents JJ J II I Go Back Close Quit Page 5 of 14 J. Ineq. Pure and Appl. Math. 7(1) Art. 25, 2006 When α > p changing α by 1 α and p by 1 p into (2.1), we have the following: Corollary 2.2. If α, p and b are strictly positive real numbers such that α > p, then α−p n X 1 pp α − p a1 . ≤ α 1 α b a0 p k=1 [xk + b]α Multiplying both sides of (2.2) by p α and raising to α1 , we obtain for 1 ≤ k ≤ n, p α1 β p α1 a α xk . ≥ βa α α bα Setting β = 1 − αp , a = pβ into the preceding expression and, after adding up the resulting inequalities, we get xpk + Corollary 2.3. If α, p and b are strictly positive real numbers such that α < p, then α1 − p1 1 n X 1 pα b an−1 p α (xk + b) ≥ 1 an αp p − α k=1 holds. Another, immediate consequence of (2.1) is the following. P Corollary 2.4. Let A(x) = nk=0 ak xk , an 6= 0, be a hyperbolic polynomial with all its zeroes x1 , x2 , . . . , xn strictly positive. Then, n X k=1 1 1 a1 ≤ 2 n 2 [xk + 2n − 1] 4n a0 Zero and Coefficient Inequalities for Hyperbolic Polynomials J. Rubió-Massegú, J.L. Díaz-Barrero and P. Rubió-Díaz Title Page Contents JJ J II I Go Back Close Quit Page 6 of 14 holds. J. Ineq. Pure and Appl. Math. 7(1) Art. 25, 2006 Proof. Setting α = 12 , p = n and b = 2n − 1 into (2.1), we have n X k=1 1 1 1 n 1 2− n n − 1 a1 2 ≤ 22 n 2 [xk + 2n − 1] n 2n − 1 a0 1 1 1 n 2− n 1 a1 2 = 2 n 2 a0 1 a1 = 2 . 4n a0 Note that equality holds when xk = 1, 1 ≤ k ≤ n. That is, when A(x) = an (x − 1)n . This completes the proof. P Considering the reverse polynomial A∗ (x) = xn A(1/x) = nk=0 an−k xk , we have the following Theorem 2.5. If α, p and b are strictly positive real numbers such that α < p, then 1 α1 n X 1 1 an−1 xpk αp (2.3) ≤ 1 1 · (p − α) α − p . p x + b a n α bp p k k=1 Equality holds when A(x) = an x − b(p−α) α p1 n , an 6= 0. Zero and Coefficient Inequalities for Hyperbolic Polynomials J. Rubió-Massegú, J.L. Díaz-Barrero and P. Rubió-Díaz Title Page Contents JJ J II I Go Back Close Quit Page 7 of 14 J. Ineq. Pure and Appl. Math. 7(1) Art. 25, 2006 Proof. Since A∗ (x) has zeros n X k=1 1 h p 1 xk 1 , . . . , x1n , x1 +b i α1 then applying (2.1) to it, we get 1 1 −1 αp p − α α p an−1 . ≤ 1 · b an pα Developing the LHS of the preceding inequality, we have 1 1 −1 α1 n p − α α p an−1 αp 1 X xpk ≤ 1 · , 1 p 1 b an pα b α k=1 b + xk and rearranging terms, yields 1 α1 1 −1 n X 1 p − α α p an−1 xpk αp ≤ bα · 1 · p 1 an b + x pα k b k=1 1 = αp p 1 α 1 1 1 · b p · (p − α) α − p an−1 . an Finally, replacing b by 1/b in the preceding inequality we get (2.3) as claimed. Applying Theorem 2.1, equality in (2.3) holds when p1 !n α A∗ (x) = an x − . b(p − α) Taking into account that we have changed b by 1/b, equality will hold if and only if 1 !n b(p − α) p , an 6= 0 A(x) = an x − α Zero and Coefficient Inequalities for Hyperbolic Polynomials J. Rubió-Massegú, J.L. Díaz-Barrero and P. Rubió-Díaz Title Page Contents JJ J II I Go Back Close Quit Page 8 of 14 J. Ineq. Pure and Appl. Math. 7(1) Art. 25, 2006 and the proof is completed. Next, we state and prove the following: Theorem 2.6. Let A(x) be a hyperbolic polynomial with zeros x1 , x2 , . . . , xn such that x1 ≤ x2 ≤ · · · ≤ xn . Let α, p and b be strictly positive real numbers such that α < p. If a < x1 or a > xn , then 1 1 −1 n X α p p − α α p P 0 (a) 1 (2.4) . 1 ≤ 1 p b P (a) α α [|x − a| + b] p k k=1 Equality holds when " A(x) = an x − a + " A(x) = an x − a − bα p−α bα p−α p1 #!n or Zero and Coefficient Inequalities for Hyperbolic Polynomials J. Rubió-Massegú, J.L. Díaz-Barrero and P. Rubió-Díaz p1 #!n . Title Page Contents Proof. First, we observe that (2.1) applied to polynomial P (−t) where P (t) has all its zeros t1 , t2 , . . . , tn negative, yields 1 1 −1 n X αp p − α α p a1 1 , (2.5) 1 ≤ 1 · p b a α α 0 [|t | + b] p k k=1 where equality holds when P (t) = an t + bα p−α JJ J II I Go Back Close Quit p1 !n , an 6= 0. Page 9 of 14 J. Ineq. Pure and Appl. Math. 7(1) Art. 25, 2006 Now, we consider the hyperbolic polynomial of the statement and assume that (i) a < x1 or (ii) a > xn . Let B(x) = A(x + a), the zeros of which are x1 − a, x2 − a, . . . , xn − a. Observe that, they are positive for case (i), and negative for case (ii). On the other hand, coefficients a0 and a1 of B(x) are B(0) = A(a) and B 0 (0) = A0 (a) respectively. Applying (2.1) to B(x) in case (i) or (2.5) in case (ii) we get (2.4). Finally, we see that equality in (2.4) holds in the case (i) when p1 !n bα B(x) = an x − , p−α J. Rubió-Massegú, J.L. Díaz-Barrero and P. Rubió-Díaz or equivalently when " A(x) = an x − a + bα p−α p1 #!n . Title Page Contents In case (ii) we will get equality when B(x) = an x + Zero and Coefficient Inequalities for Hyperbolic Polynomials bα p−α p1 !n , an 6= 0. JJ J II I Go Back That is, when " A(x) = an x − a − bα p−α p1 #!n Close Quit Page 10 of 14 and the proof is completed. J. Ineq. Pure and Appl. Math. 7(1) Art. 25, 2006 Finally, in the sequel we will extend the result obtained in Theorem 2.1 to real polynomials whose zeros lie in the half plane Re(z) > 0 and they have an imaginary part “sufficiently small”. This is stated and proved in the following. P Theorem 2.7. Let A(z) = nk=0 ak z k be a polynomial with real coefficients whose zeros z1 , z2 , . . . , zn lie in Re(z) > 0 and suppose that | Im(z)| ≤ r Re(zk ), 1 ≤ k ≤ n for some real r ≥ 0. Let α, p and b be strictly positive real numbers such that α < p, then (2.6) 1 n X 1 k=1 [|zk |p + b] α 1 ≤ αp 1 pα · p−α b α1 − p1 · √ 1+ r2 Zero and Coefficient Inequalities for Hyperbolic Polynomials a1 . a0 J. Rubió-Massegú, J.L. Díaz-Barrero and P. Rubió-Díaz For r > 0, equality holds when n is even and A(z) = z2 − √ 2 · 1 + r2 bα p−α p1 z+ bα p−α p2 ! n2 . Title Page Contents Note that when r = 0 the preceding result reduces to (2.1). Proof. Setting xk = |zk | and repeating the procedure followed in proving (2.1), we get 1 1 −1 n n X 1 αp p−α α p X 1 . 1 ≤ 1 · p b |zk | α pα k=1 [|zk | + b] k=1 P Next, we will find an upper bound for the sum S = nk=1 |z1k | . Reordering the zeros of A(z) in the way z1 , z1 , z2 , z2 , . . . , zs , zs , x1 , . . . , xt ,where x1 , . . . , xt are JJ J II I Go Back Close Quit Page 11 of 14 J. Ineq. Pure and Appl. Math. 7(1) Art. 25, 2006 the real zeros (if any), then the preceding sum becomes s t s t X X X X 1 1 |zk | 1 S=2 + =2 . 2 + |z |x |x |z | k| k| k| k k=1 k=1 k=1 k=1 On the other hand, by Cardan-Viète formulae, we have X s t s t X 1 Re zk X 1 a1 X 1 1 − = + + =2 + . 2 a0 z z x x |z | k k k k k k=1 k=1 k=1 k=1 p √ Taking into account that |zk | = (Re zk )2 + (Im zk )2 ≤ 1 + r2 |Re zk | and the fact that the zeros of A(z) lie in Re(z) > 0, yields (2.7) s t X X |zk | 1 S=2 2 + |xk | |zk | k=1 k=1 t s X √ |Re zk | X 1 2 ≤2 1+r 2 + |xk | |z | k k=1 k=1 ≤ √ 1+ r2 2 s X |Re zk | k=1 = √ 1 + r2 |zk |2 t X 1 + |xk | k=1 Zero and Coefficient Inequalities for Hyperbolic Polynomials J. Rubió-Massegú, J.L. Díaz-Barrero and P. Rubió-Díaz Title Page Contents ! a1 , a0 from which (2.6) immediately follows. Next, we will see when equality holds in (2.6). If r > 0, to get equality in p1 bα (2.6) we require that (i) all the zeros of A(z) have modulus |zk | = p−α , JJ J II I Go Back Close Quit Page 12 of 14 J. Ineq. Pure and Appl. Math. 7(1) Art. 25, 2006 because when xk = |zk | the powered GM-AM inequality (2.2) must become equality, (ii) |Im zk | = r Re zk , 1 ≤ k ≤ s, due to the fact that the inequality in (2.7) must become equality, and (iii) all the zeros of A(z) must be complex because the second inequality in (2.7) also must be an equality. Now it is easy to see that the previous conditions are equivalent to say that n is even and 1 zk = √ 1 + r2 bα p−α p1 [1 + ri], 1≤k≤ n . 2 Multiplying the preceding zeros we get that inequality in (2.6) holds when n is even and p1 p2 ! n2 2 bα bα . A(z) = z 2 − √ z+ 2 p−α p−α 1+r This completes the proof. Zero and Coefficient Inequalities for Hyperbolic Polynomials J. Rubió-Massegú, J.L. Díaz-Barrero and P. Rubió-Díaz Title Page Contents JJ J II I Go Back Close Quit Page 13 of 14 J. Ineq. Pure and Appl. Math. 7(1) Art. 25, 2006 References [1] F. VIÈTE, Opera Mathematica, Leiden, Germany, 1646. [2] M. MARDEN, Geometry of Polynomials, American Mathematical Society, Providence, Rhode Island, 1989. [3] Th.M. RASSIAS, Inequalities for polynomial zeros, 165–202, in Th.M. Rassias, (ed.), Topics in Polynomials, Kluwer Academic Publisher, Dordrecht, 2000. [4] Q.I. RAHMAN AND G. SCHMEISSER, Analytic Theory of Polynomials, Clarendon Press, Oxford 2002. [5] D. MITRINOVIĆ, G. MILOVANOVIĆ AND Th.M. RASSIAS, Topics in Polynomials: Extremal Problems, Inequalities and Zeros, World Scientific, Singapore, 1994. Zero and Coefficient Inequalities for Hyperbolic Polynomials J. Rubió-Massegú, J.L. Díaz-Barrero and P. Rubió-Díaz Title Page Contents JJ J II I Go Back Close Quit Page 14 of 14 J. Ineq. Pure and Appl. Math. 7(1) Art. 25, 2006