Journal of Inequalities in Pure and Applied Mathematics ON WEIGHTED INEQUALITIES WITH GEOMETRIC MEAN OPERATOR GENERATED BY THE HARDY-TYPE INTEGRAL TRANSFORM volume 3, issue 4, article 48, 2002. MARIA NASSYROVA, LARS-ERIK PERSSON AND VLADIMIR STEPANOV Received 27 November, 2001; accepted 29 April, 2002. Communicated by: B. Opić Department of Mathematics Luleå University of Technology S-971 87 Luleå, SWEDEN EMail: nassm@sm.luth.se Abstract EMail: larserik@sm.luth.se URL: http://www.sm.luth.se/∼ larserik/ Contents Computing Centre Russian Academy of Sciences Far-Eastern Branch Khabarovsk 680042, RUSSIA. EMail: stepanov@as.khb.ru JJ J II I Home Page Go Back Close c 2000 School of Communications and Informatics,Victoria University of Technology ISSN (electronic): 1443-5756 084-01 Quit Abstract The generalized geometric mean operator Zx 1 GK f(x) = exp k(x, y) log f(y)dy, K(x) 0 Rx with K(x) := 0 k(x, y)dy is considered. A characterization of the weights u(x) and v(x) so that the inequality Z 0 ∞ 1/q Z (GK f(x))q u (x) dx ≤C ∞ 1/p f(x)p v(x)dx , f ≥ 0, 0 holds is given for all 0 < p, q < ∞ both for all GK where k(x, y) satisfies the Oinarov condition and for Riemann-Liouville operators. The corresponding stable bounds of C = kGK kLpv →Lqu are pointed out. 2000 Mathematics Subject Classification: 26D15, 26D10 Key words: Integral inequalities, Weights, Geometric mean operator, Kernels, Riemann-Liouville operators. This research was supported by a grant from the Royal Swedish Academy of Sciences. The research by the first named author was also partially supported by the RFBR grants 00-01-00239 and 01-01-06038. The research by the third named author was partially supported also by the RFBR grant 00-01-00239 and the grant E00-1.0-215 of the Ministry of Education of Russia. On Weighted Inequalities with Geometric Mean Operator Generated by the Hardy-type Integral Transform Maria Nassyrova, Lars-Erik Persson Vladimir Stepanov Title Page Contents JJ J II I Go Back Close Quit Page 2 of 37 J. Ineq. Pure and Appl. Math. 3(4) Art. 48, 2002 http://jipam.vu.edu.au Contents 1 Introduction . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 4 2 General Schemes . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 7 3 Hardy-type Operators. Case 0 < p ≤ q < ∞ . . . . . . . . . . . . . 10 4 Hardy-type Operators. Case 0 < q < p < ∞ . . . . . . . . . . . . . 17 5 Riemann-Liouville Operators . . . . . . . . . . . . . . . . . . . . . . . . . . 26 References On Weighted Inequalities with Geometric Mean Operator Generated by the Hardy-type Integral Transform Maria Nassyrova, Lars-Erik Persson Vladimir Stepanov Title Page Contents JJ J II I Go Back Close Quit Page 3 of 37 J. Ineq. Pure and Appl. Math. 3(4) Art. 48, 2002 http://jipam.vu.edu.au 1. Introduction Let R+ := [0, ∞) and let k(x, y) ≥ 0 be a locally integrable kernel defined on R+ × R+ and such that Z k(x, y)dy = 1 R+ for almost all x ∈ R+ . Denote Z Kf (x) := ∞ k(x, y)f (y)dy, f (y) ≥ 0. 0 If Kf (x) < ∞, then there exists a limit (1.1) GK f (x) := lim [Kf α (x)]1/α Maria Nassyrova, Lars-Erik Persson Vladimir Stepanov α↓0 Title Page and Z (1.2) On Weighted Inequalities with Geometric Mean Operator Generated by the Hardy-type Integral Transform GK f (x) = exp Contents ∞ k(x, y) log f (y)dy. 0 For 0 < p < ∞ and a weight function v(x) ≥ 0 we put Z ∞ p 1/p |f (x)| v(x)dx kf kLpv := JJ J II I Go Back Close 0 Quit and make use of the abbreviation kf kLp when v(x) ≡ 1. Page 4 of 37 J. Ineq. Pure and Appl. Math. 3(4) Art. 48, 2002 http://jipam.vu.edu.au Suppose u(x) ≥ 0 and v(x) ≥ 0 are weight functions and 0 < p, q < ∞. This paper deals with Lpv − Lqu inequalities of the form Z ∞ q (GK f ) u (1.3) 1/q Z ≤C ∞ p 1/p f v 0 , f ≥ 0, 0 where a constant C is independent on f and we always assume that C is the least possible, that is C = kGK kLpv →Lqu , where (1.4) kGK kLpv →Lqu := sup f ≥0 kGK f kLqu . kf kLpv For the classical case k(x, y) = x1 χ[0,x] (y) with the Hardy averaging operator (1.5) 1 Hf (x) := x Z x f (y)dy 0 the inequality (1.3) was characterized in [6] (see also [7]). In Section 2 of this paper we present a general scheme on how inequalities of the type (1.3) can be characterized via the limiting procedure in similar characterization (in suitable forms) of some corresponding Hardy-type inequalities. In Section 3 we characterize the weights u(x) and v(x) so that (1.3) with 0 < p ≤ q < ∞ holds when Z x 1 (1.6) GK f (x) = exp k(x, y) log f (y)dy K(x) 0 On Weighted Inequalities with Geometric Mean Operator Generated by the Hardy-type Integral Transform Maria Nassyrova, Lars-Erik Persson Vladimir Stepanov Title Page Contents JJ J II I Go Back Close Quit Page 5 of 37 J. Ineq. Pure and Appl. Math. 3(4) Art. 48, 2002 http://jipam.vu.edu.au with Z x k(x, y)dy < ∞, K(x) := x > 0, 0 and K(0) = 0, K(∞) = ∞, and when k (x, y) satisfies the Oinarov condition (see Theorem 3.1). The corresponding characterization for the case 0 < q < p < ∞ can be found in Section 4 (see Theorem 4.1). A fairly precise result in the case k (x, y) = (x − y)γ , γ > 0, i.e. when GK is generated by the RiemannLiouville convolutional operator, can be found in Section 5 (see Theorem 5.1). In particular, this investigation shows that inequalities of the type (1.3) can be proved also when the Oinarov condition is violated (because for 0 < γ < 1 this kernel does not satisfy this condition). In order to prove these results we need new characterizations of weighted inequalities with the Riemann-Liouville operator which are of independent interest (see Theorem 5.2 and 5.3). Finally note that the operator (1.6) was studied in a similar connection, by E.R. Love [3], where a sufficient condition was proved for the inequality (1.3) to be valid in the case p = q = 1 and special weights. On Weighted Inequalities with Geometric Mean Operator Generated by the Hardy-type Integral Transform Maria Nassyrova, Lars-Erik Persson Vladimir Stepanov Title Page Contents JJ J II I Go Back Close Quit Page 6 of 37 J. Ineq. Pure and Appl. Math. 3(4) Art. 48, 2002 http://jipam.vu.edu.au 2. General Schemes We begin with some general remarks. By using the elementary property (2.1) GK (f s ) = (GK f )s , −∞ < s < ∞, we see that (2.2) kGK kLpv →Lqu = kGK kLp →Lqw = kGK k s/p sq/p Ls →Lw , where (2.3) q/p 1 w := GK u. v On Weighted Inequalities with Geometric Mean Operator Generated by the Hardy-type Integral Transform Maria Nassyrova, Lars-Erik Persson Vladimir Stepanov Moreover, from (1.1) and (2.2) Title Page (2.4) kGK kLpv →Lqu = lim kKk α↓0 1/α q/α Lp/α →Lw . Contents The last formula generates the “precise” scheme for characterization of (1.3) provided the norm of the associated integral operator K has very accurate twosided estimates of the norm (2.5) c1 (p, q)F (w, p, q) ≤ kKkLp →Lqw ≤ c2 (p, q)F (w, p, q) in the sense that there exist the limits h p q p q i1/α (2.6) ci (p, q, F ) = lim ci , F w, , , α↓0 α α α α JJ J II I Go Back Close Quit Page 7 of 37 i = 1, 2, J. Ineq. Pure and Appl. Math. 3(4) Art. 48, 2002 http://jipam.vu.edu.au and ci (p, q, F ) ∈ (0, ∞) , i = 1, 2. A natural consequence of (2.2) and (2.4) is then the two-sided estimate (2.7) c1 (p, q, F ) ≤ kGK kLp →Lqw ≤ c2 (p, q, F ), which characterizes (1.3) with the least possible constants provided the estimates in (2.5) are also the best. This scheme was realized in [6] where K is the Hardy averaging operator (1.5) and 0 < p ≤ q < ∞. For this purpose a new non-Muckenhoupt form of (2.5) was used. We generalize this result here for the Riemann-Liouville kernel in Section 4. Unfortunately, the above scheme does not work for a more general operator or even for the Hardy operator, if q < p, because the estimate (2.5) happens to be vulnerable, when the parameters p and q tend to ∞, so that the limits ci (p, q, F ) become either 0 or ∞. However, if the functional F is homogeneous in the sense that h p q i1/α = F (w, p, q), α > 0, (2.8) F w, , α α then an alternative “stable” scheme for (2.7) works, provided the lower bound (2.9) c3 (p, q)F (w, p, q) ≤ kGK kLp →Lqw can be established. The right hand side of (2.7) follows from the upper bound from (2.5), (2.2) and Jensen’s inequality (2.10) On Weighted Inequalities with Geometric Mean Operator Generated by the Hardy-type Integral Transform Maria Nassyrova, Lars-Erik Persson Vladimir Stepanov Title Page Contents JJ J II I Go Back Close Quit Page 8 of 37 GK f (x) ≤ Kf (x), J. Ineq. Pure and Appl. Math. 3(4) Art. 48, 2002 http://jipam.vu.edu.au because (2.8) implies (2.11) s/p sq F w, s, = F (w, p, q), p s > 1. To realize the “stable” scheme for the Hardy averaging operator, when 0 < q < p < ∞ and p > 1 an alternative (non-Mazya-Rozin) functional F was found in [6] in the form Z (2.12) F (w, p, q) = 0 ∞ !1/q−1/p Z x q/(p−q) 1 w w(x)dx x 0 which obviously satisfies (2.11). The idea to use (2.2) and (2.10) for the upper bound estimate of the norm kGK kLpv →Lqu originated from the paper by Pick and Opic [8], where the authors obtained two-sided estimates of kGH kLpv →Lqu , 0 < q < p < ∞. However, they realized (2.5) in Muckenhoupt or Mazya-Rozin form with unstable factors and, therefore, the estimate (2.7) was rather uncertain. Throughout the paper, expressions of the form 0 · ∞, ∞/∞, 0/0 are taken to be equal to zero; and the inequality A . B means A ≤ cB with a constant c > 0 independent of weight functions. Moreover, the relationship A ≈ B is interpreted as A . B . A or A = cB. Everywhere the constant C in explored inequalities are considered to be the least possible one. In the case q < p the auxiliary parameter r is defined by 1/r = 1/q − 1/p. On Weighted Inequalities with Geometric Mean Operator Generated by the Hardy-type Integral Transform Maria Nassyrova, Lars-Erik Persson Vladimir Stepanov Title Page Contents JJ J II I Go Back Close Quit Page 9 of 37 J. Ineq. Pure and Appl. Math. 3(4) Art. 48, 2002 http://jipam.vu.edu.au 3. Hardy-type Operators. Case 0 < p ≤ q < ∞ In the sequel we let k(x, y) ≥ 0 be locally integrable in R+ × R+ and satisfies the following (Oinarov) condition: there exists a constant d ≥ 1 independent on x, y, z such that 1 (k(x, z)+k(z, y)) ≤ k(x, y) ≤ d(k(x, z)+k(z, y)), d We assume that Z x (3.2) K(x) := k(x, y)dy < ∞, x > 0, (3.1) x ≥ z ≥ y ≥ 0. On Weighted Inequalities with Geometric Mean Operator Generated by the Hardy-type Integral Transform 0 and K(0) = 0, K(∞) = ∞. Without loss of generality we may and shall also assume that k(x, y) is nondecreasing in x and nonincreasing in y. We consider the following Hardy-type operator Z x 1 (3.3) Kf (x) := k(x, y)f (y)dy, f (y) ≥ 0, x ≥ 0, K(x) 0 and the corresponding geometric mean operator GK : Z x 1 GK f (x) = exp k(x, y) log f (y)dy. K(x) 0 Our main goal in this section is to find necessary and sufficient conditions on the weights u(x) and v(x) so that the inequality Z ∞ 1/q Z ∞ 1/p q p (3.4) (GK f (x)) u (x) dx ≤C f (x) v(x)dx , f ≥ 0, 0 Maria Nassyrova, Lars-Erik Persson Vladimir Stepanov Title Page Contents JJ J II I Go Back Close Quit Page 10 of 37 0 J. Ineq. Pure and Appl. Math. 3(4) Art. 48, 2002 http://jipam.vu.edu.au holds for 0 < p ≤ q < ∞, and to point out the corresponding stable estimates of C = kGK kLpv →Lqu . In view of our discussion in the previous section we first need to have the two-sided estimates of kKkLp →Lqw in suitable form. First we observe that it follows from ([1, Theorem 2.1]) by changing variables x → x1 , y → y1 and by using the duality principle (see [11, Section 2.3]) that for 1 < p ≤ q < ∞ we have c4 (d)A ≤ kKkLp →Lqw ≤ c5 (p, q, d)A, (3.5) On Weighted Inequalities with Geometric Mean Operator Generated by the Hardy-type Integral Transform where d is defined by (3.1), Maria Nassyrova, Lars-Erik Persson Vladimir Stepanov A = max (A0, A1 ) (3.6) with −1/p Z A0 := sup t (3.7) 1/q t Title Page w t>0 Contents 0 JJ J and Z p0 −1/p k(t, y) dy (3.8) A1 := sup t>0 t II I Go Back 0 Z t Z × 0 0 x 0 k(x, y)p dy q w(x) dx K(x)q 1/q . It is easy to see that A0 satisfies (2.8) or (2.11), but not A1 . It is also known, that neither A0 < ∞ nor A1 < ∞ alone is sufficient for kKkLp →Lqw < ∞ in general Close Quit Page 11 of 37 J. Ineq. Pure and Appl. Math. 3(4) Art. 48, 2002 http://jipam.vu.edu.au (see counterexamples in [4], [10] and [5]). For this reason we need to require some additional conditions of a kernel k(x, y) for the property A0 ≈ kKkLp →Lqw , (3.9) and we will soon discuss this question in detail (see Proposition 3.2). Now we are ready to state our main theorem of this section: Theorem 3.1. Let 0 < p ≤ q < ∞ and the kernel k(x, y) ≥ 0 be such that (3.9) holds. Then (3.4) holds if and only if A0 < ∞. Moreover, A0 ≤ kGK kLpv →Lqu . A0 . (3.10) Proof. The sufficiency including the upper estimate in (3.10) follows from (2.2), (2.10) and (3.9). Moreover, we note that, by (2.2), Z 1/q ∞ q ≤ kGK kLpv →Lqu (GK f ) w (3.11) Z 0 ∞ f p . t−1/p w 0 Contents 0 JJ J II I Go Back 1/q t Maria Nassyrova, Lars-Erik Persson Vladimir Stepanov Title Page 1/p By applying this estimate with ft (x) = t−1/p χ[0,t] (x) for fixed t > 0 (obviously, kft kp = 1) we see that Z On Weighted Inequalities with Geometric Mean Operator Generated by the Hardy-type Integral Transform ≤ kGK kLpv →Lqu . By taking the supremum over t we have also proved the necessity including the lower estimate in (3.10) and the proof is complete. Close Quit Page 12 of 37 J. Ineq. Pure and Appl. Math. 3(4) Art. 48, 2002 http://jipam.vu.edu.au Remark 3.1. For the case when k (x, y) ≡ 1 we have that GK coincide with the usual geometric mean operator Z 1 x Gf (x) = exp log f (y)dy x 0 and thus we see that Theorem 3.1 may be regarded as a genuine generalization of Theorem 2 in [6] (see also[7]). As mentioned before we shall now discuss the question of for which kernels k (x, y) does the condition (3.9) hold. We need the following notation: Z x 0 Kp (x) := k(x, y)p dy, 0 (3.12) 1/p0 α0 := sup Kp (t) sup x t>0 (3.13) 1/p0 1/q k(t, x) , α1 := sup t1/p 0 ∞ t>0 k(x, t)q K(x)−q d xq/p 1/q Contents , JJ J t and (3.14) 1/p0 Z α2 := sup t t>0 Maria Nassyrova, Lars-Erik Persson Vladimir Stepanov Title Page 0<x<t Z On Weighted Inequalities with Geometric Mean Operator Generated by the Hardy-type Integral Transform ∞ x q/p q −q k(x, t) d −K(x) 1/q . t Proposition 3.2. Let 1 < p ≤ q < ∞. If a kernel k(x, y) ≥ 0 is such that for all weights w (3.9) is true, then α0 + α1 < ∞. Conversely, if α0 + α2 < ∞, then (3.9) holds. In particular, if α2 . α1 , then (3.9) is equivalent with the conditions α0 < ∞ and α1 < ∞. II I Go Back Close Quit Page 13 of 37 J. Ineq. Pure and Appl. Math. 3(4) Art. 48, 2002 http://jipam.vu.edu.au Proof. It is known ([11], (see also [2, Theorem 2.13])) that kKkLp →Lqw = max (A0 , A1 ) , (3.15) where 1/q w(x) 0 t1/p , A0 := sup k(x, t) dx q K(x) t>0 t Z ∞ 1/q w(x) 0 Kp (t)1/p . A1 := sup dx q K(x) t>0 t Z ∞ q Maria Nassyrova, Lars-Erik Persson Vladimir Stepanov It follows from a more general result ([5, Theorem 4]) that A0 ≈ kKkLp →Lqw (3.16) for all weights w, if and only if α0 < ∞. Moreover, if (3.9) is true for all weights w, then (3.15) implies A0 . A 0 (3.17) and for w(x) = xq/p−1 it brings α1 < ∞. We observe that the inequality 1/q t w 0 Z t Z = q x k(x, y)dy 0 0 Contents JJ J II I Close is always true. Indeed, by applying Minkowski’s integral inequality we find that Z Title Page Go Back A0 . pA0 (3.18) On Weighted Inequalities with Geometric Mean Operator Generated by the Hardy-type Integral Transform w(x) dx K(x)q 1/q Quit Page 14 of 37 J. Ineq. Pure and Appl. Math. 3(4) Art. 48, 2002 http://jipam.vu.edu.au ∞ Z t Z ≤ 0 y Z ≤ A0 w(x) k(x, y) dx K(x)q q t 1/q dy 0 y −1/p dy 0 1/p = A0 pt and (3.18) follows. Thus, (3.9) implies (3.16). Consequently, α0 < ∞ and, thus, α0 + α1 < ∞. Now, suppose that α0 + α2 < ∞. Then (3.16) holds and it is sufficient to prove (3.17). To this end we note that Z ∞ w(x) k(x, t)q dx K(x)q t Z x Z ∞ Z ∞ w(x) w(x) q q ≈ k(t, t) dx + dk(s, t) dx K(x)q K(x)q t t t Z ∞ Z ∞ −1 q dx = k(t, t) w(x) d K(y)q t x Z ∞ Z ∞ w(x)dx q + dk(s, t) K(x)q t s Z y Z ∞ −1 q = k(t, t) d w(x)dx K(y)q t t Z ∞ Z ∞ Z ∞ −1 q + dk(s, t) w(x)dx d K(y)q t s x On Weighted Inequalities with Geometric Mean Operator Generated by the Hardy-type Integral Transform Maria Nassyrova, Lars-Erik Persson Vladimir Stepanov Title Page Contents JJ J II I Go Back Close Quit Page 15 of 37 J. Ineq. Pure and Appl. Math. 3(4) Art. 48, 2002 http://jipam.vu.edu.au ∞ −1 ≤ k(t, t)q y d q K(y) Z y Z t∞ Z ∞ −1 q + dk(s, t) d w(x)dx K(y)q t s s Z ∞ −1 q q/p q ≤ A0 y k(y, t) d K(y)q t Aq0 Z q/p 0 ≤ Aq0 α2q t−q/p . and (3.17) follows. Now (3.5), (3.6), (3.16) and (3.17) imply (3.9). The proof is complete. On Weighted Inequalities with Geometric Mean Operator Generated by the Hardy-type Integral Transform Maria Nassyrova, Lars-Erik Persson Vladimir Stepanov Title Page Contents JJ J II I Go Back Close Quit Page 16 of 37 J. Ineq. Pure and Appl. Math. 3(4) Art. 48, 2002 http://jipam.vu.edu.au 4. Hardy-type Operators. Case 0 < q < p < ∞ Put Z (4.1) B0 := 0 ∞ Z t r/q !1/r 1 w dt . t 0 A crucial condition for this case corresponding to the condition (3.9) for the case 0 < p ≤ q < ∞ is the following: (4.2) B0 ≈ kKkLp →Lqw . We now state our main result in this Section. Theorem 4.1. Let 0 < q < p < ∞ and the kernel k(x, y) ≥ 0 be such that (4.2) holds. Also we assume that Z 1 x 1 (4.3) k(x, xt) log dt ≤ α3 < ∞, x > 0. K(x) 0 t Then (3.4) holds if and only if B0 < ∞. Moreover, (4.4) kGK kLpv →Lqu ≈ B0 . On Weighted Inequalities with Geometric Mean Operator Generated by the Hardy-type Integral Transform Maria Nassyrova, Lars-Erik Persson Vladimir Stepanov Title Page Contents JJ J II I Go Back Close Proof. The sufficiency including the upper estimate in (4.4) follows by using (2.2), (2.10) and (4.2). Next we show that Quit Page 17 of 37 (4.5) D . kGK kLp →Lqw , J. Ineq. Pure and Appl. Math. 3(4) Art. 48, 2002 http://jipam.vu.edu.au where Z ∞ Z ∞ D := 0 x w(y) dy yq !1/r r/q x r/q 0 dx . For this purpose we consider f0 (x) = x r/(pq 0 ) Z x ∞ w(y) dy yq r/(pq) . Then Dr/p = kf0 kp . On Weighted Inequalities with Geometric Mean Operator Generated by the Hardy-type Integral Transform Maria Nassyrova, Lars-Erik Persson Vladimir Stepanov We have kGK kLp →Lqw kf0 kp = kGK kLp →Lqw Dr/p Z ∞ 1/q q ≥ (GK f0 ) w 0 Z ∞ Z x 1 = exp k(x, y) K(x) 0 0 #1/q ( r/(pq) ) !q Z ∞ w(z) 0 × log y r/(pq ) dz dy w(x)dx zq y "Z rq/(pq0 ) Z x ∞ 1 ≥ exp k(x, y) log ydy K(x) 0 0 Title Page Contents JJ J II I Go Back Close Quit Page 18 of 37 J. Ineq. Pure and Appl. Math. 3(4) Art. 48, 2002 http://jipam.vu.edu.au Z × x ∞ w(z) dz zq #1/q r/p w(x)dx =: J. (4.6) Moreover, 1 K(x) Z 0 x Z x 1 y k(x, y) log ydy = log x + k(x, y) log dy K(x) 0 x Z 1 x 1 = log x − k(x, xt) log dt K(x) 0 t ≥ log x − α3 , where α3 is a constant from (4.3). Then Z ∞ Z ∞ r/p −α3 rq w(z) 0 q w(x)xr/(pq ) dx ≈ Dr , (4.7) J ≥ exp dz 0 q (pq ) z 0 x the last estimate is obtained by partial integration. Now (4.5) follows by just combining (4.6) and (4.7). It remains to show that D ≥ B0 . We have Z t Z t Z s w(s) q−1 w(x)dx = q z dz ds sq 0 0 0 Z t Z t w(s) =q ds z q−1 dz q s 0 z Z t Z t w(s) q−1+q/(2p) =q ds z z −q/(2p) dz q s 0 z On Weighted Inequalities with Geometric Mean Operator Generated by the Hardy-type Integral Transform Maria Nassyrova, Lars-Erik Persson Vladimir Stepanov Title Page Contents JJ J II I Go Back Close Quit Page 19 of 37 J. Ineq. Pure and Appl. Math. 3(4) Art. 48, 2002 http://jipam.vu.edu.au (by Hölder’s inequality with conjugate exponents Z t Z t ≤q 0 z r/q w(s) 0 ds z r/q +r/(2p) dz q s r p and ) q q !q/r Z 0 t dz √ z q/p . This implies ! r/q w(s) 0 ds z r/q +r/(2p) dz tr/(2p)−r/q dt Br0 . q s 0 0 z r/q Z ∞ Z ∞ Z ∞ w(s) r/q 0 +r/(2p) r/(2p)−r/q = ds z t dt dz sq z 0 z r/q Z ∞ Z ∞ w(s) 0 ≈ ds z r/q dz = Dr . q s 0 z Z ∞ Z t Z ∞ Thus the lower bound in (4.4) and also the necessity is proved; so the proof is complete. Next we shall analyze and discuss for which kernels k (x, y) the crucial conditions (4.2) holds. First we note that it follows for the case 1 < q < p < ∞ from a well-known result ([11], see also [2, Theorem 2.19]) that kKkLp →Lqw ≈ B0 + B1 , (4.8) On Weighted Inequalities with Geometric Mean Operator Generated by the Hardy-type Integral Transform Maria Nassyrova, Lars-Erik Persson Vladimir Stepanov Title Page Contents JJ J II I Go Back Close Quit where Z ∞ Z B0 := 0 t ∞ k(x, t)q w(y) dy K(x)q r/q !1/r 0 tr/q dt Page 20 of 37 J. Ineq. Pure and Appl. Math. 3(4) Art. 48, 2002 http://jipam.vu.edu.au and ∞ Z Z ∞ B1 := 0 t w(x) dx K(x)q r/p !1/r 0 Kp (t)r/p w(t) dt . K(t)q Moreover, it is established in ([5, Theorem 13]) that B1 ≤ β0 B0 for all weights w for which B0 < ∞, if and only if, Z t −1/r r r/p0 1/p0 (4.9) β0 := sup Kp (t) k (t, x) d x < ∞. t>0 On Weighted Inequalities with Geometric Mean Operator Generated by the Hardy-type Integral Transform 0 Therefore Maria Nassyrova, Lars-Erik Persson Vladimir Stepanov kKkLp →Lqw ≈ B0 (4.10) under the condition (4.9). Partly guided by our investigation in the previous section we shall now continue by comparing the constant B0 and B0 . Proposition 4.2. Let 1 < q < p < ∞. Then Title Page Contents JJ J (a) B0 . B0 , (b) B0 ≤ β1 B0 , if II I Go Back Z ∞ Z (4.11) β1 := 0 x p/r r r/q 0 k(x, t) t dt xp/q Close 0 Quit × K(x)−p(1+1/q) d (K(x)) 1/p < ∞. Page 21 of 37 J. Ineq. Pure and Appl. Math. 3(4) Art. 48, 2002 http://jipam.vu.edu.au Proof. (a) We have Z r B0 := ∞ Z t Z q x k(x, y)dy 0 0 0 w(x) dx K(x)q r/q t−r/q dt (applying Minkowski’s integral inequality) 1/q !r Z ∞ Z t Z t w(x) ≤ k(x, y)q dx dy t−r/q dt q K(x) 0 0 y !r 1/q Z ∞ Z t Z ∞ α −α q w(x) y y dy t−r/q dt dx ≤ k(x, y) q K(x) 0 0 y (applying Hölder’s inequality, α ∈ q10 , r10 ) !Z r/q r−1 t w(x) αr −αr 0 q dx y dy y dy t−r/q dt ≤ k(x, y) q K(x) 0 0 0 y r/qZ ∞ Z ∞Z ∞ 0 1−r q w(x) r−1−αr−r/q dx t dt y αr dy = (1 − αr ) k(x, y) q K(x) 0 y y Z ∞ Z t Z ∞ (1 − αr0 )1−r r = B . r (α − 1/q 0 ) 0 Maria Nassyrova, Lars-Erik Persson Vladimir Stepanov Title Page Contents JJ J II I Go Back Close (b) Indeed, following the proof of Proposition 3.2, we find Z x Z ∞ Z ∞ r/q r/q0 r q −q B0 ≤ k(x, t) w d −K(x) t dt 0 On Weighted Inequalities with Geometric Mean Operator Generated by the Hardy-type Integral Transform t Quit Page 22 of 37 t J. Ineq. Pure and Appl. Math. 3(4) Art. 48, 2002 http://jipam.vu.edu.au (by Minkowski’s integral inequality) Z ∞ x Z k(x, t)r ≤ 0 = r/q x w 0 !q/r 0 tr/q dt r/q d −K(x)−q t !r/q q/r Z x Z x 1 0 xd −K(x)−q w k(x, t)r tr/q dt x 0 0 0 !r/q q/r Z ∞ Z x Z x 1 0 q w k(x, t)r tr/q dt xK(x)−(q+1) dK(x) x 0 0 0 Z ≤ Z ∞ (by Hölder’s inequality applied with conjugate exponents ≤q r/q β1r Z 0 ∞ r q and pq ) Z x r/q 1 w dx = q r/q β1r Br0 x 0 and the proof follows. Remark 4.1. It is easy to see that the conditions (4.3), (4.9) and (4.11) are satisfied with k(x, y) ≡ 1, i.e. when GK = G (the standard geometric mean operator) and we conclude that Theorem 4.1 may be seen as a generalization of Theorem 4 in [6] (see also [7]). We finish this Section by showing that the kernel, investigated in [4], satisfies the condition (4.3). On Weighted Inequalities with Geometric Mean Operator Generated by the Hardy-type Integral Transform Maria Nassyrova, Lars-Erik Persson Vladimir Stepanov Title Page Contents JJ J II I Go Back Close Quit Page 23 of 37 J. Ineq. Pure and Appl. Math. 3(4) Art. 48, 2002 http://jipam.vu.edu.au Example 4.1. Let the kernel k(x, y) be given by y (4.12) k(x, y) = ϕ , x where ϕ(t) ≥ 0 is decreasing function on (0, 1) satisfying (4.13) ϕ(ts) ≤ d (ϕ(t) + ϕ(s)) , 0 < t, s < 1. Then R(3.1) is obviously valid. 1 If 0 ϕ(t)dt < ∞, then the kernel k(x, y) of the form (4.12) satisfies (4.3). Indeed, Z 1 Z 1 1 1 k(x, xt) log dt = ϕ(t) log dt t t 0 0 Z −k ∞ 2 X 1 = ϕ(t) log dt t −k−1 k=0 2 Z −k ∞ 2 X 1 ≤ ϕ(2−k−1 ) log dt t 2−k−1 k=0 . = ∞ X k=0 ∞ X ϕ(2−k−1 ) (k + 1) 2−k−1 Maria Nassyrova, Lars-Erik Persson Vladimir Stepanov Title Page Contents JJ J II I Go Back ϕ(2−k )k2−k ∞ X Close Quit k=1 ≤ 2d On Weighted Inequalities with Geometric Mean Operator Generated by the Hardy-type Integral Transform ϕ 2−k/2 k2−k Page 24 of 37 k=1 J. Ineq. Pure and Appl. Math. 3(4) Art. 48, 2002 http://jipam.vu.edu.au ≤ 2cd ∞ X ϕ 2−k/2 2−k/2 k=1 3/2 =2 cd ∞ X −k/2 ϕ 2 ≤2 cd ∞ Z X dx 2−k/2 ϕ (x) dx 2(−k−1)/2 k=1 1 ≤ 23/2 cd 2−k/2 2(−k−1)/2 k=1 3/2 Z Z ϕ(t)dt On Weighted Inequalities with Geometric Mean Operator Generated by the Hardy-type Integral Transform 0 3/2 =2 1 Z cd k(x, xt)dt 0 1 = 23/2 cd x where c = supk≥0 k2−k/2 . Z Maria Nassyrova, Lars-Erik Persson Vladimir Stepanov x k(x, z)dz, 0 Title Page Contents JJ J II I Go Back Close Quit Page 25 of 37 J. Ineq. Pure and Appl. Math. 3(4) Art. 48, 2002 http://jipam.vu.edu.au 5. Riemann-Liouville Operators Let γ > 0 and consider the following Riemann-Liouville operators: Z x γ (5.1) Rγ f (x) := γ (x − y)γ−1 f (y)dy, x 0 and corresponding geometric mean operators Z x γ γ−1 Gγ f (x) = exp γ (x − y) log f (y)dy . x 0 In this section we shall study the question of characterization of the weights u (x) and v (x) so that the inequality Z Maria Nassyrova, Lars-Erik Persson Vladimir Stepanov 1/q ∞ q Title Page (Gγ f (x)) u (x) dx (5.2) On Weighted Inequalities with Geometric Mean Operator Generated by the Hardy-type Integral Transform 0 Z ≤C ∞ p f (x) v(x)dx Contents 1/p , 0 < p, q < ∞ 0 holds and also to point out the corresponding stable estimates of C = kGγ kLpv →Lqu . We note that in the case 0 < γ < 1 the kernel k(x, y) = (x − y)γ−1 in (5.1) does not satisfy the Oinarov condition (3.1) so the results in Theorems 3.1 and 4.1 cannot be applied. However, this kernel has this property for the case γ ≥ 1 so the question above can be solved by simply applying Theorems 3.1 and 4.1. Here we unify both cases in the next theorem and give a separate proof to this operator which gives a better estimate of the upper bound. JJ J II I Go Back Close Quit Page 26 of 37 J. Ineq. Pure and Appl. Math. 3(4) Art. 48, 2002 http://jipam.vu.edu.au Theorem 5.1. (a) Let 0 < p ≤ q < ∞. Then (5.2) holds if and only if A0 < ∞. Moreover, A0 ≤ kGγ kLpv →Lqu ≤ γe1/p A0, (5.3) 1 ≤ γ < ∞. and A0 ≤ kGγ kLpv →Lqu . A0, (5.4) 0 < γ < 1. (b) Let 0 < q < p < ∞. Then (5.2) holds if and only if B0 < ∞. Moreover, kGγ kLpv →Lqu ≈ B0 . (5.5) The factors of equivalence in (5.4) and (5.5) depend on p, q and γ only. Remark 5.1. By applying Theorem 5.1 with γ = 1 we obtain Theorems 2 and 4 in [6] (see also [7]) even with the same constants in the upper estimate in (5.3). Partly guided by the technique used in [6], we postpone the proof of Theorem 5.1 and first prove two auxiliary results of independent interest, namely a characterization of the inequality Z ∞ 1/q Z ∞ 1/p q (5.6) (Rγ f ) w ≤C fp , f ≥ 0, 0 0 in a form suitable for our purpose. The following two theorems may be seen as a unification and generalization of the results from ([6, Theorems 1 and 3]) and ([9, Theorems 1 and 2]). On Weighted Inequalities with Geometric Mean Operator Generated by the Hardy-type Integral Transform Maria Nassyrova, Lars-Erik Persson Vladimir Stepanov Title Page Contents JJ J II I Go Back Close Quit Page 27 of 37 J. Ineq. Pure and Appl. Math. 3(4) Art. 48, 2002 http://jipam.vu.edu.au Theorem 5.2. (a) Let γ ≥ 1 and 1 < p ≤ q ≤ ∞. Then (5.7) A0 ≤ kRγ kLp →Lqw ≤ γp0 A0 . (b) Let 0 < γ < 1 and 1/γ < p ≤ q ≤ ∞. Then (5.8) A0 ≤ kRγ kLp →Lqw # " 1/p0 p−1 ≤γ 21/p + 22/p + 21−γ p0 A0 . pγ − 1 Remark 5.2. The lower bound A0 ≤ kRγ kLp →Lqw holds for all γ > 0 and 0 < p, q ≤ ∞. Theorem 5.3. (a) Let γ ≥ 1, 0 < q < p < ∞ and p > 1. Then γ 0 1/q 0 (5.9) (p0 ) p−1/r r−1/r qB0 ≤ kRγ kLp →Lqw ≤ γq 1/q p0 B0 . γ+1/r+1/q 2 (b) Let 0 < γ < 1, 0 < q < p < ∞ and pγ > 1. Then 1/r 1/p qr/p2 γ 2q/r − 1 2 −1 B0 23+1/r ≤ kRγ kLp →Lqw " 1/p0 p−1 1+1/q 1/p0 ≤ γB0 2 1+2 pγ − 1 !1/q q/r r q . (5.10) 4q + q (p0 ) + p On Weighted Inequalities with Geometric Mean Operator Generated by the Hardy-type Integral Transform Maria Nassyrova, Lars-Erik Persson Vladimir Stepanov Title Page Contents JJ J II I Go Back Close Quit Page 28 of 37 J. Ineq. Pure and Appl. Math. 3(4) Art. 48, 2002 http://jipam.vu.edu.au Proof of Theorem 5.2. For the lower bounds on (5.7) and (5.8) we replace f in (5.6) by the test function ft (x) = χ[0,t] (x), t > 0. Then for p, q < ∞ 1/p t Z ∞ q C≥ 1/q (Rγ ft ) w Z ≥ 0 1/q t w . 0 Hence, kRγ kLp →Lqw ≥ A0 for all γ > 0, 0 < p, q < ∞. For p ≤ q = ∞, p = q = ∞ or q < p = ∞ the arguments are the same. Clearly, Rγ f (x) ≤ γHf (x), (5.11) γ≥1 and the upper bound in (5.7) follows from Theorem 1 in [6]. For the upper bound in (5.8) we follow the scheme from the proof of Theorem 1 in [9]. Put Z J := 0 ∞ 1 xγ Z x (x − y)γ−1 f (y)dy 1/q q w(x)dx On Weighted Inequalities with Geometric Mean Operator Generated by the Hardy-type Integral Transform Maria Nassyrova, Lars-Erik Persson Vladimir Stepanov Title Page Contents JJ J II I 0 Go Back and note that, by Minkowski’s inequality, (5.12) J ≤ J1 + J2 + J3 , Close Quit Page 29 of 37 J. Ineq. Pure and Appl. Math. 3(4) Art. 48, 2002 http://jipam.vu.edu.au where J1q XZ := 2k k∈Z XZ J2q := and := 2k+1 2k k∈Z J3q 2k+1 XZ 2k+1 k∈Z Z w(x)dx xγq Z γ−1 (x − y) , f (y)dy 2k !q 2k (x − y)γ−1 f (y)dy , 2k−1 !q 2k−1 Z w(x)dx xγq 2k q x w(x)dx xγq (x − y)γ−1 f (y)dy . 0 Maria Nassyrova, Lars-Erik Persson Vladimir Stepanov Applying Hölder’s inequality we find J1q ≤ X Z 2k+1 f p !q/p Z 2k k∈Z 2k+1 w(x) dx xγq 2k Z x × Title Page Contents q/p0 (γ−1)p0 (x − y) dy 2k ≤ p−1 pγ − 1 q/p ≤2 q/p0 X Z p−1 pγ − 1 k∈Z !q/p 2k+1 fp 2k k∈Z Z 2k+1 2k q/p0 X Z On Weighted Inequalities with Geometric Mean Operator Generated by the Hardy-type Integral Transform !q/p 2k+1 f p ! w(x)dx 2−kq/p JJ J II I Go Back Close Quit 2k Page 30 of 37 J. Ineq. Pure and Appl. Math. 3(4) Art. 48, 2002 http://jipam.vu.edu.au 2−(k+1)q/p × ! 2k+1 Z w(x)dx 0 (5.13) q/p ≤2 p−1 pγ − 1 q/p0 Aq0 ∞ Z f p q/p , 0 where the last step follows by the elementary inequality 1 and the definition of A0 . Similarly, we obtain (5.14) J2q q/p ≤4 p−1 pγ − 1 q/p0 Z Aq0 ∞ f p P P aβi ≤ ( ai )β , β ≥ On Weighted Inequalities with Geometric Mean Operator Generated by the Hardy-type Integral Transform q/p . 0 For the upper bound of J3 we note that Z ∞ q (1−γ)q J3 ≤ 2 (Hf )q w Title Page Contents 0 JJ J so that, by Theorem 1 in [6] , (5.15) J3q (1−γ)q ≤2 Aq0 0 q Z (p ) ∞ f p Maria Nassyrova, Lars-Erik Persson Vladimir Stepanov q/p . II I Go Back 0 By combining (5.13), (5.14) and (5.15) we obtain the upper bound of (5.8) and the proof is complete. Close Quit Page 31 of 37 J. Ineq. Pure and Appl. Math. 3(4) Art. 48, 2002 http://jipam.vu.edu.au (a) For the lower bound we write Z C ∞ fp 1/p Z ∞ 1 xγ ≥γ 0 0 Z !1/q !q x/2 (x − y)γ−1 f (y)dy w(x)dx 0 !q !1/q Z 1 x/2 ≥ γ−1 f w(x)dx 2 x 0 0 Z ∞ Z x q 1/q 1 γ . ≥ γ f w(2x)dx 2 x 0 0 γ Z ∞ By applying Theorem 3 in [6] we find kRγ kLp →Lqw ≥ γ c (p, q) B0 , 2γ On Weighted Inequalities with Geometric Mean Operator Generated by the Hardy-type Integral Transform Maria Nassyrova, Lars-Erik Persson Vladimir Stepanov Title Page where Z B0 := 0 ∞ r/q !1/r Z x 1 w (2s) ds dx = 2−1/r B0 x 0 0 Contents JJ J II I 0 and c (p, q) = 2−1/q (p0 )1/q p−1/r r−1/r q and the lower bound in (5.9) is proved. Using (5.11) and again Theorem 3 in [6] we obtain the upper bound of (5.9). Close Quit (b) It is shown in Theorem 2 in [9] that kRγ kLp →Lqw ≥ Go Back γ E, 4 Page 32 of 37 J. Ineq. Pure and Appl. Math. 3(4) Art. 48, 2002 http://jipam.vu.edu.au where E := X Z 0 2kr/p 2k+1 w(x)dx xq 2k k∈Z !r/q 1/r . We show that q/r 2 1/r 1/p qr/p2 −1 2 −1 E≥ B0 . 21+1/r On Weighted Inequalities with Geometric Mean Operator Generated by the Hardy-type Integral Transform Indeed, Br0 = k∈Z ≤ X 2k Z x r/q 1 w dx x 0 2k−1 Z k !r/q Z XZ 2 −(k−1)r/q 2 X =2 dx 2k−1 XZ 2−(k−1)r/p k∈Z r/p m≤k X −kr/p 2 k∈Z 2k w 0 k∈Z = Maria Nassyrova, Lars-Erik Persson Vladimir Stepanov Title Page !r/q 2m Contents w JJ J 2m−1 X 2 −mq 2 rp Z 2m w 2 mq 2 rp !r/q Go Back 2m−1 m≤k (by applying Hölder’s inequality with Close and pq ) r q II I Quit ≤ 2r/p X k∈Z 2−kr/p X m≤k 2−mq/p Z r/q ! 2m w 2m−1 !r/p X 2mq/r Page 33 of 37 m≤k J. Ineq. Pure and Appl. Math. 3(4) Art. 48, 2002 http://jipam.vu.edu.au = = ≤ 2r/p+q/p X −mq/p r/p X (2qr/p2 − 1) m∈Z 2r(1+1/p) r/p − 1) r/q X 2m−1 22r/p (2q/r w m∈Z (2q/r − 1) 2m 2 r/p (2q/r − 1) Z (2qr/p2 − 1) 2−kqr/p 2 k≥m −mr/p Z r/q 2m 2 w 2m−1 Er . On Weighted Inequalities with Geometric Mean Operator Generated by the Hardy-type Integral Transform Conversely, r E ≤ X −(k−1)r/p 2 ≤2 w X −kr/p ≤ 2r/p+r/q r/p+r/q =2 !r/q Z 2k Z 2 k∈Z Br0 . 2k Title Page dx 2k 0 2k+1 XZ 2k+1 w k∈Z (5.16) Maria Nassyrova, Lars-Erik Persson Vladimir Stepanov 2k−1 k∈Z r/p !r/q 2k Z Contents Z x r/q 1 w dx x 0 JJ J Go Back Using the decomposition (5.12) it is shown in Theorem 2 in [9] that J≤ p−1 pγ − 1 1/p0 1/p0 2 II I 1/p0 1+2 1−γ Z E+2 ∞ q (Hf ) w 0 Close Quit 1/q . Page 34 of 37 J. Ineq. Pure and Appl. Math. 3(4) Art. 48, 2002 http://jipam.vu.edu.au Now the upper bound in (5.10) follows from (5.16) and Theorem 3 in [6]. We are now ready to complete this section by presenting Proof of Theorem 5.1. Both sides of (5.3) follow from Theorem 5.2 (a) and (2.4). The lower bound in (5.4) follows by using the test functions from the proof of Theorem 3.1 and the upper bound is a consequence of (2.2), (2.10) and (5.8). Similarly, the proof of (b) is based upon Theorem 5.3 and we use the same test function for the lower bound as in the proof of Theorem 4.1 with subsequent application of the inequality B0 ≤ B0 . The proof is complete. On Weighted Inequalities with Geometric Mean Operator Generated by the Hardy-type Integral Transform Maria Nassyrova, Lars-Erik Persson Vladimir Stepanov Title Page Contents JJ J II I Go Back Close Quit Page 35 of 37 J. Ineq. Pure and Appl. Math. 3(4) Art. 48, 2002 http://jipam.vu.edu.au References [1] S. BLOOM AND R. KERMAN, Weighted norm inequalities for operators of Hardy-type, Proc. Amer. Math. Soc., 113 (1991), 135–141. [2] A. KUFNER AND L.-E. PERSSON, Integral inequalities with weights, book manuscript, 2000. [3] E.R. LOVE, Inequalities related to those of Hardy and of Cochran and Lee, Math. Proc. Camb. Phil. Soc., 99 (1986), 395–408. [4] P.J. MARTIN-REYES AND E. SAWYER, Weighted inequalities for Riemann-Liouville fractional integrals of order one and greater, Proc. Amer. Math. Soc., 106 (1989), 727–733. [5] M. NASSYROVA, On characterization by a single constant of the weighted Lp − Lq boundedness of generalized Hardy-type integral operator, Research Report 8, Dept. of Math., Luleå University, 2001. [6] L.-E. PERSSON AND V.D. STEPANOV, Weighted integral inequalities with the geometric mean operator, J. of Inequal. & Appl., (to appear). [7] L.-E. PERSSON AND V.D. STEPANOV, Weighted integral inequalities with the geometric mean operator, Russian Akad. Sci. Dokl. Math., 63(2) (2001), 201–202. [8] L. PICK AND B. OPIC, On geometric mean operator, J. Math. Anal. Appl., 183 (1994), 652–662. [9] D.V. PROKHOROV, On boundedness and compactness of a class of integral operators, J. London Math. Soc., 61(2) (2000), 617–628. On Weighted Inequalities with Geometric Mean Operator Generated by the Hardy-type Integral Transform Maria Nassyrova, Lars-Erik Persson Vladimir Stepanov Title Page Contents JJ J II I Go Back Close Quit Page 36 of 37 J. Ineq. Pure and Appl. Math. 3(4) Art. 48, 2002 http://jipam.vu.edu.au [10] V.D. STEPANOV, On weighted estimates for a class of integral operators, Siberian Math. J., 34 (1993), 755–766. [11] V.D. STEPANOV, Weighted norm inequalities of Hardy-type for a class of integral operators, J. London Math. Soc., 50(2) (1994), 105–120. On Weighted Inequalities with Geometric Mean Operator Generated by the Hardy-type Integral Transform Maria Nassyrova, Lars-Erik Persson Vladimir Stepanov Title Page Contents JJ J II I Go Back Close Quit Page 37 of 37 J. Ineq. Pure and Appl. Math. 3(4) Art. 48, 2002 http://jipam.vu.edu.au