Journal of Inequalities in Pure and Applied Mathematics A SHARP INEQUALITY OF OSTROWSKI-GRÜSS TYPE ZHENG LIU Institute of Applied Mathematics Faculty of Science Anshan University of Science and Technology Anshan 114044, Liaoning People’s Republic of China. volume 7, issue 5, article 192, 2006. Received 9 February, 2006; accepted 23 May, 2006. Communicated by: J. Sándor EMail: lewzheng@163.net Abstract Contents JJ J II I Home Page Go Back Close c 2000 Victoria University ISSN (electronic): 1443-5756 163-06 Quit Abstract The main purpose of this paper is to use a Grüss type inequality for RiemannStieltjes integrals to obtain a sharp integral inequality of Ostrowski-Grüss type for functions whose first derivative are functions of Lipschitizian type and precisely characterize the functions for which equality holds. A Sharp Inequality of Ostrowski-Grüss Type 2000 Mathematics Subject Classification: 26D15. Key words: Ostrowski-Grüss type inequality, Grüss type inequality for RiemannStieltjes integrals, Lipschitzian type function, Sharp bound. Zheng Liu Contents 1 Introduction . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 2 The Results . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . References 3 7 Title Page Contents JJ J II I Go Back Close Quit Page 2 of 21 J. Ineq. Pure and Appl. Math. 7(5) Art. 192, 2006 http://jipam.vu.edu.au 1. Introduction In 1935, G. Grüss (see [4, p. 296]) proved the following integral inequality which gives an approximation for the integral of a product of two functions in terms of the product of integrals of the two functions. Theorem A. Let h, g : [a, b] → R be two integrable functions such that φ ≤ h(x) ≤ Φ and γ ≤ g(x) ≤ Γ for all x ∈ [a, b], where φ, Φ, γ, Γ are real numbers. Then we have (1.1) |T (h, g)| Z b Z b Z b 1 1 1 := h(x)g(x)dx − h(x)dx · g(x)dx b−a a b−a a b−a a 1 ≤ (Φ − φ)(Γ − γ), 4 and the inequality is sharp, in the sense that the constant by a smaller one. It is clear that the constant 1 4 cannot be replaced 1 4 is achieved for a+b . h(x) = g(x) = sgn x − 2 From then on, (1.1) has been known in the literature as the Grüss inequality. In 1998, S.S. Dragomir and I. Fedotov [2] established the following Grüss type inequality for Riemann-Stieltjes integrals: A Sharp Inequality of Ostrowski-Grüss Type Zheng Liu Title Page Contents JJ J II I Go Back Close Quit Page 3 of 21 J. Ineq. Pure and Appl. Math. 7(5) Art. 192, 2006 http://jipam.vu.edu.au Theorem B. Let h, u : [a, b] → R be so that u is L-Lipschitzian on [a, b], i.e., |u(x) − u(y)| ≤ L |x − y| for all x, y ∈ [a, b], h is Riemann integrable on [a, b] and there exists the real numbers m, M so that m ≤ h(x) ≤ M for all x ∈ [a, b]. Then we have the inequality Z b Z b 1 u(b) − u(a) (1.2) h(x)du(x) − h(t)dt ≤ L(M − m)(b − a) b−a 2 a a and the constant 1 2 A Sharp Inequality of Ostrowski-Grüss Type is sharp. In a recent paper [3], the inequality (1.2) has been improved and refined as follows: Theorem C. Let h, u : [a, b] → R be so that u is L-Lipschitzian on [a, b], h is Riemann integrable on [a, b] and there exist the real numbers m, M so that m ≤ h(x) ≤ M for all x ∈ [a, b]. Then we have Z b Z u(b) − u(a) b (1.3) h(x)du(x) − h(t)dt b − a a a Z b Z b 1 h(x) − dx ≤L h(t)dt b−a a a p ≤ L(b − a) T (h, h) 1 ≤ L(M − m)(b − a). 2 Zheng Liu Title Page Contents JJ J II I Go Back Close Quit Page 4 of 21 J. Ineq. Pure and Appl. Math. 7(5) Art. 192, 2006 All the inequalities in (1.3) are sharp and the constant 12 is the best possible one. http://jipam.vu.edu.au Theorem D. Let h, u : [a, b] → R be so that u is (l, L)-Lipschitzian on [a, b], i.e., it satisfies the condition l(x2 − x1 ) ≤ u(x2 ) − u(x1 ) ≤ L(x2 − x1 ) for a ≤ x1 ≤ x2 ≤ b with l < L, h is Riemann integral on [a, b] and there exist the real numbers m, M so that m ≤ h(x) ≤ M for all x ∈ [a, b]. Then we have the inequality Z b Z u(b) − u(a) b (1.4) h(t)dt h(x)du(x) − b − a a a Z b Z b 1 L−l h(x) − h(t)dtdx ≤ 2 b−a a a p L−l ≤ (b − a) T (h, h) 2 1 ≤ (L − l)(M − m)(b − a). 4 All the inequalities in (1.4) are sharp and the constant 14 is the best possible one. In [1], L.J. Dedić et al. have proved the following Ostrowski type inequality as A Sharp Inequality of Ostrowski-Grüss Type Zheng Liu Title Page Contents JJ J II I Go Back 0 Theorem E. If u is L-Lipschitzian on [a, b], then for every x ∈ [a, b] we have Z b b − a u(a) + u(b) a + b 0 (1.5) u(t)dt − u(x) + + x− u (x) 2 2 2 a ! 3 a + b 1 (b − a)3 ≤L x− + . 3 2 48 Close Quit Page 5 of 21 J. Ineq. Pure and Appl. Math. 7(5) Art. 192, 2006 http://jipam.vu.edu.au In this paper, we will use Theorem C and Theorem D to obtain some sharp integral inequalities of Ostrowski-Grüss type for functions whose first derivative are functions of Lipschitzian type. Thus a further generalization of the Ostrowski type inequality and a perturbed version of the inequality (1.5) is obtained. A Sharp Inequality of Ostrowski-Grüss Type Zheng Liu Title Page Contents JJ J II I Go Back Close Quit Page 6 of 21 J. Ineq. Pure and Appl. Math. 7(5) Art. 192, 2006 http://jipam.vu.edu.au 2. The Results Theorem 2.1. Let u : [a, b] → R be a differentiable function so that u0 is (l, L)Lipschitzian on [a, b], i.e., satisfies the condition (2.1) l(x2 − x1 ) ≤ u0 (x2 ) − u0 (x1 ) ≤ L(x2 − x1 ) for a ≤ x1 ≤ x2 ≤ b with l < L.Then for all x ∈ [a, b] we have Z b b − a u(a) + u(b) a + b 0 (u(x) + + x− u (x) (2.2) u(t)dt − 2 2 2 a a + b 2 (b − a)2 L − l u0 (b) − u0 (a) x− − − ≤ 4 I(a, b, x), 4 2 12 Zheng Liu where (2.3) A Sharp Inequality of Ostrowski-Grüss Type I(a, b, x)= a+3b −x 4 [3(x−a)+(b−x)] i 3 a ≤ x ≤ ξ, (b−a)2 2 4 1 a+b 2 + 3 2 x− 2 , + 48 a+b [(x−a)+3(b−x)] −x x− 3a+b 2 4 h i3 ξ < x < ζ, (b−a)2 2 1 a+b 2 +4 2 x− 2 + 48 , h 1 6 16 3 a+b −x 2 1 6 1 6 1 6 h 1 2 2 x− a+b 2 x− a+b 2 + (b−a)2 48 a+3b −x 4 i 32 , ζ ≤ x ≤ θ, Contents JJ J II I Go Back Close [3(x−a)+(b−x)] h 2 (b−a)2 i 32 +4 12 x− a+b + 48 , 2 3a+b x− a+b x− [(x−a)+3(b−x)] 2 h 4 2 (b−a)2 i 32 + 34 12 x− a+b + 48 , 2 Title Page θ < x < η, Quit Page 7 of 21 η ≤x≤b J. Ineq. Pure and Appl. Math. 7(5) Art. 192, 2006 http://jipam.vu.edu.au with √ a+b 3(b − a) ξ= − , 2√ 6 6(b − a) ζ =a+ , 6 and a < ξ < 3a+b 4 <ζ< a+b 2 √ a+b 3(b − a) η= + , 2√ 6 6(b − a) θ =b− 6 <θ< a+3b 4 < η < b. Proof. Integrating by parts produces the identity Z A Sharp Inequality of Ostrowski-Grüss Type b Zheng Liu K(x, t)du0 (t) (2.4) a Z = a b 1 u(a) + u(b) a+b 0 u(t)dt − (b − a) u(x) + + x− u (x) , 2 2 2 where ( (2.5) K(x, t) = 1 (t 2 − a) t − a+b 1 (t 2 − b) t − a+b 2 2 Title Page Contents JJ J , t ∈ [a, x], II I Go Back , t ∈ (x, b]. Close Moreover, Quit (2.6) 1 b−a Z b K(x, t)dt = a 1 4 " x− a+b 2 2 2 − (b − a) 12 # . Page 8 of 21 J. Ineq. Pure and Appl. Math. 7(5) Art. 192, 2006 http://jipam.vu.edu.au Applying the Grüss type inequality (1.4) gives Z b Z u0 (b) − u0 (a) b 0 K(x, t)du (t) − K(x, t)dt b − a a a Z b Z b L−l 1 K(x, t) − ≤ K(x, s)dsdt. 2 b−a a a Then for any fixed x ∈ [a, b] we can derive from (2.4), (2.5) and (2.6) that (2.7) Z b b − a u(a) + u(b) a + b 0 u(t)dt − u(x) + + x− u (x) 2 2 2 a " # 2 a+b (b − a)2 L − l u0 (b) − u0 (a) − x− − I(a, b, x), ≤ 4 2 12 4 A Sharp Inequality of Ostrowski-Grüss Type Zheng Liu Title Page Contents where x a+b 1 a + b 2 (b − a)2 − x− − I(a, b, x) = dt (t − a) t− 2 2 2 12 a Z b 2 a + b 1 a + b (b − a) 2 (t − b) t− dt. + − x− − 2 2 2 12 x Z The last two integrals can be calculated as follows: For brevity, we put " # 2 1 a+b (b − a)2 a+b p1 (t) := (t − a) t − − x− − , 2 2 2 12 JJ J II I Go Back Close Quit Page 9 of 21 t ∈ [a, x], J. Ineq. Pure and Appl. Math. 7(5) Art. 192, 2006 http://jipam.vu.edu.au a+b p2 (t) := (t − b) t − 2 1 − 2 " a+b x− 2 2 # (b − a)2 − , 12 t ∈ [x, b]. Then we have " 2 # 1 (b − a)2 a+b p1 (a) = p2 (b) = − x− ; 2 12 2 a+b (b − a)2 x− + , 2 24 1 b−a a+b (b − a)2 p2 (x) = x− x− + . 2 2 2 24 1 p1 (x) = 2 Set √ b−a x+ 2 √ a+b 3(b − a) a+b 3(b − a) − , η= + , 2 6 2 6 √ √ 6(b − a) 6(b − a) ζ =a+ , θ =b− . 6 6 It is easy to find that p1 (a) = p2 (b) ≤ 0 for x ∈ [a, ξ] ∪ [η, b], p1 (a) = p2 (b) > 0 for x ∈ (ξ, η) and p1 (x) ≤ 0 for x ∈ [a, ζ], p1 (x) > 0 for x ∈ (ζ, b], p2 (x) > 0 for x ∈ [a, θ), p2 (x) ≤ 0 for x ∈ [θ, b]. Notice that ξ= A Sharp Inequality of Ostrowski-Grüss Type Zheng Liu Title Page Contents JJ J II I Go Back Close Quit 3a + b a+b a + 3b a<ξ< <ζ< <θ< < η < b, 4 2 4 we see that there are five possible cases to be determined. Page 10 of 21 J. Ineq. Pure and Appl. Math. 7(5) Art. 192, 2006 http://jipam.vu.edu.au (i) In case x ∈ [ζ, θ]. p1 (a) = p2 (b) > 0, p1 (x) ≥ 0, p2 (x) ≥ 0 and it is easy to find by elementary calculus that the function p1 (t) is strictly decreasing 3a+b and strictly increasing in , x , also, as the function p2 (t) is in a, 3a+b 4 4 a+3b a+3b strictly decreasing in x, 4 and strictly increasing in 4 , b . Moreover, 3a+b a+3b p1 4 = p2 4 < 0. So, p1 (t) has two zeros in (a, x) at the points " # 12 2 3a + b (b − a)2 1 a+b t1 = + − x− 4 2 2 48 and " # 12 2 (b − a)2 3a + b 1 a+b . t2 = + x− + 4 2 2 48 Also p2 (t) has two zeros in (x, b) at the points " # 12 2 1 a+b (b − a)2 a + 3b + t3 = − x− 4 2 2 48 and " # 12 2 a + 3b 1 a+b (b − a)2 t4 = + x− + . 4 2 2 48 Thus we have (2.8) I(a, b, x) # 2 Z t1 " a+b 1 a+b (b − a)2 = (t − a) t− − x− + dt 2 2 2 24 a A Sharp Inequality of Ostrowski-Grüss Type Zheng Liu Title Page Contents JJ J II I Go Back Close Quit Page 11 of 21 J. Ineq. Pure and Appl. Math. 7(5) Art. 192, 2006 http://jipam.vu.edu.au " 2 # (b − a)2 1 a+b a+b + x− − − (t − a) t− dt 2 2 24 2 t1 Z x a+b 1 a + b 2 (b − a)2 + (t − a) t− − x− + dt 2 2 2 24 t2 # 2 Z t3 " (b − a)2 a+b 1 a+b dt + (t − b) t− − x− + 2 2 2 24 x 2 # Z t4 " 1 a+b (b − a)2 a+b + x− − − (t − b) t− dt 2 2 24 2 t3 # 2 Z b" a+b 1 a+b (b − a)2 + (t − b) t− − x− + dt 2 2 2 24 t4 " # 32 2 a+b (b − a)2 16 1 + . = x− 3 2 2 48 Z t2 (ii) In case x ∈ [a, ξ], p1 (a) = p2 (b) ≤ 0, p1 (x) < 0,p2 (x) > 0 and p1 (t) is ) strictly decreasing in (a, x) as well as p2 (t) is strictly decreasing in (x, a+3b 4 a+3b and strictly increasing in ( a+3b , b) with t ∈ (x, ) such that p (t ) = 0. 3 2 3 4 4 Thus we have (2.9) I(a, b, x) 2 # Z x" a+b (b − a)2 a+b 1 = x− − − (t − a) t− dt 2 2 24 2 a A Sharp Inequality of Ostrowski-Grüss Type Zheng Liu Title Page Contents JJ J II I Go Back Close Quit Page 12 of 21 J. Ineq. Pure and Appl. Math. 7(5) Art. 192, 2006 http://jipam.vu.edu.au " # 2 a+b (b − a)2 1 a+b + (t − b) t− − x− + dt 2 2 2 24 x 2 # Z b" 1 a+b (b − a)2 a+b + x− − − (t − b) t− dt 2 2 24 2 t3 1 a+b a + 3b = −x − x [3(x − a) + (b − x)] 6 2 4 " # 32 2 (b − a)2 4 1 a+b . + x− + 3 2 2 48 Z t3 A Sharp Inequality of Ostrowski-Grüss Type Zheng Liu (iii) In case (ξ, ζ), p1 (a) = p2 (b) > 0, p1 (x) < 0,p2 (x) > 0 and p1 (t) has a unique zero t1 ∈ (a, x), p2 (t) has two zeros t3 , t4 ∈ (x, b). Thus we have (2.10) I(a, b, x) # 2 Z t1 " a+b 1 a+b (b − a)2 = (t − a) t− − x− + dt 2 2 2 24 a Z x 1 a + b 2 (b − a)2 a+b + x− − − (t − a) t− dt 2 2 24 2 t1 # 2 Z t3 " a+b 1 a+b (b − a)2 + (t − b) t− − x− + dt 2 2 2 24 x 2 # Z t4 " 1 a+b (b − a)2 a+b + x− − − (t − b) t− dt 2 2 24 2 t3 Title Page Contents JJ J II I Go Back Close Quit Page 13 of 21 J. Ineq. Pure and Appl. Math. 7(5) Art. 192, 2006 http://jipam.vu.edu.au Z b a+b 1 a + b 2 (b − a)2 + (t − b) t− − x− + dt 2 2 2 24 t4 1 a+b 3a + b −x x− [(x − a) + 3(b − x)] = 6 2 4 #3 " 2 2 2 a+b (b − a) 1 x− + . +4 2 2 48 (iv) In case x ∈ (θ, η), p1 (a) = p2 (b) > 0, p1 (x) > 0, p2 (x) < 0 and p1 (t) has two zeros t1 , t2 ∈ (a, x), p2 (t) has a unique zero t4 ∈ (x, b). Thus we have A Sharp Inequality of Ostrowski-Grüss Type Zheng Liu (2.11) I(a, b, x) Z t1 1 a + b 2 (b − a)2 a+b = (t − a) t− − x− + dt 2 2 2 24 a 2 # Z t2 " a+b (b − a)2 a+b 1 + x− − − (t − a) t− dt 2 2 24 2 t1 # 2 Z x" a+b 1 a+b (b − a)2 + (t − a) t− − x− + dt 2 2 2 24 t2 2 # Z t4 " 2 1 a+b (b − a) a+b + x− − − (t − b) t− dt 2 2 24 2 x # 2 Z b" 2 a+b 1 a+b (b − a) + (t − b) t− − x− + dt 2 2 2 24 t4 Title Page Contents JJ J II I Go Back Close Quit Page 14 of 21 J. Ineq. Pure and Appl. Math. 7(5) Art. 192, 2006 http://jipam.vu.edu.au a+b a + 3b x− − x [3(x − a) + (b − x)] 2 4 # 32 " 2 1 a+b (b − a)2 +4 x− + . 2 2 48 1 = 6 (v) In case x ∈ [η, b], p1 (a) = p2 (b) ≤ 0, p1 (x) > 0, p2 (x) < 0 and p1 (t) has a unique zero t2 ∈ (a, x), p2 (t) ≤ 0 for t ∈ [x, b]. Thus we have (2.12) I(a, b, x) 2 # Z t2 " 1 (b − a)2 a+b a+b = x− − − (t − a) t− dt 2 2 24 2 a # 2 Z x" a+b (b − a)2 1 a+b + (t − a) t− − x− + dt 2 2 2 24 t2 2 # Z b" 1 a+b (b − a)2 a+b + x− − − (t − b) t − dt 2 2 24 2 x 1 a+b 3a + b = x− x− [(x − a) + 3(b − x)] 6 2 4 " # 32 2 a+b (b − a)2 4 1 x− + + . 3 2 2 48 A Sharp Inequality of Ostrowski-Grüss Type Zheng Liu Title Page Contents JJ J II I Go Back Close Quit Page 15 of 21 Consequently, the inequality (2.2) with (2.3) follows from (2.7), (2.8), (2.9), (2.10), (2.11) and (2.12). The proof is completed. J. Ineq. Pure and Appl. Math. 7(5) Art. 192, 2006 http://jipam.vu.edu.au Remark 1. It is not difficult to prove that the inequality (2.2) with (2.3) is sharp in the sense that we can construct the function u to attain the equality in (2.2) with (2.3). Indeed, we may choose u such that 1 (t − a)2 , a ≤ t < x, 2 L (t − x)2 + 2l [2(x − a)t − (x2 − a2 )], x ≤ t < t3 , 2 u(t) = 2l [(t − t3 )2 + 2(x − a)t − (x2 − a2 )] + L2 [2(t3 − x)t − (t23 − x2 )], t3 ≤ t ≤ b, which follows A Sharp Inequality of Ostrowski-Grüss Type Zheng Liu a ≤ t < x, l(t − a), 0 L(t − x) + (x − a)l, x ≤ t < t3, u (t) = l(t − t3 + x − a) + (t3 − x)L, t3 ≤ t ≤ b, Title Page Contents for any x ∈ [a, ξ], and L (t − a)2 , 2 l (t − t1 )2 + L2 [2(t1 − a)t − (t21 − a2 )], 2 L [(t − x)2 + 2(t1 − a)t − (t21 − a2 )] 2 + 2l [2(x − t1 )t − (x2 − t21 )], u(t) = l [(t − t23 ) + 2(x − t1 )t − (x2 − t21 )] 2 + L2 [2(t3 − x + t1 − a)t − (t23 − x2 + t21 − a2 )], L [(t − t4 )2 + 2(t3 − x + t1 − a)t − (t23 − x2 + t21 − a2 )] 2 + 2l [2(t4 − t3 + x − t1 )t − (t24 − t23 + x2 − t21 )], a ≤ t < t1 , t1 ≤ t < x, x ≤ t < t3 , JJ J II I Go Back Close Quit t3 ≤ t < t4 , Page 16 of 21 J. Ineq. Pure and Appl. Math. 7(5) Art. 192, 2006 t4 ≤ t ≤ b, http://jipam.vu.edu.au which follows L(t − a), l(t − t1 ) + (t1 − a)L, 0 L(t − x + t1 − a) + (x − t1 )l, u (t) = l(t − t3 + x − t1 ) + (t3 − x + t1 − a)L, L(t − t4 + t3 − x + t1 − a) + (t4 − t3 + x − t1 )l, a ≤ t < t1 , t1 ≤ t < x, x ≤ t < t3 , t3 ≤ t < t4 , t4 ≤ t ≤ b, for any x ∈ (ξ, ζ), and L (t − a)2 , 2 l (t − t1 )2 + L2 [2(t1 − a)t − (t21 − a2 )], 2 L [(t − t2 )2 + 2(t1 − a)t − (t21 − a2 )] 2 + 2l [2(t2 − t1 )t − (t22 − t21 )], u(t) = l [(t − t23 ) + 2(t2 − t1 )t − (t22 − t21 )] 2 + L2 [2(t3 − t2 + t1 − a)t − (t23 − t22 + t21 − a2 )], L [(t − t4 )2 + 2(t3 − t2 + t1 − a)t − (t23 − t22 + t21 − a2 )] 2 + l [2(t − t + t − t )t− (t2 − t2 + t2 − t2 ) ], 2 4 3 2 1 4 3 2 1 A Sharp Inequality of Ostrowski-Grüss Type Zheng Liu a ≤ t < t1 , Title Page t1 ≤ t < t2 , t2 ≤ t < t3 , Contents JJ J II I Go Back t3 ≤ t < t4 , Close Quit t4 ≤ t ≤ b, Page 17 of 21 J. Ineq. Pure and Appl. Math. 7(5) Art. 192, 2006 http://jipam.vu.edu.au which follows L(t − a), l(t − t1 ) + (t1 − a)L, 0 L(t − t2 + t1 − a) + (t2 − t1 )l, u (t) = l(t − t3 + t2 − t1 ) + (t3 − t2 + t1 − a)L, L(t − t4 + t3 − t2 + t1 − a) + (t4 − t3 + t2 − t1 )l, a ≤ t < t1 , t1 ≤ t < t2 , t2 ≤ t < t3 , t3 ≤ t < t4 , t4 ≤ t ≤ b, for any x ∈ (ξ, ζ), and L (t − a)2 , 2 l (t − t1 )2 + L2 [2(t1 − a)t − (t21 − a2 )], 2 L [(t − t2 )2 + 2(t1 − a)t − (t21 − a2 )] 2 + 2l [2(t2 − t1 )t − (t22 − t21 )], u(t) = l [(t − x2 ) + 2(t2 − t1 )t − (t22 − t21 )] 2 + L2 [2(x − t2 + t1 − a)t − (x2 − t22 + t21 − a2 )], L [(t − t4 )2 + 2(x − t2 + t1 − a)t − (x2 − t22 + t21 − a2 )] 2 + l [2(t − x + t − t )t − (t2 − x2 + t2 − t2 )], 2 4 2 1 4 2 1 A Sharp Inequality of Ostrowski-Grüss Type Zheng Liu a ≤ t < t1 , Title Page t1 ≤ t < t2 , Contents t2 ≤ t < x, JJ J II I Go Back x ≤ t < t4 , Close Quit t4 ≤ t ≤ b, Page 18 of 21 J. Ineq. Pure and Appl. Math. 7(5) Art. 192, 2006 http://jipam.vu.edu.au which follows L(t − a), l(t − t1 ) + (t1 − a)L, L(t − t2 + t1 − a) + (t2 − t1 )l, u0 (t) = l(t − x + t2 − t1 ) + (x − t2 + t1 − a)L, L(t − t4 + x − t2 + t1 − a) + (t4 − x + t2 − t1 )l, a ≤ t < t1 , t1 ≤ t < t2 , t2 ≤ t < x, x ≤ t < t4 , t4 ≤ t ≤ b, for any x ∈ (θ, η), and l (t − a)2 , a ≤ t < t2 , 2 L (t − t2 )2 + l [2(t2 − a)t − (t2 − a2 )], t2 ≤ t < x, 2 2 2 u(t) = l [(t − x)2 + 2(t2 − a)t − (t22 − a2 )] 2 + L2 [2(x − t2 )t − (x2 − t22 )], x ≤ t ≤ b, which follows l(t − a), a ≤ t < t2 , L(t − t2 ) + (t2 − a)l, t2 ≤ t < x, u0 (t) = l(t − x + t − a) + (x − t )L, x ≤ t ≤ b. 2 2 A Sharp Inequality of Ostrowski-Grüss Type Zheng Liu Title Page Contents JJ J II I Go Back Close Quit Page 19 of 21 J. Ineq. Pure and Appl. Math. 7(5) Art. 192, 2006 for any x ∈ [η, b]. http://jipam.vu.edu.au It is clear that all the above u0 (t) satisfy the condition (2.1) on [a, b]. Remark 2. For x = a+b , 2 we have Z b 2 a + b b − a u(a) + u(b) (b − a) 0 0 u(t)dt − u + + [u (b) − u a)] 2 2 2 48 a (L − l)(b − a)3 √ ≤ . 144 3 Corollary 2.2. If u0 is L-Lipschitzian on [a, b], then for all x ∈ [a, b] we have (2.13) Z b u(a) + u(b) a+b b−a 0 u(x) + + x− u (x) u(t)dt − 2 2 2 a u0 (b) − u0 (a) a + b 2 (b − a)2 L − x− − ≤ 2 I(a, b, x), 4 2 12 where I(a, b, x) is as defined in (2.3). Proof. It is immediate by taking l = −L in the theorem. A Sharp Inequality of Ostrowski-Grüss Type Zheng Liu Title Page Contents JJ J II I Go Back Close Quit Page 20 of 21 J. Ineq. Pure and Appl. Math. 7(5) Art. 192, 2006 http://jipam.vu.edu.au References [1] L.J. DEDIĆ, M. MATIĆ, J. PEČARIĆ AND A. VUKELIĆ, On generalizations of Ostrowski inequality via Euler harmonic identities, J. of Inequal. & Appl., 7(6) (2002), 787–805. [2] S.S. DRAGOMIR AND I. FEDOTOV, An inequality of Grüss type for Riemann-Stieltjes integral and applications for special means, Tamkang J. of Math., 29(4) (1998), 286–292. [3] Z. LIU, Refinement of an inequality of Grüss type for Riemann-Stieltjes integral, Soochow J. of Math., 30(4) (2004), 483–489. [4] D.S. MITRINOVIĆ, J. PEČARIĆ AND A.M. FINK, Classical and New Inequalities in Analysis, Kluwer Academic Publishers, Dordrecht, 1993. A Sharp Inequality of Ostrowski-Grüss Type Zheng Liu Title Page Contents JJ J II I Go Back Close Quit Page 21 of 21 J. Ineq. Pure and Appl. Math. 7(5) Art. 192, 2006 http://jipam.vu.edu.au