Journal of Inequalities in Pure and Applied Mathematics ON SOME CLASSES OF ANALYTIC FUNCTIONS KHALIDA INAYAT NOOR AND M.A. SALIM Department of Mathematics and Computer Science College of Science United Arab Emirates University P.O. Box 17551, Al-Ain United Arab Emirates. volume 5, issue 4, article 98, 2004. Received 20 September, 2004; accepted 09 October, 2004. Communicated by: Th.M. Rassias EMail: KhalidaN@uaeu.ac.ae Abstract Contents JJ J II I Home Page Go Back Close c 2000 Victoria University ISSN (electronic): 1443-5756 189-04 Quit Abstract We define some classes of analytic functions related with the class of functions with bounded boundary rotation and study these classes with reference to certain integral operators. 2000 Mathematics Subject Classification: 30C45, 30C50. Key words: Close-to-convex functions, Univalent functions, Bounded boundary rotation, Integral operator. On Some Classes Of Analytic Functions Contents 1 Introduction . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 2 Preliminary Results . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 3 Main Results . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . References Khalida Inayat Noor and M.A. Salim 3 5 7 Title Page Contents JJ J II I Go Back Close Quit Page 2 of 13 J. Ineq. Pure and Appl. Math. 5(4) Art. 98, 2004 http://jipam.vu.edu.au 1. Introduction P m Let A denote the class of functions f of the form f (z) = z + ∞ m=2 am z which are analytic in the unit disk E = {z : |z| < 1}. Let C, S ? , K and S be the subclasses of A which are respectively convex, starlike, close-to-convex and univalent in E. It is known that C ⊂ S ? ⊂ K ⊂ S. In [1], Kaplan showed that f ∈ K if, and only if, for z ∈ E, 0 ≤ θ1 < θ2 ≤ 2π, 0 < r < 1, Z θ2 reiθ f 00 (reiθ ) Re 1 + dθ > −π, z = reiθ . 0 (reiθ ) f θ1 Let Vk (k ≥ 2) be the class of locally univalent functions f ∈ A that map E conformally onto a domain whose boundary rotation is at most kπ. It is well known that V2 ≡ C and Vk ⊂ K for 2 ≤ k ≤ 4. Definition 1.1. Let f ∈ A and f 0 (z) 6= 0. Then f ∈ Tk (λ), k ≥ 2, 0 ≤ λ < 1 if there exists a function g ∈ Vk such that, for z ∈ E 0 f (z) Re > λ. g 0 (z) The class Tk (0) = Tk was considered in [2, 3] and T2 (0) = K, the class of close-to-convex functions. 0 Definition 1.2. Let f ∈ A and f (z)fz (z) 6= 0, z ∈ E. Then f ∈ Tk (a, γ, λ), Re a ≥ 0, 0 ≤ γ ≤ 1 if, and only if, there exists a function g ∈ Tk (λ) such that (1.1) zf 0 (z) + af (z) = (a + 1)z(g 0 (z))γ , z ∈ E. On Some Classes Of Analytic Functions Khalida Inayat Noor and M.A. Salim Title Page Contents JJ J II I Go Back Close Quit Page 3 of 13 J. Ineq. Pure and Appl. Math. 5(4) Art. 98, 2004 http://jipam.vu.edu.au We note that Tk (0, 1, λ) = Tk (λ) and T2 (0, 1, λ) = K(λ) ⊂ K, and it follows that f ∈ Tk (a, γ, λ) if, and only if, there exists F ∈ Tk (∞, γ, λ) such that Z a + 1 z a−1 f (z) = t F (t)dt. za 0 On Some Classes Of Analytic Functions Khalida Inayat Noor and M.A. Salim Title Page Contents JJ J II I Go Back Close Quit Page 4 of 13 J. Ineq. Pure and Appl. Math. 5(4) Art. 98, 2004 http://jipam.vu.edu.au 2. Preliminary Results Lemma 2.1 ([2]). Let f ∈ A. Then, for 0 ≤ θ1 < θ2 ≤ 2π, z = reiθ , 0 < r < 1, f ∈ Tk if and only if 0 Z θ2 zf (z))0 k Re dθ > − π. 0 f (z) 2 θ1 Lemma 2.2. Let q(z) be analytic in E and of the form q(z) = 1 + b1 z + · · · for |z| = r ∈ (0, 1). Then, for a, c1 , θ1 , θ2 with a ≥ 1, Re(c1 ) ≥ 0, 0 ≤ θ1 < θ2 ≤ 2π, Z θ2 azq 0 (z) Re q(z) + dθ > −β1 π; (0 < β1 ≤ 1) c1 a + q(z) θ1 implies Z On Some Classes Of Analytic Functions Khalida Inayat Noor and M.A. Salim Title Page θ2 Re q(z)dθ > −β1 π, iθ z = re . θ1 This result is a direct consequence of the one proved in [4] for β1 = 1. From (1.1) and Lemma 2.1, we can easily have the following: Lemma 2.3. A function f ∈ Tk (∞, γ, λ) if and only if, it may be represented as f (z) = p(z) · zG0 (z), where G ∈ Vk and Re p(z) > λ, z ∈ E. Contents JJ J II I Go Back Close Proof. Since f ∈ Tk (∞, γ, λ), we have f (z) = z(g 0 (z))γ , g ∈ Tk (λ) γ 0 = z [G1 (z)p1 (z)] , G1 ∈ Vk , Re p1 (z) > λ = zG0 (z).p(z), Quit Page 5 of 13 J. Ineq. Pure and Appl. Math. 5(4) Art. 98, 2004 http://jipam.vu.edu.au where G0 (z) = (G01 (z))γ ∈ Vk and p(z) = (p1 (z))γ , Re p(z) > λ, since 0 ≤ γ ≤ 1. The converse case follows along similar lines. Using Lemma 2.1 and Lemma 2.3, we have: Lemma 2.4. (i) Let f ∈ Tk (0, γ, λ). Then, with z = reiθ , 0 ≤ θ1 < θ − 2 ≤ 2π, Z θ2 kγ (zf 0 (z))0 dθ > − , see also [3]. Re 0 f (z) 2 θ1 (ii) Let f ∈ Tk (∞, γ, λ). Then, for z = reiθ and 0 ≤ θ1 < θ2 ≤ 2π, 0 Z θ2 kγ zf (z) dθ > − . Re f (z) 2 θ1 On Some Classes Of Analytic Functions Khalida Inayat Noor and M.A. Salim Title Page Contents JJ J II I Go Back Close Quit Page 6 of 13 J. Ineq. Pure and Appl. Math. 5(4) Art. 98, 2004 http://jipam.vu.edu.au 3. Main Results Theorem 3.1. For 0 < α < f, g ∈ Tk (∞, γ, λ), z ∈ E, let (3.1) 1 , 1−λ+λβ 0 < β < λ , 1−λ 0 ≤ λ < 1 2 and 1 1+β Z z 1 1 1− α −2 1 F (z) = β+ z t α (f (t))β g(t)dt . α 0 Then F1 , with F = zF10 and 0 < γ < 1, k ≤ γ2 , is close-to-convex and hence univalent in E. On Some Classes Of Analytic Functions Khalida Inayat Noor and M.A. Salim Proof. We can write (3.1) as Z z 1 1 1− α −2 1 β+1 (3.2) (F (z)) = β+ z t α (f (t))β g(t)dt. α 0 Title Page Contents Let JJ J zF 0 (z) (zF10 (z))0 = = (1 − λ)H(z) + λ, F (z) F10 (z) (3.3) Go Back where H(z) is analytic in E and H(z) = 1 + c1 z + c2 z 2 + · · · . We differentiate (3.2) logarithmically to obtain 0 (β + 1) zF (z) = F (z) 1− 1 α + Rz 0 z t 1 α −1 1 α −2 II I Close Quit β (f (z)) g(z) . Page 7 of 13 (f (z))β (t)g(t)dt J. Ineq. Pure and Appl. Math. 5(4) Art. 98, 2004 http://jipam.vu.edu.au Using (3.2) and differentiating again, we have after some simplifications, (1 − λ)zH Now Rz 0 0 1 −2 t α (f (t))β g(t)dt + (1 − λ)H(z) 1 −1 z α (f (z))β g(z) β zf 0 (z) 1 zg 0 (z) = · + · − λ. 1 + β f (z) β + 1 g(z) 1 −1 z α (f (z))β g(z) Rz 0 1 −2 = t α (f (t))β g(t)dt 1 zF 0 (z) − 1 + (1 + β) . α F (z) Hence −λ+ β zf 0 (z) 1 zg 0 (z) · + · 1 + β f (z) β + 1 g(z) On Some Classes Of Analytic Functions Khalida Inayat Noor and M.A. Salim Title Page (1 − λ)zH 0 (z) = (1 − λ)H(z) + (1 − λ)(1 + β)H(z) + ( α1 − 1) + λ(1 + β) and we have Contents JJ J II I Go Back (3.4) 1 β 1−λ 1+β 0 zf (z) 1 −λ + f (z) 1+β 0 zg (z) −λ g(z) 1 zH 0 (z) (1+β)(1−λ) h 1 i. = H(z) + ( α −1) λ H(z) + (1+β)(1−λ) + 1−λ Close Quit Page 8 of 13 J. Ineq. Pure and Appl. Math. 5(4) Art. 98, 2004 http://jipam.vu.edu.au Since f, g ∈ Tk (∞, γ, λ), so with z = reiθ , 0 ≤ θ1 < θ2 ≤ 2π, 0 Z θ2 1 zf (z) β Re −λ dθ 1 + β θ1 1 − λ f (z) 0 Z θ2 1 1 zg (z) −kγ + Re −λ dθ > π, 1 + β θ1 1 − λ g(z) 2 and, therefore, Z θ2 Re H(z) + θ1 1 zH 0 (z) (1+β)(1−λ) H(z) + Now using Lemma 2.2 with a = 0, we obtain the required result. n 1 −1) (α (1+β)(1−λ) 1 (1+β)(1−λ) + λ 1−λ ≥ 1, c1 = −kγ o dθ > π. 2 1 α On Some Classes Of Analytic Functions Khalida Inayat Noor and M.A. Salim − 1 + (1 + β)λ ≥ Title Page Theorem 3.2. Let f, g ∈ Tk (∞, γ, λ), α, c, δ and ν be positively real, 0 < α ≤ 1 , c > α(1 − λ), (ν + δ) = α. Then the function F defined by 1−λ Z z α α−c (c−δ−ν)−1 δ ν (3.5) [F (z)] = cz t (f (t)) (g(t)) dt 0 belongs to Tk (∞, γ, λ) for k ≤ γ2 , 0 < γ < 1. Proof. First we show that there exists an analytic function F satisfying (3.5). Let G(z) = z −(ν+δ) (f (z))δ (g(z))ν = 1 + d1 z + d2 z 2 + · · · Contents JJ J II I Go Back Close Quit Page 9 of 13 J. Ineq. Pure and Appl. Math. 5(4) Art. 98, 2004 http://jipam.vu.edu.au and choose the branches which equal 1 when z = 0. For K(z) = z (c−ν−δ)−1 δ ν (f (z)) (g(z)) = z c−1 G(z), we have Z c z c L(z) = c K(t)dt = 1 + d1 z + · · · . z 0 1+c Hence L is well-defined and analytic in E. Now let 1 α α1 α F (z) = z L(z) = z [L(z)] , 1 where we choose the branch of [L(z)] α which equals 1 when z = 0. Thus F is analytic in E and satisfies (3.5). Set (3.6) zF 0 (z) = (1 − λ)h(z) + λ, F (z) and let zf 0 (z) = (1 − λ)h1 (z) + λ f (z) zg 0 (z) = (1 − λ)h2 (z) + λ. g(z) Now, from (3.5), we have h (c−δ−ν)−1 i zF 0 (z) (c−α) α δ ν (3.7) z [F (z)] (c − α) + α =c z (f (z)) (g(z)) . F (z) On Some Classes Of Analytic Functions Khalida Inayat Noor and M.A. Salim Title Page Contents JJ J II I Go Back Close Quit Page 10 of 13 J. Ineq. Pure and Appl. Math. 5(4) Art. 98, 2004 http://jipam.vu.edu.au We differentiate (3.7) logarithmically and use (3.6) to obtain zh0 (z) α(1 − λ) h(z) + + (δ + ν − α) (c − α) + α{λ + (1 − λ)h(z)} zf 0 (z) zg 0 (z) =δ +ν − αλ f (z) g(z) 0 0 zf (z) zg (z) =δ −λ +ν −λ . f (z) g(z) This gives us h(z) + On Some Classes Of Analytic Functions zh0 (z) (c − α) + α{λ + (1 − λ)h(z)} 0 0 δ zf (z) ν zg (z) = −λ + −λ . α(1 − λ) f (z) α(1 − λ) g(z) Khalida Inayat Noor and M.A. Salim Title Page Contents Since f, g ∈ Tk (∞, γ, λ), we have, for 0 ≤ θ1 < θ2 ≤ 2π, z = reiθ , Z θ2 zh0 (z) dθ Re h(z) + (c − α) + α{λ + (1 − λ)h(z)} θ1 Z θ2 Z δ ν θ2 = Re h1 (z)dθ + Re h2 (z)dθ α θ1 α θ1 δ γk ν γk > − π + − π α 2 α 2 γk γk δ+ν − π = − π, = α 2 2 JJ J II I Go Back Close Quit Page 11 of 13 J. Ineq. Pure and Appl. Math. 5(4) Art. 98, 2004 http://jipam.vu.edu.au where we have used Lemma 2.4. Now using Lemma 2.2 with a = 1 α(1−λ) > 1, for α < 1 1−λ and c1 = c − α + αλ = c − α(1 − λ) ≥ 0, we obtain the required result. On Some Classes Of Analytic Functions Khalida Inayat Noor and M.A. Salim Title Page Contents JJ J II I Go Back Close Quit Page 12 of 13 J. Ineq. Pure and Appl. Math. 5(4) Art. 98, 2004 http://jipam.vu.edu.au References [1] W. KAPLAN, Close-to-convex Schlicht functions, Michigan Math. J., (1952), 169–185. [2] K.I. NOOR, On a generalization of close-to-convexity, Intern. J. Math. & Math. Sci., 6 (1983), 327–334. [3] K.I. NOOR, Higher order close-to-convex functions, Math. Japonica, 37 (1192), 1–8. [4] R. PARVATHAN AND S. RADHA, On certain classes of analytic functions, Ann. Polon. Math., 49 (1988), 31–34. On Some Classes Of Analytic Functions Khalida Inayat Noor and M.A. Salim Title Page Contents JJ J II I Go Back Close Quit Page 13 of 13 J. Ineq. Pure and Appl. Math. 5(4) Art. 98, 2004 http://jipam.vu.edu.au