Journal of Inequalities in Pure and Applied Mathematics THE QUATERNION MATRIX-VALUED YOUNG’S INEQUALITY RENYING ZENG Department of Mathematics Saskatchewan Institute of Applied Science and Technology Moose Jaw, Saskatchewan CANADA S6H 4R4 volume 6, issue 3, article 89, 2005. Received 09 December, 2002; accepted 04 June, 2005. Communicated by: G.P. Styan EMail: zeng@siast.sk.ca Abstract Contents JJ J II I Home Page Go Back Close c 2000 Victoria University ISSN (electronic): 1443-5756 136-02 Quit Abstract In this paper, we prove Young’s inequality in quaternion matrices: for any n × n quaternion matrices A and B, any p, q ∈ (1, ∞) with p1 + 1q = 1, there exists n × n unitary quaternion matrix Usuch that U|AB ∗ |U ∗ ≤ p1 |A|p + 1q |B|q . Furthermore, there exists unitary quaternion matrix U such that the equality holds if and only if |B| = |A|p−1 . The Quaternion Matrix-Valued Young’s Inequality 2000 Mathematics Subject Classification: 15A45, 15A42. Key words: Quaternion, Matrix, Young’s inequality, Real representation. Renying Zeng Contents Title Page 1 Introduction . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 3 2 Matrix-valued Young’s inequality: the Quaternion Version . . 5 3 The Case of Equality . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 11 References Contents JJ J II I Go Back Close Quit Page 2 of 14 J. Ineq. Pure and Appl. Math. 6(3) Art. 89, 2005 http://jipam.vu.edu.au 1. Introduction The two most important classical inequalities probably are the triangle inequality and the arithmetic-geometric mean inequality. The triangle inequality states that |α + β| ≤ |α| + |β| for any complex numbers α, β. Thompson [7] extended the classical triangle inequality to n × n complex matrices: for any n × n complex matrices A and B, there are n × n unitary complex matrices U and V such that (1.1) |A + B| ≤ U |A|U ∗ + V |B|V ∗ . Thompson [6] proved that, the equality in the matrix-valued triangle inequality (1.1) holds if and only if A and B have polar decompositions with a common unitary factor. Furthermore, Thompson [5] extended the complex matrix-valued triangle inequality (1.1) to the quaternion matrices: for any n × n quaternion matrices A and B, there are n × n unitary quaternion matrices U and V such that |A + B| ≤ U |A|U ∗ + V |B|V ∗ . The arithmetic-geometric mean inequality is as follows: for any complex numbers α, β, p 1 |αβ| ≤ (|α| + |β|); 2 or, 1 |αβ| ≤ (|α|2 + |β|2 ), 2 The Quaternion Matrix-Valued Young’s Inequality Renying Zeng Title Page Contents JJ J II I Go Back Close Quit Page 3 of 14 J. Ineq. Pure and Appl. Math. 6(3) Art. 89, 2005 http://jipam.vu.edu.au which is a special case of the classical Young’s inequality: for any complex numbers α, β, and any p, q ∈ (1, ∞) with p1 + 1q = 1, 1 1 |αβ| ≤ |α|p + |β|q . p q Bhatia and Kittaneh [2], Ando [1] extended the classical arithmetic-geometric mean inequality and Young’s inequality to n×n complex matrices, respectively. This is Ando’s matrix-valued Young’s inequality: for any n × n complex matrices A and B, any p, q ∈ (1, ∞) with p1 + 1q = 1, there is unitary complex matrix U such that 1 1 U |AB ∗ |U ∗ ≤ |A|p + |B|q . p q Bhatia and Kittaneh’s result is the case of p = q = 2, i.e., Young’s inequality recovers Bhatia and Kittaneh’s arithmetic-geometric-mean inequality, likewise, Ando’s matrix version of Young’s inequality captures the Bhatia-Kittaneh matricial arithmetic-geometric-mean inequality. We mention that Erlijman, Farenick and the author [8] proved Young’s inequality for compact operators. This paper extends the Young’s inequality to n × n quaternion matrices and examines the case where equality in the inequality holds. The Quaternion Matrix-Valued Young’s Inequality Renying Zeng Title Page Contents JJ J II I Go Back Close Quit Page 4 of 14 J. Ineq. Pure and Appl. Math. 6(3) Art. 89, 2005 http://jipam.vu.edu.au 2. Matrix-valued Young’s inequality: the Quaternion Version We use R, C, and H to denote the set of real numbers, the set of complex numbers, and the set of quaternions, respectively. For any z ∈ H, we have the unique representation z = a1 + bi + cj + dk, where {1, i, j, k} is the basis of H. It is well-known that I is the multiplicative identity of H, and 12 = i2 = j 2 = k 2 = −1, ij = k, ki = j, jk = i, and ji = −k, ik = −j, kj = −i. For each z = a1 + bi + cj + dk ∈ H, define the conjugate z̄ of z by The Quaternion Matrix-Valued Young’s Inequality Renying Zeng z̄ = a1 − bi − cj − dk. Obviously we have z̄z = z z̄ = a2 + b2 + c2 + d2 . This implies that z̄z = z z̄ = 0 if and only if z = 0. So z is invertible in H if z 6= 0. We note that as subalgebras of H, the meaning of conjugate in R, or C is as usual (for any z ∈ R we have z̄ = z). We can consider R and C as real subalgebras of H : R={a1 : a ∈ R}, and C={a1 + bi : a, b ∈ R}. We define the real representation ρ of H, i.e., ρ : H → M4 (R) by a −b −c −d b a −d c , ρ(z) = ρ(a1 + bi + cj + dk) = c d a −b d −c b a Title Page Contents JJ J II I Go Back Close Quit Page 5 of 14 J. Ineq. Pure and Appl. Math. 6(3) Art. 89, 2005 where z = a1 + bi + cj + dk ∈ H. http://jipam.vu.edu.au Note that ρ(z̄) is the transpose of ρ(z). From the real representation ρ of H, we define a faithful representation by ρn : Mn (H) → M4n (R) as follows: ρ(A) = ρn ([qst ]ns,t=1 ) = ([ρ(qst )]ns,t=1 ) for all matrices A = [qst ]ns,t=1 ∈ Mn (H). We note that each ρn is an injective and homomorphism; and for all A ∈ Mn (H), ρn (A∗ ) = ρn (A)∗ . For the set Mn (F) of n × n matrices with entries from F, where F is R, C, or H, we use A∗ to denote the conjugate transpose of A ∈ Mn (F). We consider Mn (R) and Mn (H) as algebras over R, but Mn (C) as a complex algebra. Definition 2.1. The spectrum σ(A) of A ∈ Mn (F) is a subset of C that consists of all the roots of the minimal monic annihilating polynomial f of A. We note that if F = R or F = H, then f ∈ R[x]; but if F = H, then f ∈ C[x]. If F = R or F = C, then the spectrum σ(A) is the set of eigenvalues of A. But if F = H, then σ(A) is the set of eigenvalues of ρn (A). A is called Hermitian if A = A∗ . A is said to be nonnegative definite if A is Hermitian and σ(A) are all non-negative real numbers. A is said to be unitary if A∗ A = AA∗ = I, where I is the identity matrix in Mn (F). If A and B are Hermitian, we define A ≤ B or B ≥ A if B − A is nonnegative definite. The Quaternion Matrix-Valued Young’s Inequality Renying Zeng Title Page Contents JJ J II I Go Back Close Quit Page 6 of 14 J. Ineq. Pure and Appl. Math. 6(3) Art. 89, 2005 http://jipam.vu.edu.au For any Hermitian matrix A, λ1 (A) ≥ λ2 (A) ≥ · · · ≥ λn (A) are its eigenvalues, arranged in descending order; where the number of appearances of a particular eigenvalue λ is equal to the dimension of the kernel of A − λI and is known as the geometric multiplicity of λ. Lemma 2.1 ([1]). If A, B ∈ Mn (C), and if p, q ∈ (1, ∞) with there is a unitary U ∈ Mn (C) such that 1 p + 1 q = 1, then 1 1 U |AB ∗ |U ∗ ≤ |A|p + |B|q , p q where |A| denotes the nonnegative definite Hermitian matrix The Quaternion Matrix-Valued Young’s Inequality Renying Zeng 1 |A| = (A∗ A) 2 . Lemma 2.2 ([3]). Let Q ∈ Mn (H), then Q∗ Q is nonnegative definite. Furthermore, if A ∈ Mn (H) is nonnegative definite, then there are matrices U, D ∈ Mn (H) such that (i) U is unitary and D is diagonal matrix with nonnegative diagonal entries d1 , d2 , . . . , dn ; (ii) U ∗ AU = D; (iii) σ(A) = {d1 , d2 , . . . , dn }; (iv) If µ ∈ σ(A)appears tµ times on the diagonal of D , then the geometric multiplicity of µ as an eigenvalue of ρn (A)is 4tµ . Title Page Contents JJ J II I Go Back Close Quit Page 7 of 14 J. Ineq. Pure and Appl. Math. 6(3) Art. 89, 2005 Lemma 2.3. For any A, B ∈ Mn (H), http://jipam.vu.edu.au (i) ρn (|A|) = |ρn (A)|; (ii) ρn (|A|p ) = |ρn (A)|p for any nonnegative definite p; (iii) ρn (|AB|) = |ρn (A)ρn (B)|. 1 The meaning of |A| is similar to that in Lemma 2.1, i.e., |A| = (A∗ A) 2 . Proof. (i) Note that ρn : Mn (H) → M4n (R) is a homomorphism, if X ∈ Mn (H) is nonnegative definite, then there is a Y ∈ Mn (H) such that X = Y Y ∗ , so The Quaternion Matrix-Valued Young’s Inequality ρn (X) = ρn (Y ∗ Y ) = ρn (Y ∗ ) · ρn (Y ) = ρn (Y )∗ · ρn (Y ) = |ρn (Y )|2, Renying Zeng which means that ρn (X) is also nonnegative definite. Hence, for any X ∈ Mn (H) we have (since ρn is a homomorphism), Title Page 1 2 ρn (|X|) 2 1 1 = ρn (|X|) = ρn |X| 2 · |X| 2 2 1 = ρn |X| 2 1 1 So ρn (|X|) 2 = ρn |X| 2 . Therefore 1 . Contents JJ J II I Go Back 1 ρn (|A|) = (ρn (A∗ A)) 2 = (ρn (A∗ )ρn (A)) 2 = |ρn (A)|. Close Quit We get (i). (ii) For any nonnegative definite p, ρn (|A|p ) = (ρn (|A|))p = |ρn (A)|p , Page 8 of 14 J. Ineq. Pure and Appl. Math. 6(3) Art. 89, 2005 http://jipam.vu.edu.au the first equality is because ρn : Mn (H) → M4n (R) is a homomorphism, and the second equality is from (i). (iii) Similar to (ii) we have ρn (|AB|) = |ρn (AB)| = |ρn (A)ρn (B)|. The proof is complete. The following Theorem 2.4 is one of our main results. Theorem 2.4. For any A, B ∈ Mn (H), any p, q ∈ (1, ∞) with p1 + 1q = 1, there is a unitary U ∈ Mn (H), such that 1 1 U |AB ∗ |U ∗ ≤ |A|p + |B|q . p q Proof. By Lemma 2.3 ρn (|AB ∗ |) = |ρn (A)ρn (B)∗ |, and 1 p 1 q 1 1 ρn |A| + |B| = |ρn (A)|p + |ρn (B)|q . p q p q Because real n × n matrices |ρn (A)ρn (B)∗ | and p1 |ρn (A)|p + 1q |ρn (B)|q are nonnegative definite, from Linear Algebra there are n × n unitary matrices V, W ∈ Mn (C) such that 1 1 ∗ ∗ p q V |ρn (A)ρn (B) |V = C and W |ρn (A)| + |ρn (B)| W ∗ = D, p q The Quaternion Matrix-Valued Young’s Inequality Renying Zeng Title Page Contents JJ J II I Go Back Close Quit Page 9 of 14 J. Ineq. Pure and Appl. Math. 6(3) Art. 89, 2005 where C and D are diagonal matrices in M4n (R). http://jipam.vu.edu.au Thus from Lemma 2.2(iv) one has C = C1 ⊕ C2 ⊕ · · · ⊕ Cn and D = D1 ⊕ D2 ⊕ · · · ⊕ Dn with Cs = diag{cs , cs , . . . , cs } and Ds = diag{ds , ds , . . . , ds }, where cs and ds are nonnegative real numbers, s = 1, 2, . . . , n. By Lemma 2.2 (iii) we have σ(|AB ∗ |) = {c1 , c2 , . . . , cs } and 1 1 σ |ρn (A)|p + |ρn (B)|q p q Furthermore, Lemma 2.2 implies that = {d1 , d2 , . . . , dn }. C = C1 ⊕ C2 ⊕ · · · ⊕ Cn ≤ D = D1 ⊕ D2 ⊕ · · · ⊕ Dn . Hence the equation above and Lemma 2.3 yield that diag{c1 , c2 , . . . , cn } ≤ diag{d1 , d2 , . . . , dn }. Thus from Lemma 2.2 (i) (ii) (iii) there are unitary matrices U1 , U2 ∈ Mn (H) such that 1 p 1 q ∗ ∗ U1 |AB |U1 ≤ U2 |A| + |B| U2∗ , p q then there is a unitary matrix U ∈ Mn (H) for which 1 1 U |AB ∗ |U ∗ ≤ |A|p + |B|q . p q The proof is complete. The Quaternion Matrix-Valued Young’s Inequality Renying Zeng Title Page Contents JJ J II I Go Back Close Quit Page 10 of 14 J. Ineq. Pure and Appl. Math. 6(3) Art. 89, 2005 http://jipam.vu.edu.au 3. The Case of Equality Hirzallah and Kittaneh [4] proved a result as follows. Lemma 3.1. Let A, B ∈ Mn (C) be nonnegative definite. If p, q ∈ (1, ∞) with 1 + 1q = 1, and if there exists unitary U ∈ Mn (C) such that p 1 1 U |AB|U ∗ = Ap + B q p q then B = Ap−1 . The Quaternion Matrix-Valued Young’s Inequality We have the following result. Renying Zeng 1 p 1 q Theorem 3.2. For any A, B ∈ Mn (H), any p, q ∈ (1, ∞) with + = 1, there is a unitary U ∈ Mn (H) such that (3.1) 1 1 U |AB ∗ |U ∗ = |A|p + |B|q p q Contents JJ J if and only if |B| = |A|p−1 . Proof. The sufficiency. In fact, if |B| = |A|p−1 then p−1 |ρn (B)| = ρn (|B|) = ρn (|A| Title Page II I Go Back p−1 ) = |ρn (A)| . Write X = ρn (A), Y = ρn (B). Suppose X = V |X|, Y = W |Y | are the polar decomposition of X, Y respectively, where V, W are 4n × 4n unitary complex matrices. Then from (3.1) we have |XY ∗ | = W ||X||Y ||W ∗ = W |X|p W ∗ . Close Quit Page 11 of 14 J. Ineq. Pure and Appl. Math. 6(3) Art. 89, 2005 http://jipam.vu.edu.au Simply computation yields 1 1 |X|p + |Y |q = |X|p . p q So 1 1 W ∗ |XY ∗ |W = |X|p + |Y |q . p q Since W is a unitary, using the notations in Theorem 2.4, this implies C = C1 ⊕ C2 ⊕ · · · ⊕ Cn = D = D1 ⊕ D2 ⊕ · · · ⊕ Dn . The Quaternion Matrix-Valued Young’s Inequality Renying Zeng Hence Lemma 2.2 yields that diag{c1 , c2 , . . . , cn } = diag{d1 , d2 , . . . , dn }. Again, by Lemma 2.2, there is a unitary U ∈ Mn (H) such that 1 1 U |AB ∗ |U ∗ = |A|p + |B|q . p q Title Page Contents JJ J II I Go Back The necessity. Assume there exists unitary U ∈ Mn (H) such that (3.1) holds, i.e. 1 1 U |AB ∗ |U ∗ = |A|p + |B|q . p q Then 1 p 1 q ∗ ∗ |A| + |B| . ρn (U |AB |U ) = ρn p q Close Quit Page 12 of 14 J. Ineq. Pure and Appl. Math. 6(3) Art. 89, 2005 http://jipam.vu.edu.au Writing X = ρn (A), Y = ρn (B), and T = ρn (U ), one gets 1 1 T |XY ∗ |T ∗ = |X|p + |Y |q . p q This and Lemma 3.1 imply that 1 |Y | = (|X|p ) q = |X|, which means p−1 ρn (|B|) = ρn (|A|) p−1 = ρn (|A| ). Therefore (note that ρn : Mn (H) → M4n (R) is a faithful representation) |B| = |A|p−1 . This completes the proof. The Quaternion Matrix-Valued Young’s Inequality Renying Zeng Title Page Contents JJ J II I Go Back Close Quit Page 13 of 14 J. Ineq. Pure and Appl. Math. 6(3) Art. 89, 2005 http://jipam.vu.edu.au References [1] T. ANDO, Matrix Young’s inequality, Oper. Theory Adv. Appl., 75 (1995), 33–38. [2] R. BHATIA AND F. KITTANEH, On the singular values of a product of operators, SIAM J. Matrix Anal. Appl., 11 (1990), 272–277. [3] J.L. BRENNER, Matrices of quaternion, Pacific J. Math., 1 (1951), 329– 335. [4] O. HIRZALLAH AND F. KITTANEH, Matrix Young inequalities for the Hilbert-Schmidt norm, Linear Algebra and Application, 308 (2000), 77– 84. [5] R.C. THOMPSON, Matrix-valued triangle inequality: quaternion version, Linear and Multilinear Algebra, 25 (1989), 85–91 [6] R.C. THOMPSON, The case of equality in the matrix-valued triangle inequality, Pacific J. of Math., 82 (1979), 279–280. [7] R.C. THOMPSON, Convex and concave functions of singular values of matrix sums, Pacific J. Math., 66 (1976), 285–290. The Quaternion Matrix-Valued Young’s Inequality Renying Zeng Title Page Contents JJ J II I Go Back Close [8] J. ERLIJMAN, D.R. FARENICK AND R. ZENG, Young’s inequality in compact operators, Oper. Theory. Adv. and Appl., 130 (2001), 171–184. Quit Page 14 of 14 J. Ineq. Pure and Appl. Math. 6(3) Art. 89, 2005 http://jipam.vu.edu.au