Journal of Inequalities in Pure and Applied Mathematics A GRUSS TYPE INEQUALITY FOR SEQUENCES OF VECTORS IN INNER PRODUCT SPACES AND APPLICATIONS volume 1, issue 2, article 12, 2000. S.S. DRAGOMIR School of Communications and Informatics Victoria University of Technology PO Box 14428 Melbourne City MC 8001 Victoria, Australia EMail: sever@matilda.vu.edu.au URL: http://rgmia.vu.edu.au/SSDragomirWeb.html Received 5 February, 2000; accepted 29 February, 2000. Communicated by: B. Mond Abstract Contents JJ J II I Home Page Go Back Close c 2000 Victoria University ISSN (electronic): 1443-5756 002-00 Quit Abstract A Grüss type inequality for sequences of vectors in inner product spaces which complement a recent result from [6] and applications for differentiable convex functions defined on inner product spaces and applications for Fourier and Mellin transforms, are given. 2000 Mathematics Subject Classification: 26D15, 26D99, 46Cxx Key words: Grüss’ Inequality, Inner Product Spaces. Contents A Grüss Type Inequality for Sequences of Vectors in Inner Product Spaces and Applications S.S. Dragomir 1 Introduction . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 3 2 Preliminary Results . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 6 3 A Discrete Inequality of Grüss Type . . . . . . . . . . . . . . . . . . . . . 11 4 Applications for Convex Functions . . . . . . . . . . . . . . . . . . . . . . 17 5 Applications for Some Discrete Transforms . . . . . . . . . . . . . . 21 References Title Page Contents JJ J II I Go Back Close Quit Page 2 of 25 J. Ineq. Pure and Appl. Math. 1(2) Art. 12, 2000 http://jipam.vu.edu.au 1. Introduction In 1935, G. Grüss proved the following integral inequality (see [11] or [12]) Z b Z b Z b 1 1 1 (1.1) f (x) g (x) dx − f (x) dx · g (x) dx b−a a b−a a b−a a 1 ≤ (Φ − φ) (Γ − γ) , 4 provided that f and g are two integrable functions on [a, b] and satisfy the condition (1.2) φ ≤ f (x) ≤ Φ and γ ≤ g (x) ≤ Γ for all x ∈ [a, b] . A Grüss Type Inequality for Sequences of Vectors in Inner Product Spaces and Applications S.S. Dragomir The constant 1 4 is the best possible and is achieved for a+b f (x) = g (x) = sgn x − . 2 The discrete version of (1.1) states that: If a ≤ ai ≤ A, b ≤ bi ≤ B (i = 1, ..., n) where a, A, ai , b, B, bi are real numbers, then n n n 1 X 1 X 1 X 1 (1.3) ai b i − ai bi ≤ (A − a) (B − b) n 4 n n i=1 i=1 i=1 and the constant 41 is the best possible. In the recent paper [2], the author proved the following generalisation in inner product spaces. Title Page Contents JJ J II I Go Back Close Quit Page 3 of 25 J. Ineq. Pure and Appl. Math. 1(2) Art. 12, 2000 http://jipam.vu.edu.au Theorem 1.1. Let (X; h·, ·i) be an inner product space over K, K = C, R, and e ∈ X, kek = 1. If φ, Φ, γ, Γ ∈ K and x, y ∈ X such that Re hΦe − x, x − φei ≥ 0 and Re hΓe − y, y − γei ≥ 0 (1.4) holds, then we have the inequality |hx, yi − hx, ei he, yi| ≤ (1.5) The constant 1 4 1 |Φ − φ| |Γ − γ| . 4 is the best possible. It has been shown in [1] that the above theorem, for the real case, contains the usual integral and discrete Grüss inequality and also some Grüss type inequalities for mappings defined on infinite intervals. Namely, +∞) is a probability density funcR ∞if ρ : (−∞, +∞) →1 (−∞, 1 2 tion, i.e., −∞ ρ (t) dt = 1, then ρ 2 ∈ L (−∞, ∞) and obviously kρ 2 k2 = 1. Consequently, if we assume that f, g ∈ L2 (−∞, ∞) and 1 2 1 2 1 2 αρ ≤ f ≤ ψρ , βρ ≤ g ≤ θρ (1.6) 1 2 a.e. on (0, ∞) , then we have the inequality (1.7) Z ∞ −∞ A Grüss Type Inequality for Sequences of Vectors in Inner Product Spaces and Applications S.S. Dragomir Title Page Contents JJ J II I Go Back Z ∞ f (t) g (t) dt − 1 2 Z ∞ f (t) ρ (t) dt −∞ −∞ g (t) ρ (t) dt 1 2 ≤ 1 (ψ − α) (θ − β) . 4 Close Quit Page 4 of 25 J. Ineq. Pure and Appl. Math. 1(2) Art. 12, 2000 http://jipam.vu.edu.au In a similar way, if e = (ei )i∈N ∈ l2 (R) with P i∈N |ei |2 = 1 and x = (xi )i∈N , y = (yi )i∈N ∈ l2 (R) are such that (1.8) αei ≤ xi ≤ ψei , βei ≤ yi ≤ θei for all i ∈ N, then we have X 1 X X (1.9) xi yi − xi ei yi ei ≤ (ψ − α) (θ − β) . 4 i∈N i∈N i∈N In the recent paper [6], the author also proved the following discrete inequality in inner product spaces: n n n 1 X X X p a x − p a p x |A − a| kX − xk (1.10) i i i i i i i ≤ 4 i=1 i=1 i=1 provided xi ∈ H, ai ∈ K (K = C, R) and a, A ∈ K, x, X ∈ H are such that (1.11) Re [(A − ai ) (āi − ā)] ≥ 0 and Re hX − xi , xi − xi ≥ 0 for all i ∈ {1, ..., n} . The constant 41 is sharp. For other recent developments of the Grüss inequality, see the papers [1]-[6], [10] and the website http://rgmia.vu.edu.au/Gruss.html In this paper we point out some other Grüss type inequalities in inner product spaces which will complement the above result (1.10). A Grüss Type Inequality for Sequences of Vectors in Inner Product Spaces and Applications S.S. Dragomir Title Page Contents JJ J II I Go Back Close Quit Page 5 of 25 J. Ineq. Pure and Appl. Math. 1(2) Art. 12, 2000 http://jipam.vu.edu.au 2. Preliminary Results The following lemma is of interest in itself (see also [6]). Lemma 2.1. Let (H; h·, ·i) be an inner product space over the real or complex n P number field K, xi ∈ H and pi ≥ 0 (i = 1, ..., n) such that pi = 1 (n ≥ 2). i=1 If x, X ∈ H are such that Re hX − xi , xi − xi ≥ 0 for all i ∈ {1, ..., n} , (2.1) then we have the inequality 0≤ (2.2) n X i=1 The constant 1 4 2 n X 1 pi kxi k − pi xi ≤ kX − xk2 . 4 i=1 2 is sharp. A Grüss Type Inequality for Sequences of Vectors in Inner Product Spaces and Applications S.S. Dragomir Title Page Proof. Define Contents * I1 := X− n X i=1 and I2 := n X pi xi , n X + JJ J pi xi − x i=1 II I Go Back pi hX − xi , xi − xi . Close i=1 Then Quit 2 n n n X X X I1 = pi hX, xi i − hX, xi − pi xi + pi hxi , xi i=1 i=1 i=1 Page 6 of 25 J. Ineq. Pure and Appl. Math. 1(2) Art. 12, 2000 http://jipam.vu.edu.au and I2 = n X pi hX, xi i − hX, xi − i=1 n X 2 pi kxi k + i=1 n X pi hxi , xi . i=1 Consequently I1 − I2 = (2.3) n X i=1 n 2 X pi kxi k2 − pi xi . i=1 Taking the real value in (2.3) we can state (2.4) 2 n X pi kxi k − pi xi i=1 i=1 * + n n n X X X = Re X − pi xi , pi xi − x − pi Re hX − xi , xi − xi , n X 2 i=1 i=1 i=1 i=1 S.S. Dragomir Title Page Contents i=1 which is an identity of interest in itself. Using the assumption (2.1), we can conclude, by (2.4), that 2 * + n n n n X X X X (2.5) pi kxi k2 − pi xi ≤ Re X − pi xi , pi xi − x . i=1 A Grüss Type Inequality for Sequences of Vectors in Inner Product Spaces and Applications i=1 JJ J II I Go Back Close Quit It is known that if y, z ∈ H, then Page 7 of 25 (2.6) 2 4 Re hz, yi ≤ kz + yk , J. Ineq. Pure and Appl. Math. 1(2) Art. 12, 2000 http://jipam.vu.edu.au with equality iff z = y. Now, by (2.6), we can state that * + n n X X pi xi , pi xi − x Re X − i=1 i=1 2 n n X X 1 1 pi xi + pi xi − x = kX − xk2 . ≤ X − 4 4 i=1 i=1 Using (2.5), we can easily deduce (2.2). To prove the sharpness of the constant 14 , let us assume that the inequality (2.2) holds with a constant c > 0, i.e., 2 n n X X 2 (2.7) 0≤ pi kxi k − pi xi ≤ c kX − xk2 i=1 i=1 for all pi , xi and x, X as in the hypothesis of Lemma 2.1. Assume that n = 2, p1 = p2 = 12 , x1 = x and x2 = X with x, X ∈ H and x 6= X. Then, obviously, hX − x1 , x1 − xi = hX − x2 , x2 − xi = 0, which shows that the condition (2.1) holds. If we replace n, p1 , p2 , x1 , x2 in (2.7), we obtain 2 ! 2 2 X X x + X 2 1 2 2 2 pi kxi k − pi xi = kxk + kXk − 2 2 i=1 i=1 kX − xk2 = ≤ c kX − xk2 , 4 A Grüss Type Inequality for Sequences of Vectors in Inner Product Spaces and Applications S.S. Dragomir Title Page Contents JJ J II I Go Back Close Quit Page 8 of 25 J. Ineq. Pure and Appl. Math. 1(2) Art. 12, 2000 http://jipam.vu.edu.au from where we deduce c ≥ 14 , which proves the sharpness of the constant factor 1 . 4 Remark 2.1. The assumption (2.1) can be replaced by the more general condition n X (2.8) pi Re hX − xi , xi − xi ≥ 0 i=1 A Grüss Type Inequality for Sequences of Vectors in Inner Product Spaces and Applications and the conclusion (2.2) will still remain valid. The following corollary is natural. Corollary 2.2. Let ai ∈ K, pi ≥ 0 (i = 1, ..., n) (n ≥ 2) with n P pi = 1. If i=1 a, A ∈ K are such that Title Page Re [(A − ai ) (āi − ā)] ≥ 0 for all i ∈ {1, ..., n} , (2.9) then we have the inequality 0≤ (2.10) n X i=1 The constant 1 4 S.S. Dragomir 2 n X 1 pi |ai | − pi ai ≤ |A − a|2 . 4 i=1 2 is sharp. The proof follows by the above Lemma 2.1 by choosing H = K, hx, yi := xȳ, xi = ai , x = a, X = A. We omit the details. Contents JJ J II I Go Back Close Quit Page 9 of 25 J. Ineq. Pure and Appl. Math. 1(2) Art. 12, 2000 http://jipam.vu.edu.au Remark 2.2. The condition (2.9) can be replaced by the more general assumption n X (2.11) pi Re [(A − ai ) (āi − ā)] ≥ 0. i=1 Remark 2.3. If we assume that K = R, then (2.8) is equivalent with a ≤ ai ≤ A for all i ∈ {1, ..., n} (2.12) and then, with the assumption (2.12), we get the discrete Grüss type inequality !2 n n X X 1 2 (2.13) 0≤ p i ai − p i ai ≤ (A − a)2 4 i=1 i=1 A Grüss Type Inequality for Sequences of Vectors in Inner Product Spaces and Applications S.S. Dragomir Title Page and the constant 1 4 is sharp. Contents JJ J II I Go Back Close Quit Page 10 of 25 J. Ineq. Pure and Appl. Math. 1(2) Art. 12, 2000 http://jipam.vu.edu.au 3. A Discrete Inequality of Grüss Type The following Grüss type inequality holds. Theorem 3.1. Let (H; h·, ·i) be an inner product space over K; K = C, R, n P xi , yi ∈ H, pi ≥ 0 (i = 0, ..., n) (n ≥ 2) with pi = 1. If x, X, y, Y ∈ H are i=1 such that (3.1) Re hX − xi , xi − xi ≥ 0 and Re hY − yi , yi − yi ≥ 0 for all i ∈ {1, ..., n} , then we have the inequality + * n n n 1 X X X pi yi ≤ kX − xk kY − yk . pi xi , (3.2) pi hxi , yi i − 4 i=1 i=1 i=1 The constant 1 4 S.S. Dragomir Title Page is sharp. Contents Proof. A simple calculation shows that * n + n n n X X X 1X pi hxi , yi i − pi xi , pi yi = (3.3) pi pj hxi − xj , yi − yj i . 2 i=1 i=1 i=1 i,j=1 Taking the modulus in both parts of (3.3), and using the generalized triangle inequality, we obtain (3.4) * n + n n n X 1X X X pi hxi , yi i − pi xi , pi yi ≤ pi pj |hxi − xj , yi − yj i| . 2 i=1 A Grüss Type Inequality for Sequences of Vectors in Inner Product Spaces and Applications i=1 i=1 i,j=1 JJ J II I Go Back Close Quit Page 11 of 25 J. Ineq. Pure and Appl. Math. 1(2) Art. 12, 2000 http://jipam.vu.edu.au By Schwartz’s inequality in inner product spaces we have (3.5) |hxi − xj , yi − yj i| ≤ kxi − xj k kyi − yj k for all i, j ∈ {1, ..., n} , and therefore (3.6) * n + n n n X 1X X X pi pj kxi − xj k kyi − yj k . pi hxi , yi i − pi xi , pi yi ≤ 2 i,j=1 i=1 i=1 i=1 Using the Cauchy-Buniakowsky-Schwartz inequality for double sums, we can state that (3.7) n 1X pi pj kxi − xj k kyi − yj k 2 i,j=1 ≤ n 1X pi pj kxi − xj k2 2 i,j=1 S.S. Dragomir ! 12 × n 1X pi pj kyi − yj k2 2 i,j=1 and, a simple calculation shows that, 2 n n n X X 1X pi pj kxi − xj k2 = pi kxi k2 − pi xi 2 i,j=1 i=1 i=1 and A Grüss Type Inequality for Sequences of Vectors in Inner Product Spaces and Applications ! 12 Title Page Contents JJ J II I Go Back Close Quit 2 n n n X X 1X pi pj kyi − yj k2 = pi kyi k2 − pi yi . 2 i,j=1 i=1 i=1 Page 12 of 25 J. Ineq. Pure and Appl. Math. 1(2) Art. 12, 2000 http://jipam.vu.edu.au We obtain n + * n n X X X (3.8) pi hxi , yi i − pi xi , pi yi i=1 i=1 i=1 2 12 2 21 n n n n X X X X 2 2 × pi kyi k − pi yi . ≤ pi kxi k − pi xi i=1 i=1 i=1 i=1 Using Lemma 2.1, we know that n X i=1 2 12 n X 1 pi kxi k2 − pi xi ≤ kX − xk 2 i=1 A Grüss Type Inequality for Sequences of Vectors in Inner Product Spaces and Applications S.S. Dragomir Title Page and 2 21 n n X X 1 pi kyi k2 − pi yi ≤ kY − yk . 2 i=1 i=1 Therefore, by (3.8) we may deduce the desired inequality (3.3). To prove the sharpness of the constant 14 , let us assume that (3.2) holds with a constant c > 0, i.e., + * n n n X X X (3.9) p hx , y i − p x , p y i i i i i i i ≤ c kX − xk kY − yk i=1 i=1 i=1 under the above assumptions for pi , xi , yi , x, X, y, Y and n ≥ 2. Contents JJ J II I Go Back Close Quit Page 13 of 25 J. Ineq. Pure and Appl. Math. 1(2) Art. 12, 2000 http://jipam.vu.edu.au If we choose n = 2, x1 = x, x2 = X, y1 = y, y2 = Y (x 6= X, y 6= Y ) and p1 = p2 = 21 , then * 2 + 2 2 2 X X X 1X pi hxi , yi i − pi xi , pi yi = pi pj hxi − xj , yi − yj i 2 i=1 i=1 i=1 i,j=1 X = pi pj hxi − xj , yi − yj i 1≤i<j≤2 = 1 hx − X, y − Y i 4 and then * 2 + 2 2 X 1 X X pi hxi , yi i − pi xi , pi yi = |hx − X, y − Y i| . 4 i=1 i=1 i=1 Choose X − x = z, Y − y = z, z 6= 0. Then using (3.9), we derive 1 kzk2 ≤ c kzk2 , z 6= 0 4 which implies that c ≥ 14 , and the theorem is proved. Remark 3.1. The condition (3.1) can be replaced by the more general assumption (3.10) n X pi Re hX − xi , xi − xi ≥ 0, i=1 n X i=1 pi Re hY − yi , yi − yi ≥ 0 A Grüss Type Inequality for Sequences of Vectors in Inner Product Spaces and Applications S.S. Dragomir Title Page Contents JJ J II I Go Back Close Quit Page 14 of 25 and the conclusion (3.2) still remains valid. J. Ineq. Pure and Appl. Math. 1(2) Art. 12, 2000 http://jipam.vu.edu.au The following corollary for real or complex numbers holds. Corollary 3.2. Let ai , bi ∈ K (K = C, R) , pi ≥ 0 (i = 1, ..., n) with Re [(A − ai ) (āi − ā)] ≥ 0 and pi = 1. i=1 If a, A, b, B ∈ K are such that (3.11) n P Re (B − bi ) b̄i − b̄ ≥ 0, then we have the inequality n n n X 1 X X (3.12) pi ai b̄i − p i ai pi b̄i ≤ |A − a| |B − b| 4 i=1 i=1 i=1 and the constant 1 4 S.S. Dragomir is sharp. The proof is obvious by Theorem 3.1 applied for the inner product space (C, h·, ·i) where hx, yi = x · ȳ. We omit the details. Remark 3.2. The condition (3.11) can be replaced by the more general condition (3.13) n X i=1 pi Re [(A − ai ) (āi − ā)] ≥ 0, n X pi Re (B − bi ) b̄i − b̄ ≥ 0 i=1 and the conclusion of the above corollary will still remain valid. Remark 3.3. If we assume that ai , bi , a, b, A, B are real numbers, then (3.11) is equivalent to (3.14) A Grüss Type Inequality for Sequences of Vectors in Inner Product Spaces and Applications a ≤ ai ≤ A, b ≤ bi ≤ B for all i ∈ {1, ..., n} Title Page Contents JJ J II I Go Back Close Quit Page 15 of 25 J. Ineq. Pure and Appl. Math. 1(2) Art. 12, 2000 http://jipam.vu.edu.au and (3.12) becomes n n n X 1 X X (3.15) 0≤ p i ai b i − p i ai pi bi ≤ (A − a) (B − b) , 4 i=1 i=1 i=1 which is the classical Grüss inequality for sequences of real numbers. A Grüss Type Inequality for Sequences of Vectors in Inner Product Spaces and Applications S.S. Dragomir Title Page Contents JJ J II I Go Back Close Quit Page 16 of 25 J. Ineq. Pure and Appl. Math. 1(2) Art. 12, 2000 http://jipam.vu.edu.au 4. Applications for Convex Functions Let (H; h·, ·i) be a real inner product space and F : H → R a Fréchet differentiable convex mapping on H. Then we have the “gradient inequality” F (x) − F (y) ≥ h∇F (y) , x − yi (4.1) for all x, y ∈ H, where ∇F : H → H is the gradient operator associated to the differentiable convex function F . The following theorem holds. Theorem 4.1. Let F : H → R be as above and xi ∈ H (i = 1, ..., n). Suppose that there exists the vectors γ, φ ∈ H such that hxi − γ, φ − xi i ≥ 0 for all i ∈ {1, ..., m} and m, M ∈ H such that h∇F (xi ) − m, M − ∇F (xi )i ≥ 0 m P for all i ∈ {1, ..., m}. Then for all pi ≥ 0 (i = 1, ..., m) with Pm := pi > 0, i=1 A Grüss Type Inequality for Sequences of Vectors in Inner Product Spaces and Applications S.S. Dragomir Title Page we have the inequality Contents (4.2) m 1 X 0≤ pi F (xi ) − F Pm i=1 Proof. Choose in (4.1), x = (4.3) F m 1 X pi xi Pm i=1 1 PM m P m 1 X pi xi Pm i=1 ! ≤ 1 kφ − γk kM − mk . 4 Close * − F (xj ) ≥ II I Go Back pi xi and y = xj to obtain i=1 ! JJ J m 1 X ∇F (xj ) , pi xi − xj Pm i=1 + Quit Page 17 of 25 for all j ∈ {1, ..., n}. J. Ineq. Pure and Appl. Math. 1(2) Art. 12, 2000 http://jipam.vu.edu.au If we multiply (4.3) by pj ≥ 0 and sum over j from 1 to m, we have Pm F m 1 X pi xi Pm i=1 ! − m X pj F (xj ) j=1 + * m m m X X 1 X ≥ pj ∇F (xj ) , pi xi − h∇F (xi ) , xi i . Pm j=1 i=1 i=1 Dividing by Pm > 0, we obtain the inequality (4.4) m 1 X 0 ≤ pi F (xi ) − F Pm i=1 m 1 X pi xi Pm i=1 ! A Grüss Type Inequality for Sequences of Vectors in Inner Product Spaces and Applications S.S. Dragomir m 1 X ≤ pi h∇F (xi ) , xi i Pm i=1 + * m m 1 X 1 X − pi ∇F (xi ) , pi xi Pm i=1 Pm i=1 which is a generalisation for the case of inner product spaces of the result by Dragomir and Goh established in 1996 for the case of differentiable mappings defined on Rn [9]. Applying Theorem 3.1 for real inner product spaces, X = φ, x = γ, yi = Title Page Contents JJ J II I Go Back Close Quit Page 18 of 25 J. Ineq. Pure and Appl. Math. 1(2) Art. 12, 2000 http://jipam.vu.edu.au ∇F (xi ), y = m, Y = M and n = m, we easily deduce * + m m m 1 X 1 X 1 X (4.5) pi hxi , ∇F (xi )i − pi xi , pi ∇F (xi ) Pm i=1 Pm i=1 Pm i=1 1 kΦ − φk kM − mk 4 and then, by (4.4) and (4.5) we can conclude that the desired inequality (4.2) holds. ≤ Remark 4.1. The conditions (4.6) hxi − γ, φ − xi i ≥ 0, h∇F (xi ) − m, M − ∇F (xi )i ≥ 0, for all i ∈ {1, ..., m} can be replaced by the more general conditions (4.7) m m X X pi hxi − γ, φ − xi i ≥ 0 and pi h∇F (xi ) − m, M − ∇F (xi )i ≥ 0 i=1 i=1 and the conclusion (4.2) will still be valid. Remark 4.2. Even if the inequality (4.2) is not as sharp as (4.4), it can be more useful in practice when only some bounds of the gradient operator ∇F and of the vectors xi (i = 1, ..., n) are known. In other words, it provides the opportunity to estimate the difference ! m m 1 X 1 X ∆ (F, x, p) := pi F (xi ) − F pi xi , Pm i=1 Pm i=1 A Grüss Type Inequality for Sequences of Vectors in Inner Product Spaces and Applications S.S. Dragomir Title Page Contents JJ J II I Go Back Close Quit Page 19 of 25 where the differences kφ − γk and kM − mk are known. J. Ineq. Pure and Appl. Math. 1(2) Art. 12, 2000 http://jipam.vu.edu.au Remark 4.3. For example, if we know that h∇F (xi ) − m, M − ∇F (xi )i ≥ 0 for all i ∈ {1, ..., m} and the vectors xi (i = 1, ..., n) are not too far from each other in the sense that hxi − γ, φ − xi i ≥ 0 for all i ∈ {1, ..., m} and (ε > 0), then by (4.2), we can conclude that kφ − γk ≤ kM4ε −mk 0 ≤ ∆ (F, x, p) ≤ ε. A Grüss Type Inequality for Sequences of Vectors in Inner Product Spaces and Applications S.S. Dragomir Title Page Contents JJ J II I Go Back Close Quit Page 20 of 25 J. Ineq. Pure and Appl. Math. 1(2) Art. 12, 2000 http://jipam.vu.edu.au 5. Applications for Some Discrete Transforms Let (H; h·, ·i) be an inner product space over K, K = C, R and x̄ = (x1 , ..., xn ) be a sequence of vectors in H. For a given m ∈ K, define the discrete Fourier transform (5.1) Fw (x̄) (m) = n X exp (2wimk) × xk , m = 1, ..., n. k=1 The complex number n P exp (2wimk) hxk , yk i is actually the usual Fourier k=1 transform of the vector (hx1 , y1 i , ..., hxn , yn i) ∈ Kn and will be denoted by (5.2) Fw (x̄ · ȳ) (m) = n X exp (2wimk) hxk , yk i , m = 1, ..., n. k=1 The following result holds. Theorem 5.1. Let x̄, ȳ ∈ H n be sequences of vectors such that there exists the vectors c, C, y, Y ∈ H with the properties (5.3) Re hC − exp (2wimk) xk , exp (2wimk) xk − ci ≥ 0, k, m = 1, ..., n A Grüss Type Inequality for Sequences of Vectors in Inner Product Spaces and Applications S.S. Dragomir Title Page Contents JJ J II I Go Back Close Quit and Page 21 of 25 (5.4) Re hY − yk , yk − yi ≥ 0, k = 1, ..., n. J. Ineq. Pure and Appl. Math. 1(2) Art. 12, 2000 http://jipam.vu.edu.au Then we have the inequality + * n n 1X (5.5) Fw (x̄ · ȳ) (m) − Fw (x̄) (m) , yk ≤ kC − ck kY − yk , 4 n k=1 for all m ∈ {1, ..., n}. The proof follows by Theorem 3.1 applied for pk = n1 and for the sequences xk → ck = exp (2wimk) xk and yk (k = 1, ..., n). We omit the details. We can also consider the Mellin transform (5.6) M (x̄) (m) := n X k m−1 xk , m = 1, ..., n, k=1 of the sequence x̄ = (x1 , ..., xn ) ∈ H n . We remark that the complex number k m−1 hxk , yk i is actually the Mellin k=1 M (x̄ · ȳ) (m) := Contents n transform of the vector (hx1 , y1 i , ..., hxn , yn i) ∈ K and will be denoted by (5.7) S.S. Dragomir Title Page n P n X A Grüss Type Inequality for Sequences of Vectors in Inner Product Spaces and Applications k m−1 hxk , yk i . k=1 The following theorem holds. Theorem 5.2. Let x̄, ȳ ∈ H n be sequences of vectors such that there exist the vectors d, D, y, Y ∈ H with the properties (5.8) Re D − k m−1 xk , k m−1 xk − d ≥ 0 JJ J II I Go Back Close Quit Page 22 of 25 J. Ineq. Pure and Appl. Math. 1(2) Art. 12, 2000 http://jipam.vu.edu.au for all k, m ∈ {1, ..., n} , and (5.4) is fulfilled. Then we have the inequality + * n n 1X yk ≤ kD − dk kY − yk (5.9) M (x̄ · ȳ) (m) − M (x̄) (m) , 4 n k=1 for all m ∈ {1, ..., n}. The proof follows by Theorem 3.1 applied for pk = n1 and for the sequences xk → dk = kxk and yk (k = 1, ..., n). We omit the details. Another result which connects the Fourier transforms for different parameters w also holds. A Grüss Type Inequality for Sequences of Vectors in Inner Product Spaces and Applications Theorem 5.3. Let x̄, ȳ ∈ H n and w, z ∈ K. If there exists the vectors e, E, f, F ∈ H such that S.S. Dragomir Re hE − exp (2wimk) xk , exp (2wimk) xk − ei ≥ 0, k, m = 1, ..., n Title Page Contents and Re hF − exp (2zimk) yk , exp (2zimk) yk − f i ≥ 0, k, m = 1, ..., n then we have the inequality: 1 1 1 1 Fw+z (x̄ · ȳ) (m) − Fw (x̄) (m) , Fz (ȳ) (m) ≤ kE − ek kF − f k , n n n 4 for all m ∈ {1, ..., n}. The proof follows by Theorem 3.1 for the sequences exp (2wimk) xk , exp (2zimk) yk (k = 1, ..., n). We omit the details. JJ J II I Go Back Close Quit Page 23 of 25 J. Ineq. Pure and Appl. Math. 1(2) Art. 12, 2000 http://jipam.vu.edu.au References [1] S.S. DRAGOMIR, Grüss inequality in inner product spaces, Austral. Math. Soc. Gazette, 26(2) (1999), 66–70. [2] S.S. DRAGOMIR, A generalization of Grüss’ inequality in inner product spaces and applications, J. Math. Anal. Appl., 237 (1999), 74–82. [3] S.S. DRAGOMIR, A Grüss type integral inequality for mappings of rHölder’s type and applications for trapezoid formula, Tamkang J. of Math., 31(1) (2000), 43–47. [4] S.S. DRAGOMIR, Some discrete inequalities of Grüss type and applications in guessing theory, Honam Math. J., 21(1) (1999), 115–126. [5] S.S. DRAGOMIR, Some integral inequalities of Grüss type, Indian J. of Pure and Appl. Math., 31(4) (2000), 397–415. [6] S.S. DRAGOMIR, A Grüss type discrete inequality in inner product spaces and applications, J. Math. Anal. Appl., (in press). [7] S.S. DRAGOMIR AND G.L. BOOTH, On a Grüss-Lupaş type inequality and its applications for the estimation of p-moments of guessing mappings, Math. Comm., (in press). [8] S.S. DRAGOMIR AND I. FEDOTOV, An inequality of Grüss’ type for Riemann-Stieltjes integral and applications for special means, Tamkang J. of Math., 29(4) (1998), 286–292. A Grüss Type Inequality for Sequences of Vectors in Inner Product Spaces and Applications S.S. Dragomir Title Page Contents JJ J II I Go Back Close Quit Page 24 of 25 J. Ineq. Pure and Appl. Math. 1(2) Art. 12, 2000 http://jipam.vu.edu.au [9] S.S. DRAGOMIR AND C.J. GOH, A counterpart of Jensen’s discrete inequality for differentiable convex mappings and applications in information theory, Mathl. Comput. Modelling, 24(2) (1996), 1–11. [10] A.M. FINK, A treatise on Grüss’ inequality, submitted. [11] G. RGRÜSS, Über das Maximum absoluten Betrages von Rb R des b b 1 1 f (x)g(x)dx − (b−a)2 a f (x)dx a g(x)dx, Math. Z., 39 (1935), b−a a 215–226. [12] D.S. MITRINOVIĆ, J.E. PEČARIĆ AND A.M. FINK, Classical and New Inequalities in Analysis, Kluwer Academic Publishers, Dordrecht, 1993. A Grüss Type Inequality for Sequences of Vectors in Inner Product Spaces and Applications S.S. Dragomir Title Page Contents JJ J II I Go Back Close Quit Page 25 of 25 J. Ineq. Pure and Appl. Math. 1(2) Art. 12, 2000 http://jipam.vu.edu.au