Journal of Inequalities in Pure and Applied Mathematics OSTROWSKI-GRÜSS TYPE INEQUALITIES IN TWO DIMENSIONS NENAD UJEVIĆ Department of Mathematics University of Split Teslina 12/III, 21000 Split CROATIA. EMail: ujevic@pmfst.hr volume 4, issue 5, article 101, 2003. Received 08 January, 2003; accepted 07 August, 2003. Communicated by: B.G. Pachpatte Abstract Contents JJ J II I Home Page Go Back Close c 2000 Victoria University ISSN (electronic): 1443-5756 003-03 Quit Abstract A general Ostrowski-Grüss type inequality in two dimensions is established. A particular inequality of the same type is also given. 2000 Mathematics Subject Classification: 26D10, 26D15. Key words: Ostrowski’s inequality, 2-dimensional generalization, Ostrowski-Grüss inequality. Contents Ostrowski-Grüss type Inequalities in Two Dimensions Nenad Ujević 1 Introduction . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 3 2 A General Ostrowski-Grüss Inequality . . . . . . . . . . . . . . . . . . . 4 3 A Particular Inequality . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 18 References Title Page Contents JJ J II I Go Back Close Quit Page 2 of 26 J. Ineq. Pure and Appl. Math. 4(5) Art. 101, 2003 http://jipam.vu.edu.au 1. Introduction In 1938 A. Ostrowski proved the following integral inequality ([17] or [16, p. 468]). Theorem 1.1. Let f : I → R, where I ⊂ R is an interval, be a mapping differentiable in the interior Int I of I, and let a, b ∈ Int I, a < b. If |f 0 (t)| ≤ M , ∀t ∈ [a, # b], then we have " Z b a+b 2 (x − ) 1 1 2 f (x) − (1.1) f (t)dt ≤ + (b − a)M, b−a a 4 (b − a)2 for x ∈ [a, b]. The first (direct) generalization of Ostrowski’s inequality was given by G.V. Milovanović and J. Pečarić in [14]. In recent years a number of authors have written about generalizations of Ostrowski’s inequality. For example, this topic is considered in [2], [4], [6], [9] and [14]. In this way, some new types of inequalities have been formed, such as inequalities of Ostrowski-Grüss type, inequalities of Ostrowski-Chebyshev type, etc. The first inequality of OstrowskiGrüss type was given by S.S. Dragomir and S. Wang in [6]. It was generalized and improved in [9]. X.L. Cheng gave a sharp version of the mentioned inequality in [4]. The first multivariate version of Ostrowski’s inequality was given by G.V. Milovanović in [12] (see also [13] and [16, p. 468]). Multivariate versions of Ostrowski’s inequality were also considered in [3], [7] and [11]. In this paper we give a general two-dimensional Ostrowski-Grüss inequality. For that purpose, we introduce specially defined polynomials, which can be considered as harmonic or Appell-like polynomials in two dimensions. In Section 3 we use the mentioned general inequality to obtain a particular two-dimensional Ostrowski-Grüss type inequality. Ostrowski-Grüss type Inequalities in Two Dimensions Nenad Ujević Title Page Contents JJ J II I Go Back Close Quit Page 3 of 26 J. Ineq. Pure and Appl. Math. 4(5) Art. 101, 2003 http://jipam.vu.edu.au 2. A General Ostrowski-Grüss Inequality Let Ω = [a, b] × [a, b] and let f : Ω → R be a given function. Here we suppose that f ∈ C 2n (Ω). Let Pk (s) and Qk (t) be harmonic or Appell-like polynomials, i.e. (2.1) Pk0 (s) = Pk−1 (s) and Q0k (t) = Qk−1 (t), k = 1, 2, . . . , n + 1, with P0 (s) = Q0 (t) = 1. (2.2) We also define (2.3) Rk (s, t) = Pk (s)Qk (t), k = 0, 1, 2, . . . , n + 1. Lemma 2.1. Let Rk (s, t) be defined by (2.3). Then we have (2.4) ∂ 2 Rk (s, t) = Rk−1 (s, t) ∂s∂t for k = 1, 2, . . . , n + 1. Proof. From (2.1) – (2.3) it follows that ∂ 2 Rk (s, t) ∂ ∂Rk (s, t) = ∂s∂t ∂t ∂s ∂ = (P 0 (s)Qk (t)) ∂t k = Pk−1 (s)Q0k (t) = Pk−1 (s)Qk−1 (t) = Rk−1 (s, t). Ostrowski-Grüss type Inequalities in Two Dimensions Nenad Ujević Title Page Contents JJ J II I Go Back Close Quit Page 4 of 26 J. Ineq. Pure and Appl. Math. 4(5) Art. 101, 2003 http://jipam.vu.edu.au We now define Z b ∂ 2k−1 f (b, t) ∂ 2k−1 f (a, t) (2.5) Jk = Rk (b, t) − Rk (a, t) dt, ∂sk−1 ∂tk ∂sk−1 ∂tk a ∂ k−1 f (b, t) ∂ k−1 f (a, t) , v (t) = , k−1 ∂sk−1 ∂sk−1 for k = 1, 2, . . . , n. We also define Z b Z b ∂ 2k−1 f (b, t) (k) (2.7) Jk,1 = Rk (b, t) dt = Pk (b) Qk (t)uk−1 (t)dt k−1 ∂tk ∂s a a (2.6) uk−1 (t) = Ostrowski-Grüss type Inequalities in Two Dimensions Nenad Ujević and Z (2.8) b Jk,2 = a ∂ 2k−1 f (a, t) dt = Pk (a) Rk (a, t) ∂sk−1 ∂tk b Z (k) Qk (t)vk−1 (t)dt a Contents such that JJ J Jk = Jk,1 − Jk,2 . (2.9) Lemma 2.2. Let Jk,1 be defined by (2.7). Then we have (2.10) Jk,1 = Pk (b) k X II I Go Back h i (j−1) (j−1) (−1)k−j Qj (b)uk−1 (b) − Qj (a)uk−1 (a) j=1 k Z + (−1) Pk (b) Close Quit Page 5 of 26 b uk−1 (t)dt, a for k = 1, 2, . . . , n. Title Page J. Ineq. Pure and Appl. Math. 4(5) Art. 101, 2003 http://jipam.vu.edu.au Proof. We introduce the notation b Z Uk (uk−1 ) = (k) Qk (t)uk−1 (t)dt. a Then we have k k Z b (−1) Uk (uk−1 ) = (−1) (k) Qk (t)uk−1 (t)dt ha i (k−1) (k−1) = (−1) Qk (b)uk−1 (b) − Qk (a)uk−1 (a) Z b (k−1) k−1 Qk−1 (t)uk−1 (t)dt. + (−1) k Ostrowski-Grüss type Inequalities in Two Dimensions Nenad Ujević a Title Page We can write the above relation in the form (−1)k Uk (uk−1 ) i h (k−1) (k−1) k = (−1) Qk (b)uk−1 (b) − Qk (a)uk−1 (a) + (−1)k−1 Uk−1 (uk−1 ). In a similar way we get k−1 (−1) Contents JJ J II I Go Back k−1 Uk−1 (uk−1 ) = (−1) Z b (k−1) Qk−1 (t)uk−1 (t)dt ha i (k−2) (k−2) = (−1)k−1 Qk−1 (b)uk−1 (b) − Qk−1 (a)uk−1 (a) Z b (k−2) k−2 + (−1) Qk−2 (t)uk−1 (t)dt a Close Quit Page 6 of 26 J. Ineq. Pure and Appl. Math. 4(5) Art. 101, 2003 http://jipam.vu.edu.au or (−1)k−1 Uk−1 (uk−1 ) h i (k−2) (k−2) = (−1)k−1 Qk−1 (b)uk−1 (b) − Qk−1 (a)uk−1 (a) + (−1)k−2 Uk−2 (uk−1 ). If we continue the above procedure then we obtain (−1)k Uk (uk−1 ) = k X Ostrowski-Grüss type Inequalities in Two Dimensions i h (j−1) (j−1) (−1)j Qj (b)uk−1 (b) − Qj (a)uk−1 (a) + U0 (uk−1 ) Nenad Ujević j=1 = k X j (−1) h (j−1) Qj (b)uk−1 (b) − i (j−1) Qj (a)uk−1 (a) b Z + uk−1 (t)dt. a j=1 Contents JJ J Note now that Jk,1 = Pk (b)Uk (uk−1 ) such that (2.10) holds. (2.11) Jk,2 = Pk (a) II I Go Back Lemma 2.3. Let Jk,2 be defined by (2.8). Then we have k X Title Page k−j (−1) h (j−1) Qj (b)vk−1 (b) − Close i (j−1) Qj (a)vk−1 (a) j=1 + (−1)k Pk (a) Z Page 7 of 26 b vk−1 (t)dt, a Quit J. Ineq. Pure and Appl. Math. 4(5) Art. 101, 2003 http://jipam.vu.edu.au for k = 1, 2, . . . , n. Proof. The proof is almost identical to that of Lemma 2.2. We now define Z b ∂Rk (s, b) ∂ 2k−2 f (s, b) ∂Rk (s, a) ∂ 2k−2 f (s, a) (2.12) Kk = − ds, ∂s ∂sk−1 ∂tk−1 ∂s ∂sk−1 ∂tk−1 a for k = 2, . . . , n, (2.13) xk−1 (s) = ∂ k−1 f (s, b) ∂ k−1 f (s, a) , y (s) = k−1 ∂tk−1 ∂tk−1 Nenad Ujević and b Z (2.14) Z x0 (s)ds − Q1 (a) K1 = Q1 (b) a b y0 (s)ds. Contents b ∂Rk (s, b) ∂ 2k−2 f (s, b) ds ∂s ∂sk−1 ∂tk−1 a Z b (k−1) = Qk (b) Pk−1 (s)xk−1 (s)ds Z Kk,1 = a and Kk,2 b ∂Rk (s, a) ∂ 2k−2 f (s, a) = ds ∂s ∂sk−1 ∂tk−1 a Z b (k−1) = Qk (a) Pk−1 (s)yk−1 (s)ds Z (2.16) Title Page a We also define (2.15) Ostrowski-Grüss type Inequalities in Two Dimensions a JJ J II I Go Back Close Quit Page 8 of 26 J. Ineq. Pure and Appl. Math. 4(5) Art. 101, 2003 http://jipam.vu.edu.au such that (2.17) Kk = Kk,1 − Kk,2 , k = 1, 2, . . . , n. Lemma 2.4. Let Kk,1 be defined by (2.15). Then we have (2.18) Kk,1 = Qk (b) k X h i (j−2) (j−2) (−1)k−j+1 Pj−1 (b)xk−1 (b) − Pj−1 (a)xk−1 (a) j=2 k−1 + (−1) Z Qk (b) b xk−1 (s)ds, a Ostrowski-Grüss type Inequalities in Two Dimensions Nenad Ujević for k = 2, . . . , n. Title Page Proof. We introduce the notation Contents b Z Uk−1 (xk−1 ) = (k−1) JJ J Pk−1 (s)xk−1 (s)ds. a Then we have II I Go Back (−1)k−1 Uk−1 (xk−1 ) = (−1)k−1 Z b (k−1) Close Pk−1 (s)xk−1 (s)ds a k−1 = (−1) h (k−2) Pk−1 (b)xk−1 (b) + (−1)k−2 Z b − i (k−2) Pk−1 (a)xk−1 (a) Page 9 of 26 (k−2) Pk−2 (s)xk−1 (s)ds. a Quit J. Ineq. Pure and Appl. Math. 4(5) Art. 101, 2003 http://jipam.vu.edu.au We can write the above relation in the form (−1)k−1 Uk−1 (xk−1 ) h i (k−2) (k−2) = (−1)k−1 Pk−1 (b)xk−1 (b) − Pk−1 (a)xk−1 (a) + (−1)k−2 Uk−2 (xk−1 ). In a similar way we get k−2 (−1) k−2 Uk−2 (xk−1 ) = (−1) Z b (k−2) Pk−2 (s)xk−1 (s)ds ha i (k−3) (k−3) = (−1) Pk−2 (b)xk−1 (b) − Pk−2 (a)xk−1 (a) Z b (k−3) k−3 Pk−3 (s)xk−1 (s)ds + (−1) k−2 a (−1)k−2 Uk−2 (xk−1 ) i h (k−3) (k−3) = (−1)k−2 Pk−2 (b)xk−1 (b) − Pk−2 (a)xk−1 (a) + (−1)k−3 Uk−3 (xk−1 ). If we continue the above procedure then we get (−1)k−1 Uk−1 (xk−1 ) k X j=2 Nenad Ujević Title Page Contents or = Ostrowski-Grüss type Inequalities in Two Dimensions h i (j−2) (j−2) (−1)j−1 Pj−1 (b)xk−1 (b) − Pj−1 (a)xk−1 (a) + U0 (xk−1 ) JJ J II I Go Back Close Quit Page 10 of 26 J. Ineq. Pure and Appl. Math. 4(5) Art. 101, 2003 http://jipam.vu.edu.au = k X j−1 (−1) h (j−2) Pj−1 (b)xk−1 (b) − i (j−2) Pj−1 (a)xk−1 (a) Z + b xk−1 (t)dt. a j=2 Note now that Kk,1 = Qk (b)Uk−1 (xk−1 ) such that (2.18) holds. Lemma 2.5. Let Kk,2 be defined by (2.16). Then we have (2.19) Kk,2 = Qk (a) k X Ostrowski-Grüss type Inequalities in Two Dimensions k−j+1 (−1) h (j−2) Pj−1 (b)yk−1 (b) − i (j−2) Pj−1 (a)yk−1 (a) Nenad Ujević j=2 k−1 + (−1) Z Qk (a) b yk−1 (s)ds, a for k = 2, . . . , n. Proof. The proof is almost identical to that of Lemma 2.4. Title Page Contents JJ J II I Let (X, h·, ·i) be a real inner product space and e ∈ X, kek = 1. Let γ, ϕ, Γ, Φ be real numbers and x, y ∈ X such that the conditions Go Back hΦe − x, x − ϕei ≥ 0 and hΓe − y, y − γei ≥ 0 Quit (2.20) Page 11 of 26 hold. In [5] we can find the inequality (2.21) |hx, yi − hx, ei hy, ei| ≤ Close 1 |Φ − ϕ| |Γ − γ| . 4 J. Ineq. Pure and Appl. Math. 4(5) Art. 101, 2003 http://jipam.vu.edu.au We also have (2.22) |hx, yi − hx, ei hy, ei| ≤ kxk2 − hx, ei2 12 kyk2 − he, yi2 12 . Let X = L2 (Ω) and e = 1/(b − a). If we define Z bZ b 1 (2.23) T (f, g) = f (t, s)g(t, s)dtds (b − a)2 a a Z bZ b Z bZ b 1 − f (t, s)dtds g(t, s)dtds, (b − a)4 a a a a then from (2.20) and (2.21) we obtain the Grüss inequality in L2 (Ω), 1 |T (f, g)| ≤ (Γ − γ)(Φ − ϕ), 4 (2.24) γ ≤ f (x, y) ≤ Γ, ϕ ≤ g(x, y) ≤ Φ, (x, y) ∈ Ω. T (f, g)2 ≤ T (f, f )T (g, g). II I Go Back We now define Z bZ b In = a a ∂ 2n f (s, t) dsdt Rn (s, t) ∂sn ∂tn Close Quit Page 12 of 26 and (2.27) Contents JJ J From (2.22), we have the pre-Grüss inequality (2.26) Nenad Ujević Title Page if (2.25) Ostrowski-Grüss type Inequalities in Two Dimensions Sn = 1 (b − a)2 Z bZ Z bZ b Rn (s, t)dsdt a a a a b ∂ 2n f (s, t) dsdt. ∂sn ∂tn J. Ineq. Pure and Appl. Math. 4(5) Art. 101, 2003 http://jipam.vu.edu.au Lemma 2.6. Let In and Sn be defined by (2.26) and (2.27), respectively. Then we have the inequality |In − Sn | ≤ (2.28) where M2n − m2n C(b − a)2 , 2 ∂ 2n f (s, t) ∂ 2n f (s, t) , m = min 2n (s,t)∈Ω ∂sn ∂tn (s,t)∈Ω ∂sn ∂tn M2n = max and (2.29) C = 1 (b − a)2 Z a b Pn (s)2 ds Z Ostrowski-Grüss type Inequalities in Two Dimensions b Qn (t)2 dt Nenad Ujević a 1 − (b − a)4 Z b Z Pn (s)ds a b 2 ) 12 . Qn (t)dt Contents Proof. From (2.23), (2.26) and (2.27) we see that ∂ 2n f (s, t) 2 . In − Sn = (b − a) T Rn (s, t), ∂sn ∂tn JJ J II I Go Back Then from (2.25) we get 2 Title Page a 1 2 |In − Sn | ≤ (b − a) T (Rn (s, t), Rn (s, t)) T ∂ 2n f (s, t) ∂ 2n f (s, t) , ∂sn ∂tn ∂sn ∂tn From (2.24) we have 2n 1 ∂ f (s, t) ∂ 2n f (s, t) 2 M2n − m2n T , ≤ . n n n n ∂s ∂t ∂s ∂t 2 12 Close . Quit Page 13 of 26 J. Ineq. Pure and Appl. Math. 4(5) Art. 101, 2003 http://jipam.vu.edu.au We also have 1 T (Rn (s, t), Rn (s, t)) = (b − a)2 Z b 2 Z b Qn (t)2 dt Pn (s) ds a 1 − (b − a)4 Z a b Z Pn (s)ds a b 2 Qn (t)dt . a From the last three relations we see that (2.28) holds. Theorem 2.7. Let Ω = [a, b]×[a, b] and let f : Ω → R be a given function such that f ∈ C 2n (Ω). Let the conditions of Lemma 2.6 hold. If Jk , Kk are given by (2.9), (2.17), where Jk,1 , Jk,2 , Kk,1 , Kk,2 are given by Lemmas 2.2 – 2.5, then we have the inequality Ostrowski-Grüss type Inequalities in Two Dimensions Nenad Ujević Title Page (2.30) Z Z n n b b X X f (s, t)dsdt + Jk − Kk − S n a a k=1 k=1 M2n − m2n C(b − a)2 , ≤ 2 Contents JJ J II I Go Back where Close 1 (2.31) Sn = [Pn+1 (b) − Pn+1 (a)] [Qn+1 (b) − Qn+1 (a)] (b − a)2 × [v(b, b) − v(b, a) − v(a, b) + v(a, a)] , and v(s, t) = ∂ 2n−2 t(s,t) . ∂sn−1 ∂tn−1 Quit Page 14 of 26 J. Ineq. Pure and Appl. Math. 4(5) Art. 101, 2003 http://jipam.vu.edu.au Proof. We have Z bZ (2.32) b ∂ 2n f (s, t) In = Rn (s, t) dsdt ∂sn ∂tn a a Z b Z b ∂ ∂ 2n−1 f (s, t) = dt Rn (s, t) ds ∂s ∂sn−1 ∂tn a a Z b ∂ 2n−1 f (a, t) ∂ 2n−1 f (b, t) = Rn (b, t) − Rn (a, t) dt ∂sn−1 ∂tn ∂sn−1 ∂tn a Z bZ b ∂Rn (s, t) ∂ 2n−1 f (s, t) dsdt − ∂s ∂sn−1 ∂tn a a = Jn − Ln , Ostrowski-Grüss type Inequalities in Two Dimensions Nenad Ujević Title Page where Z bZ Ln = a a b ∂Rn (s, t) ∂ 2n−1 f (s, t) dsdt. ∂s ∂sn−1 ∂tn We also have Z b Z b ∂Rn (s, t) ∂ ∂ 2n−2 f (s, t) Ln = ds dt ∂s ∂t ∂sn−1 ∂tn−1 a a Z b ∂Rn (s, b) ∂ 2n−2 f (s, b) ∂Rn (s, a) ∂ 2n−2 f (s, a) = − ds ∂s ∂sn−1 ∂tn−1 ∂s ∂sn−1 ∂tn−1 a Z bZ b ∂ 2n−2 f (s, t) − Rn−1 (s, t) n−1 n−1 dsdt ∂s ∂t a a = Kn − In−1 . Contents JJ J II I Go Back Close Quit Page 15 of 26 J. Ineq. Pure and Appl. Math. 4(5) Art. 101, 2003 http://jipam.vu.edu.au Hence, we have In = Jn − Kn + In−1 . In a similar way we obtain In−1 = Jn−1 − Kn−1 + In−2 . If we continue this procedure then we get In = (2.33) n X Jk − k=1 n X Ostrowski-Grüss type Inequalities in Two Dimensions Kk + I0 , k=1 Nenad Ujević where Z bZ I0 = (2.34) b Title Page f (s, t)dsdt. a Contents a We now consider the term 1 Sn = (b − a)2 (2.35) We have Z bZ Z bZ a Z bZ Rn (s, t)dsdt a a a a b ∂ 2n f (s, t) dsdt. ∂sn ∂tn II I Go Back Close b Z Rn (s, t)dsdt = a b JJ J b Z Pn (s)ds a Quit b Qn (t)dt a Page 16 of 26 = [Pn+1 (b) − Pn+1 (a)] [Qn+1 (b) − Qn+1 (a)] J. Ineq. Pure and Appl. Math. 4(5) Art. 101, 2003 http://jipam.vu.edu.au and Z bZ a a b ∂ 2n f (s, t) dsdt ∂sn ∂tn Z b Z b ∂ ∂ 2n−1 f (s, t) = dt ds ∂sn−1 ∂tn a a ∂s Z b 2n−1 ∂ f (b, t) ∂ 2n−1 f (a, t) = − dt ∂sn−1 ∂tn ∂sn−1 ∂tn a ∂ 2n−2 f (b, b) ∂ 2n−2 f (b, a) ∂ 2n−1 f (a, b) ∂ 2n−1 f (a, a) = − − + ∂sn−1 ∂tn−1 ∂sn−1 ∂tn−1 ∂sn−1 ∂tn−1 ∂sn−1 ∂tn−1 = [v(b, b) − v(b, a) − v(a, b) + v(a, a)] , Thus (2.31) holds. From (2.33) – (2.35) we see that Z bZ In − Sn = b f (s, t)dsdt + a a n X Jk − k=1 Then from Lemma 2.6 we conclude that (2.30) holds. Ostrowski-Grüss type Inequalities in Two Dimensions Nenad Ujević Title Page n X k=1 Contents Kk − S n . JJ J II I Go Back Close Quit Page 17 of 26 J. Ineq. Pure and Appl. Math. 4(5) Art. 101, 2003 http://jipam.vu.edu.au 3. A Particular Inequality Here we use the notations introduced in Section 2. In Theorem 2.7 we proved a general inequality of Ostrowski-Grüss type. Many particular inequalities can be obtained if we choose specific harmonic or Appell-like polynomials Pk (s), Qk (t) in (2.30). For example, in [8] we can find the following harmonic polynomials 1 Pk (s) = (s − a)k , k! k 1 a+b Pk (s) = s− , k! 2 (b − a)k s−a Pk (s) = Bk , k! b−a (b − a)k s−a Pk (s) = Ek , k! b−a where Bk (s) and Ek (s) are Bernoulli and Euler polynomials, respectively. We shall not consider all possible combinations of these polynomials. Here we choose the following combination s−a (b − a)k (3.1) Pk (s) = Bk , k! b−a (b − a)k t−a Qk (t) = Bk . k! b−a We now substitute the above polynomials in (2.10), (2.11), (2.18), (2.19) to obtain Ostrowski-Grüss type Inequalities in Two Dimensions Nenad Ujević Title Page Contents JJ J II I Go Back Close Quit Page 18 of 26 J. Ineq. Pure and Appl. Math. 4(5) Art. 101, 2003 http://jipam.vu.edu.au (3.2) Jk,1 = J¯k,1 k j X (b − a)k k−j (b − a) = Bk (1) (−1) k! j! j=1 h i (j−1) (j−1) × Bj (1)uk−1 (b) − Bj (0)uk−1 (a) Z (b − a)k b k + (−1) Bk (1) uk−1 (t)dt, k! a (3.3) Ostrowski-Grüss type Inequalities in Two Dimensions Jk,2 = J¯k,2 k X (b − a)k (b − a)j = Bk (0) (−1)k−j k! j! j=1 h i (j−1) (j−1) × Bj (1)vk−1 (b) − Bj (0)vk−1 (a) Z (b − a)k b k vk−1 (t)dt, + (−1) Bk (0) k! a (3.4) Kk,1 = K̄k,1 Title Page Contents JJ J II I Go Back k = Nenad Ujević k X j−1 (b − a) (b − a) Bk (1) (−1)k−j+1 k! (j − 1)! j=2 h i (j−2) (j−2) × Bj−1 (1)xk−1 (b) − Bj−1 (0)xk−1 (a) Z b k k−1 (b − a) Bk (1) xk−1 (s)ds, + (−1) k! a Close Quit Page 19 of 26 J. Ineq. Pure and Appl. Math. 4(5) Art. 101, 2003 http://jipam.vu.edu.au and (3.5) Kk,2 = K̄k,2 = k X (b − a)k (b − a)j−1 Bk (0) (−1)k−j+1 k! (j − 1)! j=2 h i (j−2) (j−2) × Bj−1 (1)yk−1 (b) − Bj−1 (0)yk−1 (a) Z b k k−1 (b − a) + (−1) Bk (0) yk−1 (s)ds. k! a We have (3.6) Ostrowski-Grüss type Inequalities in Two Dimensions Nenad Ujević Jk = J¯k = J¯k,1 − J¯k,2 , k = 1, 2, . . . , n, Title Page Contents (3.7) Kk = K̄k = K̄k,1 − K̄k,2 , k = 2, . . . , n and (3.8) b−a K̄1 = 2 Z b Z x0 (s)ds + a b y0 (s)ds , a where J¯k,1 , J¯k,2 , K̄k,1 , K̄k,2 are defined by (3.2) – (3.5), respectively. Basic properties of Bernoulli polynomials can be found in [1]. Here we emphasize the following properties: Z 1 (3.9) Bk (s)ds = 0, k = 1, 2, . . . 0 JJ J II I Go Back Close Quit Page 20 of 26 J. Ineq. Pure and Appl. Math. 4(5) Art. 101, 2003 http://jipam.vu.edu.au and Z (3.10) 1 Bk (s)Bj (s)ds = (−1)k−1 0 k!j! Bk+j , k, j = 1, 2, . . . , (k + j)! where (3.11) Bk = Bk (0), k = 0, 1, 2, . . . are Bernoulli numbers. We also have (3.12) B2i+1 = 0, i = 1, 2, . . . , Ostrowski-Grüss type Inequalities in Two Dimensions Nenad Ujević Title Page (3.13) Bk (0) = Bk (1) = Bk , k = 0, 2, 3, 4, . . . , and, in particular, (3.14) 1 1 B1 (0) = − , B1 (1) = . 2 2 From (3.2) – (3.8) and (3.12) we see that (3.15) J¯2i+1 = K̄2i+1 = 0, i = 1, 2, . . . , n. Contents JJ J II I Go Back Close Quit Page 21 of 26 Note also that sums in (3.2) – (3.5) have only even-indexed terms and the term for j = 1 (j = 2) is non-zero. J. Ineq. Pure and Appl. Math. 4(5) Art. 101, 2003 http://jipam.vu.edu.au Theorem 3.1. Under the assumptions of Theorem 2.7 we have Z Z n n b b X X ¯ (3.16) f (s, t)dsdt + Jk − K̄k a a k=1 k=1 M2n − m2n |B2n | · (b − a)2n+2 , 2 (2n)! ≤ where Bk are Bernoulli numbers and J¯k , K̄k are given by (3.6), (3.7), respectively. Proof. The proof follows from the proof of Theorem 2.7, since the following is valid. Let Pn and Qn be defined by (3.1), for k = n. Firstly, we have Z bZ b Z b Z b 2n 1 ∂ f (s, t) Sn = Rn (s, t)dsdt dsdt = 0, 2 (b − a) a a ∂sn ∂tn a a since Z bZ b Z b (s, t)dsdt = a an Pn (s)ds a a = Title Page Contents JJ J II I Go Back Qn (t)dt Close 2 b Nenad Ujević b Z Z Ostrowski-Grüss type Inequalities in Two Dimensions Pn (s)ds Quit a n+1 (b − a) = n! Z1 2 Bn (s)ds = 0, 0 Page 22 of 26 J. Ineq. Pure and Appl. Math. 4(5) Art. 101, 2003 http://jipam.vu.edu.au because of (3.9). Secondly, we have Z b Z b 1 2 Pn (s) ds C= Qn (t)2 dt 2 (b − a) a a Z b 2 ) 12 Z b 1 Pn (s)ds Qn (t)dt − (b − a)4 a a 12 Z b Z b 1 = Pn (s)2 ds Qn (t)2 dt (b − a)2 a a Z b 1 = Pn (s)2 ds b−a a Z 1 (b − a)2n+1 1 · Bn (s)2 ds = 2 b−a (n!) 0 2 2n (b − a) (n!) |B2n | = |B2n | = (b − a)2n , 2 (n!) (2n)! (2n)! since (3.10) holds. Ostrowski-Grüss type Inequalities in Two Dimensions Nenad Ujević Title Page Contents JJ J II I Go Back Close Quit Page 23 of 26 J. Ineq. Pure and Appl. Math. 4(5) Art. 101, 2003 http://jipam.vu.edu.au References [1] M. ABRAMOWITZ AND I.A. STEGUN (Eds), Handbook of Mathematical Functions with Formulas, Graphs, and Mathematical Tables, National Bureau of Standards, Applied Mathematics Series 55, 4th printing, Washington, 1965 [2] G.A. ANASTASSIOU, Multivariate Ostrowski type inequalities, Acta Math. Hungar., 76 (1997), 267–278. [3] G.A. ANASTASSIOU, Ostrowski type inequalities, Proc. Amer. Math. Soc., 123(12) (1995), 3775–3781. [4] X.L. CHENG, Improvement of some Ostrowski-Grüss type inequalities, Comput. Math. Appl., 42 (2001), 109–114. [5] S.S. DRAGOMIR, A generalization of Grüss inequality in inner product spaces and applications, J. Math. Anal. Appl., 237 (1999), 74–82. [6] S.S. DRAGOMIR AND S. WANG, An inequality of Ostrowski–Grüss type and its applications to the estimation of error bounds for some special means and for some numerical quadrature rules, Comput. Math. Appl., 33(11) (1997), 16–20. [7] G. HANNA, P. CERONE AND J. ROUMELIOTIS, An Ostrowski type inequality in two dimensions using the three point rule, ANZIAM J., 42(E) (2000), 671–689. Ostrowski-Grüss type Inequalities in Two Dimensions Nenad Ujević Title Page Contents JJ J II I Go Back Close Quit Page 24 of 26 J. Ineq. Pure and Appl. Math. 4(5) Art. 101, 2003 http://jipam.vu.edu.au [8] M. MATIĆ, J. PEČARIĆ AND N. UJEVIĆ, On new estimation of the remainder in generalized Taylor’s formula, Math. Inequal. Appl., 2(3), (1999), 343–361. [9] M. MATIĆ, J. PEČARIĆ AND N. UJEVIĆ, Improvement and further generalization of some inequalities of Ostrowski-Grüss type, Comput. Math. Appl., 39 (2000), 161–175. [10] M. MATIĆ, J. PEČARIĆ AND N. UJEVIĆ, Generalizations of weighted version of Ostrowski’s inequality and some related results, J. Inequal. Appl., 5 (2000), 639–666. [11] M. MATIĆ, J. PEČARIĆ AND N. UJEVIĆ, Weighted version of multivariate Ostrowski type inequalities, Rocky Mountain J. Math, 31(2) (2001), 511–538. [12] G.V. MILOVANOVIĆ, On some integral inequalities, Univ. Beograd Publ. Elektrotehn. Fak. Ser. Mat. Fiz., No 498-541, (1975), 119–124. [13] G.V. MILOVANOVIĆ, O nekim funkcionalnim nejednakostima, Univ. Beograd Publ. Elektrotehn. Fak. Ser. Mat. Fiz., No 599, (1977), 1–59. [14] G.V. MILOVANOVIĆ AND J.E. PEČARIĆ, On generalization of the inequality of A. Ostrowski and some related applications, Univ. Beograd Publ. Elektrotehn. Fak. Ser. Mat. Fiz., No 544-576, (1976), 155-158. [15] D.S. MITRINOVIĆ, J.E. PEČARIĆ AND A.M. FINK, Classical and New Inequalities in Analysis, Kluwer Academic Publishers, Dordrecht, 1993. Ostrowski-Grüss type Inequalities in Two Dimensions Nenad Ujević Title Page Contents JJ J II I Go Back Close Quit Page 25 of 26 J. Ineq. Pure and Appl. Math. 4(5) Art. 101, 2003 http://jipam.vu.edu.au [16] D.S. MITRINOVIĆ, J.E. PEČARIĆ AND A.M. FINK, Inequalities Involving Functions and Their Integrals and Derivatives, Kluwer Acad. Publ., Dordrecht, Boston/London, 1991. [17] A. OSTROWSKI, Über die Absolutabweichung einer Differentiebaren Funktion von ihren Integralmittelwert, Comment. Math. Helv., 10 (1938), 226–227. [18] B.G. PACHPATTE, On multidimensional Grüss type inequalities, J. Inequal. Pure Appl. Math., 3(2) (2002), Article 27. [ONLINE http:// jipam.vu.edu.au/v3n2/063_01.html]. Ostrowski-Grüss type Inequalities in Two Dimensions Nenad Ujević Title Page Contents JJ J II I Go Back Close Quit Page 26 of 26 J. Ineq. Pure and Appl. Math. 4(5) Art. 101, 2003 http://jipam.vu.edu.au