Journal of Inequalities in Pure and Applied Mathematics ON AN INTEGRAL INEQUALITY WITH A KERNEL SINGULAR IN TIME AND SPACE volume 4, issue 4, article 82, 2003. NASSER-EDDINE TATAR King Fahd University of Petroleum and Minerals Department of Mathematical Sciences Dhahran 31261, Saudi Arabia. EMail: tatarn@kfupm.edu.sa Received 07 March, 2003; accepted 01 August, 2003. Communicated by: D. Bainov Abstract Contents JJ J II I Home Page Go Back Close c 2000 Victoria University ISSN (electronic): 1443-5756 030-03 Quit Abstract In this paper we deal with a nonlinear singular integral inequality which arises in the study of partial differential equations. The integral term is non local in time and space and the kernel involved is also singular in both the time and the space variable. The estimates we prove may be used to establish (global) existence and asymptotic behavior results for solutions of the corresponding problems. On an Integral Inequality with a Kernel Singular in Time and Space 2000 Mathematics Subject Classification: 42B20, 26D07, 26D15. Key words: Nonlinear integral inequality, Singular kernel. Nasser-eddine Tatar The author would like to thank King Fahd University of Petroleum and Minerals for its financial support. Title Page Contents Contents 1 Introduction . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 2 Preliminaries . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 3 Estimation . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . References 3 6 8 JJ J II I Go Back Close Quit Page 2 of 20 J. Ineq. Pure and Appl. Math. 4(4) Art. 82, 2003 http://jipam.vu.edu.au 1. Introduction We consider the following integral inequality Z Z t F (s)ϕm (s, y) dyds, (1.1) ϕ(t, x) ≤ k(t, x) + l(t, x) 1−β |x − y|n−α Ω 0 (t − s) x ∈ Ω, t > 0, where Ω is a domain in Rn (n ≥ 1) (bounded or possibly equal to Rn ), the functions k(t, x), l(t, x) and F (t) are given positive continuous functions in t. The constants 0 < α < n, 0 < β < 1 and m > 1 will be specified below. This inequality arises in the theory of partial differential equations, for example, when treating the heat equation with a source of polynomial type ut (t, x) = ∆u(t, x) + um (t, x), x ∈ Rn , t > 0, m > 1 On an Integral Inequality with a Kernel Singular in Time and Space Nasser-eddine Tatar Title Page Contents u(0, x) = u (x), x ∈ Rn . 0 If we write the (weak) solution using the fundamental solution G(t, x) of the heat equation ut (t, x) = ∆u(t, x), namely, JJ J II I Go Back Close Z tZ Z G(t, x − y)u0 (y)dy + u(t, x) = Rn 0 G(t − s, x − y)um (s, y)dyds Rn and take into account the Solonnikov estimates of this fundamental solution (see [14] for instance), then one is led to an inequality of type (1.1). Quit Page 3 of 20 J. Ineq. Pure and Appl. Math. 4(4) Art. 82, 2003 http://jipam.vu.edu.au The features of this inequality, which make it difficult to deal with, are the singularities of the kernel in both the space and time variables. It is also non integrable with respect to the time variable. The standard methods one can find in the literature (see the recent books by Bainov and Simeonov [1] and Pachpatte [12] and the references therein) concerning regular and/or summable kernels cannot be applied in our situation. Indeed, these methods are based on estimates involving the value of the kernels at zero and/or some Lp −norms of the kernels. In contrast, there are very few papers dealing explicitly with singular kernels similar to ours. Let us point out, however, some works concerning integral equations with singularities in time. In Henry [4, Lemmas 7.1.1 and 7.1.2], a similar inequality to (1.1) with only the integral with respect to time, namely Z t ψ(t) ≤ a(t) + b (t − s)β−1 sγ−1 ψ(s)ds, β > 0, γ > 0 0 i.e. the linear case (m = 1) has been treated. The case m > 1 has been considered by Medved in [9], [10]. More precisely, the following inequality Z t ψ(t) ≤ a(t) + b(t) (t − s)β−1 sγ−1 F (s)ψ m (s)ds, β > 0, γ > 0 0 was discussed. The result was used to prove a global existence and an exponential decay result for a parabolic Cauchy problem with a source of power type and a time dependent coefficient, namely ut + Au = f (t, u), u ∈ X, u(0) = u ∈ X 0 On an Integral Inequality with a Kernel Singular in Time and Space Nasser-eddine Tatar Title Page Contents JJ J II I Go Back Close Quit Page 4 of 20 J. Ineq. Pure and Appl. Math. 4(4) Art. 82, 2003 http://jipam.vu.edu.au with kf (t, u)k ≤ tκ η(t) kukm α , m > 1, κ ≥ 0, where A is a sectorial operator (see [4]) and k·kα stands for the norm of the fractional space X α associated to the operator A (see also [11]). This, in turn, has been improved and extended to integro-differential equations and functional differential equations by M. Kirane and N.-E. Tatar in [6] (see also N.-E. Tatar [13] and S. Mazouzi and N.-E. Tatar [7, 8] for more general abstract semilinear evolution problems). Here, we shall combine the techniques in [9, 10], based on the application of Lemma 2.1 and the use of Lemma 2.3 below, with the Hardy-LittlewoodSobolev inequality (see Lemma 2.2) to prove our result. We will give sufficient conditions yielding boundedness by continuous functions, exponential decay and polynomial decay of solutions to the integral inequality (1.1). The paper is organized as follows. In the next section we prepare some notation and lemmas needed in the proofs of our results. Section 3 contains the statement and proof of our result and two corollaries giving sufficient conditions for the exponential decay and the polynomial decay. Finally we point out that our results hold (a fortiori) for weakly singular kernels in time. On an Integral Inequality with a Kernel Singular in Time and Space Nasser-eddine Tatar Title Page Contents JJ J II I Go Back Close Quit Page 5 of 20 J. Ineq. Pure and Appl. Math. 4(4) Art. 82, 2003 http://jipam.vu.edu.au 2. Preliminaries In this section we introduce some material necessary for our results. We will use the usual Lp -space with its norm k·kp . Lemma 2.1. (Young inequality) We have, for 1 r = 1 ρ + 1q , the inequality kf gkr ≤ kf kρ · kgkq . Lemma 2.2. Let α ∈ [0, 1) and β ∈ R. There exists a positive constant C = C(α, β) such that Ceβt , if β > 0; Z t −α βs C(t + 1), if β = 0; s e ds ≤ 0 C, if β < 0. Lemma 2.3. (Hardy-Littlewood-Sobolev inequality) Let u ∈ Lp (Rn ) (p > 1), 0 < γ < n and nγ > 1 − p1 , then (1/ |x|γ ) ∗ u ∈ Lq (Rn ) with 1q = nγ + p1 − 1. Also the mapping from u ∈ Lp (Rn ) into (1/ |x|γ ) ∗ u ∈ Lq (Rn ) is continuous. See [5, Theorem 4.5.3, p. 117]. Lemma 2.4. Let a(t), b(t), K(t), ψ(t) be nonnegative, continuous functions on the interval I = (0, T ) (0 < T ≤ ∞), ω : (0, ∞) → R be a continuous, On an Integral Inequality with a Kernel Singular in Time and Space Nasser-eddine Tatar Title Page Contents JJ J II I Go Back Close Quit Page 6 of 20 J. Ineq. Pure and Appl. Math. 4(4) Art. 82, 2003 http://jipam.vu.edu.au nonnegative and nondecreasing function, ω(0) = 0, ω(u) > 0 for u > 0 and let A(t) = max0≤s≤t a(s), B(t) = max0≤s≤t b(s). Assume that Z t ψ(t) ≤ a(t) + b(t) K(s)ω(ψ(s))ds, t ∈ I. 0 Then ψ(t) ≤ W −1 Z t W (A(t)) + B(t) K(s)ds , t ∈ (0, T1 ), 0 where Z v W (v) = v0 W −1 dσ , v ≥ v0 > 0, ω(σ) is the inverse of W and T1 > 0 is such that Z t W (A(t)) + B(t) K(s)ds ∈ D(W −1 ) 0 See [2] (or [5]) for the proof. Lemma 2.5. If δ, ν, τ > 0 and z > 0, then Z z 1−ν z (z − ζ)ν−1 ζ δ−1 e−τ ζ dζ ≤ M (ν, δ, τ ) , 0 See [6] for the proof of this lemma. Nasser-eddine Tatar Title Page Contents JJ J for all t ∈ (0, T1 ). where M (ν, δ, τ ) = max (1, 21−ν ) Γ (δ) 1 + On an Integral Inequality with a Kernel Singular in Time and Space δ ν τ −δ . II I Go Back Close Quit Page 7 of 20 J. Ineq. Pure and Appl. Math. 4(4) Art. 82, 2003 http://jipam.vu.edu.au 3. Estimation In this section we state and prove our result on boundedness and also present an exponential and a polynomial decay result. Theorem 3.1. Assume that the constants α, β and m are such that 0 < α < βn, 0 < β < 1 and m > 1. (m−1)n m n (i) If Ω = R , then for any r satisfying max , β < r < mn , we have α α On an Integral Inequality with a Kernel Singular in Time and Space kϕ(t, x)kr ≤ Up,r,ρ (t) with Nasser-eddine Tatar Up,r,ρ (t) = 2 m(p−1) r 1 K(t) p Title Page × 1 − 2m(p−1) (m − 1)C1p−1 C2p K(t)m−1 L(t)eεpt Z × t −εps e p F (s)ds Contents m (1−m)r , 0 where K(t) = max0≤s≤t kk(s, ·)kpr , L(t) = max0≤s≤t kl(s, ·)kpρ , p = mr nr and ρ = αr−(m−1)n for some ε > 0. Here C1 and C2 are the best constants in Lemma 2.2 and Lemma 2.3, respectively. The estimation is valid as long as Z t 1 m−1 εpt (3.1) K(t) L(t)e e−εps F p (s)ds ≤ m(p−1) (m − 1)C1p−1 C2p . 2 0 JJ J II I Go Back Close Quit Page 8 of 20 J. Ineq. Pure and Appl. Math. 4(4) Art. 82, 2003 http://jipam.vu.edu.au (ii) If Ω is bounded, then kϕ(t, x)kr̃ ≤ Up,r,ρ (t) n (but for any r̃ ≤ r where p, r and ρ are as in (i). If moreover, r < nβ−α not necessarily r > (m−1)n ) that is m < r < min mn , n , then this α β α nβ−α estimation holds for any 1 β <p≤ r m provided that ρ > nr . n−(nβ−α)r Proof. (i) Suppose that Ω = Rn . By the Minkowski inequality and the Young inequality (Lemma 2.1), we have (3.2) kϕ(t, x)kr ≤ kk(t, x)kr Z + kl(t, x)kρ Z Rn for r, ρ and q such that 1 r 1 q = 1 + 1q . ρ α and p0 n Let p be such that p1 = + the Hölder inequality, we see that 0 t F (s)ϕm (s, y) dsdy n−α (t − s)1−β |x − y| q 1 p its conjugate i.e. + 1 p0 = 1. Using 0 Z ≤ 0 t Title Page JJ J II I Go Back (t − s)β−1 F (s)ϕm (s, y)ds (3.3) Nasser-eddine Tatar Contents t Z On an Integral Inequality with a Kernel Singular in Time and Space p10 Z t p1 −εps p mp (β−1)p0 εp0 s (t − s) e ds e F (s)ϕ (s, y)ds , 0 Close Quit Page 9 of 20 εs −εs for any positive constant ε. We have multiplied by e ·e Hölder inequality. before applying J. Ineq. Pure and Appl. Math. 4(4) Art. 82, 2003 http://jipam.vu.edu.au nr Choosing q = (nm−αr) , we see that p = mr . By our assumption on r it is easy to see that q > 1, p > 1 and 1 + (β − 1)p0 > 0. Therefore, we may apply Lemma 2.2 to get Z t 0 0 0 (t − s)(β−1)p eεp s ds < C1 eεp t . 0 Hence, inequality (3.3) becomes Z t β−1 (t − s) m 1 p0 εt Z F (s)ϕ (s, y)ds ≤ C1 e p1 t −εps e p F (s)ϕ mp (s, y)ds . 0 0 It follows that Z Z (3.4) Nasser-eddine Tatar t F (s)ϕm (s, y) dsdy n−α 1−β n |x − y| R 0 (t − s) q Z Z p1 t 1 dy 0 e−εps F p (s)ϕmp (s, y)ds ≤ C1p eεt n−α . Rn |x − y| 0 q As r < (3.5) mn , α On an Integral Inequality with a Kernel Singular in Time and Space we may apply the results in Lemma 2.3 to obtain Title Page Contents JJ J II I Go Back Z Z p1 t dy e−εps F p (s)ϕmp (s, y)ds n−α Rn |x − y| 0 q Z p1 t −εps p mp ≤ C2 e F (s)ϕ (s, ·)ds , 0 p Close Quit Page 10 of 20 J. Ineq. Pure and Appl. Math. 4(4) Art. 82, 2003 http://jipam.vu.edu.au with p as above and C2 is the best constant in the result of Lemma 2.3. From (3.2), (3.4) and (3.5) it appears that kϕ(t, x)kr Z p1 t ≤ kk(t, x)kr + C3 eεt kl(t, x)kρ e−εps F p (s)ϕmp (s, ·)ds 0 p or (3.6) On an Integral Inequality with a Kernel Singular in Time and Space kϕ(t, x)kr Z εt ≤ kk(t, x)kr + C3 e kl(t, x)kρ −εps e Rn p1 t Z p F (s)ϕ mp (s, x)dsdx Nasser-eddine Tatar , 0 Title Page 1 p0 where C3 = C1 C2 . Inequality (3.6) can also be written as Contents kϕ(t, x)kr εt Z t −εps ≤ kk(t, x)kr + C3 e kl(t, x)kρ e F p (s) kϕ(s, x)kmp mp 1 p ds . 0 Go Back Quit kϕ(t, x)kr ≤ kk(t, x)kr + C3 eεt kl(t, x)kρ II I Close Observe that by our choice of p we have r = mp. It follows that (3.7) JJ J Z 0 t e−εps F p (s) kϕ(s, x)krr ds Page 11 of 20 p1 . J. Ineq. Pure and Appl. Math. 4(4) Art. 82, 2003 http://jipam.vu.edu.au Applying the algebraic inequality (a + b)p ≤ 2p−1 (ap + bp ), a, b ≥ 0, p > 1, we deduce from (3.7) that (3.8) kϕ(t, x)kpr p−1 ≤2 kk(t, x)kpr εpt + C4 e kl(t, x)kpρ Z t e−εps F p (s) kϕ(s, ·)krr ds, 0 where C4 = form 2p−1 C3p . Let us put ψ(t) = kϕ(t, x)kr/m , r then (3.8) takes the On an Integral Inequality with a Kernel Singular in Time and Space Nasser-eddine Tatar ψ(t) ≤ 2p−1 kk(t, ·)kpr + C4 eεpt kl(t, x)kpρ Z t e−εps F p (s)ψ m (s)ds. 0 1 By the Lemma 2.4 with ω(u) = um , W (v) = 1−m (v 1−m − v01−m ) and 1 W −1 (z) = (1 − m)z + v01−m 1−m , we conclude that Z t −1 p−1 εpt −εps p ψ(t) ≤ W W 2 K(t) + C4 e L(t) e F (s)ds 0 m−1 εpt p−1 ≤ 2 K(t) 1 − (m − 1)C4 2p−1 K(t) e L(t) Z × t e−εps F p (s)ds Title Page Contents JJ J II I Go Back Close Quit 1 1−m , Page 12 of 20 0 where K(t) and L(t) are as in the statement of the theorem. J. Ineq. Pure and Appl. Math. 4(4) Art. 82, 2003 http://jipam.vu.edu.au (ii) If Ω is bounded, then the first part in the assertion (ii) of the theorem follows from the argument in (i) by an extension procedure and the applin cation of the embedding Lr (Ω) ⊂ Lr̃ (Ω) for r̃ ≤ r. Now if r < nβ−α n nr we choose q such that r < q < nβ−α and ρ > n−(nβ−α)r . The Young np inequality is therefore applicable. Also as 1 < q < n−αp , the HardyLittlewood-Sobolev inequality (Lemma 2.3) applies (see also [3, p. 660] when Ω is bounded). In what follows, in order to simplify the statement of our next results, we define v := r or r̃ according to the cases (i) or (ii) in Theorem 3.1, respectively. Corollary 3.2. Suppose that the hypotheses of Theorem 3.1 hold. Assume further that k(t, x) and l(t, x) decay exponentially in time, that is k(t, x) ≤ e−k̃t k̄(x) and l(t, x) ≤ e−l̃t ¯l(x) for some positive constants k̃ and ˜l. Then ϕ(t, x) is also exponentially decaying to zero i.e., (3.9) kϕ(t, x)kv ≤ C5 e−µt , t > 0 for some positive constants C5 and µ provided that Z ∞ m−1 1 p k̄ (x) ¯l(x) F (s)ds ≤ (m − 1)C6p−1 C2p , r ρ m(p−1) 2 0 where C6 is the best constant in Lemma 2.2 (third estimation) and the other constants are as in (i) and (ii) of Theorem 3.1. On an Integral Inequality with a Kernel Singular in Time and Space Nasser-eddine Tatar Title Page Contents JJ J II I Go Back Close Quit Page 13 of 20 J. Ineq. Pure and Appl. Math. 4(4) Art. 82, 2003 http://jipam.vu.edu.au Proof. From the inequality (1.1) we have Z Z −k̃t −l̃t ¯ (3.10) ϕ(t, x) ≤ e k̄(x) + e l(x) Ω t 0 F (s)ϕm (s, y) dsdy. (t − s)1−β |x − y|n−α After multiplying by e−mµt · emµt , where µ = min{k̃, ˜l}, we use the Hölder inequality to get Z t (t − s)β−1 F (s)ϕm (s, y)ds 0 Z ≤ t (β−1)p0 −mp0 µt (t − s) e p1 p10 Z t p mpµt mp F (s)e ϕ (s, y)ds . ds As in the proof of Theorem 3.1, 0 < (1 − β)p0 < 1. If C6 is the best constant in Lemma 2.2, then we may write t (t − s)β−1 F (s)ϕm (s, y)ds ≤ C6 (3.11) 0 Z t p1 F p (s)ϕmp (s, y)ds . 0 Z Z Ω 0 t Title Page Contents JJ J II I Go Back From (3.10) and (3.11) it appears that eµt ϕ(t, x) ≤ k̄(x) + C6 ¯l(x) Nasser-eddine Tatar 0 0 Z On an Integral Inequality with a Kernel Singular in Time and Space p1 p mpµt mp F (s)e ϕ (s, y)ds Close dyds . |x − y|n−α Quit Page 14 of 20 r Taking the L −norm and applying the Minkowski inequality and then the Young J. Ineq. Pure and Appl. Math. 4(4) Art. 82, 2003 http://jipam.vu.edu.au inequality (Lemma 2.1), we find eµt kϕ(t, x)kr ≤ k̄ (x)r + C6 ¯l(x)ρ Z Z p1 t dyds × F p (s)empµt ϕmp (s, y)ds n−α , Ω |x − y| 0 q with 1 r = 1 ρ + 1q . Applying Lemma 2.3, we arrive at On an Integral Inequality with a Kernel Singular in Time and Space µt e kϕ(t, x)kr Z p1 t p mpµt mp k̄ ¯ ≤ (x) r + C2 C6 l(x) ρ F (s)e ϕ (s, y)ds 0 Nasser-eddine Tatar p Title Page or Contents (3.12) eµt kϕ(t, x)kr ≤ k̄ (x)r + C2 C6 ¯l(x)ρ t Z F p (s)empµt kϕ(s, x)kmp r ds p1 . 0 Close Quit (3.13) eµpt kϕ(t, x)kpr ≤2 II I Go Back Taking both sides of (3.12) to the power p, we obtain p−1 JJ J k̄ (x)p + C7 ¯l(x)p r ρ Z Page 15 of 20 t p mpµt F (s)e 0 kϕ(s, x)kmp r ds. J. Ineq. Pure and Appl. Math. 4(4) Art. 82, 2003 http://jipam.vu.edu.au Next, putting χ(t) := eµpt kϕ(t, x)kpr , the inequality (3.13) may be written as p−1 χ(t) ≤ 2 k̄ (x)p + C7 ¯l(x)p r ρ Z t F p (s)χm (s)ds. 0 The rest of the proof is essentially the same as that of Theorem 3.1. In the following corollary we consider the somewhat more general inequality Z Z (3.14) ϕ(t, x) ≤ k(t, x) + l(t, x) Ω 0 t sδ F (s)ϕm (s, y) dyds, (t − s)1−β |x − y|n−α x ∈ Ω, t > 0 for some specified δ. On an Integral Inequality with a Kernel Singular in Time and Space Nasser-eddine Tatar Title Page Contents Corollary 3.3. Suppose that the hypotheses of Theorem 3.1 hold. Assume further that k(t, x) ≤ t−k̂ k̄(x) and 1 + δp0 − mp0 min{k̂, 1 − β} > 0. Then any ϕ(t, x) satisfying (3.14) is also polynomially decaying to zero kϕ(t, x)kv ≤ C8 t−ω , C8 , ω > 0 JJ J II I Go Back Close provided that Quit k̄ (x)m−1 L(t) r Z t eεps F p (s)ds ≤ 0 where C9 is the best constant in Lemma 2.5. 1 2m(p−1) (m − 1)C9p−1 C2p Page 16 of 20 J. Ineq. Pure and Appl. Math. 4(4) Art. 82, 2003 http://jipam.vu.edu.au Proof. Let us consider the inequality Z Z −k̂ ϕ(t, x) ≤ t k̄(x) + l(t, x) (3.15) Ω 0 t sδ F (s)ϕm (s, y) dyds. (t − s)1−β |x − y|n−α Multiplying by s−m min{k̂,1−β} e−εs · sm min{k̂,1−β} eεs , we obtain Z t (3.16) (t − s)β−1 sδ F (s)ϕm (s, y)ds 0 Z ≤ t (β−1)p0 δp0 −mp0 min{k̂,1−β} −εp0 s (t − s) s e p10 On an Integral Inequality with a Kernel Singular in Time and Space ds 0 Z p1 t × s mp min{k̂,1−β} pεs e p F (s)ϕ mp (s, y)ds . Nasser-eddine Tatar 0 As 1 + δp0 − mp0 min{k̂, 1 − β} > 0, we may apply Lemma 2.5 to the first term in the right hand side of (3.16) to get Z t (3.17) (t − s)β−1 sδ F (s)ϕm (s, y)ds 0 ≤ M tβ−1 Z t smp min{k̂,1−β} epεs F p (s)ϕmp (s, y)ds p1 . Title Page Contents JJ J II I Go Back 0 Close Using (3.17) we infer from inequality (3.15) that tmin{k̂,1−β} ϕ(t, x) ≤ k̄(x) + M l(t, x) p1 Z Z t mp min{k̂,1−β} pεs p mp × s e F (s)ϕ (s, y)ds Ω 0 Quit Page 17 of 20 dy . |x − y|n−α J. Ineq. Pure and Appl. Math. 4(4) Art. 82, 2003 http://jipam.vu.edu.au Next, after using the Hardy-Littlewood-Sobolev inequality and defining φ(t, x) := tp min{k̂,1−β} kϕ(t, x)kpr , we proceed as in Theorem 3.1 to find a (uniform) bound for φ(t, x). Remark 3.1. The investigation of (1.1) with a weakly singular kernel in time, that is Z Z t −γ(t−s) e F (s)ϕm (s, y) ϕ(t, x) ≤ k(t, x) + l(t, x) dyds, γ > 0 1−β |x − y|n−α Ω 0 (t − s) is simpler since this kernel is summable (in time). On an Integral Inequality with a Kernel Singular in Time and Space Nasser-eddine Tatar Title Page Contents JJ J II I Go Back Close Quit Page 18 of 20 J. Ineq. Pure and Appl. Math. 4(4) Art. 82, 2003 http://jipam.vu.edu.au References [1] D. BAINOV AND P. SIMEONOV, Integral Inequalities and Applications, Kluwer Academic Publishers, New York, 1992. [2] G. BUTLER AND T. ROGERS, A generalization of a lemma of Bihari and applications to pointwise estimates for integral equations, J. Math. Anal. Appl. 33(1) (1971), 77–81. [3] R.E. 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On an Integral Inequality with a Kernel Singular in Time and Space Nasser-eddine Tatar Title Page Contents JJ J II I Go Back Close Quit Page 20 of 20 J. Ineq. Pure and Appl. Math. 4(4) Art. 82, 2003 http://jipam.vu.edu.au