291184405 5/28/16 1/1 Minimize this by setting the partials with respect to cm equal to zero. Two body correlation function 2 cm Approximate the two body correlation function as M g A r1 , r2 ck S k r1 r2 k 0 M 2 ck Sk r1 r2 g r1 , r2 S m r1 r2 d1d 2 0 k 0 Eqn 1 Where Sk(r) is as shown in figure 1 Eqn 4 The array of k,m S values becomes ck S k r1 r2 S m r1 r2 d1d 2 ckV S k x S m x d 3 x ckV 4 km rk 1 r dr 2 rk 4 ckV km rk31 rk3 3 Eqn 5 Figure 1 SK(r) Thus the equation for the coefficients becomes The two-body correlation function is defined to be 4 cmV rm31 rm3 S m r1 r2 g r1 , r2 d 1d 2 3 g r1 , r2 N 2 r1 , r2 , r3 , , rN d 3 r , r , r , , rN d1 2 1 2 d N 3 d N Eqn 2 N S m r1 r2 2 r1 , r2 , r3 , r , r , r , 2 1 Form 2 g A r1 r2 g r1 , r2 d 1d 2 2 3 , rN d 1d 2 d 3 , rN d 1 d N d N 2 Eqn 6 2 M ck S k r1 r2 g r1 , r2 d1d 2 k 0 __________________________________________________ Eqn 3 _________________________________________________ Any coordinate can be 1 and any other can be 2 so that this is 4 cmV rm31 rm3 3 N N 1 Sm ri rj 2 r1 , r2 , r3 , 2 N N 1 i 1 , rN d1d 2 d 3 d N j i r , r , r , 2 1 2 3 , rN d1 d N Note that this merely amounts to counting the number of distances in the ranges r m to rm+1 and dividing by the appropriate volume factor. The Markov chain method is to put N particles in the volume V. Move particle j a small amount . N V v ri rj v ri rj Evaluate the change in i j beginning if all particles start on lattice sites. If . If V 0 rj r V 0 rj r with probability . Note that this will not happen in the exp V Assignment Use the Markov chain – see ..\..\integration\MonteCarlo\Expectation value of H.htm for details -with a periodically repeated box containing ~64 atoms. Combine this with the OZ equations ..\..\Fourier\OZeqn.doc .htm to find the two body correlation function for a Lennard Jones Liquid. Do this at both a high T ~ 1000 0 and for a low T ~ 100. Send me plots of the various g(r) ‘s. Periodic distances are discussed in ..\..\integration\MonteCarlo\Periodic Distance.htm.