Error Correcting Codes: Combinatorics, Algorithms and Applications (Fall 2007) Lecture 42: Achieving List-Decoding Capacity December 7, 2007 Lecturer: Atri Rudra Scribe: Sandipan Kundu 1 Introduction !"$# as % &(')*+ . factoring out (E(X)) mod (E(X)) is poly over - is such .0/1 and , 32.4/1 for at least - , 27&+98 # . If , that , values of 6 , which implies , 5 ;:=<> over ? < A@B . Find the roots of -+< " , 27&DCFEHG % & , Lemma 1.1. There exists a irreducible polynomial E(X) such that , , -AS.4< /1" , 3:H2I/ &JCFEHG 32% .4/1& KLM>/ .4/A;:H/AKM>/N "O#QPR S.D/T S.DS.4/T+/1:UK/T KM>/12I .4"$/1 # "O# which in turn implies " and , " , then it implies , , If , V &X"W , &K , 27&+ has Y[ZU5 roots. G]\>^ V _`+aUbIKbcAE , d_fe as 5gih j . (Done) We know , & , 27&+ "$# which implies , & , 32I&; "O# . In other words, & &l"W +m<( n < J@oB for general C we have, pS, 32IqlrNK , 2sqlrut0v>(w(w>w> , 2sqlrut7q!xyvK+z . If , , 327qlisrNaK root , 2sqlofrut0k v>(w(w>w> , 2sqlrut7q!xyvKover +{8 # <xyv @ B S > ( w > w > w _fe~} q!xyv of degree }fa . < T < | Find roots of over ? < maximum number of roots -+< " , 27&DCFEHG % & , Lemma 1.2. There exists a irreducible polynomial E(X) such that , k S needs to be non-zero or [ < does’t divide . _ degree of Y in+ (1) degree of Y in _ eV } by choice of D (2) +a In fact for constant rate code, h 6T & " <xyv &2 is irreducible over ? < . Lemma 1.3. % . Exact characterization of irreducible polynomial of the form &A<8 , for , & ? < Lemma 1.4. , SK < " o < K < Proof. Hint: Show Proof. Proof of lemma (1.1) using (1.4) Done if &<xyv{2 True if % 27&8 # CFEUG % & , & < < , 27 8 # CFEHG % & P P % &AG 6No6 G]\ <Kxyv &2y 1 (3) (4) (5) In for number of folds, C general, 5Xg bc / v +aO¡j + 2