# MATH 152 - SPRING 2015 FOR PARAMETRIC FUNCTIONS - LECTURE CORRECTIONS ```MATH 152 - SPRING 2015
ARC LENGTH AND SURFACE AREA OF REVOLUTION
FOR PARAMETRIC FUNCTIONS - LECTURE CORRECTIONS
CHRISTOPHER O’NEILL
Problem: Consider the following parametric function.
x(t) = t2 + 1
y(t) = 2t3 + t2
Find the arc length between t = 0 to t = 2.
Solution: For a function y = f (x), we would use the following integral.
s
2
Z x=b
dy
1+
dx
dx
x=a
We wish to express this as an integral w.r.t. t. We use the following fact from Math 151
dy
dy/dt
=
dx
dx/dt
to change the integrand, and (this is the part I missed in class) we replace dx with
This yields
s

2
Z t=s
dy/dt
 1+
 dx dt,
dx/dt
dt
t=r
which we can also write as
Z
t=s
t=r
s
dx
dt
2
+
dy
dt
dx
dt dt.
2
dt
by bringing dx
dt inside the square root.
For the specific functions in this problem, we arrive at
Z t=2 q
(2t)2 + (6t2 + 2t)2 dt.
t=0
Note that a similar change must be made for questions involving surface area of revolution
for a parametric curve. The resulting integral has the following form (when revolving about
the x-axis).
s 2
Z t=s
dx 2
dy
+
dt
2πy(t)
dt
dt
t=r
1
```