Adv. Geom. 4 (2004), 263–277 Advances in Geometry ( de Gruyter 2004 (1, 1)-knots via the mapping class group of the twice punctured torus Alessia Cattabriga and Michele Mulazzani (Communicated by G. Gentili) Abstract. We develop an algebraic representation for ð1; 1Þ-knots using the mapping class group of the twice punctured torus MCG2 ðTÞ. We prove that every ð1; 1Þ-knot in a lens space Lð p; qÞ can be represented by the composition of an element of a certain rank two free subgroup of MCG2 ðTÞ with a standard element only depending on the ambient space. As notable examples, we obtain a representation of this type for all torus knots and for all two-bridge knots. Moreover, we give explicit cyclic presentations for the fundamental groups of the cyclic branched coverings of torus knots of type ðk; ck þ 2Þ. Key words. ð1; 1Þ-knots, Heegaard splittings, mapping class groups, two-bridge knots, torus knots. 2000 Mathematics Subject Classification. Primary 57M05, 20F38; Secondary 57M12, 57M25 1 Introduction and preliminaries The topological properties of ð1; 1Þ-knots, also called genus one 1-bridge knots, have recently been investigated in several papers (see [1], [5], [6], [8], [9], [10], [12], [13], [14], [15], [18], [19], [20], [21], [24], [25], [26]). These knots are very important in the light of some results and conjectures involving Dehn surgery on knots (see in particular [9] and [25]). Moreover, the strict connections between cyclic branched coverings of ð1; 1Þ-knots and cyclic presentations of groups have been pointed out in [5], [12] and [21]. Roughly speaking, a ð1; 1Þ-knot is a knot which can be obtained by gluing along the boundary two solid tori with a trivial arc properly embedded. A more formal definition follows. A set of mutually disjoint arcs ft1 ; . . . ; tb g properly embedded in a handlebody H is trivial if there exist b mutually disjoint discs D1 ; . . . ; Db H H such that ti V Di ¼ ti V qDi ¼ ti , ti V Dj ¼ q and qDi ti H qH for all i; j ¼ 1; . . . ; b and i 0 j. Let M ¼ H Uj H 0 be a genus g Heegaard splitting of a closed orientable 3manifold M and let F ¼ qH ¼ qH 0 ; a link L H M is said to be in b-bridge position with respect to F if: (i) L intersects F transversally and (ii) L V H and L V H 0 are both 264 Alessia Cattabriga and Michele Mulazzani H A ϕ H' A' Figure 1. A ð1; 1Þ-decomposition. the union of b mutually disjoint properly embedded trivial arcs. The splitting is called a ðg; bÞ-decomposition of L. A link L is called a ðg; bÞ-link if it admits a ðg; bÞdecomposition. Note that a ð0; bÞ-link is a link in S 3 which admits a b-bridge presentation in the usual sense. So the notion of ðg; bÞ-decomposition of links in 3manifolds generalizes the classical bridge (or plat) decomposition of links in S 3 (see [7]). Obviously, a ðg; 1Þ-link is a knot, for every g d 0. Therefore, a ð1; 1Þ-knot K is a knot in a lens space Lð p; qÞ (possibly in S 3 ) which admits a ð1; 1Þ-decomposition ðLðp; qÞ; KÞ ¼ ðH; AÞ Uj ðH 0 ; A 0 Þ; where j : ðqH 0 ; qA 0 Þ ! ðqH; qAÞ is an (attaching) homeomorphism which reverses the standard orientation on the tori (see Figure 1). It is well known that the family of ð1; 1Þ-knots contains all torus knots (trivially) and all two-bridge knots (see [16]) in S 3 . In this paper we develop an algebraic representation of ð1; 1Þ-knots through elements of MCG2 ðTÞ, the mapping class group of the twice punctured torus. In Section 2 we establish the connection between the two objects. In Section 3 we prove that every ð1; 1Þ-knot in a lens space Lðp; qÞ can be represented by an element of MCG2 ðTÞ which is the composition of an element of a certain rank two free subgroup and of a standard element only depending on the ambient space Lðp; qÞ. This representation will be called ‘‘standard’’. As a notable application, in Sections 4 and 5 we obtain standard representations for the two most important classes of ð1; 1Þknots in S 3 : the torus knots and the two-bridge knots. Moreover, applying certain results obtained in [5], we give explicit cyclic presentations for the fundamental groups of all cyclic branched coverings of torus knots of type ðk; ck þ 2Þ, with c; k > 0 and k odd. ð1; 1Þ-knots via the mapping class group of the twice punctured torus 265 b T α P1 g P2 Figure 2. Generators of MCG2 ðTÞ. In what follows, the symbol Lðp; qÞ will denote any lens space, including S 3 ¼ Lð1; 0Þ and S 1 S 2 ¼ Lð0; 1Þ. Moreover, homotopy and homology classes will be denoted with the same symbol of the representing loops. 2 (1, 1)-knots and MCG2 (T ) Let Fg be a closed orientable surface of genus g and let P ¼ fP1 ; . . . ; Pn g be a finite set of distinguished points of Fg , called punctures. We denote by HðFg ; PÞ the group of orientation-preserving homeomorphisms h : Fg ! Fg such that hðPÞ ¼ P. The punctured mapping class group of Fg relative to P is the group of the isotopy classes of elements of HðFg ; PÞ. Up to isomorphism, the punctured mapping class group of a fixed surface Fg relative to P only depends on the cardinality n of P. Therefore, we can simply speak of the n-punctured mapping class group of Fg , denoting it by MCGn ðFg Þ. Moreover, for isotopy classes we will use the same symbol of the representing homeomorphisms. The n-punctured pure mapping class group of Fg is the subgroup PMCGn ðFg Þ of MCGn ðFg Þ consisting of the elements pointwise fixing the punctures. There is a standard exact sequence 1 ! PMCGn ðFg Þ ! MCGn ðFg Þ ! Sn ! 1; where Sn is the symmetric group on n elements. A presentation of all punctured mapping class groups can be found in [11] and in [17]. In this paper we are interested in the two-punctured mapping class group of the torus MCG2 ðTÞ. According to previously cited papers, a set of generators for MCG2 ðTÞ is given by a rotation r of p radians which exchanges the punctures and the right-handed Dehn twists ta ; tb ; tg around the curves a; b; g respectively, as depicted in Figure 2. Since r commutes with the other generators, we have MCG2 ðTÞ G PMCG2 ðTÞ l Z2 : 266 Alessia Cattabriga and Michele Mulazzani T T m g T b h α T l Figure 3. Action of tm and tl . The following presentation for PMCG2 ðTÞ has been obtained in [22]: hta ; tb ; tg j ta tb ta ¼ tb ta tb ; ta tg ta ¼ tg ta tg ; tb tg ¼ tg tb ; ðta tb tg Þ 4 ¼ 1i: ð1Þ The group PMCG2 ðTÞ (as well as MCG2 ðTÞ) naturally maps by an epimorphism to the mapping class group of the torus MCGðTÞ G SLð2; ZÞ, which is generated by ta and tb ¼ tg . So we have an epimorphism W : PMCG2 ðTÞ ! SLð2; ZÞ 1 0 1 1 defined by Wðta Þ ¼ and Wðtb Þ ¼ Wðtg Þ ¼ . 1 1 0 1 The group ker W will play a fundamental role in our discussion. In order to investigate its structure, let us consider the two elements tm ¼ tb tg1 and tl ¼ th t1 a , where th is the right-handed Dehn twist around the curve h depicted in Figure 3. The e¤ect of tm and tl is to slide one puncture (say P2 ) respectively along a meridian and along a longitude of the torus, as shown in Figure 3. Observe that, since h ¼ t1 m ðaÞ, we have th ¼ t1 m t a tm . The following result can be obtained from [3, Theorem 1] and [2, Theorem 5] by classical techniques. Proposition 1. The group ker W is freely generated by tm ¼ tb tg1 and tl ¼ th t1 a , where th ¼ t1 m t a tm . Now, let K H Lðp; qÞ be a ð1; 1Þ-knot with ð1; 1Þ-decomposition ðLðp; qÞ; KÞ ¼ ðH; AÞ Uj ðH 0 ; A 0 Þ and let m : ðH; AÞ ! ðH 0 ; A 0 Þ be a fixed orientation-reversing homeomorphism, then c ¼ jmjqH is an orientation-preserving homeomorphism of ðqH; qAÞ ¼ ðT; fP1 ; P2 gÞ. Moreover, since two isotopic attaching homeomorphisms ð1; 1Þ-knots via the mapping class group of the twice punctured torus 267 produce equivalent ð1; 1Þ-knots, we have a natural surjective map from the twice punctured mapping class group of the torus MCG2 ðTÞ to the class K1; 1 of all ð1; 1Þknots Y : c A MCG2 ðTÞ 7! Kc A K1; 1 : q s If WðcÞ ¼ , then Kc is a ð1; 1Þ-knot in the lens space Lðj pj; jqjÞ [4, p. 186], p r and therefore it is a knot in S 3 if and only if p ¼ G1. As will be proved in Section 3, we have the following ‘‘trivial’’ examples: i) if either c ¼ 1 or c ¼ tb or c ¼ tg , then Kc is the trivial knot in S 1 S 2 ; ii) if c ¼ ta , then Kc is the trivial knot in S 3 . Moreover, it is possible to prove that if c ¼ ta tb ta ta tg ta , then Kc is the knot S 1 fPg H S 1 S 2 , where P is any point of S 2 . So, in this case, Kc is a standard generator for the first homology group of S 1 S 2 . Every element c of MCG2 ðTÞ can be written as c ¼ c 0 r k , k A f0; 1g, where 0 c A PMCG2 ðTÞ. Since r can be extended to a homeomorphism of the pair ðH; AÞ, the ð1; 1Þ-knots Kc and Kc 0 are equivalent. So, for our discussion it is enough to consider the restriction Y 0 ¼ YjPMCG2 ðTÞ : c A PMCG2 ðTÞ 7! Kc A K1; 1 : 3 Standard decomposition In this section we show that every ð1; 1Þ-knot K H Lðp; qÞ admits a representation by the composition of an element in ker W and an element which only depends on Lðp; qÞ. A representation of this type will be called ‘‘standard’’. Note that a similar result, using a rank three free subgroup of MCG2 ðTÞ, has been obtained in [6, Theorem 3]. First of all, we deal with trivial knots in lens spaces. Let T be the subgroup of PMCG2 ðTÞ generated by ta and tb . There exists a disk D H H, with A V D ¼ A V qD ¼ A and qD A H T, such that D V a ¼ D V b ¼ q. So any element of T produces a trivial knot in a certain lens space. On the other hand, any trivial knot in a lens space admits a representation through an element of T, as will be proved in Proposition 3. We need a preparatory result. Lemma 2. Let K be a ð1; 1Þ-knot in Lð p; qÞ. Then, for q qr ps ¼ 1 there exists c A PMCG2 ðTÞ, with WðcÞ ¼ p each r; s A Z such that s , such that K ¼ Kc . r 268 Alessia Cattabriga and Michele Mulazzani q s Proof. Let K ¼ Kc , with WðcÞ ¼ . Since qr ps ¼ 1, there exist c A Z such p r that r ¼ r þ cp and s ¼ s þ cq. If c ¼ ctbc , we have Kc ¼ Kc , since tbc can be extended toa homeomorphism of the pair ðH; AÞ. Moreover WðcÞ ¼ WðcÞWðtbc Þ ¼ 1 c q s q s þ cq ¼ . r 0 1 p r p r þ cp For integers p; q such that 0 < q < p and gcdðp; qÞ ¼ 1 consider the sequence of equations of the Euclidean algorithm (with r0 ¼ p, r1 ¼ q): r0 ¼ a 1 r1 þ r2 r1 ¼ a2 r2 þ r3 .. . rm2 ¼ am1 rm1 þ rm rm1 ¼ am rm ; with r1 > r2 > > rm1 > rm ¼ 1. The ai ’s are the coe‰cients of the continued fraction p 1 ¼ a1 þ q a2 þ 1 a3 þþa1m : In the following we will use the notation p=q ¼ ½a1 ; a2 ; . . . ; am . Proposition 3. The trivial knot in S 3 ¼ Lð1; 0Þ is represented by c1; 0 ¼ tb ta tb . The trivial knot in S 1 S 2 ¼ Lð0; 1Þ is represented by c0; 1 ¼ 1. Let p; q be integers such that 0 < q < p and gcdðp; qÞ ¼ 1. If p=q ¼ ½a1 ; a2 ; . . . ; am , then the trivial knot in the lens space Lð p; qÞ is represented by ( a taa1 tb 2 . . . taam if m is odd; cp; q ¼ a1 a2 m ta tb . . . ta t t t if m is even: b a b b Proof. Since all the involved homeomorphisms belong to T, all the knots are trivial. It is easy to check (see also [4, p. 186]) that, for suitable r; s A Z, we have: 8 > 1 > > < a q s 1 ¼ > 1 p r > > : a1 1 a2 1 0 0 ... 1 0 1 am 1 1 a2 0 0 1 am ... 1 0 1 0 1 1 if m is odd; 1 0 if m is even. ð1; 1Þ-knots via the mapping class group of the twice punctured torus 1 Since ¼ ai ment is obtained. Wðtaai Þ 0 1 ai , Wðtb Þ ¼ 1 0 269 ai 0 1 , and Wðtb ta tb Þ ¼ , the state1 1 0 r Now we can prove the result announced at the beginning of this section. Theorem 4. Let K be a ð1; 1Þ-knot in Lðp; qÞ. Then there exist c 0 ; c 00 A ker W such that K ¼ Kc , with c ¼ c 0 cp; q ¼ cp; q c 00 . Proof. By Lemma 2, there exists c, with WðcÞ ¼ Wðcp; q Þ, such that K ¼ Kc . It suf00 1 fices to define c 0 ¼ cc1 r p; q and c ¼ cp; q c. A representation c A PMCG2 ðTÞ of a ð1; 1Þ-knot will be called standard if c is of the type described in the previous theorem. We point out that ð1; 1Þ-knots admit di¤erent (usually infinitely many) standard representations. For example, tmc represents the trivial knot in S 1 S 2 , for all c A Z. 4 Representation of torus knots In this section we give a standard representation for all torus knots in S 3 . Let K ¼ tðk; hÞ be a torus knot of type ðk; hÞ. Then gcdðk; hÞ ¼ 1, and we can assume that K lies on the boundary T ¼ qH of a genus one handlebody H canonically embedded in S 3 . The homology class of K is hl þ km, where l and m respectively denote a longitude and a meridian of T. By slightly pushing (the interior of ) an arc A 0 H K outside H and K A 0 inside H, we obtain an obvious ð1; 1Þ-decomposition of K. Observe that 0 < jkj < h can be assumed without loss of generality (see [4, p. 45]). In the next statement bxc denotes the integral part of x. Theorem 5. The torus knot tðk; hÞ H S 3 is the ð1; 1Þ-knot Kc with: c¼ h Y ðtbði1Þk=hcbik=hc t1 m l Þtb ta tb ; i¼1 1 where tm ¼ tb tg1 and tl ¼ t1 m t a tm t a . Proof. Up to isotopy, we can suppose that the arc A ¼ Kc intðA 0 Þ lies on qH, as in Figure 4. The arc A can be transformed into an arc A~ in such a way that A~ U A 0 is a trivial knot in S 3 , represented by the standard homeomorphism c1; 0 ¼ tb ta tb , via a suitable sequence of homeomorphisms tl and tm , according to the following algorithm. Consider the sequence of equations: 270 Alessia Cattabriga and Michele Mulazzani H A A' Figure 4. l l m Figure 5. k ¼ q1 h þ r1 ; 2k ¼ q2 h þ r2 ; .. . hk ¼ qh h þ rh ; where 0 c ri < h, for i ¼ 1; . . . ; h. Moreover, define q0 ¼ 0. So qi ¼ bik=hc, for i ¼ 0; 1; . . . ; h. Now define the homeomorphisms ci ¼ tl tmqi qi1 , for i ¼ 1; . . . ; h. Figure 5 depicts the e¤ect of tl and tl tm on A. As a consequence, the homeomorphism f ¼ ch ch1 . . . c1 transforms the arc A into the arc A~ (Figure 6 shows the case tð5; 7Þ), and therefore we have c1; 0 ¼ fc. So f1 c1; 0 represents the torus knot tðk; hÞ. r 1 1 2 1 1 1 3 For example, tð5; 7Þ ¼ Kc , with c ¼ t1 l ðtm tl Þ tl ðtm tl Þ tb ta tb (see Figure 6). As a consequence, we obtain a cyclic presentation for the fundamental group for all cyclic branched coverings of a particular class of torus knots. ð1; 1Þ-knots via the mapping class group of the twice punctured torus 271 l l m l m l l m l m l m Figure 6. Trivialization of tð5; 7Þ. Proposition 6. The fundamental group of the n-fold cyclic branched covering of the torus knot tðk; ck þ 2Þ, with k > 1 odd and c > 0, admits the cyclic presentation Gn ðwÞ, where w is equal to ðk3Þ=2 Y cðk1Þ=2 Y i¼0 x1iðckþ2Þþjk cðkþ1Þ=2 Y j¼0 (subscripts are taken modulo n). l¼0 x1 ckðk1Þ=2iðckþ2Þlk cðk1Þ=2 Y m¼0 x1ðk1Þðckþ2Þ=2þmk 272 Alessia Cattabriga and Michele Mulazzani Proof. Let r ¼ ðk 1Þ=2. From Theorem 5 we have tðk; ck þ 2Þ ¼ Kc with 1 r 1 c 1 r c 1 1 c ¼ ðtc l tm Þ tl ðtl tm Þ tl tm tl tb ta tb . Applying [5, Proposition 1], we obtain 3 p1 ðS tðk; ck þ 2ÞÞ ¼ ha; g j rða; gÞi, with rða; gÞ ¼ ðg1 a crþ1 g1 acðrþ1Þ1 Þ r g1 a crþ1 . Then H1 ðS 3 tðk; ck þ 2ÞÞ ¼ ha; g j a kgi. Since, up to equivalence, of ðgÞ ¼ 1, we have of ðaÞ ¼ k. We set a ¼ xg k , therefore p1 ðS 3 tðk; ck þ 2ÞÞ ¼ hx; g j rðx; gÞi, with rðx; gÞ ¼ ðg1 ðxg k Þ 1þcðk1Þ=2 g1 ðgk x1 Þ 1þcðkþ1Þ=2 Þðk1Þ=2 g1 ðxg k Þ 1þcðk1Þ=2 . The statement derives from a straightforward application of [5, Theorem 7]. r For example, the fundamental group of the n-fold cyclic branched covering of tð5; 7Þ admits the cyclic presentation Gn ðwÞ, where 1 1 1 1 1 1 1 w ¼ x15 x20 x25 x1 24 x19 x14 x9 x8 x13 x18 x17 x12 x7 x2 x1 x6 x11 : 5 Representation of two-bridge knots In this section we give a standard representation for all two-bridge knots in S 3 . Let bða=bÞ be a non-trivial two-bridge knot in S 3 of type ða; bÞ. Then we can assume gcdða; bÞ ¼ 1, a odd, b even and 0 < jbj < a, without loss of generality (see [4, Ch. 12B]). It is known that bða=bÞ admits a Conway presentation with an even number of even parameters ½2a1 ; 2b1 ; . . . ; 2an ; 2bn (see Figure 7), satisfying the following relation: a 1 ¼ 2a1 þ b 2b1 þ 1 2a2 þþ2b1 : n Theorem 7. The two-bridge knot bða=bÞ H S 3 having Conway parameters ½2a1 ; 2b1 ; . . . ; 2an ; 2bn is the ð1; 1Þ-knot Kc with: b1 a1 n an c ¼ tb ta tb tb m t e . . . tm t e ; 1 where te ¼ t1 l tm tl tm is the right-handed Dehn twist around the curve e depicted in Figure 8. b1 a1 n an Proof. Figure 8 shows the result of the application of tb m te . . . tm te . By applying c1; 0 ¼ tb ta tb we obtain the two-bridge knot with Conway parameters ½2a1 ; 2b1 ; . . . ; 2an ; 2bn . 2b1 2a1 2bn 2an Figure 7. Conway presentation for two-bridge knots. ð1; 1Þ-knots via the mapping class group of the twice punctured torus 273 e g b a te 1 2a1 A -b1 m 2bn 2a n -bn an t m e -b 2 a2 t m ε 2b1 2b1 2a1 2a1 Figure 8. Standard representation of two-bridge knots. 274 Alessia Cattabriga and Michele Mulazzani T e b d1 g d2 z g A Figure 9. 1 Now we show that te ¼ t1 l tm tl tm (note that no disk bounded by e and properly embedded in H is disjoint from A). Referring to Figure 9, the following ‘‘lantern’’ 1 relation tg2 td1 td2 ¼ te tb tz holds (see [23]). So we obtain z ¼ ta tg t1 b ta ðgÞ and therefore 1 1 1 1 2 1 1 1 1 tz ¼ ta tg tb ta tg ta tb tg ta . Since td1 ¼ td2 ¼ 1 we have te ¼ tg tz tb ¼ tg2 ta tg t1 b ta tg 1 1 1 ta tb tg ta tb . Now, using the relations of (1) we get 1 1 1 1 1 1 1 1 1 1 te ¼ tg2 ta tg tb1 t1 a tg ta tb tg ta tb ¼ tg ta tg ta tb ta tg ta tb tg ta tb 1 1 1 1 1 1 1 1 1 1 1 ¼ tg ta tg t1 b ta tb tg ta tb tg ta tb ¼ tg ta tb tg ta tg tb ta tb tg ta tb 1 1 1 1 1 1 1 1 1 1 1 ¼ tg ta t1 b ta tg ta tb ta tb tg ta tb ¼ tg tb ta tb tg ta tb ta tb tg ta tb 1 1 1 1 1 1 1 1 1 1 1 ¼ tg t1 b ta tb tg ta ta tb ta tg ta tb ¼ tg tb ta tb tg ta ta tb tg ta tg tb 1 1 1 1 1 1 1 1 ¼ t1 m ta tm ta ta tm ta tm ¼ tm ta tm ta tm tm ta tm ta tm 1 1 1 1 ¼ t1 h ta tm th ta tm ¼ tl tm tl tm : r For example, the figure-eight knot bð5=2Þ, which has Conway parameters ½2; 2, is the knot Kc with c ¼ tb ta tb t1 m te (see Figure 10). Acknowledgements. The authors would like to thank Sylvain Gervais and Andrei Vesnin for their helpful suggestions. We also would like to thank the Referee for his valuable comments and remarks. Work performed under the auspices of the G.N.S.A.G.A. of I.N.d.A.M. 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