707 Internat. J. Math. & Math. Sci. Vol. i0 No. 4 (1987) 707-724 ON MEASURE REPLETENESS AND SUPPORT FOR LATTICE REGULAR MEASURES GEORGE BACHMAN Department of Mathematics Polytechnic Institute of New York Brooklyn, NY 11201 U.S.A. P.D. STRATIGOS Department of Mathematics Long Island University Brooklyn, NY 11201 (Received ABSTRACT. October 31, 1984) The present paper is mainly concerned with establishing conditions which .assure that all lattice regular measures have additional smoothness properties or that simply all two-valued such measures have such properties and are therefore Dirac measures. These conditions are expressed in terms of the general Wallman space. The general results are then applied to specific topological lattices, yielding new conditions for measure compactness, Borel measure compactness, clopen measure replete- ness, strong measure compactness, etc. In addition, smoothness properties in the general setting for lattice regular measures are related to the notion of support, and numerous applications are given. - KEY WORDS AND PHRASES. Support of a measure, repleteness, realcompaetness, and completeness, mease completeness, measure compactness, and Borel measure compactness, clopen measure repleteness, strong measure repleteness, strong measure compactness, etc. 1980 AMS SUBJECT i. CLASSIFICATION CODES. 28A60, 28A32. INTRODUCTION. In an earlier paper [5], we obtained conditions for o-smoothness, T-smoothness, and tightness of lattice regular measures. This was done in a general framework for a set X and a lattice of subsets of X, i, which was just disjunctive and at times separating. which are not The general approach was adopted so as to fit many topological lattices 6 or not normal. This approach was made possible by utilizing gen- eral lattice regular measure extension theorems (see [4]). Thus it was possible to bypass the general Alexandroff Representation Theorem [2] in which a delta normal lattice is needed. The results were then expressed in terms of IR(i)-X, where IR(i) is the general Wallman space associated with the set X and the lattice These results generalized known results pertaining to Baire measures and where 8X is the Stone-ech compactification of the Tychonoff space X. [. 8X-X, In particu- lar, our general approach lead to new results pertaining to smoothness and tightness G. BACHMAN and P.D. STRATIGOS 708 T of closed regular Borel measures in just mX-X, where of mX X is the Wallman compactification of and also to clopen regular BoX-X, spaces expressible in terms of o-dimensional T Borel measures in topological spaces expressible in terms BoX where X. is the Banaschewski compactification of In the first part of this paper we utilize the framework of the previously mentioned paper and obtain new results for lattice repleteness, measure repleteness and strongly measure repleteness. We then apply these results to specific topological lattices and obtain new conditions for measure compactness, Borel measure compactness, and clopen measure repleteness and similar facts for strongly measure compactness, strongly Borel measure compactness, and strongly clopen measure repleteness. (See, in particular, Theorems 2.4, 2.6 and their consequences and associated examples.) It is advantageous to be able to characterize various repleteness properties in We pursue this in general in the second part of terms of support of certain measures. the paper. L We cite here just one of the more important results (see Theorem 3.3): L is separating and disjunctive, then o-smooth, L-regular measure (which is not the zero measure) is nonempty. has many applications. If is measure replete iff the support of every This result Thus, in this part of the paper, we concentrate on various as- pects of support of a measure. 2. TERMINOLOGY AND NOTATION. Most of the terminology used in the present paper goes back to Wallman [10] I. Some of the more recent terminology appears inNoebeling [7] and Alexandroff [l], [2]. For the reader’s convenience, in this part we and Frolik [6], as well as in [5], [8]. will collect some of the special terminology which is used throughout the paper. X Consider any set of X L generated by L ated by measure on is dnoted by A o{LI. M(L). Igl(X)} <An>, if L <An > M(L), for , M(L), in L is decreasing and is denoted by L-(T-smooth) iff for every (L) 0. net in lim n M(L) M(o* L). L, gener- A. X, g S(). A{LI, E L M(L) which L-(o-smooth) An ’ then < L > A{L An element of Ig(E)-g(L)l E and is M(L), L-regular < e. is denoted by iff for every sequence in n) lim g(A n L-(o-smooth) M(L) which An element of M(L) g > is de- for every positive num- which is if < L A is the support of The set whose general element is an element of < A > n then lim R, such that to such that is said to be whose general element is an element of M(o,L). A and is denoted by L there exists an element of An element of X whose general element is a measure on The set The set whose general element is an element of MR(L). A{LI, The algebra of subsets Next, consider any algebra of subsets of L-regular iff for every element of g, is said to be L. The o-algebra of subsets of For the general element of L/Ig l(e) n{e e fined to be ber, e A{LI. is defined to be a function, g, from bounded and finitely additive. is denoted by X, and any lattice of subsets of is denoted by 0. The set is denoted by is o-smooth just is said to be is decreasing and lim L =4, The set whose general element is an element of is said L-(-smooth) is denoted by M(,L). An element of M(L), an exists there number, g M(o,L) and for every positive to be L -tight iff M(L) which is L-compact set, , K, such that Igl,(K) < The set whose general element is an ele- SUPPORT FOR LATTICE REGULAR MEASURES M(6) 709 6-tight is denoted by M(t,6). The set whose general such that (A([)) {0,i}, that is, the set of 0-I element is an element of (6), measures is denoted by I([). 6 is said to be replete iff whenever an element of 1(6) belongs to 6 is said to be prime complete iff whenever an element of IR(o,6), then S() # 6 is said to be measure replete iff I(6), belongs to I(o*,6), then S() # MR(o,[) MR(r,6). [ is said to be strongly measure replete iff MR(o,6) MR(t,6). ment of which is , . . Next, consider any topological space 0, its collection of open sets by Z. tion of zero sets by X and denote its collection of closed sets by In case X is replete. X is said to be s-complete C is replete. X X X M(6), elements of II. ,, and its collec- is replete. X is said to be N- is said to be measure compact iff M(6) C F Z is is measure replete. is measure replete. is expressible as the difference of nonnega- without loss of generality, we shall work with nonnegative M(6). Among the principal tools utilized in the present work are three measures in- M(6), denoted by duced by the general element of and ’) ,, and certain criteria for which are expressed in terms of (these measures are denoted by o-smoothness, ’. or r-smoothness, or tightness, (See [5].) , For the reader’s convenience, in this part we collect thedefinitions of0, ’ Z is said to be realcompact iff is said to be Borel measure compact iff Since every element of rive elements of F iff Moreover, is said to be clopen measure replete iff NOTE. X T3, is compact iff measure replete. C, its collection of clopen sets by and and we summarize (in the form of a theorem) the principal facts pertaining to the criteria mentioned above. Preliminaries. that < 6 is separating and disjunctive. IR(6), tW(6) and [9]). > Consider the function IR(6). identified with It is known that the topological space T it is 2 iff 6 . Consequently Then is a IR(6) < t6, tW(6) I} W(A). # Moreover, X. Moreover, 2. For every two W(A u B) ) 8) 3. A{6), A, W(A)’ elements of A{61, A, B, For every element of B) W(A y) If A 6) e) If W(A) A(6) {W(L); L A B iff W(B), W(A) W(A) then is 6} is denoted by W(A’). W(B). A{w{L) 6 (X) A. W(B); A B; (Note all these statements are true, if and by W(A) u W(B); W(A) W(B); B, then X In case (X) Proposition I.I. I. is > -homeomorphlsm. IR(6). Denote the general element of is denoted by X. is a compactificatlon of is said to be embedded in Definition of (See e.g., [4] is normal. is topologically identifiable with X, X { IR(6)/(A) w(L). x X, 6, such and any lattice of subsets of which is such that the domain of X, x, (x) For this reason, (X) (i) TI; is compact and for every element of dense in X Consider any set is just disjunctive.) Then is G. BACHMAN and P.D. STRATIGOS 710 M(L), Next, consider any element of which is such that and the function (A). is A(W(L)) and for every element of A(W([)), W(A), (W(A)) E MR(W([)). Conversely, consider any MR(L), then M(W(L)) and if is and he function element of M(W(L)), whic is such that the domain of M(L) and (W(A)). Note A{LI and for every element of AILI, A (A) MR(L). E MR(W(L)), then and if Note since W(L) is compact, MR(t,W([)). MR(,W([)) MR(o,W(L)) MR(W([)) MR(o,W([)). Hence MR(W([)) Then Next, consider any element of MR(L), the domain of Note E 6W(L)-regular. (ii) ’. I} sets, uniquely, and the extension is for this extension. Continue to use Definition of IR(o,f)/(A) { *-measurable o-algebra of is extendible to the A{LI Denote the general element of Wo(A}. is denoted by {Wo(L); Moreover, A. by L} L Then is denoted by w ILl. If, in each statement of Proposition I.I, REMARK. W o, the is replaced by W resulting statement is true. M(L), Next, consider any element of ’ ’ A(Wo(L)) Note M(Wo(L)) and if any element of M(Wo(L)), the domain of (A). consider domain of M(L) then is A{LI is ’ and MR(o,L) e MR(Wo([)), ’ e Conversely, which is such that the A{LI, A o(Wo(A)). (A) MR(L). then ’(Wo(A)) (A), MR(Wo(L)). and the function and for every element of and if ’ MR(L), then which is such that Note MR(L), e Moreover, if MR(o,Wo(L)). Definition of (iii) Consider any set Lemma I.i. such that iff E ’ A(Wo(L)), and the function and for every element of L MR(L2)’ 2’ c2" For every element of such that 21 A(L I) i MR(LI), I’ and if L [I’ X, and any two lattices of subsets of X there exists an element of L 2, then separates 2 is unique. (See [2].) Next, consider any set disjunctive. X . and any lattice of subsets of Consider any element of MR(L), Lemma I.i, there exists an element of MR(tw(L)), Then X, L is Hence, by IA(w(L)) uch that L such that MR(W(L)). and is unique. tW(L), because W(L) is compact, tW(L) is compact, MR(,tW([)) MR(t,tW(L)). MR(tW(L)) MR(o,tW(L)) is extendible to the u-algebra of MR(o,tW(L)). Hence Consequently, measurable sets, uniquely, and the extension is tW(L)-regular. Continue to use W(L) since separates Note since *- for this extension. THEOREM 1.1. t Consider any set is.(separating) and disjunctive. I. g E *(IR(o, L)) MR(o,L) iff (IR([)). O*(X) X and any lattice of subsets of For every element of O(IR(L)); equivalently, X, L, such that MR(L), u: E MR(o,L) iff 711 SUPPORT FOR LATTICE REGULAR MEASURES 2. MR(,L) 3. ’ MR(T,wo(L)) 4. L If (IR(L)) iff *(X) (IR(L)). *(IR(o,L)) iff (IR(L)). T 2, then is also separating and normal, or X and L, iff for every sequence in " i < >, if iff 0" " W(L i) X) or to is decreasing and gi *(X) MR(o,L) e MR(o,L) IR(L) -g (For more details refer to [I].) parts. 3. < L e Similarly, equivalent statements are obtainable for the other 0". [W(Li)) *(X) iff *-measurable. is We not for example, that the statement of part I, (IR(L))" is equivalent to "p e MR(o,L) iff ,(IR(L) then MR(t,L) p NECESSARY AND SUFFICIENT CONDITIONS. In this section we work with an arbitrary set X L L b) L X, sets of such that sufficient conditions for and an arbitrary lattice of sub- is separating and disjunctive and we give necessary and to be a) LindelSf, replete, c) measure replete, d) strongly measure replete. a) LindelSf property. The following statements are equivalent: Theorem 2.1. i. L 2. For every subset of L, A, A*, is LindelSf. there exists a subset of {W(L); n{W(La); e A*} A} IR(L) IR([) X Consider any subset of L, A}, if {L; such that X, then A* and countable. {W(L); that L A* X. L Since is disjunctive, Consider any such A*. Then a e A} {L A} {L; A* A, is Lindelf, there exists a subset of is countable. Consequently B) IR(L) A} a Hence, since and Assume i, and show 2. ) Proof. A*} such CA} n{L such that n{W(La); . is IR(L) -X. 2 is true. (Proof omitted.) Conversely, assume 2, and show i. L Assume Corollary 2.1. Then the follow- is normal and countably paracompact. ing statements are equivalent: of i. L 2. For every element of is Lindelf. Z(tW(L)), K0, a) Proof. K IR([) K {W(L); X. tW([), K, if K K IR(L)-X. 0 Assume 1, and show 2. A}. tW([), there K Since a K such that Consider any such IR(L)-X, then there tW([), K, such that Consider any element of [, exists a subset of A}. {L; Then exists an element {L a e {W(L); A}, A} such that IR(L) -X. such by Theorem 2.1, there exists a subset of A, A* such X and A* is countable Consider any IR([) a e that Since [ is normal and countably paracompact, by [5], Theorem 2.2, part 2, there A*} K 0 IR(L) X. Conexists an element of Z(tW(L)), K 0, such that Hence, since L is LindelDf A* A* o{W(La); n{W(L);a sider any such B) such that K0 Then K K0 IR([) X. Consider any subset of Conversely, assume 2, and show o{W(La) A} IR(L) X. Consequently 2 is true. Set {W(Le); A} K. L, {L Then K e A}, IR(L)-X. G. BACHMAN and P.D. STRATIGOS 712 Z(tW([)), K 0, such Then, since 2 is true, there exists an element of X. IR(i) tW(/), there Ln A} n[W(L ); a n{W(La); ; n) W(L Ln /, hence > a tW(i)-compact and a is 0 K such that E A} n{W(Ln)’ W(i) since o{W(Ln)’; 0 N}. n a K 0 G6-set n E of N}. Hence for every there exists an ele- is compact W(Ln)’;.consider any such n" n’ such that W(L n A} and {W(L ); n N}co{W(Ln)’; n N} K0 IR([) a A, ment of {L 0. Then >" K Then, since exists a sequence in Consider any such n K Consider any such K that {L Then a n N} n X. Then, by Theorem n L R. 1, is LindelBf. (I). Examples. Z. [ X Consider any topological space X, is T3 and is LindelDf iff for every closed subset of Then, by Corollary 2.1, X there exists a zero set of X such that KO, K0 K such that let BX-X, K, (This result is well- 8X-X. kno). (2). Consider any topological space arid let of Then, by Corollary 2.1, K, there exists a zero set of 80X-X b) C. [ such that X is LindelDf BoX and O-dimensional iff for every closed subset K such that K0, T is K BoX-X 0 Repleteness. Le 2.1. Consider any lattice of subsets of , ([), (,L). every element of I. 2. X X For every net in X, [ [ such that is . For the following statements are equivalent: L L > L > A}, if if *(nL is decreasing, then (n). inf 3. a) V (0L inf [ {L a {L = A} is a filter base, then (See [8].) (La). The following statements are equivalent: Theorem 2.2. i., L For every subset of is replete. IR() X, then there exists an eleV IR([) -X. ment of o(W([)), B, such that V and consider any element X # Proof. a) Assume I, and show 2. Assume IR([) X. Consequently X. Since [ is replete, IR(o,[) Then X, of IR([) > that < L i > Is desuch L IR(,[). Hence there exists a sequence in [ i 2. For every element of IR(), V, if B . creasing and i, (Li) ’ limi Li I. but Consequently limi v(Li) W(L i) O. Consider any such IR([) -X and io W(Li) <L.1 >" Note for every o(W([)). Conse- . . quently 2 is true. is replete, it suffices to ) Conversely, assume 2, and show I. Note to show element of IR(o,[) -X, any Consider X Assume IR(o,[) X show IR(o,[) IR([) -X. Hence, since 2 is true, there exists an element of o(W([)), Then X. Consider any such B. IR([) B B, such that . (i) Since ([), the extension of sets (also denoted by ) is 6W([)-regular. to the *-measurable sup{(K)/K W([) o-algebra of Consequently (B) 713 SUPPORT FOR LATTICE REGULAR MEASURES 6w(L), Consider any element of B}. K and O. Hence, by Theorem I.i, part I, (K) n{W(L)/L e IR(L), {x,} (ii) Since -X. *({}) 2.1, t COROLLARY 2.2. L, sequence in L and (W(L)) L , (B) ({u}) u X IR(o,[) Consequently ed. IR(/) K Then O. (B) Hence, by Lemma I}. I. Consequently (iii) B. K K, such that Consequently [ and is replete. is replete iff whenever >, such that i L Thus a contradiction has been reach- 0. IR([) b X, then there exists a oW(Li) IR(L) X. ’is decreasing and H (Proof omitted.) F, F i > F such that > i X such that T is F. [ and let X, then there exists a nF X, where X i mX X is a-complete iff whenever Then, by Corollary 2.2, sequence in X Consider any topological space Example. is decreasing and the closure is taken in X. COROLLARY 2.3. [ Assume Then the follow- is normal and countably paracomDact. ing statements are equivalent: I. [ 2. For every element of is replete. a) Proof. IR([) -X, [, quence in . K 0 Assume I, and show 2. L.I >. Consider any such IR(L) Assume L. such that i X. 8) Assume [ Then, since K Consider any such Conversely, assume 2, IR([) X in tW(L), every of < H K Z(tW([)), an K i, show i. 7(tW([)), [ H.l i’ Li’ K 0. Hence Then ing. K i K ni’ > is a H’. 0 K IR([) 0 [ To show W(L i) 0 and K0, G-set Z. Then, by Corollary 2.3, there exists a zero set of is known. Consequently 2 is true. t|at 1 . < L i > X BX, K 0 is X, Then, since 2 is e K IR([) 0 tW([), there of tW(L), separates Hi W( i) H and Then for W( i) W(L i) e such that realcompact iff whenever e K 0 BX Con- exists a sequence i Consequently K X X. there exist two elements is decreasing and such that 0 is replete, use Corollary 2.2. X. iH"i W(Li) 0 L. Without loss of generality, assume that and K .W(Li) Xo such that i; then K0W(Li ) W( i) ’H i’. is in [5], such Consider any such W(L) X. IR([) W(Li) e KO, IR() Hence, by Corollary 2.2, [ is replete. Examples. (I). Consider any topological space [ 2.2, there exists a se- i hence, since oW(Li)’i 0 < L ’ such that consider any such K0 Then, since such that i n 0 K and consider any element of 0. and consider any element is normal and countably paracompact, by Then O. true, there exists an element .of sider any such X # is decreasing and Theorem 2.2, part 2, there exists an element of IR([) X, then there exists an ele- is replete, by Corollary Then, since < L IR([) IR([) -X. if Z(tW([)), K O, such that ment of of IR([), 0W(Li) i X is e > is decreas- IR([) T31/2 X. and let BX- X, then (This special case G. BACHMAN and P.D. STRATIGOS 714 (2). Consider any topological space X such that X L C. Then, by Corollary 2.3, X is N-compact BoX KO, then there exists a zero-set of X X nH H’ Consider any such tW(L). of G6-set L.l >. any such L 2.2, L L To show Hao o(W(L)) IR([) i IR(L) i) Since HO tW([), L, B) of Corollary 2.3.) e 0W(L . X, A, a O, such that there exists a sequence in and A}, is replete, use F -set of is an a e Li > < Consider Hence, by Theo- X. {Ke; Z(tW([)), If there exists a subset of A}, a such that e e A} {K tW(L). a, K’a is an Fo-set A}, a of tW([). oK’. X such that Z(tW(L)), K a, since Note for every Hence for every {Ka; Z(tW([)), K is a Then, by Corollary is replete. c) Measure repleteness. W ILl). ’ Next for the general element of 1}. (W (L)) . Consider any element of ’, (L) by the definition of S(’) IR(L), IR(o,W ([)), IR(,[) Note for every element of Observation. and A}, a is replete. Consider any such 2.4, A}. E H’O, e Proof. Assume there exists a subset of of {H=; {Ha; tW([), -sets of (See the proof of part 0W(L i) X, X. tW(L), -sets of BoX E is replete. K’, then G-set F i COROLLARY 2.5. X {Ha; Then, since 0" Then, since Then BoX 0 Consequently there exists an element of H’ nW(Li) i e such that X K and consider any element of X # uH’ IR([) is a rein IR(L) nH 0 F and 0-dimensional iff whenever is replete. Consider any such Assume Theorem 2.2. e L Assume there exists a collection of such that X then 0H Proof. E If there exists a collection of COROLLARY 2 4 such that such that T is and let Consequently L If Summarizing: I. W (L) o L, L Consequently ’ W(L). ’ (Wo(L)) Hence ’ IR(, n{W (L)/L S(’) note such that iff I. S(’), Then, so is replete. is disjunctive, then W (L) is replete. We will obtain a necessary and sufficient condition for W (L) to be measure re- plete. Preliminaries: ’ such that According to MR(,W([)). [5], Theorem 3.2, Theorem 2.3. I. W (L) 2. M{L} Proo@. show MR(,L) Consider the set whose general element is an element of a) This set is denoted by part R([). MR([), (See [5], P. 1517.) I, PR([)= MR(o,[). The following statements are equivalent: is measure replete. Assume 1, and show 2. R(L). Note to show Consider any element of R(L) MR(o,L), . MR(o,L), it suffices to ’ (o,W (L)). Then SUPPORT FOR LATTICE REGULAR MEASURES W (L) Since p’ e (,W (L)), o MR(o,L). quently (L) B) asume Conversely, COROLLARY 2.6. I. R(L). M(L). MR(o,i) Hence MR(T Wo([)). Conse- Consequently, (Proof omitted.) 2, and show 1. The following statements are equivalent: is measure replete. [ 2. R([) is replete and IR(o,[) X. L. o is measure replete, [ [ SiTce W ([) Consequently, Wo(L) assumption, MR(o,[). Assume 1, and show 2. ) Proof. Hence p e so (o W (L)) by assumption is measure replete 715 M(L) Then,by Theorem 2.3, is measure replete. is replete. is measure replete, by [ Hence, since MR(o,[). Conse- quently 2 is true. Z. L MT(Z) Consider any topological space (i). Examples. let (Proof omitted). Conversely, assume 2, and show 1. B) X such that X is measure compact iff X Then, by Corollary 2.6, X and T31/2 is is realcompact and m(o,Z). (2). Then, by Corollary 2.6, X T F. [ and let such that X is is Borel measure compact iff X is -complete and such that X is X Consider any topological space R(F) MR(o,F). (3). and let C. compact and R(C) is N- X MR(o,C). for every element of MR([), For every element of {W(L); A} {W(L );e and Since 6W([) Note 6 is inf MR(T,tW([)) and (W(L {W(L )- )) Hence tW([), K The condition "[ tW([) (K). tW([), K L and W(L) Set {W(L)/L MR(,TW([)) and {W(Le) e by Lemma 2.1, inf (W(L )). e A} Hence, by eemma 2. I, inf (W(L )) e and is a filter base IA{W{[II o Remark. K}. L and W(L) n{W(L)/L a e A}. and any element of MR([), Consider any element of tW(L), K e 0-dimensional and =fi(K). Proof. K T is clopen measure replete iff Then, by Corollary 2.6, X Lemma 2.2 fl*(K) X Consider any topological space _and 6*(K) tW([) Now, note {W(L ); Consequently inf e A} *(K) Since K} A} 6W(L) (W(Le)). is and is a filter base (K). is separating and disjunctive" was not needed in the proof. IR([) , Observation. For every element of THEOREM 2.4. The following statements are equivalent: i. [ 2. For every element of Lemma 2.2, MR(,[). p* e *. (Proof omitted.) is measure replete. X, then Proof. ) element of MR([), *(K) MR(o,[), for every element of tW(), K, if K O. Assume i, and show 2. Consider any element of MR(o,[), and any such that K IR([) X Since K tW([) and p MR([), by *IK (K). Since [ is measure replete, by assumption, MR(o,[) tW(L), K, Consequently Theorem i.I, part 2, (K) (MR(T,[). 0. Hence, since Consequently *(K) K tW([) and K IR([) 0. Thus 2 is true. X, by G. BACHMAN and P.D. STRATIGOS 716 ) Conversely, assume 2, and show I. MR(o,L) suffices to show MR(,L). [ Note to show . is measure replete, it MR(,L), tW(L), K Consider any element of To show MR(,L), use Theorem I.i, part 2. *(K) D(K). E MR(L), by Lemma 2.2, tW(L) and IR(L) X. Since K O. IR(L) K X and tW(L) and K MR(,[), by the assumption, *(K) MR(,L). Hence MR(o,L) 0. Then, by Theorem i.I, part 2, quently (K) (T, L). Consequently L is measure replete. Consider any element of E such that K In this connection, we note Remark. L L2 and any element of . IA(LII * B* Then MR(,L2) LI, X, IA{[) such that iff L2 MR(,LI). such that Set L on (Proof omitted. COROLLARY (). For every element of MR(L), iff on Proof. Consider any element of MR(L), Now, use Proposition 2.1 with . L2 W(L), tW(L), * tW(L). L D. COROLLARY (B). MR(o,L) Conse- following useful result: .the Consider any two lattices of subsets of Proposition 2.1. Since For every element of implies E MR(L), (Proof omitted). COROLLARY 2.7. If for every element of exists an element of * if MR(T,L). (W(L)), B such that tW(L), K K B K D on tW(L)’, then IR(L) X implies there X, then L is measure IR(L) replete. Assume for every element of Proof. exists an element of tW(L), K K (W(L)), B IR(L) X implies there IR(L) X. To show L is mea- such that K B sure replete, use Theorem 2.4. Consider any element of MR(o,L), and any element of tW(L), K such that K IR(L) X. Then, by the assumption, there exists an element of (W ()), B, such that K B IR(L) X. Consider any such B. Then *(K) (B). Moreover, since E MR(,L) and B (B) O. (See the proof of Theorem 2.2, part ). b L Theorem 2.4, REMARK. (W(L)) and Consequently B IR(L) *(K) X, 0. Then is measure replete. Corollary 2.7 is the measure repleteness analog of Theorem 2.2 for re- pleteness. Observation. o(Z(tW(L))) Z. set of o(W(t)), o(Z(tW(t)),c o(W(t)). IR(L).) Z(tW(t)) is the class of Baire sets of (I). Examples. L Since, In general, Consider any topological space If for every closed subset of BX, B such that K B BX X such that X is T31/2 (Note and let BX, K, K BX X implies there exists a Balre X, then, by Corollary 2.7, X is measure com- pact. (2). Consider any topological space X such that X is T and let t X, K K X X implies there exists a Balre set of X, then, by Corollary 2.7, X s Borel measure compact. Consider any topological space X such that X is T and 0-dlmenslonal If for every closed subset of X, B . such that (3). and let L a Balre set of K B X If for every cosed subset of BoX, measure replete. B, such that KCBC BO BOX, K,.K BoX-X implies there exists X_X, then, by Corollary 2.7, X is clopen SUPPORT FOR LATTICE REGULAR MEASURES THEOREM 2.5. and The following statements are equivalent: I. L 2. For every element of is measure replete. , A} n{La; 717 (n{L MR(u,[), A, A *, such that then there exists a subset of A*}) L, for every subset of A}, {L; if A* is countable 0. (Proof omitted.) REMARK. is separating and disjunctive" is not needed in the "/ The condition proof of this theorem. d) Strongly measure repleteness. THEOREM 2.6. L If is normal (or T 2) and a(W(/)), then Lis strongly X mea- sure replete. Assume Proof. [ is normal (or T 2) X and a(U(i)). [ Note to show is (t,/). Consider any eleMR(o,[) (t,i), use Theorem 1.1, part 4. Since X strongly measure replete, it suffices to show ment of MR(o,[), u. (W(L)), X To show *-measurable. is U *(X) Moreover, 0(X), since (X), since O*(X), *(X) (IR(L)) T2) and normal (or i Consequently Examples. [ Z. If X and X is *-measurable. Then, since by Theorem I.I, part 4, MR(t,[). is strongly measure replete. (I). Consider any topological space is a Baire set of X Io(W(i)) [ *-measurable, X is since (IR([)), 5 (IR([)). *-measurable, X is since Consequently is separating, disjunctive, Hence X such that 8X, then, by Theorem 2.6, X MR(t,[). MR(q,[) is T31/2 and let is strongly measure com- pact. (2). Consider any topological space T and let i F. If 2 Borel measure compact. X L C. If X s such that a Bare set of X X is T31/2 and normal or simply X, then, by Theorem 2.6, X is a Baire set of (3). Consider any topological space and let X such that BoX, then, X is T and by Theorem 2.6, is strongly O-dimensional X is strongly clopen measure replete. 4. REPLETENESS PROPERTIES. It is advantageous to be able to characterize various repleteness properties in terms of support of certain measures. In this section we pursue this matter in general Consider any set X and any lattice of subsets of X, [ such that L is separating and disjunctive. ) Repleteness and support. Preliminaries. Consider the set whose general element is an elemen of MR(1), such that whenever 0 e IR(i) IR(o,[), then there exists an element of tW([)’, O such that 0 O and (O) O. This set is denoted by R([). (See [I], p. 1519.) Next, consider the set whose general element is an element of MR(L), such that whenever 0 IR([) X, then there exists an element of tW(L)’, O such that O O and (0) O. Denote this setbyMR(i). Note MR(L) # and MR(L) R(i). G. BACHMAN and P.D. STRATIGOS 718 LEMLMA 3.1. For every element of (L), u, p e MR(L) iff S() X. }(i), p. Now, consider any element of S(), p. (Note, since tW(L) is compact, S() # .) Then, since S() IR(/), p IR(L). Assume p X. Then p IR(L) -X. Hence, since u E MR(/), by the definition of {(L), there exists an element of tW([)’, O such that 0 and 9(0) 0. Consequently, p S(). Thus a contradiction has been reached. Consequently S() c X. 8) Consider any element of MR(L), such that S() X. Assume IR(L) X# and consider any element of IR(L) S(). Consequently there exists X, p. Then p an element of tW(/)’, 0 such that p E O and (0) O. Then, by the definition of MR(L). MR(L), u COROLLARY 3.1. For every element of MR(L), p p MR(L) iff S(p) S(). Proof. ) Consider any element of MR(L), p. Since }[R(L), exists and S(p) S() X. Since p E R([), by Lemma 3.1, part ), S() X. Consequently s() s(). e) Proof. 8) S(p) Consider any element of Consider any element of X, S() X. COROLLARY 3.2. MR(1), such that V Then; by Lemma 3.1, part 8), S(U) MR([). S(). Then, since MR(,[). MR([) To show U MR(1), fl(,[), use Theorem I.I, part 2. Consider any element of tW(1), K such that K IR(/) X. Since p MR(L), by Lemma 3.1, S() X. Consequently K n S() Moreover, since S()= I and (W(L)) o{W(L)/L (IR([))}, by Lemma 2.1, (S()) (IR([)). Consequently (K) 0. Then, by Theorem i.I, part 2, p MR(,[). Hence MR([) MR(,[). Proof. Consider any element of . Proof. is replete iff R([) By [5], Theorem 3.5, part 3, I X. By Lemma 3.1, for every element of THEOREM 3.1. S() [ sequently / i) L If R(L). R([) is replete iff THEOREM 3.2. R(/). is replete iff whenever MR([), , p E R([) (Recall that, in general, is replete, then for every element of R([), p iff S() X. then Con- R(/)c R(/).) M(/), S(’ )= s(). 2) If for every element of 1) Proof. S() S(p’) S() 0 IR(o,[). S(B). X Hence, since S(p’) Consequently assume the contrary. [ IR(o,[), V, S(V’) {B} S(p’) S() [ is replete. M[), S() n X. / is replete, S(p’) V Then Further, note . . IR(o,[) Then and S(V), then Consider any element of is replete. Assume for every element of 2) Then [ Assume S(p). S(’) S(). To show / is replet IR()[), B Consider any element of IR(o,/) X # X, Thus a contradiction has been reached. Consequently is rep.lete. 8) Measure repleteness and support. The purpose of the following example is to show that the condition "there exists an element of MR(o,/), such that S(9) # measure replete. sider L Example. Assume e) IR(/) X, and denote it by v. Since is not compact. " Then Consider any element of B + x E . is not sufficient for X # and any element of IR(/) IR(/) and x i to be X, x. Then, conIR(L) (because L is 719 SUPPORT FOR LATTICE REGULAR MEASURES Consider any element of 2. Consequently + . (L) + S(), and S() MR(,L). Next, show x quently X. L. Conse- Px’ p Then, since is separating and disjunctive, [ Thus a contradiction has been reached. X. Consequently Since x i, and +x(X) (X) (X) Then (L) x(L) MR(,L). Assume IR(,/). p Consequently MR(z,L) IR(,L) x(L) Hence 2. (X)}. [/(L) {L S() By the definition of support, (X). [, L such that (L) MR([). disjunctive), Consequent- MR(,L). ly 8) [ Assume a) (as in part X, x and Consequently MR(,L) (see part )). any element of X, and MR(o,i), , e MR(o,/), S() but Then , IR(o,L) Consider any element of IR(o,/) # X. Then is not replete. S() i is not , measure replete. IR(z,[). then v S() in terms repleteness measure for condition sufficient and We will give a necessary IR(o,[), v For every element of Observation. if of support. Consider any set LEMMA 3.2 MR(L), any element of call w(L)-regular and is IR (L), H. an X, [. Consider on o(tW(L)). (Reo(W(/)) and any subset of consider tW(L)-regular.) Next, and lattice of subsets of on is Then , There exists a countably additive measure on Case I: 0 < O < O Case 2: 0 < O < X and the measures , W(L)-regular, and is p(H) o(IR(L)) There exists a countably additive measure on tW(L)-regular, and is O o(H) o(W(L)), p, such that (H). o(tW(L)), such that (H). =p(IR([)) (See [5], Lemma 4.1.) i. L 2. For every element of is measure replete. t Sine Hence . is measure replete {0}, MR(o,L) Assume i, and show 2. ) Poof. MR(o,L) S() {0}, HR(o,L) MR(z,L) {0}. Consequently MR(,L). MR(o,L) MR(,L). , Consider any element of S() @ ) Conversely, assume 2, and show i. fices to show . The following statements are equivalent: THEOREM 3.3. Note to show [ Consider any element of MR(,L). Then, by Theorem i.I, part 2, there exists an K X and (K) IR(L) 0. Consider any such K. there exists a countably additive measure on o(tW(L)), p *(K). Consider any tW(L)-regular, and o(K) O (IR(L)) and the element of M(L), v which is such that that O[A(W(L)) OIA(W{LI MR(W(L)). Show v such tat < W(L i) MR(o,L). ei > o(W(L)) and Since 0 < Uniqueness of Extension W(L i) (by 01o(W(L}I OIo(W(L) <- Io(w(L) ). Consequently Then, by Lemma 3.2, Case 2, such that such . 0 < p -< , is O Now, consider 0. 0[A(W(L)) Consider any sequence in IN(L) since , element Assume {0}, such of tW(L), K Note MR(L). Use Theorem 1.1, part i. is decreasing and i p(0.w(el)). Consequently is measure replete, it suf- MR(o,L) OIo(W(L) X, and show . (w(el)) Uniqueness of Extension), Further, note -< lo(W([)) Consequently L, < L 0. , i >, Note (W(LI)) i (W(LI)) i by G. BACHHAN and P.D. STITIOS ?20 P(nW(Li))i (nW(Li))’i -< (D.W(Li)) Consequently . (IR(i)) s() # Further, note tw(L), A(tw(L)) o(IR(L)) and . S(O) S(v) . 0 X. MR(o,L). u 0. Moreover, This theorem generalizes Remark. L 0 , (K) X, S(0) o X IR(L) K Consequently Thus a contradiction has been reached. Consequently ([) separates and X. Moreover, since Hence, since S(0)c K. 0(K), O]A(w(L)) S(0) S(9) Then, by the assumption, # 0. (K) # 0, Also, since Consequently MR(,L). MR(o,L) *(K) o(IR(i)) 0*(K) S() sequently Hence Then, by Theorem I.I, part I, 0. (0W(Li))i MR(o,L), by Theorem I.I, part I, U 1 u(X) since Since . Con- MR(z,[). U is measure replete. [8], Theorem 2.2, where it is assumed that L is MR(o,7) every element of , {0} . S() # Consider any topological space (2). . X such that Then, by Theorem 3.3, (or by [8], Theorem 2.2), X Consider any topological space (3). C. Then, and let [ ment of MR(o,C) y) S() # {0}, MR(o,) element of . by Theorem 3.3, X {0}, S() # X T31/2 is and let is measure compact iff for Then, by Theorem 3.3, (or by [8], Theorem 2.2), X Z. [ X such that X Consider any topological space (I). Examples. X is F. [ and let T is Borel measure compact iff for every such that X is and 0-dimensional T is clopen measure replete iff for every ele- Other properties of support. The following statements are equivalent: Theorem 3.4. I. [ 2. For every two elements of S() then is regular. M([), < if [ on and (X) (X), S(). such 9 Assume i, and show 2. Consider any two elements of M([), (X), S() < on [ and (X) 9(X). Since < 9 on [ and (X) that such that x of element an exists there S(u), Then S(9). S(B) # S(). Assume {L [/(L) (X)}, there exx { S(9). Consider any such x. Then, since S() Proof. e) ists an element of Then, since and L B’ [ [, L such that 9(L) 9(X) and L. x is regular, there exist two elements of i, A Consider any such L. B A’ such that x B’ @. Consider any such A, B. Then L B’ A. Conseand A’ [ and 9(L) < 9(B’) < (B’) < (A) < (X). Consequently A 9(X) (X) reached. been has a contradiction e (X). Hence, since x (A) S(B), x A. Thus S(). Consequently S() 8) Conversely, assume 2, and show I. Note, by the assumption, for every two ele< 9 on [, then S() S(). Then, i is regular. ments of I([), 9, if c quently (Proof known, see, e.g., 6].) Remark I. The condition "i is separatlmg and disjunctive" was not needed in the proof. Remark 2. Observation measures. This theorem generalizes a known result on 0 I. Assume there exists an element of [ is regular. MR([), 9 Consider any element of such that < 9 on [ and M(i), iX) . Then (X). (See SUPPORT FOR LATTICE REGULAR MEASURES . Consider any such e.g.,[10].) S(W) is regular, by Theorem 3.4, i Then, since 721 s(). assume M(L), ment of (X) p. v(X). MR(o,L). v M([), of is regular, in it is permissible to W MR(L). p Observation 2. and element facts about the support of an checking [ Given that The significance of this observation is this: Assume L is regular and countably compact. Consider any eleS v on L such that Then, consider any element of MR(L), v MR(o,L). Consequently Since L is countably compact, MR(L) L Moreover, since is regular, S() S(9). L Given that The significance of this observation is this: is regular and M(o*,L),w,it countably compact, in checking facts about the support of an element of is permissible to assume MR(o,L). W X Consider any topological space Example. is regular and count- X such that Then, by Observation 2, for every element of M(* F) such that u there exists an element of MR(,F), thatis, a Borel measure, S(v). and p(X) 9(X) and S() Observation 3. Assume L is regular, normal, and countably paracompact. Con- on F L ably compact and let M(o*,/), sider any element of . MR(o,L), v pact, there exists an element of (See [8], Theorem 4.1) 9(X). S() Theorem 3.4, L Then, since is normal and countably paracom- s such that Consider any such v. L on 9 L Then, since (X) and is regular, by S(9). L Given that The significance of this observation is this: normal, is regular, and countably paracompact, in checking facts about the support of an element of M(o*,L), it is permissible to assume p MR(o,L). U Consider any topological space Example. X X such that is Z. [ and let T31/2 there exists an element of Then, by Observation 3, for every element of M(o*,Z), W v(X) and s v on Z and w(X) such that p MR(o,Z), that is, a Baire measure, v s(.) s(). Consider any element of v p on MR(0), F. Next, show v < F >, such that n < F any such n > Fn > Since such that v Assume p on 0 and p. and T31/2 is Note M(0). p v(X). p(X) Then v M(*,F). n) is pseudocompact, there exists a value of uF’n X. Since nl --’Fk X. Consider any such ing and v X Then there exists a sequence in F, 0. Consider 0, but lim v(F is decreasing and lim Fn n n 0, < Fn > is increasF < F > is decreasin and lim n n n M(*,F). < M(F), Now, consider any element of F. L pseudocompact and let such that X Consider any topological space Observation 4. X such n, n o n that k increasing. note since --’ limn V(Fn) MR(, there sider any such inim v(Fn) 0, exists an element of G n then G n F n o Since and for every X Fn0 Consequently, n Set > 0. 0, Gn, hence G n < F’n n > no n, if limn 9(Fn) such that < is increasing, > . G Fn then F’n X. > is Now, Then for every n, since F n n F ’; consequently n and v(Gn) > e; con- G’n G n F’n hence G. BACHMAN and P.D.. STRATIGOS 722 ’ G’n if n, if Consequently for every n n e n " Gn then o M(o*,L). F ’= X. Consequently is completely regular, it is regular; equivalently, F X is S(). S(p) Then, by Theorem 3.4, X Given that The significance of this observation is this: is M(F), compact, in checking facts about the support of an element of and pseudo- T31/2 p, it is permissi- M(o*,F). e ble to assume Hence for every n, n Thus a contradiction has been reached. Finally, note since regular. G’n then nO n The purpose of the following discussion is to illustrate the importance of consid- ering o-smoothness with respect to lattices. L L If Lemma 3.3 Assume Proof. is complement Note to show e MR(L), {(’)/ L and inf and for every element of M(o* generated, then MR(L) L) L, L it suffices to show for every element of ’ L} inf{(’ L (L) D which is such that Consider the function L, L, p(L) M(o*,L’), Consider any element of is complement generated. ’ and L}. Show for every (L). Consider any element of L, L. Note (L) N o(L). Now, show o(L) (L). Since L [ and L is complement generated, there exists a sequence in L >. Without loss of generality, < Consider any such L, L n >, such that L nL’. n n L, L element of L’n assume < and since L’n L’n > o(L) N Consequently L L If Assume Proof. M(o*,L), To show is decreasing and L, n > is countably paracompact. 0. Assume M(a*,L’) Now, show e) Since 8) Since Lemma 3 4, and L such that for every n, THEOREM 3.5. Proof. n lim L n n < Consider any such lm (Ln) and show lim (L L L M(o*,L’) n > L, L If L O. L’n L’ inf{(’)/ L, limn (L (L). Since such that < L n > L}. M(o*,L). M(o*,L’) > Conse- ’ L and M(o*, L’), Consider any element of < L is in > L M(o*,L’), L’). L < is in L L ’ n n <’> n and M(o*,L’), M(o* L’) Hence is complement generated, then is complement generated. and is decreasing and < Ln lm ()= O. lim n n Consequent- M(o* L) M(o*,L’) Note in general, MR(o,L). MR(o,L) M(o*,L’). MR(a,L). is complement generated, by Lemma is complement generated, M(o* L) . is de- > is countably paracompact, there exists a sequence Then, since M(o* L) Thus n) (L (L) + 0 L’) i (L’n is countably paracompact, then , e Then, since L) + < L) + is decreasing and since > consider any sequence in lim L n n creasing and ly L’ Note > (L). Thus (L) (L). Then o(L) MR(L) MR(L). Hence M(o* L’) Lemma 3.4. . . L’n is decreasing, (L (L) n, <L’n n L’ Next, consider L. (L’n L’) (L) L’ Consequently lm (L) lm (L quently in L Note for every L’) lim(Ln O. is decreasing. L, L Since > o(L) L 3.3, M(o*,[’) MR([). is countably paracompact. Hence, by ?23 SUPPORT FOR LATTICE REGULAR NEASURES y) M(o*,[’) Consequently M(o*,L) MR(L) n M(o*,[’) M(o,[) Note Observation. MR(o,L). MR(o,[) This result generalizes the following well-known result: X X such that is [ and let T31/2 2. MR(o,[). MR(o,[). M(o,[) Hence Consider any topological space MR(o,Z); expressed otherwise: M(o,2) Then M(o*,[’) Thus M(o,L). every Baire measure is regular. "[ Note the condition Remark. is separating and disjunctive" was not needed in the proof. Finally, we will consider the question of when the support of a measure is LindelSf. , Proposition 3.1. () S() is 8) If [ If [ MR(t,L), 6, then for every element of is y) For every element of if MR(t[), IA{[ of (compact), then for every element of M([), is Lindelof Lindelf (con,act). , MR(o,[), S() is LindelDf, then for every element if *(S()). (S()) then (X). (S()) (Proof omitted.) "[ The condition Remark. disjunctive" was not needed in the is separating and proof. Definition. [ is paracompact iff {As; A}, if u{A’" of [, e A}, such X, x a e that for every B’ a [ A} X, A’ and [, L there exists an element of is regular and for every subset then there exists a subset of u{B; A} a such that X L’ x e {B; [, and for every element of A/L’ n B’ {e and } is finite. THEOREM 3.6. . is LindelDf. S() # A}o t[ Assume Proof. Then t[ (t[)’, Hence, since t[ {0 A* A, a subset of G to show that for every n, [ Since Observation. (Proof omitted.) is disjoint. {S() S() O; 0 0 # ; Gn MR(t,t[), G, 0 S() Since 0 G n 0 < A*} . , if S(B) # is discrete, Therefore to show Gn S() {0}, . u{Oe; S(B) is paracompact. S() cuG and uGn and for every n, G n >. Note to show there exists A* is countable, it suffices and MR(t,[), by [5], Theorem 2.5, 91A{[ and L’ # S() , then is unique. (S() L’)>O. without loss of generality assume Gn is disjoint; hence {S(B) O; is countable, it suffices to show is countable; consider any element of consider any element of t[ S() such that S() To do this, proceed as follows: [, L # such that Gn >, such that G such that 9 uG and S() Since Now, consider any n. n countable. For every element of for every element of G s A}, G is separating and disjunctive, and there exists an element of 0 n is paracompact, e u{Oe, S() such that < {Oe; A}, e G and any such Consider any such is discrete. G, of there exists a sequence of subsets MR(t,[) Consider any element of is paracompact. Then there exists an open refinement of Gn MR(t,[), is paracompact, then for every element of Consider any subset of S() Note t[ If G n O; then, by assumption, O, x; then, there exists an element of [, G. BAC and P.D. STRATIGOS 724 O; consider any such (S() n O) > 0. Therefore consequently 0; ; ’ x such that Gn (proof omitted’) consequently S() Whence Examples. (Note compact. MR(,Z), X (3). Lindelf. Consider any topological space is T31/2). Let is Lindelf. by Theorem [ Z. 3.6 Let C. X such that Then by Theorem 3.6 X is T and para- for every element of (This result is known.) X such that for every element of Consider any topological space and paracompact. S () countable. 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