Low Dimensional Representations of the Loop Braid Group LB3 Liang Chang Texas A&M University UT Dallas, June 1, 2015 Supported by AMS MRC Program Joint work with Paul Bruillard, Cesar Galindo, Seung-Moon Hong, Ian Marshall, Julia Plavnik, Eric Rowell and Michael Sun 1 / 18 Outline Loop braid group LB3 Irreps of B3 for dimension d ≤ 5 Irreps of LB3 for dimension d ≤ 5 2 / 18 Braid Group B3 The 3-strand braid group B3 is a group generated by σ1 and σ2 subject to σ1 σ2 σ1 = σ2 σ1 σ2 3 / 18 Loop Braid Group LB3 The loop braid group LB3 is defined as the motion group of 3 unknotted and unlinked oriented circles in R 3 . 4 / 18 Loop Braid Group LB3 LB3 is generated by σ1 , σ2 , s1 and s2 subject to Braid relation: σ1 σ2 σ1 = σ2 σ1 σ2 Permutation relation: s1 s2 s1 = s2 s1 s2 , s12 = s22 = 1 Mixed relation: s1 s2 σ1 = σ2 s1 s2 , σ1 σ2 s1 = s2 σ1 σ2 5 / 18 Irreps of B3 for dimension d ≤ 5 Tuba and Wenzl completely classified all irreducible B3 representations of dimension d ≤ 5. For any dim ≤ 5 irrep of B3 , there exists a basis, with respect to which A = ρ(σ1 ) and B = ρ(σ2 ) act in ordered triangular form. λ1 · · · ∗ λd 0 0 A = 0 . . . ... , B = ... . . . 0 0 0 λd ∗ · · · λ1 where all nonzero entries are rational functions of λ1 , . . . , λd and γ := (λ1 · · · λd )1/d . 6 / 18 Irreps of B3 for dimension d ≤ 5 " # " # λ1 λ1 λ2 0 d = 2: A = , B= 0 λ2 −λ2 λ1 λ1 λ1 λ3 λ2−1 + λ2 λ2 d = 3: A = 0 λ2 λ2 , 0 0 λ3 λ3 0 0 B = −λ2 λ2 0 λ2 −λ1 λ3 λ2−1 − λ2 λ1 7 / 18 Irreps of B3 for dimension d ≤ 5 λ1 (1 + D −1 + D −2 )λ2 (1 + D −1 + D −2 )λ3 0 λ2 (1 + D −1 )λ3 d = 4: A = 0 0 λ3 0 0 0 λ4 0 0 −λ λ3 0 3 B= Dλ2 −(D + 1)λ2 λ2 3 3 2 2 −D λ1 (D + D + D)λ1 −(D + D + 1)λ1 p where D = λ2 λ3 /λ1 λ4 . λ4 λ4 , λ4 λ4 0 0 0 λ1 8 / 18 Irreps of B3 for dimension d ≤ 5 d = 5: λ1 ∗ ∗ ∗ ∗ 0 λ ∗ ∗ ∗ 2 A = 0 0 λ3 ∗ ∗ , 0 0 0 λ4 ∗ 0 0 0 0 λ5 λ5 0 0 0 0 ∗ λ 0 0 0 4 B = ∗ ∗ λ3 0 0 ∗ ∗ ∗ λ2 0 ∗ ∗ ∗ ∗ λ1 where all nonzero entries are rational functions of λ1 , . . . , λ5 and γ := (λ1 · · · λ5 )1/5 . 9 / 18 Irreps of LB3 extended from ρ TW Goal: For dimension d ∈ {2, 3, 4, 5}, classify the irreps of LB3 over C extended from Tuba-Wenzl representation ρ TW . That is, given A and B in Tuba-Wenzl representation, find matrices S1 and S2 such that S1 S2 S1 =S2 S1 S2 , S12 = S22 = Id S1 S2 A =BS1 S2 , ABS1 = S2 AB 10 / 18 Irreps of LB3 extended from ρ TW Strategy: 1. Find S := S1 S2 satisfying S 3 = Id , SA = BS. 2. Solve for S1 and S2 from S. "Standard solution": S = cAB for (σ1 σ2 )3 is in the center of B3 . Extending S to a rep of S3 is not always possible. An matrix S over C with S 3 = Id extends to a rep of S3 if and only if tr (S) ∈ R 11 / 18 Irreps of LB3 extended from ρ TW Strategy: 1. Find S := S1 S2 satisfying S 3 = Id , SA = BS. 2. Solve for S1 and S2 from S. "Standard solution": S = cAB for (σ1 σ2 )3 is in the center of B3 . Extending S to a rep of S3 is not always possible. An matrix S over C with S 3 = Id extends to a rep of S3 if and only if tr (S) ∈ R 11 / 18 Irreps of LB3 extended from ρ TW Strategy: 1. Find S := S1 S2 satisfying S 3 = Id , SA = BS. 2. Solve for S1 and S2 from S. "Standard solution": S = cAB for (σ1 σ2 )3 is in the center of B3 . Extending S to a rep of S3 is not always possible. An matrix S over C with S 3 = Id extends to a rep of S3 if and only if tr (S) ∈ R 11 / 18 Irreps of LB3 extended from ρ TW Let ω be a third root of unity. Proposition 2 For d ∈ {2, 3, 4, 5}, S = (−1)d−1 (λ1 · · · λd )− d AB satisfies S 3 = Id and has eigenvalues ω and ω 2 appearing in pair. In R S =U .. . R −1 U , where R = ω 0 . 0 ω2 12 / 18 Irreps of LB3 extended from ρ TW Proposition The above S induces a representation of the permutation group, that is, there exist S1 and S2 s.t. S12 = S22 = Id and S = S1 S2 . ε1 Sk = U .. −1 U , . εn φ Pk 1 .. . φ Pk m " where εi ∈ {1, −1}, k ∈ {1, 2} and Pkα 0 = φ ωk # φ −1 ω −k for any φ 6= 0. 0 13 / 18 Irreps of LB3 extended from ρ TW Theorem For each dimension d ∈ {2, 3, 4, 5}, every irrep of B3 extends to an irrep ρ (ε,φ ) of LB3 by the above S1 and S2 . 14 / 18 Irreps of LB3 extended from ρ TW Theorem For each dimension d ∈ {2, 3, 4, 5}, every irrep of B3 extends to an irrep ρ (ε,φ ) of LB3 by the above S1 and S2 . Remark There exists 6-dimensional irrep of B3 that can not be extended. 14 / 18 Irreps of LB3 extended from ρ TW Theorem For each dimension d ∈ {2, 3, 4, 5}, every irrep of B3 extends to an irrep ρ (ε,φ ) of LB3 by the above S1 and S2 . Remark There exists 6-dimensional irrep of B3 that can not be extended. Conjecture For any dimension, an irreducible B3 representation can be extended if and only if AB can be normalized to be an S such that S 3 = I and tr (S) ∈ R. 14 / 18 Irreps of LB3 extended from ρ TW Question: Are there "non-standard" solutions for S? 15 / 18 Irreps of LB3 extended from ρ TW Question: Are there "non-standard" solutions for S? Proposition Suppose matrices A and B corresponds to a Tuba-Wenzl irrep. The equation SA = BS has the general solution d−1 S= ∑ an B n AB n=0 for a0 , . . . , ad−1 ∈ C. 15 / 18 Irreps of LB3 extended from ρ TW λ1 Example: A = 0 0 λ1 λ3 λ2 λ2 0 λ3 0 0 λ2 λ2 0 λ2 , B = −λ2 λ1 λ3 − λ λ λ − λ3 2 2 1 λ2 0 0 ∗ S = a0 AB + a1 BAB + a2 B 2 AB = 0 ∗ ∗ ∗ ∗ ∗ ⇒ S 2 and (BSA)2 are skew upper triangular matrices. ⇒ 6 homogeneous linear eqns of a0 a1 , a0 a2 , a12 , a1 a2 and a22 with coefficients in C[λ1 , λ2 , λ3 ]. ⇒ a1 = a2 = 0 if (λ1 , λ2 , λ3 ) is not a zero of a set of polynomials in C[λ1 , λ2 , λ3 ]. 16 / 18 Irreps of LB3 extended from ρ TW Theorem For each dimension d ∈ {2, 3, 4, 5}, there is Jd ⊂ C[λ1 , . . . , λd , δ ] 2 such that if (λ1 , . . . , λd ) ∈ / V (Jd ), S = (−1)d−1 (λ1 · · · λd )− d AB is the only solution for the loop braid relations. Therefore, for such generic (λ1 , . . . , λd ), ρ (ε,φ ) are all irreps of LB3 extended from the given Tuba-Wenzl representation. 17 / 18 Irreps of LB3 extended from ρ TW Theorem For each dimension d ∈ {2, 3, 4, 5}, there is Jd ⊂ C[λ1 , . . . , λd , δ ] 2 such that if (λ1 , . . . , λd ) ∈ / V (Jd ), S = (−1)d−1 (λ1 · · · λd )− d AB is the only solution for the loop braid relations. Therefore, for such generic (λ1 , . . . , λd ), ρ (ε,φ ) are all irreps of LB3 extended from the given Tuba-Wenzl representation. J2 = 0/ J3 = h (λ1 + λ2 )(λ2 + λ3 )(λ3 + λ1 ) i If (λ1 , λ2 , λ3 ) ∈ J3 , S = a0 (t)AB + a2 (t)B 2 AB. 1 12 4 J4 = h δ Πn=1 Σi6=n (λi + ) i λi J5 | det(M14×14 (λ1 , . . . , λ5 , δ )) 17 / 18 Thank You! 18 / 18