Vectors (1) •Units Vectors •Magnitude of Vectors Notation B The vector AB A … as a column vector () 8 5 8 across, 5 up a The vector a Notation a The vector a 2a a This bit is a scaler a The vector 2 a Is twice as long as a, but in the same direction Displacement “a measure of distance and direction” An object moves 50m at 60o to the East-West x-axis N How far East has it gone? 50m Cos 60o = adj/hyp = E/50 E = 50 cos 60o = 25m N 60o How far North has it gone? E Sin 60o = opp/hyp = N/50 N = 50 sin 60o = 43.3m (1 d.p.) This can be expressed as a column vector:- Displacement = [] 25 43.3 Unit Vectors (1) i is the unit vector in 3 i the x-direction 2 j 1 Y i= j is the unit vector in the y-direction 0 -1 [] 1 0 0 1 2 3 j= -1 X [] 0 1 All vectors can be expressed as a linear combination of these 2 vectors e.g. displacement = [] 25 43.3 = 25 [ ] + 43.3 [ ] 1 0 0 1 Unit Vectors (2) i= [] 1 0 j= [] 0 1 All vectors can be expressed as a linear combination of these 2 vectors e.g. displacement = [] 25 43.3 = 25 [ ] + 43.3 [ ] 1 0 = 25 i + 43.3 j This is the standard way displacement vectors are presented 0 1 Magnitude of a vector The displacement of a boat is given by :- -10 i + 15 j What is it’s magnitude ? -10 i + 15 j 15 By Pythagoras, the magnitude = (152 + 102) = 325 = 18.0 (1 d.p.) The displacement is 18.0m 10 Magnitude a = -10 i + 15 j a is notation for magnitude -10 i + 15 j a By Pythagoras, the magnitude = (152 + 102) = 325 = 18.0 (1 d.p.) a = 18.0 Magnitude of a 3D Vector (1) z a 10 3 o 4 x y 4 a 3 10 Magnitude of a 3D Vector (2) z a 10 3 o B 4 3 x y 4 a 3 10 By Pythagoras, OB = (32 + 42) Magnitude of a 3D Vector (3) z By Pythagoras, OB = (32 + 42) A 4 a 3 10 a 10 3 o (32 + 42) 4 B 3 x y By Pythagoras, OA2 = AB2 + OB2 AB2 = 102 OB2 = (32 + 42) OA2 = 102 + 32 + 42 OA = (102 + 32 + 42) |a| = OA = 11.2 Magnitude of a 3D Vector (General) r a s t z a t y |a| = (r2 + s2 + t2) s o “the magnitude is the square root of the sum of the squares of the 3 components.” r x [Pythagoras in 3D]