Chemistry Study Guide – Stoichiometry Name ___________________________ Date ______________ Period _________ 1 mole is defined as ___________________ particles, also known as Avogadro’s number. Molar Mass – Calculate for the molar mass of each compound a. b. c. d. e. H3PO4 Na2S C4H10 KOH Fe2O3 f. g. h. i. j. P4O10 SI6 C6H13OH NH4NO3 Al(CN)3 Balancing Equations – Balance each of the following equations a. b. c. d. e. f. g. h. ___ Na + ___ O2 → ___ Na2O ___ Hg + ___ O2 → ___ HgO ___ Ag + ___ O2 → ___ Ag2O ___ Cu + ___ O2 → ___ CuO ___ NH4NO3 → ___ N2 + ___ O2 + ___ H2O ___ KOH + ___ H3PO4 → ___ K3PO4 + ___ H2O ___ P4O10 + ___ H2O → ___ H3PO4 ___ Cl2 + ___ H2O → ___ HCl + ___ O2 Simple Stoichiometry a. How many atoms of Na are present in a 34.5 g sample of Na metal? b. How many atoms of K are present in a 58.8 g sample of K metal? c. How many liters of O2 are present in a 60.4 g sample of O2 gas? d. How many liters of NH3 are present in a 105.3 g sample of NH3 gas? e. How many grams of HCl are present in a sample of 5.04 x 1024 atoms HCl? f. How many grams of H2 are present in a 13.2 L sample of H2 gas? Stoichiometry (SHOW ALL WORK) a. In the formation of rust, Fe metal reacts with O2 gas. If 6.3 moles of O2 gas is added to the reaction, how many moles of rust will be produced in the following reaction? 4Fe(s) + 3O2 (g) → 2Fe2O3 (s) Rust b. Consider the following balanced reaction: C6H12O6 + 6 O2 → 6 CO2 + 6 H2O If you fully react 360 grams of glucose (C6H12O6) with oxygen, then how many grams of water will you produce? c. Using the following equation: 2 NaOH + H2SO4 2 H2O + Na2SO4 How many grams of sodium sulfate will be formed if you start with 200 grams of sodium hydroxide and you have an excess of sulfuric acid? d. Using the following equation: ____ KClO3 → ____ KCl + ____ O2 i. Calculate the molar mass of KClO3, KCl, and O2 ii. Balance the equation iii. If you have 150 grams of KClO3 how many moles of O2 will you generate in the reaction? iv. If you produce 250 grams of KCl how many grams of KClO3 did you start with?