Unit 4 Measurement of Skewness 1 Objective : At the end of the course, student should be Able to : i) Define the measurement of skewness ii) Identify the measures of skewness a) Pearson’s Coefficient of Skewness 1 b) Pearson’s Coefficient of Skewness 2 iii) Sketch the data distribution based on the value of PCS 1 and 2 2 Definition of Measurement of Skewness is a measurement that shows the forms of data distribution and the direction of the frequency distribution; whether skewness to the left, right or symmetrical. 3 Definition of Measurement of Skewness The concept of skewness helps us to understand the relationship between three measures; mean, median and mode as illustrated below: Mean<Median<Mode Mode exceeds Mean and Median. Distribution is Skewed to the left (negative) Mode<Median<Mean Mean exceeds Mode and Median. Distribution is Skewed to the right (positive) Mean=Median=Mode Distribution is Symmetrical (0) 4 Definition of Measurement of Skewness There are two formulas to calculate the measurement of skewness : Pearson' s Coefficien t of Skewness 1 Mean - Mode Standard Deviation Pearson' s Coefficien t of Skewness 2 3(Mean - Median) Standard Deviation 5 Definition of Measurement of Skewness Measure of the skewness is use to determine the difference between the mean, median and mode in distribution. The following table can summarize it: 6 Example 17 : The following table shows the height distribution (cm) for 100 students Height (cm) 151-155 Frequency 5 156-160 20 161-165 42 166-170 26 171-175 7 a) Calculate the: i) Pearson’s Coefficient of Skewness 1 ii) Pearson’s Coefficient of Skewness 2 b) Sketch the distribution’s form based on answers in question (b) c) Give conclusion based on the sketch. 7 Solution: Step 1 : Obtain the midpoint, fx ( to calculate the mean), cumulative frequency and location of data ( to calculate the median) , x2, fx2( to calculate the variance and standard deviation) in a frequency distribution table. 8 Class Intervals 151-155 156-160 161-165 166-170 171-175 f 5 20 42 26 7 ∑f= 100 Mid point, x 153 158 163 168 173 Cumulative Location x2 fx2 Frequency of data 765 5 1-5 23409 117045 3160 25 6-25 24964 499280 6846 67 26-67 26569 1115898 4368 93 68-93 28224 733824 1211 100 94-100 29929 209503 ∑fx2 = ∑fx= 267555 16350 0 fx Step 2 : Find the mean by using the formula : _ fx Mean, x f 16350 100 = 163.5 9 Step 3 : Identify the location of median class by using the formula : Location of median class f 2 100 2 = 50 10 Step 4 : Find the median by using the formula : f f ~ m 2 Median, X L xC m fm 100 2 25 160.5 x 5 42 = 160.5 + 2.98 = 163.48 11 Step 5 : Identify the mode class (161-165), since this class has the highest frequency = 42 Step 6 : Find the mode by using the formula : ^ Δ1 Mode, X Lb xC Δ1 Δ2 (42 20) 160.5 x5 (42 20) (42 26) 22 160.5 x5 22 16 = 160.5+ 2.89 = 163.39 12 Step 7 : Calculate the standard deviation using the formula : Standard Deviation, S 2 fx 1 2 fx f 1 f 2 (16350) 2675550 100 1 100 1 1 (2675550 2673225) 99 23.49 = 4.85 13 Step 8 : Calculate the Pearson’s Coefficient of Skewness 1 by using the formula : Pearson' s Coefficien t of Skewness 1 Mean - Mode Standard Deviation 163.5 163.39 4.85 0.11 4.85 = 0.02 14 Step 9 : Calculate the Pearson’s Coefficient of Skewness 2 using the formula: Pearson' s Coefficien t of Skewness 2 3(Mean - Median) Standard Deviation 3(163.5 163.48) 4.85 0.06 4.85 = 0.01 15 Step 10 : Sketch the distribution’s form based on answers in Step 9 or 10 Mode<Median<Mean The conclusion is the distribution is skewed to the right or positive skewed 16 Exercise : 1. The following data was collected from an analysis conducted by a student. Average = 64.6 Variance = 24432.1 Median = 34.3 Mode = 35.4 a) Find the value of Pearson’s Coefficient of Skewness 1 and 2. b) Determine the type of skewness for the answer in question (a) 18