Section 2 – WARM UP
Use your graphing calculator to find the answers to the
following trig. values or angle measurements.
1. sin θ = .76
2. sec θ = 3.719
3. sec 𝛼 =
3
5
5
4. cos−1 𝛼 =
4
Section 2 – Solving Right Triangles
After this section you should be able to show that you can:
• Given a specified angle: name the parts of a right triangle
• Solve for missing pieces of right triangles(for all three sides and angles)
• Given a specified angle: name the parts of a right triangle


c
c
HYP
HYP
a
ADJ
a OPP

OPP
sin  
HYP
SOH


b
ADJ
b
OPP
ADJ
cos  
HYP
-
CAH

OPP
tan  
ADJ
-
TOA
•
REVIEW CONCEPT: Apply the Pythagorean theorem to solve for a missing side
of a right triangle
•
REVIEW CONCEPT: Use properties of triangles to solve for a missing angle.

a
c
a2  b2  c 2

      180

b
• Solve for missing pieces of right triangles(for all three sides and angles)
Given some of the information about sides and angles, find all missing pieces.

a
c


b
a  7.1
b  6.3
c


  90
• Solve for missing pieces of right triangles(for all three sides and angles)

a
c


b
7.1
tan  
6.3
a  7.1
b  6.3
c  9.492
  48.417
  41.583
  90
a2  b2  c 2
      180
• Solve for missing pieces of right triangles(for all three sides and angles)

c
a

b
36
sin  
61

a  36
b  49.244
c  61
  36.169
  53.831
  90
a2  b2  c 2
      180
• Solve for missing pieces of right triangles(for all three sides and angles)

c
a

b
17.1
sin  
23.6

a  16.265
b  17.1
c  23.6
  43.566
  46.434
  9 0
a2  b2  c 2
      180
• Solve for missing pieces of right triangles(for all three sides and angles)

c
a

b
a
sin21 
16

a  5.734
b  14.937
c  16
a2  b2  c 2
  21
  69
  90
      180
• Solve for missing pieces of right triangles(for all three sides and angles)

c
a

b
tan32 

b
17.31
a  17.31
b 10.816
c  20.412
  58
  32
  90
a2  b2  c 2
      180
• Solve for missing pieces of right triangles(for all three sides and angles)

c
a

b
15.47
tan71 
b

a  15.47
b  5.327
c  16.361
  71
  19
  90
a2  b2  c 2
      180
Section 2 – Solving Right Triangles
After this section you should be able to show that you can:
• Given a specified angle: name the parts of a right triangle
• Solve for missing pieces of right triangles(for all three sides and angles)
Section 2 – HW: Do any FOUR problems from worksheet#2
(solving for each missing piece of the right triangle)
Tomorrow: Clean up day…practice solving trig. equations
Wednesday: You will work with your groups to solve real-life
problems using Trig. equations.