Lesson 7: How Do Dilations Map Segments?

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Lesson 7
NYS COMMON CORE MATHEMATICS CURRICULUM
M2
GEOMETRY
Lesson 7: How Do Dilations Map Segments?
Student Outcomes


Students prove that dilation 𝐷𝑂,π‘Ÿ maps a line segment 𝑃𝑄 to a line segment 𝑃′𝑄′, sending the endpoints to the
endpoints so that 𝑃′ 𝑄′ = π‘Ÿπ‘ƒπ‘„. If the center 𝑂 lies in line 𝑃𝑄 or π‘Ÿ = 1, then ⃑𝑃𝑄 = ⃑𝑃′𝑄′. If the center 𝑂 does
⃑ .
not lie in line 𝑃𝑄 and π‘Ÿ ≠ 1, then ⃑𝑃𝑄 || 𝑃′𝑄′
Μ…Μ…Μ…Μ… are line segments in the plane of different lengths, then there is a dilation
Students prove that if Μ…Μ…Μ…Μ…
𝑃𝑄 and 𝑅𝑆
⃑ or ⃑𝑃𝑄 || 𝑅𝑆
⃑ .
that maps one to the other if and only if ⃑𝑃𝑄 = 𝑅𝑆
Lesson Notes
In Grade 8, students informally showed that a dilation maps a segment to a segment on the coordinate plane. The
lesson includes an opening discussion that reminds students of this fact. Next, students must consider how to prove that
dilations map segments to segments when the segment is not tied to the coordinate plane. We again call upon our
knowledge of the triangle side splitter theorem to show that a dilation maps a segment to a segment. The goal of the
lesson is for students to understand the effect that dilation has on segments, specifically that a dilation maps a segment
to a segment so that its length is π‘Ÿ times the original.
To complete the lesson in one class period, it may be necessary to skip the opening discussion and Example 4 and focus
primarily on the work in Examples 1–3. Another option is to extend the lesson to two days so that all examples and
exercises can be given the time required to develop student understanding of the dilation of segments.
Classwork
Opening Exercise (2 minutes)
Scaffolding:
Opening Exercise
a.
MP.3
Is a dilated segment still a segment? If the segment is transformed under a dilation,
explain how.
Accept any reasonable answer. The goal is for students to recognize that a segment
dilates to a segment that is 𝒓 times the length of the original.
Lesson 7:
How Do Dilations Map Segments?
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This file derived from GEO-M2-TE-1.3.0-08.2015
Use a segment in the
coordinate plane with endpoint
𝑃(−4,1) and endpoint 𝑄(3,2).
Show that a dilation from a
center at the origin maps Μ…Μ…Μ…Μ…
𝑃𝑄 to
′
′
Μ…Μ…Μ…Μ…Μ…Μ…
𝑃𝑄.
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NYS COMMON CORE MATHEMATICS CURRICULUM
Lesson 7
M2
GEOMETRY
b.
Dilate the segment 𝑷𝑸 by a scale factor of 𝟐 from center 𝑢.
MP.3
Is the dilated segment 𝑷′𝑸′ a segment?
i.
Yes, the dilation of segment 𝑷𝑸 produces a segment 𝑷′ 𝑸′ .
How, if at all, has the segment 𝑷𝑸 been transformed?
ii.
Segment 𝑷′𝑸′ is twice the length of segment 𝑷𝑸. The segment has increased in length according to the
scale factor of dilation.
Opening (5 minutes)
In Grade 8, students learned the multiplicative effect that dilation has on points in the coordinate plane when the center
of dilation is the origin. Specifically, students learned that when the point located at (π‘₯, 𝑦) was dilated from the origin
by scale factor π‘Ÿ, the dilated point was located at (π‘Ÿπ‘₯, π‘Ÿπ‘¦). Review this fact with students, and then remind them how to
informally verify that a dilation maps a segment to a segment using the diagram below. As time permits, review what
students learned in Grade 8, and then spend the remaining time on the question in the second bullet point.

Let Μ…Μ…Μ…Μ…
𝐴𝐡 be a segment on the coordinate plane with endpoints at (−2, 1) and (1, −2). If we dilate the segment
from the origin by a scale factor π‘Ÿ = 4, another segment is produced.

What do we expect the coordinates of the endpoints to be?
οƒΊ
Based on what we know about the multiplicative effect dilation has on coordinates, we expect the
coordinates of the endpoints of Μ…Μ…Μ…Μ…Μ…Μ…
𝐴′𝐡′ to be (−8, 4) and (4, −8).
Lesson 7:
How Do Dilations Map Segments?
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Lesson 7
M2
GEOMETRY

The question becomes, how can we be sure that the dilation maps the points between 𝐴 and 𝐡 to the points
between 𝐴′ and 𝐡′? We have already shown that the endpoints move to where we expect them to, but what
about the points in between? Perhaps the dilation maps the endpoints the way we expect, but all other points
form an arc of a circle or some other curve that connects the endpoints. Can you think of a way we can verify
that all of the points of segment 𝐴𝐡 map to images that lie on segment 𝐴′ 𝐡′ ?
οƒΊ

We can verify other points that belong to segment 𝐴𝐡 using the same method as the endpoints. For
example, points (−1,0) and (0, −1) of segment 𝐴𝐡 should map to points (−4,0) and (0, −4). Using
the π‘₯- and 𝑦-axes as our rays from the origin of dilation, we can clearly see that the points and their
dilated images lie on the correct ray and more importantly lie on segment 𝐴′ 𝐡′ .
Our next challenge is to show that dilations map segments to segments when they are not on the coordinate
plane. We will prove the preliminary dilation theorem for segments: A dilation maps a line segment to a line
segment sending the endpoints to the endpoints.
Lesson 7:
How Do Dilations Map Segments?
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Lesson 7
NYS COMMON CORE MATHEMATICS CURRICULUM
M2
GEOMETRY
Example 1 (2 minutes)
Example 1
Case 1. Consider the case where the scale factor of dilation is 𝒓 = 𝟏. Does a dilation from center 𝑢 map segment 𝑷𝑸 to a
segment 𝑷′𝑸′? Explain.
A scale factor of 𝒓 = 𝟏 means that the segment and its image are equal. The dilation does not enlarge or shrink the
image of the figure; it remains unchanged. Therefore, when the scale factor of dilation is 𝒓 = 𝟏, then the dilation maps
the segment to itself.
Example 2 (3 minutes)
Example 2
Case 2. Consider the case where a line 𝑷𝑸 contains the center of the dilation. Does a dilation from the center with scale
factor 𝒓 ≠ 𝟏 map the segment 𝑷𝑸 to a segment 𝑷′𝑸′? Explain.
At this point, students should be clear that a dilation of scale factor π‘Ÿ ≠ 1 changes the length of the segment. If
necessary, explain to students that a scale factor of π‘Ÿ ≠ 1 simply means that the figure changes in length. The goal in
this example and, more broadly, this lesson is to show that a dilated segment is still a segment not some other figure.
The focus of the discussion should be on showing that the dilated figure is in fact a segment, not necessarily the length
of the segment.
Yes. The dilation sends points 𝑷 and 𝑸 to points 𝑷′ and 𝑸′. Since the points 𝑷 and 𝑸 are collinear with the center 𝑢, then
both 𝑷′ and 𝑸′ are also collinear with the center 𝑢. The dilation also takes all of the points between 𝑷 and 𝑸 to all of the
points between 𝑷′ and 𝑸′ (again because their images must fall on the rays 𝑢𝑷 and 𝑢𝑸). Therefore, the dilation maps
Μ…Μ…Μ…Μ…Μ…Μ….
Μ…Μ…Μ…Μ… to 𝑷′𝑸′
𝑷𝑸
Example 3 (12 minutes)
Scaffolding:
Example 3
⃑ does not contain the center 𝑢 of the dilation, and the scale
Case 3. Consider the case where 𝑷𝑸
factor 𝒓 of the dilation is not equal to 1; then, we have the situation where the key points 𝑢, 𝑷,
and 𝑸 form β–³ 𝑢𝑷𝑸. The scale factor not being equal to 1 means that we must consider scale
factors such that 𝟎 < 𝒓 < 𝟏 and 𝒓 > 𝟏. However, the proofs for each are similar, so we focus on
the case when 𝟎 < 𝒓 < 𝟏.
Lesson 7:
How Do Dilations Map Segments?
This work is derived from Eureka Math ™ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org
This file derived from GEO-M2-TE-1.3.0-08.2015
For some groups of students, it
may be necessary for them to
perform a dilation where the
scale factor of dilation is
0 < π‘Ÿ < 1 so they have recent
experience allowing them to
better answer the second
question of Example 3.
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NYS COMMON CORE MATHEMATICS CURRICULUM
Lesson 7
M2
GEOMETRY
When we dilate points 𝑷 and 𝑸 from center 𝑢 by scale factor 𝟎 < 𝒓 < 𝟏, as shown,
what do we know about points 𝑷′ and 𝑸′?
We know 𝑷′ lies on ray 𝑢𝑷 with 𝑢𝑷′ = 𝒓 ⋅ 𝑢𝑷, and 𝑸′ lies on ray 𝑢𝑸 with
𝑢𝑸′ = 𝒓 ⋅ 𝑢𝑸. So,
𝑢𝑷′
𝑢𝑷
=
𝑢𝑸′
𝑢𝑸
= 𝒓. The line segment 𝑷′𝑸′ splits the sides
of β–³ 𝑢𝑷𝑸 proportionally.
Μ…Μ…Μ…Μ… and
By the triangle side splitter theorem, we know that the lines containing 𝑷𝑸
Μ…Μ…Μ…Μ…Μ…Μ…
𝑷′𝑸′ are parallel.
Μ…Μ…Μ…Μ… and
We use the fact that the line segment 𝑷′𝑸′ splits the sides of β–³ 𝑢𝑷𝑸 proportionally and that the lines containing 𝑷𝑸
Μ…Μ…Μ…Μ…Μ…Μ…
𝑷′𝑸′ are parallel to prove that a dilation maps segments to segments. Because we already know what happens when
points 𝑷 and 𝑸 are dilated, consider another point 𝑹 that is on the segment 𝑷𝑸. After dilating 𝑹 from center 𝑢 by scale
factor 𝒓 to get the point 𝑹′, does 𝑹′ lie on the segment 𝑷′𝑸′?
Consider giving students time to discuss in small groups Marwa’s proof shown on the next page on how to prove that a
dilation maps collinear points to collinear points. Also consider providing students time to make sense of it and
paraphrase a presentation of the proof to a partner or the class. Consider also providing the statements for the proof
and asking students to provide the reasoning for each step independently, with a partner, or in small groups.
⃑
The proof below relies heavily upon the parallel postulate: Two lines are constructed, 𝑃′𝑄′
and ⃑𝑃′𝑅′, both of which are
⃑ and contain the point 𝑃′, they must be the same line by the parallel
parallel to ⃑𝑃𝑄 . Since both lines are parallel to 𝑃𝑄
postulate. Thus, the point 𝑅′ lies on the line 𝑃′𝑄′.
Note: This proof on the next page is only part of the reasoning needed to show that dilations map segments to
segments. The full proof also requires showing that points between 𝑃 and 𝑄 are mapped to points between 𝑃′ and 𝑄′,
and that this mapping is onto (that for every point on the line segment 𝑃′𝑄′, there exists a point on segment 𝑃𝑄 that
gets sent to it). See the discussion following Marwa’s proof for more details on these steps.
Lesson 7:
How Do Dilations Map Segments?
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Lesson 7
NYS COMMON CORE MATHEMATICS CURRICULUM
M2
GEOMETRY
Marwa’s proof of the statement: Let 𝑂 be a point not on ⃑𝑃𝑄 and 𝐷𝑂,π‘Ÿ be a dilation with center 𝑂 and scale factor
⃑ , then 𝐷𝑂,π‘Ÿ (𝑅) is a point that
0 < π‘Ÿ < 1 that sends point 𝑃 to 𝑃′ and 𝑄 to 𝑄′. If 𝑅 is another point that lies on 𝑃𝑄
⃑
lies on 𝑃′𝑄′.
Statement
1.
2.
A dilation 𝐷𝑂,π‘Ÿ with center 𝑂 and scale factor
π‘Ÿ sends point 𝑃 to 𝑃′ and 𝑄 to 𝑄′ .
𝑂𝑃′
𝑂𝑃
=
𝑂𝑄′
𝑂𝑄
=π‘Ÿ
Reason
1.
Given
2.
By definition of dilation
3.
⃑
⃑𝑃𝑄 ||𝑃′𝑄′
3.
By the triangle side splitter theorem
4.
Let 𝑅 be a point on segment 𝑃𝑄 between 𝑃 and 𝑄.
Let 𝑅′ be the dilation of 𝑅 by 𝐷𝑂,π‘Ÿ .
4.
Given
5.
By definition of dilation
5.
𝑂𝑃′
𝑂𝑃
=
𝑂𝑅′
𝑂𝑅
=π‘Ÿ
Lesson 7:
How Do Dilations Map Segments?
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Lesson 7
NYS COMMON CORE MATHEMATICS CURRICULUM
M2
GEOMETRY
6.
⃑𝑃′𝑅′||𝑃𝑄
⃑
6.
By the triangle side splitter theorem as applied to
β–³ 𝑂𝑃𝑅 and the fact that ⃑𝑃𝑄 and ⃑𝑃𝑅 are the same
line
7.
⃑𝑃′𝑅′ = 𝑃′𝑄′
⃑
7.
By the parallel postulate: Through a given
external point 𝑃′ , there is at most one line parallel
to a given line 𝑃𝑄.
8.
The point 𝑅′ lies on ⃑𝑃′𝑄′.
8.
By Step 7
There are still two subtle steps that need to be proved to show that dilations map segments to segments when the
center does not lie on the line through the segment. The teacher may decide whether to show how to prove these two
steps or just claim that the steps can be shown to be true. Regardless, the steps should be briefly discussed as part of
what is needed to complete the proof of the full statement that dilations map segments to segments.
The first additional step that needs to be shown is that points on 𝑃𝑄 are sent to points on 𝑃′ 𝑄′ , that is, if 𝑅 is between 𝑃
and 𝑄, then 𝑅′ is between 𝑃′ and 𝑄′ . To prove this, we first write out what it means for 𝑅 to be between 𝑃 and 𝑄: 𝑃, 𝑅,
and 𝑄 are different points on the same line such that 𝑃𝑅 + 𝑅𝑄 = 𝑃𝑄. By the dilation theorem (Lesson 6), 𝑃′ 𝑅′ = π‘Ÿ ⋅
𝑃𝑅, 𝑅′ 𝑄′ = π‘Ÿ ⋅ 𝑅𝑄, and 𝑃′ 𝑄′ = π‘Ÿ ⋅ 𝑃𝑄. Therefore,
𝑃′ 𝑅′ + 𝑅′ 𝑄′ = π‘Ÿ ⋅ 𝑃𝑅 + π‘Ÿ ⋅ 𝑅𝑄 = π‘Ÿ(𝑃𝑅 + 𝑅𝑄) = π‘Ÿ ⋅ 𝑃𝑄 = 𝑃′ 𝑄′
Hence, 𝑃′ 𝑅′ + 𝑅′ 𝑄′ = 𝑅′𝑄′, and therefore 𝑅′ is between 𝑃′ and 𝑄′.
The second additional step is to show that the dilation is an onto mapping, that is, for every point 𝑅′ that lies on 𝑃′ 𝑄′ ,
there is a point 𝑅 that lies on 𝑃𝑄 that is mapped to 𝑅′ under the dilation. To prove, we use the inverse dilation at
center 𝑂 with scale factor
1
π‘Ÿ
to get the point 𝑅 and then follow the proof above to show that 𝑅 lies on 𝑃𝑄.
Lesson 7:
How Do Dilations Map Segments?
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Lesson 7
NYS COMMON CORE MATHEMATICS CURRICULUM
M2
GEOMETRY
Putting together the preliminary dilation theorem for segments with the dilation theorem, we get
DILATION THEOREM FOR SEGMENTS: A dilation 𝑫𝑢,𝒓 maps a line segment 𝑷𝑸 to a line segment 𝑷′𝑸′ sending the endpoints to
⃑
⃑ || 𝑷′𝑸′
the endpoints so that 𝑷′ 𝑸′ = 𝒓𝑷𝑸. Whenever the center 𝑢 does not lie in line 𝑷𝑸 and 𝒓 ≠ 𝟏, we conclude 𝑷𝑸
.
⃑
⃑ or if 𝒓 = 𝟏, we conclude 𝑷𝑸
⃑ = 𝑷′𝑸′
Whenever the center 𝑢 lies in 𝑷𝑸
.
As an aside, observe that a dilation maps parallel line segments to parallel line segments. Further, a dilation maps a
directed line segment to a directed line segment that points in the same direction.
If time permits, have students verify these observations with their own scale drawings. It is not imperative that students
do this activity, but this idea is used in the next lesson. At this point, students just need to observe this fact or at least be
made aware of it, as it is discussed in Lesson 8.
Example 4 (7 minutes)
Example 4
Μ…Μ…Μ…Μ… and 𝑹𝑺
Μ…Μ…Μ…Μ… are line segments of different lengths in
Now look at the converse of the dilation theorem for segments: If 𝑷𝑸
⃑ = 𝑹𝑺
⃑ or 𝑷𝑸
⃑ || 𝑹𝑺
⃑ .
the plane, then there is a dilation that maps one to the other if and only if 𝑷𝑸
Μ…Μ…Μ…Μ…, so that
Based on Examples 2 and 3, we already know that a dilation maps a segment 𝑷𝑸 to another line segment, say 𝑹𝑺
⃑ = 𝑹𝑺
⃑ (Example 2) or 𝑷𝑸
⃑ || 𝑹𝑺
⃑ (Example 3). If 𝑷𝑸
⃑ || 𝑹𝑺
⃑ , then, because 𝑷𝑸
Μ…Μ…Μ…Μ… and 𝑹𝑺
Μ…Μ…Μ…Μ… are different lengths in the plane,
𝑷𝑸
they are the bases of a trapezoid, as shown.
S
R
P
Q
Since Μ…Μ…Μ…Μ…
𝑷𝑸 and Μ…Μ…Μ…Μ…
𝑹𝑺 are segments of different lengths, then the non-base sides of the trapezoid are not parallel, and the
lines containing them meet at a point 𝑢 as shown.
O
R
P
S
Q
Recall that we want to show that a dilation maps Μ…Μ…Μ…Μ…
𝑷𝑸 to Μ…Μ…Μ…Μ…
𝑹𝑺. Explain how to show it.
Provide students time to discuss this in partners or small groups.
Lesson 7:
How Do Dilations Map Segments?
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Lesson 7
NYS COMMON CORE MATHEMATICS CURRICULUM
M2
GEOMETRY
The triangle formed with vertex 𝑢, β–³ 𝑢𝑷𝑸, has 𝑷𝑸 as its base. Since ⃑𝑷𝑸 || ⃑𝑹𝑺, then the segment 𝑹𝑺 splits the sides of
the triangle proportionally by the triangle side splitter theorem. Since we know the proportional side splitters of a
triangle are the result of a dilation, then we know there is a dilation from center 𝑢 by scale factor 𝒓 that maps points 𝑷
Μ…Μ…Μ…Μ… to 𝑹𝑺
Μ…Μ…Μ…Μ….
and 𝑸 to points 𝑹 and 𝑺, respectively. Thus, a dilation maps 𝑷𝑸
Μ…Μ…Μ…Μ… and 𝑹𝑺
Μ…Μ…Μ…Μ… are such that 𝑷𝑸
⃑ = 𝑹𝑺
⃑ is left as an exercise.
The case when the segments 𝑷𝑸
Exercises 1–2 (8 minutes)
Students complete Exercises 1–2 in pairs. Students may need support to complete Exercise 2. A hint is shown below
that can be shared with students if necessary.
Exercises 1–2
In the following exercises, you will consider the case where the segment and its dilated image belong to the same line,
Μ…Μ…Μ…Μ… and 𝑹𝑺
Μ…Μ…Μ…Μ… are such that 𝑷𝑸
⃑ = 𝑹𝑺
⃑ .
that is, when 𝑷𝑸
1.
Μ…Μ…Μ…Μ…
Consider points 𝑷, 𝑸, 𝑹, and 𝑺 on a line, where 𝑷 = 𝑹, as shown below. Show there is a dilation that maps 𝑷𝑸
Μ…Μ…Μ…Μ…. Where is the center of the dilation?
to 𝑹𝑺
S
Q
P=R
Μ…Μ…Μ…Μ… to 𝑹𝑺
Μ…Μ…Μ…Μ…, with a scale factor so that 𝒓 =
If we assume there is a dilation that maps 𝑷𝑸
𝑹𝑺
, then the center of the
𝑷𝑸
dilation must coincide with endpoints 𝑷 and 𝑹 because, by definition of dilation, the center maps to itself. Since
points 𝑷 and 𝑹 coincide, it must mean that the center 𝑢 is such that 𝑢 = 𝑷 = 𝑹. Since the other endpoint 𝑸 of 𝑷𝑸
⃑ , the dilated image of 𝑸 must also lie on the line (draw the ray from the center through point 𝑸, and the
lies on 𝑷𝑸
⃑ ). Since the dilated image of 𝑸 must lie on the line, and point 𝑺 is to the right of 𝑸, then a
ray coincides with 𝑷𝑸
dilation from center 𝑢 with scale factor 𝒓 > 𝟏 maps Μ…Μ…Μ…Μ…
𝑷𝑸 to Μ…Μ…Μ…Μ…Μ…
𝑹𝑺.
2.
Μ…Μ…Μ…Μ… ≠ 𝑹𝑺
Μ…Μ…Μ…Μ…. Show there is a dilation that maps 𝑷𝑸
Μ…Μ…Μ…Μ…
Consider points 𝑷, 𝑸, 𝑹, and 𝑺 on a line as shown below where 𝑷𝑸
to Μ…Μ…Μ…Μ…
𝑹𝑺. Where is the center of the dilation?
P
Q
R
S
Students may need some support to complete Exercise 2. Give them enough time to struggle with how to complete the
Μ…Μ…Μ…Μ… as
exercise and, if necessary, provide them with the following hint: Construct perpendicular line segments Μ…Μ…Μ…Μ…Μ…
𝑃𝑄′ and 𝑅𝑆′
shown so that 𝑃𝑄′ = 𝑃𝑄 and 𝑅𝑆 ′ = 𝑅𝑆.
Lesson 7:
How Do Dilations Map Segments?
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Lesson 7
NYS COMMON CORE MATHEMATICS CURRICULUM
M2
GEOMETRY
S'
Q'
P
Q
S
R
Construct perpendicular line segments of lengths 𝑷𝑸 and 𝑹𝑺 through points 𝑷 and 𝑹 respectively. Note the
endpoints of the perpendicular segments as 𝑸′ and 𝑺′ . Draw an auxiliary line through points 𝑸′ and 𝑺′ that
⃑ (perpendicular lines),
intersects with ⃑𝑷𝑸. The intersection of the two lines is the center of dilation 𝑢. Since ⃑𝑷𝑸′||𝑹𝑺′
by the triangle side splitter theorem, the segment 𝑷𝑸′ splits the triangle β–³ 𝑢𝑹𝑺′ proportionally, so by the dilation
theorem,
𝑹𝑺′
𝑷𝑸′
= 𝒓. This ratio implies that 𝑹𝑺′ = 𝒓 ⋅ 𝑷𝑸′. By construction, 𝑷𝑸′ = 𝑷𝑸 and 𝑹𝑺′ = 𝑹𝑺. Therefore,
𝑹𝑺 = 𝒓 ⋅ 𝑷𝑸. By definition of dilation, since 𝑹𝑺 = 𝒓 ⋅ 𝑷𝑸, there is a dilation from center 𝑢 with scale factor 𝒓 that
Μ…Μ…Μ…Μ… to 𝑹𝑺.
Μ…Μ…Μ…Μ…Μ…
maps 𝑷𝑸
Closing (3 minutes)
Revisit the Opening Exercises. Have students explain their thinking about segments and dilated segments. Were their
initial thoughts correct? Did they change their thinking after going through the examples? What made them change
their minds? Then ask students to paraphrase the proofs as stated in the bullet point below.

Paraphrase the proofs that show how dilations map segments to segments when π‘Ÿ = 1 and π‘Ÿ ≠ 1 and when
the points are collinear compared to the vertices of a triangle.
Either accept or correct students’ responses accordingly. Recall that the goal of the lesson is to make sense of what
happens when segments are dilated. When the segment is dilated by a scale factor of π‘Ÿ = 1, then the segment and its
image would be the same length. When the points 𝑃 and 𝑄 are on a line containing the center, then the dilated points
𝑃′ and 𝑄′ are also collinear with the center producing an image of the segment that is a segment. When the points 𝑃
and 𝑄 are not collinear with the center, and the segment is dilated by a scale factor of π‘Ÿ ≠ 1, then the point 𝑃′ lies on
the ray 𝑂𝑃 with 𝑂𝑃′ = π‘Ÿ ⋅ 𝑂𝑃, and 𝑄′lies on 𝑂𝑄 with 𝑄′ = π‘Ÿ ⋅ 𝑂𝑄. Then
𝑂𝑃′
𝑂𝑃
=
𝑂𝑄′
𝑂𝑄
= π‘Ÿ. Μ…Μ…Μ…Μ…Μ…Μ…
𝑃′𝑄′ splits the sides of β–³ 𝑂𝑃𝑄
proportionally, and by the triangle side splitter theorem, the lines containing Μ…Μ…Μ…Μ…
𝑃𝑄 and Μ…Μ…Μ…Μ…Μ…Μ…
𝑃′𝑄′ are parallel.
Lesson Summary

When a segment is dilated by a scale factor of 𝒓 = 𝟏, then the segment and its image would be the
same length.

When the points 𝑷 and 𝑸 are on a line containing the center, then the dilated points 𝑷′ and 𝑸′ are also
collinear with the center producing an image of the segment that is a segment.

When the points 𝑷 and 𝑸 are not collinear with the center and the segment is dilated by a scale factor
of 𝒓 ≠ 𝟏, then the point 𝑷′ lies on the ray 𝑢𝑷′ with 𝑢𝑷′ = 𝒓 ⋅ 𝑢𝑷, and 𝑸′ lies on ray 𝑢𝑸 with
𝑢𝑸′ = 𝒓 ⋅ 𝑢𝑸.
Exit Ticket (5 minutes)
Lesson 7:
How Do Dilations Map Segments?
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Lesson 7
NYS COMMON CORE MATHEMATICS CURRICULUM
M2
GEOMETRY
Name
Date
Lesson 7: How Do Dilations Map Segments?
Exit Ticket
1.
Given the dilation 𝐷𝑂,3 , a line segment 𝑃𝑄, and that 𝑂 is not on ⃑𝑃𝑄 , what can we conclude about the image of Μ…Μ…Μ…Μ…
𝑃𝑄 ?
2
2.
Μ…Μ…Μ…Μ…, and Μ…Μ…Μ…Μ…
Μ…Μ…Μ…Μ…, determine which figure has a dilation mapping the
Given figures A and B below, Μ…Μ…Μ…Μ…
𝐡𝐴 βˆ₯ Μ…Μ…Μ…Μ…
𝐷𝐢 , Μ…Μ…Μ…Μ…
π‘ˆπ‘‰ βˆ₯ π‘‹π‘Œ
π‘ˆπ‘‰ ≅ π‘‹π‘Œ
parallel line segments, and locate the center of dilation 𝑂. For one of the figures, a dilation does not exist. Explain
why.
Figure A
Figure B
Lesson 7:
How Do Dilations Map Segments?
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NYS COMMON CORE MATHEMATICS CURRICULUM
M2
GEOMETRY
Exit Ticket Sample Solutions
1.
Μ…Μ…Μ…Μ…?
Given the dilation 𝑫𝑢,πŸ‘ , a line segment 𝑷𝑸, and that 𝑢 is not on ⃑𝑷𝑸, what can we conclude about the image of 𝑷𝑸
𝟐
πŸ‘
Since 𝑷 and 𝑸 are not in line with 𝑢, Μ…Μ…Μ…Μ…Μ…Μ…
𝑷′𝑸′ is parallel to Μ…Μ…Μ…Μ…
𝑷𝑸, and 𝑷′ 𝑸′ = (𝑷𝑸).
𝟐
2.
Given figures A and B below, Μ…Μ…Μ…Μ…
𝑩𝑨 βˆ₯ Μ…Μ…Μ…Μ…
𝑫π‘ͺ, Μ…Μ…Μ…Μ…
𝑼𝑽 βˆ₯ Μ…Μ…Μ…Μ…
𝑿𝒀, and Μ…Μ…Μ…Μ…
𝑼𝑽 ≅ Μ…Μ…Μ…Μ…
𝑿𝒀, determine which figure has a dilation mapping the
parallel line segments, and locate the center of dilation 𝑢. For one of the figures, a dilation does not exist. Explain
why.
𝑂
Figure A
Μ…Μ…Μ…Μ… to 𝑿𝒀
Μ…Μ…Μ…Μ…. If the segments are both
There is no dilation that maps 𝑼𝑽
parallel and congruent, then they form two sides of a parallelogram,
which means that ⃑𝑼𝑿 βˆ₯ ⃑𝑽𝒀. If there was a dilation mapping Μ…Μ…Μ…Μ…
𝑼𝑽 to
Μ…Μ…Μ…Μ…
𝑿𝒀, then ⃑𝑼𝑿 and ⃑𝑽𝒀 would have to intersect at the center of
dilation, but they cannot intersect because they are parallel. We
also showed that a directed line segment maps to a directed line
segment pointing in the same direction, so it is not possible for 𝑼 to
map to 𝒀 and also 𝑽 map to 𝑿 under a dilation.
Figure B
Lesson 7:
How Do Dilations Map Segments?
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Lesson 7
M2
GEOMETRY
Problem Set Sample Solutions
1.
Draw the dilation of parallelogram 𝑨𝑩π‘ͺ𝑫 from center 𝑢 using the scale factor 𝒓 = 𝟐, and then answer the
questions that follow.
a.
Is the image 𝑨′𝑩′π‘ͺ′𝑫′ also a parallelogram? Explain.
Μ…Μ…Μ…Μ…Μ…Μ… and 𝑩𝑫
Μ…Μ…Μ…Μ…Μ…Μ…, and because 𝑨π‘ͺ
Μ…Μ…Μ…Μ…Μ…Μ… βˆ₯ 𝑩′𝑫′
Μ…Μ…Μ…Μ…Μ…Μ…. A
Μ…Μ…Μ…Μ… βˆ₯ 𝑨′π‘ͺ′
Μ…Μ…Μ…Μ… βˆ₯ 𝑩𝑫
Μ…Μ…Μ…Μ…Μ… βˆ₯ 𝑩′𝑫′
Μ…Μ…Μ…Μ…Μ…, it follows that 𝑨′π‘ͺ′
Yes By the dilation theorem, 𝑨π‘ͺ
Μ…Μ…Μ…Μ…Μ…Μ… βˆ₯ 𝑩′𝑫′
Μ…Μ…Μ…Μ…Μ…Μ… and 𝑨′𝑩′
Μ…Μ…Μ…Μ…Μ…Μ… βˆ₯ π‘ͺ′𝑫′
Μ…Μ…Μ…Μ…Μ…Μ…, 𝑨′𝑩′π‘ͺ′𝑫′ is
similar argument follows for the other pair of opposite sides, so with 𝑨′π‘ͺ′
a parallelogram.
b.
What do parallel lines seem to map to under a dilation?
Parallel lines map to parallel lines under dilations.
2.
Given parallelogram 𝑨𝑩π‘ͺ𝑫 with 𝑨(−πŸ–, 𝟏), 𝑩(𝟐, −πŸ’), π‘ͺ(−πŸ‘, −πŸ”), and 𝑫(−πŸπŸ‘, −𝟏), perform a dilation of the plane
centered at the origin using the following scale factors.
a.
Scale factor
Lesson 7:
𝟏
𝟐
How Do Dilations Map Segments?
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M2
GEOMETRY
b.
Scale factor 𝟐
c.
Are the images of parallel line segments under a dilation also parallel? Use your graphs to support your
answer.
𝟏
The slopes of sides Μ…Μ…Μ…Μ…
𝑨𝑩 and Μ…Μ…Μ…Μ…
π‘ͺ𝑫 in the original graph are − , and the slopes of each of the images of those
𝟐
𝟐
𝟏
𝟐
Μ…Μ…Μ…Μ… in the original graph are , and the
Μ…Μ…Μ…Μ… and 𝑩π‘ͺ
sides under the dilations are also − . The slopes of sides 𝑨𝑫
𝟐
πŸ“
slopes of each of the images of those sides under the dilations are also . This informally verifies that the
πŸ“
images of parallel line segments are also parallel line segments.
3.
In Lesson 7, Example 3, we proved that a line segment 𝑷𝑸, where 𝑢, 𝑷, and 𝑸 are the vertices of a triangle, maps to
a line segment 𝑷′𝑸′ under a dilation with a scale factor 𝒓 < 𝟏. Using a similar proof, prove that for 𝑢 not on ⃑𝑷𝑸, a
dilation with center 𝑢 and scale factor 𝒓 > 𝟏 maps a point 𝑹 on 𝑷𝑸 to a point 𝑹′ on line 𝑷𝑸.
The proof follows almost exactly the same as the proof of Example 3, but using the following diagram instead:
Lesson 7:
How Do Dilations Map Segments?
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Lesson 7
NYS COMMON CORE MATHEMATICS CURRICULUM
M2
GEOMETRY
4.
Μ…Μ…Μ…Μ… βˆ₯ Μ…Μ…Μ…Μ…Μ…Μ…
⃑ ≠ ⃑𝑨′𝑩′. Describe a dilation mapping 𝑨𝑩
Μ…Μ…Μ…Μ… to Μ…Μ…Μ…Μ…Μ…Μ…
On the plane, 𝑨𝑩
𝑨′𝑩′ and 𝑨𝑩
𝑨′𝑩′. (Hint: There are 2 cases to
consider.)
Case 1: Μ…Μ…Μ…Μ…
𝑨𝑩 and Μ…Μ…Μ…Μ…Μ…Μ…
𝑨′𝑩′ are parallel directed line segments oriented in the same direction.
By the dilation theorem for segments, there is a dilation mapping 𝑨 and 𝑩 to 𝑨′ and 𝑩′, respectively.
Case 2: Μ…Μ…Μ…Μ…
𝑨𝑩 and Μ…Μ…Μ…Μ…Μ…Μ…
𝑨′𝑩′ are parallel directed line segments oriented in the opposite directions.
We showed that directed line segments map to directed line segments that are oriented in the same direction, so
there is a dilation mapping the parallel segments but only where the dilation maps 𝑨 and 𝑩 to 𝑩′ and 𝑨′,
respectively.
Note to the teacher: Students may state that a scale factor π‘Ÿ < 0 would produce the figure below where the center of a
dilation is between the segments; however, this violates the definition of dilation. In such a case, discuss the fact that a
scale factor must be greater than 0; otherwise, it would create negative distance, which of course does not make
mathematical sense.
5.
Only one of Figures 𝑨, 𝑩, or π‘ͺ below contains a dilation that maps 𝑨 to 𝑨′ and 𝑩 to 𝑩′. Explain for each figure why
the dilation does or does not exist. For each figure, assume that ⃑𝑨𝑩 ≠ ⃑𝑨′𝑩′.
a.
Μ…Μ…Μ…Μ…Μ…Μ… are line segments in the plane of different lengths, then there is a
Μ…Μ…Μ…Μ… and 𝑨′𝑩′
By the dilation theorem, if 𝑨𝑩
⃑
⃑
⃑ = 𝑨′𝑩′
⃑ || 𝑨′𝑩′
dilation that maps one to the other if and only if 𝑨𝑩
or 𝑨𝑩
. The segments do not lie in the
same line and are also not parallel, so there is no dilation mapping 𝑨 to 𝑨′ and 𝑩 to 𝑩′.
Lesson 7:
How Do Dilations Map Segments?
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Lesson 7
M2
GEOMETRY
b.
Μ…Μ…Μ…Μ…Μ…Μ… are line segments in the plane of different lengths, then there is a
Μ…Μ…Μ…Μ… and 𝑨′𝑩′
By the dilation theorem, if 𝑨𝑩
⃑
⃑
⃑ = 𝑨′𝑩′
⃑ || 𝑨′𝑩′
Μ…Μ…Μ…Μ… and
dilation that maps one to the other if and only if 𝑨𝑩
or 𝑨𝑩
. The diagram shows that 𝑨𝑩
Μ…Μ…Μ…Μ…Μ…Μ…
𝑨′𝑩′ do not lie in the same line, and it can also be seen that the line segments are not parallel. Furthermore,
for the dilation to exist that maps 𝑨 to 𝑨′ and 𝑩 to 𝑩′, the center of dilation 𝑷 would need to be between the
segments, which violates the definition of dilation. Therefore, there is no dilation in Figure B mapping 𝑨 and
𝑩 to 𝑨′ and 𝑩′, respectively.
c.
By the dilation theorem, if Μ…Μ…Μ…Μ…
𝑨𝑩 and Μ…Μ…Μ…Μ…Μ…Μ…
𝑨′𝑩′ are line segments in the plane of different lengths, then there is a
dilation that maps one to the other if and only if ⃑𝑨𝑩 = ⃑𝑨′𝑩′ or ⃑𝑨𝑩 || ⃑𝑨′𝑩′. Assuming that ⃑𝑨𝑩 ≠ ⃑𝑨′𝑩′, the
segments are shown to lie in the same line; therefore, the dilation exists.
Lesson 7:
How Do Dilations Map Segments?
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