Lesson 7 NYS COMMON CORE MATHEMATICS CURRICULUM M2 GEOMETRY Lesson 7: How Do Dilations Map Segments? Student Outcomes ο§ ο§ Students prove that dilation π·π,π maps a line segment ππ to a line segment π′π′, sending the endpoints to the endpoints so that π′ π′ = πππ. If the center π lies in line ππ or π = 1, then β‘ππ = β‘π′π′. If the center π does β‘ . not lie in line ππ and π ≠ 1, then β‘ππ || π′π′ Μ Μ Μ Μ are line segments in the plane of different lengths, then there is a dilation Students prove that if Μ Μ Μ Μ ππ and π π β‘ or β‘ππ || π π β‘ . that maps one to the other if and only if β‘ππ = π π Lesson Notes In Grade 8, students informally showed that a dilation maps a segment to a segment on the coordinate plane. The lesson includes an opening discussion that reminds students of this fact. Next, students must consider how to prove that dilations map segments to segments when the segment is not tied to the coordinate plane. We again call upon our knowledge of the triangle side splitter theorem to show that a dilation maps a segment to a segment. The goal of the lesson is for students to understand the effect that dilation has on segments, specifically that a dilation maps a segment to a segment so that its length is π times the original. To complete the lesson in one class period, it may be necessary to skip the opening discussion and Example 4 and focus primarily on the work in Examples 1–3. Another option is to extend the lesson to two days so that all examples and exercises can be given the time required to develop student understanding of the dilation of segments. Classwork Opening Exercise (2 minutes) Scaffolding: Opening Exercise a. MP.3 Is a dilated segment still a segment? If the segment is transformed under a dilation, explain how. Accept any reasonable answer. The goal is for students to recognize that a segment dilates to a segment that is π times the length of the original. Lesson 7: How Do Dilations Map Segments? This work is derived from Eureka Math ™ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from GEO-M2-TE-1.3.0-08.2015 Use a segment in the coordinate plane with endpoint π(−4,1) and endpoint π(3,2). Show that a dilation from a center at the origin maps Μ Μ Μ Μ ππ to ′ ′ Μ Μ Μ Μ Μ Μ ππ. 104 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. NYS COMMON CORE MATHEMATICS CURRICULUM Lesson 7 M2 GEOMETRY b. Dilate the segment π·πΈ by a scale factor of π from center πΆ. MP.3 Is the dilated segment π·′πΈ′ a segment? i. Yes, the dilation of segment π·πΈ produces a segment π·′ πΈ′ . How, if at all, has the segment π·πΈ been transformed? ii. Segment π·′πΈ′ is twice the length of segment π·πΈ. The segment has increased in length according to the scale factor of dilation. Opening (5 minutes) In Grade 8, students learned the multiplicative effect that dilation has on points in the coordinate plane when the center of dilation is the origin. Specifically, students learned that when the point located at (π₯, π¦) was dilated from the origin by scale factor π, the dilated point was located at (ππ₯, ππ¦). Review this fact with students, and then remind them how to informally verify that a dilation maps a segment to a segment using the diagram below. As time permits, review what students learned in Grade 8, and then spend the remaining time on the question in the second bullet point. ο§ Let Μ Μ Μ Μ π΄π΅ be a segment on the coordinate plane with endpoints at (−2, 1) and (1, −2). If we dilate the segment from the origin by a scale factor π = 4, another segment is produced. ο§ What do we expect the coordinates of the endpoints to be? οΊ Based on what we know about the multiplicative effect dilation has on coordinates, we expect the coordinates of the endpoints of Μ Μ Μ Μ Μ Μ π΄′π΅′ to be (−8, 4) and (4, −8). Lesson 7: How Do Dilations Map Segments? This work is derived from Eureka Math ™ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from GEO-M2-TE-1.3.0-08.2015 105 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. NYS COMMON CORE MATHEMATICS CURRICULUM Lesson 7 M2 GEOMETRY ο§ The question becomes, how can we be sure that the dilation maps the points between π΄ and π΅ to the points between π΄′ and π΅′? We have already shown that the endpoints move to where we expect them to, but what about the points in between? Perhaps the dilation maps the endpoints the way we expect, but all other points form an arc of a circle or some other curve that connects the endpoints. Can you think of a way we can verify that all of the points of segment π΄π΅ map to images that lie on segment π΄′ π΅′ ? οΊ ο§ We can verify other points that belong to segment π΄π΅ using the same method as the endpoints. For example, points (−1,0) and (0, −1) of segment π΄π΅ should map to points (−4,0) and (0, −4). Using the π₯- and π¦-axes as our rays from the origin of dilation, we can clearly see that the points and their dilated images lie on the correct ray and more importantly lie on segment π΄′ π΅′ . Our next challenge is to show that dilations map segments to segments when they are not on the coordinate plane. We will prove the preliminary dilation theorem for segments: A dilation maps a line segment to a line segment sending the endpoints to the endpoints. Lesson 7: How Do Dilations Map Segments? This work is derived from Eureka Math ™ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from GEO-M2-TE-1.3.0-08.2015 106 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. Lesson 7 NYS COMMON CORE MATHEMATICS CURRICULUM M2 GEOMETRY Example 1 (2 minutes) Example 1 Case 1. Consider the case where the scale factor of dilation is π = π. Does a dilation from center πΆ map segment π·πΈ to a segment π·′πΈ′? Explain. A scale factor of π = π means that the segment and its image are equal. The dilation does not enlarge or shrink the image of the figure; it remains unchanged. Therefore, when the scale factor of dilation is π = π, then the dilation maps the segment to itself. Example 2 (3 minutes) Example 2 Case 2. Consider the case where a line π·πΈ contains the center of the dilation. Does a dilation from the center with scale factor π ≠ π map the segment π·πΈ to a segment π·′πΈ′? Explain. At this point, students should be clear that a dilation of scale factor π ≠ 1 changes the length of the segment. If necessary, explain to students that a scale factor of π ≠ 1 simply means that the figure changes in length. The goal in this example and, more broadly, this lesson is to show that a dilated segment is still a segment not some other figure. The focus of the discussion should be on showing that the dilated figure is in fact a segment, not necessarily the length of the segment. Yes. The dilation sends points π· and πΈ to points π·′ and πΈ′. Since the points π· and πΈ are collinear with the center πΆ, then both π·′ and πΈ′ are also collinear with the center πΆ. The dilation also takes all of the points between π· and πΈ to all of the points between π·′ and πΈ′ (again because their images must fall on the rays πΆπ· and πΆπΈ). Therefore, the dilation maps Μ Μ Μ Μ Μ Μ . Μ Μ Μ Μ to π·′πΈ′ π·πΈ Example 3 (12 minutes) Scaffolding: Example 3 β‘ does not contain the center πΆ of the dilation, and the scale Case 3. Consider the case where π·πΈ factor π of the dilation is not equal to 1; then, we have the situation where the key points πΆ, π·, and πΈ form β³ πΆπ·πΈ. The scale factor not being equal to 1 means that we must consider scale factors such that π < π < π and π > π. However, the proofs for each are similar, so we focus on the case when π < π < π. Lesson 7: How Do Dilations Map Segments? This work is derived from Eureka Math ™ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from GEO-M2-TE-1.3.0-08.2015 For some groups of students, it may be necessary for them to perform a dilation where the scale factor of dilation is 0 < π < 1 so they have recent experience allowing them to better answer the second question of Example 3. 107 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. NYS COMMON CORE MATHEMATICS CURRICULUM Lesson 7 M2 GEOMETRY When we dilate points π· and πΈ from center πΆ by scale factor π < π < π, as shown, what do we know about points π·′ and πΈ′? We know π·′ lies on ray πΆπ· with πΆπ·′ = π ⋅ πΆπ·, and πΈ′ lies on ray πΆπΈ with πΆπΈ′ = π ⋅ πΆπΈ. So, πΆπ·′ πΆπ· = πΆπΈ′ πΆπΈ = π. The line segment π·′πΈ′ splits the sides of β³ πΆπ·πΈ proportionally. Μ Μ Μ Μ and By the triangle side splitter theorem, we know that the lines containing π·πΈ Μ Μ Μ Μ Μ Μ π·′πΈ′ are parallel. Μ Μ Μ Μ and We use the fact that the line segment π·′πΈ′ splits the sides of β³ πΆπ·πΈ proportionally and that the lines containing π·πΈ Μ Μ Μ Μ Μ Μ π·′πΈ′ are parallel to prove that a dilation maps segments to segments. Because we already know what happens when points π· and πΈ are dilated, consider another point πΉ that is on the segment π·πΈ. After dilating πΉ from center πΆ by scale factor π to get the point πΉ′, does πΉ′ lie on the segment π·′πΈ′? Consider giving students time to discuss in small groups Marwa’s proof shown on the next page on how to prove that a dilation maps collinear points to collinear points. Also consider providing students time to make sense of it and paraphrase a presentation of the proof to a partner or the class. Consider also providing the statements for the proof and asking students to provide the reasoning for each step independently, with a partner, or in small groups. β‘ The proof below relies heavily upon the parallel postulate: Two lines are constructed, π′π′ and β‘π′π ′, both of which are β‘ and contain the point π′, they must be the same line by the parallel parallel to β‘ππ . Since both lines are parallel to ππ postulate. Thus, the point π ′ lies on the line π′π′. Note: This proof on the next page is only part of the reasoning needed to show that dilations map segments to segments. The full proof also requires showing that points between π and π are mapped to points between π′ and π′, and that this mapping is onto (that for every point on the line segment π′π′, there exists a point on segment ππ that gets sent to it). See the discussion following Marwa’s proof for more details on these steps. Lesson 7: How Do Dilations Map Segments? This work is derived from Eureka Math ™ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from GEO-M2-TE-1.3.0-08.2015 108 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. Lesson 7 NYS COMMON CORE MATHEMATICS CURRICULUM M2 GEOMETRY Marwa’s proof of the statement: Let π be a point not on β‘ππ and π·π,π be a dilation with center π and scale factor β‘ , then π·π,π (π ) is a point that 0 < π < 1 that sends point π to π′ and π to π′. If π is another point that lies on ππ β‘ lies on π′π′. Statement 1. 2. A dilation π·π,π with center π and scale factor π sends point π to π′ and π to π′ . ππ′ ππ = ππ′ ππ =π Reason 1. Given 2. By definition of dilation 3. β‘ β‘ππ ||π′π′ 3. By the triangle side splitter theorem 4. Let π be a point on segment ππ between π and π. Let π ′ be the dilation of π by π·π,π . 4. Given 5. By definition of dilation 5. ππ′ ππ = ππ ′ ππ =π Lesson 7: How Do Dilations Map Segments? This work is derived from Eureka Math ™ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from GEO-M2-TE-1.3.0-08.2015 109 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. Lesson 7 NYS COMMON CORE MATHEMATICS CURRICULUM M2 GEOMETRY 6. β‘π′π ′||ππ β‘ 6. By the triangle side splitter theorem as applied to β³ πππ and the fact that β‘ππ and β‘ππ are the same line 7. β‘π′π ′ = π′π′ β‘ 7. By the parallel postulate: Through a given external point π′ , there is at most one line parallel to a given line ππ. 8. The point π ′ lies on β‘π′π′. 8. By Step 7 There are still two subtle steps that need to be proved to show that dilations map segments to segments when the center does not lie on the line through the segment. The teacher may decide whether to show how to prove these two steps or just claim that the steps can be shown to be true. Regardless, the steps should be briefly discussed as part of what is needed to complete the proof of the full statement that dilations map segments to segments. The first additional step that needs to be shown is that points on ππ are sent to points on π′ π′ , that is, if π is between π and π, then π ′ is between π′ and π′ . To prove this, we first write out what it means for π to be between π and π: π, π , and π are different points on the same line such that ππ + π π = ππ. By the dilation theorem (Lesson 6), π′ π ′ = π ⋅ ππ , π ′ π′ = π ⋅ π π, and π′ π′ = π ⋅ ππ. Therefore, π′ π ′ + π ′ π′ = π ⋅ ππ + π ⋅ π π = π(ππ + π π) = π ⋅ ππ = π′ π′ Hence, π′ π ′ + π ′ π′ = π ′π′, and therefore π ′ is between π′ and π′. The second additional step is to show that the dilation is an onto mapping, that is, for every point π ′ that lies on π′ π′ , there is a point π that lies on ππ that is mapped to π ′ under the dilation. To prove, we use the inverse dilation at center π with scale factor 1 π to get the point π and then follow the proof above to show that π lies on ππ. Lesson 7: How Do Dilations Map Segments? This work is derived from Eureka Math ™ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from GEO-M2-TE-1.3.0-08.2015 110 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. Lesson 7 NYS COMMON CORE MATHEMATICS CURRICULUM M2 GEOMETRY Putting together the preliminary dilation theorem for segments with the dilation theorem, we get DILATION THEOREM FOR SEGMENTS: A dilation π«πΆ,π maps a line segment π·πΈ to a line segment π·′πΈ′ sending the endpoints to β‘ β‘ || π·′πΈ′ the endpoints so that π·′ πΈ′ = ππ·πΈ. Whenever the center πΆ does not lie in line π·πΈ and π ≠ π, we conclude π·πΈ . β‘ β‘ or if π = π, we conclude π·πΈ β‘ = π·′πΈ′ Whenever the center πΆ lies in π·πΈ . As an aside, observe that a dilation maps parallel line segments to parallel line segments. Further, a dilation maps a directed line segment to a directed line segment that points in the same direction. If time permits, have students verify these observations with their own scale drawings. It is not imperative that students do this activity, but this idea is used in the next lesson. At this point, students just need to observe this fact or at least be made aware of it, as it is discussed in Lesson 8. Example 4 (7 minutes) Example 4 Μ Μ Μ Μ and πΉπΊ Μ Μ Μ Μ are line segments of different lengths in Now look at the converse of the dilation theorem for segments: If π·πΈ β‘ = πΉπΊ β‘ or π·πΈ β‘ || πΉπΊ β‘ . the plane, then there is a dilation that maps one to the other if and only if π·πΈ Μ Μ Μ Μ , so that Based on Examples 2 and 3, we already know that a dilation maps a segment π·πΈ to another line segment, say πΉπΊ β‘ = πΉπΊ β‘ (Example 2) or π·πΈ β‘ || πΉπΊ β‘ (Example 3). If π·πΈ β‘ || πΉπΊ β‘ , then, because π·πΈ Μ Μ Μ Μ and πΉπΊ Μ Μ Μ Μ are different lengths in the plane, π·πΈ they are the bases of a trapezoid, as shown. S R P Q Since Μ Μ Μ Μ π·πΈ and Μ Μ Μ Μ πΉπΊ are segments of different lengths, then the non-base sides of the trapezoid are not parallel, and the lines containing them meet at a point πΆ as shown. O R P S Q Recall that we want to show that a dilation maps Μ Μ Μ Μ π·πΈ to Μ Μ Μ Μ πΉπΊ. Explain how to show it. Provide students time to discuss this in partners or small groups. Lesson 7: How Do Dilations Map Segments? This work is derived from Eureka Math ™ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from GEO-M2-TE-1.3.0-08.2015 111 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. Lesson 7 NYS COMMON CORE MATHEMATICS CURRICULUM M2 GEOMETRY The triangle formed with vertex πΆ, β³ πΆπ·πΈ, has π·πΈ as its base. Since β‘π·πΈ || β‘πΉπΊ, then the segment πΉπΊ splits the sides of the triangle proportionally by the triangle side splitter theorem. Since we know the proportional side splitters of a triangle are the result of a dilation, then we know there is a dilation from center πΆ by scale factor π that maps points π· Μ Μ Μ Μ to πΉπΊ Μ Μ Μ Μ . and πΈ to points πΉ and πΊ, respectively. Thus, a dilation maps π·πΈ Μ Μ Μ Μ and πΉπΊ Μ Μ Μ Μ are such that π·πΈ β‘ = πΉπΊ β‘ is left as an exercise. The case when the segments π·πΈ Exercises 1–2 (8 minutes) Students complete Exercises 1–2 in pairs. Students may need support to complete Exercise 2. A hint is shown below that can be shared with students if necessary. Exercises 1–2 In the following exercises, you will consider the case where the segment and its dilated image belong to the same line, Μ Μ Μ Μ and πΉπΊ Μ Μ Μ Μ are such that π·πΈ β‘ = πΉπΊ β‘ . that is, when π·πΈ 1. Μ Μ Μ Μ Consider points π·, πΈ, πΉ, and πΊ on a line, where π· = πΉ, as shown below. Show there is a dilation that maps π·πΈ Μ Μ Μ Μ . Where is the center of the dilation? to πΉπΊ S Q P=R Μ Μ Μ Μ to πΉπΊ Μ Μ Μ Μ , with a scale factor so that π = If we assume there is a dilation that maps π·πΈ πΉπΊ , then the center of the π·πΈ dilation must coincide with endpoints π· and πΉ because, by definition of dilation, the center maps to itself. Since points π· and πΉ coincide, it must mean that the center πΆ is such that πΆ = π· = πΉ. Since the other endpoint πΈ of π·πΈ β‘ , the dilated image of πΈ must also lie on the line (draw the ray from the center through point πΈ, and the lies on π·πΈ β‘ ). Since the dilated image of πΈ must lie on the line, and point πΊ is to the right of πΈ, then a ray coincides with π·πΈ dilation from center πΆ with scale factor π > π maps Μ Μ Μ Μ π·πΈ to Μ Μ Μ Μ Μ πΉπΊ. 2. Μ Μ Μ Μ ≠ πΉπΊ Μ Μ Μ Μ . Show there is a dilation that maps π·πΈ Μ Μ Μ Μ Consider points π·, πΈ, πΉ, and πΊ on a line as shown below where π·πΈ to Μ Μ Μ Μ πΉπΊ. Where is the center of the dilation? P Q R S Students may need some support to complete Exercise 2. Give them enough time to struggle with how to complete the Μ Μ Μ Μ as exercise and, if necessary, provide them with the following hint: Construct perpendicular line segments Μ Μ Μ Μ Μ ππ′ and π π′ shown so that ππ′ = ππ and π π ′ = π π. Lesson 7: How Do Dilations Map Segments? This work is derived from Eureka Math ™ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from GEO-M2-TE-1.3.0-08.2015 112 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. Lesson 7 NYS COMMON CORE MATHEMATICS CURRICULUM M2 GEOMETRY S' Q' P Q S R Construct perpendicular line segments of lengths π·πΈ and πΉπΊ through points π· and πΉ respectively. Note the endpoints of the perpendicular segments as πΈ′ and πΊ′ . Draw an auxiliary line through points πΈ′ and πΊ′ that β‘ (perpendicular lines), intersects with β‘π·πΈ. The intersection of the two lines is the center of dilation πΆ. Since β‘π·πΈ′||πΉπΊ′ by the triangle side splitter theorem, the segment π·πΈ′ splits the triangle β³ πΆπΉπΊ′ proportionally, so by the dilation theorem, πΉπΊ′ π·πΈ′ = π. This ratio implies that πΉπΊ′ = π ⋅ π·πΈ′. By construction, π·πΈ′ = π·πΈ and πΉπΊ′ = πΉπΊ. Therefore, πΉπΊ = π ⋅ π·πΈ. By definition of dilation, since πΉπΊ = π ⋅ π·πΈ, there is a dilation from center πΆ with scale factor π that Μ Μ Μ Μ to πΉπΊ. Μ Μ Μ Μ Μ maps π·πΈ Closing (3 minutes) Revisit the Opening Exercises. Have students explain their thinking about segments and dilated segments. Were their initial thoughts correct? Did they change their thinking after going through the examples? What made them change their minds? Then ask students to paraphrase the proofs as stated in the bullet point below. ο§ Paraphrase the proofs that show how dilations map segments to segments when π = 1 and π ≠ 1 and when the points are collinear compared to the vertices of a triangle. Either accept or correct students’ responses accordingly. Recall that the goal of the lesson is to make sense of what happens when segments are dilated. When the segment is dilated by a scale factor of π = 1, then the segment and its image would be the same length. When the points π and π are on a line containing the center, then the dilated points π′ and π′ are also collinear with the center producing an image of the segment that is a segment. When the points π and π are not collinear with the center, and the segment is dilated by a scale factor of π ≠ 1, then the point π′ lies on the ray ππ with ππ′ = π ⋅ ππ, and π′lies on ππ with π′ = π ⋅ ππ. Then ππ′ ππ = ππ′ ππ = π. Μ Μ Μ Μ Μ Μ π′π′ splits the sides of β³ πππ proportionally, and by the triangle side splitter theorem, the lines containing Μ Μ Μ Μ ππ and Μ Μ Μ Μ Μ Μ π′π′ are parallel. Lesson Summary ο§ When a segment is dilated by a scale factor of π = π, then the segment and its image would be the same length. ο§ When the points π· and πΈ are on a line containing the center, then the dilated points π·′ and πΈ′ are also collinear with the center producing an image of the segment that is a segment. ο§ When the points π· and πΈ are not collinear with the center and the segment is dilated by a scale factor of π ≠ π, then the point π·′ lies on the ray πΆπ·′ with πΆπ·′ = π ⋅ πΆπ·, and πΈ′ lies on ray πΆπΈ with πΆπΈ′ = π ⋅ πΆπΈ. Exit Ticket (5 minutes) Lesson 7: How Do Dilations Map Segments? This work is derived from Eureka Math ™ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from GEO-M2-TE-1.3.0-08.2015 113 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. Lesson 7 NYS COMMON CORE MATHEMATICS CURRICULUM M2 GEOMETRY Name Date Lesson 7: How Do Dilations Map Segments? Exit Ticket 1. Given the dilation π·π,3 , a line segment ππ, and that π is not on β‘ππ , what can we conclude about the image of Μ Μ Μ Μ ππ ? 2 2. Μ Μ Μ Μ , and Μ Μ Μ Μ Μ Μ Μ Μ , determine which figure has a dilation mapping the Given figures A and B below, Μ Μ Μ Μ π΅π΄ β₯ Μ Μ Μ Μ π·πΆ , Μ Μ Μ Μ ππ β₯ ππ ππ ≅ ππ parallel line segments, and locate the center of dilation π. For one of the figures, a dilation does not exist. Explain why. Figure A Figure B Lesson 7: How Do Dilations Map Segments? This work is derived from Eureka Math ™ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from GEO-M2-TE-1.3.0-08.2015 114 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. Lesson 7 NYS COMMON CORE MATHEMATICS CURRICULUM M2 GEOMETRY Exit Ticket Sample Solutions 1. Μ Μ Μ Μ ? Given the dilation π«πΆ,π , a line segment π·πΈ, and that πΆ is not on β‘π·πΈ, what can we conclude about the image of π·πΈ π π Since π· and πΈ are not in line with πΆ, Μ Μ Μ Μ Μ Μ π·′πΈ′ is parallel to Μ Μ Μ Μ π·πΈ, and π·′ πΈ′ = (π·πΈ). π 2. Given figures A and B below, Μ Μ Μ Μ π©π¨ β₯ Μ Μ Μ Μ π«πͺ, Μ Μ Μ Μ πΌπ½ β₯ Μ Μ Μ Μ πΏπ, and Μ Μ Μ Μ πΌπ½ ≅ Μ Μ Μ Μ πΏπ, determine which figure has a dilation mapping the parallel line segments, and locate the center of dilation πΆ. For one of the figures, a dilation does not exist. Explain why. π Figure A Μ Μ Μ Μ to πΏπ Μ Μ Μ Μ . If the segments are both There is no dilation that maps πΌπ½ parallel and congruent, then they form two sides of a parallelogram, which means that β‘πΌπΏ β₯ β‘π½π. If there was a dilation mapping Μ Μ Μ Μ πΌπ½ to Μ Μ Μ Μ πΏπ, then β‘πΌπΏ and β‘π½π would have to intersect at the center of dilation, but they cannot intersect because they are parallel. We also showed that a directed line segment maps to a directed line segment pointing in the same direction, so it is not possible for πΌ to map to π and also π½ map to πΏ under a dilation. Figure B Lesson 7: How Do Dilations Map Segments? This work is derived from Eureka Math ™ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from GEO-M2-TE-1.3.0-08.2015 115 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. NYS COMMON CORE MATHEMATICS CURRICULUM Lesson 7 M2 GEOMETRY Problem Set Sample Solutions 1. Draw the dilation of parallelogram π¨π©πͺπ« from center πΆ using the scale factor π = π, and then answer the questions that follow. a. Is the image π¨′π©′πͺ′π«′ also a parallelogram? Explain. Μ Μ Μ Μ Μ Μ and π©π« Μ Μ Μ Μ Μ Μ , and because π¨πͺ Μ Μ Μ Μ Μ Μ β₯ π©′π«′ Μ Μ Μ Μ Μ Μ . A Μ Μ Μ Μ β₯ π¨′πͺ′ Μ Μ Μ Μ β₯ π©π« Μ Μ Μ Μ Μ β₯ π©′π«′ Μ Μ Μ Μ Μ , it follows that π¨′πͺ′ Yes By the dilation theorem, π¨πͺ Μ Μ Μ Μ Μ Μ β₯ π©′π«′ Μ Μ Μ Μ Μ Μ and π¨′π©′ Μ Μ Μ Μ Μ Μ β₯ πͺ′π«′ Μ Μ Μ Μ Μ Μ , π¨′π©′πͺ′π«′ is similar argument follows for the other pair of opposite sides, so with π¨′πͺ′ a parallelogram. b. What do parallel lines seem to map to under a dilation? Parallel lines map to parallel lines under dilations. 2. Given parallelogram π¨π©πͺπ« with π¨(−π, π), π©(π, −π), πͺ(−π, −π), and π«(−ππ, −π), perform a dilation of the plane centered at the origin using the following scale factors. a. Scale factor Lesson 7: π π How Do Dilations Map Segments? This work is derived from Eureka Math ™ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from GEO-M2-TE-1.3.0-08.2015 116 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. Lesson 7 NYS COMMON CORE MATHEMATICS CURRICULUM M2 GEOMETRY b. Scale factor π c. Are the images of parallel line segments under a dilation also parallel? Use your graphs to support your answer. π The slopes of sides Μ Μ Μ Μ π¨π© and Μ Μ Μ Μ πͺπ« in the original graph are − , and the slopes of each of the images of those π π π π Μ Μ Μ Μ in the original graph are , and the Μ Μ Μ Μ and π©πͺ sides under the dilations are also − . The slopes of sides π¨π« π π slopes of each of the images of those sides under the dilations are also . This informally verifies that the π images of parallel line segments are also parallel line segments. 3. In Lesson 7, Example 3, we proved that a line segment π·πΈ, where πΆ, π·, and πΈ are the vertices of a triangle, maps to a line segment π·′πΈ′ under a dilation with a scale factor π < π. Using a similar proof, prove that for πΆ not on β‘π·πΈ, a dilation with center πΆ and scale factor π > π maps a point πΉ on π·πΈ to a point πΉ′ on line π·πΈ. The proof follows almost exactly the same as the proof of Example 3, but using the following diagram instead: Lesson 7: How Do Dilations Map Segments? This work is derived from Eureka Math ™ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from GEO-M2-TE-1.3.0-08.2015 117 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. Lesson 7 NYS COMMON CORE MATHEMATICS CURRICULUM M2 GEOMETRY 4. Μ Μ Μ Μ β₯ Μ Μ Μ Μ Μ Μ β‘ ≠ β‘π¨′π©′. Describe a dilation mapping π¨π© Μ Μ Μ Μ to Μ Μ Μ Μ Μ Μ On the plane, π¨π© π¨′π©′ and π¨π© π¨′π©′. (Hint: There are 2 cases to consider.) Case 1: Μ Μ Μ Μ π¨π© and Μ Μ Μ Μ Μ Μ π¨′π©′ are parallel directed line segments oriented in the same direction. By the dilation theorem for segments, there is a dilation mapping π¨ and π© to π¨′ and π©′, respectively. Case 2: Μ Μ Μ Μ π¨π© and Μ Μ Μ Μ Μ Μ π¨′π©′ are parallel directed line segments oriented in the opposite directions. We showed that directed line segments map to directed line segments that are oriented in the same direction, so there is a dilation mapping the parallel segments but only where the dilation maps π¨ and π© to π©′ and π¨′, respectively. Note to the teacher: Students may state that a scale factor π < 0 would produce the figure below where the center of a dilation is between the segments; however, this violates the definition of dilation. In such a case, discuss the fact that a scale factor must be greater than 0; otherwise, it would create negative distance, which of course does not make mathematical sense. 5. Only one of Figures π¨, π©, or πͺ below contains a dilation that maps π¨ to π¨′ and π© to π©′. Explain for each figure why the dilation does or does not exist. For each figure, assume that β‘π¨π© ≠ β‘π¨′π©′. a. Μ Μ Μ Μ Μ Μ are line segments in the plane of different lengths, then there is a Μ Μ Μ Μ and π¨′π©′ By the dilation theorem, if π¨π© β‘ β‘ β‘ = π¨′π©′ β‘ || π¨′π©′ dilation that maps one to the other if and only if π¨π© or π¨π© . The segments do not lie in the same line and are also not parallel, so there is no dilation mapping π¨ to π¨′ and π© to π©′. Lesson 7: How Do Dilations Map Segments? This work is derived from Eureka Math ™ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from GEO-M2-TE-1.3.0-08.2015 118 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. NYS COMMON CORE MATHEMATICS CURRICULUM Lesson 7 M2 GEOMETRY b. Μ Μ Μ Μ Μ Μ are line segments in the plane of different lengths, then there is a Μ Μ Μ Μ and π¨′π©′ By the dilation theorem, if π¨π© β‘ β‘ β‘ = π¨′π©′ β‘ || π¨′π©′ Μ Μ Μ Μ and dilation that maps one to the other if and only if π¨π© or π¨π© . The diagram shows that π¨π© Μ Μ Μ Μ Μ Μ π¨′π©′ do not lie in the same line, and it can also be seen that the line segments are not parallel. Furthermore, for the dilation to exist that maps π¨ to π¨′ and π© to π©′, the center of dilation π· would need to be between the segments, which violates the definition of dilation. Therefore, there is no dilation in Figure B mapping π¨ and π© to π¨′ and π©′, respectively. c. By the dilation theorem, if Μ Μ Μ Μ π¨π© and Μ Μ Μ Μ Μ Μ π¨′π©′ are line segments in the plane of different lengths, then there is a dilation that maps one to the other if and only if β‘π¨π© = β‘π¨′π©′ or β‘π¨π© || β‘π¨′π©′. Assuming that β‘π¨π© ≠ β‘π¨′π©′, the segments are shown to lie in the same line; therefore, the dilation exists. Lesson 7: How Do Dilations Map Segments? This work is derived from Eureka Math ™ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from GEO-M2-TE-1.3.0-08.2015 119 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.