Ch 7.4: Basic Theory of Systems of First Order Linear Equations The general theory of a system of n first order linear equations x1 p11 (t ) x1 p12 (t ) x2 p1n (t ) xn g1 (t ) x2 p21 (t ) x1 p22 (t ) x2 p2 n (t ) xn g 2 (t ) xn pn1 (t ) x1 pn 2 (t ) x2 pnn (t ) xn g n (t ) parallels that of a single nth order linear equation. This system can be written as x' = P(t)x + g(t), where x1 (t ) g1 (t ) p11 (t ) x2 (t ) g 2 (t ) p21 (t ) x(t ) , g(t ) , P(t ) x (t ) g (t ) p (t ) n n n1 p12 (t ) p1n (t ) p22 (t ) p2 n (t ) pn 2 (t ) pnn (t ) Vector Solutions of an ODE System A vector x = (t) is a solution of x' = P(t)x + g(t) if the components of x, x1 1 (t ), x2 2 (t ), , xn n (t ), satisfy the system of equations on I: < t < . For comparison, recall that x' = P(t)x + g(t) represents our system of equations x1 p11 (t ) x1 p12 (t ) x2 p1n (t ) xn g1 (t ) x2 p21 (t ) x1 p22 (t ) x2 p2 n (t ) xn g 2 (t ) xn pn1 (t ) x1 pn 2 (t ) x2 pnn (t ) xn g n (t ) Assuming P and g continuous on I, such a solution exists by Theorem 7.1.2. Example 1 Consider the homogeneous equation x' = P(t)x below, with the solutions x as indicated. 1 1 x ; x 4 1 e3t 1 3t x(t ) 3t e 2e 2 To see that x is a solution, substitute x into the equation and perform the indicated operations: 1 1 1 1 e3t 3e3t e3t x 3t 3t 3 3t x 4 1 4 1 2e 6e 2e Homogeneous Case; Vector Function Notation As in Chapters 3 and 4, we first examine the general homogeneous equation x' = P(t)x. Also, the following notation for the vector functions x(1), x(2),…, x(k),… will be used: x11 (t ) x12 (t ) x1n (t ) x21 (t ) ( 2) x22 (t ) x2 n (t ) (1) (k ) x (t ) , x (t ) ,, x (t ) , x (t ) x (t ) x (t ) n1 n2 nn Theorem 7.4.1 If the vector functions x(1) and x(2) are solutions of the system x' = P(t)x, then the linear combination c1x(1) + c2x(2) is also a solution for any constants c1 and c2. Note: By repeatedly applying the result of this theorem, it can be seen that every finite linear combination x c1x (1) (t ) c2 x ( 2) (t ) ck x ( k ) (t ) of solutions x(1), x(2),…, x(k) is itself a solution to x' = P(t)x. Example 2 Consider the homogeneous equation x' = P(t)x below, with the two solutions x(1) and x(2) as indicated. 3t t e e 1 1 (1) ( 2) x ; x (t ) 3t , x (t ) x t 4 1 2e 2e Then x = c1x(1) + c2x(2) is also a solution: 1 1 1 1 c1e 3t 1 1 c2 e t x 3t t 4 1 4 1 2c1e 4 1 2c2 e 3c1e 3t c2 e t 3t t 6c1e 2c2 e 3e 3t e t c1 3t c2 t x 6e 2e Theorem 7.4.2 If x(1), x(2),…, x(n) are linearly independent solutions of the system x' = P(t)x for each point in I: < t < , then each solution x = (t) can be expressed uniquely in the form x c1x (1) (t ) c2 x ( 2) (t ) cn x ( n ) (t ) If solutions x(1),…, x(n) are linearly independent for each point in I: < t < , then they are fundamental solutions on I, and the general solution is given by x c1x (1) (t ) c2 x ( 2) (t ) cn x ( n ) (t ) The Wronskian and Linear Independence The proof of Thm 7.4.2 uses the fact that if x(1), x(2),…, x(n) are linearly independent on I, then detX(t) 0 on I, where x11 (t ) x1n (t ) X(t ) , x (t ) x (t ) nn n1 The Wronskian of x(1),…, x(n) is defined as W[x(1),…, x(n)](t) = detX(t). It follows that W[x(1),…, x(n)](t) 0 on I iff x(1),…, x(n) are linearly independent for each point in I. Theorem 7.4.3 If x(1), x(2),…, x(n) are solutions of the system x' = P(t)x on I: < t < , then the Wronskian W[x(1),…, x(n)](t) is either identically zero on I or else is never zero on I. This result enables us to determine whether a given set of solutions x(1), x(2),…, x(n) are fundamental solutions by evaluating W[x(1),…, x(n)](t) at any point t in < t < .