Aim: How do we find the zeros of polynomial functions? Do Now: A rectangular playing field with a perimeter of 100 meters is to have an area of at least 500 square meters. Within what bounds must the length of the rectangle lie? Aim: Roots of Polynomial Equations Course: Alg. 2 & Trig. General Features of a Polynomial Function DEFINITION: Function Describe somePolynomial basic characteristics of thisinteger and let a , a , Let n be a nonnegative 0 1 function: a ,polynomial . . . a , a be real numbers with a ≠ 0. 4 2 2 n-1 n n The function given by Continuous n - 1 + . . . . + a x2 + a x + a f(x) =noanbreaks xn + anin x curve -1 2 1 0 5 -2 -4 is aSmooth polynomial function of degree n. The leading coefficient no sharp turnsis an. The zero function f(x) = 0 is a polynomial function. It has no sharp turn discontinuous degree and no leading coefficient. -6 -8 10 4 8 2 NOT POLYNOMIAL FUNCTIONS 6 5 4 -2 2 -4 5 -6 -2 Aim: Roots of Polynomial Equations Course: Alg. 2 & Trig. General Features of a Polynomial Function Standard Form Degree P( x) 2 x 5 x 2 x 5 3 2 Leading Coefficient Cubic Quadratic Linear Constant term term term term Polynomial of 4 terms Aim: Roots of Polynomial Equations Course: Alg. 2 & Trig. General Features of a Polynomial Function Simplest form of any polynomial: y = xn n>0 When n is even When n is odd looks similar to x2 looks similar to x3 f x = x2 rx = x3 6 hx = x4 q x = x 6 sx = x5 4 4 2 t x = x7 2 -5 -2 -5 5 -4 The greater the value of n, the flatter the graph is on the interval [ -1, 1]. Aim: Roots of Polynomial Equations Course: Alg. 2 & Trig. Transformations of Higher Degree Polys If k and h are positive numbers and f(x) is a function, then f(x ± h) ± k shifts f(x) right or left h units shifts f(x) up or down k units f(x) = (x – h)3 + k - cubic f(x) = (x – h)4 + k - quartic ex. f(x) = (x – 4)4 – 2 ux = x4 4 2 5 -5 vx = x-4 4 -2 -2 Aim: Roots of Polynomial Equations Course: Alg. 2 & Trig. Zeros of Polynomial Functions The zero of a function is a number x for which f(x) = 0. Graphically it’s the point where the graph crosses the x-axis. For polynomial function f of degree n, •the function f has at most n real zeros •the graph of f has at most n – 1 relative extrema (relative max. or min.). Ex. Find the zeros of f(x) = x2 + 3x f(x) = 0 = x2 + 3x = x(x + 3) x = 0 and x = -3 4 2 -5 -2 How many roots does f(x) = x2 + 1 have? Aim: Roots of Polynomial Equations Course: Alg. 2 & Trig. Fundamental Theorem of Algebra If f(x) is a polynomial of degree n, where n > 0, then f has at least one zero in the complex number plane. Degree of polynomial 1st n=1 2nd n=2 3rd n=3 4th n=4 Function Zeros f(x) = x – 3 x=3 f(x) = x2 – 6x + 9 = (x – 3)(x – 3) f(x) = x3 + 4x = x(x – 2i)(x + 2i) x = 3 and x = 3 repeated zero x = 0, x = 2i, x = -2i f(x) = x4 – 1 = x = 1, x = -1, (x – 1)(x + 1)(x – i)(x + i) x = i, x = -i Aim: Roots of Polynomial Equations Course: Alg. 2 & Trig. Finding Zeros 2 Find the zeros of f(x) = x3 – x2 – 2x •Has at most 3 real roots •Has 2 relative extrema -2 f(x) = 0 = x3 – x2 – 2x = x(x2 – x – 2) = x(x – 2)(x + 1) x = 0, x = 2 and x = -1 Aim: Roots of Polynomial Equations -4 Course: Alg. 2 & Trig. Finding a Function Given the Zeros Write a quadratic function whose zeros (roots) are -2 and 4. x=4 x = -2 x+2=0 x–4=0 (x + 2)(x – 4) = 0 x2 – 2x – 8 = 0 x2 – 2x – 8 = f(x) reverse the process used to solve the quadratic equation. Find a polynomial function with the following zeros: -2, -1, 1, 2 f(x) = (x + 2)(x + 1)(x – 1)(x – 2) f(x) = (x2 – 4)(x2 – 1) = x4 – 5x2 + 4 Aim: Roots of Polynomial Equations Course: Alg. 2 & Trig. Multiplicity Find the zeros of f(x) = x4 + 6x3 + 8x2. f(x) = x4 + 6x3 + 8x2 x2 x2 6 x 8 f x = x 4+6x 3+8x 2 6 GCF x 2 x 4 x 2 4 Factor trinomial 2 x 4 0 Zero Product Property x 2 =0 x 0 Multiple zeros - Multiplicity of 2 x 4 A multiple zero has a multiplicity equal to the numbers of times the x 2 zero occurs. x2 0 -5 -2 Aim: Roots of Polynomial Equations Course: Alg. 2 & Trig. Regents Prep The graph of y = f(x) 15 is shown at right. 10 Which set lists all the real solutions of f(x) = 0? 5 -2 2 1. {-3, 2} -5 2. {-2, 3} -10 3. {-3, 0, 2} 4. {-2, 0, 3} Aim: Roots of Polynomial Equations -15 Course: Alg. 2 & Trig. 4 Model Problem Find the zeros of f(x) = 27x3 + 1. 27 x 3 1 0 3x 3 Sum of perfect cubes 1 0 Rewrite as sum of cubes u 3x v 1 3 3 x 1 3 x 2 3x 1 0 Factor 3 x 1 9 x 2 3x 1 0 Simplify 3x 1 0 Zero Product Property 2 9 x 3 x 1 0 2 9 x 3x 1 0 1 3 x 1 0; x 3 Quadratic Formula Factoring Difference/Sum of Perfect Cubes 2 + uv + v2) u3 – v3 = (u – v)(u Aim: Roots of Polynomial Equations u3 + v3 = (u + v)(u2 – uv + v2) Course: Alg. 2 & Trig. Model Problem Find the zeros of f(x) = 27x3 + 1. 1 3 x 1 0; x 3 2 9x 3x 1 0 b b 2 4ac x Quadratic Formula 2a x 3 3 4 9 1 2 9 2 3 27 3 3i 3 1 i 3 18 18 6 1 1 i 3 x and 3 6 Aim: Roots of Polynomial Equations Course: Alg. 2 & Trig. Polynomial in Quadratic Form f ( x) 0 the zeros of function Find the zeros f ( x ) x 4 4 x 2 4 = 0 u x2 f ( u) u 2 4u 4 u 2 u 2 0 u 2 u 2 0; u2 u 2 x 2; x 2 u 2 x 2; x 2 2 u’s – 4 zeros zero @ + 2 - Multiplicity of 2 zero @ 2 - Multiplicity of 2 x 2x 2 2 2 2 0 x 2 2 2 x 2 2 0; x 2 x2 2 0 x 2 Aim: Roots of Polynomial Equations 2 0 Course: Alg. 2 & Trig. Finding zeros by Factoring by Groups Find the roots of the following polynomial function. f x = x 3-2x 2-3x +6 f(x) = x3 – 2x2 – 3x + 6 = 0 6 Group terms (x3 – 2x2) – (3x – 6) = 0 Factor Groups x2(x – 2) – 3(x – 2) = 0 4 2 Distributive Property Solve for x (x2 – 3)(x – 2) = 0 x2 – 3 = 0; x 3 1.73 x – 2 = 0; x=2 Aim: Roots of Polynomial Equations Course: Alg. 2 & Trig. Regents Prep Factored completely, the expression 12x4 + 10x3 – 12x2 is equivalent to 1) x 2 4 x 6 3 x 2 2) 2 2 x 2 3 x 3x2 2x 3) 2x 2 2 x 3 3 x 2 4) 2x 2 2 x 3 3 x 2 Aim: Roots of Polynomial Equations Course: Alg. 2 & Trig.