LESSON PLAN
Name of the teacher : Anjana .A
Standard
: IX
Name of the school : St.vincent ‘s H .S.Kaniyapuram
Date
: 25.07.2014
Subject
: Mathematics
Duration
: 40 min
Unit
: Pairs of equations
Strength
: 40
Subunit
: pairs of equations
CURRICULAR STATEMENT
Computing the value of the numbers in the equations if the
equations have only one unknown numbers.
CONTENT ANALYSIS
TERMS
:
Equations, Variables.
FACTS
:
1.Variables are the letters used to denote numbers in
algebraic expressions.
2. Mathematical expressions with equal signs are
equations.
CONCEPT
:
The concept of pairs of equations .
PROCESS
:
Process of finding the values of unknown numbers .
PRE-REQUISITES
Equations,terms
TEACHING LEARNING RESOURCES
CC
CCharts showing equations, internet resource
Class room interaction procedure
Pupil response
Activity 1 : Introduction
TT The teacher asks some informal questions
to create a friendly rapport with the students .
Teacher triggers the thought of the learners by
asking. Certain questions which lead to the
Previous knowledge.
Teacher asks the below mathematical concepts
Converted in to equations .
1. The number of boys and girls in a
classroom is 42.
x+y =42 , x is the
no.of boys .
y is the
no.of girls .
2. The difference of two numbers is 7 .
3. The length of the rectangle is three times
larger than the breadth of the rectangle .
x-y = 7
x is the breadth of the
rectangle then the length
of the rectangle is 3x .
Class room interaction procedure
Pupil response
Yes ,very good you tell the right answers .
Activity 2 : Development
Any one of you defines the term equations ?
Ok, all of you known about equations right ?
Mathematical expressions
With equal signs are
equations.
Yes
Now we are going to study about pairs of
equations .
I will give you a simple question you think and
answer it .Ok ?
Ok
Three books of the same price and a pen for five
rupees were brought for thirty five rupees .What
Is the price of one book ?
Price of one book is Rs 10
How do you get the answer ?
Cost of a pen is Rs 5
Cost of three books = Rs 30
So,cost of one book = 30 /3
=Rs 10
Very good
Class room interaction procedure
Pupil response
ACTIVITY 3
The process of introducing the known
numbers.
We can go through a problem .
The perimeter of a rectangle is 20 cm ; and its
length is 2 cm more than the breadth.
Draw a rectangle ?
What is the length of each side ?
20cm
The perimeter of a rectangle is ?
What about the length of the rectangle ?
Its length is 2cm more than
the breadth of the
rectangle .
No
Do you know the breadth of the rectangle?
Then how can you find the length ?
Yes
Here breadth is unknown right ?
Yes
So we can take breadth as a unknown number .
Do you agree with me ?
How we can denote it ?
How ?
We can denote it by using
Variables .
Take the unknown number
as x.
Breadth = x
Class room interaction procedure
Pupil response
Ok, your answer is in the right way.
Then what about its length ?
Its length is 2 cm more
than the breadth.
length = x + 2
Correct ,then we will find the value of
X right ?
How can we find it ?
yes
Perimeter of rectangle is
20 cm.
Then
2 [x+x+2] =20
2x+2
=10
X+1
=5
X
=4
So we find the value of unknown number that is
Its breadth, right ?
yes
Then find its length ?
Length = 4+2
= 6 cm
Activity 4 : Group activity
Divided the students in to two groups and gave
two problems .
Group 1
In a box there are black and white beads . The
number of black beads is eight more than the
number of white beads and the total number of
beads are four times the number white beads .
How many black and how many beads are there
In the box ?
Class room interaction procedure
Pupil response
Group 2
In a box there are black and white beads . The
number of black beads is 5 more than the number
Of whit beads, and the total number of beads is
three times the number of white beads . How many
black and how many beads are there in the box ?
Group 1
The no .of white beads
=x
The no.of black beads
=x+8
The total no.of beads
=4x
We get the equation
X+(x+8) =4x
2x +8
=4x
2x
=8
X
=4
Group 2
The no.of white beads
=y
The no.of black beads
=y+5
The total no.of beads
=3y
We get the equation
Y+(y+5) =3y
2y+5
=3y
y
= 5
Class room interaction procedure
Pupil response
Ok, tell the answer
Group 1
No.of white beads
=x
=4
No.of black beads
=x+8
=4+8
=12
Group 2
No .of white beads
=y
=5
No.of black beads
=y+5
=5+5
=10
So , do you understand how to find the
Value of unknown numbers ?
yes
REVIEW
1.What is mean by an equation ?
2. In this chapter how we can used variable ?
FOLLOW –UP ACTIVITY
1. The perimeter of a rectangle is 20 cm and its length 2 cm more than
the breadth . What is the length of each side ?
2. When five pens were bought together , the total price was reduced by
three rupees and only seventeen rupees had to be paid . Had they
been bought one by one , how much would have been the price of
each pen ?