Chp 11 Gas Laws Pages 369 377 Boyle’s Law P Volume (mL) Pressure (torr) P·V (mL·torr) 10.0 20.0 30.0 40.0 760.0 379.6 253.2 191.0 7.60 x 103 7.59 x 103 7.60 x 103 7.64 x 103 PV = k V Boyle’s Law The pressure and volume of a gas are inversely related (at constant mass & temp) P PV = k V Boyle’s Law Boyle’s Law 4e20.40.mpeg No sound … In all movies, the air is being pumped out from the jar, which DECREASES PRESSURE. You can easily see that the VOLUME of a gas INCREASES as you DECREASE PRESSURE! Boyle’s Law P 1 V 1 = P2 V 2 Initial Pressure and Volume Changed Pressure and Volume V2 Boyle’s Law Practice Problem #1 P1 V1 A gas occupies a volume of 458 mL at a pressure of 1.01 kPa and temperature of 295 K. When the pressure is changed, the volume becomes 477 mL, If there has been no change in temperature, what is the new pressure? P 1 V1 = P2 V2 Boyle’s Law P 1 V1 = P 2 V2 (1.01 kPa)(458 mL) = P2 (477 mL) P2 = P2 = (1.01 kPa) (458 mL) (477 mL) 0.970 kPa Charle’s Law V T Volume (mL) Temperature (K) V/T (mL/K) 40.0 44.0 47.7 51.3 273.2 298.2 323.2 348.2 0.146 0.148 0.148 0.147 V k T Charle’s Law The volume of a fixed amount of gas is directly proportional to its absolute temperature. (at constant pressure) V T V k T Charle’s Law No sound … it is easy to see that as the gas TEMPERATURE INCREASES, the VOLUME INCREASES! Charle’s Law V1 T1 Initial Volume and Temperature = V2 T2 Changed Volume and Temperature T2 Charle’s Law V1 T1 Practice Problem #6 What will be the volume of a gas sample at 309 K if its volume at 215 K is 3.42 L V1 T1 = V2 T2 Charle’s Law V1 T1 = 3.42 L 215 K V2 T2 = V2 309 K (3.42 L) (309 K) V2 = 215 K = 4.92 L Dalton’s Law The sum of the partial pressures of all the components in a gas mixture is equal to the total pressure of the gas mixture. Ptotal = P1 + P2 + P3 ... Dalton’s Law P1 P2 Practice Problem #13 What is the pressure of a mixture of helium, nitrogen, and oxygen if their partial pressures are 600. mm Hg, 150. mm Hg, and 102 mm Hg? P3 Ptotal = P1 + P2 + P3 Dalton’s Law Practice Problem #13 What is the pressure of a mixture of helium, nitrogen, and oxygen if their partial pressures are 600. mm Hg, 150. mm Hg, and 102 mm Hg? Ptotal = P1 + P2 + P3 Ptotal = 600 + 150 + 102 Ptotal = 852 mm Hg *Dalton’s Law Practice Problem #16 The barometer shows the atmospheric pressure to be 762 mm Hg. What is the partial pressure of nitrogen if nitrogen makes up 78% of the air. 762 mm Hg (0.78) = 594 mm Hg Gay-Lussac’s Law The pressure of a fixed mass of gas at constant volume varies directly with the Kelvin temperature. P1 P2 = T1 T2 Combined Gas Law P V PV PV = k T P 1V 1 P 2V 2 = T1 T2 P 1 V 1T 2 = P 2V 2 T 1 Avogadro’s Law Equal volumes of gases at the same temperature and pressure contain an equal number of particles. V = k3n volume Constant (molar volume of a gas at STP) Number of moles Avogadro’s Law If you keep pressure and temperature constant, what is the only way to increase the volume? BY INCREASING THE NUMBER OF PARTICLES! V = k3n