In-class Handout, Section 3.3 and 3.4, June 5th, 2012, Page 1 of 2 Definitions from 3.3 Intercepts; Vertical and Horizontal Lines π₯-intercept (p. 182) The π₯-coodinate of a point, sometimes designated π, where a graph intersects the π₯-axis is an π₯-intercept. The π¦-coordinate of any π₯-intercept must be zero. π¦-intercept (p. 182) The π¦-coordinate of a point, sometimes designated π, where a graph intersects the π¦-axis is a π¦-intercept. The π₯-coordinate of any π¦-intercept must be zero. Horizontal Line (p. 185) The equation of a horizontal line with π¦-intercept π is π¦ = π. Also, the slope of any horizontal line is zero. Vertical Line (p. 186) The equation of a vertical line with π₯-intercept π is π₯ = π. Also, the slope of any vertical line is undefined. Definitions from 3.4 Slope and Rate of Change Slope (informal) (p. 193) The slope is a real number that measures the “tilt” or “angle” of a line. Slope, π (p. 194) The slope π of the line passing through the points (π₯1 , π¦1 ) and (π₯2 , π¦2 ) is π= πππ π ππ’π = π¦2 −π¦1 π₯2 −π₯1 Please memorize! Slope, positive (p. 196) A line with a positive slope rises from left-to-right. Slope, negative (p. 196) A line with a negative slope falls from left-to-right. Slope (word problems) (p. 198) The slope represents the rate of change between the units of the π¦-variable and the units of the π₯-variable. Example, Finding Intercepts, p. 182, Q29: What is the π₯-intercept and the π¦-intercept of the line given by the equation 4π₯ − π¦ = 8? ο· ο· ο· Find the π₯-intercept: Set π¦ = 0. Find the π¦-intercept: Set π₯ = 0. 4π₯ − 0 = 8 4π₯ = 8 π₯=2 So, the π₯-intercept is π = 2 or (2, 0) 4β0−π¦ =8 −π¦ = 8 π¦ = −8 So, the π¦-intercept is π = −8 or (0, −8) Shortcut Method: Recognize that the equation is in Standard Form (p. 175) π΄π₯ + π΅π¦ = πΆ and use the shortcut formulas (presented in an earlier handout). π₯-intercept, π = πΆ π΄ 8 = 4 = 2 or (2, 0) π¦-intercept, π = πΆ π΅ 8 = −1 = −8 or (0, −8) Examples, Graphing Horizontal and Vertical Lines, p. 185, p. 186: A) Graph the equation π¦ = −3. ο· ο· If we were graphing this on a number line, the result might look like: However, on an π₯π¦-plane the equation π¦ = −3 has a different look (see below): -3 π¦-axis Why is the graph a point on a number line but a line in the 2D π₯π¦-plane? One explanation is that the line represents all solutions to the equation π¦ = −3. Every point on the line has a π¦-coordinate of −3 and this is enough to be a solution to the given equation π¦ = −3. 5 π¦-axis 4 3 2 1 π₯-axis 0 -5 -4 -3 -2 -1 0 1 2 3 4 5 -1 -2 π¦ = −3 -3 -4 -5 B) Graph the equation π₯ = −2. ο· If you recognize that an equation is missing a variable, in this case π¦, this means you can set the missing variable to any value. The one constant is that π₯ = −2 no matter what the value of π¦ is. Using a table: π π ο· −2 0 −2 1 −2 2 Graphing these points should result in a vertical line (left to the student to graph). −2 3 In-class Handout, Section 3.3 and 3.4, June 5th, 2012, Page 2 of 2 Example, Calculating the Slope, p. 194 Calculate the slope of a line passing through the points (−3, 2) and (2, −1). ο· One method would be the sketch these two points and use the formula π = π ππ π . π π’π The disadvantages of this method are that a sketch may be inaccurate and if your problem has fractions or decimals then it will be more difficult to get an accurate result. ο· π= The preferred method is to use the formula o First, label your points: ο· Then, plug these values into the formula: π¦2 −π¦1 π₯2 −π₯1 (−3, 2) π₯1 π¦1 π= ο· . Summarizing, the slope of this line is (2, −1) π₯2 π¦2 π¦2 − π¦1 −1 − 2 3 = =− π₯2 − π₯1 2 − (−3) 5 π=− 3 5 Example, Calculating the Slope from a Graph, p. 196 What is the slope of the line in the graph? 5 4 3 2 1 Look for perfect intersections through the grid. 0 -5 -4 -3 Rise -2 -1 0 1 2 3 4 5 -1 -2 -3 Run -4 -5 Either write the coordinates of two points and use the method of the previous example. Or use π = π ππ π π π’π = −4 . 5 Example, Sketch a Line with a Given Slope, p. 197 Sketch a line with the slope π = 2 that passes through the point (−1, −1). ο· The slope cannot be used until we graph the point. So the first step is to graph the point. ο· From this point, we can use the slope π = 1. Rise positive 2 (go up) and Run positive 1 (go right). ο· Alternatively, we can Rise negative 2 (go down) and Run negative 1 (go left) since π = 1 = −1 2 2 −2 5 4 3 2 1 0 -5 -4 -3 -2 -1 0 1 2 3 4 5 -1 -2 -3 -4 -5 (finish the sketch) Example, Recognizing the Slope in a Word Problem A car travels at 60 mph. Over 4 hours it will cover 240 miles. ο· ο· ο· In this problem, which number corresponds to a slope? In the formula π = ππ‘ which variable corresponds to the slope? (Which variable corresponds to the π₯variable or input; which variable corresponds to the π¦-variable or output) How would you graph the distance a car travels at 60 mph for π‘ hours?