Topic 10: Thermal physics 10.3 The second law and entropy 10.3.1 State that the second law of thermodynamics implies that thermal energy cannot spontaneously transfer from a region of low temperature to a region of high temperature. 10.3.2 State that entropy is a system property that expresses the degree of disorder of a system. 10.3.3 State the second law of thermodynamics in terms of entropy changes. 10.3.4 Discuss examples of natural processes in terms of entropy changes. Topic 10: Thermal physics 10.3 The second law and entropy State that the second law of thermodynamics implies that thermal energy cannot spontaneously transfer from a region of low temperature to a region of high temperature. In the previous lesson we studied hot reservoir at TH the heat engine. Because heat energy has a tendency QH to flow from objects of high temperature to objects of low engine W temperature, useful work can be harvested during the process. Visualize the internal combustion QL engine where fuel and oxygen ignite to produce great heat, which cold reservoir at TL then does work, and is exhausted at a lower temperature. Topic 10: Thermal physics 10.3 The second law and entropy State that the second law of thermodynamics implies that thermal energy cannot spontaneously transfer from a region of low temperature to a region of high temperature. Because heat energy does NOT have a hot reservoir at TH tendency to flow from objects of LOW temperature to objects of HIGH QH temperature, the reverse process does not naturally occur. pump W If we want it to happen, we must do work ON the system. This is what a heat pump does. QL Visualize the refrigerator, which cold reservoir through external work removes heat at TL from cold objects inside and pumps it into the warm air outside. Topic 10: Thermal physics 10.3 The second law and entropy State that the second law of thermodynamics implies that thermal energy cannot spontaneously transfer from a region of low temperature to a region of high temperature. The second law of thermodynamics has various forms of statement: STATEMENT 1: (Has to do with heat pumps.) ”Heat will not flow spontaneously from a colder body into a warmer body.” STATEMENT 2: (Has to do with heat engines.) ”No heat engine which operates in a cycle can be 100% efficient.” FYI A corollary to Statement 2 is that “it is not possible to construct a perpetual motion machine.” Why? Topic 10: Thermal physics 10.3 The second law and entropy State that the second law of thermodynamics implies that thermal energy cannot spontaneously transfer from a region of low temperature to a region of high temperature. An analysis of possible cycles for heat engines performed by the great Boffins on high has shown that the following processes on an ideal gas would produce the maximum efficiency per cycle: (AB) An isothermal expansion. The Carnot Cycle (BC) An adiabatic expansion. P A (CD) An isothermal contraction. (DA) An adiabatic contraction. B FYI We call this cycle a Carnot cycle. D An engine having maximum efficienC cy is called a Carnot engine. V Topic 10: Thermal physics 10.3 The second law and entropy State that the second law of thermodynamics implies that thermal energy cannot spontaneously transfer from a region of low temperature to a region of high temperature. The efficiency of a Carnot engine can be calculated using the following relationship: Efficiency = 1 – ( Tcold / Thot ) The temperatures are absolute. EXAMPLE: Find the efficiency of a Carnot engine having an operating temperature of 1500ºC which exhausts into 20ºC ambient air. SOLUTION: Tcold = 293 K and Thot = 1773 K so that Efficiency = 1 - 293/1773 = 0.85. efficiency of a Carnot engine The Carnot Cycle P A B D C V Topic 10: Thermal physics 10.3 The second law and entropy State that the second law of thermodynamics implies that thermal energy cannot spontaneously transfer from a region of low temperature to a region of high temperature. It turns out that Statement 1 and Statement 2 can be shown to be equivalent. (Not by us, mind you!) Recall our Sankey Diagrams from Topic 8: CHEMICAL POTENTIAL ENERGY ENERGY KINETIC ENERGY ELECTRICAL ENERGY Note that every process in the diagram is inefficient to some extent, and energy (the yellow) is lost at each conversion. Topic 10: Thermal physics 10.3 The second law and entropy State that entropy is a system property that expresses the degree of disorder of a system. We now define the entropy S of a system to be the degree of disorder of that system. EXAMPLE: Consider the divided container that has its lower half filled with a gas under pressure. A feather rests on top of the divider. When we pull out the divider, the air does work on the feather, increasing its potential energy (at least temporarily). We say that the system (of container, gas and feather) has become more disordered. Thus ∆S > 0. (S increased.) Furthermore, the original order cannot come back spontaneously. Topic 10: Thermal physics 10.3 The second law and entropy State that entropy is a system property that expresses the degree of disorder of a system. We now define the entropy S of a system to be the degree of disorder of that system. Measuring the entropy S of a system is difficult. However, measuring its change in entropy ∆S can be done quite easily. When thermal energy Q is given to (or taken from) a system having an absolute temperature T, the system’s change in entropy ∆S is given by ∆S = Q/T change in entropy of a system and is measured in J K-1. Its sign is that of Q. FYI If the temperature T of a system changes during a thermodynamic process, we must use calculus. Topic 10: Thermal physics 10.3 The second law and entropy State that entropy is a system property that expresses the degree of disorder of a system. ∆S = Q/T change in entropy of a system PRACTICE: Find the change in entropy caused by freezing 50 grams of water at 0°C to ice at 0°C. SOLUTION: Recall from Topic 3 that during phase changes T remains constant. Thus the formula ∆S = Q/T applies, with T a constant 273 K. During phase change we use Q = mL. For freezing water we remove energy so that Q = -mL = -(.050 kg)(3.33105 J/kg) = -16650 J. Then ∆S = Q/T = (-16650 J) / 273 K = -60 J K-1. Since the entropy decreased that means that the order of the system increased. Did it? Topic 10: Thermal physics 10.3 The second law and entropy State the second law of thermodynamics in terms of entropy changes. The second law can also be expressed in terms of entropy: STATEMENT 3: (Has to do with entropy.) ”In any process, the entropy of the universe must either stay the same, or it must increase.” EXAMPLE: Our previous example showed that the entropy of the ice cube decreased. Does this violate the second law of thermodynamics? SOLUTION: No, it does not. We looked only at the change in entropy of the ice cube and ignored the process used to freeze the water. As a whole, we put more heat into the system containing the ice cube than we took out. Topic 10: Thermal physics 10.3 The second law and entropy State the second law of thermodynamics in terms of entropy changes. The freezer hot reservoir PRACTICE: Show the complete system at TH used in the process of making the ice cube. QH SOLUTION: Use energy diagrams: The power plant pump CHEMICAL POTENTIAL KINETIC ELECTRICAL W ENERGY ENERGY ENERGY ENERGY QL cold reservoir at TL The heat energy represented in yellow is dissipated in the environment (increasing its entropy) and far outweighs the loss of entropy of the water! Topic 10: Thermal physics 10.3 The second law and entropy Discuss examples of natural processes in terms of entropy changes. ”In any process, the entropy of the universe must either stay the same, or it must increase.” ∆S = Q/T change in entropy of a system Note that there are two ways to increase the entropy of a system. (1) Increase Q, the thermal energy of the system. (2) Decrease T, the temperature of the system. PRACTICE: Discuss why the universe is tending toward a temperature of 0 K (its so-called heat death). SOLUTION: Assuming that Q is a fixed quantity in the universe as a whole, and that the entropy S is ever increasing, T must eventually approach 0. Topic 10: Thermal physics 10.3 The second law and entropy Discuss examples of natural processes in terms of entropy changes. EXAMPLE: Entropy has been called “the arrow of time.” Consider a wine glass that has been shattered. (a) Explain how its entropy has increased. (b) Explain how entropy prevents the glass from spontaneously reassembling itself. SOLUTION: (a) The glass is certainly more disorganized. It has lost potential energy, for example. The wine is dispersed. (b) Reassembling the glass will increase its order (decrease its entropy). According to the second law this can’t happen by itself. Topic 10: Thermal physics 10.3 The second law and entropy Discuss examples of natural processes in terms of entropy changes. Here are some “fun” facts about entropy. (1) Net entropy can be increased, but never reduced. (2) Since all natural processes create entropy, the evolution of the universe will continue to increase the entropy. (3) Thus, no matter how organized the universe appears, its tendency to disorganization is ever growing. (4) At the beginning of the big bang, the temperature of the universe was extremely high. Hence the entropy low. S has increased ever since. (5) T is presently about 3 K, and dropping! Topic 10: Thermal physics 10.3 The second law and entropy Discuss examples of natural processes in terms of entropy changes. An increase in disorder of the system. In any process the entropy of the universe must stay the same, or increase. During the development of the embryo, the egg must give off enough heat so that the surroundings have an increase in entropy greater than the chicken’s decrease. Topic 10: Thermal physics 10.3 The second law and entropy Discuss examples of natural processes in terms of entropy changes. The refrigerator adds more heat to the air than it removes. Thus BOTH increase. Topic 10: Thermal physics 10.3 The second law and entropy Discuss examples of natural processes in terms of entropy changes. Subsystems of the universe (like the freezing of water into an ice cube) may have a decrease in entropy, but overall the entropy of the whole universe is increasing. Topic 10: Thermal physics 10.3 The second law and entropy Discuss examples of natural processes in terms of entropy changes. A phase change of freezing makes for –Q so that the entropy decreases for the wax. Since the air gains a corresponding Q its entropy increases.