Bellringer
Have Notes and HW out on your desk.
Work on p. 503 #1 – 4
(Remember yesterday. If you waste my time at
the beginning, I will hold on to you and waste
your time at the end)
SPI 3108.4.15 Determine and use the
appropriate trigonometric ratio for a
right triangle to solve a contextual
problem.
Special Right Triangles
Why would we need more than our two special
right triangles??
Because there are many right triangles besides
just a 45-45-90 or 30-60-90!
We need a way to find side lengths in ALL right
triangles
SOHCAHTOA
S
O
H
C
A
H
T
O
A
SOHCAHTOA
SINE
OPPOSITE
HYPOTENUSE
COSINE
ADJACENT
HYPOTENUSE
TANGENT
OPPOSITE
ADJACENT
Opposite/Adjacent
“Opposite” means the *SIDE* that is furthest
away from the given *ANGLE*
“Adjacent” means the *SIDE* that is attached to
the given *ANGLE*
Trigonometric Ratios
These are RATIOS!! So can be written in several
ways:
First, if given the diagram, your answer should be
as a fraction or decimal (depending on the
question)
Second, if given of a degree, your answer will
definitely be a decimal using your calculator
To Find a Side Length
1. Figure out what pieces you have. Use that to
decide which ratio are we going to use.
2. Set up that ratio with the angle on one side
3. Set up the ratio using SOHCAHTOA of lengths
on the other side
• If x is on top, multiply
• If x is on the bottom, divide
Classwork/Homework
Work on p. 510 #1 – 7 which will be turned in
today!!
When you turn this in, you will receive a
worksheet which will be due tomorrow
For +5 points on the HW assignment, write/draw
your own story and solve it.