Superior Lalazar Public School and College Thana www.slpsorg.com 0932-442385 email. 0917351@rgu.ac.uk Solved Physics 9th 2013 paper Malakand Board. Section B (Marks 32) Q. 2 Answer any eight parts. Each part carries 4 marks (i) Why steam at 100C produces more severe burns than boiling water at 100C The steam at 100C produces more severe burns than boiling water at 100C because steam have latent heat of vaporization which is much higher than latent heat of boiling water. The severe burn is due to high amount of heat steam passes to the human body. (ii) What is Pascal principle? Write its practical application. Pascal Principle “ All liquids transmit pressure equally in all direction” In other words "When pressure on any portion of a confined liquid is changed, the pressure on every other part of the liquid is also changed by the same amount." Pascal's Law has a number of applications in our daily such as: i) • Hydraulic Brakes ii) • Hydraulic Press iii) • Hydraulic Lift (iii) Is the distance covered by a body may be greater than the magnitude of the dispalacement? Ans. Yes, it is possible because distance is the total length of the actual path followed by a body during its motion, but displacement is the shortest distance between initial and final position in a particular direction. For example, when a body does not move in a straight line but moves in a curved path then distance will be greater than displacement. (iv) How we can find the volume of a small pebble with the help of measuring cylinder? a. Take water in a measuring cylinder b. Note the initial volume of water by V1 c. Drop the pebble in the cylinder gently d. Note the final volume after dropping pebble inside by V2 e. Now subtract V1 from V2 f. The difference will be the volume of pebble or irregular shape body (v) Explain why white cloths are preferred wearing in summer? Ans The white cloths are preferred wearing in summer because white colour is bad absorbent but good reflector of sun light so keep our body cool due to which we feel comfortable in summer. (vi) Moon is attracted by earth why it does not fall on earth? Moon is attracted by the earth but it does not fall on earth because the gravitational force of attraction between moon and earth provides centripetal force which keeps the moon in motion around the earth and tangential velocity of moon is very high which prevents moon from falling. (vii) Why a bootman tie his boat to a pillar before allowing the passengers to step on the river bank? When passengers jump from the boat they apply some force on the boat with their feet in backward direction which produce backward motion in boat. Therefore the boat is tied with pillar to keep the boat in static position so that passengers move out from the boat easily. (viii) Distinguish between base and derived quantities. Give two examples of each Ans See solved paper Mardan board answer in Section B Q 2 (i) (ix) Why a small needle sinks in water and huge ships travel easily in water with out sinking? The small needle sinks in water because weight of the needle is greater than the weight of water displaced by needles so upthrust is less than downward weight. In contrast the huge ships easily travel in water without sinking because the weight of ships is less than the weight of water displaced by ships so upthrust is greater than downward weight of ships. (x) Define work and its unit joule. Give mathematical expression of work Ans. See solved paper Mardan board answer in Section B Q 2 (vi) (xi) how much heat is required to increase the temperature of 0.5Kg of water from 10C to 65C (C= 4200J/KgK) Ans. See example 8.6 page 174 Given Data; Mass of water m = 0.5Kg Initial temperature T1 = 10C Final temperature T2 = 65 C Specific heat of water C = 4200J/KgK Required Data: Heat required βQ = ? Solution: Rise in temperature βT = T2-T1 = 65-10 = 55C βQ = cmβT = 4200 x 0.5 x 55 = 115500J Section C Q. 3 (i) Derive Vf= Vi + at by graphical method Consider a body which has initial velocity ‘Vi’ and this body accelerates uniformly, then after time ‘t’ its final velocity will become Vf at uniform acceleration. Now consider velocity time graph shown in figure 1 AD = DC/AC---------- (1) but AD= a (slope of graph is acceleration), DC= ΔV and AC= t putting the values in equation -1 a = ΔV/t or at = ΔV (2) but ΔV= Vf-Vi therefore at= Vf-Vi or Vf= Vi + at Vf= Vi + at (first equation of motion) Q 3 (ii) A truck moving at a speed of 20m/s begins to slow at constant rate of 3m/S2 find how far it goes before stopping. Ans See videos lecture chap 2 Q 3 Q 4 (i) What is mean by force? State second law of motion and give its mathematical expression. FORCE "Force is an agent which changes or tends to change the state of rest or of uniform motion of a body." Force is a vector quantity and SI unit is Newton SECOND LAW OF MOTIONS STATEMENT "When a force acts on an object it produces an acceleration which is directly proportion to the amount of the force and inversely proportional to the product of mass" EXPLANATION According to the Newton`s Second law of motion when a force acts on an object it produces an acceleration which is directly proportion to the amount of the force and inversely proportional to the product of mass Combining equation i and ii where k is constant of proportionality If the Value of K is 1 so, a = F/m or F = ma SECOND STATEMENT With the help of above equation 2nd law of motion can be expressed as: The net force acting on a body is equal to the product of the mass of body and the acceleration produced in it. Q 4 (ii) a 5Kg object is placed on a horizontal wooden surface how much force is required to set in it motion. (u = 0.6 g= 10m/s2) Ans. Given data Mass of the object m= 5Kg = 0.6 g= 10m/s2 Required data : Force F = ? Formula used: F = Fn = W= mg Solution; F = mg = 0.6 x 5 x 10 = 30N So minimum force required will be 30N Q 5 (i) Find mass of earth with the help of universal gravitation law where G (6.67 x 10-11 Nm2/kg2) and Re (6.4x106m). MASS OF EARTH: Consider a body of mass m which is lying on the surface of earth. Let the mass of earth is Me and radius is Re. The gravitational force between earth and body mass m will be πΊπππ F= ------(1) π π2 But the force with which the earth attracts a body towards its centre is called weight so F= W= mg Putting the value of F in above equation 1 mg = πΊπππ π π2 πΊππ g= π π2 OR Me= ππ π2 πΊ ---(2) By putting the value of g(10m/sec2 MASS OF EARTH: The mass of earth was determined by Newton with the help of law of gravitation. Consider a body of mass m which is lying on the surface of earth. Let the mass of earth is Me and radius is Re. The gravitational force between earth and body mass m will be πΊπππ F= ------(1) π π2 But the force with which the earth attracts a body towards its centre is called weight so F= W= mg Putting the value of F in above equation 1 mg = πΊπππ π π2 πΊππ g= π π2 OR ππ π2 Me= ---(2) πΊ By putting the value of g(10m/sec2), G (6.67 x 10-11 Nm2/kg2) and Re (6.4x106m) we will get the value of Me Me= 9.8 π₯(6.4x106m)2 6.67 x 10−11 Me = 6x 1024Kg ) we will get the value of Me Me= 9.8 π₯(6.4x106m)2 6.67 x 10−11 Me = 6x 1024Kg Q 5 (ii) how much energy is generated when 1gram of mass is completely converted into energy? Ans. Given data Mass m= 1g = 10-3Kg Velocity of light c= 3x108 m/s Required data. Energy = ? Formula used. E= mc2 Solution. E= mc2 = 10-3Kg x 3x108 m/s = 9x1013J Q. 6 (i) Explain rectangular components of a vector with the help of examples. Ans. The two components of a vector which make right angle (900) with each other is called rectangular components of that vector. Consider vector F which makes angle αΆΏ with x-axix. Draw perpendicular from head of F on x-axis. So OB and AB are rectangular components of vector F which can also be represented by Fx and Fy. The Fx is called horizontal component while Fy is called vertical component of vector F Q 6 (ii) a force of 100N is applied perpendicularly at a distance of 0.50m to turn a nut of the wheel of a bus. Find the torque acting on the nut. Ans see video lectures Q 1 chapter No 4 Superior Lalazar Public School and College Thana www.slpsorg.com 0932-442385 email. 0917351@rgu.ac.uk Solved Physics 9th 2013 paper Malakand Board.