Equilibrium Worksheet
Honors Chemistry Sayers-O’Neill
Name: ____________________________
1
Solubility Product and Common Ion Effect
What is the concentration of a saturated silver (I) acetate solution? Ksp(AgC2H3O2) = 1.94 x 10-3. 1)
Since Ksp = [Ag+][C2H3O2-], and the concentration of silver ions is the same as the concentration of acetate
ions, we can set up the following equation: 1.94 x 10-3 = x2
x = 0.0440 M
2) What is the concentration of a saturated lead chloride solution?
Ksp(PbCl2) = 1.17 x 10-5. Ksp = [Pb+2][Cl-]2. Since the concentration of chloride ions is twice that of lead (II)
ions, this boils down to the following equation:
1.17 x 10-5 = (x)(2x)2
1.17 x 10-5 = 4x3
x = 0.0143 M
What are the concentrations at equilibrium of calcium and fluoride ions in a saturated solution of calcium fluoride?
(Ksp = 3.9 x 10-11) CaF2  Ca 2+ + 2F- Since the concentration of fluoride ions is twice that of calcium ions,
this boils down to the following equation: 3.9 x 10-11= (x)(2x)2 x = 2.1 x 10 -4
Consider the following equilibrium system: PbCl2 (s)  Pb2+(aq) + 2Cl-(aq)
Describe what happens to the
solubility of PbCl2 when the following substances are added to the solution. Why?
a) Pb(NO3)2
d) AgNO3
b) NaCl
e) NaBr
c) H2O Part of review PPT
Consider the following equilibrium system: AgBr(s) Ag+(aq) + Br-(aq)
Describe what happens to the
solubility of AgBr(s) when the following substances are added to the solution. Why?
a) Pb(NO3)2 Lead could react with bromide and remove it (a product ) from system; this would push
system towards product side
b) AgNO3 Silver could react with bromide and remove it (a product ) from system; this would push system
towards product side
c) NaCl adding chloride a product would shift to reactant side
d) NaBr Bromide could react with silver ion and remove it (a product ) from system; this would push
system towards product side
Explain why more Zn(OH)2 dissolves when 3 M HCl is added to a saturated solution of Zn(OH)2. Start by writing
the correct equilibrium equation
Zn(OH)2  Zn 2+ + 2OHAdding HCl (H+ and Cl-) provides H+ ions which react with OH- ions to form water. This removes OH- from
the product side and shifts the reaction to the right (product side)
.