Chemistry I-Honors
Molecular Geometry Worksheet
Solution Set
For each of the species (molecules or ions) listed give the following information:
number of
number of
lone pair
bonded pair type of
electrons
electron
hybridization
shape
bond angle
------------------------------------------------------------------------------------------------------------------------------------1. nitrate ion
0
3 (sites)
sp2
trig. planar
120o
2. sulfate ion
0
4
sp3
tetrahedral
109.5o
3. GeS2
0
2 (sites)
sp
linear
-1
1
4
sp3d
seesaw or
teeter totter
120o
& 90o
5. BrF5
1
5
sp3d2
sq. based pyramid
90o
6. PH3
1
3
sp3
trig. pyramid
<109.5o
7. BrCl
3
1
not appl.
2
3
1
2 (sites)
4. AsI4
8. TeBr3
9. SeS2
-1
180o
linear
180o
sp3d
T-shaped
90o
sp2
bent
<120o
number of
number of
lone pair
bonded pair type of
electrons
electron
hybridization
shape
bond angle
-------------------------------------------------------------------------------------------------------------------------------------1
3
2
sp3d
linear
180o
0
6
sp3d2
octahedral
90o
1
3
sp3
trig. pyramid
<109.5o
13. SbCl5
0
5
sp3d
trig. bipyramid
120o
& 90o
14. XeF2
3
2
sp3d
linear
180o
0
3 (sites)
sp2
trig. planar
120o
2
4
sp3d2
square planar
90o
10. I3
11. XeF6
+2
12. SeBr3
15. CO3
-2
16. XeF4
+1
------------------------------------Rank the bond angles of H2O, H2S, H2Se, and H2Te from largest to smallest.
Bond angle of H-O-H (104.5o) > H-S-H (~92o) > H-Se-H (~91o) > H-Te-H (~90o)
Explain why you ranked them as you did.
As the size of the central atom increased, the lone pair electrons were able to exert a greater repulsion.