Lecture 3-3A: Factoring

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Lecture 3–3A Factoring Out Common Factors with Negative Exponents

When you factor out a common factor from a polynomial the answer contains a distributive expression x

2 + x

= x ( x

+

1) 6 x

5 −

9 x

4 =

3 x

4

(2 x

3)

The common factor is placed outside a bracket and what remains inside the bracket is found by dividing each term by the common factor

Example 1 Example 2

Factor a x out of x

2 + x Factor a 3x

4

out of 6 x

5 −

9 x

4

= x

⎝ x x

2

+

= x ( x

+

1) x x

=

3 x

4

6 x

3 x

4

5

9 x

4

3 x

4

=

3 x

4

(2 x

3)

If you have several terms with x to a power the lowest power of x is the common factor. The lowest power of x will be divided out and the remaining polynomial inside the parenthesis will be simplified using the Laws of Exponents.

In the problems below the lowest power of x is a negative number.

Factor out the lowest power of x and simplify the remaining polynomial inside the parenthesis using the Laws of

Exponents. If the coefficient also has a common factor, be sure and factor that out as well.

Example 3

Factor a x

2

out of x

3 + x

2

= x

2

⎝ x x

3

2

+ x x

2

2

= x

2

( x

3 • x

2 + x

2 • x

2

)

= x

2

( x

5 + x

0

)

= x

2 5 +

1

= x

5 +

1 x

2

Math 400 3–3A Factoring Out Least Powers Page 1 of 4

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Eitel

Example 4 factor out a x

1 2

3 from x 3 + x

1

3

= x

1

3

⎝ x

2 x 3

1

3

+ x x

1

3

1

3

= x

1

3

⎜ x

2

3

1

• x 3 + x

1

3 • x

1

3

= x

1

3

⎜ x

3

3 + x

0

= x

1

3

( x

+

1

)

=

( x

+

1

)

1 x 3

=

( x

+

1

)

3 x

Math 400 3–3A Factoring Out Least Powers Page 2 of 4

© 2013

Eitel

x

1 x

2

= x

Dividing out a common x term using the power rule requires us to subtract exponents.

Subtracting a negative exponent creates an addition problem

Quotient Rule

1

+

2 = x

Quotient Rule x a x b

= x a

− b

Quotient Rule x x

2

5

3

5

= x

2

5

+

3

5 = x

Quotient Rule

( x

5)

( x

5)

3

4

=

( x

5)

3

+

4 =

( x

5)

This technique may be easier for many problems.

Example 5 factor out a x

3

5 from 2 x

2

5

7 x

3

5

= x

3

5 ⎜

2

• x

2

5

+

3

5 −

7

• x

3

5

+

3

5

= x

3

5

(

2 x

7

)

=

(

2 x

7

)

3 x 5

=

(

2 x

7

)

5 x

3

Math 400 3–3A Factoring Out Least Powers Page 3 of 4

© 2013

Eitel

Example 6 factor out a x

1

3 from 4 x

2

3

9 x

1

3

= x

1

3 ⎜

4

• x

2

3

+

1

3 −

9

• x

1

3

+

1

3

= x

1

3

(

4 x

9

)

=

(

4 x

9

)

1 x 3

=

(

2 x

7

)

3 x

Example 7 factor out a ( x

1)

3

from 2( x

1)

2 −

5( x

1)

3

=

( x

1)

3

2( x

1)

( x

1)

2

3

5( x

1)

( x

1)

3

3

=

( x

1)

3 (

2( x

1)

5

)

=

( x

1)

3 (

2 x

2

5

)

=

2 x

7

( x

1)

3

Math 400 3–3A Factoring Out Least Powers Page 4 of 4

© 2013

Eitel

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