2024-05-12T09:20:13+03:00[Europe/Moscow] en true <p>Superposition cannot be used to solve for circuit values using Ohm 's Law in circuits having more than one connected voltage source.</p><p></p><p>Select one:</p><p>True</p><p>False</p>, <p>When solving for values in circuits having more than one voltage source, all voltage</p><p>sources but one must be ? when calculating the Superposition Theorem.</p><p></p><p>a.connected</p><p>b.opened</p><p>c.shorted</p><p>d.tied to ground</p>, <p>Using the principle of superposition, proper calculation of currents from each ? can be</p><p>found for individual components to be used for determining final values.</p><p></p><p>a.parallel source</p><p>b.power source</p><p>c.resistor</p><p>d.series branch</p>, <p>Using superposition, the current must be found for each ? .</p><p></p><p>a.inductor</p><p>b.parallel resistor</p><p>c.power source</p><p>d.series resistor</p>, <p>The total current using the principle of superposition will be the algebraic sum of the</p><p>individual currents.</p><p></p><p>Select one:</p><p>True</p><p>False</p>, <p>Which of the following steps are involved in applying the principle of superposition?</p><p></p><p>a.Assume a direction of current flow through the load.</p><p>b.Calculate the current flow for the selected source.</p><p>c.Repeat this procedure for each power source in the circuit; determine the amount of</p><p>current and the direction of current flow through the load.</p><p>d.Select one power source and replace all the other power sources in the circuit with a</p><p>short circuit.</p><p>e.All of the above</p>, <p>Find the total current through R in the circuit using the principle of superposition.</p><p>Calculate to one decimal place.</p>, <p>The circuit represents the circuit and direction of current flow to solve for the effects of</p><p>voltage source E .</p><p></p><p>Select one:</p><p>True</p><p>False</p>, <p>Given the circuit and parameters shown, solve for the absolute value (input a positive number) and for personal reference be sure to note polarity of the following:</p><p>(Note: The calculated values and polarities from this question will be used to answer other questions. Assume polarity of current flow from source E to be positive.)</p><p></p><p>IR1 = ? mA </p><p></p><p></p><p>IR2 = ? mA</p><p></p><p></p><p>IR3 = ? mA</p>, <p>Given the circuit and parameters shown, solve for the absolute value (input a positive number) and for personal reference, be sure to note polarity of the following:</p><p>(Note: The calculated values and polarities from this question will be used to answer</p><p>other questions. Assume polarity of current flow from source E to be positive.)</p><p></p><p>IR1 = ? mA </p><p></p><p></p><p>IR2 = ? mA</p><p></p><p></p><p>IR3 = ? mA</p>, <p>Using the polarities and values computed in previous questions, and referring to the circuit shown, calculate the values and polarity of the following:</p><p>(Note: When recording final answers, make sure to input the negative sign when necessary and assume polarity of current flow from source E to be positive.)</p><p></p><p>IR1 = ? mA</p><p></p><p>ER1 = ? V</p><p></p><p>IR2 = ? mA</p><p></p><p>ER2 = ? V </p><p></p><p>IR3 = ? mA </p><p></p><p>ER3 = ? V</p>, <p>Given the circuit and parameters shown, solve for the absolute value (input a positive number) and for personal reference be sure to note polarity of the following:</p><p>(Note: The calculated values and polarities from this question will be used to answer other questions. Assume polarity of current flow from source E to be positive.)</p><p></p><p>IR1 = ? mA </p><p></p><p></p><p>IR2 = ? mA</p><p></p><p></p><p>IR3 = ? mA</p>, <p>Given the circuit and parameters shown, solve for the absolute value (input a positive</p><p>number) and for personal reference be sure to note polarity of the following:</p><p>(Note: The calculated values and polarities from this question will be used to answer other questions. Assume polarity of current flow from source E to be positive.)</p><p></p><p>IR1 = ? mA </p><p></p><p></p><p>IR2 = ? mA</p><p></p><p></p><p>IR3 = ? mA</p>, <p>Using the polarities and values computed in previous questions and referring to the</p><p>circuit shown, calculate the values and polarity of the following:</p><p>(Note: When recording final answers, make sure to input the negative sign when necessary and assume polarity of current flow from source E to be positive.)</p><p></p><p>IR1 = ? mA </p><p></p><p></p><p>IR2 = ? mA</p><p></p><p></p><p>IR3 = ? mA</p>, <p>Given the circuit and parameters shown, solve for the value of I with source E shorted.</p><p>(Note: The calculated value and polarity from this question will be used to answer other</p><p>questions.)</p><p></p><p>IR4 = ? mA</p>, <p>Given the circuit and parameters shown, solve for the value of I with source E shorted.</p><p>(Note: The calculated value and polarity from this question will be used to answer other questions.)</p><p></p><p>IR4 = ? mA</p>, <p>Given the previously calculated currents, find the resultant current for R . (Calculate to three decimal places.)</p>, <p>What is the voltage across R when all voltage sources are considered? Calculate to one decimal place.</p> flashcards
DC Theory Lesson 1

DC Theory Lesson 1

  • Superposition cannot be used to solve for circuit values using Ohm 's Law in circuits having more than one connected voltage source.

    Select one:

    True

    False

    The correct answer is 'False'.

  • When solving for values in circuits having more than one voltage source, all voltage

    sources but one must be ? when calculating the Superposition Theorem.

    a.connected

    b.opened

    c.shorted

    d.tied to ground

    The correct answer is: shorted

  • Using the principle of superposition, proper calculation of currents from each ? can be

    found for individual components to be used for determining final values.

    a.parallel source

    b.power source

    c.resistor

    d.series branch

    The correct answer is: power source

  • Using superposition, the current must be found for each ? .

    a.inductor

    b.parallel resistor

    c.power source

    d.series resistor

    The correct answer is: power source

  • The total current using the principle of superposition will be the algebraic sum of the

    individual currents.

    Select one:

    True

    False

    The correct answer is 'True'.

  • Which of the following steps are involved in applying the principle of superposition?

    a.Assume a direction of current flow through the load.

    b.Calculate the current flow for the selected source.

    c.Repeat this procedure for each power source in the circuit; determine the amount of

    current and the direction of current flow through the load.

    d.Select one power source and replace all the other power sources in the circuit with a

    short circuit.

    e.All of the above

    The correct answer is: All of the above

  • Find the total current through R in the circuit using the principle of superposition.Calculate to one decimal place.

    Find the total current through R in the circuit using the principle of superposition.

    Calculate to one decimal place.

    The correct answer is: 0.5 A

  • The circuit represents the circuit and direction of current flow to solve for the effects ofvoltage source E .Select one:TrueFalse

    The circuit represents the circuit and direction of current flow to solve for the effects of

    voltage source E .

    Select one:

    True

    False

    The correct answer is 'False'.

  • Given the circuit and parameters shown, solve for the absolute value (input a positive number) and for personal reference be sure to note polarity of the following:(Note: The calculated values and polarities from this question will be used to answer other questions. Assume polarity of current flow from source E to be positive.)IR1 =   ?   mA IR2 =   ?   mAIR3 =   ?   mA

    Given the circuit and parameters shown, solve for the absolute value (input a positive number) and for personal reference be sure to note polarity of the following:

    (Note: The calculated values and polarities from this question will be used to answer other questions. Assume polarity of current flow from source E to be positive.)

    IR1 = ? mA

    IR2 = ? mA

    IR3 = ? mA

    The correct answer is: 140 mA

    The correct answer is: 100 mA

    The correct answer is: 40 mA

  • Given the circuit and parameters shown, solve for the absolute value (input a positive number) and for personal reference, be sure to note polarity of the following:(Note: The calculated values and polarities from this question will be used to answerother questions. Assume polarity of current flow from source E to be positive.)IR1 =   ?   mA IR2 =   ?   mAIR3 =   ?   mA

    Given the circuit and parameters shown, solve for the absolute value (input a positive number) and for personal reference, be sure to note polarity of the following:

    (Note: The calculated values and polarities from this question will be used to answer

    other questions. Assume polarity of current flow from source E to be positive.)

    IR1 = ? mA

    IR2 = ? mA

    IR3 = ? mA

    The correct answer is: 100 mA

    The correct answer is: 140 mA

    The correct answer is: 40 mA

  • Using the polarities and values computed in previous questions, and referring to the circuit shown, calculate the values and polarity of the following:(Note: When recording final answers, make sure to input the negative sign when necessary and assume polarity of current flow from source E to be positive.)IR1 =   ?   mAER1 =   ?   VIR2 =   ?   mAER2 =   ?   V IR3 =   ?   mA ER3 =   ?   V

    Using the polarities and values computed in previous questions, and referring to the circuit shown, calculate the values and polarity of the following:

    (Note: When recording final answers, make sure to input the negative sign when necessary and assume polarity of current flow from source E to be positive.)

    IR1 = ? mA

    ER1 = ? V

    IR2 = ? mA

    ER2 = ? V

    IR3 = ? mA

    ER3 = ? V

    The correct answer is: 40 mA

    The correct answer is: 4 V

    The correct answer is: -40 mA

    The correct answer is: -4 V

    The correct answer is: 80 mA

    The correct answer is: 20 V

  • Given the circuit and parameters shown, solve for the absolute value (input a positive number) and for personal reference be sure to note polarity of the following:(Note: The calculated values and polarities from this question will be used to answer other questions. Assume polarity of current flow from source E to be positive.)IR1 =   ?   mA IR2 =   ?   mAIR3 =   ?   mA

    Given the circuit and parameters shown, solve for the absolute value (input a positive number) and for personal reference be sure to note polarity of the following:

    (Note: The calculated values and polarities from this question will be used to answer other questions. Assume polarity of current flow from source E to be positive.)

    IR1 = ? mA

    IR2 = ? mA

    IR3 = ? mA

    The correct answer is: 300 mA

    The correct answer is: 225 mA

    The correct answer is: 75 mA

  • Given the circuit and parameters shown, solve for the absolute value (input a positivenumber) and for personal reference be sure to note polarity of the following:(Note: The calculated values and polarities from this question will be used to answer other questions. Assume polarity of current flow from source E to be positive.)IR1 =   ?   mA IR2 =   ?   mAIR3 =   ?   mA

    Given the circuit and parameters shown, solve for the absolute value (input a positive

    number) and for personal reference be sure to note polarity of the following:

    (Note: The calculated values and polarities from this question will be used to answer other questions. Assume polarity of current flow from source E to be positive.)

    IR1 = ? mA

    IR2 = ? mA

    IR3 = ? mA

    The correct answer is: 150 mA

    The correct answer is: 200 mA

    The correct answer is: 50 mA

  • Using the polarities and values computed in previous questions and referring to thecircuit shown, calculate the values and polarity of the following:(Note: When recording final answers, make sure to input the negative sign when necessary and assume polarity of current flow from source E to be positive.)IR1 =   ?   mA IR2 =   ?   mAIR3 =   ?   mA

    Using the polarities and values computed in previous questions and referring to the

    circuit shown, calculate the values and polarity of the following:

    (Note: When recording final answers, make sure to input the negative sign when necessary and assume polarity of current flow from source E to be positive.)

    IR1 = ? mA

    IR2 = ? mA

    IR3 = ? mA

    The correct answer is: 150 mA

    The correct answer is: 25 mA

    The correct answer is: 125 mA

  • Given the circuit and parameters shown, solve for the value of I with source E shorted.(Note: The calculated value and polarity from this question will be used to answer otherquestions.)IR4 =   ?   mA

    Given the circuit and parameters shown, solve for the value of I with source E shorted.

    (Note: The calculated value and polarity from this question will be used to answer other

    questions.)

    IR4 = ? mA

    The correct answer is: 180

  • Given the circuit and parameters shown, solve for the value of I with source E shorted.(Note: The calculated value and polarity from this question will be used to answer other questions.)IR4 =   ?   mA

    Given the circuit and parameters shown, solve for the value of I with source E shorted.

    (Note: The calculated value and polarity from this question will be used to answer other questions.)

    IR4 = ? mA

    The correct answer is: 73.75

  • Given the previously calculated currents, find the resultant current for R . (Calculate to three decimal places.)

    Given the previously calculated currents, find the resultant current for R . (Calculate to three decimal places.)

    The correct answer is: 0.106 A

  • What is the voltage across R when all voltage sources are considered? Calculate to one decimal place.

    What is the voltage across R when all voltage sources are considered? Calculate to one decimal place.

    The correct answer is: 5.3 V