There is no phase change when light reflects from..
A region with lower (n) index of refraction (aka soft surface)
There is a phase change equal to π when light reflects from a region with a...
Higher index of refraction or from a solid surface (hard boundary)
There is phase _____change in the refracted wave.
NO
For air, there is
always a phase difference between two waves:
True or False: When light reflects off the boundary of a medium with a higher index of refraction, it experiences a phase change equal to π.
True
True or False: If light is reflected of a soft surface (lower n), it experiences a phase change of π/2.
False; there would be no phase change.
For constructive interference, the phase difference (deltaphi) is a (even or odd) multiple of π
even
For destructive interference, the phase difference (deltaphi) is a (even or odd) multiple of π
odd
For what value of
phase difference we will have a constructive interference? A.) 2π B.) π C.) π/4 D.) π/2
A.) 2π a.
since it
is a constructive interference and it must be an even multiple.
the visible light spectrum consists of what wavelengths?
380 to 750 mn
To find what visible wavelength will be constructive reflected from a film...
Find phase difference, and solve for lambda and plug in (m) until there are
multiple answers that are in the visible light spectrum wavelengths.
***remember how wavelength changes when changing mediums***
From air to solid divide wavelength by (n) index of refraction
To find smallest possible thickness, use
m=0
How can you find the angular location of a dark for a single-slit diffraction?
Tan theta = y/LWhere a is width
of slits m=order of dark
fringe
In a single-slit diffraction experiment, as the width of the slit is made smaller, the width of the central maximum of the diffraction pattern becomes
LARGER