Thevenin's Theorem states that any two-terminal source can be reduced to an opencircuit voltage and an equivalent resistance in series with the voltage.
Select one:
True
False
The correct answer is 'True'.
Norton's Theorem states that any two-terminal source can be reduced to a maximum current and an equivalent shunt resistance.
Select one:
True
False
The correct answer is 'True'.
Find the current for an 11.5 ohm resistor connected as the load for the Thevenin's equivalent circuit.
The correct answer is: 2 A
Given the circuit shown, find the voltage drop on a load resistor with a value of 13.9 ohms if R = 0.5 ohms and E = 18 volts. (Round the FINAL answer to two decimal places of the specified unit.)
ERL = ? V
The correct answer is: 17.38
Given the circuit shown, find the voltage drop on a load resistor with a value of 5.4 ohms if I = 52 amperes and R = 0.5 ohms. (Round the FINAL answer to two decimal places of the specified unit.)
ERL = ? V
The correct answer is: 23.80
Given the circuit and parameters shown, reduce the circuit to Thevenin’s equivalent circuit, and solve for the following: (Round the FINAL answers to whole numbers in the specified unit.)
RT = ? Ω
IT = ? mA
ETH = ? V
RTH = ? Ω
The correct answer is: 18 Ω
The correct answer is: 667 mA
The correct answer is: 8 V
The correct answer is: 4 Ω
Using the Thevenin's equivalent circuit values from Question 6, calculate the current flow through a load resistor of 1 Ω. Calculate to one decimal place.
The correct answer is: 1.6 A
Using the Thevenin’s equivalent circuit values from Questions 6 and 7, calculate how much power is dissipated by the 1 ohm load. Calculate to two decimal places.
The correct answer is: 2.56 W
Using the Thevenin's equivalent circuit values, calculate the current flow through a load resistor of 2 ohms. Calculate to three decimal places.
The correct answer is: 1.333 A
How much power is dissipated by the 2 ohm load? Calculate to one decimal place.
The correct answer is: 3.6 W
Using the Thevenin's equivalent circuit values, calculate the current flow through a load resistor of 4 ohms. Calculate to one decimal place.
The correct answer is: 1 A
How much power is dissipated by the 4 ohm load? Calculate to one decimal place.
The correct answer is: 4 W
Using the Thevenin's equivalent circuit values, calculate the current flow through a load resistor of 8 ohms. Calculate to three decimal places.
The correct answer is: 0.667 A
How much power is dissipated by the 8 ohm load? Calculate to two decimal places.
The correct answer is: 3.56 W
Using the Thevenin's equivalent circuit values, calculate the current flow through a load resistor of 12 ohms. Calculate to one decimal place.
The correct answer is: 0.5 A
How much power is dissipated by the 12 ohm load? Calculate to one decimal place.
The correct answer is: 3 W
Using the Thevenin's equivalent circuit values, calculate the current flow through a load resistor of 15 ohms. Calculate to three decimal places.
The correct answer is: 0.421 A
How much power is dissipated by the 15 ohm load?
Calculate to two decimal places.
The correct answer is: 2.66 W
Given the circuit and parameters shown, convert the circuit to a Norton’s equivalent and solve for the following:
In = ? A
Rn = ? Ω
The correct answer is: 2 A
The correct answer is: 4Ω
Using the Norton's equivalent circuit values from previous questions, calculate the current flow through a load resistor (RLOAD ) with a value of 1 ohm. Calculate to one decimal place.
The correct answer is: 1.6 A
Calculate the power dissipated by the 1 ohm load resistor (RLOAD ). Calculate to two
decimal places.
The correct answer is: 2.56 W
Using the Norton's equivalent circuit values from previous questions, calculate the current flow through a load resistor (R ) with a value of 2 ohms. Calculate to three decimal places.
The correct answer is: 1.333 A
Calculate the power dissipated by the 2 ohm load resistor (RLOAD ). Calculate to one
decimal place.
The correct answer is: 3.6 W
Using the Norton's equivalent circuit values from previous questions, calculate the current flow through a load resistor (RLOAD ) with a value of 4 ohms. Calculate to one decimal place.
The correct answer is: 1 A
Calculate the power dissipated by the 4 ohm load resistor (R ). Calculate to one
decimal place.
The correct answer is: 4 W
Using the Norton's equivalent circuit values from previous questions, calculate the current flow through a load resistor (RLOAD ) with a value of 8 ohms. Calculate to three decimal places.
The correct answer is: 0.667 A
Calculate the power dissipated by the 8 ohm load resistor (RLOAD ). Calculate to one
decimal place.
The correct answer is: 3.6 W
Using the Norton's equivalent circuit values from previous questions, calculate the current flow through a load resistor (RLOAD ) with a value of 12 ohms. Calculate to one decimal place.
The correct answer is: 0.5 A
Calculate the power dissipated by the 12 ohm load resistor (RLOAD ).
The correct answer is: 3 W
Using the Norton's equivalent circuit values from previous questions, calculate the current flow through a load resistor (RLOAD ) with a value of 15 ohms. Calculate to three decimal places.
The correct answer is: 0.421 A
Calculate the power dissipated by the 15 ohm load resistor (RLOAD ). Calculate to two decimal places.
The correct answer is: 2.66 W
The values calculated for current and power are not the same using Norton's Theorem as they are when using Thevenin's Theorem.
Select one:
True
False
The correct answer is 'False'.
Maximum power will be delivered to the load when RLOAD = RTH = RN .
Select one:
True
False
The correct answer is 'True'.
Given the circuit and parameters shown, solve for the current through the load resistor using Thevenin’s Theorem. (Round the FINAL answer to at least two decimal places in
the specified unit.)
IRL = ? A
The correct answer is: 4.29
Given the circuit and parameters shown, solve for the current through the load resistor using Norton’s Theorem. (Round the FINAL answer to at least two decimal places in the specified unit.)
IRL = ? A
The correct answer is: 4.29