X-Ray Reflectivity Measurement (From Chapter 10 of Textbook 2) http://www.northeastern.edu/nanomagnetism/downloads/Basic %20Principles%20of%20Xray%20Reflectivity%20in%20Thin%20Films%20%20Felix%20JimenezVillacorta%20[Compatibility%20Mode].pdf http://www.google.com/url?sa=t&rct=j&q=xray+reflectivity+amorphous&source=web&cd=1&cad=rja&v ed=0CDEQFjAA&url=http%3A%2F%2Fwww.stanford.edu %2Fgroup%2Fglam%2Fxlab%2FMatSci162_172%2FLectur eNotes%2F09_Reflectivity%2520%26%2520Amorphous.pd f&ei=L3zBUKfSEaLNmAX8vIC4AQ&usg=AFQjCNFfiktSw8bSPGGyx1ckTK5WBTnSA X-ray is another light source to be used to perform reflectivity measurements. Refractive index of materials (: X-ray): n 1 i 2 re e 2 x 4 re: classical electron radius = 2.818 × 10-15 m-1 e: electron density of the materials x: absorption coefficient Definition in typical optics: n1sin1 = n2sin2 In X-ray optics: n1cos1 = n2cos2 > 1 n <1, 1 2 Critical angle for total reflection n1cos1 = n2cos2, n1= 1; n2=1- ; 1 = c; 2 = 0 cosc =1- sinc = 1 (1 )2 and c <<1 c 2 ~ 10-5 – 10-6; and c ~ 0.1o – 0.5o 1 c 1- 1 (1 )2 X-ray reflectivity from thin films: Single layer: Path difference = BCD 2t sin 2 Snell’s law in X-ray optics: n1cos1 = n2cos2 cos1 = n2cos2=(1-)cos2. cos 1 cos 2 1 (1 )2 cos2 1 sin 2 1 1- 2 (1 ) 2 cos2 1 cos1 cos2 1 2 2 2 sin 2 1 1 ( 1 sin )( 1 ...) 1 2 (1 ) (1 2 3 2 ...) 1 2 When 1 , 2, and << 1 1 12 Ignore Constructive interference: 2t sin 2 2t 12 2 n 2 12 2 4t 2 (12 2 ) n 22 2 2 n 12 2 2 4t Si on Ta 2 1 2 2 n 2 2 4t y ax b /180 2 b 2 re e e 2 a 2 t 4t 2 a Slope = a b use y 2 ax 2 b So that the horizontal axis is linear Fresnel reflectivity: classical problem of reflection of an EM wave at an interface – continuity of electric field and magnetic field at the interface Reflected k 3 3 beam Incident k1 x 1 y beam Reflection and Refraction: • Random polarized beam travel in two homogeneous, n1 n2 isotropic, nondispersive, and nonmagnetic media (n1 and n2). Snell’s law: n1 sin 1 n2 sin 2 and 1 3 E2 x t x 0 E1x E 0 t E y 1y 2y and E3 x rx E 0 3y Refracted beam k2 2 0 E1x ry E1 y Continuity can be written for two different cases: (a) TE (transverse electric) polarization: electric field is to the plane of incidence. E1 E1x E3x H1y 1 3 H2y E3 H3y E2x E2 E2 x tx E1x E3 x rx E1x E1x E3 x E2 x E1x rx E1x tx E1x tx 1 rx 2 H1 y cos 1 H 3 y cos 1 H 2 y cos 2 (horizontal field) E / H 0 / n (scalar) n1E1x cos1 / 0 n1E3 x cos1 /0 n2 E2 x cos2 / 0 n1E1x cos1 n1rx E1x cos1 n2tx E1x cos2 1 rx tx n2 cos2 / n1 cos1 & 1 rx t x 2n1 cos 1 n1 cos 1 n2 cos 2 tx ; rx n1 cos 1 n2 cos 2 n1 cos 1 n2 cos 2 (b) TM (transverse magnetic) polarization: magnetic field is to the plane of incidence. E1y E3y E1 H1x 1 3 H2x 2 E3 E2 y t y E1 y E3 y ry E1 y H3x H1x H 3 x H 2 x E2y E2 n1E1 y ry n1E1 y t y n2 E1 y & E / H 0 / n n1 (1 ry ) n2t y E1 y cos 1 E3 y cos 1 E2 y cos 2 E1 y cos 1 ry E1 y cos 1 t y E1 y cos 2 1 ry t y cos 2 / cos 1 1 ry t y n2 / n1 2n1 cos 1 n2 cos 1 n1 cos 2 ty ; ry n2 cos 1 n1 cos 2 n2 cos 1 n1 cos 2 http://en.wikipedia.org/wiki/Image:Fresnel2.png Rs: s-polarization; TE mode Rp: p-polarization; TM mode Another good reference (chapter 7) http://www.ece.rutgers.edu/~orfanidi/ewa/ In X-ray arrangement n1 = 1, change cos sin n1 sin 1 n2 sin 2 sin 1 n2 sin 2 1 cos rx 1 2 n1 sin 1 n2 sin 2 sin 1 n2 sin 2 n cos1/n2 all angles are small; sin1 ~ 1. cos 1 cos Snell’s law obey cos1 = n2 cos2. 2 2 1 2 2 n2 cos 1 2 2 sin 2 1 n sin n cos 1 2 2 2 2 n2 2 n22 (1 i )2 1 2 2i 2i 2 2 n2 sin 2 1 2 2i cos 1 sin 1 2 2i 2 2 12 2 2 sin 1 n2 sin 2 1 1 c 2i rx sin 1 n2 sin 2 1 12 c2 2i c2 1 2i R flat (1 ) r r 1 12 c2 2i 2 1 * x x in term of q 2 c 2 4 sin q1 q q 2 1 2 c 32 i 2 2 2 R flat ( q1 ) 2 32 i 2 2 q1 q1 qc 2 Effect of surface roughness is similar to Debye-Waller factor Rroughness(1 ) R flat (1 ) exp( 8 212 2 / 2 ) Rroughness(q1 ) R flat (q1 ) exp( 0.5q1q2 2 ) The result can be extended to multilayer. The treatment is the same as usual optics except definition of geometry! One can see that the roughness plays a major role at high wave vector transfers and that the power law regime differs from the Fresnel reflectivity at low wave vector transfers X-ray reflection for multilayers L. G. Parratt, “Surface studies of solids by total reflection of x-rays”, Phys. Rev. 95 359 (1954). y z Electric vector of the incident beam: E1 ( z1 ) Reflected beam: E1R ( z1 ) Refracted beam: E2 ( z2 ) E1 ( z1 ) E1 (0) expit k1, y y1 k1,z z1 E1R ( z1 ) E1R (0) expit k1, y y1 k1, z z1 E2 ( z2 ) E2 (0) expi t k2, y y2 k2, z z2 k1, k2 : wavevecto r in medium 1 and 2 Boundary conditions for the wave vector at the interface between two media: frequencies must be equal on either side of the interface: 1 = 2 , n1 1 = n22 n2k1 = n1k2; wave vector components parallel to the interface are equal k1, || k2, || From first boundary condition n1 1 k k22, y k22,z k22 n22 k12 n22 2 n2 1 2 i 2 cos 1 2 k1, y 2 2 2 n2 k ( 1 2 2 i ) 1, y 2 2 1 2 cos 1 From second boundary condition k1, y k2, y k 2 2,z k k 2 1, y n k k n k k k (n22 1)k12 k12 sin 2 1 k12 (12 2 2 2i2 ) 2 2 2 2, y 2 2 2 1 2 1, y 2 2 2 1 2 1 2 1, z k2, z k1 (12 2 2 2i 2 )1 / 2 f 2k1 E2 ( z2 ) E2 (0) exp[i(t k2, y x2 )] exp[ik1 f 2 z2 ] Shape of reflection curve: two media The Fresnel coefficient for reflection E1R n1 sin 1 n2 sin 2 F1, 2 E1 n1 sin 1 n2 sin 2 Page 10 n2 sin 2 1 2 2 2i 2 cos2 1 sin 2 1 2 2 2i 2 1 f 2 f1 f 2 F1, 2 1 f 2 f1 f 2 f2 f1 (12 21 2i1 )1/ 2 A, B are real value f 2 A iB 1 A {(12 2 2 ) [(12 2 2 )2 422 ]1/ 2 }1/ 2 2 1 B {(12 2 2 ) [(12 2 2 )2 4 22 ]1/ 2 }1/ 2 2 From Snell’s law c 2 2 2 Page 4 1 A {(12 c22 ) [(12 c22 )2 422 ]1/ 2 }1/ 2 2 1 B {(12 c22 ) [(12 c22 )2 422 ]1/ 2 }1/ 2 2 R 2 1 IR E I E1 (1 A)2 B 2 h (1 / c 2 ) 2 (h 1)1 / 2 2 2 (1 A) B h (1 / c 2 ) 2 (h 1)1 / 2 1 1 h 1 2 c 2 2 c 2 2 2 2 1/ 2 N layers of homogeneous media Thickness of nth layer: d n medium 1: air or vacuum an : the amplitude factor for half the perpendicular depth ik n d n if n k1d n if n d n an exp exp exp 2 2 0 dn n-1 1 n a En R n an E En , E n an En 1 n a E R n R n The continuity of the tangential components of the electric vectors for the n-1, n boundary an1En1 a E 1 n 1 R n 1 a En an E 1 n R n (1) The continuity of the tangential components of the magnetic field for the n-1, n boundary (an1H n1 an11H nR1 ) sin n1 (an1H n an H nR ) sin n (an1En1 an11EnR1 )nn1 sin n1 (an1En an EnR )nn sin n f n1k1 f n k1 (an1En1 an11EnR1 ) f n1k1 (an1En an EnR ) f n k1 Solve (1) and (2); (1)fn-1+(2), (1)fn-1-(2) (2) En 1 E R n 1 1 2an 1 f n 1 1 [an1 En ( f n 1 f n ) an EnR ( f n 1 f n )] [an1 En ( f n 1 f n ) an EnR ( f n 1 f n )] 2an11 f n 1 1 R EnR1 [ a E ( f f ) a E 2 n n n 1 n n n ( f n 1 f n )] an1 1 En 1 [an En ( f n 1 f n ) an EnR ( f n1 f n )] 2 R EnR1 2 [( f n 1 f n ) an ( En / En )( f n 1 f n )] an 1 En 1 [( f n 1 f n ) an2 ( EnR / En )( f n 1 f n )] 2 R EnR1 [( f f ) /( f f ) a ( E 2 n 1 n n 1 n n n / En )] an1 En1 [1 an2 ( EnR / En )( f n1 f n ) /( f n 1 f n )] Rn,n1 an2 ( EnR / En ) ; Fn1,n ( f n1 f n ) /( f n1 f n ) Rn 1,n a 2 n 1 EnR1 4 [ Fn 1, n Rn , n 1 ] an 1 En 1 [1 Rn ,n 1 Fn 1,n ] For N layers, starting at the bottom medium RN , N 1 0 (N+1 layer: substrate) R R E Also, a1 = 1 (air or vacuum) 1, 2 1 E1 Finally, the reflectivity of the system is R 1 2 IR E R1, 2 I0 E1 2 For rough interfaces: Fn 1,n [( f n 1 f n ) /( f n 1 f n )] f n (12 2 n 2i n )1/ 2 nn2 cos 2 1 Fn1,n [( f n1 f n ) /( f n1 f n )] exp( 8 2 f n1 f n n21 / 2 ) Can be calculated numerically! Example of two layers with roughness Au on Si substrate Interface roughness nn 1 n i n z Probability density nn1 1 n1 i n1 z2 Pn ( z ) exp 2 2 n 2 n Integration z zn nn nn 1 nn nn 1 nn ( z ) erf 2 2 2 n 1 Refractive index Same roughness & refractive index profile / 1 / 1 Félix Jiménez‐Villacorta