Physics 2102 Jonathan Dowling Physics 2102 Lecture: 07 TUE 09 FEB Electric Potential II QuickTime™ and a decompressor are needed to see this picture. PHYS2102 FIRST MIDTERM EXAM! 6–7PM THU 11 FEB 2009 Dowling’s Sec. 4 in ??? YOU MUST BRING YOUR STUDENT ID! YOU MUST WRITE UNITS TO GET FULL CREDIT! The exam will cover chapters 21 through 24, as covered in homework sets 1, 2, and 3. The formula sheet for the exam can be found here: http://www.phys.lsu.edu/classes/spring2010/phys2102/formulasheet.pdf KNOW SI PREFIXES n, cm, k, etc. Conservative Forces, Work, and Potential Energy W F rdr Work Done (W) is Integral of Force (F) U W Potential Energy (U) is Negative of Work Done dU F r dr Hence Force is Negative Derivative of Potential Energy Coulomb’s Law for Point Charge kq1q2 F12 2 r Force [N] = Newton kq1q2 U12 r Potential Energy [J]=Joule v kq2 E12 2 r q1 P1 P2 U12 F12dr Electric Potential [J/C]=[V] =Volt kq2 V12 r dV12 E12 dr dU12 F12 dr q2 Electric Field [N/C]=[V/m] q2 P2 P1 V 12 E 12 dr Continuous Charge Distributions • Divide the charge distribution into differential elements • Write down an expression for potential from a typical element — treat as point charge • Integrate! • Simple example: circular rod of radius r, total charge Q; find V at center. r dq V dV k r k dq r Q kdq r Nm2 C Nm J Units : 2 V C m C C Potential of Continuous Charge Distribution: Line of Charge • Uniformly charged rod • Total charge Q • Length L • What is V at position P? x P dx L a Q/L dq dx kdq kdx V r ( L a x ) 0 L k ln(L a x) L 0 L a V k ln a Units: [Nm2/C2][C/m]=[Nm/C]=[J/C]=[V] Electric Field & Potential: A Simple Relationship! Focus only on a simple case: electric field that points along +x axis but whose magnitude varies with x. Notice the following: • Point charge: E = kQ/r2 V = kQ/r • Dipole (far away): E = kp/r3 V = kp/r2 • E is given by a DERIVATIVE of V! • Of course! f V E ds i dV Ex dx Note: • MINUS sign! • Units for E: VOLTS/METER (V/m) E from V: Example • Uniformly charged rod • Total charge Q • Length L • We Found V at P! • Find E from V? x dx L Units: a Q/L L a V k ln a kln L a ln a dV d E k ln L a ln a da da 1 1 P k L a a a L a L k k L aa L aa Nm2 C m N V 2 2 C m m C m √ Electric Field! Electric Field & Potential: Question • • Hollow metal sphere of radius R has a charge +q Which of the following is the electric potential V as a function of distance r from center of sphere? V 1 r (a) V r r=R V +q (c) r=R (b) r=R 1 r r 1 r r Electric Field & Potential: Example +q E V Outside the sphere: • Replace by point charge! Inside the sphere: • E = 0 (Gauss’ Law) • E = –dV/dr = 0 IFF V=constant 1 2 r 1 r dV E dr d Q k dr r Q k 2 r Equipotentials and Conductors • Conducting surfaces are EQUIPOTENTIALs • At surface of conductor, E is normal (perpendicular) to surface • Hence, no work needed to move a charge from one point on a conductor surface to another • Equipotentials are normal to E, so they follow the shape of the conductor near the surface. V E Conductors Change the Field Around Them! An Uncharged Conductor: A Uniform Electric Field: An Uncharged Conductor in the Initially Uniform Electric Field: Sharp Conductors • Charge density is higher at conductor surfaces that have small radius of curvature • E = s/e0 for a conductor, hence STRONGER electric fields at sharply curved surfaces! • Used for attracting or getting rid of charge: – lightning rods – Van de Graaf -- metal brush transfers charge from rubber belt – Mars pathfinder mission -tungsten points used to get rid of accumulated charge on rover (electric breakdown on Mars occurs at ~100 V/m) (NASA) Ben Franklin Invents the Lightning Rod! LIGHTNING SAFE CROUCH If caught out of doors during an approaching storm and your skin tingles or hair tries to stand on end, immediately do the "LIGHTNING SAFE CROUCH ”. Squat low to the ground on the balls of your feet, with your feet close together. Place your hands on your knees, with your head between them. Be the smallest target possible, and minimize your contact with the ground. Summary: • Electric potential: work needed to bring +1C from infinity; units = V = Volt • Electric potential uniquely defined for every point in space -- independent of path! • Electric potential is a scalar -- add contributions from individual point charges • We calculated the electric potential produced by a single charge: V = kq/r, and by continuous charge distributions : V = kdq/r • Electric field and electric potential: E= -dV/dx • Electric potential energy: work used to build the system, charge by charge. Use W = U = qV for each charge. • Conductors: the charges move to make their surface equipotentials. • Charge density and electric field are higher on sharp points of conductors.