P.o.D. – Solve each system 3π§ − 6π€ = 15 1.) { 0.5π§ − π€ = 22 2π₯ + 10π¦ = 16 2.) { π₯ = −3π¦ π = 2π − 4 3.) { π = 2π + 2 π = 4π + 6 1.) No Solution 2.) X= -12, y=4 3.) a= -8/5, b= 6/5, c= -2/5 6-1: Quadratic Functions Learning Targets: be able to expand products and squares of binomials. Quadratic Expression: ππ₯ 2 + ππ₯ + π Quadratic Equation: ππ₯ 2 + ππ₯ + π = 0 Quadratic Function: π (π₯ ) = ππ₯ 2 + ππ₯ + π *All three of these are known as standard form of a quadratic. If we had a quadratic in two or more variables, it would be written as π΄π₯ 2 + π΅π₯π¦ + πΆπ¦ 2 + π·π₯ + πΈπ¦ + πΉ. We will use this later in the year when we study The Conic Sections. Review: FOIL {Binomial Expansion} First Outer Inner Last Binomial – an expression with two terms. EX: FOIL (x-3)(x+8) π₯ 2 + 8π₯ − 3π₯ − 24 = π₯ 2 + 5π₯ − 24 EX: A portrait is 20 centimeters by 90 centimeters. A frame around the portrait is f centimeters wide. Write the total area of the portrait and the frame in standard form. Begin by drawing a picture. (show on the whiteboard) Write a product of the length times the width. (20 + 2π)(90 + 2π) FOIL these binomials. 1800 + 40π + 180π + 4π 2 = 4π 2 + 220π + 1800 *Note: it is customary to write your answer in descending order (highest exponent to lowest). EX: Write the area of a square with sides of length (2a+b) in standard form. (draw a picture on the whiteboard) π (π€) = π πππ (π πππ) = (2π + π)(2π + π) = 4π2 + 2ππ + 2ππ + π 2 = 4π2 + 4ππ + π 2 Binomial Square Theorem: (π₯ + π¦)2 = π₯ 2 + 2π₯π¦ + π¦ 2 (π₯ − π¦)2 = π₯ 2 − 2π₯π¦ + π¦ 2 Use the Binomial Square Theorem to find the following: a.) (3π₯ + π¦)2 b.) (2π₯ − 4π¦)2 a.) (3π₯)2 + 2(3π₯ )(π¦) + (π¦)2 = 9π₯ 2 + 6π₯π¦ + π¦ 2 b.) (2π₯)2 − 2(2π₯ )(4π¦) + (−4π¦)2 = 4π₯ 2 − 16π₯π¦ + 16π¦ 2 http://www.youtube.com/watch?v=w8smA_akWBY http://www.youtube.com/watch?v=Axv7cqezipY EX: A large circular pipe coming up from the ground is surrounded by a circular region of drainage stones. The distance from the edge of the pipe to the outer edge of the drainage stones is w feet, and the radius of the drainage stones, including the large pipe, is 7 feet. a. Write a quadratic expression in standard form for the area of the opening of the circular pipe, not including the drainage stones. b. How many square feet are covered by drainage stones, in terms of w? a. Draw a picture (draw on the whiteboard) Next, find the radius of the inner pipe. r = (7-w). Apply this to the formula for the area of a circle, π΄ = ππ 2 . π΄ = π(7 − π€)2 Expand this polynomial. π΄ = π(7 − π€)(7 − π€) = π(49 − 7π€ − 7π€ + π€ 2 ) = π(49 − 14π€ + π€ 2 ) = 49π − 14ππ€ + ππ€ 2 = ππ€ 2 − 14ππ€ + 49π b. First find the area of the pipe and the drainage stones. π΄ = ππ 2 = π(7)2 = 49π Now, subtract the area of the pipe (which we previously calculated). π΄ = 49π − (ππ€ 2 − 14ππ€ + 49π) = −ππ€ 2 + 14ππ€ = 14ππ€ − ππ€ 2 EX: A city park wants to build a brick walkway around a rectangular flower garden. The garden is 6ft wide by 25ft long. Find an expression for the area of the walkway if it is x feet wide. (Draw a picture) First, find the area of the walkway and the flower garden combined. (2π₯ + 6)(2π₯ + 25) = 4π₯ 2 + 50π₯ + 12π₯ + 150 = 4π₯ 2 + 62π₯ + 150 Now, find the area of the flower garden. 6(25) = 150 The area of the walkway will be the difference of the previous two areas. π΄ = 4π₯ 2 + 62π₯ + 150 − 150 = 4π₯ 2 + 62π₯ Suppose each brick covers ¼ square foot. How many more bricks are needed to make a 5ft walkway than to make a 4ft walkway? Begin by finding the area of a 5ft walkway. π΄(5) = 4(5)2 + 62(5) = 410 π ππ’πππ ππππ‘ Now find the number of bricks needed. 410 = 1640 1⁄ 4 Next, find the area of a 4ft walkway. π΄(4) = 4(4)2 + 62(4) = 312 Now find the number of bricks needed. 312(4) = 1248 Finally, find the difference between the number of bricks needed for a 5ft walkway and the number of bricks needed for a 4ft walkway. 1640-1248=392 more bricks. Try the following on your own: a.) (x-3)(x+4) b.) (3n+1)(2n-5) c.) (3x-y)(3x+y) d.) (π₯ + 5)2 a.) π₯ 2 + 4π₯ − 3π₯ − 12 = π₯ 2 + π₯ − 12 b.) 6π2 − 15π + 2π − 5 = 6π2 − 13π − 5 c.) 9π₯ 2 + 3π₯π¦ − 3π₯π¦ − π¦ 2 = 9π₯ 2 − π¦ 2 d.) π₯ 2 + 2(π₯ )(5) + 52 = π₯ 2 + 10π₯ + 25 Upon completion of this lesson, you should be able to: 1. Identify the different forms of a quadratic function. 2. Expand binomials (FOIL). 3. Apply binomial expansion to story problems. For more information, visit https://www.youtube.com/watch?v=qgtUXG4r_wM HW Pg.377 2-28E