Advanced Thermodynamics Instructor: Prof. Chi-Chung Hua Complex Fluids & Molecular Rheology Laboratory, Department of Chemical Engineering, National Chung Cheng University, Chia-Yi 621, Taiwan, R.O.C. Molecular Rheology LAB Course Outline Instructor: 華 繼 中 教授 (工二館 Rm 412 Ext. 33412) Textbook: Herbert B. Callen, 1985, “Thermodynamics and Introduction to Thermostatistics”, 2nd ed., John Wiley & Sons, Inc. (歐亞書局代理) Grading: Homework (20 %) Two Exams (80 %) Teaching assistants: 易函柳 (Rm414, Ext. 23482 ) Molecular Rheology LAB 2 Part one: Classic Thermodynamics Chapter 1: Basic Concepts and Principles Chapter 2: Thermodynamic potentials and Legendre Transformations Chapter 3: Stabilities, Phase Transitions, and Critical Phenomena Chapter 4: Applications to Material Properties Part two: Statistic Thermodynamics Chapter 5: Statistic Ensembles and Formulism Chapter 6: Statistical Fluctuations and Quantum Fluids 3 Molecular Rheology LAB Chapter 1 Basic Concepts and Principles Contents 1-1 1-2 1-3 1-4 1-H Thermodynamic Equilibrium and Postulate I The Entropy Maximum and Postulates II & III Intensive Parameters and Equations of State The Euler Equation and the Gibbs-Duhem Relation Homework 4 Molecular Rheology LAB 1-1 Thermodynamic Equilibrium and 1-1 Postulate I 1-1.1 Thermodynamic coordinates Macroscopic vs. Microscopic Variables Responses Experimental variables Experimental results Simulation variables Simulation data 5 Molecular Rheology LAB 1-1 Q1: How to select variables of an experimental or simulation system? A1: 1. Use minimum number of measurable variables. 2. Each variables must be independent. Q2: Select macroscopic or microscopic variables? A2: The basis of selection is the scale of the phenomena or substances of primary interest. Microscopic 1μm Macroscopic length scale 6 Molecular Rheology LAB 1-1 Microscopic properties can spread to macroscopic properties Microscopic Macroscopic But macroscopic properties cannot spread to microscopic properties We usually used macroscopic properties to describe engineering problem, simply because it’s easier to do. The price paid is, however, that small-scale problems cannot be studied, and some macroscopic properties themselves become difficult to understand. 7 Molecular Rheology LAB Figure 1.1 Length and time scales of atoms and cats http://www.bibalex.org/English/lectures/printable/zewail.htm Molecular Rheology LAB 8 1-1 1-1.2 Definition of equilibrium states System has no external influences (such as flow, electrical fields). All thermodynamic properties must be “time invariance” (time independent). When all properties have reached time independence in our selected time scale, the system would seem to reach an equilibrium. Yet, since different people may have different opinions of time scale, the viewpoint of equilibrium could also be different. 9 Molecular Rheology LAB 1-1 1-1.3 Limitations of thermodynamic equilibrium Scale limitation: Length scale must be greater than ca.10nm. Time invariance: All variables and properties must be time independent. Postulate I: All macroscopic properties of an equilibrium system can be completely characterized by extensive parameters U, V, and N1,N2,…Nr; e.g., S = S(U, V, N) for a one-component system. 10 Molecular Rheology LAB 1-2 The Entropy Maximum Postulates: 1-2 Postulate II & III Postulate II: For an isolated system with constant V, N, U the equilibrium criterion requires that the entropy S reaches a maximum value. Postulate III: S is a monotonically increasing function of U. S S (U , V , N 1 , ... , N r ) S 0 U V , N1 , ... , N r 11 Molecular Rheology LAB 1-2 The system may then be further divided into two sub-systems subject to certain constraints: S = S(U , V , N) V1 V2 U1 U2 N1 N2 thermodynamic constraints U1 U 2 U1' U 2' S = S(U) only U1' ? U ? ' 2 By entropy max. 12 Molecular Rheology LAB 1-2 S dS dU ; S is extreme value dS 0 U N ,V Use d2S to check S is S S1 (U 1 ) S 2 (U 2 ) max. or min. S1 S 2 1 1 dS dU 1 dU 2 dU 1 dU 2 0 T1 T2 U 1 N ,V U 2 N ,V 1 1 dS ( )dU 1 0 T1 T2 1 1 ( )0 T1 T2 dU 1 dU 2 0 dU 1 0 T1 = T2 An important equilibrium condition 13 Molecular Rheology LAB 1-2 Fixed V & U Fixed U & N V1 V2 V1 V2 U1 U2 U1 U2 N1 N2 N1 N2 thermodynamic constraints thermodynamic constraints Others equilibrium conditions can be derived with fixed V & U or N & U. μ1 = μ2 for fixed V & U P1 = P2 for fixed N & U 14 Molecular Rheology LAB 1-3 Intensive Parameters and Equations of 1-3 State 1-3.1 Extensive parameters & intensive parameters Extensive parameters S , U , V , N : First order extensive parameters S (U , V , N ) 1 S (U , V , N ) First order S (9U , 9V , 9N ) 9 S (U , V , N ) Example: Enlarged 9 times S Molecular Rheology LAB S S S S S S S S S 15 1-3 Intensive parameters S S (U , V , N ) ; U U ( S , V , N ) Fundamental equations 1 S P S S ; ; U T N , V T V U , N T N U , V U U U T ; P ; S N , V V N , S N S , V At first, people didn’t know the meanings of T, P and μ. Later, they realized that T, P and μ were identical with temperature, pressure and chemical potential in our ordinary life. 16 Molecular Rheology LAB 1-3 Chemical potential: The definition of chemical potential is the energy change from a particle, molecule or electron move into or leave the system. U N S, V Example: Gas Liquid If the overall system has reached an equilibrium, the energy reduction(increase) in the liquid phase due to the moving of a molecule into the gas phase is the same as the energy increase(reduction) in the gas phase. So, the total system energy remains unchanged. 17 Molecular Rheology LAB 1-3 1-3.2 Fundamental equations & equations of state Fundamental equations S S (U , V , N ) Entropy representation U U(S, V , N ) Energy representation Two equations are alternative forms of the fundamental relation, and each contains all thermodynamic information about the system. The fundamental equations describe homogeneous first-order parameters. 18 Molecular Rheology LAB 1-3 Equations of state U U S ,V , N U U U T ; P ; S V N N , V N , S S, V T T(S, V , N ) Equations of state: P P( S , V , N ) ( S , V , N ) An intensive parameter is expressed in terms of independent extensive parameters. Knowledge of a single equation of state does not constitute complete knowledge of the thermodynamic properties of a system. Knowledge of all independent equations of state is equivalent to the knowledge of the fundamental equation. 19 Molecular Rheology LAB 1-3 Figure 1.2 U vs. S & U vs. T in constant V & N 20 Molecular Rheology LAB 1-3 (U ) (U ) 0T ( S ) N , V ( S ) N , V Zero order U & S are first order parameters T ( S , V , N ) T ( S , V , N ) P ( S , V , N ) P ( S , V , N ) ( S , V , N ) ( S , V , N ) Equations of state The equations of state describe homogeneous zero-order parameters. 21 Molecular Rheology LAB 1-3 1-3.3 Unit of temperature Thermodynamic engine Thermodynamic engine efficiency: Th dQh dWrev Tc dWrev Tc εe 1 dQh Th Used to define temperature scale. T1 T1 T2 T2 Permissible scale (e.g. K, R) T1 T1 k T2 T2 k Non-permissible scale (e.g. oC, oF) Molecular Rheology LAB 22 1-3 Question: All heat can be transfer to work? Answer: It is impossible unless Tc = 0K Rotation Tc ≠ 0K Heat Internal energy Molecular Vibration Kinetic energy Work Rotation Tc = 0K Heat Internal energy = 0 Molecular Vibration Kinetic energy All heat transfers to produce work 23 Molecular Rheology LAB 1-3 Unit of temperature Unit of U is energy. U T S N , V What is the unit of entropy? So, unit of temperature is energy. Unit of entropy: In classic thermodynamics, entropy is dimensionless parameter. In thermostatistics, unit of entropy correlates with states. The temperature scale, Kelvin, was used in molecular scale. e.g. Energy of a simple molecule = 3/2 kBT = 3/2 Kelvin Joule/Kelvin = 1.38 x 10-23 = kB 24 Molecular Rheology LAB 1-3 1-3.4 The general case of entropy max. in equilibrium Stotal S1 (U1 , V1 , N 1 ) S2 (U 2 , V2 , N 2 ) w.s.t. dU , dV , dN 1 T1 P1 T1 1 T1 S1 S1 S1 dS dU1 dV1 dN 1 U1 V1 , N1 V1 U1 , N1 N 1 V1 ,U1 S 2 S 2 S 2 dU 2 dV2 dN 2 U 2 V2 , N 2 V2 U 2 , N 2 N 2 V2 ,U 2 1 T2 P2 T2 2 T2 25 Molecular Rheology LAB 1-3 1 1 P1 P2 1 2 dS dU1 dV1 dN 1 0 at equilibrium T1 T2 T1 T2 T1 T2 T1 T2 This equation always holds only if P1 P2 1 2 If dS 0 in reaching equilibrium initial state 1. P1 P2 , 1 2 , T1 T2 dU1 0 2. P1 P2 , 1 2 , T1 T2 dV1 0 3. P1 P2 , 1 2 , T1 T2 dN 1 0 26 Molecular Rheology LAB 1-4 The Euler Equation and the Gibbs-Duhem 1-4 Relation 1-4.1 The Euler relation Homogenous first order property U ( S , V , N 1 , N 2 , ...) U ( S , V , N 1 , N 2 , ...) differentiating w.r.t. (d ) T S P V U ( S , V , N 1 , N 2 , ...) ( S ) U ( S , V , N 1 , N 2 , ...) ( V ) ( S ) (V ) U ( S , V , N 1 , N 2 , ...) ( N 1 ) ... U ( S , V , N 1 , N 2 , ...) ( N 1 ) 1 N1 27 Molecular Rheology LAB 1-4 U ( S , V , N 1 , N 2 , ...) TS PV 1 N 1 2 N 2 ... TS PV j N j j=1 Let PX i i PV j N j i=1 j=1 U ( S , V , N 1 , N 2 , ...) TS Pi X i i=1 Another form: j 1 P S (U , V , N 1 , N 2 , ...) U V N j T T j T The Euler relation is useful for deducing many important thermodynamic relationships, including the famous Gibbs-Duhem equation. 28 Molecular Rheology LAB 1-4 1-4.2 The Gibbs-Duhem equation Euler relation: U ( S , V , N 1 , N 2 , ...) TS Pi X i dU TdS SdT PdX i i X i dPi i=1 Given that i=1 i=1 dU TdS PdX i i i=1 One obtains SdT X i dPi 0 the Gibbs-Duhem equation i=1 Another form j 1 P Ud Vd N jd 0 T T j T Not all intensive properties are independent, but only n-1 of them are independent. Another one can be deduced from the Gibbs-Duhem equation. 29 Molecular Rheology LAB 1-4 Example: For one-component systems (having 3 intensive properties T , P & ) SdT VdP Nd 0 S V d dT dP sdT vdP N N s & v : unit number S & V Only T & P are independent, μ can be deduced from the GibbsDuhem equation. The Euler relation is useful for deducing many important thermodynamic relationships, including the famous Gibbs-Duhem equation. The Gibbs-Duhem relation specifies, in a differential form, the relationship among all “intensive” properties of a thermodynamic system. Clearly, μ is not independent of T and P in the previous example. 30 Molecular Rheology LAB 1-4 1-4.3 Summary of formal structure The fundamental equation U=U(S, V, N) contains “all” thermodynamic information. Equations of state + the Euler equation = The full expression of U T T(S, V , N ) P P( S , V , N ) U TS Pi X i U U(S, V , N ) ( S, V , N ) The totality of all equations of state can be used to reconstruct the fundamental equation. 31 Molecular Rheology LAB 1-H 1-H Homework Problem 1.10-1: (a), (f), (g), (i) Problem 2.2-1 Problem 3.3-2 Read Sec. 3-5 (The ideal van der Waals fluid) 32 Molecular Rheology LAB Thermodynamic Potentials and Chapter 2 Legendre Transformations Contents 2-1 2-2 2-3 2-4 Legendre Transformations The Legendre Transformed Functions and Thermodynamic Potentials Minimum Principles for the Potentials Applications of various Legendre Transformed Potentials 2-5 Maxwell Relations and Some Applications 33 Molecular Rheology LAB 2-1 2-1 Legendre Transformations 2-1.1 The S max. principle & the U min. principle An isolated system must conform with two extremum criteria when equilibrium is reached. Entropy max. principle: Energy min. principle: Entropy is max. value for given total energy. Energy is min. value for given total entropy. Equivalent representations 34 Molecular Rheology LAB 2-1 S max. principle U min. principle Fundamental surface Figure 2.1 The equilibrium state A as a point of max. S for constant U & min. U for constant S. S max. principle: The equilibrium value of any unconstrained internal parameter is such as to maximize the entropy for a given value of the total internal energy. U min. principle: The equilibrium value of any unconstrained internal parameter is such as to minimize the energy for a given value of the total internal entropy. 35 Molecular Rheology LAB 2-1 Question: How to prove the two principles are equivalent? Answer: Using either physical argument or mathematical exercise. Physical argument Assume: The system is in equilibrium but the energy does not have its smallest possible value consistent with the given entropy. Can withdraw energy dU = -dW Energy System Return energy to sys. The system would be restored to its original energy but with an increased S. So, it is inconsistent with the principle that the initial equilibrium state is the state of maximum entropy. -dW = dQ = TdS The original equilibrium state must have had min. energy consistent with the prescribed entropy. The inverse argument is the same. 36 Molecular Rheology LAB 2-1 Mathematical exercise Entropy maximum principle: 2S S X 0 and X 2 0 U U X : Particular extensive parameter S X U S U T X X 0 S S U U X U X 0 S By eqn. A.22 of Appendix A 37 Molecular Rheology LAB 2-1 Chain Rule S 2U X U = 2 X S X S U X 2S T 0 2 X 2S 2 S 2 X U S X U 2 S X U S U U X S X S at 0 X From S max. principle: 2S S X 0 ; X 2 0 U U 2S 0 & T 0 2 X U U min. principle: 2U U X 0 ; X 2 0 S S 38 Molecular Rheology LAB 2-1 2-1.2 Legendre transformations Motivation: U(S, V, N) or S(U, V, N) both are extensive parameters. Some of these parameters might be difficult to control or measure under usual experimental conditions. Basic idea: Using Legendre transformations is to cast the above representation into equivalent forms which, by contrast, utilize intensive parameters as independent variables. 39 Molecular Rheology LAB 2-1 X, Y are extensive properties & Y=Y(X). Let slope is P Y ; P: intersive properties X If one considers the slope and the intercept at the same time, the transformation from Y(X) to ψ(P) is an unambiguous mapping. Y Y(X ) Y Y X X 0 Y PX P (P) X P Y PX Elimination of X and Y yields Elimination of P and yields (P) Y Y(X ) 40 Molecular Rheology LAB 2-1 Generalization of the Legendre transformation Y Y ( X 0 , X 1 , ... , X t ) Pk Y X k ( P0 , P1 , ... , Pn , X n1 , ... , X t ) Y Pk X k k Elimination of Y and X 0 , X 1 , Xk Pk Y Pk X k k ... , X n yields Elimination of and P0 , P1 , ( P0 , P1 , ... , Pn , X n1 , ... , Pn yields ... , X t ) Y Y ( X 0 , X 1 , ... , X t ) 41 Molecular Rheology LAB 2-2 The Legendre Transformed Functions 2-2 and Thermodynamic Potentials Legendre transformed functions Y Y ( X 0 , X 1 , ... , X t ) Pk Y X k The energy representation of the fundamental equation: U U ( S , V , N ) Intensive parameters T , P , 1 , 2 , ... Y Pk X k k Thermodynamic potentials F F (T , V , N ) H H (S, P, N ) G G (T , P , N ) 42 Molecular Rheology LAB 2-2 The Helmholtz potential, F U(S, V , N ) F (T , V , N ) ψ P Y X Y Y ( X 0 , X 1 , ... , X t ) U U(S, V , N ) Y Pk X k Y Pk X k k ( P0 , P1 , ... , Pn , X n1 , U S F U TS F F (T , V , N ) T ... , X t ) F F F S ; P ; T V N N , V T , N T , V dF SdT PdV dN 43 Molecular Rheology LAB 2-2 The Enthalpy, H U(S, V , N ) Y H (S, P, N ) ψ X P Y Y ( X 0 , X 1 , ... , X t ) Y Pk X k Y Pk X k k ( P0 , P1 , ... , Pn , X n1 , U U(S, V , N ) U V H U PV H H (S, P, N ) P ... , X t ) H H H T ; V ; S P N P, V S, N P, S dH TdS VdP dN 44 Molecular Rheology LAB 2-2 The Gibbs potential, G U(S, V , N ) G (T , P , N ) ψ P1 P2 Y X1 X2 Y Y ( X 0 , X 1 , ... , X t ) Y Pk X k Y Pk X k k ( P0 , P1 , ... , Pn , X n1 , U U(S, V , N ) U U ; P S V G U ST PV G G (T , P , N ) T ... , X t ) G G G S ; V ; T P N P, N T , N P, T dG SdT VdP dN 45 Molecular Rheology LAB 2-2 The main spirit of the Legendre transformation is that the new fundamental equation must be so derived that it does not lose any thermodynamic information as incorporated in the original one. The following equations are all fundamental equations: S (U , V , N ) U ( S , V , N ) F (T , V , N ) H ( S , P , N ) G(T , P , N ) Typical applications of the derived fundamental equations: F=F(T, V, N): Incompressible fluids H=H(S, P, N): Heat transfer G=G(T, P, N): Chemical reactions & Phase equilibrium 46 Molecular Rheology LAB 2-3 2-3 Minimum Principles for the Potentials The Helmholtz potential Consider a subsystem in contact with a thermal reservoir. Reservoir T r Thermal reservoir (Cp → ∞, T = T r ) T(1) Subsystem T(2) Using U representation U=U(S, V, N) : dU total 0 d 2U total 0 from the extremum principle at equilibrium 47 Molecular Rheology LAB 2-3 dU r dU dU total (dU r dU ) (T r dS r T (1)dS (1) T (2)dS (2) ) ( P (1)dV (1) P (2)dV (2) ) ( (1) dN (1) (2) dN (2) ) 0 r r r U U U r r r r dU dS dV dN r r r S V r , N r V S r , N r N V r , S r T r dS r S total constant dS total dS dS r dS (1) dS ( 2) dS r 0 dS (1) dS ( 2) dS r The subsystem of interest dV (1) dV ( 2) 0 ; dN (1) dN ( 2) 0 dV (1) dV ( 2) ; dN (1) dN ( 2) 48 Molecular Rheology LAB 2-3 (T (1) T r )dS (1) (T (2) T r )dS (2) ( P (1) P (2) )dV (1) ( (1) (2) )dN (1) 0 This equation always holds only if T (1) T (2) T r P (1) P (2) (1) (2) At equilibrium dU total (dU dU r ) dU T r dS r d (U T r S r ) d (U TS ) 0 dF 0 F U TS d 2U total d 2 (U U r ) d 2U d 2U r d 2U d 2U d 2 (TS ) d 2 (U TS ) 0 d 2F 0 By eqn. A.9 of Appendix A ; For thermal reservoir T = T r, V r & N r = constant 49 Molecular Rheology LAB 2-3 By the same way, consider a subsystem in contact with a pressure reservoir, or with both pressure & thermal reservoirs. Reservoir P r P(1) P(2) Reservoir T r & P r Subsystem T(1) P(1) T(2) P(2) H H (S, P, N ) G G (T , P , N ) dH 0 dG 0 d 2H 0 d 2G 0 50 Molecular Rheology LAB 2-3 The overall system: Representation: U U ( S ,V , N ) Experimental conditions: V total , N total , S total Extremum criteria: dU total 0 ; d 2U total 0 The subsystem: Representation: Experimental conditions: Extremum criteria: F F (T ,V , N ) T, V, N dF 0 ; d 2 F 0 H H (S, P, N ) S, P, N dH 0 ; d 2 H 0 G G (T , P , N ) T , P, N dG 0 ; d 2G 0 51 Molecular Rheology LAB 2-3 The equilibrium value of any unconstrained internal parameter in contact with a heat reservoir minimizes the Helmholtz potential over the manifold of states for which T = T r Similarly, one can prove the Enthalpy minimum principle H(S, P, N) for systems in contact with a pressure reservoir, as well as the Gibbs potential minimum principle G(T, P, N) for systems in contact with both a heat and pressure reservoir. 52 Molecular Rheology LAB Applications of various Legendre 2-4 Transformed Potentials 2-4 2-4.1 The Helmholtz potential Question: What are the main applications? Answer: Experiments carried out in rigid vessels with diathermal walls, so that the ambient atmosphere acts as a thermal reservoir. Constant T Constant V, N (the subsystem) The F(T, V, N) is admirably suited. 53 Molecular Rheology LAB 2-4 Example: Two simple subsystems separated by a movable, adiabatic, impermeable wall. V (1) ? V ( 2) ? Wrev ? P (1) (T r , V (1) , N (1) ) P ( 2) (T r , V ( 2) , N ( 2) ) V (1) V ( 2) V , a constant Can solve V (1) & V (2) dWrev dU dU r dU T r dS r dU T r dS d (U T r S ) dF The number of independent variables: V & N The work delivered in a reversible process, by a system in contact with a thermal reservoir, is equal to the decrease in the Helmholtz potential of the system. 54 Molecular Rheology LAB 2-4 Focus our attention exclusively on the subsystem of interest, and relegate the reservoir only to an implicit role. The Helmholtz potential is often referred to as the Helmholtz free energy, though the term available work at constant temperature, would be less subject to misinterpretation. As shown in Chap. 16, statistical mechanical calculations are enormously simpler for such systems, permitting calculations that would otherwise be totally intractable. See Example.1 in page 159, which shows that one can increases the entropy of a subsystem without changing the associated internal energy. 55 Molecular Rheology LAB 2-4 2-4.2 The enthalpy dH TdS VdP 1dN 1 2dN 2 ... At constant P , N i dH TdS dQ As a potential for heat H (S, P, N ) H V V (S, P, N ) P S , N H (V , P , N ) Qi f H (V f , P , N ) H (Vi , P , N ) At constant P , N Heating of a system is so frequently done while the system is maintained at const. P. The enthalpy is generally useful in discussion of heat transfers, and H is as a heat content of the system. Using a similar argument, U is a potential for heat, too. dU TdS PdV dN ; at constant V , N dU TdS dQ 56 Molecular Rheology LAB 2-4 The Joule-Thomson process u f ui Pi vi Pf v f ; by conservation of energy u f Pf v f ui Pi vi h f hi A constant H process u: initial molar energy v: molar volume h: molar enthalpy We do not imply anything about the enthalpy during the process; the intermediate states of the gas are non-equilibrium states for which the enthalpy is not defined. 57 Molecular Rheology LAB 2-4 The isenthalpic curves (“isenthalps”) The final temperature Tf can be higher or lower then Ti in this process, depending on the local relationship: T dT dP P H , N1 , N 2 , ... By eqn. A.22 of Appendix A & Maxwell relations v dT T 1 dP CP If Tα >1, T will increase with a small increase in pressure, and vice versa. For ideal gas, α = 1 / T, so that there will be no change in T. 58 Molecular Rheology LAB 2-4 2-4.3 The Gibbs potential Most experiments are carried out under constant T & P. G (T , P , N1 , N 2 , ...) is a particularly convenient choice. by defition: G U TS VP the Euler relation: U TS VP i N i G i N i i As a potential for chemical potential i r Consider the chemical reaction: 0 j A j 1 Aj : symbols for the chemical components j : stoichiometric coefficients 59 Molecular Rheology LAB 2-4 Change of G associated with changes in Nj can be described by dG SdT VdP j dN j j since dN1 1 dN 2 2 ... dN One has for the equilibrium condition: dN j j dN dG dN j j 0 j or j j 0 j The final state of a chemical reaction can thus be determined if the solution of the above equation is known, given that there is no depletion of any species. While G determines the equilibrium condition, H the heat of the reaction can be obtained by the following relation: dH r T j j dN T 1 P , N1 , N 2 , ... 60 Molecular Rheology LAB 2-4 2-4.4 Compilations of empirical data In practice, it is common to compile data on h (T, P), s (T, P), v (T, P); v is redundant but convenient. These relationships can, in principle, be utilized to construct the Gibbs potential via g = h –Ts, and thus all thermodynamic may be obtained using proper relationships, such as the Maxwell relationships. 61 Molecular Rheology LAB 2-5 2-5 Maxwell Relations and Some Applications 2-5.1 The Maxwell relations & mnemonic diagram Maxwell relations U U(S, V , N ) Constant N 2nd derivatives of potential U S V U V S P T Maxwell relation equation P T S V , N V S , N 62 Molecular Rheology LAB 2-5 In a similar way, we can derive other forms as shown below: Table 2.1. Maxwell relations for several potentials with various pairs of independent variables. (see also pp. 182 & 183 of the textbook) 63 Molecular Rheology LAB 2-5 Mnemonic diagram Valid V Facts F Understanding U S Solutions Theoretical T G Generate H Hard P Problems Pithy formula: “Valid Facts and Theoretical Understanding Generate Solutions to Hard Problems” 64 Molecular Rheology LAB 2-5 The first derivative of potential: Example: U T S S, N V (" " arrow pointed away) F U U P V V , N Maxwell relations: Example: V T S P P S (" " arrow pointed toward) (" ") S S V P T T P S Molecular Rheology LAB G S V T H P T P S P (" ") T V T (" ") P (" ") P 65 2-5 If we are interested in Legendre transformations dealing with S and Nj , the mnemonic diagram takes the form shown as below in the left diagram: Nj F U [T ] U S U [ j ] T X1 U [T , j ] U j X2 U(S, Nj) mnemonic diagram U [ P2 ] P1 U[ P1 , P2 ] U[ P1 ] P2 General-form mnemonic diagram 66 Molecular Rheology LAB 2-5 2-5.2 Procedure for the reduction of derivatives Four customarily used derivatives 1 v 1 V Thermal expansion coefficient: v T P V T P Isothermal compressibility: T v P T V P T 1 v 1 V Molar leat capacity at constant pressure: T S 1 dQ s cP T T P N T P N dT P Molar leat capacity at constant volume: T S 1 dQ s cV T T V N T V N dT V 67 Molecular Rheology LAB 2-5 For single-component systems and constant molecule numbers, the second derivatives of Gibbs representation can be expressed by cP , , and T . 2g 2g 2g c P /T ; v ; v T 2 2 T T P P All first derivative, such as dT T P V , N dP (involving both extensive and intensive parameters), can be written in terms of three independent second derivatives of the Gibbs potential (for the case of single-component systems), conventionally chosen as , cP and T . 68 Molecular Rheology LAB 2-5 Reduction of derivatives If the derivative contains any potential, bring them one by one to the numerator and elimin2 e by the thermodynamic square. Example: P Reduce the derivative U G , N P U G , N U P G , N (See also pp. 187-188 of the textbook) 1 S V T P P P G , N G , N G T P S , N 1 G G P S P P, N V , N G V P , N S T P S , N V S T P V , N V T P S T S S T V P, N P , N Molecular Rheology LAB 1 1 69 2-5 If the derivative contains the chemical potential, bring it to the numerator and eliminate by means of the Gibbs-Duhem relation, d sdT vdP . Example: Reduce the derivative V S , N T P s v V V V S, N S, N S, N If the derivative contains the entropy, bring it to the numerator. If one of the four Maxwell relations of the thermodynamic square now eliminates the entropy, invoke it. If the Maxwell relations do not eliminate the entropy put a T under S. The numerator will then be expressible as one of the cV or cP. Example: T Reduce the derivative P S , N T S S V P P T , N T P , N T P , N S, N N c T P 70 Molecular Rheology LAB 2-5 Bring the volume to the numerator. The remaining derivative will be expressible in terms of and T . Example: T Reduce the derivative P V , N T T V V P P T , N T P , N V , N The originally given derivative has now been expressed in terms of the four quantities cP , cV , , and T . The specific heat at constant volume is eliminated by the follow equation. cV c P Tv 2 T 71 Molecular Rheology LAB 2-5 2-5.3 Some simple applications I. Adiabatic compression Adiabatic wall Ti Adiabatic wall Quasi-static process Pi Tf =? Pf If known: fundamental equation, Pi , Pf , and Ti Fundamental equation Equations of state: ΔT=T(S, Pf , N)- T(S, Pi , N) (see p. 190) If known: Pi , Pf , Ti ,c P , , and T Tv sTv T dT dP dP ; d dP ( v )dP P P c c S, N S, N P P 72 Molecular Rheology LAB 2-5 II. Isothermal compression dS ? Quasi-static process Pf Pi Constant T dU ? Q ? If known: fundamental equation, Pi , and Pf Equations of state: S S (T , P , N ) Fundamental equation U U (T , P , N ) Q T S TS (T , Pf , N ) TS (T , Pi , N ) If known: Pi , Pf ,c P , , and T S U dS dP VdP ; dU dP ( T v PV T )dP P T , N P T , N dQ TVdP Q T VdP Pf Molecular Rheology LAB Pi 73 2-5 III. Free expansion Adiabatic wall Vacuum Adiabatic wall Gas Vi ; Ti Gas Constant U Vf ; Tf =? If known: fundamental equation, Vi , V f , and Ti Fundamental equation Equations of state: T f Ti T (U , V f , N ) T (U , Vi , N ) If known: Vi , V f ,Ti , c P , , and T P T T dT dV V U , N NcV NcV T Molecular Rheology LAB dV 74 2-H 2-H Homework Problem 5.3-1 Problem 5.3-12 Problem 6.3-2 Problem 7.4-7 Problem 7.4-15 Problem 7.4-23 Molecular Rheology LAB 75 Stabilities, Phase Transitions, and Chapter 3 Critical Phenomena Contents 3-1 3-2 3-3 3-4 3-H Stability Conditions for Thermodynamic Potentials Le Chaterlier’s Principle and Effects of Fluctuations First-order Phase Transitions in Single-Component Systems Thermodynamic States near Critical Points Homework 76 Molecular Rheology LAB 3-1 Stability Conditions for Thermodynamic 3-1 Potentials 3-1.1 Intrinsic stability of thermodynamic systems Basic extremum principle of thermodynamics: dS 0 The S is an extremum value. d 2S 0 The extremum value is a maximum, which guarantees the stability of predicted equilibrium states. 77 Molecular Rheology LAB 3-1 Remove ΔU from the right subsystem and transfer it to the left subsystem. Initial state S(U) S(U) New state S(U+ΔU) S(U-ΔU) S Total S U U S U U S Total 2S U Convex Concave S U U S U U 2 S (U ) Unstable (see later dicussion on phase separation) S U U S U U 2 S (U ) Stable (see later discussion on the Le Chaterlier’s principle) 78 Molecular Rheology LAB 3-1 The condition of stability is the concavity of the entropy. S U U S U U 2S (U ) for all By eqn. A.4 of Appendix A (refer to problem 8.1-1 of the textbook) 2S 0 2 U V , N For U 0 The same considerations apply to a transfer of volume. S V V S V V 2 S (V ) for all 2S 0 2 V U , N For V 0 The differential form is less restrictive than the concavity condition, which must hold for all ΔU(ΔV) rather than for ΔU→ 0(ΔV→ 0) only. 79 Molecular Rheology LAB 3-1 The portion BCDEF is unstable, because it violates the global form of concavity of entropy. Yet, only the portion CDE fails to satisfy the differential form of the stability condition. The portions of the curve BC and EF are said to be “locally stable” but “globally unstable.” (e.g., it is susceptible to large-amplitude perturbations) Points on the straight line BHF correspond to a phase separation in which part of the system is in state B and part in state F. 80 Molecular Rheology LAB 3-1 If one simultaneously changes U and V: 2S 0 2 U V , N 2S 0 2 V U , N The local conditions of stability ensure the curve of the intersection of the entropy surface with the plane of constant V or U have a negative curvature. But these two “ partial curvatures” are not sufficient to ensure concavity. S U U , V V S U U , V V 2 S (U , V ) By eqn. A.4 of Appendix A (refer to problem 8.1-1 of the textbook) 2 2S 2S 2S 0 2 2 U V U V 81 Molecular Rheology LAB 3-1 3-1.2 Stability condition for thermodynamic potentials Convexity of the energy surface: U S S , V V , N U S S , V V , N 2U ( S , V , N ) The local conditions of convexity: 2U T 0 2 S V , N S 2U P 0 2 V V S , N For cooperative variations of S and V : 2 2U 2U 2U 0 2 2 S V S V 82 Molecular Rheology LAB 3-1 Transform to other potential representations by Legendre transformation : Example: F (T , V , N ) 2F 2U 1 U S T 1 1 1 2 2 S V , N S V , N T V , N S V , N T V , N 2F 0 2 T V , N ; 2U 0 2 S V , N 2F ; By the same way 0 2 V T , N F T T , V V , N F T T , V V , N 2F (T , V , N ) By eqn. A.4 of Appendix A (refer to problem 8.1-1 of the textbook) 2 2F 2F 2F 0 2 2 V T V T 83 Molecular Rheology LAB 3-1 Similarly, one has for other potentials H (S, P, N ) 2 2H 2H 2H 2H 2H 0 ; 0 ; 0 2 2 2 2 S V , N P V , N S P S P G (T , P , N ) 2 2G 2G 2G 2G 2G 0 ; 2 0 ; 2 2 2 0 T V , N P V , N T P T P In summary, for constant N the thermodynamic potentials are convex functions of their extensive variables and concave function of their intensive variables. 84 Molecular Rheology LAB Le Chaterlier’s Principle and the Effects 3-2 of Fluctuations 3-2 3-2.1 Le Chatelier’s principle The Le Chatelier’s principle: any inhomogeneity that somehow develops will induce a process that eradicates the inhomogeneity. Example: Incident photon Container Fluid T1 In equilibrium state Fluid T1 T1 Locally heating the fluid slightly. T1’ Heat flows away The system restores form heated region. homogeneous state. 85 Molecular Rheology LAB 3-2 3-2.2 Effect of fluctuations From the perspective of statistical mechanics all physical systems undergo continual local fluctuations even in the absence of externally induced vibrations, only to attenuate and dissipate in accordance with the Le Chatelier principle. The curvature of the potential well then plays a crucial and continual role, restoring the system toward the “expected state” after each Brownian impact (fluctuation). 86 Molecular Rheology LAB 3-2 3-2.3 The Le Chatelier-Braun principle The Le Chatelier-Braun principle: Various other secondary processes that are also induced indirectly act to attenuate the initial perturbation. Example: Consider a subsystem contained within a cylinder with diathermal walls and a loosely fitting piston. Piston is moved outward slightly by external agent or fluctuation. Primary effect: The Pi decreased-the pressure difference across the piston then acts to push it inward; this is the Le Chatelier principle. Po Pi ; Ti ; Vi T&P reservoirs Molecular Rheology LAB 87 3-2 Secondary effect: An increased Vi alters Ti ; heat flows inward if α>0 and outward if α<0. T T dT dV dV NcV T V S Piston is moved outward slightly by external agent or fluctuation. Then, Pi is increased for either sing of α due to the heat flow. Thus a secondary induced process also acts to diminish the initial perturbation. This is the Le Chatelier-Braun principle. 1 P dP dQ dQ ; dQ TdS 2 T S S NT cV T (note that dQ is always positive) Po Pi ; Ti ; Vi Q T&P reservoirs 88 Molecular Rheology LAB 3-3 First-order Phase Transitions in Single3-3 Component Systems 3-3.1 First-order & second-order phase transitions Fluctuation Fluctuations (e.g. Brownian motions) play an important role bringing the system form one local min. to the other. The possibility associated with a successful jump is exponentially inverse to the energy gap. It is therefore possible that the system trapped in a metastable min. is effectively in stable equilibrium. • Global min. is path independent state, yet the metastable one is path dependent. The system spends almost all the time in the more stable minimum. 89 Molecular Rheology LAB 3-3 First-order phase transitions Definition: Shift of the equilibrium state from one local minimum to the other, induced by a change in certain thermodynamic parameters. Equilibrium state at constant T & P correspond to the min. in G(T, P, N). The slope of the curve in the left figure is simply difference in pressure. At T4, the molar Gibbs potential of two minima are equal, but other properties (e.g. u, f, h, v ,s) are discontinuous across the transition. High-density phase is more stable below the transition temperature, T4. Molecular Rheology LAB 90 3-3 Second-order phase transitions Definition: At the so-called critical point (point D), the difference between two distinct states disappears and there is only one equilibrium state. Moving along the liquid-gas coexistence curve toward higher temperatures, the discontinuities of two phase in molar volume and molar energy become progressively smaller. The existence of the critical point (D) precludes the possibility of a sharp distinction between the generic term liquid and the generic term gas. 91 Molecular Rheology LAB 3-3 3-3.2 Latent heat At first-order phase transition: ( I ) ( II ) Discontinued in u, f , h, v , s. But P ( I ) P ( II ) T ( I ) T ( II ) Example: Latent heat of fusion: dQ Tds Q l LS T ( s ( L ) s ( S ) ) T s since h Ts ; at phase transition point ( L ) ( S ) h T s l LS l LS 80 cal Ice cP 2.1kJ kg-K g lGL 540 cal Water cP 4.2 kJ g Steam Saturated steam table kg-K Superheated steam table 92 Molecular Rheology LAB 3-3 93 Molecular Rheology LAB 3-3 3-3.3 The Clapyron equation Some interesting natural observations: Ice skating: The pressure applied to ice on the blade of the skate shifts the ice, providing a lubricating film of liquid on which the skate slides. Mountain climbing: The pressure decreased and the water boiling point decreased with the higher altitude. Therefore, it is difficult to cook on the high altitude mountain. 94 Molecular Rheology LAB 3-3 The Clapron equation Clapron equation is the slope of coexistence curves. dP Slope: dT At phase equilibrium A A ; B B B A B A ; d sdT vdP B A sdT vdP B A sdT v dP (v v )dP ( s s )dT and l T s s dP l dT T v dP ( s' s ) s dT (v' v ) v l T The Clapeyron equation 95 Molecular Rheology LAB 3-3 The Clapeyron equation embodies the Le Chatelier principle. Consider a solid-liquid transition with a positive latent heat (sl > ss): dP If (vl v s ) Slope 0 dT Increase P at constant T System tends towards the more dense (solid) phase Increase T System tends towards the more entropic (liquid) phase dP If (vl v s ) Slope 0 dT Increase P at constant T System tends towards the more liquid phase The Clapeyron-Clausius approximation: v v g vl v g ; assume ideal gas v g From Clapeyron equation RT P dP P l 2 dT RT 96 Molecular Rheology LAB 3-3 3-3.4 1st phase transition based on van der Waals eq. The van der Waals equation of state describes rather well the general features of many gases and liquids. RT a P 2 (v b) v van der Waals E.O.S. P Stability criteria: T 0 or 0 V T Not all curves conform to the stability criteria. Clearly, portion FKM of T1 curve violates the stability criterion. Setting constant P will get one solution T in the T9 curve, and three solutions O, K and D in the T1 curve. But only O and D have physical meaning because K violates the stability criterion. 97 Molecular Rheology LAB 3-3 The given P-v isotherms may be used to compute the molar Gibbs free energy to better perceive the stability criterion. d sdT vdP or v ( P )dP (T ) (T ) is an undetermined function of the T The area of region I is the same as that of region II, and for the region in between liquid and gas (OD) coexist. This is the way to determine the phase transition points (O, D). O D v( P )dP 0 Molecular Rheology LAB 98 3-3 It should be obvious that B, C, D are more stable than M, L, K and R, Q, O are more stable than F, J, K etc. In general, for P < PD, the right-hand branch (ABCD) of the isotherm in right figure is physically significant, whereas for P > PD the left-hand branch (SRQD) is physically significant. The intermedium region is physically unstable. 99 Molecular Rheology LAB 3-3 The O, D, O’, D’, O’’, D’’ are first-order phase transitions, and O’’’ (D’’’) corresponds to the critical point, termination of the gas-liquid coexistence. The component in each of the phases is governed by the lever rule. x g xl 1 ; x g v g xl v l v z xl v g vz v g vl v z vl xg v g vl Molecular Rheology LAB 100 3-3 The entropy change during the phase transition can be computed using the following relation along hypothetical isotherm OMKFD. s ds dv v T P s dv T v OMKFD s P v T the Maxwell relation T v The total change in the molar energy: u T s Pv Limitation: Can’t apply near critical point. Molecular Rheology LAB 101 3-3 3-3.5 Summary of stability criteria U=U(x1, x2, …) or U=U(P1, P2, …) must be a “convex function” of its “extensive parameters” and a “concave function” of its “intensive parameter.” Geometrically, the function must lie above its tangent hyper-planes in the x1, … , xs-1 subspace and below its tangent hyper-planes in the Ps, … , Pt subspace. 102 Molecular Rheology LAB 3-3 3-3.6 1st phase transitions in multi-component system For a multi-component system the fundamental relation: U = U(S, V, N1 ,N2, … ,Nr) or the molar form: u = u(s, v, x1, x2, … , xr-1) At the equilibrium stable the “energy” , i.e., the enthalpy and the Helmholtz and Gibbs potentials are “convex functions” of the mole fraction x1, x2, … , xr-1. The mole fractions, like the molar entropies and the molar volumes, differ in each phase during a phase transition. Can be utilized for the purpose of purification by distillation. 103 Molecular Rheology LAB 3-3 Gibbs phase rule Gibbs phase rule is the thermodynamic degrees of freedom (f). f 2 M ( r 1) r ( M 1) r M 2 variations equations r : No. of components M : No. of phases f : No. of intensive parameters capable of independent variations 2 M ( r 1): P , T each phase have ( r - 1) variations No. of phases ( M ) 1I 1II ... 1M r ( M 1): rI rII ... rM 104 Molecular Rheology LAB 3-3 Application of the Gibbs phase rule Example: I. Single-component system (r=1) a: M=2 → f=1 → at a given T, another variable P must be unique b: M=3 → f=0 → the triple point II. Two-component system (r=2) a: M=1 → f=3 → T, P, x1 (or x2) can be arbitrarily assigned b: M=2 → f=2 → T, P can be arbitrarily assigned c: M=3 → f=1 → T, for example, can be arbitrarily assigned d: M=4 → f=0 → four phases coexist at unique point ※There cannot be five phases coexist in this case 105 Molecular Rheology LAB 3-3 3-3.7 Phase diagrams for binary systems Example: The three-dimensional phase diagram of a typical gas-liquid binary system. The two-dimensional sections are constant P planes, with P1 < P2 < P3 < P4. The C state in the twophase state is composed of A and B, and only A and B are physical point. 106 Molecular Rheology LAB 3-3 Example: Typical phase diagram for a binary system. Phase diagram for a binary system in equilibrium with its vapor phase. (P is not constant) 107 Molecular Rheology LAB 3-4 Thermodynamic States near Critical 3-4 Points 3-4.1 Features in the vicinity of the critical point As the point approaches the critical point the two minima of the underlying Gibbs potential coalesce. The distinction in phases utilized in the first-order transition breaks. 108 Molecular Rheology LAB 3-4 As the critical point is reached the single minimum is a flat bottom, which implies the absence of a “restoring force” for fluctuations away from the critical state. In the critical region, long-range correlated fluctuation become the dominant factor affecting the thermodynamic properties, and the shortrange atomistic feature becomes unimportant. Universal scaling behavior is predicted by the “ renormalization group theory” and verified in experiments for the behavior of the susceptibilities “ near the critical point.” 109 Molecular Rheology LAB 3-4 The generalized susceptibilities, such as cp, κT and α diverge. Example: 1 v T v P T v P at first phase transition or near critical point T T diverges; and c p diverge in a similar way. 110 Molecular Rheology LAB 3-4 3-4.2 The failure of the classical theory in predicting the scaling behavior near the critical point. Over-simplification of the extremum principle in classical thermodynamics. It must be replaced by the associated “probability distribution” and the consequent average properties. 111 Molecular Rheology LAB 3-4 The basic postulate of thermodynamics incorrectly identifies the most probable value of the energy as the equilibrium or average value. The deviation becomes very pronounced near critical points when the thermodynamic potentials become very shallow. Renormalization-group theory demonstrates that the numerical values of the scaling exponents for a large class of materials are identical, dependent primarily on the dimensionality of the system and on the order parameter. 112 Molecular Rheology LAB 3-H 3-H Homework Problem 9.1-1 Problem 9.3-3 Problem 9.4-11 Problem 9.7-1 113 Molecular Rheology LAB Chapter 4 Applications to Material Properties Contents 4-1 4-2 4-3 4-4 The general ideal gas Small Deviations from Ideality—The Virial Expansion Law of Corresponding States for Gases Applications to Dilute Solutions—The van’t Hoff Relation and the Raoult’s law 4-H Homework 114 Molecular Rheology LAB 4-1 4-1 The general ideal gas 4-1.1 The essence of ideal gas behavior Ideal gas behavior (which is good at sufficiently low density and fails evidently in the vicinity of their critical points) means that the gas do not interact, implying the following properties: 1. PV = NRT 2. For single-component ideal gas, T = T(u) or u = u(T) 3. The Helmholtz potential F(T, V, N1, …) is additive (Gibbs’s theorem) 4. T 1 1 , , c p cv R have the same value for all ideal gas P T 115 Molecular Rheology LAB 4-1 The F , U and S of general multicomponent ideal gas: F (T , V ) U j (T ) T S j (T , V ) U TS j j U j N j u j (T ) N j u j 0 N j cvj (T )dT T T0 T0 : arbitrarily chosen standard temperature v N 1 S N j s j0 N j c (T )dT N j R ln T0 T vj j j j v0 N j T 1 v N c v (T )dT NR ln NR x j ln x j T0 T v0 j T (see also Eq. (3.40) entropy of mixing Molecular Rheology LAB (at the same temperature and particle density) 116 4-1 Step-like The heat capacity of real gases approaches a constant value at high temperatures. At intermediate temperatures, each such mode contributes additively and independently to the heat capacity. This accounts for a “step-like” feature in the cv versus T curves. In general, however, the heat capacity, for instance, depends on the internal degrees of freedom, as well as on the system temperature which has to do with different modes of excitation. e.g. stretching of interatomic bond, kinetic energy of vibration, rotation, translational motions of the molecules, other potential and kinetic energy 117 Molecular Rheology LAB 4-1 4-1.2 Chemical reactions in ideal gases Partial molar Gibbs poential: j RT j (T ) ln P ln x j Since v j j 0 at chemical equilibrium j v j ln x j v j ln P v j ln j (T ) j j j The only temperaturedependent term Let K (T ), equilibrium constant, be defined by ln K (T ) v j ln j (T ) j j (T ) can in principle be known, so that K (T ) can be considered as known. For given T & P together with x j 1 each of x j can be determined. j The mass action law: x j j P j j K (T ) v v j 118 Molecular Rheology LAB 4-1 Logarithmic additivity of K(T) (1) (2) reaction1: 0 v A ; reaction2: 0 v j j j Aj v (3) If 0 j A j can be obtained by summing the previous reaction, (1) (2) v (3) that is, 0 A ( B v B v ; B1 & B2 are constant j j 1 j 2 j )A j Then it can be shown that: ln K 3 (T ) B1 ln K 1 (T ) B2 ln K 2 (T ) Can help tabulations of K(T) for various chemical reactions. The reaction heat can also be computed from K (T ) as dH d RT 2 ln K (T ) (the van't Hoff relation) dN dT (see an example in page 295 of the textbook.) 119 Molecular Rheology LAB 4-2 Small Deviations from Ideality—The Virial 4-2 Expansion 4-2.1 Virial expansion P R B(T ) C (T ) 1 2 T v v v Correction term for v B(T ): "Second virial coefficient" which accounts for the contribution from Ideal behavior two-body interactions. C (T ): "Third virial coefficient" which accounts for the contribution from three-body interactions etc. For simple gases, use of the second virial coefficient may suffice to capture their physical behaviors; for complex fluids, more correction terms 120 must be introduced. Molecular Rheology LAB 4-2 4-2.2 Other thermodynamic quantities may be expanded in a self-consistent fashion B(T ) C (T ) D(T ) (f is the molar Helmholtz potential) f f ideal RT 2v 2 3v 2 v f (from P ) v 1 d 2 ( BT ) 1 d 2 (CT ) 1 d 2 ( DT ) cv cv ,ideal RT 2 2 2 2 2 2v dT 3v dT v dT f s (from cv T ; s ) T T v 1 dC 1 dD 1 dB u uideal RT 2 2 2 v dT 2v dT 3v dT (from u f Ts ) 121 Molecular Rheology LAB 4-2 The second virial coefficient vanishes at some special temperatures for several simple gases. 122 Molecular Rheology LAB 4-3 4-3 Law of Corresponding States for Gases 4-3.1 Important observations for gases In the equation of state of a given fluid, there is one unique point-the critical point—characterized by Tcr, Pcr, and vcr. The dimensionless constant Pcr vcr/R Tcr has value on the order of 0.27 for all “normal” fluids of the three parameters that characterizes the critical point. It thus appears that “only two are independent”. (see more data in Table13.1 of the textbook) 123 Molecular Rheology LAB 4-3 4-3.2 The Law of corresponding states There exists, at least semi-quantitatively, a universal equation of state containing no arbitrary constants if expressed in the reduced variables v /vcr, P/Pcr, and T/Tcr. This empirical fact is known as the “Law of corresponding state”. e.g. It has been customary to plot the compressibility factor in a way Z Pv RT or P v T Z 0.27 P v T cr cr cr as functions of P/Pcr, and T/Tcr. 124 Molecular Rheology LAB 4-3 Tr curve 125 Molecular Rheology LAB 4-3 The Lennard-Jones potential 1 r6 1 Repulsive force 12 r Attractive force A possible origin of the universal, two-parameter equations of state-the “van der Waals force” of two spherical-like, non-polar molecules. The force between two molecules can be parameterized by the radius of the molecule, which describes the short-range repulsion, and the strength of the long-range attraction. The long-range attractive force falls with distance as 1/r6 and has arisen from the instaneous dipole moment fluctuations. 126 Molecular Rheology LAB 4-4 Applications to Dilute Solutions—the van’t 4-4 Hoff Relation and the Raoult’s law 4-4.1 the van’t Hoff relation for osmotic pressure Consider a single-component fluid system, the Gibbs potential of the dilute solution can be written in the general form: G (T , P , N 1 , N 2 ) N 1 10 ( P , T ) N 2 ( P , T ) N 1 RT ln N 2 RT ln N1 N1 N 2 N2 N1 N 2 represents the effect of the interaction energy between the two types of molecules, while the last two terms accounts for the entropy of mixing In dilute region (N 2 N 1 ) ln N1 N N1 2 , N 1 ln N2 N1 N 2 N1 N1 N 2 G (T , P , N 1 , N 2 ) N 1 10 ( P , T ) N 2 ( P , T ) N 2 RT N 2 RT ln Molecular Rheology LAB N2 N 1 127 4-4 Solvent and solute partial molar Gibbs potentials: 1 ( P , T , x ) G 10 ( P , T ) xRT N 1 2 ( P , T , x ) N G ( P , T ) RT ln x ; ( x 2 ) N 2 N1 The pressure on the pure solvent side is maintained constant (=P), but the mixture side can alter by change in height of the liquid level in a vertical tube. The equilibrium condition: 1 ( P , T , 0) 1 ( P , T , x ) P : The pressure on the solute side of the membrane 128 Molecular Rheology LAB 4-4 1 ( P , T , 0) 1 ( P , T , 0) xRT Expanding 1 ( P , T , 0) around the pressure P 1 ( P , T , 0) ( P P ) P 1 ( P , T , 0) ( P P )v 1 ( P , T , 0) 1 ( P , T , 0) ( P P )v xRT Multiplying by N 1 V P N 2 RT the van’t Hoff relation for osmotic pressure in dilute solutions 129 Molecular Rheology LAB 4-4 4-4.2 Application to vapor pressure The vapor pressure reduced by addition of low concentration of nonvolatile solute: liq ( P , T ) gas ( P , T ) liq ( P , T ) xRT gas ( P , T ) Expanding liq ( P , T ) and gas ( P , T ) around the pressure P liq ( P , T ) liq ( P , T ) v liq ( P P ) gas ( P , T ) gas ( P , T ) v gas ( P P ) P P xRT v g vl v g vl ; (the ideal gas equation: v g P x P RT ) P Raoult’s law 130 Molecular Rheology LAB 4-H 4-H Homework Problem 13.2-2 Problem 13.5-2 Problem 13.5-3 131 Molecular Rheology LAB Chapter 5 Statistic Ensembles and Formulism Contents 5-1 The entropy representation—the Boltzmann’s law 5-1.1 Physical significance of entropy for closed system (15.1) 5-1.2 The Einstein model of a crystalline solid (15.2) 5-1.3 The two-state system (15.3); a polymer model (15.4) 5-2 The Canonical Formalism 5-2.1 The probability distribution (16.1) 5-2.2 The partition function (16.2) 5-2.3 The classical ideal gas (16.10) 5-3 Generalized Canonical Formulations 5-3.1 Entropy as a measure of disorder (17.1) 5-3.2 The grand canonical formalism (17.3) 132 Molecular Rheology LAB 5-1 The Entropy Representation—the 5-1 Boltzmann’s law 5-1.1 Physical significance of entropy for closed system Classical Thermodynamics Erected on a basis of few hypotheses of entropy. e.g. S=S(U, V, N) ; extremum principle Statistical Thermodynamics Statistical mechanics provides the physical interpretation of the entropy and a heuristic justification for the extremum principle. 133 Molecular Rheology LAB 5-1 Atomic systems Quantum mechanics If the system is macroscopic, there may exist many discrete quantum states consistent with the specified values of U, V, and N. Macroscopic systems Closed system given V & N U, V, and N are the only constraints on the system. Naively, we might expect the system in a particular quantum state would remain forever in that state. The apparent paradox is seated in the assumption of isolation of physical system. No physical system is, or ever can be, truly isolated. A realistic view of a macroscopic system is one in which the system makes enormously rapid random transitions among its quantum states. A macroscopic measurement senses only an average of the properties of myriads of quantum states. 134 Molecular Rheology LAB 5-1 Equal probability assumption Consider a “isolated” system and “constraint N, V, & U.” Not all of the system microstates are determined, and hence one is concerned with the probability associated with each of these microstates. Equal probability assumption brought out by Boltzmann: A macroscopic system samples every permissible quantum state with equal probability. The assumption of equal probability of all permissible microstates is the fundamental postulate of statistical mechanics. Equal probability assumption applies only to isolated systems. 135 Molecular Rheology LAB 5-1 Correlation of Ω & S The No. of microstates (Ω) among which the system undergoes transitions, and which thereby shares uniform probability of occupation, increases to the max. permitted by the imposed constraints. According to the postulate of the entropy increases to the max. permitted by the imposed constraints. It suggests that the entropy can be identified with the number of microstates consistent with the imposed macroscopic constraints. 136 Molecular Rheology LAB 5-1 Entropy (S ) additive (extensive) No. of microstates ( ) Multiplicative 6 6 + ? = 6 × 6 S kB ln The constant prefactor merely determines the scale of S, and agrees with Boltzmann’s constant kB =R/NA=1.3807 × 10-23 J/K. Nevertheless, the microcanonical formulation establishes the clear and basic logical foundation of statistical mechanics. 137 Molecular Rheology LAB 5-1 5-1.2 The Einstein model of a crystalline solid Consider a nonmetallic crystalline solid, and just focus on the vibrational modes. Electronic excitations, nuclear modes, and various other types of excitations were ignored. Assumed the N atoms in the crystal are free to vibrate around its equilibrium position in any of three coordinate directions, and can be replaced by 3N harmonic oscillators, all with the same natural frequency 0 . Einstein introduced the energy of harmonic oscillators discretely: =n 0 ; n 0, 1, 2, ... h / 2 ; h: Planck's constant Discrete values of energy: n 0 138 Molecular Rheology LAB 5-1 If the energy of the system is U it can be considered as constituting U 0 quanta. Theres quanta are to be distributed among 3 N vibrational modes. Number of permutations of (3 N 1 U 0 ) 3 N U 1 ! H C 3 N 1 ! U ! 3 N U 1 ! 3 N U ! 3 N 1 ! U ! 3 N ! U ! 3N U 0 3 N U U 0 0 1 0 0 0 0 0 ( N ) 0 139 Molecular Rheology LAB 5-1 u u u s 3 R ln 1 3 R ln 1 ; u0 3 N A 0 u0 u0 u0 From S k B ln & ln( M !) M ln M M (if M 1) According to this equation, which is independent of the volume, the pressure is identically zero. Such a nonphysical result is a reflection of the naive omission of volume dependent effect from the model. k 1 S 3N B ln 1 N A 0 T U 0 U There are 3 NN A oscillator in the system Thermal equation of state: mean energy per oscillator U 3 NN A e 0 0 k BT 1 The quantity 0 k B is called the "Einstein temperature" of the crystal, and it generally is of the same order of magnitude as the melt point of the solid. 140 Molecular Rheology LAB 5-1 cv approaches a constant value (3R) at high temperature. cv is zero at zero temperature. Einstein model is in qualitative agreement with experiment, but the rate of increase of the heat capacity is not quantitatively correct. At low temperature cv rises exponentially, whereas experimentally the heat capacity rises approximately as T 3. 141 Molecular Rheology LAB 5-1 5-1.2 The two-state system ; a polymer model Two-state system Total atoms N U : system energy (N - U ) atoms are Ground state Excited state in the ground state (with energy 0) (with energy ε) CUN N! U ! N U U atoms are in the excited state ! U U U U S N k B ln 1 ln N N From S k B ln & ln( M !) M ln M M (if M 1) 142 Molecular Rheology LAB 5-1 Thermal equation of state: N U 1 e k BT 1 S k B N ln 1 T U U ( U N ) ; du 2 e k BT c NA dT k BT 2 1 e 2 k B T 2 NA 2 k BT 2 e 2 k BT e 2 k BT 2 The energy approaches N 2 as the temperature approaches infinity in this model. At infinite temperature half the atoms are excited and half are in their ground state. 143 Molecular Rheology LAB 5-1 Schottky hump The max. is taken as an indication of a pair of low lying energy states, with all other energy states lying at considerably higher energies. It is an example of the way in which thermal properties can reveal information about the atomic structure of materials. 144 Molecular Rheology LAB 5-1 A polymer model Each monomer unit of the chain is permitted to lie +x, -x, +y, and –y. The length between two monomer unit is a. Represent interference by assigning a positive energy ε to such a perpendicular monomer. 145 Molecular Rheology LAB 5-1 N x N x N y N y N Lx Lx a Ly Ny Ny Ly a U N y N y U N x N x 1 2 1 Nx 2 1 N y 2 1 N y 2 N x N U L x N U L x U L y U L y The number of configurations of the polymer consistent with given corrdinates Lx and Ly of its terminus and given energy U : (U , Lx , Ly , N ) N! N x ! N x ! N y ! N y ! 146 Molecular Rheology LAB 5-1 S k B ln Nk B ln N N x k B ln N x N x k B ln N x N y k B ln N y N y k B ln N y or 1 1 N U Lx k B ln N U Lx 2 2 1 1 N U Lx k B ln N U Lx 2 2 S Nk B ln N 1 1 U Ly k B ln U Ly 2 2 1 1 U Ly k B ln U Ly 2 2 Ty S k B U Ly ln 0 ; ( y 0) T Ly 2a U Ly Ly Ly N y N y Molecular Rheology LAB Ly a Ly & a 0 Ly Ly 0 N y N y 147 5-1 S k B N U Lx ln T Lx 2a N U Lx Tx N U Lx e N U L kB kB 1 S k B ln N Lx U ln N Lx U ln U T U 2 2 2 Tx a k B T e 2 k BT N U 2 Lx 2 U2 sinh Tx a k BT Lx N cosh Tx a k BT e k BT Tx Na 2 1 For small Tx a (relative to k BT ) Lx k BT 1 e k BT The modulus of elasticity of the rubber band: 1 Lx a2 1 e N Tx T k BT Molecular Rheology LAB k BT 1 148 5-2 5-2 The Canonical Formalism 5-2.1 The probability distribution Limitation of microcanonical formalism: The microcanonical formalism is simple in principle, but it is computationally feasible only for a few highly idealized models. Isolated system Must calculate the no. of combinatorial ways that a given total energy can be distributed in arbitrarily sized boxes. Generally beyond our mathematical capabilities! Canonical formalism (Helmholtz representation) T reservoir system Remove the limitation on the amount of energy available -to consider a system in contact with T reservoir rather than an isolated system. 149 Molecular Rheology LAB 5-2 Canonical formalism Closed system T reservoir Closed system = Subsystem + T reservoir subsystem (note that the energy of the subsystem fluctuates) In “subsystem,” each “state” does not have the same probability, as for an closed system” to which the principle of equal probability of “microstates” applies. i.e., the subsystem does not spend the same fraction of time in each state. The key to the canonical formalism is the determination of the probability distribution of the subsystem among its microstates. 150 Molecular Rheology LAB 5-2 A Simple analogy thrown Sum of no. =12 Sum of no. 12 Record red dice no. What fraction of these recorded throws has the red die shown a one, a two,…, a six ? Sum is12 corresponds to given total energy 2/25 3/25 Reservoir subsystem The numbers shown correspond to the energy of the system 4/25 Each state does not have the same 5/25 probability. 6/25 5/25 151 Molecular Rheology LAB 5-2 Probability of subsystem The probability f j of the subsystem in state j: fj res Etot E j tot Etot fj ; E j : the energy in state j exp k B1 S res Etot E j exp k Stot Etot 1 B ; from S k B ln If U is the average value of the subsystem Stot Etot S U S res Etot U Expanding S res Etot E j around the equilibrium point Etot U : S res Etot E j S res Etot U U E j S res Etot U f j e U Ej T 1 k BT U TS ( U ) 1 k RT E j Molecular Rheology LAB e 152 5-2 f j e 1 k BT U TS ( U ) 1 k RT E j e 1 k BT define f j e F e Ej e F is state-independent normalization factor f j e F e j Ej j define Z e Ej e F e Ej 1 j e F Z j Fundamental relation in the canonical formalism: F ln e Ej ln Z j The probability of occupation of the j -th state: fj e Ej e Ei i 153 Molecular Rheology LAB 5-2 The average energy: U E j f j E je j j Ej e Ei i or d U d ln Z ; F U F T & F ln Z T Two equations are very useful in statistical mechanics, but it must be stressed that these equations do not constitute a fundamental relation. The quantity β is merely the reciprocal temperature in “natural units.” 154 Molecular Rheology LAB 5-2 5-2.2 The partition function Consider a system composed of Ñ “distinguishable elements,” an element being an “independent (noninteracting) excitation mode” of the system. System Element Each element can exist in a set of orbital states (use the term orbital state to distinguish the states of an element from the state of the collective system). The identifying characteristic of an “element” is that the energy of the system is a sum over the energies of the element, which are independent and noninteracting. 155 Molecular Rheology LAB 5-2 Each element is permitted to occupy any one of its orbitial states independently of the orbital states of the other elements. Then the partition sum: ε ε ε ε i j : the energy of the i -th element Z e 1 j 2 j 3 j j , j , j , ... in its j -th orbitial state ε ε ε e 1 j e 2 j e 3 j j , j , j , ... e ε1 j ε 2 j j j zi e e εi j ; e ε 3 j j z1z 2 z 3 z i : the "partition sum of the i -th element" j The Helmholtz potential : F ln Z ln z1 ln z 2 The energy is additive over elements, and each element is permitted to occupy and its orbital states independently. 156 Molecular Rheology LAB 5-2 Applied to two- state model: Z z e e N 0 ε F ln e Ej N 1 e j F Nk BT ln 1 e N Total atoms Ñ 1 & k BT ln Z ε ε N Ground state Excited state (with energy 0) (with energy ε) If the number of orbitals had been three rather than two, the partition sum per particle z would merely have contained three terms. z e ε j e ε1 e ε2 e ε3 j 157 Molecular Rheology LAB 5-2 Applied to the Einstein model: Einstein introduced the energy of harmonic oscillators discretely: 1 h / 2 ; = 0 n 2 n 0, 1, 2, ... ; h: Planck's constant The "elements" are the vibrational modes. ze e 1 0 2 1 0 2 e 3 0 2 1 e 1 0 2 e z 1 e 0 F 1 ln z 3 N e 0 5 0 2 e 2 0 e 7 0 2 e 3 0 1 xn 1 x x2 xn 1 x n 0 3 0 Nk BT 3 Nk BT ln 1 e 0 2 (1 x 1) 158 Molecular Rheology LAB 5-2 5-2.3 The classical ideal gas Definition of the classical ideal gas: Can neglect the interactions between gas particles (unless such interactions make no contribution to the energy-as, for instance, the instantaneous collisions of hard mass points). Consider monatomic classical ideal gas: Neglect interactions between gas molecules T reservoir No. of atoms Ñ(=NNA) The energy is the sum of one-particle “kinetic energies,” and the partition sum factors. Container volume V 159 Molecular Rheology LAB 5-2 The one-particle translational partition sum ztransl: kp ; p: generalized momentum H( x , y , z , p x , p y , pz ): Hamiltonian function dq j dp j Z e 1 2 1 2 z transl z internal j h h 1 p 2x p 2y pz2 2 m z transl 3 dxdydz dp xdp y dpz e h p2 2 m p2 1 p 2x 2 m y 3 dxdydz e dp x e dp y e z h H V 32 V 3 2 mk BT h ( - e ax = 2 a 2m dpz ) 160 Molecular Rheology LAB 5-2 32 V 2 mk T B h3 If one identifies Z as z N and thereby z transl calculates F . Finding F is not extensive! To identify Z as zÑ is to assume the particles to be distinguishable. To correct this partition sum by taking indistinguishability into account, the result must be further divided by Ñ!. Definition of indistinguishability in quantum mechanics: Indistinguishability does not imply merely that the particles are “identical” -it requites that the identical particles behave under interchange in ways that have no classical analogue. 161 Molecular Rheology LAB 5-2 The partition sum for a classical monatomic ideal gas: N! Z= 1 N z transl V 2 mk BT 3 2 F k BT ln Z Nk BT ln Nk BT 2 h N U 3 2V F 5 3 2 S Nk B ln 3 m Nk B ln 5 2 T 2 2 N Thermodynamic context for monatomic ideal gases: U 3 2 V N 5 2 S Ns0 NR ln U 0 V0 N 0 The constant s0, undetermined in classic thermodynamic context, has now been evaluated in terms of fundamental constants. 162 Molecular Rheology LAB 5-2 Orbital model Reflection on the problem of counting states reveals that division by Ñ! is a rather crude classical attempt to account for indistinguishability. Classical counting Fermi particles Bose particles 1 2 1 2 1 2 2 1 “Corrected” number of states = 4.1/2! 163 Molecular Rheology LAB Classical counting Fermi particles 5-2 Bose particles 1 2 1 2 1 2 2 1 “Corrected” number of states = 4.1/2! “Corrected classical counting” is incorrect for either type of real particle! At sufficiently high temperature the particles of a gas are distributed over many orbital states, form very low to very high energies. The probability of two particles being in the same orbital state becomes very small at high temperature. The error of classical counting then becomes insignificant, as that error is associated with the occurrence of more than one particle in a one-particle state. All gases approach “ideal gas” behavior at “sufficiently high temperature”. 164 Molecular Rheology LAB 5-2 The Equipartition Theorem Suppose the energy (Hamiltonian) to be of the form E Aq Bp 2 2 Then, the classical partition function yields z~ dq dp ( Aq Bp ) 2 e 2 k BT ~ 1/ 2 k BT 1/ 2 h hA hB The significance is that, at sufficiently high temperature when the classical density of 1 states is applicable, every quadratic term in the energy contributes a term Nk B 2 to the heat capacity. This is the "equipartition theorem" of classical statistical mechanics. Exp. A heteronuclear diatomic molecule has three translational modes, one vibrational mode (with both kinetic and potential energy), two rotational modes (i.e., it requires two angles to specify its orientation and has only kinetic energy). Therefore, the heat capacity per molecule at high temperature is 3 2 2 7 7 k B k B k B k B ( or R per mole). 2 2 2 2 2 Molecular Rheology LAB 165 5-3 5-3 Generalized Canonical Formulations 5-3.1 Entropy as a measure of disorder Information Theory Define the information I in terms of the probability fj, subject to the following requirements: Information is a non-negative quantity, I(fj) ≧0. If an event has probability 1, it’s no information from the occurrence for event, I(1) =0 . If two independent events occur, then the information we get from observing the events is the sum of the two of them: I(f1 × f2) = I(f1) + I(f2). I(fj) is monotonic and continuous in fj. 166 Molecular Rheology LAB 5-3 Four properties can thus be derived: 1 I f j log b log b f j fj b: the positive constant b was used in different units e.g. log 2 units are bits (from "binary") log 3 units are trits (from "trinary") log e units are nats (from "natural logarithm") log10 units are Hartleys Define the disorder (entropy) of the porbability distribution n H j 1 f ,f , 1 2 , f j is 1 f j log b fj 167 Molecular Rheology LAB 5-3 Several requirements of the measure of disorder reflect our qualitative concepts: The measure of disorder should be defined entirely in terms of the set of numbers ﹛fj﹜. The maximum disorder corresponds to all event have equal possibility. Example: Given sample space S and it's possibility distribution: S s1 , s2 , s3 , s4 ; possibility distribution f1 , f 2 , f 3 , f 4 Situation I: f1 f 2 f 3 f 4 1 / 4 1 1 1 1 log 2 4 log 2 4 log 2 4 log 2 4 2 bits 4 4 4 4 Situation II: H P Have max. disorder f1 1 / 2, f 2 1 / 4, f 3 f 4 1 / 8 1 1 1 1 log 2 2 log 2 4 log 2 8 log 2 8 1.75 bits 2 4 8 8 Molecular Rheology LAB H P 168 5-3 At max. f 1- f 1/ 2 H 1 1 log 2 2 log 2 2 1 bits 2 2 Entropy in the case of two possibilities with probabilities f and (1-f). C. E. Shannon, J. Bell Syst. Tech. 27, 379-423 (1948). The conceptual framework of “information theory,” erected by Claude Shannon in 1948, provides a basis for interpretation of the entropy in terms of Shannon’s measure of disorder. 169 Molecular Rheology LAB 5-3 From the definition of disorder (entropy): n H j 1 n 1 f j log b k f j ln f j fj j 1 If the system is isolated, it spends equal time in each of the permissible states. 1 fj ; j 1, 2, 1 1 1 H k f j ln f j k ln k ln k ln j 1 j 1 H k ln Microcanonical formalism: S k B ln k kB For a closed system the “entropy” corresponds to “Shannon’s quantitative measure of the maximum possible disorder” in the distribution of the system over its permissible microstates. 170 Molecular Rheology LAB 5-3 If the system is in contact with a thermal reservoir, the probability of j-th sate is fj e Ej Z ; j 1, 2, H k B f j ln f j k B f j ln e j 1 j 1 H k B f j E j k B ln Z j 1 Ej Z k B f j E j ln Z j 1 S k B f j E j k B ln Z j 1 This agreement between entropy and disorder is preserved for all other boundary conditions-that is for systems in contact with pressure reservoirs, with particle reservoirs, and so forth. Thus we recognize that the physical interpretation of the entropy is that the entropy is a quantitative measure of the disorder in the relevant distribution of the system over its permissible microstates. In thermodynamics the entropy enters as a quantity that is maximum in equilibrium. Identification of the entropy as the disorder simply brings theses two viewpoints into concurrence for closed systems. 171 Molecular Rheology LAB 5-3 5-3.2 The grand canonical formalism Closed system Closed system = Subsystem + T reservoir T & μ reservoir Consider a system of fixed V in contact with both energy and particle reservoirs, and given energy Ej and mole number Nj. subsystem Probability of a state of the system: fj res Etot E j , N tot N j fj tot Etot , N tot exp k B1 S res Etot E j , N tot N j Expanding S res Etot E j , N tot N j fj e U TS N E j N j Molecular Rheology LAB e ; & S E exp k Stot Etot , N tot 1 B tot tot from S kB ln , N tot 172 5-3 fj e U TS N E j N j e defined =U TS N U T , ; is the "grand canonical potential" f j e e E j N j e is state-independent normalizing factor E j N j E j N j f j e e e e 1 j j j define Z e E j N j ; Z : the grand canonical partition sum j e Z ln Z The conventional view is that Ψ(T, V, μ) is the Legendre transform of U, or Ψ(T, V, μ) = U[T, μ]. 173 Molecular Rheology LAB 5-3 Mnemonic figure F U T Useful relationships : Multiplied 1 kB lnZ U 174 Molecular Rheology LAB 5-3 To corroborate the grand canonical formalism from maximizing the disorder (entropy): S k B f j ln f j j 1 Auxiliary conditions: f j 1 j 1 j 1 f j 1 j S kB ln f j 1 f j 0 j 1 Auxiliary conditions: 1 f j 0 j 1 fE j Taking differentials j E Nj N 2 E j f j 0 Taking differentials & multiplying by Lagrange 3 multiplier λ1, λ2, λ3. j 1 N f j 1 j 0 175 Molecular Rheology LAB 5-3 S kB ln f j 1 f j 0 j 1 Adding 4 equations Auxiliary conditions: 1 f j 0 j 1 ln f j 1 j 1 1 2 E j 3 N j 0 2 E j f j 0 If this equation is always to hold true, 3 N j f 0 each term must be equal to zero. ln f j 1 1 2 E j 3 N j 0 j 1 j 1 fj e fj e 1 1 2 E j 3 N j f j e e 1 1 2 E j 3 N j 1 1 E j N j Compare the two equations to identify λ1, λ2, & λ3. 2 3 176 Molecular Rheology LAB 5-3 Example: Molecular Adsorption on a Surface Consider a gas in contact with a solid surface. The molecules of the gas can adsorb on specific sites on the surface. T & μ reservoir Solid surface (system) There are Ñ such sites, and each site can adsorb zero, one, or two molecules. the site is empty 0 Each site has an energy: singly occupied 1 doubly occupied 2 We seek the “fractional coverage” of the surface. The gaseous phase which bathes the surface establishes the values of T and μ, being both a thermal and a particle reservoir. In such a case μ, the Gibbs potential per particle of the gas, must first be evaluated from the fundamental equation of the gas, if known, or from integration of the Gibbs-Duhem relation if the equation of state are known. 177 Molecular Rheology LAB 5-3 The surface sites do not interact, the grand partition sum: Z zN z = e E j N j e0 e 1 e 2 2 1 e 1 e 2 2 j The mean number of molecules adsorbed per site is E j N j e Nj E j N j n fjN j e e Nj z j j j 0e 0 0 z 1 e z 2e 2 2 z 2e 2 n z The mean energy per site is e 1 1 e z 2 fjEj e e E j N j j j Ej 1e 1 2e z 2 2 178 Molecular Rheology LAB 5-3 An alternative route to these two results, and to the general thermodynamics of the system, is via calculation of the grand canonical potential: k BT ln Z . k BT ln Z = k BT ln z N k BT ln 1 e 1 e 2 2 The number Nˆ of adsorbed atoms on the N sites: ˆ N Nn ; T is constant ˆ U N 179 Molecular Rheology LAB Density of States " sum " ... e Ej j The quantity in the parenthesis is unity " sum " 1 e Ej Z j The quantity in the parenthesis is the energy ,and the "sum" divided by Z " sum " Ej E j e Z U Z j Under the circumstance that E j 1 E j 1 ,the sum can be replaced by integral. " sum " ≈ Emin ... e E j D E dE Density of state 180 Molecular Rheology LAB Example: Problem 16.10-4 Consider a particle of mass m in a cubic container of volume V. 2 2 Show that E ≈ 2mV 2 3 h k k 2 Planck constant : h 2 Momentum : P Just consider the kinetic energy p2 Ej 2m Substitute k P for Wave factor : k 1 3 n1 , n2 , n3 V 2 2 k2 2 2 2 n n n 2 3 2m 2mV 2 3 1 2 E E j 1 E j Molecular Rheology LAB ≈ 2 2 n1 0,1, 2, ... n2 0,1, 2, ... n3 0,1, 2, ... 2mV 2 3 181 Example: Problem 16.10-4 Show that the partition sum can be approximated well by an integral under certain temperature criterion. Under the circumstance that E j 1 E j 1 ,the sum can be replaced by integral. ztransl e Ej ≈ j E j 1 E j T Emin e Ej D E dE 2 2 1 E 1 2 3 kbT 2mV 2 2 2kb mV 2 3 Molecular Rheology LAB 182 5-H 5-H Homework Problem 15.1-1 Problem 15.2-1 Problem 15.4-4 Problem 16.1-1 Problem 16.1-4 Problem 16.2-1 Problem 16.10-4 Molecular Rheology LAB 183 Statistical Fluctuations and Solution Chapter 6 Strategies Contents 6-1 Fluctuations 6-1.1 The probability distribution of fluctuations (19.1) 6-1.2 Moments and the energy fluctuations (19.2) 6-2 Quantum Fluids 6-2.1 Quantum particle-fermions and bosons (18.1) 6-2.2 The ideal Fermi fluid (18.2) 6-2.3 The ideal Bose fluid (18.5) 6-2.4 The classical limit and the quantum criterion (18.3) 6-2.5 The strong quantum regime: electrons in a metal (18.4) 6-2.6 Bose condensation (18.7) 184 Molecular Rheology LAB 6-1 6-1 Fluctuations 6-1.1 The probability distribution of fluctuations T reservoir subsystem The subsystem and the reservoir together undergo incessant and rapid transitions among their joint microstates. The subsystem energy thereby fluctuates around its equilibrium value reservoir subsystem The “subsystem” may, in fact, be a small portion of a larger system, the remainder of the system then constituting the “reservoir.” In that case the fluctuations are local fluctuations within a nominally homogeneous system. 185 Molecular Rheology LAB 6-1 The statistical mechanical form of the probability distribution for a fluctuating extensive parameter is familiar. Case I: T reservoir The probability that the system occupies a particular microstate of energy Eˆ : subsystem f e F E ˆ Case II: T, P reservoir subsystem The probability that the system occupies a particular microstate of energy Eˆ and volume Vˆ : f e G Eˆ PVˆ 186 Molecular Rheology LAB 6-1 Generally, for a system in contact with reservoirs corresponding to the extensive parameters X 0 , X 1 , , X s , the probability that the system occupies a particular microstate with parameters Xˆ , Xˆ , , Xˆ : 0 f Xˆ 0, Xˆ 1 , , Xˆ s S F0 , F0 , e.g. k =e 1 B S F0 , , Fs k B1 F0 Xˆ 0 F1 Xˆ 1 , , Fs Xˆ s 1 s , Fs : the Massueu function , Fs : the entropic intensive parameters 1 S , T T T 1 F0 ; F1 T T Xˆ 0 Eˆ ; Xˆ 1 Nˆ F 1 S T T 1 F0 T Xˆ 0 Eˆ ˆ f e F E f e Eˆ Nˆ G 1 P S , T T T 1 P F0 ; F1 T T Xˆ 0 Eˆ ; Xˆ 1 Vˆ f e G Eˆ PVˆ 187 Molecular Rheology LAB 6-1 6-1.2 Moments and the energy fluctuations Suppose that the Ê is the only fluctuating variable, all other extensive parameters being constrained by restrictive walls. Eˆ U : the deviations Eˆ U ; Eˆ U Eˆ U 2 : the mean-square deviation (the second central moment) 2 Eˆ U Eˆ U 0 Ej U 2 fj Ej U j 2 2 e F Ej j j Ej U e j Molecular Rheology LAB F Ej Ej U e F Ej U F U 188 6-1 Eˆ U E 2 j U e Eˆ U F Ej j F Ej j Ej U e U Ej U fj E U 0 j 2 U U k BT 2 Ncv 1 k BT A very useful expression to estimate the heat capability of a system in computer simulations. The mean square energy fluctuations are proportional to the size of the system. U , which measures The relative root-mean-square dispersion Ê U the amplitude of the fluctuations relative to the mean energy, is proportional to N-1/2 . 2 12 For large systems (N→∞) the fluctuation amplitudes become negligible relative to the mean values, and thermodynamics becomes precise. 189 Molecular Rheology LAB 6-1 Higher-order moments of the energy fluctuations: Eˆ U n1 E j U F Ej e n j E j U e F Ej e j F Ej j E U E U e.g. the third moment: n n e n F Ej Ej U j n Eˆ U n 3 E U n 1 Ej U n 1 n U U c Nk B2 T 2 2Tcv T 2 v T The higher-order moments of the energy fluctuations can be generated from the lower-order moments by the recursion relation. 190 Molecular Rheology LAB 6-1 For a system in which both E and V fluctuates: Eˆ 2 U kB (1 / T ) P / T , N1 ,... kBT 2 Nc p kBT 2 PV k BTP 2V T Eˆ Vˆ 2 V kB (1 / T ) P / T , N1 ,... kBT 2V k BTPV T Vˆ 2 V kB ( P / T ) 1/ T , N1 ,... kBT V T The energy and the volume fluctuations are correlated, as expected. 191 Molecular Rheology LAB 6-2 6-2 Quantum Fluids As so often happens in physics, the formalism points the way to reality. The awkwardness of the formalism is a signal that the model is unphysical-there are no classical particles in nature! Quantum Mechanical Particles Fermions Bosons Fermions are the quantum analogues of the material particles of classical physics. Bosons are the quantum analogues of the “waves” of classical physics. e.g. electrons, protons, and neutrons e.g. photons (quanta of light) Molecular Rheology LAB 192 6-2 (From Astro-group, department of physics of Hong Kong university) 193 Molecular Rheology LAB 6-2 6-2.1 Fermions and bosons & ideal quantum fluids Fermions Fermions obey “law of impenetrability of matter”, only a single fermion can occupy a given orbital state. The intrinsic angular momentum for fermions: 2 n , n 1, 3, 5, (odd multiples) Spin quantum number m s : 1 1 ( ), ( ) 2 2 194 Molecular Rheology LAB 6-2 Consider a pre-gas model system in which only three spatial orbits are permitted; particles in these spatial orbits have energies ε1, ε2, and ε3. The model system is in contact with a T reservoir and a μ reservoir. There are therefore six orbital states: 1 1 ( n, ms ) ; n 1, 2, 3 ; m s , 2 2 T & μ reservoir subsystem The Grand canonical partition sum factors: Z z1, 1 2 z1, 1 2 z 2, 1 2 z 2, 1 2 z 3, 1 2 z 3, 1 2 z n , ms n N n n n 0 e e e 1 e n ,ms f n , ms e n e n 1 n z n , ms 1 e e n 1 195 Molecular Rheology LAB 6-2 Pair the two orbital states with the same n but with ms 1: 2 1 e n 1 2e n e n 2 z n, 1 2 z n, 1 2 2e n 1 empty 2 singly occupied e 2 n double occupied The fundamental equation: e Z 1 e 1 2 1 e 2 2 1 e 3 2 196 Molecular Rheology LAB 6-2 N N f n, m or N 2 e 1 U n, m n, m n, m n, m U f f n, m n, m or 1 U 2 e 2 n, m 1 2 e 3 1 f n, m n, m 2 1 e 1 1 2 2 e 2 1 2 3 e 3 1 By the same way, S determines the entropy. T The fundamental equation is an attribute of the thermodynamic system, independent of boundary conditions. In general, the Fermi level μ as a function of T and Ñ must be determined. 197 Molecular Rheology LAB 6-2 Ideal Fermi fluids The ideal Fermi fluid is a quantum analogue of the classical ideal gas; it is a system of fermion particles between which there are no (or negligibly small) interaction forces. Composite “particles,” such as atoms, behave as fermion particles if they contain an odd number of fermion constituents e.g. 3He. The partition sum of orbital state k , m s : z k , ms k Nk k k 0 e e e 1 e k , ms The partition sum factors: Z z k , ms k , ms The probability of occupation: f k , ms e k 1 z k , ms e k 1 198 Molecular Rheology LAB 6-2 The grand canonical potential: k BT lnZ k BT ln 1 e k k k 2 The energy of an occuppied orbital state k , m s : 2 2 p2 k k ,ms , k: wave vector (can refer to eq. 16.43 in textbook) 2m 2m The density of orbital states: (see Chap. 16) V 2 dk V 2m D d k d 2 2 d 4 2 2 32 1 2d 2k BT ln 1 e D d 0 V 2m k BT 2 2 2 32 0 ln 1 e 1 2 d which can be utilized to determine U and N . U ;N 199 Molecular Rheology LAB 6-2 Bosons Fermions as waves can be freely superposed, so an arbitrary number of bosons can occupy a single orbital state. The intrinsic angular momentum for fermions: 2 n , n 0, 2, 4, (even multiples) 200 Molecular Rheology LAB 6-2 Ideal Bose fluids The partition sum of a single orbital state is independent of m s , and is, for each value of m s , 2 2 3 3 z k z k , ms e 0 e k e k e k 1 n ; x k 1 x 1 e n 0 The probability of occupation with various occupated no. i in orbital state k, m s is 1 f k , ms , i i i e k z k , ms The average number of bonsons in the orbital state k , m s : 2 2 3 3 nk , ms i f k , ms ,i e k e k e k i ln z k , ms Molecular Rheology LAB k BT zk , m s 201 6-2 e k k nk , ms k BT ln z k , ms k BT ln 1 e k BT 1 e k 1 e k 1 1 occupation probability (or nk , ms f k , ms mean occupation number) e k 1 ln 1 e D d 0 2 V 2m 3 2 2 2 32 32 0 e k d which determines U and N . 1 The quantity fk , ms is not necessarily less than unity, and therefore is more properly identified as a “mean occupation number” .nk , ms If μ were positive the orbital state with εk equal to μ would have an infinite occupation number! So, the molar Gibbs potential μ is always negative. 202 Molecular Rheology LAB 6-2 6-2.2 The classical limit and the quantum criterion At low densities or high temperatures, the probability of occupation of each orbital state is small, thereby minimizing the effect of the fermion prohibition against multiple occupancy. 1 The probability of occupancy: f k , ms 1 e If fugacity e 1 ; classical regime The occupation probability reduces to f k , ms e e e The Boltzmann distribution The number of particles N reduces to g V 2m 0 2 2 N 2 λT h 2 mk BT Molecular Rheology LAB ; 32 e 0 e 1 2 d g0V e 3 λT λ T : the thermal wave length 203 6-2 The energy reduces to 32 g0V 2V 2m 3 3 2 U e e d k BT 3 e 2 2 0 2 λT 2 U 3 Nk BT 2 N The equation of state of classical ideal gas The criterion that divides the quantum and classical regimes: e 1 or gV λ T3 0 1 classical-quantum boundary N The classical limit the fugacity is the ratio of the “thermal volume” λ3T to the volume per particleV/(Ñ/g0). The system is in the quantum regime if the thermal volume is larger than the actual volume per particle (of a single spin orientation) either by virtue of large Ñ or by virtue of low T (and consequently of large λT). 204 Molecular Rheology LAB 6-2 6-2.3 Example of Fermi fluid: electrons in a metal At T=0 K, to calculate the number of particles: 2m 12 d T 0K for 0 1 N f T , 2 3 0 3 2 3 for 0 0 The number of conduction electrons per unit volume in metals is of the order 2m 3 2V 0 32 V 32 0 of the order of 1022 to 1023 electrons cm 3 , the Fermi temperature TF is TF 0 kB 104 K to 105 K Metal TF (K) Metal TF (K) Li 5.5×104 Cs 1.8×104 Na 3.7×104 Cu 8.2×104 K 2.4×104 Ag 6.4×104 Rb 2.1×104 Au 6.4×104 205 Molecular Rheology LAB 6-2 All reasonable temperatures μ>> kBT, the electrons in a metal are an example of an ideal Fermi gas in the strong quantum regime. The heat capacity: 2 k BT 3 C Nk B 2 3 0 3 O T The prefactor 3ÑkBT/2 is the classical result, and the factor in parentheses is the “quantum correction factor” due to the quantum properties of the fermions, which is of the order of 1/10 at room temperature. This drastic reduction of the heat capacity from its classically expected value is in excellent agreement with experiment for essentially all metals. 206 Molecular Rheology LAB 6-2 6-2.4 Bose condensation The number of particles N e : g V 2m Ne 0 2 2 2 32 1 2 0 1 e 1 d Fugacity e , and 0 1 Expand the integral of equation of N e in powers of the fugacity: g V 2m 3 2 g0V 32 0 Ne k BT λ 3 F3 2 2 2 2 2 T h λT ; λ T : the thermal wave length 2 mk BT F3 2 r 1 r r 32 2 2 2 3 3 3 207 Molecular Rheology LAB 6-2 The energy: g0V 2m U 2 2 2 32 32 0 1 e 1 d Expand the integral of equation of U in powers of the fugacity: 2V 2m 3 2 3 g0V 3 52 U k T F k T F5 2 B 52 B 2 2 3 2 λT 4 2 F5 2 r 52 r 1 r Ne 2 4 2 3 9 3 g0V g0V Ne F λ T3 3 2 λ T3 F3 2 F5 2 3 U N e k BT 2 F3 2 The ratio F5 2 F3 2 measures the deviation from the classical equation of state. 208 Molecular Rheology LAB 6-2 At 1 F5 2 1.34 At 0 slope of F5 2 1 F3 2 2.612 slope of F3 2 1 The two functions F5 2 and F3 2 satisfy the relation: d 1 F5 2 F3 2 d 209 Molecular Rheology LAB 6-2 If g0V 2.612, to first evaluate the temperature at which the failure of the 3 N e T "integral analysis" occurs. gV Set 0 3 2.612 N e T λT h 2 mk BT 2 2 1 N k BTc m 2.612 g0V 23 Tc : the Bose condensation temperature Example of Bose condensation of 4He For temperature greater than Tc the “integral analysis” is valid. At and below Tc a “Bose condensation” occurs, associated with anomalous population of the orbital ground state. 210 Molecular Rheology LAB 6-2 211 Molecular Rheology LAB 6-2 ρs(T): superfluid density of 4He ρn(T): normal fluid density of 4He Below Tc the fluid flows freely through the finest capillary tubes, as its name denotes, “superfluid.” This component cannot easily dissipate energy through friction, as it is already in the ground state. The condensed phase has a quantum coherence with no classical analogue. These electron pairs then act as bosons. The Bose condensation of the pairs leads to superconductivity, the analogue of the superfluidity of 4He. 212 Molecular Rheology LAB