Basic Rules of Integration: Worksheet #1 Name:;_________________________________ Determine the Following: 1. e dx 2. 4. x 5. sin xdx 7. csc x cot xdx x 10. 2/3 x 2/5 dx 5 1 25 x 2 x dx 3. 2 6. sec xdx 9. 9 3 xdx 8. 5 cos xdx x 1 dx 1 12. x dx 15. 18. 4e4 x 1 e8 x dx 11. 12dx dx Determine the following. Beware of compensation. 14. sec(12 x) tan(12 x)dx 13. sin(8 x) dx 16. e 18 x 17. 3cos(9 x) dx dx x 1. e C 2. 1 10 x10 C 3. 3 4 x 4/3 C 4. 3 5 x 5/3 C 5. cos x C 6. tan x C 2 x 1dx 7. csc x C 8. 5sin x C 9. ln x C 10. sin 1 (5 x) C 11. 12x C 12. ln x C 13. 18 cos(8 x) C 14. 1 3 (2 x 1) 3/2 C 16. 1 18 18 x e C 17. 13 sin(9 x) C 1 18. tan (e ) C 4x 1 12 sec(12 x) C 15. Fundamental Theorem of Calculus Part 2 Name:_________________________________________ What is the difference between a definite integral and an indefinite integral? Fundamental Theorem of Calculus Part 2 (Yes, we’re starting with Part 2) Practice with Definite integrals Worksheet #2- No Calculator Name:_______________________________________ 6 1. 3. 2 x dx 2. 3 3 5 0 x e dx 4. 1 7. 4t du 3x 2e dx x t 7/2 dt 4 1 3 t 10 4 3/2 2 2 3 5. u 6. 2 dt 1 dx .2 3x Turn Over 2 8. du 2 Worksheet # 2 (Continued) /2 t 1 dt 9. t 1 27 3 / 4 11. 10. /2 /4 sin d sec 12. /3 1/2 14. csc x cot xdx /6 11. tdt 2 1 4x 2 dx 0 5 3 1. 27/2 2. 35/3 3. e e 60 3 2 0 /4 13. cos xdx 2 4. 2e 8 8 10. 2 3 2 12. 1 13. 2 2 3 3 14. π/4 5. 162 3 82 5 45 6. ¾ 7. 1/3 ln50 2 8. 2 9. U-Substitution Worksheet #3 Name:_______________________ Date:___ 1. x2 (1 x3 )dx 8 2 2. cot csc d 3. sin x 4. e cos xdx 4 tan sec 2 d 5. sin(2 x 4)dx 6. x( x 2 5)10 dx 10. 2 4 9. sec x tan xdx 11. dx x ln x 3 1. 1/ 3ln 1 x C 1 22 csc2 (ln x) x dx 8. 2 7. sin x cos xdx e x dx (e x 1)3 x xe dx 2 12. 2. 19 cot 9 C 3. 4 5 tan 5/ 4 C 4. esin x C 5. 12 cos(2 x 4) C 6. ( x 2 5)11 C 7. 13 sin 3 x C 8. cot(ln x) C 9. 1 5 tan 5 x C 10. 12 (e x 1) 2 C 11. 2(ln x)1/2 C 12. U-Substitution Definite Integrals: Worksheet #4 No Calculator. x2 1 (2 x2 8x)2 dx Name:____________________ Period:___ 1 2 1. 2. /2 1 2 3. cos( )d 4. 0 x(7 x 0 4 x cos(3x 2 )dx 0 /2 1 5. ex 0 e x 7 dx 2 1) dx 1/3 6. sin /4 5 x cos xdx /6 7. tan 2x dx x3 dx 9. 2 ( x 6 x 1)3 0 e 8. (ln x) 4 1 x dx /4 2 10. 2 x x 9dx 0 2 x sec 2 xdx 0 4 11. tan 1 12. cos x dx x 0 2 e7 5. 45/56 6. 7/48 7. 1/2ln1/2 8. 1/5 9. 72/289 10. 1/3 11. 98/3 12. 3. 1/2sin1 4. 3 8 1. 7/480 2. ln 2sin1 Warm Up: Name your u Name:______________________________________ For the following problems, name the u you would use to solve by u-substitution. 1. 2. 4xe 3. 4. tan 5. cos 6. 7. 8. x ln x dx u=_____________ 9. sec 2 xe 4 tan x dx u=_____________ 10. 3 x sec 2 ( x 2 )dx u=_____________ 11. 3 sin x cos xdx 3 x2 u=_____________ dx 52 x dx x 2 3 u=_____________ u=_____________ x sec 2 xdx u=_____________ x sin xdx u=_____________ csc x csc x cot xdx u=_____________ ln x dx x u=_____________ 3 x2 1 x3 3x dx u=_____________ 12. cos 2t sin 5 2tdt u=_____________ xe 13. dx u=_____________ 14. sin(1/ x) dx 3x 2 u=_____________ e 2 y 1 dy 2 y 1 u=_____________ 3 x4 15. U-Substitution Practice #5 Name:____________________ Period:___ 2 x2 x (4 x3 3x2 )2 dx 1. 2 x x 4dx 2. 3. x( x 1) 4. sin 5 x cos xdx 5. tan 9xdx 1/4 dx 6. cos 2 x (1 sin 2 x) 2 dx 7. sec 2 x(4 tan 3 x 3 tan 2 x)dx 8. (ln x) 4 x dx /4 x3 9. 2 dx ( x 6 x 1)3 0 2 10. 17 11. tan( )d 2 12. x sec 2 xdx ( x 9) 2/3 dx 10 0 2 3/2 1. 13 ( x 4) C 2 0 1 tan 3 2 1 2. 16 (4 x 3 x ) C 6 4. 16 sin x C 5. 19 ln cos9x C 5 8. 15 (ln x) C 9. 72/289 10. 1/3 3. 4 9 ( x 1)9/4 54 ( x 1)5/4 C 1 4 3 6. 12 (1 sin 2 x) C 7. tan x tan x C 11. 12 ln(sec1) 12. 3 Worksheet #6: Initial Conditions Name:___________________________________________Period:____ Solve the differential equation with the given initial condition. 1. dy cos 2 x y ( 2 ) 3 dx 2. dy x3 dx 3. dy 8 x3 3 x 2 3 y (1) 1 dx 4. dy sec 2 (3 x) y ( 4 ) 2 dx 5. dy e5 x dx 6. dy t dt y (0) 3 y (1) 1 y (1) 1 First, find f '( x ) . Then find f ( x ) . 7. f ''( x) x3 2 x 1, f '(0) 1, f (0) 2 8. f ''( ) 2cos , f '( 2 ) 1, f (0) 6 9. A particle located at the origin at t=1 begins moving 2 along the x-axis with velocity v(t ) 12 t t ft / sec . Let s(t) be its position at time t. Find s(t). 10. A particle moves along the x-axis with velocity v(t ) 5t t 2 ft / sec . Find s(t) assuming the particle is located at x=5 at time t=2. 11. A particle located at the origin at time t=0 moves in a straight line with the acceleration a(t ) 4 3t ft / sec2 . A. State the solve the differential equation for v(t) assuming that the particle is at rest at time t=2. B. Find s(t). 12. The velocity of a particle is v(t ) t 3 10t 2 24t ft / s Use your calculator to sketch a graph of the velocity. Place units on your answers. a. Find the equation for the position of the particle. b. Using your calculator or your answer above find the displacement over [4,6] and [0,4] c. Using your above answers, what is the particles total displacement from [0,6]? d. What is the total distance traveled over [0,6]? 5 e. What is the meaning of v(t )dt ? What is the meaning of 0 5 v(t ) dt ? 0 5x 4 3/2 1. y 12 sin(2 x) 3 2. y 14 x 34 3. y 2 x 4 x3 3x 1 4. y 13 tan(3x) 73 5. y 15 e 145 6. y 23 t 13 4 2 7. f '( x) 14 x x x 1 f ( x) 1 20 x 5 13 x 3 12 x 2 1x 2 8. f '( ) 2sin 1 f ( ) 2 cos x 8 3 2 2 3 2 3 2 9. s (t ) 16 t 12 t 13 10. s (t ) 52 t 13 t 73 11a. v(t ) 4t 32 t 2 11b. s (t ) 2t 12 t 2t 12a. s (t ) 14 t 103 t 12t C 12b. -20/3 ft, 128/3 ft 12c. 36 ft. 12d. 148/3 ft 12e. Total displacement of the particle for the first 5 seconds. Total distance of the particle for the first 5 seconds. 4 3 2 Calculus Name Differential Equations Find the general solution of the differential equations. Do work on your own paper. 1. dy x3 5 dx 2. dy 1 8x dx 2 3. dW 4 t dt 4. y 2 10 dr 3sin p dp Solve the initial value differential equations. 5. dy 1 cos x dx y π 0 6. dy 6 x2 4 x dx 7. dP 10e t dt P 0 25 8. ds 32t 100 dt 9. dq 2 sin z dz q (0) 5 10. y e x 3 2 x 1 11. y x 9 x2 y(0) = -2 12. dy 2e t dt s 50 t 0 y 3 4 y(ln 2) = 0 13. d2y sin x dx 2 y (0) 3; y(0) 0 14. d2y 2 6x dx 2 y (0) 1; y(0) 4 d3y 1 15. dx3 t 3 y (1) 1; The velocity v ds dv or acceleration a of a body moving along a coordinate line is given. Find the body’s dt dt y(1) 3; y(1) 2 position s at time t. 16. v t 9.8t 5 18. a t cos t s(0) 10 17. a(t ) 32 s(0) 0; v(0) 20 s(0) 1; v(0) 1 On earth acceleration due to gravity is a(t) = -32 ft/sec2 or a(t) = -9.8 m/sec2. 19. A tomato is thrown upward from a bridge 25 m above the ground at 40 m/sec. a. What is v(0)? What is s(0)? b. Give formulas for the acceleration, velocity, and height (position) of the tomato at time t. c. How high does the tomato go, and when does it reach its highest point? velocity at the highest point? Find the value of t when this occurs.) (Hint: What is d. How long is the tomato in the air? (Hint: When is position 0?) 20. When Apollo 15 astronaut David Scott dropped a hammer and a feather on the moon to demonstrate that in a vacuum all bodies fall with the same (constant) acceleration, he dropped them from about 4 ft. above the ground. The television footage of the event shows the hammer and feather falling more slowly than on Earth, where, in a vacuum, they would have taken only half a second to fall 4 ft. On the moon acceleration due to gravity a(t)= 5.2 ft / sec2 . a. What is the initial velocity and initial position? b. Find the position equation s(t). c. How long did it take the hammer and feather to fall 4 feet on the moon? Answers: 1. y 1 x4 8 3 5 x c 2. y 4 x 2 x c 3. w t 2 c 2 4 3 4. r 3cos p c 20e 32 t 25 8. S 16t 2 100t 50 5. y x sin x π 6. y 2 x 2 x 14 y 7. P 3 3 2 9. q 2 z cos z 4 10. y e x 3 x 2 x 3 13. y cos x 1, y sin x x 3 15. y 1 5 , 2t 2 2 17. v t 32t 20, y 1 5t , 2t 2 2 11. y 9 x 5 12. y 2et 4 14. y 2 x 3x 2 4, y x3 x 2 4 x 1 1 5 1 2 y ln t t 2 16. v(t ) 4.9t 5, s(t ) 4.9t 5t 10 2 4 4 s t 16t 2 20t 18. v(t ) sin t 1, s(t ) cos(t ) t 2 19. a. 40, 25 b. v(0) 9.8t 40, s(t ) 4.9t 40t 25 c.106.633m 20. a. 0, 4 b. s(t ) 2.6t 2 4 c. 1.240 sec d. 80 sec 9.8 More Practice Integration Name: _________________________________ Answers are on the blog. Find the indefinite integral. 1. 3x (x 2. x 5 x 4 2x 1 dx x3 2 3) 4 dx sin (3 )cos(3 )d 3 2t d 5. 6. 9. dx x ln x 10. ex dx ex 4 13. 5 sec(2x ) tan(2x )dx 16. x 1 dx x 2 2x 17. 11. 1 e 2x dx 4. 2 8. cos(3 )d dx 18. ln x 4 dx x 12. 15. cos x cos(sin x )dx e 3x e 3x 3 dx sin(3x ) cos(2x )dx 14. ex 2x 5 x 2 1 sec (7 x )dx 7. 5 2 3. cos x dx sin x 1 2 3 dx x x Evaluate the definite integral. 2 5 1 19. 1 cos(2 x) dx 20. 3x 4 dx 21. dx 22. x 0 2 2 8 24. 25. 6 1 29. xe 0 9 5 x x 9e dx 2 dx 26. 3 x2 /3 dx 30. 0 sin d cos 2 8 4 x3 dx e4 31. e dw 32. w ln w 0 /4 1 27. 1 u du u 0 4 3 4sec x tan x dx 23. 2 2 3 5 x (1 2 x ) dx 0 1/2 0 sin 1 x 1 x2 dx 28. sin(4 x)dx 0 AP Calculus Name___________________ Fundamental Theorem Worksheet Evaluate the following: x 4x d (3t 2 2t )dt 1. dx 2 d (3t 2)dt 2. dx 2 x2 d 3. cos tdt dx 2 x3 d 3t 1 5. ( 2 )dt dx 2 x 5t 2 5 4. d ln(t ) dt dx 3x2 x3 d 6. (4t 3 2t 2 3)dt dx 2 x2 Evaluate the following: 10 7. (3x 4 x 8)dx 2 3 8. 2 2 8 9. 1 x 3 dx cos( x)dx 10. 4x 12. x 3 3x 2 2 x 4 4 11. 1 x 6 dx 2 3 4 x 5 4 dx 1 AP Calculus: Practice FTC/Basic Integrals Name:_______________________ Period:___ Find the following using the Fundamental Theorem of Calculus. x x d 2 t dt 1. dx 2 d 4. dx 2. 2 x 1 x 1 t 2 dt d t4 5. 1 t dt dx 1/3 5 d 8. cos t dt dx ex d sec t dt 7. dx ex d 10. dx sin 1 x x x4 ln x t e dt e d cos tdt dx d 1 dt 11. dx sec x x 3. d tan 1 t dt dx x x2 d 1 6. dt dx 2 1 t 2 d 9. dx tan 1 x t 3 dt sin x d 12. dx 3 x x 1/3 2x 5 x dt Simplifying the following: 13. x 5 dx 14. cos x dx 16. x 5 x dx 17. 19. csc x cot x dx 20. 1 x 22. 23. e 4 1 1 x 2 dx /3 25. 26. 1 25 x dx 3/2 0 1 x 2 18. csc 2 x dx dx dx 1 dx 1 x2 5 21. x 24. 27. 1 x 1 x2 dx /6 1 20dx 1/ 3 1 1 1/2 1 x 2 dx 30. 2 32. dx sin xdx 1 29. 2 /3 sec 2 xdx /2 15 31. 1 dx x /3 csc x cot xdx /6 28. 8 15. sec x tan x dx 64 33. 16 1 dx 4 x 1 1 x2 dx AP Calculus: Practice MC Basic Integration 1. (Calculator) Let F(x) be the antiderivative of A. 0.048 B. 0.144 Name:__________________________________ ln x 3 x C. 5.827 . If F(1)=0, then F(9)= D. 23.308 E. 1,640.250 k 2. What are the values of k for which x dx 0 2 3 A. -3 B. 0 C. 3 D. -3 and 3 E. -3, 0, 3 2 B. e e e2 1 C. e 2 2 2 D. e 2 e2 3 E. 2 2 B . 7/24 C. 1/2 D. 1 E. 2ln2 x2 1 1 x dx e 3. A. e 2 4. 1 x 2 1 e dx 1 A. -1/2 5.(Calculator) At time t 0 , the acceleration of a particle moving on the x-axis is a (t ) t sin t . At t=0, the velocity of the particle is -2. For what value of t will the velocity of the particle be zero? A. 1.02 6. B. 1.48 C. 1.85 D. 2.81 E. 3.14 1 2t e dt 2 t A. e C b 7. If a B. e 2t C t C. e 2 C t D. 2e 2 C E. et C b f ( x)dx a 2b , then ( f ( x) 5)dx a A. a+2b+5 B. 5b-5a 1.C 2. A 3. E 4. C 5. B 6. C 7. C C. 7b-4a D. 7b-5a E. 7b-6a