Qn.1
Two bowls are taken, one contains water and another contains tea. One spoon of water is added
to second bowl and mixed well, and a spoon of mixture is taken from second bowl and added to
the first bowl. Which statement will hold good for the above?
Second liquid in first bowl is less than the first mixture in second bowl
Second liquid in first bowl is more than the first mixture in second bowl
Second liquid in first bowl is equal to the first mixture in second bowl
Answer:
Second liquid in first bowl is equal to the first mixture in second bowl
Explanation:
Exchanged quantity of liquid is negligible.
So, option 3
None of these
Qn.2
1/1000
Answer:
1/1000
Explanation:
Given Exp. = (a2 + b2 - ab)/(a3 + b3) = 1/(a + b)=1/(753 + 247) = 1/1000
1/506
253/500
None of these
Qn.3
Which is the smallest number that divides 2880 and gives a perfect square?
1
2
5
Answer:
5
Explanation:
Solving from given options.
2880/5 = 576
where 24*24 = 576
6
Qn.4
A die is rolled and a coin is tossed. Find the probability that the die shows an odd number and
the coin shows a head.
1/4
Answer:
1/4
Explanation:
The sample space S of the experiment described in question 5 is as follows
S = { (1,H),(2,H),(3,H),(4,H),(5,H),(6,H)
(1,T),(2,T),(3,T),(4,T),(5,T),(6,T)}
Let E be the event "the die shows an odd number and the coin shows a head". Event
E may be described as follows
E={(1,H),(3,H),(5,H)}
The probability P(E) is given by
P(E) = n(E) / n(S) = 3 / 12 = 1 / 4
1/2
3/4
2/3
Qn.5
Rearrange and categorize the word 'RAPETEKA'?
vehicle
bird
Answer:
bird
Explanation:
parakeet -bird
person
city
Qn.6
In a box, there are 8 red, 7 blue and 6 green balls. One ball is picked up randomly. What is the
probability that it is neither red nor green?
1/3
Answer:
1/3
Explanation:
Total number of balls = (8 + 7 + 6) = 21.
Let E = event that the ball drawn is neither red nor green = event that the ball drawn
is blue.
n(E) = 7. P(E) = n(E)/n(S) = 7/21 = 1/3
3/4
7/19
8/24
Qn.7
Some work is done by two people in 24 minutes. One of them can do this work alone in 40
minutes. How much time does the Second person take to do the same work?
60 minutes
Answer:
60 minutes
Explanation:
1st person does in 1 min. = 1/ 40 of total work.
So, the other person does in 1 min. = (1/24 - 1/40) = 1 / 60. i.e., 60 minutes
30 minutes
20 minutes
10 minutes
Qn.8
5, 15, x, 51, 53,159,161. Find X
17
Answer:
17
Explanation:
2nd term-> 5*3=15
3rd term-> 2nd term+2=17
4th term-> 3rd term*3=51
5th term-> 4th +2=53 so on
15
51
18
Qn.9
There are 5 materials to make a perfume: Lilac, Balsamic, Lemon, and Woody and MI mosaic.
To make a perfume that is in demand the following conditions are to be followed: Lilac and
Balsamic go together. Woody and MI mosaic go together; Woody and Balsamic never go
together. Lemon can be added with any material. Which of the following is not a possible
combination?
Balsamic and Lilac
Woody and Lemon
MI mosaic and Woody
MI mosaic and Lilac
Answer:
MI mosaic and Lilac
Explanation:
Possible combination materials are
Lilac and Balsamic
Woody and MI mosaic
And Lemon can be mixed with any material.Therefore from given option d is
answer
Qn.10
There are 3 boys A, B, C and 2 Girls D, E. D always sit right to A. Girls never sit in extreme
positions and in the middle position. C always sits in the extreme positions. Who is sitting
immediate right to E?
A
Answer:
A
Explanation:
From given data
B/C D A
E C/B
A is right to E
B or C
C
B
Qn.11
One grandfather has three grandchildren, two of their young children age difference is 3, eldest
child age is 3 times 2nd child's age and eldest child's age is two times of sum of other two
children. What is the age of eldest child?
6
18
Answer:
18
Explanation:
Let as assume that x is youngest, y is middle one and z is eldest child
Y - X =3
Z=3y
and
Z= 2(x + y)
y= z/3
X=Y-3; X= z/3 -3
Substitute X and Y in Z i.e Z = 2(z/3 + z/3 -3 )
Z= 18; x=3; y =6
15
9
Qn.12
In an organization if material, labour and maintenance cost are in the ratio of 4:6:7, the material
cost is 100, what is the total cost?
380
425
Answer:
425
Explanation:
material: labour: maintenance = 4:6:7
Let total cost be x
4X/(4+6+7) =100
4x=17*100
X=425
420
475
Qn.13
A metal carrying a current 1m ampere with supply voltage of 1 volts .What is resistance value?
10 ohms
100 ohms
1000 ohms
Answer:
1000 ohms
Explanation:
V/ I = 1/ (1mA) = 1000
1 ohms
Qn.14
The ages of two people has the ratio of 6:5 and by adding ages we get 44, after how many years
the ratio would be 8:7?
9
5
7
8
Answer:
8
Explanation:
People ages has the ratio 6:5
so the ages can be 6x and 5x (the ration of age 6x and 5x is 6x/5x=6/5)
Adding the ages will get 44(Given in the question)
ie,6x+5x=44 11x=44
x=4
ie, the ages will be
6x=6*4=24
5x=5*4=20
After 'n' years the age ratio will be 8/7 (after n years the ages will be 24+n and
20+n)
ie 8/7=(24+n)/(20+n)
160+8n=168+7n
ie,n=8
After 8 years the age ratio will become 8/7
Qn.15
Two years before Paul's age was 6 times Alice's age,and than present age of Paul is 2 times than
Alice's. What is the present age of Paul ?
3 years
5 years
Answer:
5 years
Explanation:
Let Alice age be x
Then Paul's present age = 2x;
Before 2 years Paul's age = 6(x-2)
i.e 2x - 2 =6(x-2);
x= 5/2
Paul's present age 2*5/2 =5
9 years
18 years
Qn.16
In a school, out of a 100 a student got 74 as the average of 7 subjects and he got 79 marks in 8th
subject. What is the average of all the subjects?
76
74.6255
Answer:
74.6255
Explanation:
The average of 7 subjects=74 and 8th subject marks is 79
Therefore Total marks of 7 subjects = 74*7
Total marks of 8 subjects = 74*7 +79 =597
Average of 8 subjects =597/8 =74.625
76.67
77.67
Qn.17
In T nagar there are residential & commercial buildings. For residential buildings they number as
1 to 100. For commercial buildings, corporation numbered them with prime numbers between
150 and 200. How many times 6 will appear in building numbers?
18
19
22
Answer:
22
Explanation:
For 1 to 10 - 1 six
2 to 20 - 1 six
Similarly up to 59 we utilize six, 6 times from 60 to 69 (including 66) - 11 times
from 70 to 100 - 3 six,
from 150 - 200 -> 2 six (i.e. 163 ,167 )
Hence answer = 6+11+3+2 = 22
20
Qn.18
In a family there are some boys and girls. All boys told that they are having equal number of
brothers and sisters and girls told that they are having twice the number of brothers than sisters.
How many boys and girls are present in a family?
3 boys and 4girls
3 boys and 3girls
4 boys and 3girls
Answer:
4 boys and 3girls
Explanation:
Considering option [3] i.e, take one boy he is having three brothers and 3 sisters and
take one girl she is having two sisters and 4 brothers. The condition in the question
is satisfied. ie total 4 boys and 3 girls in a family
None of these
Qn.19
A tank is filled in 5 hours by three pipes A, B and C. The pipe C is twice as fast as B and B is
twice as fast as A. How much time will pipe A alone take to fill the tank?
20 hours
25 hours
35 hours
Answer:
35 hours
Explanation:
Suppose pipe A alone takes x hours to fill the tank.
Then, pipes B and C will take x /2 and x/4 hours respectively to fill the tank. 1/x +
2/x + 4/x = 1/5
7/x = 1/5
x = 35 hrs.
Cannot be determined
Qn.20
In school there are some bicycles and 4 wheeler wagons. On Tuesday there are 58 wheels in the
campus. How many bicycles are there?
7
Answer:
7
Explanation:
Let the number of bicycles = B
Then the number of wagons = W
Each bicycle has 2 wheels & wagons have 4 wheels.
Therefore, total no of wheels 2B +4W=58
B+2W=29
W = (29-B)/2
W is whole number only when b is 7.
8
6
4
Qn.21
A salesperson by mistake multiplied a number and got the answer as 3, instead of dividing the
number by 3. What is the answer he should have actually got?
0
1/3
Answer:
1/3
Explanation:
Let the number be 1; i.e., 1* 3 = 3
so, 1*1/3=1/3
Therefore he had to get 1/3
1
2
Qn.22
Horse started to chase dog as it relieved stable two hrs ago and ran with average speed 22km/hr,
horse crossed 10 meters road and two small ponds with depth 3m, and it crossed two small street
with 200 meters length. After traveling 6 hrs, 2hrs after sunset it got dog. Compute the speed of
dog?
16.2km/hr
16.5km/hr
Answer:
16.5km/hr
Explanation:
As we have speed and travel time of horse, we can get distance travelled by it.
Hence d = 22*6 = 132km,
Exactly this 132km was travelled by dog in 8 hours (as it started two hours earlier).
Hence speed of dog = 132/8 = 16.5 km/hr
13.5km/hr
13.8km/hr
Qn.23
Friends A, B, C went for week end party to McDonald's restaurant and there they measure their
weights in some order IN 7 rounds. A; B; C; AB; BC; AC; ABC. Final round measure is 155 kg
then find the average weight of all the 7 rounds?
32
35
31
None of these
Answer:
None of these
Explanation:
Given is A+B+C=155
Average weight of all 7 rounds will be A+B+C+(A+B)+(B+C)+(A+C)+(A+B+C)/7
= 4(A+B+C)/7= 4*155/7=88.571
Qn.24
Ram Singh goes to Pushkar Mela with Rs 10000 to buy exactly 100 animals. He finds that cows
are sold at Rs 1000, horses at Rs 300 and chicken at Rs 50. How much chicken should be buying
to meet his target of 100 animals?
92
94
Answer:
94
Explanation:
Solve through options, We find that if he buys 94 chickens, 1 horse and 5 cows, he
spends 4700 + 300 + 5000 = 10,000 and he also has 100 animals.
90
88
Qn.25
Like Fibonacci series, students tried to find new series. They got the new series as 3 12 7 26 15
b. Find b?
34
54
Answer:
54
Explanation:
3*2+1=7
12*2+2=26
7*2+1=15
26*2+2=54
45
24
Qn.26
A scientist in Antarctic region conducts research on bears came to know that bears changes
according to the location .once he moves 1 mile towards north, then he moves 2 miles towards
east, then 1 mile towards south. Now the color of bear he found will be in:
black
white
Answer:
white
Explanation:
as only white bears can live in north and south poles
brown
blue
Qn.27
How many 3-digit numbers can be formed from the digits 2, 3, 5, 6, 7 and 9, which are divisible
by 5 and none of the digits is repeated?
5
10
15
20
Answer:
20
Explanation:
Since each desired number is divisible by 5, so we must have 5 at the unit place. So,
there is 1 way of doing it.
The tens place can now be filled by any of the remaining 5 digits (2, 3, 6, 7, 9).
So, there are 5 ways of filling the tens place.
The hundreds place can now be filled by any of the remaining 4 digits. So, there are
4 ways of filling it.
Required number of numbers = (1 x 5 x 4) = 20.
Qn.28
Six bells commence tolling together and toll at intervals of 2, 4, 6, 8 10 and 12 seconds
respectively. In 30 minutes, how many times do they toll together ?
4
10
16
Answer:
16
Explanation:
L.C.M. of 2, 4, 6, 8, 10, 12 is 120. So, the bells will toll together after every 120
seconds(2 minutes).
In 30 minutes, they will toll together 30/2+ 1 = 16 times.
15
Qn.29
Pointing to a photograph, a man said, "I have no brother or sister but that man's father is my
father's son." whose photograph was it?
His own
His son's
Answer:
His son's
Explanation:
Since the narrator has no brother, his father's son is he himself. So the man who is
talking is the father of the man in the photograph or the man in the photograph is
his son.
His father's
His nephew's
Qn.30
Difference between two numbers is 4 and their product is 17. Then find the sum of their squares?
45
60
50
Answer:
50
Explanation:
a^2+b^2-2ab=(a-b)^2
(a)^2+b^2=16+(2*17) =50
38
Qn.31
Find (4x+2y)/ (4x-2y) if x/2y=2
1
7/9
3
9/7
Answer:
9/7
Explanation:
Taking 2y as common from both denominator and numerator
(4(x/2y) + 1)/ (4(x/2y) -1) = (9 /7)
Qn.32
One man want to build a wall the length and breadth of the wall are 20, 30 respectively. If he
requires 35 bricks for one square centimeter then how many bricks he need to build a wall?
12000
21000
Answer:
21000
Explanation:
Number of Bricks required to build a wall = l*b*35
20*30*35=21000
18000
24000
Qn.33
Find average speed if a man travels at speed of 24kmph up and 36kmph down at an altitude of
200m.
25
32
28.8
Answer:
28.8
Explanation:
Formula is 2xy/(x + y)
2*24*36/ (24+36) =28.8
26
Qn.34
In a shopping mall along with staff the average age of 5 members is 45 years. After 5 years a
person joined them and the average age is again 45 years. What's the age of 6th person?
45
43
34
20
Answer:
20
Explanation:
(m1+m2+...+m5)/5=45 ------------(1)
then after 5 years m6 joined
(m1+5+m2+5+...+m5+5+m6)/6=45 -------(2)
(2)-> [m1+m2+..m5+(5*5)+m6]/6=45-----(3)
from (1) m1+m2+...+m5=45*5
(3)-> (45*5)+(5*5)+m6=45*6---(4)
(4)-> m6=45-25
m6=20
so the sixth person age is 20
Qn.35
Given digits 2,2,3,3,4,4,4,4 how many distinct 4 digit numbers greater than 3000 can be formed?
50
51
Answer:
51
Explanation:
Now, let us fix the first, second and third digits as 3, 2, 2 and then the fourth place
can be filled in 3 ways
Similarly, we fix first, third and fourth places as 3, 2 and 2 respectively, so the
second place can be filled in 3 ways again
Now, we fix first, second and fourth places just as previous cases and we obtain the
same result.
The number of ways is 3 so; the total number of ways is 9.
Similarly this can do by fixing the numbers as 3 and 4 (instead of 2) and thereby we
obtain the 9 ways in each case. The number of numbers greater than 3000 starting
with 3 is 27
Similarly by taking 4 as the first digit and applying the same process, we get 27
numbers
The total number of numbers that are greater than 3000 is 27 + 27 = 54
But, 3222 and 4222 is not possible as there are only two 2's (given), 3333 is also
not possible as there are only two 3's (given)
The total number of numbers that are greater than 3000 is 54 - 3 = 51.
52
54