Cube Calculus Overview Of This Presentation • A Brief Review of Cube Calculus. • Summary of Cube Calculus operations. • Positional notation concept for Cube Calculus operations. • Summary of Positional Notation concept for Cube Calculus operations. • Why we need hardware realization of Cube Calculus? Brief Review Of Cube Calculus Representation of cubes in (Binary logic) • For the function f(a,b,c,d)= A + B = a’bc’+ac’d we have two cubes (a’bc’ and ac’d) Cube is a Product of literals. • In binary logic, they can be represented as A = a{0} .b{1} .c{0} .d{0,1} and B = a{1} .b{0,1} .c{0} .d{1} General Representation of cubes in (n valued logic) • A = x1s1A. x2s2A………xnsnA • B = x1s1B. x2s2B……….xnsnB • where x1s1A …..xnsnA.,x1s1B, .…xnsnB are literals. • n is the number of variables. • siA, siB are true sets of literal xi . • An example of a ternary logic is: A = x1{0}. x2{0,2}. x3{1}. x4{1,2} B = x1{1}. x2{1}. x3{2} . x4{0,1} Comparison of Notations for ternary logic Set-theoretical: A = x1{0}. x2{0,2}. x3{1}. x4{1,2} Positional: 100-101-010-011 Cube Calculus Operations Cube Calculus Operations The cube calculus operations are classified as : • Simple Combinational operations (e.g. Intersection, SuperCube ). • Complex Combinational operations (e.g. Prime, Consensus, Cofactor). • Sequential operations (e.g. Crosslink, Sharp(nondisjoint), Sharp (disjoint)). • Let us discuss these operations.. Simple Combinational Cube Operations Simple Combinational Operations • Defined as a SINGLE set operation on all pairs of true sets and produces one resultant cube. • Intersection and Supercube are simple combinational cube operations. • These operations are fast in software and very fast when realized in hardware. • Have various applications in two-level synthesis, set covering, graph coloring and all kinds of basic algorithms Example Of Binary Function Kmap representation of Intersection • B= ab • A= bc’ • Set theory : B = ab = abx = a{1}b{1}c{0,1} • A= bc’ = xbc’ = a{0,1}b{1}c{0} • B A=a{1}{0,1}b{1}{1} c{0,1} {0} = abc’ Kmap representation of Intersection A B • Fig 1: Input Cubes A and B to be Intersected. Here A = x2*x3 B = x1*x2 • Fig 2:Resultant Cube C=A B= x1*x2 *x3 Kmap representation of Supercube • A and B has 3 variables. • A = ab • B = bc’ • In set theory A= abx B=xbc’ • AB=b K-map representation of Super cube • Input Cubes A and B to be supercubed. A=x1’x2’x4 B= x1x3x4 • Resultant Cube C=A B = x4 Supercube has applications in SOP and ESOP minimization to find primes or product terms for best covers. Examples Of Cube Operations for Multi-Valued Functions K-map representation of Supercube ) • For 4 valued input logic. • Input Cubes A and B to be supercubed. A=a01b1. B=a12b2 • Resultant Cube C=A B = a012b12 K-map representation of Intersection • For 4 valued input logic. • Input Cubes A and B for Intersection. A=a12b12. B=a2b012 • Resultant Cube C=A B = a2b12 You have to be familiar with different notations and representations when reading research papers Definitions of Simple Combinational Cube Operations Intersection of two cubes : Is the largest cube that is included in both A and B. Supercube of two cubes : Is the smallest cube that includes both cubes. You have to understand meaning of operators when you create new algorithms You have to understand mathematical formalism of operators to realize them efficiently in software or hardware. Simple Combinational Operation • Intersection operation mathematically is defined as As B As B s s AB= x1 1 1 ……xn n n if siAsiB = otherwise. • Union (supercube) operation mathematically is defined as As B As B s s A B = x1 1 1 ……xn n n Complex Combinational Cube Operations Complex combinational cube operations • They have two set operations and one set relation. • All variables whose pair of true sets satisfy a relation are said to be Special Variables. • Two set operations are called before(bef) and active(act),the active set operation is applied on true sets of special variables and before set operation to others • All Combinational cube operations (Complex and Simple) produce one resultant cube, all special variables taken at a time. • The examples are prime operation, cofactor operation, consensus operation. Examples of Complex Combinational Cube Operations Example Of Binary Function Example of prime operation Notation of “prime” operation on cubes A and B • • • • A&B has 4binary variables A=x1’x2x3x4 B=x1x3’ Step 1: Find intersection operation(set relation) on all true sets(siAsiB ) • Step 2: If the set relation is satisfied apply active set operation(siA siB ) else before set operation( siA ). Explanation of the Example • Using set theory B=x1{1} x2{0,1}x3{0}x4{0,1} A=x1{0}x2{1}x3{1}x4{1} Step 1. Find if set relation (siAsiB ) is satisfied or not . x2 and x4 are special variables. Step 2. As the given set relation is satisfied for the variables x2 and x4 to these variables active set operation (siA siB ) is applied and to the others (x1 , x3 ) before set operation ( siA ) is applied A’B = x1{0}x3{1} = x1’x3 B = x1{1} x2{0,1} x3{0} x4{0,1} A = x1{0} x2{1 } x3{1} x4{1} ---------------------------------------------------- A’B = x1{0} x2{0,1} x3{1} x4{0,1} = x1’x3 Example of another complex combinational operation: consensus • A & B have 4 binary variables – A = x1x2x3’ – B = x1x2’ • Steps: find the set relation siAsiB=. • If satisfied then it is a special variable. • Active operation (siAsiB) applied to special variables. • And to remaining variables (before variables) the set operator siAsiB is applied Explanation of consensus operation • In set theory A = x1{1}x2{1}x3{0}x4{0,1} B = x1{1}x2{0}x3{0,1}x4{0,1} • Applying the set relation siAsiB= on all the true set of variables x2 is a special variable and to x2 active operation (siAsiB) is applied • and to x1 ,x3 ,x4 before set operator (siAsiB ) is applied A * B = x1{1} x3{0} = x1x3’ A= B= x1{1} x2{1} x3{0} x4{0,1} x1{1} x2{0} x3{0,1} x4{0,1} ---------------------------------------------------- A*B = x1{1} x2{0,1} x3{0} x4{0,1} Use of consensus to prove tautology YZ YZ 00 WX 0 01 1 1 1 00 4 5 11 3 10 00 WX 2 01 11 10 0 1 3 2 4 5 7 6 12 4 13 15 14 8 9 11 10 00 7 6 01 01 12 4 13 15 14 11 11 8 9 11 10 10 10 Table of all ones Cube of minterms YZ YZ 00 WX YZ 0 00 WX 0 01 1 11 3 10 00 WX 01 1 11 3 10 2 01 11 10 0 1 3 2 4 5 7 6 12 4 13 15 14 8 9 11 10 00 00 2 4 00 5 7 6 01 01 4 5 7 6 12 4 01 13 15 14 11 11 12 4 13 15 14 8 11 10 8 10 9 11 10 9 11 10 10 Proving tautology • By using consensus I combine step-by-step larger and larger cubes of ones. • Ultimately, the cube of ones that covers the whole map is created. • Thus the function is a tautology. • The process of combining cubes can be represented as a tree The same Cube Calculus has dual meaning when applied to cubes of zeros (maxterms) It is called resolution and used in automatic theorem proving to derive empty clause = cube of all zeros Use of consensus to derive empty clause YZ YZ 00 WX 01 0 11 1 3 10 00 WX 2 00 01 11 10 0 1 3 2 4 5 7 6 12 4 13 15 14 8 9 11 10 00 4 5 7 6 01 01 12 4 13 15 14 11 11 8 9 11 10 10 10 Cube of maxterms (zeros) Table of all zeros YZ YZ 00 WX YZ 0 00 WX 0 01 1 11 3 10 00 WX 01 1 11 3 10 2 01 11 10 0 1 3 2 4 5 7 6 12 4 13 15 14 8 9 11 10 00 00 2 4 00 5 7 6 01 01 4 01 12 4 11 Cube representing empty clause 5 13 7 15 6 12 4 10 9 11 15 14 11 11 14 8 10 8 13 10 9 11 10 10 Proving non-satisfiability is deriving empty clause • By using resolution operator (dual to consensus) I combine step-by-step larger and larger cubes of zeros. • Ultimately, the cube of zeros that covers the whole map is created. This is empty clause. • Thus the function is always zero. • The process of combining cubes can be represented as a tree. • This is used in automatic theorem proving to prove that a set of clauses is inconsistent •Please do a complete example with all formulas applied in formal way , step by step. •What would be a program? Example of cofactor operation • A and B have 4 binary variables. – A = x1x2x3 – B= x1 • Steps: Find siAsiB (If satisfied special variable) • Apply U(Universal set(0,1)) for special variables and siAsiB for others Explanation • Set theory: A = x1{1}x2{1}x3{1}x4{0,1} B = x1{1}x2{0,1}x3{0,1}x4{0,1} • Testing the relation siAsiB for the variables. x1 and x4 are special variables. Universal set operator applied to these variables. • To the rest of the variables the intersection operation is applied. The result is x2 x3. • In K-map apply the intersection operator and remove the special variables. Example Of Complex Combinational Operations for MultiValued Functions K-map representation of Consensus • A= X 01234 Y01 • B = X012 Y23 • A*B= X 01234Y01*X012Y23 = X012 Y0123 Definitions of Complex Combinational Cube Operations General Description of Consensus Cube Operation Complex combinational cube operation • The consensus operation on cubes A and B is defined as A B when distance (A,B) = 0 A*B= when distance (A,B) > 1 A *basic B when distance (A,B) = 1 • where A *basic B = A s1B A sk-1B A skB s1 sk-1 sk x1 ….xk-1 xk A sk+1B A snB sk+1 sn xk+1 …… xn . • Set relation: siAsiB = , if satisfied, a special variable • Active set operation : siAsiB • Before set operation : siAsiB Complex combinational cube operation • Application of consensus theorem: – For finding prime implicants (Used for two-level logic minimization), – three level, – multilevel minimization, – and machine learning. Most applications are in few-level circuit design, basic operations and automatic theorem proving in AND/OR logic General Description of Cofactor Cube Operation Complex combinational cube operation • Cofactor operation of two cubes A and B is A| B = A |basic B when A B = otherwise Set relation for cofactor operation = siA siB Active set operator = U (Universal set(0,1)) Before set operator = siA siB • Application: – Used in recursive paradigms – Used to create trees and DDs – Used in functional decomposition. General Description of Prime Operation Complex combinational cube operations • Prime operation of two cubes A and B is defined as A A skAskB A s1 sk-1 sk+1 A’B=x1 …xk-1 xk xk+1 ….xnsnA where set relation : siAsiB is applied to true and if satisfied active set operation is applied else before set operation is applied. • Active set operation(act):siA siB • Before set operation(bef): siA • Application: Used in ESOP minimization . sets Sequential Cube Operations Sequential cube operations • They have three set operations and one set relation. • All variables whose pair of true sets satisfy a relation are said to be Special Variables. • Three set operations are called before(bef),active(act) and after(aft) • The active set operation is applied on true sets of special variable • The before set operation to variables before the special variable • The after set operation to variables after the special variable. • Every special variable is taken once at a time. Sequential cube operations • All sequential cube operations produce ‘n’ resultant cubes, where n is the number of special variables. • The examples are: sharp operation, –cross link operation. – Examples of Sequential Cube Operations Example Of Binary Function Let us consider the following example, where the relation operation is SA SB = b is a special variable Cubes A and B are of 4 variables Let us consider the following two cubes, Cube A = x1 x2 x3’ = x1{1}*x2{1}*x3{0} *x4{0,1} Cube B = x1 x2’ = x1{1}*x2{0}*x3{0,1} *x4{0,1} These two variables (x1 and x3) are the so called special variables , and we find them out by checking the relation between every literal in both cubes for a relation which is for the crosslink ( is the intersection between these two variables is empty?). Cube A Cube B x1{0} x2{0,1} || || x1{1} x2{0,1} x3{0} x4{0,1} || || x3{1} x4{0,1} We can see that the intersection is empty for only X1 and X3 therefore they are special variables. Example of crosslink operation • A and B has 4 binary variables. • A = x1’x3’ = x1{0}x2{0,1}x3{0}x4{0,1 • B = x1x3 = x1{1}x2{0,1}x3{1}x4{0,1} • A c B = x1’x3’ + x1x3 = x3’ + x1 Example x1{0}x2{0,1} x3{0} x4{0,1} x1{1}x2{0,1}x3{1} x4{0,1} ------------------------------------------ First check relation x1{} x2{0,1}x3{} x4{0,1} active active before x1{0} x2{0,1} x3{0} x4{0,1} x1{1} x2{0,1}x3{1} x4{0,1} x1{0} x2{0,1} x3{0} x4{0,1} x1{1} x2{0,1} x3{1} x4{0,1} ------------------------------------------ x1 {0,1} x2{0,1}x3{0} x4 ------------------------------------------ {0,1} x1{1} x2{0,1} x3{0,1} x4{0,1} after • Cubes : • x1{0}x2{0,1} x3{0}x4{0,1} • x1{1}x2{0,1}x3{1} x4{0,1} • Set Relation: siAsiB = x1 and x3 are special variables.. • Act: siAsiB, Bef: siA, Aft: siB • x1{0} {1}x2{0,1} x3{0}x4{0,1} and Since the order of {1} {0,1} {0} {1} {0,1} x1 x 2 x3 x4 argument cubes is • Two resultant cubes one for each special variable. arbitrary, the result A B = x3’ x1 is not unique Non-uniqueness of crosslink operation One variant of crosslink Another variant of crosslink Complex crosslink example • A,B,C,D are 4 cubes • F = ABCD • F = ABEF • F = GH Graphical Crosslink in Karnaugh Maps Y 0 X Y 1 0 0 X 0 X 0 1 0 Y 1 Y 1 2 0 3 0 X 1 0 1 2 3 0 1 1 0 Y 2 0 X 1 1 0 3 1 1 2 0 3 1 1 0 2 3 1 Y 0 X 1 Y 0 X Y 0 0 X 0 2 3 0 1 1 2 1 3 1 1 0 1 0 2 1 0 3 Y 0 X 1 1 0 Y 1 0 0 X 2 1 3 1 0 1 2 3 0 1 Use of crosslink to derive minimum ESOP YZ YZ 00 WX 0 01 11 1 3 10 00 WX 2 00 01 11 10 0 1 3 2 4 5 7 6 12 4 13 15 14 8 9 11 10 00 4 5 7 6 01 01 12 4 13 15 14 11 11 8 9 11 10 10 10 Cube of minterms (ones) Table of all zeros YZ YZ 00 WX YZ 0 00 WX 0 01 1 11 3 10 00 WX 01 1 11 3 10 2 01 11 10 0 1 3 2 4 5 7 6 12 4 13 15 14 8 9 11 10 00 00 2 4 00 5 7 6 01 01 4 5 7 6 12 4 01 13 15 14 11 11 12 4 13 15 14 8 9 11 10 10 11 10 8 10 9 11 10 a a=0 Use of Crosslink for ESOP minimization • Please write formulas for the previous example • The solution is not unique • You have to use backtracking, heuristics, or probabilistic methods to obtain good solution • Look-ahead methods. • Start from several starting points. Example of nondisjoint sharp • A and B has 4 binary variables. • A=x3’=x1{0,1}x2{0,1}x3{0}x4{0,1} • B = x2x4 x1{0,1}x2{1}x3{0,1}x4{1} • Set relation: (siAsiB) – 1.x1{0,1} x2{0,1}n({1}} x3{0}x4{0,1} Act: siA siB, Bef: siA, Aft: siA – 2. x1{0,1}x2{0,1} x3{0} x4{0,1}n({1}} Act: siA siB, Bef: siA, Aft: siA • A # B= x2’x3’+ x3 ’x4’ Example of disjoint sharp • A and B has 4 binary variables. • A=x3’= x1{0,1}x2{0,1}x3{0}x4{0,1} • B = x2x4 • • • • x1{0,1}x2{1}x3{0,1}x4{1} Set relation: (siAsiB) x1{0,1}n{0,1}x2{0,1}n({1}} x3{0}x4{0,1} Act: siA ( siB), Bef: siA, Aft: siA siB x1{0,1}n{0,1}x2{0,1}n{1} x3{0}n{0,1} x4 {0,1}n({1}} Act: siA ( siB), Bef: siA, Aft: siA siB • A #d B= x2’x3’+ x2x3 ’x4’ Example Of Multi-Valued Function Example of crosslink operation • Let A=x0y1 and B=x2y3 X and Y are special variables. x{0}U {2} y1 and x {2} y{1}U{3} Resultant cubes:x02y1+x2y13 Definitions of Sequential Cube Operations General Description of Nondisjoint sharp Operation Sequential cube operations. • The nondisjoint sharp operation on cubes A and B A#B= A when A B = when A B = A #basic B otherwise s1A…x sk-1Ax skA(skB)x sk+1A….x snA for k-1 k k+1 n • A #basic B = x1 such that k=1,….n for which the set relation is true. • Set relation: (siAsiB). Active set operation: siA( siB), After set operation: siA, Before set operation: siA • Used in tautology problem. General Description of disjoint sharp operation Sequential cube operations. • The disjoint sharp operation on cubes A and B A#dB= A when A B = when A B = A #dbasic B otherwise s1A…x sk-1Ax skA(skB)x sk+1A….x snA k-1 k k+1 n • A #dbasic B = x1 for such that k=1,….n for which the set relation is true. • Set relation: (siAsiB) Active set operation: siA( siB), After set operation: siA siB , Before set operation: siA • Used in tautology problem, conversions between SOP and ESOP representations General Description of Crosslink Operation Sequential cube operations. • Generalized equation of Crosslink operation: B B skAskB A A s1 sk-1 sk+1 sn x1 …xk-1 xk xk+1 ….xn A B= where k=1,….n for which the set relation is true. • • • • • Set relation: siAsiB = , Active set operation : siAsiB, After set operation : siB, Before set operation : siA. Used in the minimization of logic function on EXOR logic, Generalized Reed-Muller form. Applications of Crosslink And we all know that the answer is that we are looking for two cubes as shown down here, so that our function is to be expressed in the ESOP form as follows: f=ED So the solution is to find these two cubes out (Cubes E, D). Let us see how the crosslink operation does that!!! Here is the K map for the original function again Here if we think about it, we are looking for literals, in which the intersection of these literals in both cubes is empty, that is X1 and X3, Because in the first cube we have Summary of the Cube Calculus Operation Summary of cube calculus operation Positional Notation Positional notation • Cube operations were broken into several set relations and set operations. Easy to carry out by hand. • To Process set operations efficiently by computers, we use positional notation. • Positional notation : Possible value of a variable is 0 or 1. • P valued variable a string of p bit • Positional notation of binary literals:x’ x{0} x10 10 x x{1} x01 01, don’t care x x{0,1} x11 11, contradiction x{} x00 00 Set operations in positional notation • Three basic set operations are executed using bit wise operations in positional notation. • Set intersection bitwise AND • Example A = ab B=bc’ A B = abc’ • In positional notation: A = 01-01-11 B = 11-01-10 B = (01/11)-(01/01)-(11/10) 01-01-10(abc’) • Set union bitwise OR • Example A = ab B=bc’ A B = b • In positional notation: A = 01-01-11 B = 11-01-10 B = (01/11)-(01/01)-(11/10) 11-01-11(b) A A Positional notation Set complement operation bitwise NOT Example: A= ab then A’ = (ab)’ In positional notation: A = 01-01 A’ = 10-10 Example of multi valued variable:A= x{0,1,2} B=x{0,2,3} A B = {0,2}, A B = {0,1,2,3} • In positional notation: A=1110, B=1011 A B =1110/1011=1010{0,2},A B =1110/1011=1111{0,1,2,3 A’=0001{3}, B’=0100{1} • • • • Set relations in positional notation • 1 True and 0 False • Set relation cannot be done by bit wise operation as it is a function of all bits of operands. • Set relation is broken into Partial relation and Relation type. The partial relation determine whether or not the two literals satisfy the relation locally. The relation type determines the method of combining partial relations. • Relation(A,B) = (a0’+b0’).(a1’+b1’)…………(an’-1+ bn’-1) for crosslink operation Partial relation ai’+bi’and relation type is AND. Table of partial relation Summary of cube operations in positional notation Why We Need Cube Calculus Hardware? Why Using Cube Calculus Machine? • The cube calculus Operations can be implemented on general-purpose computers, • But in general-purpose computers, the control is located in the program that is stored in the memory. • This results in a considerable control overhead. • Since the instructions have to be fetched from the memory, if an algorithm contains loops, the same instruction will be read many times. That makes the memory interface the bottleneck of these architectures. The cube calculus operations involve nested loops, it leads to poor performance on these generalpurpose computers. Slides by Nouraddin Alhagi & Syeda Mohsina Lecture on Oct 8,2001